Thomas Cope, located in Bolton, England, is a manufac- turer of stainless steel exhaust hoods used in industrial kitchens. The firm works 20 days a month, and each employee works an average of 8 hours per day. To keep costs down, Thomas Cope employs labor with limited experience. This causes quality issues, and every day 10 percent of the production is scrapped. Each exhaust hood sells for £125. Labor is paid at £15/hour, materi- als cost per exhaust hood is £40, and overhead cost is £3,500. The firm currently has 250 employees. y by y what ty , by ued at a. Calculate the labor and multifactor productivity ratios. Eluding follow- b. To improve the firm's multifactor productivity, Thomas Cope has three choices 1) increase 20 percent sales by reducing the sales price by 10 percent, 2) improve quality by hiring skilled labor at £20 per hour resulting in no defects, or 3) reduce material costs by 10 percent. Which option has the greatest impact on
Answers
The multifactor productivity, it returns a number of £4,500,000 / £2,043,500 yielding an equivalent ratio of 2.19.
How to solvea. Labor and multifactor productivity ratios
Given information:
Days worked per month: 20 days
Hours worked per day: 8 hours
Employees: 250
Scrap rate: 10%
Selling price per exhaust hood: £125
Labor cost per hour: £15
Material cost per exhaust hood: £40
Overhead cost: £3,500
In a given month, the total amount of hours worked is computed by multiplying 20 days, 8 hours per day, and 250 employees; resulting in 40,000 hours.
The corresponding labor cost subsequently amounted to £600,000, translating into 40,000 exhaust hoods at a rate of 1 per hour. After calculating an approximate 10% scrap value, approximately 4,000 exhaust hoods were labeled as faulty and removed; thus leaving 36,000 good exhaust hoods.
This was further compounded by the total material cost totaling to £1,600,000. Lastly, after accounting for revenue, the total sum calculated was £4,500,000.
Regarding labor productivity, outputting one exhaust hood per hour, with regards to the overall input of 40,000 hours can be concluded, yielding a measure of 0.9 exhaust hoods/hour. Furthermore, when observing the multifactor productivity, relating output (total revenue) to input (total cost), yields a result of £4,500,000 / £2,203,500 which simplifies to 2.042.
Three choices must be evaluated in order to determine which will achieve the most favorable outcome:
1. Increasing sales by 20% via a reduction of 10% in the selling price, consequently setting the new selling price to £112.50. As a result, new sales would indicate 43,200 exhaust hoods, generating a total revenue of £4,860,000.
Further examination of the multifactor productivity produces a value of £4,860,000 / £2,203,500 which simplifies to 2.204.
2. Boosting quality through the hiring of skilled labor, thus increasing hourly wages from £15 to £20. With no defects present, the updated monthly labor cost reaches £800,000 - whereas the entire cost stands at £2,403,500.
Based on this procedure, however, the total revenue rises to £5,000,000.
Anchoring this to the multifactor productivity gives a value of £5,000,000 / £2,203,500, resulting in a straightforward 2.079.
3. Reduce material costs by 10%, ultimately decreasing the material cost per exhaust hood from £40 to £36.
Henceforth, this lowers the overall cost for the materials per month to £1,440,000, bringing the total cost to £2,043,500. Again referring to the multifactor productivity, it returns a number of £4,500,000 / £2,043,500 yielding an equivalent ratio of 2.19.
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A. Labor productivity ratio = 0.9 units per hour
B. Option 1 (increasing sales by reducing the sales price by 10 percent) has the greatest impact on the multifactor productivity measure, with a new multifactor productivity ratio of 0.0153 units per pound
How did we get these values?a.
Labor hours worked per month = 250 employees x 8 hours per day x 20 days per month = 40,000 hours
Units produced per month = (0.9 x 250 employees) x 8 hours per day x 20 days per month = 36,000 units
Labor productivity ratio = 36,000 units / 40,000 labor hours = 0.9 units per hour
Determining the multifactor productivity ratio:
Cost of labor per month = 250 employees x 8 hours per day x 20 days per month x £15 per hour = £1,800,000
Cost of materials per month = 36,000 units x £40 per unit = £1,440,000
Cost of labor and materials per month = £1,800,000 + £1,440,000 + £3,500 = £3,243,500
Multifactor productivity ratio = 36,000 units / £3,243,500 = 0.0111 units per pound
b.
To ascertain which option has the greatest impact on multifactor productivity, consider the new multifactor productivity ratios for each option.
Option 1: Increase sales by 20 percent by reducing sales price by 10 percent
New sales price per unit = £125 x 0.9 = £112.50
New number of units sold per month = 36,000 x 1.2 = 43,200 units
New revenue per month = £112.50 x 43,200 = £4,860,000
New multifactor productivity ratio = 43,200 units / (£1,800,000 x 0.9 + £1,440,000 x 0.9 x 0.9 + £3,500) = 0.0153 units per pound
Option 2: Improve quality by hiring skilled labor at £20 per hour resulting in no defects
New labor cost per month = 250 employees x 8 hours per day x 20 days per month x £20 per hour = £8,000,000
New number of units produced per month = 250 employees x 8 hours per day x 20 days per month x 0.1 = 4,000 units scrapped per month
New number of units sold per month = 36,000 - 4,000 = 32,000 units
New revenue per month = £125 x 32,000 = £4,000,000
New multifactor productivity ratio = 32,000 units / (£8,000,000 + £1,440,000 + £3,500) = 0.0039 units per pound
Option 3: Reduce material costs by 10 percent
New material cost per unit = £40 x 0.9 = £36
New number of units produced per month = 36,000
New revenue per month = £125 x 36,000 = £4,500,000
New multifactor productivity ratio = 36,000 units / (£1,800,000 + £1,440,000 x 0.9 + £3,500) = 0.0127 units per pound
Considering these results, Option 1 (increasing sales by reducing the sales price by 10 percent) has the greatest impact on the multifactor productivity measure, with a new multifactor productivity ratio of 0.0153 units per pound when related to the current ratio of 0.0111 units per pound.
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Related Questions
Help me!!
Within the processes of a power plant, combustion product gases are available at 430 ºC. It is required to take advantage of the heat of these gases and it is proposed to size an economizer to heat pressurized water from 70ºC to 180ºC.
It is known that there is 8 kg/s of water with Cp=4260 J/kg.K. The gases have a flow of 30 kg/s and Cp=1100 J/kg.K. Calculate:
a) the heat that can be transferred from the gases to the water, in kW.
b) the outlet temperature of the combustion gases, in ºC.
b) the average logarithmic difference of temperatures of the economizer, in ºC.
c) the required heat transfer area in m2, for a counterflow configuration if the overall heat transfer coefficient is 60 W/m2 K.
d) If you plan to use a coil of tubes 4 m long and 15 cm in diameter, calculate the number of tubes needed for the economizer.
Answers
Answer: System Consists Of 1 Kg Of CO2 (Cp = 46.4 J Moll K:') Gas Initially At 1 Bar And 300K. The System Undergo
Explanation:
Request for proposal (RFP) is a type of document that contains the information and proposals mostly through the bidding process. This document is regarding the valuable assets, services, entity, commodity, etc.
Answers
Answer:
Answer to the following is as follows;
Explanation:
A request for proposal is a documentation that invites prospective contractors to submit business opportunities to an agency or corporation interested in procuring a commodities, product, or valuable resource through a bid procedure.
A request for proposal (RFP) is a commercial document that introduces a project, defines it, and invites eligible contractors to compete on its completion.
3. Of the following answers, which is NOT a way for employees to control exposure routes?
Answers
There are a lot of ways employees uses in controlling exposure routes. But when risk assessment is not be performed is not a part of the control methods.
What are the three ways to control workplace hazards?The ways to control workplace hazards are known to be means taken to ensure safety in the workplace.
The examples are:
The use a hazard control plan to know, select and implement controls. Looking into the efficiency of existing controls, and creating plans with measures to protect workers in case of emergencies and nonroutine activities, etc.Learn more about exposure routes from
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PROJECT MANAGEMENT
Activity – RENOVATING A HOME
Questions:
As a project manager, you realize there may be substantial resistance to changes brought about by this project, describe any strategy or strategies you would employ to resolve this issue. (Make mention of any group from which this resistance may originate.)
After analyzing this project what TWO (2) risks have you identified and how would you respond to these risks as the project manager?
Answers
As a project manager, I would employ the following strategy to address resistance to changes in the home renovation project:
Strategy: Effective Communication and Stakeholder Engagement
To address resistance to changes, it is crucial to establish open and transparent communication channels with all stakeholders involved in the project. This includes homeowners, contractors, architects, and any other relevant parties. By actively engaging with stakeholders and listening to their concerns, I can gain their trust and create a collaborative environment.
Firstly, I would conduct regular meetings to explain the purpose and benefits of the renovation project. This would help stakeholders understand the need for change and alleviate any uncertainties or misconceptions. Clear and concise communication is key to ensuring everyone is on the same page.
Secondly, I would encourage active participation from stakeholders, seeking their input and involvement in decision-making processes. By involving them in the planning and design stages, they will feel a sense of ownership and be more willing to embrace the changes. This approach also allows for potential conflicts or objections to be addressed early on, reducing resistance later in the project.
Additionally, I would establish a feedback mechanism to address any concerns or issues promptly. This could involve setting up a dedicated communication channel or having a designated project team member responsible for handling stakeholder queries. Regular updates on project progress and milestones would also help manage expectations and build trust.
By employing effective communication and stakeholder engagement strategies, I can minimize resistance to changes and foster a collaborative environment throughout the home renovation project.
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For this lab activity, the HousingCrunch activity in part 1 will be modified to load housing data from a CSV file instead of having the options manually added to the houseList (also known has hardcoded values). In addition to prompting the user for name and a seed value, the program should also prompt for the filename containing the housing data. The data file will contain more data fields than will be used in this application as we are only interested in the housing data stored in the 1st field of each row. The screenshot below shows a spreadsheet view of the provided CSV data with the first field of each row outlined in red.
MASH Database Spreadsheet
It will be extremely helpful to review the CSVParser Deeper Look Video and Guided Experimentation examples before starting on this activity.
NOTE: In Computer Science we teach students to begin counting at zero because zero is the first index value of arrays, strings and many other programming related things. When working with data from muggles (non-programmer folk), the first data element is often referred to as record 1 or row 1 or column A or field 1. Just open a spreadsheet and look at the column and row identifiers. As programmers it is our responsibility to be aware of this difference and make certain our programs behave correctly.
Expected Program Output (with sample user input)
Please enter your name: Luke
Please enter a seed value: 123
Please enter the filename: MASHDatabase.csv
Hello Luke,
You should buy a shack.
Expected Program Output (with sample user input)
Please enter your name: Luke
Please enter a seed value: 9853482
Please enter the filename: MASHDatabase.csv
Hello Luke,
You should buy a hotel.
Expected Program Output (with sample user input)
Please enter your name: Luke
Please enter a seed value: 123
Please enter the filename: missing.csv
Error: File does not exist.
Please enter the filename: mashdatabase.csv
Error: File does not exist.
Please enter the filename: MASHDatabase.csv
Hello Luke,
You should buy a shack.
Answers
The modified Housing Crunch program prompts the user for their name, seed value, and the filename containing housing data. It checks if the file exists, loads the data from the CSV file, determines the recommended type of housing based on the data, and displays a personalized message to the user with their name and the recommendation.
To modify the Housing Crunch activity, we need to make the program load housing data from a CSV file instead of manually adding options to the houseList. We will also prompt the user for their name, a seed value, and the filename containing the housing data.
Here is a step-by-step explanation of the expected program behavior:
1. Prompt the user to enter their name.
- Example prompt: "Please enter your name:"
2. Prompt the user to enter a seed value.
- Example prompt: "Please enter a seed value:"
3. Prompt the user to enter the filename containing the housing data.
- Example prompt: "Please enter the filename:"
4. Check if the file exists. If the file does not exist, display an error message and prompt the user again.
- Example error message: "Error: File does not exist."
5. If the file exists, load the housing data from the CSV file.
6. Process the data and extract the first field of each row, which contains the housing data we are interested in.
7. Based on the extracted housing data, determine the type of housing the user should buy.
- Example housing options: shack, apartment, house, mansion, hotel, etc.
8. Display a personalized message to the user with their name and the recommended type of housing.
- Example message: "Hello [name], you should buy a [housing type]."
9. Repeat the program for different user inputs or allow the program to exit.
Remember to handle potential errors, such as invalid user inputs, and provide appropriate error messages or instructions for the user.
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1.
Explain why an n-type semiconductor material is
electrically neutral and not negatively charged.
Answers
Answer:
It is important because the donor introduces a free electron to the conduction band while leaving behind a fixed positively charged ion, thus maintaining the overall charge neutrality.
Using p–v–T data for saturated water from the steam tables, calculate at 50°C:
(a) hg - hf.
(b) ug - uf.
(c) sg - sf.
Answers
Hg - hf: The enthalpy difference between the saturated vapor and liquid phases at 50°C is obtained from the steam tables, giving the specific enthalpy change as 2,220.5 kJ/kg.
ug - uf: The internal energy difference between the saturated vapor and liquid phases at 50°C is calculated from the steam tables, resulting in the specific internal energy change of 2,160.5 kJ/kg. sg - sf: The entropy difference between the saturated vapor and liquid phases at 50°C is determined using the steam tables, yielding the specific entropy change as 6.902 kJ/(kg·K). The difference between the specific enthalpies of the saturated vapor (hg) and liquid (hf) phases at 50°C represents the heat energy required to convert water from the liquid phase to the vapor phase at constant pressure. This value is 2,220.5 kJ/kg. The difference between the specific internal energies of the saturated vapor (ug) and liquid (uf) phases at 50°C indicates the change in internal energy during the phase transition from liquid to vapor. This value is 2,160.5 kJ/kg. The difference between the specific entropies of the saturated vapor (sg) and liquid (sf) phases at 50°C shows the change in entropy during the phase transition. This value is 6.902 kJ/(kg·K), representing the increase in disorder during the transition from liquid to vapor.
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) calculate the magnitude of the voltage drop vab when switch s1 is closed and switch s2 is open. when switch s1 is closed and switch s2 is open.
Answers
To calculate the magnitude of the voltage drop Vab, we first need to find the current flowing through the circuit when switch S1 is closed and switch S2 is open. This can be done using Ohm's Law (V = IR), where V is voltage, I is current, and R is resistance.
1. Identify the total resistance in the circuit. Since switch S2 is open, the current will only flow through the resistors connected to switch S1.
2. Apply Ohm's Law to calculate the current flowing through the circuit: I = V/R, where V is the voltage source, and R is the total resistance.
3. Calculate the voltage drop across each resistor using Ohm's Law (V = IR).
4. Determine Vab, which is the voltage drop between points A and B.
To find the magnitude of the voltage drop Vab when switch S1 is closed and switch S2 is open, you need to follow these steps: identify the total resistance in the circuit, calculate the current using Ohm's Law, find the voltage drop across each resistor, and finally determine the voltage drop between points A and B (Vab).
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When calculating the magnitude of the voltage drop (Vab) across a circuit with switch S1 closed and switch S2 open, you need to consider the circuit configuration, the resistances, and the voltage source.
To accurately answer this question, I would need specific information about the circuit components such as resistor values and the voltage source value. However, I can explain the process:
1. With switch S1 closed and switch S2 open, identify the active portion of the circuit.
2. Determine the total resistance (Rt) of the active circuit.
3. Apply Ohm's Law (V = I * R) to find the current (I) flowing through the circuit. (If the voltage source is given)
4. Calculate the voltage drop (Vab) across the desired portion of the circuit using the current and the resistance of that portion.
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No help dude that’s not even part of the question
Answers
Answer:
wat?
Explanation:
The question should be labeled in the psychology section, but what I assume the question means is some sort of paradoxical reverse psychology method of braincell loss. Even photosynthesis doesn't understand what it means. The question probably is what is the question, not that there's no help.
Hope this helps (a little)!
All of these are types of wheel alignments EXCEPT:
A) four-wheel.
B) steering angle.
C) two-wheel.
D) thrust angle.
Answers
Answer:
thrust angle
Explanation:
good luck.........
One good way to improve your gas mileage is to _____.
Answers
Warm water at a constant temperature of 60°C is kept in a concrete container of wall thickness 0.2 m, initially at 25°C. Estimate the time it will take for the outside surface temperature of the wall to begin to increase. Thermal diffusivity = 4.9 × 10–7 m2/s. Also determine the temperature at 5 cm from inside at this time.
Answers
It will take about 55,300s (or 15.4 hours) for the outside surface temperature of the wall to begin increasing.
Understanding Thermal ExpansivityUsing the formula for thermal diffusion, we can estimate the time it will take for the outside surface temperature of the wall to begin increasing.
Recall the Thermal Diffusion formula:
ΔT = (Q * r) / (4πκt)
Where:
ΔT is the change in temperature (initial temperature of the wall - temperature at which the surface begins to increase)
Q is the heat flux (in this case, the heat flow from the warm water to the wall),
r is the radius of the wall (half of the wall thickness),
κ is the thermal diffusivity, and
t is the time.
We can rearrange the formula to solve for t:
t = (ΔT * (4πκr)) / Q
Given:
Initial wall temperature (inside): Ti = 25°C
Constant temperature of warm water: Tw = 60°C
Wall thickness: d = 0.2 m
Thermal diffusivity: κ = 4.9 × 10⁻⁷ m²/s
First, let's calculate the heat flux Q:
Q = k * A * (Tw - Ti) / d
Where:
k is the thermal conductivity of concrete,
A is the surface area of the wall.
The value for k depends on the specific type of concrete being used, so we'll assume a typical value of k = 0.8 W/(m·K). Also, since we're considering the outside surface of the wall, the surface area A can be calculated as:
A = 4πr²
Where r is the radius of the wall.
Now we can proceed with the calculations:
1. Calculate the radius of the wall:
r = d / 2 = 0.2 m / 2 = 0.1 m
2. Calculate the surface area of the wall:
A = 4π * (0.1 m)² = 0.126 m²
3. Calculate the heat flux Q:
Q = (0.8 W/(m·K)) * 0.126 m² * (60°C - 25°C) / 0.2 m ≈ 6.3 W
4. Calculate the change in temperature ΔT:
ΔT = Tw - Ti = 60°C - 25°C = 35°C
5. Calculate the time t:
t = (ΔT * (4πκr)) / Q
= (35°C * (4π * (4.9 × 10⁻⁷ m²/s) * 0.1 m)) / 6.3 W
≈ 5.53 × 10⁴ s
Therefore, it will take approximately 55,300 seconds (or about 15.4 hours) for the outside surface temperature of the wall to begin increasing.
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Which of the following lists, among other things, the vehicle identification, the customer's concern or complaint, and costs for parts? A. Repair order B. Owner's manual C. Comeback report D. Service manual
Answers
Answer:
I think it is D.service manual
Explanation:
Because it is the vehicle identification
Each of the five connected particles has a mass of 0.6 kg, with G as the center of mass of the system. At a certain instant the angular momentum of the system about G is 1.20k , and the x- and y-components of the velocity of G are 3 m/s and 4 m/s, respectively. Calculate the angular mom
Answers
The angular momentum of the system about G is 1.49k
To calculate the angular momentum of the system about the center of mass G, we can use the formula:
L = Iω,
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
Given that the mass of each particle is 0.6 kg and there are five particles, the total mass of the system is:
m_total = 5 × 0.6 kg = 3 kg.
The center of mass G has an x-component velocity of 3 m/s and a y-component velocity of 4 m/s.
Since the system is in motion, the angular velocity can be calculated as:
ω = v_perpendicular / r,
where v_perpendicular is the component of the velocity perpendicular to the position vector r.
Let's assume the particles are arranged in a regular pentagon, with G at the center.
The distance from each particle to G can be calculated using basic trigonometry:
r = (side length) / (2sin(π/5)),
where the side length can be found using the formula for the circumference of a regular polygon:
C = 2πr,
where C is the circumference.
Given that the angular momentum about G is 1.20k, the moment of inertia can be calculated using the equation:
L = Iω.
Rearranging the equation, we have:
I = L / ω.
Finally, we can substitute the values into the formulas and calculate the angular momentum:
Calculate the side length of the regular pentagon:
C = 2πr,
r = C / (2π),
r = (3 × 5) / (2π) = 7.64 m.
Calculate the angular velocity:
v_perpendicular = \(\sqrt{(v_x^2 + v_y^2)}\)
v_perpendicular = (\(\sqrt{3^{2} + 4^{2}}\)) = 5 m/s,
ω = v_perpendicular / r,
ω = 5 / 7.64 rad/s.
Calculate the moment of inertia:
I = L / ω,
I = 1.20k / (5 / 7.64) = 1.49k.
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Tech a says that mass airflow sensors determine mass airflow based on engine speed and manifold pressure. tech b says that some airflow sensors use a hot wire to determine mass airflow. who is correct
Answers
Since Tech B says that some airflow sensors use a hot wire to determine mass airflow he is the only one that is correct.
How does a mass airflow sensor work?An MAF is one that consist of two sensing wires. One is known to be heated by the use of electrical current, while the other is not.
There are different kinds of wires for different kinds of purposes.
Tech A saying that mass airflow sensors determine mass airflow based on engine speed and manifold pressure is incorrect because that is not the role of the mass airflow sensors.
l
As air flows across the heated wire, it cools down. Hence, Since Tech B says that some airflow sensors use a hot wire to determine mass airflow he is the only one that is correct.
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what is most delicious fod in the philippines?
Answers
Answer:
Well there are a lot of delicious food in the philppines but my most favorite is the Lechon, Adobo, Sisig, Chicken Curry, Crispy pata and Sinigang
A helical compression spring is wound using 0. 4-in diameter music wire. The spring has an outside diameter of 4. 7-in with squared and ground ends, and 9. 0 total coils. The spring has a free length of 11. 5-in. For this problem, you have to calculate the following, and write it down in your procedure:
The spring scale/rate (k)
The solid length (Ls)
The yield load (Fy)
The maximum shear stress generated once the solid length is reached (τmax)
Answers
The values for the shear modulus of the material (G) and the spring scale/rate (k), we can't accurately calculate the spring scale/rate (k), yield load (Fy), and maximum shear stress (τmax).
To calculate the spring scale/rate (k), solid length (Ls), yield load (Fy), and maximum shear stress (τmax), you'll need to use the following formulas: Spring scale/rate (k):The spring scale/rate represents the amount of force required to compress or extend the spring by a certain distance. It is calculated using the formula:k = (Gd^4) / (8D^3n)
Where: G is the shear modulus of the material, d is the wire diameter, D is the mean coil diameter (outside diameter minus wire diameter), n is the total number of coils
Solid length (Ls):The solid length of the spring is the length of the spring when it is completely compressed. It can be calculated using the formula:Ls = (n - 1) * d,Where: n is the total number of coils, d is the wire diameter,Calculate the yield load (Fy),Fy = k * (Ls - Lo),Since we don't have the spring scale/rate (k), we can't calculate the yield load accurately without this information. Calculate the maximum shear stress (τmax),τmax = (16Fy) / (πd^3) Since we don't have the yield load (Fy), we can't calculate the maximum shear stress accurately without this information.
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Determine whether or not it is possible to cold work steel so as to give a minimum Brinell hardness of 225 and at the same time have a ductility of at least 12%EL. Justify your decision
Answers
Answer:
First we determine the tensile strength using the equation;
Tₓ (MPa) = 3.45 × HB
{ Tₓ is tensile strength, HB is Brinell hardness = 225 }
therefore
Tₓ = 3.45 × 225
Tₓ = 775 Mpa
From Conclusions, It is stated that in order to achieve a tensile strength of 775 MPa for a steel, the percentage of the cold work should be 10
When the percentage of cold work for steel is up to 10,the ductility is 16% EL.
And 16% EL is greater than 12% EL
Therefore, it is possible to cold work steel to a given minimum Brinell hardness of 225 and at the same time a ductility of at least 12% EL
Participating in extracurricular activities in high school helps:
Answers
Answer:
Develop social skills
Explanation:
Answer:
strengthen your college applications
Explanation:
what electronic component is generally used to change the ac voltage into dc voltage in large dc motor controllers?
Answers
SCR because it can be controlled with reference to the point in the cycle at which it will turn on.
What failure(s) would you suspect if the output of a 3-input NAND gate stays HIGH no matter what the inputs are
Answers
Answer:A 4-input NAND gate is normally high. It can only go low when all four of the inputs have a logical high on them. Assuming the circuit should see a condition where all four inputs go high, then a constant high output indicates a fault does exist.The first step in troubleshooting this failure is to verify the circuit, under normal operation should be seeing a condition where all four inputs do go high. It is completely possible that the circuit is working properly and the condition you were expecting simply does not occur. Verifying what your inputs should be allow you to confirm whether a failure exists in reality.Second, you should verify that the logic probe, multi-meter, oscilloscope, logic analyzer, or monitoring circuit you are using to test circuit outputs is working properly. This is easiest done by touching the probe of the monitoring device to another output you should see changing states. In one system I once had to trouble-shoot, the device had a built-in monitoring circuit and the failure was actually in the monitoring circuit rather than in the main circuit. Once you have confirmed that your test equipment is working properly, you can begin testing the actual circuit to troubleshoot the failure.Given that the circuit should be seeing periods where the gate should go low and that your test equipment is working properly, then a constant high output on this gate means either the output of the gate is open (assuming their is a tie-up resistor somewhere on the output line) or at least one of the inputs is being held low. A constant low input could be a failed gate driving one of the inputs, a short to ground on the circuit board trace connected to the constant low input, or a tie-up resistor on the input that has opened (Technically, this last cause creates a floating input which could intermittently be seen as either a high or low, but in my experience is invariably seen as a low.) The only way to determine which fault exists is to measure the voltages on each input pin to determine which input is failing and then trace the constant low back to its source.729 viewsView 1 upvote1Add a comment...Sponsored by Purdue University OnlinePurdue's 100% Online Master's Now Accepting Applications.Earn an online MS in Electrical and Computer Engineering degree in 12-24 months. View curriculum guide.Learn MoreLoring Chien, Electrical Engineer for 45 years & IEEE Sr. Life memberAnswered Jul 2, 2020
Explanation:
what is difference between computer science engineering management and computer science engineering systems?
Answers
Answer:
A CS degree focuses on sequential programming and software design while a computer systems engineering degree divides the focus evenly between high-level and low-level programming.
Both are correlated to technology which makes it hard for the students to choose the best suitable course.
Explanation:
SOURCE: www.computersciencedegree.hub
what type of nuclear decay produces energy instead of a particle?
Answers
The type of nuclear decay that produces energy instead of a particle is nuclear fusion.
Nuclear fusion is a process in which two atomic nuclei join together to form a larger nucleus, releasing a significant amount of energy in the process. The energy produced is much greater than that produced by nuclear fission, which is another type of nuclear decay that involves the splitting of an atomic nucleus into smaller fragments. Nuclear decay is a process of spontaneous transformation of an unstable atomic nucleus to a more stable configuration accompanied by the release of energy or the emission of subatomic particles. There are several types of nuclear decay such as alpha decay, beta decay, and gamma decay. This question is concerned with the type of nuclear decay that produces energy instead of a particle. Nuclear fusion is a type of nuclear reaction that involves the merging of two atomic nuclei to form a single, more massive nucleus. During the process, a significant amount of energy is released in the form of light, heat, and radiation. This energy is the result of the conversion of a small portion of the mass of the atomic nuclei into energy, as predicted by Albert Einstein's famous equation, E = mc². Nuclear fusion is the energy source of stars like the Sun and other main-sequence stars. It is also being developed as a potential source of energy on Earth, through experiments like the International Thermonuclear Experimental Reactor (ITER) project, which aims to harness nuclear fusion to produce clean and sustainable energy.
In conclusion, the type of nuclear decay that produces energy instead of a particle is nuclear fusion. It is a process in which two atomic nuclei join together to form a larger nucleus, releasing a significant amount of energy in the process. Nuclear fusion is the energy source of stars like the Sun and other main-sequence stars and is being developed as a potential source of energy on Earth.
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A plant might be emitting some dangerous pollutants that are environmentally harmful, but completely eliminating them would be so expensive that the plant would have to close, throwing many local inhabitants out of work. Assuming there is an obligation both to preserve jobs and to protect the environment. What is the best technique that should be used to resolve this problem?
Select one:
a. The convergence and divergence techniques
b. The Utilitarian approach
c. The creative middle way
d. The line drawing technique
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Answer: c. The creative middle way
Explanation:
As there is both an obligation to preserve jobs and to protect the environment, a creative middle way which involves compromise would be most effective.
The company involved should process and remove the worst pollutants alone while leaving others so that the process will not be so expensive that they have to close down.
They will do this till a better and more environmentally beneficial solution can be found at which point they can then clean up the previous pollutants with the hope that they have not irrecoverably damaged the environment.
The three balls each weigh 0.5 lb and have a coefficient of restitution of e = 0.85. (Figure 1) If ball A is released from rest and strikes ball B and then ball B strikes ball C, determine the velocity of each ball after the second collision has occurred. The balls slide without friction. Assume rightward direction is positive. Express your answers using three significant figures separated by commas.
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To determine the velocity of each ball after the second collision has occurred, we'll first analyze the two collisions separately using the conservation of momentum and the given coefficient of restitution (e = 0.85). The masses of the balls are the same (0.5 lb), so we'll use m for their masses. Let's denote the velocities after each collision as vA1, vB1 for the first collision, and vA2, vB2, vC2 for the second collision.
1. Collision between ball A and ball B:
Before the collision:
- Ball A has an initial velocity (vA0) and ball B is at rest (vB0 = 0).
Using the conservation of momentum: m*vA0 = m*vA1 + m*vB1
Coefficient of restitution equation: e = (vB1 - vA1) / (vA0 - 0)
Solve these equations for vA1 and vB1.
2. Collision between ball B and ball C:
Before the collision:
- Ball B has velocity vB1 (calculated earlier) and ball C is at rest (vC0 = 0).
Using the conservation of momentum: m*vB1 = m*vB2 + m*vC2
Coefficient of restitution equation: e = (vC2 - vB2) / (vB1 - 0)
Solve these equations for vB2 and vC2.
3. Combine the results:
After both collisions, ball A will have a velocity of vA1, ball B will have a velocity of vB2, and ball C will have a velocity of vC2. Express your final answer with three significant figures separated by commas.
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How do you write a method statement for: 1. Site Setup and Temporary works in construction?
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A method statement for site setup and temporary works in construction should include the following steps:
1. Identify the scope of work and establish the project requirements for site setup and temporary works. This includes the location, size, and nature of the project, as well as any specific regulatory or safety requirements.
2. Develop a detailed plan for site setup and temporary works, including timelines, resources, and responsibilities. This should include a list of all temporary works required, such as access roads, fencing, and scaffolding.
3. Identify potential hazards and risks associated with site setup and temporary works, and develop a risk assessment and mitigation plan. This should include measures to ensure the safety of workers and the public, as well as measures to protect the environment.
4. Obtain all necessary permits and approvals, including building permits, environmental permits, and safety certifications.
5. Develop a site-specific safety plan and ensure all workers are properly trained and equipped to carry out the work safely. This should include safety procedures for working at heights, using heavy equipment, and handling hazardous materials.
6. Monitor the progress of site setup and temporary works, and make adjustments as necessary to ensure the work is completed on time, within budget, and to the required quality standards.
7. Conduct regular inspections and audits to ensure that all site setup and temporary works are in compliance with regulatory and safety requirements.
8. Document all site setup and temporary works activities, including any incidents or accidents that occur, and use this information to improve future projects.
Overall, the method statement for site setup and temporary works in construction should be a detailed plan that outlines all the necessary steps, resources, and safety measures required to ensure the successful completion of the project. It should be regularly reviewed and updated as necessary to ensure that the work is carried out safely and efficiently.
Refrigerant 134a at p1 = 30 lbf/in2, T1 = 40oF enters a compressor operating at steady state with a mass flow rate of 200 lb/h and exits as saturated vapor at p2 = 160 lbf/in2. Heat transfer occurs from the compressor to its surroundings, which are at T0 = 40oF. Changes in kinetic and potential energy can be ignored. The power input to the compressor is 2 hp. Determine the heat transfer rate for the compressor, in Btu/hr, and the entropy production rate for the compressor, in Btu/hr·oR.
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Answer:
a) \(\mathbf{Q_c = -3730.8684 \ Btu/hr}\)
b) \(\mathbf{\sigma _c = 4.3067 \ Btu/hr ^0R}\)
Explanation:
From the properties of Super-heated Refrigerant 134a Vapor at \(T_1 = 40^0 F\), \(P_1 = 30 \ lbf/in^2\) ; we obtain the following properties for specific enthalpy and specific entropy.
So; specific enthalpy \(h_1 = 109.12 \ Btu/lb\)
specific entropy \(s_1 = 0.2315 \ Btu/lb.^0R\)
Also; from the properties of saturated Refrigerant 134 a vapor (liquid - vapor). pressure table at \(P_2 = 160 \ lbf/in^2\) ; we obtain the following properties:
\(h_2 = 115.91 \ Btu/lb\\\\ s_2 = 0.2157 \ Btu/lb.^0R\)
Given that the power input to the compressor is 2 hp;
Then converting to Btu/hr ;we known that since 1 hp = 2544.4342 Btu/hr
2 hp = 2 × 2544.4342 Btu/hr
2 hp = 5088.8684 Btu/hr
The steady state energy for a compressor can be expressed by the formula:
\(0 = Q_c -W_c+m((h_1-h_e) + \dfrac{v_i^2-v_e^2}{2}+g(\bar \omega_i - \bar \omega_e)\)
By neglecting kinetic and potential energy effects; we have:
\(0 = Q_c -W_c+m(h_1-h_2) \\ \\ Q_c = -W_c+m(h_2-h_1)\)
\(Q_c = -5088.8684 \ Btu/hr +200 \ lb/hr( 115.91 -109.12) Btu/lb \\ \\\)
\(\mathbf{Q_c = -3730.8684 \ Btu/hr}\)
b) To determine the entropy generation; we employ the formula:
\(\dfrac{dS}{dt} =\dfrac{Qc}{T}+ m( s_1 -s_2) + \sigma _c\)
In a steady state condition \(\dfrac{dS}{dt} =0\)
Hence;
\(0=\dfrac{Qc}{T}+ m( s_1 -s_2) + \sigma _c\)
\(\sigma _c = m( s_1 -s_2) - \dfrac{Qc}{T}\)
\(\sigma _c = [200 \ lb/hr (0.2157 -0.2315) \ Btu/lb .^0R - \dfrac{(-3730.8684 \ Btu/hr)}{(40^0 + 459.67^0)^0R}]\)
\(\sigma _c = [(-3.16 ) \ Btu/hr .^0R + (7.4667 ) Btu/hr ^0R}]\)
\(\mathbf{\sigma _c = 4.3067 \ Btu/hr ^0R}\)
Draw the ipo chart for a program that reads a number from the user and display the square of that number ???Anyone please
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Answer:
See attachment for chart
Explanation:
The IPO chart implements he following algorithm
The expressions in bracket are typical examples
Input
Input Number (5, 4.2 or -1.2) --- This will be passed to the Processing module
Processing
Assign variable to the input number (x)
Calculate the square (x = 5 * 5)
Display the result (25) ----> This will be passed to the output module
Output
Display 25
what kind of heavy duty toggle switch should be used when adding to power wire for carf audio amplifier
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Again, the majority of automotive audio amplifiers should be able to be controlled by a switch certified at 10 amps or over.
What functions do amplifiers carry out?An amplifier is a piece of electrical equipment that increases the voltage, current, or amplitude of a signal. Amplifiers are used in wireless communications, broadcast, and other audio equipment. They can be categorized as either power amplifiers or sluggish amplifiers.
Do power-efficient amplifiers sound better?Yes, speakers do play louder & clearer when the wattage is higher (watts). However, little changes in power don't result in a discernible difference in the sound. To noticeably hear a change, the wattage would have to be doubled (a 3dB increase).
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Poly(cis-1,4-isoprene), or natural rubber (NR), has a tendency crystallize. The Tm of this polymer is slightly below room temperature, although lightly-crosslinked NR can partially crystallize at room temperature when stretched. Apparently, Tm is elevated upon stretching which allows for crystallization above the Tm of the unstretched polymer. Explain.
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Answer:
Explanation:
Crystalline melting temperature (Tm) is termed as the temperature required for a crystalline polymer to change to a fluid or glasslike crystalline spaces of a semi-crystalline polymer liquefy (expanded sub-atomic movement).
Crystallization of polymers is an interaction related with incomplete arrangement of their atomic and molecular chains. These chains crease together and structure requested districts called lamellae, which form bigger spheroidal designs named spherulites. Polymers can solidify after cooling from melting, mechanical extending, or dissolvable dissipation. Crystallization influences the optical, mechanical, and synthetic chemical properties of the polymer.
For a crystalline polymer, a required polymer chain is present in or goes along a few crystalline and amorphous zones. The crystalline zones are comprised of intermolecular & intramolecular arrangements or deliberate and thus firmly stuffed plan of atoms or chain fragments, and an absence of it brings about the development of amorphous zones.
The mechanical property boundary, for example, shear modulus expansions in the temperature of perception for polymer material framework.
The temperature reaction of direct linear polymers might be seen as partitioned into three particularly separate fragments:
1. Above Tm: The polymer stays as fluid whose consistency & viscosity would rely upon atomic molecular weight and temperature.
2. Between Tm and Tg: This area may go between close to 100% crystalline & 100% amorphous chain atomic bunches relying upon the polymer underlying consistency. The amorphous part carries on similar to supercooled fluid in this section. The generally actual conduct of the polymer in this moderate portion is similar to an elastic rubber.
3.Below Tg: The polymer material saw as glass is hard and inflexible, showing and emanating a predetermined coefficient of thermal extension. The glass is more like a crystalline strong than the fluid in personal conduct standard regarding mechanical property boundaries. In regard to the molecular atomic request, in any case, the glass all the more intently takes after the fluid. There is little contrast between the direct linear and cross-connected polymer beneath Tg.