Three set of single-phase transformers, 20 kVA, 2300/230 V, 50 Hz are connected to form a threephase, 3984/230 V, transformer bank. The equivalent impedance of each transformer referred to its low voltage side is (0.0012 + j0.024) . The three- phase transformer bank supplies a load of 54 KVA at a power factor of 0.85 lagging at rated voltage by means of a common three-phase load impedance with (0.09 + j0.01) per phase. Compute the following: i) A schematic diagram showing the transformer connection. ii) The sending end voltage of the three-phase transformer. iii) The voltage regulation.
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Three single-phase transformers having a rating of 20 kVA, 2300/230 V, 50 Hz are used to create a three-phase transformer bank.
The three-phase transformer bank is capable of providing a voltage of 3984/230 V. Each transformer's equivalent impedance referred to its low voltage side is (0.0012 + j0.024).The transformer connection is shown below: \(Y-\Delta\) Connection Method:ii) Calculation of Sending-End Voltage of Transformer: The sending-end voltage of the three-phase transformer bank is given as below:The voltage of the load is 230 V.The power rating of the load is 54 KVA.The power factor of the load is 0.85 (lag).
The total load on the three-phase system is given by P = 3 × V LIL cos φor54 × 10³ = 3 × 230 × I × 0.85orI = 120.76 AThe complex power of the load is given byS = P + jQ= 54 × 10³ + j × 120.76 × 230= (54 + j32.8) × 10³ VAThe equivalent impedance of the load is given as \((0.09+j0.01)\) per phase.
Hence, the impedance of the entire load would be \(3 \times (0.09+j0.01)\).Z L = \(0.09+j0.01\)R L = 0.09 Ω andX L = 0.01 ΩLet the sending-end voltage be V S.
Then the current flowing through the system can be calculated using the expression, V S = V L + IZ LorV S = V L + I(R L + jX L)orI = (V S - V L)/Z L = (V S - 230)/\((0.09+j0.01)\)Substituting the value of I in the equation, S = P + jQ and V L = 230, we have(54 + j32.8) × 10³ = \(3 \times\) (V S - 230) × [(0.09+j0.01)]\(\Rightarrow\) (54 + j32.8) × 10³ = \(3 \times\) (V S - 230) × (0.09 + j0.01)\(\Rightarrow\) (54 + j32.8) × 10³ = \(3 \times\) (V S × 0.09 - 20.7 + jV S × 0.01 - j46)\(\Rightarrow\) (54 + j32.8) × 10³ = (0.27 V S - 20.7 + j0.03 V S - j46)\(\Rightarrow\) (54 + j32.8) × 10³ = (0.27 V S - 20.7 - j46 + j0.03 V S)\(\Rightarrow\) (54 + j32.8) × 10³ = (0.27 V S - 20.7) + (0.03 V S + j46)\(\Rightarrow\) Real Part: 54 × 10³ = 0.27 V S - 20.7
Imaginary Part: j32.8 × 10³ = 0.03 V S + j46 × 10³Solving the above equations, we get,Real Part: \(V_S = 3947.9V\)Imaginary Part: \(V_S = 183.2V\).
Thus, the sending-end voltage of the three-phase transformer is given as V S = 3948 ∠ 2.64°.iii) Voltage Regulation Calculation:Voltage regulation, which is the difference between the voltage at the sending-end and the voltage at the receiving-end, is given by,% Voltage Regulation = [(V S - V R ) / V R ] × 100 %The voltage regulation can be calculated using the following formula:% Voltage Regulation = [(V S - V R ) / V R ] × 100 %.
Where, V R is the voltage at the load or receiving-end .The equivalent impedance of each transformer referred to its low voltage side is \((0.0012+j0.024)\).Hence, the per-unit equivalent impedance of the transformer referred to its low voltage side is,Z P.U = \(\frac{Z}{(V_L)^2/20}\) = \(\frac{(0.0012+j0.024)}{(230)^2/20}\) = 0.0003 + j0.0059. The per-unit equivalent impedance of the transformer referred to the high voltage side is given as \(Z_P.U'\).
Therefore,Z P.U' = \(Z_P.U ×\) (3984 / 230)²= 0.0501 + j0.9772Hence, the voltage drop in the transformer isV R = \(I_L × Z_P.U'\) = \((120.76 × \sqrt{3}) × (0.0501+j0.9772)\) = 66.66 + j 1300.73The voltage regulation is given by,% Voltage Regulation = [(V S - V R ) / V R ] × 100 %Substituting the value of V S and V R in the equation, we have,% Voltage Regulation = [(3948 ∠ 2.64°) - (66.66 + j1300.73)] / (66.66 + j1300.73) × 100 %= 98.23%The voltage regulation is 98.23%.
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Related Questions
this is it dont anwser this is for my other account
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Answer:
thanks for the poiunts
Explanation:
How do i untange my headphone cords? If you give me a good answer i will mark u brainliest
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Answer:
scissors best way 100%
Explanation:
Which of these methods is likely to make a product design more suitable for mass production?
OA. using standardized parts
OB. using highly customized parts
c. using parts that can fit only in one product
D. using parts that have a single function
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Answer:
using standardized parts
Explanation:
This agency develops standards for pressure vessels and pressure relief valves, as well as the design, welding, and materials that may be used in pipeline construction.
Select one:
a. American Petroleum Institute
b. American Society of Mechanical Engineers
c. American Gas Association
d. National Fire Protection Association
Answers
Answer:
b. American Society of Mechanical Engineers
Explanation:
The "American Society of Mechanical Engineers" (ASME) is an organization that ensures the development of engineering fields. It is an accreditation organization that ensures parties will comply to the ASME Boiler and Pressure Vessel Code or BPVC.
The BPVC is a standard being followed by ASME in order to regulate the different pressure vessels and valves. Such standard prevents boiler explosion incidents.
Calculate the areas under the stress-strain curve (toughness) for the materials shown in Fig. below, (a) plot them as a
function of temperature, and describe your observations. (b) As expected, the elastic modulus of the polymer decreases as
temperature increases. Using the stress-strain curves in the figure, make a plot of the modulus of elasticity versus the
temperature. Comment on the shape of the curve.
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what characteristics differentiate unconventional hydraulic fracturing wells from conventional oil wells?
Answers
The difference between unconventional hydraulic fracturing wells from conventional oil wells is pumpjacks generate pressure when atmospheric pressure drops.
What are unconventional hydraulic fracturing wells ?
A method for producing unconventional gas is hydraulic fracturing. Only a unique recovery procedure and technology, like hydraulic fracturing, or other specialized stimulation techniques can be used to cost-effectively generate gas from unconventional reservoirs.
Therefore, pumpjacks generate pressure when atmospheric pressure drops. The wells are horizontal and extend from a vertical well shaft's base. Additional extraction is possible thanks to sand, water, and chemicals.
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How would you expect an increase in the austenite grain size to affect the hardenability of a steel alloy? Why?
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Answer:
The hardenability increases with increasing austenite grain size, because the grain boundary area is decreasing. This means that the sites for the nucleation of ferrite and pearlite are being reduced in number, with the result that these transformations are slowed down, and the hardenability is therefore increased.
____________ motors are used when very small starting and running torques are required. group of answer choices split-phase 3-phase ecm shaded pole
Answers
Shaded pole motors are used when very small starting and running torques are required.
Shaded pole motors are a type of single-phase induction motors commonly used in applications where low starting and running torques are sufficient. They are simple and inexpensive motors that find applications in various small appliances, such as fans, refrigerators, and small pumps.
The operation of shaded pole motors relies on the principle of induction. They have a stator with salient poles, and each pole has a portion called a shading coil that is made of a short-circuited copper or aluminum conductor. When an AC voltage is applied to the motor, a rotating magnetic field is created, but due to the presence of the shading coil, there is a phase shift in the magnetic field, resulting in an uneven distribution of magnetic flux. This imbalance creates a small starting torque, and once the motor is running, the shaded pole generates a rotating magnetic field that keeps the motor in motion. However, shaded pole motors generally have low efficiency and limited power output, which restricts their use to applications with low torque requirements.
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QUESTION 4
D
Which of the four strokes of a four-cycle internal combustion engine is the shortest in crankshaft duration?
O A.Power
O b.Exhaust
O c. Intake
O d. Compression
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Answer:
The answer will be B i hope this helps
state the parallelogram law of forces
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Answer:
The law of parallelogram of forces states that if two vectors acting on a particle at the same time be represented in magnitude and direction by the two adjacent sides of a parallelogram drawn from a point their resultant vector is represented in magnitude and direction by the diagonal of the parallelogram drawn from .
Compare and contrast the roles of agricultural and environmental scientists.
Answers
Answer:
HUHHHHHH BE SPECIFIC CHILE
Explanation:
ERM IRDK SORRY BOUT THAT
perception distance plus reaction distance plus braking distance is called:
Answers
Perception distance plus reaction distance plus braking distance is called the total stopping distance.
It is the total distance a vehicle travels from the moment a driver perceives a hazard to the point where the vehicle comes to a complete stop.
1. Perception distance: This is the distance traveled by a vehicle from the moment a driver sees a hazard until they recognize the need to apply the brakes. It depends on factors such as driver alertness, visibility conditions, and speed.
2. Reaction distance: Once the driver perceives the hazard and recognizes the need to brake, there is a delay in reacting and actually applying the brakes. Reaction distance is the distance covered during this reaction time. It depends on factors like driver reaction time and vehicle speed.
3. Braking distance: After the driver applies the brakes, the vehicle still needs to travel a certain distance to come to a complete stop. Braking distance is influenced by factors such as vehicle speed, road conditions, tire grip, and braking system effectiveness.
Combining these three components gives us the total stopping distance, which is essential for understanding and maintaining safe driving distances and speeds.
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Consider this example of a recurrence relation. A police officer needs to patrol a gated community. He would like to enter the gate, cruise all the streets exactly once, and then leave by the same gate. What information would you need to determine a Euler circuit and a Hamilton circuit
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Answer:
the police officer cruise each streets precisely once and he enters and exit with the same gate.
Explanation:
NB: kindly check below for the attached picture.
The term ''Euler circuit'' can simply be defined as the graph that shows the edge of K once in a finite way by starting and putting a stop to it at the same vertex.
The term "Hamiltonian Circuit" is also known as the Hamiltonian cycle which is all about a one time visit to the vertex.
Here in this question, the door is the vertex and the road is the edge.
The information needed to detemine a Euler circuit and a Hamilton circuit is;
"the police officer cruise each streets precisely once and he enters and exit with the same gate."
Check attachment for each type of circuit and the differences.
the police officer cruise each streets precisely once and he enters and exit with the same gate.
which systems engineering support discipline has the goal to ensure that support considerations are an integral part of the system design requirements so that the system can be cost-effectively supported throughout its life cycle
Answers
Answer:what's the question
Explanation:
Define hermetic compressor
Answers
Answer:
Hermetic compressors are ideal for small refrigeration systems, where continuous maintenance cannot be ensured.
Because of its high dielectric strength, SF6 (sulfur hexafluoride) gas is widely used as an insulator and a dielectric in HV applications such as HV transformers, switches, circuit breakers, transmission lines, and even HV capacitors. The SF6 gas at 1 atm and at room temperature has a dielectric constant of 1.0015. The number of SF6 molecules per unit volume Ncan be found by the gas law, P= (N/NA)RT.
Required:
Calculate the electronic polarizability αeof the SF6 molecule.
Answers
Answer:
5.31 × 10⁻⁴⁰ Fm²
Explanation:
Using the Clausius-Mossotti equation
(ε - 1)/(ε + 2) = Nα/3ε₀ where ε = dielectric constant = 1.0015, ε₀ = 8.854 × 10⁻¹² F/m, N = number of molecules of SF6 per unit volume and α = electronic polarizability
So, α = (ε - 1)3ε₀/[(ε + 2)N]
Also
P = (N/NA)RT where P = pressure = 1 atm = 1.013 × 10⁵ Pa, N = number of molecules of SF6 per unit volume, NA = Avogadro's constant = 6.022 × 10²³ /mol, R = molar gas constant = 8.314 J/mol-K and T = room temperature = 25° = 273 + 25 = 293 K
So, N = PNA/RT
= 1.013 × 10⁵ Pa × 6.022 × 10²³ /mol ÷ (8.314 J/mol-K × 293 K)
= 6.100286 × 10²⁸ Pa/mol ÷ (2436.002 J/mol)
= 0.0025 × 10²⁸ molecules/m³
= 2.5 × 10²⁵ molecules/m³
So,
α = (ε - 1)3ε₀/[(ε + 2)N]
α = (1.0015 - 1)× 3 × 8.854 × 10⁻¹² F/m/[(1.0015 + 2)2.5 × 10²⁵ molecules/m³]
α = (0.0015)26.562 × 10⁻¹² F/m/[(3.0015)2.5 × 10²⁵ molecules/m³]
α = 0.039843 × 10⁻¹² F/m/[7.50375 × 10²⁵ molecules/m³]
α = 0.00531 × 10⁻³⁷ Fm²
α = 5.31 × 10⁻⁴⁰ Fm²
If a person runs a distance of 0.7 km in 3 min, what is his average speed in kilometres/hour
Answers
Answer:
14 km/hour
Explanation:
The posted speed limit is the highest speed that you are
permitted to drive unless
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Hope this helps! Please make me the brainliest, it’s not necessary but appreciated, I put a lot of effort and research into my answers. Have a good day, stay safe and stay healthy.
Answer:
d
Explanation:
the first ftir instruments used three different interferometer systems. briefly, describe how it has been possible to simplify the optical systems in more contemporary instruments
Answers
Modern equipment no longer employ white light because the IR also reaches its maximum at zero. This does away with the requirement for a white light.
What does FTIR instrumentation consist of?An ordinary FTIR spectrometer is made up of the following components: a source, an interferometer, a sample compartment, a detector, an amplifier, an converter, and a computer. Radiation from the source flows via the interferometer and the detector to reach the detector after passing through the sample.
Which is more qualitative, FTIR, or FTIR?FTIR provides quantitative and qualitative analysis for samples that are both organic and inorganic. A molecule's chemical bonds can be identified using Fourier Transform Infrared Spectroscopy (FTIR) by creating an infrared absorption spectrum.
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The * key is used for ____.
Answers
1. The only purpose of a personal fall arrest system is to
A) Keep workers from falling
B) Hoist materials
C) Avoid having to use a
net
D)All of the above
Answers
✅C) Avoid having to use a net ✅
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in a steady flow process, energy can be transferred by . multiple choice question. work only work, mass, and heat mass and heat only mass only work and heat only
Answers
In a steady flow process, energy can be transferred by work and heat only.
In a steady flow process, energy transfer occurs through work and heat. Work refers to the mechanical energy transfer due to forces acting on the system, such as work done by a pump or work done by a turbine. Heat, on the other hand, is the transfer of thermal energy between the system and its surroundings due to a temperature difference. The flow of energy in a steady flow process can be characterized by the exchange of work and heat, while mass does not directly contribute to energy transfer in this context. Therefore, the correct answer is work and heat only.
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Use the standard free energy data in the Standard State Thermodynamic Data table to determine the free energy change for each of the following reactions (in kJ/mol), which are run under standard state conditions and 25°C. Identify each as either spontaneous or nonspontaneous at these conditions.
(a)B(s) + O2(g) → BO2(g)
(b)PCl3(l) + Cl2(g) → PCl5(g)
(c) Al2O3(s) + 3 CO(g) → 2 Al(s) + 3 CO2(g)
(d) BeO(s) + H2O(l) → Be(OH)2(s)
(e) N2O(g) + O2(g) → N2O3(g)
(f) CaSO4 · 2 H2O(s) → CaSO4(s) + 2 H2O(g)
ΔG⁰298 = −1797.4 kJ/mol
ΔG⁰298 = −1321.9 kJ/mol
ΔG⁰298 = −228.6 kJ/mol
Answers
(a) The free energy change for the reaction B(s) + O2(g) → BO2(g) is 1797.4 kJ/mol, and the reaction is nonspontaneous.
(b) The free energy change for the reaction PCl3(l) + Cl2(g) → PCl5(g) is -1321.9 kJ/mol, and the reaction is spontaneous.
To determine the free energy change for each reaction, we can use the equation:
ΔG = ΣΔG⁰(products) - ΣΔG⁰(reactants)
where ΔG⁰ is the standard free energy change for each species at 25°C.
Let's calculate the free energy change for each reaction and determine if they are spontaneous or nonspontaneous.
a) B(s) + O2(g) → BO2(g)
ΔG = ΔG⁰(BO2) - [ΔG⁰(B) + ΔG⁰(O2)]
ΔG = 0 - [0 + ΔG⁰(O2)]
= -ΔG⁰(O2)
= -(-1797.4 kJ/mol)
= 1797.4 kJ/mol
The free energy change for this reaction is 1797.4 kJ/mol. Since the free energy change is positive, the reaction is nonspontaneous under these conditions.
(b) PCl3(l) + Cl2(g) → PCl5(g)
ΔG = ΔG⁰(PCl5) - [ΔG⁰(PCl3) + ΔG⁰(Cl2)]
ΔG = -1321.9 kJ/mol - [0 + 0]
= -1321.9 kJ/mol
The free energy change for this reaction is -1321.9 kJ/mol. Since the free energy change is negative, the reaction is spontaneous under these conditions.
(c) Al2O3(s) + 3 CO(g) → 2 Al(s) + 3 CO2(g)
ΔG = ΔG⁰(2Al) + 3ΔG⁰(CO2) - [ΔG⁰(Al2O3) + 3ΔG⁰(CO)]
ΔG = 0 + 3(0) - [0 + 3(-228.6 kJ/mol)]
= -3(-228.6 kJ/mol)
= 685.8 kJ/mol
The free energy change for this reaction is 685.8 kJ/mol. Since the free energy change is positive, the reaction is nonspontaneous under these conditions.
(d) BeO(s) + H2O(l) → Be(OH)2(s)
ΔG = ΔG⁰(Be(OH)2) - [ΔG⁰(BeO) + ΔG⁰(H2O)]
ΔG = 0 - [0 + 0]
= 0 kJ/mol
The free energy change for this reaction is 0 kJ/mol. Since the free energy change is zero, the reaction is at equilibrium under these conditions.
(e) N2O(g) + O2(g) → N2O3(g)
ΔG = ΔG⁰(N2O3) - [ΔG⁰(N2O) + ΔG⁰(O2)]
ΔG = 0 - [0 + ΔG⁰(O2)]
= -ΔG⁰(O2)
= -(-1797.4 kJ/mol)
= 1797.4 kJ/mol
The free energy change for this reaction is 1797.4 kJ/mol. Since the free energy change is positive, the reaction is nonspontaneous under these conditions.
(f) CaSO4 · 2 H2O(s) → CaSO4(s) + 2 H2O(g)
ΔG = ΔG⁰(CaSO4)
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An athlete is holding 24 lb of weights at a height of 6 inches above the stack as shown. To lower the weights, she applies a constant force of 5 lb to the handle. Determine the velocity of the weights immediately before they hit the stack.
Answers
The velocity of the weights immediately before they hit the stack is 3.4672 ft/s
How to solve for the velocity1 Lb = 0.453 kg
24 = 24 x 0.453
= 10.872kg
Therefore the m = 10.872
g = 9.87
m1 = 10.872/9.87
m1g = 1.112
T = 5 lb
= 5 x 0.453 = 2.265kg
m1g = T + 2T
1.112a = 10.872 - 3(2.265)
a = 3.66m/s²
initial velocity = 0
6x 2.54
= 15.24x10⁻²m
v² = 0+ 2as
v = √2as
v = √2x3.66x 15.24x10⁻²
= √1.1174
= 1.0571
a meter is equal to 3.28 ft
v*m = 1.0571 * 3.28
= 3.4672 ft/s
The velocity of the weights immediately before they hit the stack is 3.4672 ft/s.
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A Newtonian liquid flows in the annular space between to fixed horizontal concentric cylinders. The radius of the inner cylinder is ri and the outer cylinder is ro. Two static pressure taps separated by a distance L along the outer pipe are connected to a manometer with reading of h. Develop an expression for the shear stress on the inner and outer cylinder walls as a function of h. Assume the flow is fully developed and laminar.
Answers
Answer:
See explaination
Explanation:
please kindly see attachment for the step by step solution of the given problem
Side or diagonal cutting pliers are used best for which of the following?
Cutting wire
Tightening electrical connectors
Stripping wire insulation
Shaping wire into a hook
Answers
For cutting wire, side or diagonal cutting pliers work best. These pliers have clean, minimally distorting jaws that are sharp and angled to cut through wire. In electrical work, they are frequently employed.
What are the purposes of diagonal side cutting pliers?To use diagonal cutting pliers correctly: for tasks involving the removal of pins, nails, and other fasteners, as well as the cutting and skinning of wires.
When cutting steel wires, which component of the pliers is used?The jaws are used to remove undesired nails and tiny needles from a surface as well as to bend, cut, and slice wires. Pliers can be used for a number of tasks depending on the length and unique layout of the jaws.
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Which type of voltage do generators produce?
Generators are essential components of electric power systems. They contain wire coils placed between the magnets. They produce a/n voltage when they spin between the poles of the magnetic field, or when magnets spin around them.
Answers
Answer:
How does electricity produce magnetism?
Explanation:
When the electricity is switched on, the electric magnets create powerful magnetic fields. Coils of wire are mounted around the shaft. As the shaft with the magnets rotates, the coils of wire are exposed to changing magnetic fields, and an electric current is generated in the wires.
Answer:
Explanation:
I am pretty sure it depends but most of the time I think they produce direct current/voltage.
What Is Soil Tunneling?
Answers
Answer:
A tunnel built in soft ground—such as clay, silt, sand, gravel or mud—requires specialized techniques compared to hard rock, to compensate for the shifting nature of the soil.
It's from web...
Soft ground tunneling describes the additional measures needed when Microtunneling through soil conditions that are vulnerable to collapse. ... This process ensures tunneling can happen effectively in soft grounds.
It's from me...
2..Three formations, each 25 m thick, overlie one another. If a constant-velocity vertical flow field is set up across the set of formations with h = 120 m at the top and h = 100 m at the bottom, calculate h at the two internal boundaries. The hydraulic conductivity of the top formation is 0.0001 m/s, the middle formation 0.0005 m/s, and the bottom formation 0.0010 m/s.
Answers
The values of h at the two internal boundaries are :
h₁ = 104.625 m h₂ = 101.55 mGiven data :
Z₁ = Z₂ = Z₃ = 25 m
h top = 120 m
h bottom = 100 m
K₁ = 0.0001 m/s
K₂ = 0.0005 m/s
K₃ = 0.0010 m/s
First step : Calculate the value of Keqwe will apply the formula below since flow is perpendicular to the bedding plane
Keq = \(\frac{Z1 + Z2 + Z3 }{\frac{Z1}{K1}+\frac{Z2}{K2} + \frac{Z3}{K3} }\) ----- ( 1 )
Insert values given above into equation 1
Therefore ; Keq = 2.307 * 10⁻⁴ m/s
Next step : determine the hydraulic gradientHydraulic gradient ( Ieq ) = head loss / length
= ( 120 - 100 ) / 3 * 25
Ieq = 0.266
Given that the flow is perpendicular to bedding plane
q1 = q2 = q3
V₁ = V₂ = V₃ = V
K₁i₁ = K₂i₂ = K₃i₃ = Keq * ieq
Hence :
V = Keq* Ieq
= 2.307 * 10⁻⁴ * 0.266
= 6.15 * 10⁻⁵ m/s .
Also;
K₁i₁ = Keq * ieq = K₂i₂ = K₃i₃
therefore :
i₁ = 0.615
i₂ = 0.123
i₃ = 0.0615
Final step : determine the value of h at the two internal boundariesPressure at point 1 ( i.e. pressure between first two formations )
h₁ = h top - i₁L₁
= 120 - 0.615 * 25
= 104.625 m
Pressure at point 2 ( i.e. pressure between the 2nd and 3rd formation )
h₂ = h₁ - i₂L₂
= 104.625 - 0.123 * 25
= 101.55 m
Therefore we can conclude that The values of h at the two internal boundaries are : h₁ = 104.625 m , h₂ = 101.55 m
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Question 40 and the next Question 41
Answers
Answer:
there's no photo? but I'm willing to help