To determine the viscosity of a liquid of specific gravity 0.95, you fill to a depth of 12 cm a large container that drains through a 30 cm long vertical tube attached to the bottom. The tube diameter is 2 mm, and the rate of draining is found to be 1.9 cm3 /s. What is the fluid viscosity (assume laminar flow)
Answers
Answer:
Fluid viscosity, \(\mu = 2.57 * 10^{-3} kgm^{-1}s^{-1}\)
Explanation:
Container depth, D = 12 cm = 0.12 m
Tube length, l = 30 cm = 0.3 m
Specific Gravity, \(\rho\) = 0.95
Tube diameter, d = 2 mm = 0.002 m
Rate of flow, Q = 1.9 cm³/s = 1.9 * 10⁻⁶ m³/s
Calculate the velocity at point 2 ( check the diagram attached)
Rate of flow at section 2, \(Q = A_2 v_2\)
\(Area, A_2 = \pi d^{2} /4\\A_2 = \pi/4 * 0.002^2\\A_2 = 3.14159 * 10^{-6} m^2\)
\(v_{2} = Q/A_{2} \\v_{2} =\frac{1.9 * 10^{-6}}{3.14 * 10^{-6}} \\v_{2} = 0.605 m/s\)
Applying the Bernoulli (energy flow) equation between Point 1 and point 2 to calculate the head loss:
\(\frac{p_{1} }{\rho g} + \frac{v_{1}^2 }{2 g} + z_1 = \frac{p_{2} }{\rho g} + \frac{v_{2}^2 }{2 g} + z_2 + h_f\\ z_1 = L + l = 0.12 + 0.3\\z_1 = 0.42\\p_1 = p_{atm}\\v_1 = 0\\z_2 = 0\\\frac{p_{atm} }{\rho g} + \frac{0^2 }{2 g} + 0.42= \frac{p_{atm} }{\rho g} + \frac{0.605^2 }{2 *9.8} +0 + h_f\\h_f = 0.401 m\)
For laminar flow, the head loss is given by the formula:
\(h_f = \frac{128 Q \mu l}{\pi \rho g d^4} \\\\0.401 = \frac{128 * 1.9 * 10^{-6} * 0.3 \mu}{\pi *0.95* 9.8* 0.002^4}\\\\\\\mu = \frac{0.401 * \pi *0.95* 9.8* 0.002^4}{128 * 1.9 * 10^{-6} * 0.3} \\\\\mu = 2.57 * 10^{-3} kgm^{-1}s^{-1}\)
Answer:
0.00257 kg / m.s
Explanation:
Given:-
- The specific gravity of a liquid, S.G = 0.95
- The depth of fluid in free container, h = 12 cm
- The length of the vertical tube , L = 30 cm
- The diameter of the tube, D = 2 mm
- The flow-rate of the fluid out of the tube into atmosphere, Q = 1.9 cm^3 / s
Find:-
To determine the viscosity of a liquid
Solution:-
- We will consider the exit point of the fluid through the vertical tube of length ( L ), where the flow rate is measured to be Q = 1.9 cm^3 / s
- The exit velocity ( V2 ) is determined from the relation between flow rate ( Q ) and the velocity at that point.
\(Q = A*V_2\)
Where,
A: The cross sectional area of the tube
- The cross sectional area of the tube ( A ) is expressed as:
\(A = \pi \frac{D^2}{4} \\\\A = \pi \frac{0.002^2}{4} \\\\A = 3.14159 * 10^-^6 m^2\)
- The velocity at the exit can be determined from the flow rate equation:
\(V_2 = \frac{Q}{A} \\\\V_2 = \frac{1.9*10^-^6}{3.14159*10^-^6} \\\\V_2 = 0.605 \frac{m}{s}\)
- We will apply the energy balance ( head ) between the points of top-surface ( free surface ) and the exit of the vertical tube.
\(\frac{P_1}{p*g} + \frac{V^2_1}{2*g} + z_t_o_p = \frac{P_2}{p*g} + \frac{V^2_2}{2*g} + z_d_a_t_u_m + h_L\)
- The free surface conditions apply at atmospheric pressure and still ( V1 = 0 ). Similarly, the exit of the fluid is also to atmospheric pressure. Where, z_top is the total change in elevation from free surface to exit of vertical tube.
- The major head losses in a circular pipe are accounted using Poiessel Law:
\(h_L = \frac{32*u*L*V}{S.G*p*g*D^2}\)
Where,
μ: The dynamic viscosity of fluid
L: the length of tube
V: the average velocity of fluid in tube
ρ: The density of water
- The average velocity of the fluid in the tube remains the same as the exit velocity ( V2 ) because the cross sectional area ( A ) of the tube remains constant throughout the tube. Hence, the velocity also remains constant.
- The energy balance becomes:
\(h + L = \frac{V_2^2}{2*g} + \frac{32*u*L*V_2}{S.G*p*g*D^2} \\\\0.42 = \frac{0.605^2}{2*9.81} + \frac{32*u*(0.3)*(0.605)}{0.95*998*9.81*0.002^2} \\\\u = 0.00257 \frac{kg}{m.s}\)
- Lets check the validity of the Laminar Flow assumption to calculate the major losses:
\(Re = \frac{S.G*p*V_2*D}{u} \\\\Re = \frac{0.95*998*0.605*0.002}{0.00257} \\\\Re = 446 < 2100\)( Laminar Flow )
Related Questions
As the asteroid falls closer to the Earth's surface its _______ energy decreases and its _______ energy increases.
Answers
Answer:
As the asteroid falls closer to the Earth's surface its Gravitational Potential energy decreases and its Kinetic energy increases.
n order to test whether camshafts are being manufactured to specification a sample of n = 35 camshafts are selected at random. The average value of the sample is calculated to be 4.44 mm and the depths of the camshafts in the sample vary by a standard deviation of s = 0.34 mm. Test the hypotheses selected previously, by filling in the blanks in the following: An estimate of the population mean is 4.44 . The standard error is 0.06 . The distribution is normal (examples: normal / t12 / chisquare4 / F5,6). The test statistic has value TS= . Testing at significance level α = 0.01, the rejection region is: less than and greater than (2 dec places). Since the test statistic (is in/is not in) the rejection region, there (is evidence/is no evidence) to reject the null hypothesis, H0. There (is sufficient/is insufficient) evidence to suggest that the average hardness depth, μ, is different to 4.5 mm. Were any assumptions required in order for this inference to be valid? a: No - the Central Limit Theorem applies, which states the sampling distribution is normal for any population distribution. b: Yes - the population distribution must be normally distributed.
Answers
F/(4566)
467dtgc
An AC bridge has 4 arms. In arm AB, a 120 kilo-ohm resistor and a 47 microfarads capacitor are connected in parallel while arm BC has 330 microfarads capacitor. If arm AD has a 330 kilo-ohm resistor, calculate the value of the unknown capacitor and resistor in arm CD connected in series. (AC power is supplied through A and C while the detector is connected across BD)
Answers
The unknown capacitor in arm CD must have a value of 330 microfarads, and the unknown resistor must have a value of 100 kilo-ohms.
To solve the problem, use the following formula:
Cseries = C1 x C2 / (C1 + C2)
Where C1 is the value of the capacitor in arm AB (47 microfarads) and C2 is the value of the capacitor in arm BC (330 microfarads).
Therefore, Cseries = 330 microfarads.
Also, the total resistance of arms CD is the sum of the resistance of the resistor (R) and the reciprocal of the capacitive reactance of the capacitor (1/Xc).
Using the following formula:
Rtotal = R + 1/Xc
Where Xc = 1/2πfC,
f is the frequency and C is the capacitance.
For this problem,
Xc = 1/2π(50)(330 x 10-6)
=> 100 kilo-ohm.
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A certain printer requires that all of the following conditions be satisfied before it will send a HIGH to la microprocessor acknowledging that it is ready to print: 1. The printer's electronic circuits must be energized. 2. Paper must be loaded and ready to advance. 3. The printer must be "on line" with the microprocessor. As each of the above conditions is satisfied, a HIGH is generated and applied to a 3-input logic gate. When all three conditions are met, the logic gate produces a HIGH output indicating readiness to print. The basic logic gate used in this circuit would be an): A) NOR gate. B) NOT gate. C) OR gate. D) AND gate.
Answers
Answer:
D) AND gate.
Explanation:
Given that:
A certain printer requires that all of the following conditions be satisfied before it will send a HIGH to la microprocessor acknowledging that it is ready to print
These conditions are:
1. The printer's electronic circuits must be energized.
2. Paper must be loaded and ready to advance.
3. The printer must be "on line" with the microprocessor.
Now; if these conditions are met the logic gate produces a HIGH output indicating readiness to print.
The objective here is to determine the basic logic gate used in this circuit.
Now;
For NOR gate;
NOR gate gives HIGH only when all the inputs are low. but the question states it that "a HIGH is generated and applied to a 3-input logic gate". This already falsify NOR gate to be the right answer.
For NOT gate.
NOT gate operates with only one input and one output device but here; we are dealing with 3-input logic gate.
Similarly, OR gate gives output as a high if any one of the input signals is high but we need "a HIGH that is generated and applied to a 3-input logic gate".
Finally, AND gate output is HIGH only when all the input signal is HIGH and vice versa, i.e AND gate output is LOW only when all the input signal is LOW. So AND gate satisfies the given criteria that; all the three conditions must be true for the final signal to be HIGH.
In the context of mechanical systems, what does the term efficiency mean? OA the factor by which a machine multiplies a force B. the ratio of a machine's power to the force of its input Ос. the rate at which a machine performs work D. the rate at which a machine consumes energy E. the ratio of the work output of a machine to the work input
Answers
Answer:
E
Explanation:
I have a big brain and I just took the test and got it correct.
What lives at layer 3 (the network layer) of the OSI model?
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Layer 3 of the OSI (Open Systems Interconnection) model, known as the network layer, is responsible for providing end-to-end communication between hosts in different networks.
The network layer is responsible for routing and forwarding data packets across different networks, as well as handling addressing and logical connectivity.
The main entities that live at layer 3 (the network layer) of the OSI model include:
Routers: Routers are network devices that operate at the network layer and are responsible for forwarding data packets between different networks. They use routing tables and protocols to determine the best path for data packets to reach their destination across multiple networks.
IP (Internet Protocol): IP is a network layer protocol that provides logical addressing and routing functionality. It is responsible for assigning unique IP addresses to devices on a network, and for routing data packets based on those IP addresses.
ICMP (Internet Control Message Protocol): ICMP is a network layer protocol that is used for sending error messages and operational information about network conditions. It is often used for diagnostic purposes, such as ping and traceroute, to check the connectivity and status of network devices.
Network Addressing: Layer 3 is also responsible for assigning and managing IP addresses, which are used to uniquely identify devices on a network.
Subnetting and VLANs: Layer 3 may also involve subnetting and VLANs (Virtual Local Area Networks), which are used for network segmentation and management to improve efficiency and security.
In summary, layer 3 of the OSI model includes routers, IP, ICMP, network addressing, and other protocols and technologies that are responsible for routing, addressing, and logical connectivity in a network.
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The team needs to choose a primary view for the part drawing. Three team members make suggestions:
- Team member 1 suggests an orthographic top view because that is how the plans for the part were submitted.
- Team member 2 suggests an isometric view showing side details that were documented within the submitted plans.
- Team member 3 suggests all three orthogonal views should be presented as the primary view.
What is the best way to proceed?
Answer choices below:
Answers
Answer:
Option 1
Explanation:
As the team has already submitted the plans for the part drawing, the best way to proceed would be how it was given in the plans. Hence, the option to be selected :
Team member 1 suggests an orthographic top view because that is how the plans for the part were submitted.Answer:
The first option
Explanation:
Team member 1 suggests an orthographic top view because that is how the plans for the part were submitted.
All of the following are instruments involved in changing a tire EXCEPT:
Answers
Answer:
can you please give us the option for this question
“Snow Cover Area change Analysis for Kabul Basin”
Summarize how GIS & Remote Sensing is incorporated in this study.
Answers
GIS
The full for GIS is : Geographic Information System.
The GIS is a system of mapping that is used to create, analyze, manage and map all the types of data.
It is a method capturing, checking as well as displaying all the data that is related to the position of the surface of earth.
Remote Sensing
Remote sensing is defined as a process where the various physical characteristics of an area are constantly monitored and detected by a process of measuring the reflection of the emitted radiations at ta distance.
The snow covered areas of the Kabul basin can be monitored and analyzed by using the process of GIS and remote sensing.
They provide a continuous source of information and data about snow covered peaks, the amount of snow to the authorities.
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Question Is in the image provided
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The two ways through which a computer model is likely to be used by an engineer in order to help refine a design are as follows:
Calculating the possible costs of building a design.Running simulations to test a problem with the design.Thus, the correct options for this question are A and D.
What do you mean by Computer model?A Computer model may be defined as a type of computer program that significantly runs on a computer that typically develops a model, or simulation, of a real-world feature, phenomenon, or any other event.
According to the context of this question, an engineer would try to perform the ways in order to support the refining of the design through the help of calculating the possible costs of building a design and the run simulations to test a problem with the design.
Therefore, the correct options for this question are A and D.
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On a motion graph a line going up to the right indicates what? *
No motion
Forward Motion
Reverse Motion
Sudden Motion
All of the following are reasons for poor brainstorming sessions e
Answers
If the graph is going upward in the right direction then the motion on the graph is "Forward Motion".
Consider the various uses for network devices like routers, switches, hubs, repeaters, etc. and how one or more of them would aid situations where network performance is degraded. Provide some details about your scenario, why you chose the particular device or devices to solve a poor network performance and reasons why the device would correct the situation. Which network media would be appropriate for the device(s) that you chose? Why were the other devices inappropriate in your opinion?
Answers
In a scenario where network performance is degraded, the appropriate network device to improve the situation would depend on the specific issue and requirements of the network. Let's consider a scenario where a network is experiencing high network congestion and slow data transfer speeds. In this case, a combination of routers and switches can help alleviate the degraded performance.
Routers: Routers are essential network devices that connect multiple networks and facilitate the efficient routing of data packets. They analyze network traffic and determine the most optimal path for data transmission. In our scenario, routers can help by implementing intelligent routing algorithms to redirect network traffic and avoid congested routes. This can distribute the traffic load across different network paths, reducing congestion and improving overall network performance.
Switches: Switches are used to create a local area network (LAN) by connecting multiple devices within a network. They provide dedicated bandwidth for each connected device, allowing simultaneous and efficient data transmission. In our scenario, switches can be strategically placed to create separate network segments, reducing the scope of congestion. By dividing the network into smaller segments, switches can prevent unnecessary data collisions and improve the overall network performance.
Network Media: The appropriate network media for routers and switches would typically be Ethernet cables, such as Cat5e or Cat6 cables. These cables provide reliable and high-speed data transmission, ensuring efficient communication between the devices in the network. Ethernet cables are suitable for these devices as they offer sufficient bandwidth and low latency, supporting fast data transfer and minimizing network congestion.
Hubs and Repeaters: Hubs and repeaters are not suitable in this scenario of degraded network performance. Hubs operate at the physical layer of the network and simply broadcast data to all connected devices, resulting in network collisions and reduced performance. Repeaters, on the other hand, regenerate and amplify signals to extend the network distance but do not address congestion issues. In the case of degraded network performance due to congestion, using hubs or repeaters would not alleviate the issue but rather exacerbate it by increasing network collisions and signal degradation.
By using routers and switches in our scenario, we can intelligently route network traffic, distribute the load, and create separate network segments to address congestion issues. This helps optimize the network performance by improving data transfer speeds and reducing latency.
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Many of the problems applied scientists address are multidisciplinary issues and therefore require the collaboration of scientists with a variety of skills and knowledge. Explain which types of scientists might be involved in studying global warming.
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The consensus couldn’t be clearer. Climate change is happening. It’s caused primarily by the burning of oil, gas, and coal. If we do nothing, the world will become significantly less habitable.
We’ve lost precious time, but if we act now—decisively and dramatically—we still have a chance at avoiding climate change’s most catastrophic impacts
A stratum of clean sand and gravel 30 ft deep is supplied with water from a channel that penetrates to the bottom of the stratum. If the water surface in an infiltration gallery is 4 ft above the bottom of the stratum and its distance to the channel is 100 ft. What is q as a function of hydraulic conductivity?
Answers
The value of q as a function of hydraulic conductivity is q = K/B.
The hydraulic conductivity is the capacity of an aquifer to transmit water. The formula for the flow rate through an unconfined aquifer with a constant hydraulic conductivity is given by;
q = Ki(A/L)
Here;
q = flow rate through the unconfined aquifer
K = hydraulic conductivity
A = cross-sectional area of the aquifer
L = length of the flow path
The depth of the stratum of clean sand and gravel is given as 30 ft, while the water surface in an infiltration gallery is 4 ft above the bottom of the stratum. The distance between the infiltration gallery and the channel is 100 ft. Since the infiltration gallery penetrates to the bottom of the stratum, the length of the flow path (L) can be determined as;
L = 100 + 30 = 130 ft
The cross-sectional area (A) of the aquifer can be determined as;
A = (q/B), where B is the width of the flow path. We assume B = 1m.
Now we know that the pressure difference (head loss) between the channel and the gallery is;
h = 30 - 4 = 26 ft
The hydraulic gradient i = h/L = 26/130 = 0.2
Therefore, the formula for flow rate through the unconfined aquifer with a constant hydraulic conductivity is;
q = Ki(A/L)
q = K [(q/B) / L]
q = K (q/B) / 130B
q = Kq / 130
q [130/B] = Kq
q [1/B] = K
Thus, the value of q as a function of hydraulic conductivity is q = K/B.
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what are the besl measures used for data variation or dispersion
Answers
Answer:
STANDARD DAVIATION OR SD
Explanation:
BECAUSE it is commonly in measuring of dispersion and it also the most roubst measure of variability
Deduce the general exponential fourier series as derived in biomedical analog signals and systems
Answers
Answer:
Exponential Series
Explanation:
Answer:
\({ \rm{x(t) = a_{0} + \sum a_{k} \cos \omega t + \sum b _{k} \sin \omega t }}\)
\({ \tt{ a_{0} = \frac{2}{t} \int x(t) \: dx}} \\ \\ { \tt{ a_{k} = \frac{1}{t} \int x(t) \cos \omega t \: dx }} \\ \\ { \tt{ b_{k} = \frac{1}{t} \int x(t) \sin \omega t \: dx }}\)
Convert an acceleration of 12m/s² to km/h²
Answers
Question 3
[9]
A 25 kW separately-excited dc machine is operated at a constant speed of 3000
r/min with a constant field current such that the open-circuit armature voltage is 125
V. The armature resistance is 0.02 ohm. Determine the following for a terminal
voltage of 128 V:
(a) Is this a motor or generator?
(1)
(b) The armature current.
(2)
(c) The terminal power.
(d) Power developed in the armature.
(e) Torque.
Final answer
Final answer
Final answer
Final answer
[12]
Question 4
A short shunt compound machine having terminal voltage 250 V delivers a load
current of 40 A. The armature, series field and shunt field resistances are 0.050,
0.040 and 1000 respectively. Calculate the following if there is voltage drop of 1V
per brush.
(a) The armature current.
Answers
The armature current, terminal power, and the torque will be 150A, 18750 watts and 59.67Nm respectively.
How to calculate the current?From the information given, the armature current will be:
E = 128 - I(2/100)
125 = 128 - I(0.02)
I = (128 - 125)/0.02
= 150A
The terminal power will be:
= E × I
= 125 × 150
= 18750 watts
The torque developed in the armature will be:
= (18750 × 60)/(2π × 3000)
= 59.67 Nm
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Describe the extent of their own responsibility. When to act on their own innitiative to find , clarify and evaluate information , and to whom they should report if they have problems they cannot resolve in the work place
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Answer:
whatsthe question choices
please i want to paraphrase this paragraph please helppppppppp don't skip!!!!!!
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Question 4 Q.4.1 A properly designed extranet allows companies to reduce internetworking costs and gives participating companies a competitive advantage, which can lead to increased profits. 21, 22, 23 Q.4.3 The Independent Institute of Education (Pty) Ltd 2022 Q.4.4 Q.4.5 Write a brief including the following: Explain how an extranet improves coordination among business partners (3) Identify two companies that are using extranets as an internetworking platform (2) a. b. Q.4.2 In the context of Internet telephony, in addition to cost savings, list three advantages of Voice over Internet Protocol (VoIP). Q.4.6 C. Identify two challenges that must be overcome for designing a successful extranet (2) (Marks: 40) Explain a podcast and how it differs from a regular audio file Discuss social networking by addressing the following: • Briefly explain what social networking is (2 marks) • Provide three examples of social networking sites (3 marks) • For each identified site, explain how it helps a small business (6 marks) in your own words, define the Internet of Everything (loE) then explain how it differs from Internet of Things (IoT). Identify a well-known organisation of your choice then briefly explain two application examples in the organisation for each of the following • Internet Intranet (7) Page 4 of 5 2022 (3) (5) (4) (10)
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To overcome this challenge, companies need to ensure that their systems are compatible with each other.
Extranet is a platform that allows businesses to interact and exchange data with their partners. This allows the sharing of information between the companies and reduces internetworking costs. The extranet helps to increase coordination between business partners in the following ways:Encourages sharing of information: The extranet allows companies to share data with their partners. This allows the partners to stay updated on the latest trends in the market and come up with new business ideas. It also allows companies to improve their supply chain and speed up delivery times. Improves communication: The extranet allows companies to communicate more effectively with their partners. This is done through the use of chat rooms, message boards, and email. This allows partners to exchange ideas and discuss business strategies in real-time.Identify two companies that use extranets as an internetworking platform:Two companies that use extranets as an internetworking platform are:a. Walmart: Walmart uses an extranet to manage its supply chain.
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A 2.75-kN tensile load is applied to a test coupon made from 1.6-mm flat steel plate (E = 200 GPa, ν = 0.30). Determine the resulting change in (a) the 50-mm gage length, (b) the width of portion AB of the test coupon, (c) the thickness of portion AB, (d) the cross- sectional area of portion AB.
Answers
Answer:
I have attached the diagram for this question below. Consult it for better understanding.
Find the cross sectional area AB:
A = (1.6mm)(12mm) = 19.2 mm² = 19.2 × 10⁻⁶m
Forces is given by:
F = 2.75 × 10³ N
Horizontal Stress can be found by:
σ (x) = F/A
σ (x) = 2.75 × 10³ / 19.2 × 10⁻⁶m
σ (x) = 143.23 × 10⁶ Pa
Horizontal Strain can be found by:
ε (x) = σ (x)/ E
ε (x) = 143.23 × 10⁶ / 200 × 10⁹
ε (x) = 716.15 × 10⁻⁶
Find Vertical Strain:
ε (y) = -v · ε (y)
ε (y) = -(0.3)(716.15 × 10⁻⁶)
ε (y) = -214.84 × 10⁻⁶
PART (a)For L = 0.05m
Change (x) = L · ε (x)
Change (x) = 35.808 × 10⁻⁶m
PART (b)
For W = 0.012m
Change (y) = W · ε (y)
Change (y) = -2.5781 × 10⁻⁶m
PART(c)
For t= 0.0016m
Change (z) = t · ε (z)
where
ε (z) = ε (y) ,so
Change (z) = t · ε (y)
Change (z) = -343.74 × 10⁻⁹m
PART (d)
A = A(final) - A(initial)
A = -8.25 × 10⁻⁹m²
(Consult second picture given below for understanding how to calculate area)
The resulting change in the 50-mm gauge length; the width of portion AB of the test coupon; the thickness of portion AB; the cross- sectional area of portion AB are respectively; Δx = 35.808 × 10⁻⁶ m; Δy = -2.5781 × 10⁻⁶m; Δ_z = -343.74 × 10⁻⁹m; A = -8.25 × 10⁻⁹m²
What is the stress and strain in the plate?Let us first find the cross sectional area of AB from the image attached;
A = (1.6mm)(12mm) = 19.2 mm² = 19.2 × 10⁻⁶m
We are given;
Tensile Load; F = 2.75 kN = 2.75 × 10³ N
Horizontal Stress is calculated from the formula;
σₓ = F/A
σₓ = (2.75 × 10³)/(19.2 × 10⁻⁶)m
σₓ = 143.23 × 10⁶ Pa
Horizontal Strain is calculated from;
εₓ = σₓ/E
We are given E = 200 GPa = 200 × 10⁹ Pa
Thus;
εₓ = (143.23 × 10⁶)/(200 × 10⁹)
εₓ = 716.15 × 10⁻⁶
Formula for Vertical Strain is;
ε_y = -ν * εₓ
We are given ν = 0.30. Thus;
ε_y = -(0.3) * (716.15 × 10⁻⁶)
ε_y = -214.84 × 10⁻⁶
A) We are given;
Gauge Length; L = 0.05m
Change in gauge length is gotten from;
Δx = L * εₓ
Δx = 0.05 × 716.15 × 10⁻⁶
Δx = 35.808 × 10⁻⁶ m
B) From the attached diagram, the width is;
W = 0.012m
Change in width is;
Δy = W * ε_y
Δy = 0.012 * -214.84 × 10⁻⁶
Δy = -2.5781 × 10⁻⁶m
C) We are given;
Thickness of plate; t = 1.6 mm = 0.0016m
Change in thickness;
Δ_z = t * ε_z
where;
ε_z = ε_y
Thus;
Δ_z = t * ε_y
Δ_z = 0.0016 * -214.84 × 10⁻⁶
Δ_z = -343.74 × 10⁻⁹m
D) The change in cross sectional area is gotten from;
ΔA = A_final - A_initial
From calculating the areas, we have;
A = -8.25 × 10⁻⁹ m²
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someone should help me and explain stress strain curve
Answers
Answer:
In engineering and materials science, a stress–strain curve for a material gives the relationship between stress and strain. It is obtained by gradually applying load to a test coupon and measuring the deformation, from which the stress and strain can be determined (see tensile testing).
Explanation:
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For some metal alloy, a true stress of 345 MPa (50040 psi) produces a plastic true strain of 0.02. How much will a specimen of this material elongate when a true stress of 418 MPa (60630 psi) is applied if the original length is 500 mm (19.69 in.)
Answers
The specimen of this material will elongate to 24.348mm K = d / €^n.
The letter d symbolizes the Greek letter epsilon.
K = 345 / 0.02⁰.²² = 816mPa
The real strain based on 414mPa stress equals
€= (€/k)^1/n = (414/816)¹/⁰.²² = 0.04576
The genuine connection between true strain and length, on the other hand, is provided by
ln(Li/Lo) = €
By rearranging, we may make Li the subject of a formula.
Li = Lo.e^€
Li = 520e⁰.⁰⁴⁵⁷⁶
Li = 544.348mm
From this, the amount of elongation may be estimated.
Change in L = Li - Lo = 544.348 - 520 = 24.348mm.
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the types of fire-extinguishing agents for aircraft interior fires are
Answers
Answer:
Halon 1211 or equivalent fire extinguishers are spaced throughout the cabin and easily accessible from the aisle or entryway. A water fire extinguisher is typically located near a lavatory-galley complex. In some cases, one or more Halon 1211 extinguishers are used in place of the water fire extinguisher.
The machine language file is loaded onto the robot where the files can run test written as part of the program called __________________.
Answers
Answer:
C++ and Python
Explanation:
C++ and Python
A cylindrical rod of copper (E = 110 GPa) having a yield strength of 240 MPa is to be subjected
to a load of 6660 N. If the length of the rod is 380 mm, what must be the diameter to allow an
elongation of 0.50 mm?
Answers
Answer:
"7.654 mm" is the correct solution.
Explanation:
According to the question,
\(E=110\times 10^3 \ N/mm^2\)\(\sigma_y = 240 \ mPa\)\(P = 6660 \ N\)\(L = 380 \ mm\)\(\delta = 0.5 \ mm\)Now,
As we know,
The Elongation,
⇒ \(E=\frac{\sigma}{e}\)
\(=\frac{\frac{P}{A} }{\frac{\delta}{L} }\)
or,
⇒ \(\delta=\frac{PL}{AE}\)
By substituting the values, we get
\(0.5=\frac{6660\times 380}{(\frac{\pi}{4}D^2)(110\times 10^3)}\)
then,
⇒ \(D^2=58.587\)
\(D=\sqrt{58.587}\)
\(=7.654 \ mm\)
when the same presynaptic neuron fires at 20 aps per second, however, the postsynaptic cell fires. this is an example of
Answers
When the same presynaptic neuron fires at 20 aps per second, however, the postsynaptic cell fires; this is an example of a convergent neural pathway.What is a neural pathway?A neural pathway refers to the network of nerve fibers or neurons that conduct nerve impulses from one part of the body to another.
The transmission of information from one neuron to another is mediated by the release of chemical neurotransmitters, which bind to receptors on the postsynaptic membrane of the next neuron in line. This process results in the transmission of information from one neuron to the next.
Consequently, when the same presynaptic neuron fires at 20 aps per second, however, the postsynaptic cell fires, this is an example of a convergent neural pathway in action. In other words, the postsynaptic neuron is receiving input from multiple sources and is responding based on the relative strengths of those signals.
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A diode has Is = 10-17 A and n=1.05. (a) What is the diode voltage if the diode current is 70 uA? (b) What is the diode current for Vp = 0.1 mV?
Answers
the diode current for a voltage of 0.1 mV is approximately 2.88 pA.
(a) To find the diode voltage for a current of 70 uA, we can use the Shockley diode equation:
I = Is * (exp(qV/nkT) - 1)
where I is the diode current, q is the charge of an electron, k is Boltzmann's constant, T is the temperature in Kelvin, and V is the diode voltage. Rearranging the equation and plugging in the given values, we get:
V = (nkT/q) * ln(I/Is + 1)
V = (1.05 * 1.38e-23 * 300 / 1.6e-19) * ln(70e-6 / 1e-17 + 1)
V ≈ 0.682 V
Therefore, the diode voltage for a current of 70 uA is approximately 0.682 V.
(b) To find the diode current for a voltage of 0.1 mV, we can use the same equation and solve for I:
I = Is * (exp(qV/nkT) - 1)
I = Is * (exp(0.1e-3 * q / nkT) - 1)
I = 1e-17 * (exp(0.1e-3 * 1.6e-19 / (1.05 * 1.38e-23 * 300)) - 1)
I ≈ 2.88 pA
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Project: Kitchen Redesign
Background
You have just completed a postgraduate diploma in project management and a home owner has asked you in your
capacity as a shop-fitter to redesign/remodel his kitchen. Develop a project proposal for the implementation of this
kitchen redesign project. All processes planned for should be finalised within 2 weeks as the home owner plans to
move into his new home in 2 weeks. You are required to submit a proposal in the report format provided, outlining how
all planning and preparation would be effected.
GENERAL PROJECT INFORMATION
Project Tasks Team Rates
- Design: layout and plan for the kitchen Electrician R150 p/d
- Cabinets: style and finish of cabinets Plumber R150 p/d
- Countertops: material and colour for countertops - Granite,
solid surface, and plastic laminate
Purchaser R100 p/d
- Flooring: type and finish of flooring for kitchen - tile and wood Tiler R200 p/d
- Appliances: refrigerator, dishwasher, microwave, and stove for
kitchen – finishes: stainless steel or painted
Countertop Specialist R200 p/d
- Tap(s) and Sink: finishes: chrome, stainless steel or porcelain
enamel are often used for sinks
Cabinet Maker R200 p/d
- Lighting: recessed, pendant, and/or under cabinet mounted
task lights
Graphic Designers R120 p/d
NB: Assign resources as much as
you can to accomplish all your
identified tasks.
1.2 List and discuss all assumed resources required on the project.
Answers
The team members should be allocated based on their expertise and availability to ensure efficient completion of tasks within the given timeframe of two weeks.
Assumed Resources Required for the Kitchen Redesign Project:
1. Design:
- Experienced kitchen designer or interior designer to create the layout and plan for the kitchen.
- Necessary design software or tools to create visual representations and floor plans.
2. Cabinets:
- Skilled cabinet maker to design and construct the cabinets according to the chosen style and finish.
- Required woodworking tools and equipment.
- Quality cabinet materials and hardware.
3. Countertops:
- Knowledgeable purchaser to research and select the appropriate materials (granite, solid surface, or plastic laminate) and colors for the countertops.
- Access to suppliers or manufacturers of the chosen countertop materials.
4. Flooring:
- Skilled tiler or flooring specialist to install the chosen type of flooring (tile or wood).
- Adequate flooring materials based on the selected flooring type.
- Necessary tools and equipment for flooring installation.
5. Appliances:
- Purchaser or procurement specialist to select and purchase the necessary kitchen appliances (refrigerator, dishwasher, microwave, stove) with the chosen finishes (stainless steel or painted).
- Access to reliable appliance suppliers or vendors.
6. Tap(s) and Sink:
- Cabinet maker or plumber to install the chosen tap(s) and sink with the desired finishes (chrome, stainless steel, or porcelain enamel).
- Access to plumbing fixtures and suppliers.
7. Lighting:
- Electrician to install the selected lighting fixtures, including recessed, pendant, and/or under cabinet mounted task lights.
- Adequate lighting fixtures and necessary electrical equipment.
8. Graphic Designers:
- Graphic designers to function with any visual design elements, such as creating digital renderings or graphics for presentation purposes.
It is important to note that the rates provided for the team members are specified as daily rates.
The team members should be allocated based on their expertise and availability to ensure efficient completion of tasks within the given timeframe of two weeks.
Additionally, coordination and communication among team members are crucial to ensure smooth workflow and successful implementation of the project.
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