This makes nooooooooooooooooooooooooooooooooooooooooooooooooooooo sense

i don't know if you mean C° to F° but in F° the change would be 123.8°

Answer:

2 e

Explanation:

d orbit contain 10 electrons .

Answer:

The fly cells must be compared with human cells

Explanation:

Dr. Gracia's aim is the development of a potential cancer treatment. Remember that the treatment is meant for human beings.

Usually, the pre-clinical trials of the treatment is carried out on other organisms and the success rate is evaluated before trial on humans.

If protein W has been effective on flies, its effect on human cells should also be diligently compared before conclusions are drawn regarding the therapeutic effects of protein W.

Answer:

when two surfaces rub together in outer space, there will be friction. Friction is a surface effect and doesn't depend upon there being air. There is also a force like air resistance from the very sparse gas in space, but it will be very, very small, since space is a very good vacuum.

Explanation:

Answer:

Tungsten(VI) fluoride, also known as tungsten hexafluoride, is an inorganic compound with the formula WF6. It is a toxic, corrosive, colorless gas, with a density of about 13 g/L (roughly 11 times heavier than air.[

Explanation:

The WF6 molecule is octahedral with the symmetry point group of Oh. The W–F bond distances are 183.2 pm. Between 2.3 and 17 °C, tungsten hexafluoride condenses into a pale yellow liquid having a density of 3.44 g/cm^3 at 15 °C. At 2.3 °C it freezes into a white solid having a cubic crystalline structure, the lattice constant of 628 pm, and a calculated density of 3.99 g/cm^3. At −9 °C this structure transforms into an orthorhombic solid with the lattice constants of a = 960.3 pm, b = 871.3 pm, and c = 504.4 pm, and the density of 4.56 g/cm3. In this phase, the W–F distance is 181 pm, and the mean closest intermolecular contacts are 312 pm. Whereas WF6 gas is one of the densest gases, with the density exceeding that of the heaviest elemental gas radon (9.73 g/L), the density of WF6 in the liquid and solid-state is rather moderate. The vapor pressure of WF6 between −70 and 17 °C can be described by the equation

log10 P = 4.55569 −

1021.208

T + 208.45,

where the P = vapor pressure (bar), T = temperature (°C).

The moles of water in 45.9 g  is 2.54 mol.

The moles are defined as the mass of substance with respect to the molar mass. The moles of sample are given by:

\(\rm Moles=\dfrac{Mass}{Molar\;mass}\)

The molar mass is the sum of mass of each element in the formula unit. The molar mass of water is 18.02 g/mol.

The given mass of water is 45.9 g.

Substitute the values for the moles of water:

\(\rm Moles=\dfrac{45.9 \;g}{18. 02 \;g/mol}\\\\ Moles=2.54\;mol\)

The moles of water in 45.9 g  is 2.54 mol.

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magnesium hydroxide is an osmotic laxative, that is that it works by pumping water into the intestines, which helps in producing bowel movement.

This medicine is used to relieve sporadic constipation. It is an antacid that reduces the stomach's acid production. Magnesium hydroxide lowers stomach acid and raises gut water levels, which may encourage bowel motions. Magnesium hydroxide is a laxative used to treat sporadic constipation. Magnesium hydroxide is also employed as an antacid to treat heartburn, indigestion, and sour stomach.

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Answer:

17

Explanation:

br is liquid

cl is gas

and iodide is solid

The Combining insulation with phase change materials ensures that a heat pack maintains a safe and effective temperature for an extended duration, providing optimal relief for minor injuries.

Two features that would help a heat pack maintain a safe and effective temperature for the longest amount of time are insulation and phase change materials (PCMs).

Insulation is crucial to minimize heat loss from the pack. A heat pack with a thick, high-quality insulation layer would reduce thermal energy transfer to the surrounding environment, allowing the pack to retain heat for a longer duration. This ensures that the pack remains at a desirable temperature range for an extended period, enhancing its effectiveness.

Additionally, incorporating phase change materials into the heat pack can help maintain a consistent temperature. PCMs have the ability to absorb and release thermal energy during phase transitions, such as solid to liquid or vice versa. By selecting a PCM with a melting point within the desired temperature range, it can act as a heat reservoir, absorbing excess heat when the pack is heated beyond the required temperature and releasing heat as it cools down. This phase change process helps regulate the pack's temperature, preventing it from getting too hot or cooling down too quickly.

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Answer:

false

Explanation:

because  i know it

Answer:

2C4H10(g) + 13O2(g) → 8CO2(g) + 10H2O(l) ΔH = -2871 kJ/mol

The enthalpy of combustion is the amount of heat released when one mole of a substance is burned in oxygen. In this case, the enthalpy of combustion of butane is -2871 kJ/mol, which means that 2871 kJ of heat is released when two moles of butane are burned in oxygen.

Enzymes exhibit high specificity, meaning that they catalyze specific reactions by binding to specific substrates. They achieve this through their three-dimensional structure, which includes an active site where the substrate binds and the catalytic reaction takes place.

Enzymes can be involved in a wide range of biochemical processes, including metabolism, digestion, DNA replication, and cellular signaling. Regarding daily applications, enzymes have numerous practical uses in various industries. In the food industry, they are used for food processing, such as in the production of bread, cheese, and beverages. Enzymes are also used in the detergent industry for stain removal and fabric care. In medicine, enzymes are utilized for diagnostic purposes, drug development, and as therapeutic agents. Enzymes find applications in environmental and energy-related processes, such as in biofuel production and waste treatment.

Overall, enzymes have extensive applications in different fields, and their unique catalytic properties make them invaluable for various biological, industrial, and technological processes.

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Analyzing and attempting to identify the chemical components of fiber and paint evidence typically involves a multi-step process that combines various analytical techniques.

Here is a general outline of the best process for analyzing such evidence:

1. Visual Examination: Begin by visually examining the fiber and paint samples under a microscope or magnifying glass. Note the color, texture, shape, and any other visible characteristics that may provide initial insights.

2. Microscopic Examination: Use microscopy techniques, such as polarized light microscopy, to further examine the samples. This can help determine fiber morphology, fabric type, layer structure, and other microscopic features.

3. Chemical Tests: Perform preliminary chemical tests to obtain information about the chemical composition of the evidence. For fibers, tests like burn tests, solubility tests, and dye tests can provide initial indications of the fiber type. For paint, chemical tests can help identify the presence of binders, pigments, and additives.

4. Fourier Transform Infrared Spectroscopy (FTIR): FTIR analysis can be used to identify functional groups and chemical bonds present in the fiber and paint samples. By comparing the obtained spectra with reference databases, it is possible to identify specific compounds or groups of compounds.

5. Microspectrophotometry: This technique allows for the measurement of the absorption and reflection spectra of microscopic samples. Microspectrophotometry can assist in identifying pigments and dyes used in paints and fibers by comparing their spectra with known standards.

6. Pyrolysis Gas Chromatography Mass Spectrometry (Py-GC/MS): This technique involves heating the sample to break down complex compounds into smaller fragments, which are then separated and identified using gas chromatography and mass spectrometry. Py-GC/MS can provide detailed information about the organic components of both fibers and paints.

7. Scanning Electron Microscopy with Energy-Dispersive X-ray Spectroscopy (SEM-EDS): SEM allows for high-resolution imaging of the surface morphology of the samples, while EDS enables the elemental analysis of the evidence. This combination can help identify inorganic components, elemental compositions, and provide additional clues about the origin of the fibers or paints.

8. Database Comparison: Compare the obtained analytical data with databases of known fiber and paint compositions. These databases may include information on common fibers, dyes, pigments, binders, and additives, which can aid in the identification process.

9. Expert Analysis: Seek the expertise of forensic scientists or specialists who have experience in fiber and paint analysis. They can provide interpretations, evaluate the significance of the results, and offer expert opinions in court proceedings if required.

It is important to note that this process may vary depending on the specific circumstances, available resources, and the nature of the evidence being analyzed. Additionally, maintaining appropriate controls, following laboratory protocols, and ensuring proper documentation of all steps and findings are crucial to ensure accurate and reliable results.

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Answer:

this is from another brainliest answers.

Explanation:

Ionic compounds need to be molten or in solution for electrolysis to work. This is because the charged particles that make them up (ions) need to be free to move to the electrodes.

The observation implies that the solubility of a solution depends on both the amount of solute and the volume of solvent.

The solubility of a substance is the property of that substance to dissolve in a solvent.

The solubility of a solution is the ability of the solution to dissolve solutes.

Solubility depends on the quantity of solutes and solvents.

Thus, 100 mL water may be able to dissolve 35 g NaCl but not 70 g because the maximum solubility of the water is breached. In order to dissolve more NaCl, the volume of the water might need to be increased.

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Sedimentary rocks include limestone. When ocean water evaporates, calcium carbonate is left behind, and this is how it forms.

Limestone is one of the most common types of chemical rocks. Limestone is created in the ocean by calcium and bicarbonate ions that erode from the remains of shells, coral, crustaceans, and mollusks. Wave action gradually disintegrates these structures into calcite and other calcium carbonate-based minerals, which accumulate in ocean water. As they are carried from the deep ocean environment to shallow places like lagoons and tidal pools, these solutes have the potential to precipitate to create sediments rich in calcium carbonate.  calcium carbonate can precipitate in lagoons to create ooids, which are spherical nodules that stick together to produce oolitic limestone, or limestone.

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Explanation:

Good question!

When you react an acid with a base,the pH of the product is determined by the concentrations of the reactants (the acid and the base)

If both reactants (acid and base) are strong,the pH of the product is 7

If the acid is stronger than the base,the pH of the product will be less than 7

If the base is stronger,the pH of the product will be greater than 7

I hope this helps

The Daniel cell is a simple electrochemical cell consisting of a copper electrode (cathode) and a zinc electrode (anode) in separate solutions of copper(II) sulfate and zinc sulfate, respectively. The two half-cells are connected by a salt bridge, which allows the flow of ions between the two solutions without allowing mixing. At the anode, zinc metal oxidizes to Zn2+ ions and releases two electrons, while at the cathode, copper(II) ions are reduced to copper metal by gaining two electrons. This results in the overall reaction: Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s). The cell potential of the Daniel cell is 1.10 V at standard conditions, which means that the reaction is spontaneous and the cell can produce an electric current.

To construct a Daniel cell, a zinc electrode is placed in a solution of zinc sulfate and a copper electrode is placed in a solution of copper(II) sulfate. The two half-cells are connected by a salt bridge, which can be made of a gel or soaked paper strip containing a salt solution, such as potassium chloride. The salt bridge completes the circuit by allowing the movement of ions between the two half-cells while preventing the mixing of the two solutions. The anode reaction is: Zn(s) → Zn2+(aq) + 2e-, while the cathode reaction is: Cu2+(aq) + 2e- → Cu(s). The overall reaction of the cell is: Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s), with a standard cell potential of 1.10 V. The figure below shows the construction of a Daniel cell with a salt bridge.

                 _______

                |       |

       Zn(s)---|ZnSO4  |---CuSO4|---Cu(s)

                |_______|      |

                      Salt Bridge

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Answer: Fertilization defintion

Explanation:

the action or process of fertilizing an egg, female animal, or plant, involving the fusion of male and female gametes to form a zygote.

Or giving rise to new indivisual organisms or offspring and initiating development

The concentration is measured by molarity, the formula of molarity is:

Based on the given data, we've already had the volume in liters and we have to convert 6.25 grams of HCl to moles. We have to use the molar mass of HCl which is 36.4 g/mol (you can find the molar mass using the periodic table). The conversion would be:

And the final step is to replace the values we have in the formula of molarity:

The molarity of 6.25 g of HCl in 0.300 L of solution is 0.573 M.

Explanation:

true

false

hope it helps

thank you

Answer: 1.  True

Explanation: 1. Multicellular organisms use cell division for growth and repair of damage such as wounds.

Answer:

30 moles of CO₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Al₂(CO₃)₃ —> Al₂O₃ + 3CO₂

From the balanced equation above,

1 mole of Al₂(CO₃)₃ decomposed to produce 3 moles of CO₂.

Finally, we shall determine the number of mole of CO₂ produced from the decomposition of 10 moles of Al₂(CO₃)₃. This can be obtained as follow:

From the balanced equation above,

1 mole of Al₂(CO₃)₃ decomposed to produce 3 moles of CO₂.

Therefore, 10 moles of Al₂(CO₃)₃ will decompose to produce = 3 × 10 = 30 moles of CO₂.

Thus, 30 moles of CO₂ were obtained from the reaction.

30 moles of CO₂ will be produced by the decomposition of 10 moles of  \(\rm Al_2(CO_3)_3\).

Carbon dioxide is a gas made up of two elements, carbon, and oxygen.

It is the gas that is used by plants to make their food.

The % of this gas on Earth is 0.03%

The balanced equation is

\(\rm Al_2(CO_3)_3 \longrightarrow Al_2O_3 + 3CO_2\)

1 mole of \(\rm Al_2(CO_3)_3\) decomposes to produce 3 moles of CO₂.

If 1 mole of \(\rm Al_2(CO_3)_3\) produce 3 moles of CO₂, then decomposition of 10 moles of \(\rm Al_2(CO_3)_3\) will produce

3 × 10 = 30 moles of CO₂.

Thus, 30 moles of CO₂ will be produced by the decomposition of 10 moles of  \(\rm Al_2(CO_3)_3\).

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In the Lewis structure of methanol (CH3OH), the OH group is placed on the outside because it is an important functional group that influences the chemical properties and reactivity of the molecule.

The Lewis structure is a representation of a molecule that shows the arrangement of atoms and valence electrons. In methanol, carbon (C) is the central atom bonded to three hydrogen (H) atoms and one oxygen (O) atom. The oxygen atom forms a single bond with carbon and also has two lone pairs of electrons.

The placement of the OH group (hydroxyl group) on the outside of the Lewis structure is significant because it determines the chemical behavior of methanol. The OH group consists of an oxygen atom bonded to a hydrogen atom and represents the presence of an alcohol functional group.

In organic chemistry, functional groups are specific arrangements of atoms within a molecule that give rise to characteristic chemical reactions and properties. The presence and position of functional groups can greatly influence the behavior and reactivity of a compound. In the case of methanol, the hydroxyl group provides the molecule with its characteristic properties.

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Answer:

d= 4.8g/mL

m= 19.2 g

V=m/d

V= 4 mL

The major product is 3-methyl-2-pentene and the minor product is 2-ethyl-1-butene.

The alkyl halide shown is 3-bromo-3-methyl pentane. We can see that it is a tertiary alkyl halide. The proportion of products formed during the reaction are determined by Markovnikov rule.

The two products of this reaction are; 3-methyl-2-pentene and 2-ethyl-1-butene. The major product is 3-methyl-2-pentene because it is formed from a more stable carbocation intermediate.  2-ethyl-1-butene is the minor product.

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Answer:

CO3- is an example of a polyatomic ion.

Explanation:

Answer:

28.5 moles of O2

Explanation:

The balanced chemical equation for the reaction between potassium chloride (KCl) and oxygen gas (O2) is:

2 KCl + 3 O2 → 2 KClO3

According to this equation, 2 moles of KCl react with 3 moles of O2 to produce 2 moles of potassium chlorate (KClO3).

Therefore, to determine how many moles of O2 are required to react with 19 moles of KCl, we can use the mole ratio as a conversion factor:

19 moles KCl x (3 moles O2 / 2 moles KCl) = 28.5 moles O2

So, 28.5 moles of O2 are required to react with 19 moles of KCl.

Yes, the statement is True i.e. Sodium chloride is a buffer creating an injectable solution that is isotonic.

A buffer solution, also referred to as a pH buffer or hydrogen ion buffer, is an aqueous mixture of a weak acid and its conjugate base, or vice versa. The pH scarcely changes at all when a small amount of a strong acid or basic is added to it. Buffer solutions are used in a wide range of chemical processes to keep pH values almost constant. Buffering is used by many living systems to regulate pH in the natural world. For instance, the bicarbonate buffering system regulates the pH of blood, and bicarbonate also acts as a buffer in the ocean. Because of a chemical equilibrium between the weak acid HA and its conjugate base A, buffer solutions are resistant to pH change: HA ⇌ H+ + A− According to Le Chatelier's principle, an equilibrium between a weak acid and its conjugate base shifts to the left when hydrogen ions (H+) are supplied. Because of this, despite the supply of strong acid, the concentration of hydrogen ions increases less than anticipated.

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