To demonstrate the tremendous acceleration of a top fuel drag racer, you attempt to run your car into the back of a dragster that is "burning out" at the red light before the start of a race. (Burning out means spinning the tires at high speed to heat the tread and make the rubber sticky.) You drive at a constant speed of v0 toward the stopped dragster, not slowing down in the face of the imminent collision. The dragster driver sees you coming but waits until the last instant to put down the hammer, accelerating from the starting line at constant acceleration, a. Let the time at which the dragster starts to accelerate be t = 0.
(A) What is tmax, the longest time after the dragster begins to accelerate that you can possibly run into the back of the dragster if you continue at your initial velocity?

This question involves the concepts of kinetic energy, escape velocity, and rms speed.

a) The rms speed of hydrogen atom at 5800 K is "11991 m/s".

b) The escape velocity for the Sun is "6.18 x 10⁵ m/s".

a)

We will use the formula of the average kinetic energy of gas molecules to find out the rms speed of the hydrogen atom. rms speed is the root mean square speed of an atom:

\(K.E = \frac{3}{2}KT=\frac{1}{2}mv^2\\\\v=\sqrt{\frac{3KT}{m}}\)

where,

v =rms speed = ?

K = Boltzman's Constant = 1.38 x 10⁻²³ J/k

T = absolute temperature = 5800 k

m = mass of hydrogen atom = 1.67 x 10⁻²⁷ kg

Therefore,

\(v=\sqrt{\frac{3(1.38\ x\ 10^{-23}\ J/k)(5800\ k)}{1.67\ x\ 10^{-27}\ kg}}\)

v = 11991 m/s

b)

The escape velocity of the Sun is given by the following formula:

\(v_e=\sqrt{\frac{2GM}{R}}\)

where,

ve = escape velocity = ?

G = Gravitational Constant = 6.673 x 10⁻¹¹ N.m²/kg²

M = Mass of Sun = 1.99 x 10³⁰ kg

R = radius of Sun = 6.96 x 10⁸ m

Therefore,

\(v_e=\sqrt{\frac{2(6.673\ x\ 10^{-11}\ N.m^2/kg^2)(1.99\ x\ 10^{30}\ kg)}{6.96\ x\ 10^8\ m}}\)

\(v_e = 6.18\ x\ 10^5\ m/s\)

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The acceleration, in m/s² , that riders experience is 50.3 m/s²

Since the riders move in a circle, they undergo circular motion and will have a centripetal acceleration.

So, the centripetal acceleration, is given by a = v²/r where

Given that a rider in one swing is moving at 34 m/s with respect to the ground in a 46- m -diameter circle. We have that

So, substituting the values of the variables into the equation for the acceleration, we have

a = v²/r

a = (34 m/s)²/23 m

a = 1156 m²/s²/23 m

a = 50.26 m/s²

a ≅ 50.3 m/s²

So, the acceleration, in m/s² , that riders experience is 50.3 m/s²

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The formula gives the electric potential resulting from a charged object q experienced at the a point P that is r distances away.

powered by, by, or involving electricity. an electric flow. An electric heater that feels electric shock-like. a performance with energy.

Its name, "elektron," which meaning amber, is derived from this word. In tree sap, you can find amber, a golden fossilized rock. The Greeks discovered that when they rubbed silver against wool, light materials (like straw or feathers) stuck to it. The term "static" electricity refers to this type of electricity.

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Answer:

I think the distance should be given in the question because the formula for getting the

average speed= total distance/total time taken

Let the circumference of the circle be 10L.

A moves at 10L/2 = 5L per hour

B moves at 10L/5 = 2L per hour

Therefore it takes 10L/(5L+2L) = 10/7 hours

Answer: the ice cube to melt more quickly on the metal block than on the wooden block.

Explanation:

This is because Gravity exists everywhere in the universe.

This is the force of attraction which acts on all matters in the universe. Astronauts appear weightless while in orbiting the Earth because the space shuttle and the astronauts are in free fall around it.

They fall at the same rate as the space shuttle which is why the astronauts appear weightless.

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Astronauts and their spaceship are affected by Earth's gravity in space. Even though Earth's gravitational influence is weaker in orbit than on Earth's surface, they have weight. They don't feel their weight since nothing's pushing back.

Weightlessness means no weight. It's also called zero-G. Weight is the force on a stationary object in a strong gravitational field.

The sensation of weightlessness that astronauts on board the International Space Station enjoy is due to the fact that they are free falling toward the planet Earth. Because the space station and the astronauts are moving at the same rate, there is no external normal force acting upon the body in free fall to balance out the effects of the body's own weight (equal to g).

Therefore, the astronauts and their spaceship continue to have mass and are still affected by the gravitational pull of the Earth.

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It is not recommended to fire a gun straight up into the air.

When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.

Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.

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The coefficient of kinetic friction is determined as 0.75.

The coefficient of kinetic friction is calculated by applying the newton's second law of motion.

Fsinθ - Ff = ma

where;

W = mg

where;

m = W/g

m = 325/9.8

m = 33.2 kg

425 sin(35.2)   -  Ff = 33.2a

425 sin(35.2)   -  μW = 33.2a

at constant velocity, a = 0

425 sin(35.2)   -  μW= 0

μW = 244.98

μ = 244.98/W

μ = 244.98/325

μ = 0.75

Thus, the coefficient of kinetic friction is 0.75.

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Answer:

belpw

Explanation:

The distance prior to the sliding friction dispersing her energy would be:

- The distance will remain unaffected by the sliding friction i.e. 354m

As we know, When Sliding friction dissolves her energy, leading her Kinetic Energy to turn 0 on coming to the state of rest. So,

\(1/2 mv^2 - 1/2 mu^2 = -W\)            (∵ Work in -ve denotes it is done opposite to friction)

Given that,

m(mass) \(= 50 kg\)

v(velocity) \(= 30 km/hr\) or \(8.33 m/s\)

The coefficient of Kinetic Friction \(= 0.01\)

g(gravitational force) \(= 9.8 m/s^2\)

Initial Velocity(u) \(= 30\) × \(1000/3600 m/s\)

\(= 8.33 m/s\)

Now by employing the provided values,

\(F =\) μ\(mg\)

\(= (0.01) (50) (9.8)\)

\(= 4.9\)

∵ \(F = 4.9 N\)

By using the above expression, we will find the distance;

\(1/2 mv^2 - 1/2 mu^2 = -W\)

⇒ \(1/2 (50) (0)^2 - 1/2 (50) (8.33)^2 = -4.9(S)\)

⇒ \(1734.7225 = 4.9S\)

⇒ \(S = 1734.7225/4.9\)

∵ \(S = 354 m\)

Because \(1/2 mv^2 - 1/2 mu^2 = -W\)  \(= -\) μmgS

⇒ \(S = (u^2 - v^2)\)/2μ\(g\)

Thus, the distance will remain unaffected by the sliding friction i.e. 354m

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The true statements are:

Cellular respiration is a vital component of the respiratory system.

Individual cells carry out respiration.

Cellular respiration is a continuous process.

An elephant's cells undergo cellular respiration.

Every cell in the mitochondria of plants and animals engages in cellular respiration, which is the breakdown of carbohydrates in the presence of oxygen obtained by breathing to produce energy in the form of ATP.

In both plants and animals including elephants, this basic process takes place.

As waste products, the lungs expel carbon dioxide and water during this process.

This remark implies a connection between breathing and cellular respiration.

The function of cellular respiration is to get ATP-based energy for the vital tasks that live cells must do.

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Your question was incomplete, but most probably your question would be:

Which statements about cellular respiration are true? Choose more than one answer.

Breathing and cellular respiration are unrelated.

Cellular respiration is a vital component of the respiratory system.

Individual cells carry out cellular respiration.

Cellular respiration is a continuous process.

The main purpose of cellular respiration is to create new cells.

An elephant's cells undergo cellular respiration.

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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Answer: Graphite and iodine are non-metals that have lustre.

Explanation:

Graphite is a non-metal which has metallic luster. Metallic lustre is due to presence of free electrons in them, generally non metals don't exhibit this property, but iodine and graphite are non metals they exhibit metallic lustre.

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When reading the simile "Bolt runs as fast as lightning," the most appropriate visual interpretation would be that "Bolt runs very fast."

This simile compares Bolt's speed to that of lightning, which is known for its incredible swiftness. The intention is to emphasize Bolt's exceptional speed by equating it to the rapid movement of lightning.

While the simile highlights Bolt's remarkable speed, it does not specify the manner in which he runs or the impact of each step. Therefore, the options suggesting Bolt runs in a straight line, in a wavy manner, or that each step produces thunder are not directly implied by the simile itself. These additional details go beyond the comparison of speed and introduce elements that are not explicitly mentioned.

Hence, the most accurate interpretation based solely on the simile is that Bolt runs very fast, comparable to the speed of lightning.

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Answer: 20

Explanation:

Given data:

* The power of the engine is,

* The force exerted by the engine is,

Solution:

The power of the engine in terms of force and average speed is,

where v is the average speed,

Substituting the known values,

Thus, the average speed of the vehicle is 20 meters per second.

Answer:

C. amplitude = 0.10 m, wavelength = 0.60 m

Explanation:

The diagram shows an oscillating progressive wave, with its amplitude and wavelength.

Amplitude of a wave is the maximum distance covered either upward or downward.

So that,

amplitude of the wave, A = \(\frac{0.2}{2}\)

                                          = 0.1

Amplitude of the wave = 0.1 m

Wavelength in this case is the distance from crest to crest, or trough to trough of the wave.

So that,

wavelength = \(\frac{1.5}{2.5}\)

                   = 0.6

wavelength of the wave = 0.6 m

Therefore, the amplitude of the wave is 0.10 m, while the wavelength is 0.60 m.

Answer:

Archimedes' principle states that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially submerged, is equal to the weight of the fluid that the body displaces.

Answer:

12 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 7.6 kg

Distance (d) = 6 m

Velocity (v) = 5 m/s

Force (F) = 2 N

Workdone (Wd) =.?

Workdone can be defined as the product of force and distance moved in the direction of the force. Mathematically, it is expressed as:

Workdone = Force × distance

Wd = F × d

With the above formula, we can obtain the workdone as follow:

Distance (d) = 6 m

Force (F) = 2 N

Workdone (Wd) =.?

Wd = F × d

Wd = 2 × 6

Wd = 12 J

Thus, the workdone is 12 J

Answer:

B.

Explanation:

hope it helps

give me brainliest

Answer:

A.

Explanation:

because it lifts up the plane pls give me brainliest

Answer:

v = 172 km/h

Explanation:

For the first 12  hours, it traveled at an average speed of 185 km/h. Let d₁ is distance. So,

\(d_1=v_1\times t_1\\\\d_1=185\ km/h\times 12\ h\\\\d_1=2220\ km\)

For the  next 13 hours, it traveled at an average speed of 160 km/h. Let d₂ is the distance. So,

\(d_2=v_2\times t_2\\\\d_2=160\ km/h\times 13\ h\\\\d_2=2080\ km\)

Average speed = total distance/time taken

So,

\(v=\dfrac{d_1+d_2}{t_1+t_2}\\\\v=\dfrac{2220+2080}{12+13}\\\\v=172\ km/h\)

So, the average speed of the whole journey is 172 km/h.

The final velocity after 6.0 s is

1304.2 .

What is velocity?

velocityis the most fundamental quantity of physics . Work is said to be done when a force applied to an object cause a displacement of a object.

Solution -

As per the given-

Mass of runner m = 74kg

initial velocity of runner u=4.8 m/s

final velocity of runner v =0

Coefficient of friction ¥=0.7

Let's d be the distance moved by runner till the stop.

a- mechanical energy lost due to friction

As friction does negetive work causing the runner to stop.

As we know,

Mechanical energy lost= Kinetic energy of runner

Mechanical energy lost =

1/2 mv^2 = 1/2 ×74×4.8^2=852.2

Distance move by runner-

Work done by friction = mechanical energy lost

-¥×mg×d =852.2 j

-0.7×74×9.8×d = -491.2

Solving the equation we get

1304.2.

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Answer:

0.5 m/s²

Explanation:

Net force = mass × acceleration

∑F = ma

20,000 N = (40,000 kg) a

a = 0.5 m/s²

Answer:

which one will not start moving faster

Explanation:

Mass is also described by physics. If you apply the same amount of force to a small sports car and to a big garbage truck.

Answer:

Explanation:

The horizontal velocity is 1.61.

(a) The work done by the force applied by the tractor is 79,968.47 J.

(b) The work done by the frictional force on the tractor is 55,977.93 J.

(c) The total work done by  all the forces is 23,990.54 J.

The work done by the force applied by the tractor is calculated as follows;

W = Fd cosθ

W = (5000 x 20) x cos(36.9)

W = 79,968.47 J

W = Ffd cosθ

W = (3500 x 20) x cos(36.9)

W = 55,977.93 J

W(net) = work done by applied force  -  work done by friction force

W(net) = 79,968.47 J -  55,977.93 J

W(net) = 23,990.54 J

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Energy effectiveness would be a term that refers to the proportion of input power over output. Power generation, as well as simply energy utilization, is the process of reducing the amount of energy used to produce goods and services.

Considering that,

A cookie contains 54.0 kcal of energy. An athlete utilizes the 54.0 kcal inside this cookie from input energy.

The following diagram illustrates the relationship among input as well as output energy:

Efficiency = output energy / input energy...(i)

Output energy = efficiency × input energy

By using equation (i)

⇒ output energy = 0.25 × 54 kcal = 13.5 kcal.

The lifting exercise has been performed n times for the output energy.

In terms of potential energy, such output energy could be written as follows:

Mass × gravity ×height.

So, energy per repetition = mgh = 103 kg × 9.8 m/ × (2.45 × 0.1m) = 247.303 J =  0.059 kcal.

So, Count of repetitions = sim of output energy / energy per repetition..(ii)

By using equation (ii)

Count of repetitions = 13.5 kcal / 0.059 kcal =229 repetitions.  

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