Translate (-3, 5) down 2 units.
Then reflect the result over the y-axis.
What are the coordinates of the final point?

Answer:

2/7b + 10

Step-by-step explanation:

Polygons are shapes that have the following:

-sides are all straight

-no overlapping

-shape is always closed

Hope this helps :)

Answer:

\(\sf c = -4\)  and  \(\sf b = -6\)

Explanation:

using the formula: \(\sf x = \frac{ -b \pm \sqrt{b^2 - 4ac}}{2a}\)

Here the a = 1

using the equation:

\(3 \pm\sqrt{13}= \frac{ -b \pm \sqrt{b^2 - 4(1)c}}{2(1)}\)

\(6 \pm2\sqrt{13}= -b \pm \sqrt{b^2 - 4(1)c}}\)

matching the coefficients: b = - 6

find c:

\(6 \pm2\sqrt{13}= -(-6) \pm \sqrt{(-6)^2 - 4(1)c}}\)

\(6 \pm2\sqrt{13}= 6 \pm \sqrt{36 - 4c}}\)

\(\sf 6 \pm\sqrt{52}= 6 \pm \sqrt{36 - 4c}}\)

\(\sf 36-4c = 52\)

\(\sf -4c = 52-36\)

\(\sf -4x = 16\)

\(\sf c = -4\)

Answer: x = 10

Step-by-step explanation: 4 times 250 is 1000 and divided by 100 is 10

The solutions to the equation -30x² + 9x + 60 = 0 are x = 5/2 and x = -4/5.

To solve the equation, we can start by bringing all the terms to one side to have a quadratic equation equal to zero. Let's go step by step:

-5/3 x² + 3x + 11 = -9 + 25/3 x²

First, let's simplify the equation by multiplying each term by 3 to eliminate the fractions:

-5x² + 9x + 33 = -27 + 25x²

Next, let's combine like terms:

-5x² - 25x² + 9x + 33 = -27

-30x² + 9x + 33 = -27

Now, let's bring all the terms to one side to have a quadratic equation equal to zero:

-30x² + 9x + 33 + 27 = 0

-30x² + 9x + 60 = 0

Finally, we have the quadratic equation in standard form:

-30x² + 9x + 60 = 0

Dividing each term by 3, we get:

-10x² + 3x + 20 = 0

(-2x + 5)(5x + 4) = -10x² + 3x + 20

So, the factored form of the equation -30x² + 9x + 60 = 0 is:

(-2x + 5)(5x + 4) = 0

Now we can set each factor equal to zero and solve for x:

-2x + 5 = 0 --> x = 5/2

5x + 4 = 0 --> x = -4/5

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Since there are only two vectors in the subspace spanned by {u, v}, w is not there in the subspace.

No, w is not in {u, v}. Two vectors are there in the set {u, v}. b. Two vectors are in span{u, v}. c. w is not in the subspace spanned by {u, v}. Let's find out the details about these terms and answers.In linear algebra, a vector is a matrix with a single column or a single row. Spanning is a collection of vectors that could be reached by linear combination. In this question, {u, v} denotes the two vectors and we need to find out if w is there in the set or not.

The second part of the question asks about how many vectors are in the span of {u, v}? Since we have only two vectors in the set {u, v}, there are only two vectors in span{u, v}.The third part of the question is asking if w is in the subspace spanned by {u, v}.

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Answer:

54 degrees

Step-by-step explanation:

120+6= 126

180-126=54

we are given that circle A has a secant EC and a tangent BC that intersect at point C. We are also given that mEB = 166° and mBD = 80°. Our task is to find the measure of angle ZBCD, which is formed by the intersection of secant EC and tangent BC.

To find mZBCD, we first need to find mECB. Since EC is a secant and BC is a tangent to circle A, and EC and BC intersect at C, we know that:

mECB = mBEC (because they are opposite angles formed by intersecting lines)

Also, mBEC = 180° - mEB (because BEC is a straight line)

So, mECB = 180° - mEB = 180° - 166° = 14°

Since mBD is 80°, we have:

mZBCD = mECB + mBD = 14° + 80° = 94°

So, mZBCD = 94°. This means that angle ZBCD is 94°.

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The domain of the function is defined as 0 ≤  x ≤ 4.

option A is the correct answer.

A domain of a function refers to "all the values" that can go into a function without resulting in undefined values.

So the domain of a function is the set of x values, while the range of a function is the set of y values.

From the given statement, the range of the function is defined as;

y = vt

where;

y = 60 mph x 4 hr

y = 240 miles

From the given statement, the domain of the function is defined as;

0 ≤  x ≤ 4

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Answer:

A. True
B. False
C. False
D. True

Step-by-step explanation:

#a

True

#b

False

#c

False

#d

Let's check

True

The angle also should be known to prove congruency.

It states that two triangles are said to be congruent if they are exact copies of one another and completely cover one another when superposed. In other words, two triangles are congruent if their corresponding sides and angles are equal to those of the first triangle.

It is ineffective to only know angle-angle-angle (AAA), as this can result in triangles that are similar but not congruent. There are four short cuts that can be used to check whether two triangles are congruent.

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Ozone can be both harmful and beneficial to health, depending on its location in the atmosphere and the levels at which it is present.

In the stratosphere (the layer of the atmosphere that is located about 10-50 kilometers above the Earth's surface), ozone is a beneficial gas that protects life on Earth by absorbing harmful ultraviolet (UV) radiation from the sun. However, at ground level, ozone can be harmful to health, particularly for people with respiratory problems such as asthma.

Exposure to high levels of ozone can irritate the respiratory system and cause coughing, throat irritation, and chest pain. It can also worsen bronchitis, emphysema, and other lung diseases. Ozone can also reduce lung function and inflame the linings of the lungs, leading to more serious health problems.

It is important to note that ground-level ozone is not emitted directly into the air, but is formed when pollutants from sources such as vehicle exhaust, power plants, and industrial facilities react with sunlight and heat.

Therefore, Ozone can be both harmful and beneficial to health.

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Answer:

I'm pretty sure it's:

5x5x5x5x5x5x5x5x5 x 2x2

Answer:

Yes, they are similar by SSS

Answer:

x=1.144714

Step-by-step explanation:

Let's solve your equation step-by-step.

−2+(3)(4)x3=16

By using the elimination method, the solution of the given equations are x = 1 and y = -4

The equations are

2x - 3y = 14

x + 3y = -11

Here we have to use the elimination method. Eliminate one variable and find another variable

Add the equation 1 and 2. Then we can eliminate the y terms

2x + x = 14 - 11

3x = 3

x = 3/3

x = 1

The value of x = 1

Substitute the value of x in the first equation

2x - 3y = 14

2(1) - 3y = 14

2 - 3y = 14

3y = -14+2

3y = -12

y = -12/3

y = -4

The value of y = -4

Hence, by using the elimination method the solution of the given equations are x = 1 and y = -4

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Answer:

12:45 pm

Step-by-step explanation:

She started at 8:15 we can add the 15 minutes to 30 minutes and get 45 minutes  then we add the 4 hours to 8 am  and get 12 pm. add the 45 minutes and you get 12:45 pm

(a) On the basis of eigenvectors for T, it is diagonalizable.

(b) C is diagonalizable.

To determine whether the given linear operator/matrix is diagonalizable, we need to check if it has a complete set of linearly independent eigenvectors. Let's analyze both parts of the question:

(a) T: R³ → R³ with T(1, 1, 1) = (2, 2, 2), T(0, 1, 1) = (0, -3, -3), and T(1, 2, 3) = (-1, -2, -3).

To check if T is diagonalizable, we need to find the eigenvalues and eigenvectors.

First, let's find the eigenvalues:

We solve the equation T(v) = λv, where v is a vector and λ is a scalar.

From the given information:

T(1, 1, 1) = (2, 2, 2) --> T - 2I = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]

T(0, 1, 1) = (0, -3, -3) --> T - λI = [[-λ, 0, 0], [0, -λ, 0], [0, 0, -λ]]

T(1, 2, 3) = (-1, -2, -3) --> T - λI = [[-1-λ, 0, 0], [0, -2-λ, 0], [0, 0, -3-λ]]

To find the eigenvalues, we need to solve the equation det(T - λI) = 0:

det([[-λ, 0, 0], [0, -λ, 0], [0, 0, -λ]]) = (-λ)(-λ)(-λ) = -λ³

Setting -λ³ = 0 gives λ = 0 as a possible eigenvalue.

To find the eigenvectors, we solve the equation (T - λI)v = 0 for each eigenvalue:

For λ = 0, we have (T - 0I)v = 0:

[[-2, 0, 0], [0, -2, 0], [0, 0, -2]]v = 0

Row reducing the augmented matrix [[-2, 0, 0, 0], [0, -2, 0, 0], [0, 0, -2, 0]], we get:

[1, 0, 0, 0]

[0, 1, 0, 0]

[0, 0, 1, 0]

This shows that the null space of (T - 0I) is spanned by the vectors [1, 0, 0], [0, 1, 0], and [0, 0, 1]. These vectors form a basis for R³.

Since we have a basis of eigenvectors for T, it is diagonalizable.

(b) C = [[-2², 3], [1, -2]]

To check if C is diagonalizable, we need to find the eigenvalues and eigenvectors.

The eigenvalues of C are the solutions to the equation det(C - λI) = 0:

det([[-2² - λ, 3], [1, -2 - λ]]) = (-2² - λ)(-2 - λ) - 3 = λ² + 4λ + 1

Therefore, C is diagonalizable.

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The point (1,2) is the point of intersection of the two lines.

It should be noted that to verify if the point (1,2) is a solution to the system of linear equations, we need to substitute x=1 and y=2 into both equations and check if they are true.

The equation is true, so (1,2) is a solution to the first equation.

Substituting x=1 and y=2 into the second equation also makes the equation true.

Therefore, the point (1,2) is the point of intersection of the two lines.

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Answer:

the whole number is 1.09842519685

that is in meters

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

Answer: The second one

Step-by-step explanation: Because I said so nons

Answer:

4) y=-4x

Step-by-step explanation:

The lines goes down 4 units as it moves 1 unit right.

Thus, we have rewritten sin (x - pi/6) in terms of sin (x) and cos (x) as: sin (x - pi/6) = (sqrt(3)/2) sin x - (1/2) cos x

To rewrite sin (x - pi/6) in terms of sin (x) and cos (x), we can use the trigonometric identity for the sine of the difference between two angles:
sin (a - b) = sin a cos b - cos a sin b
In this case, we can let a = x and b = pi/6, so we have:
sin (x - pi/6) = sin x cos (pi/6) - cos x sin (pi/6)
We know that cos (pi/6) = √(3)/2 and sin (pi/6) = 1/2, so we can substitute those values into the equation:
sin (x - pi/6) = sin x (√(3)/2) - cos x (1/2)
Thus, we have rewritten sin (x - pi/6) in terms of sin (x) and cos (x) as:
sin (x - pi/6) = (√(3)/2) sin x - (1/2) cos x

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Assuming that the crews are approaching the growing wild fire in a form that assumes polygonal dimensions as depicted in the image attached, the crew with the shortest distance to the fire is the closest to the fire. Hence the crew with the shortest distance to the fire is Crew B.

The distance of position between two places on a line or line segment is the length along the line or line segment between the specified spots.

It can also be defined as the numerical measurement of the distance between two objects or places.

Hence, according to the image attached, the crew closest to the fire is Crew B.

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Answer:

y = 10x-37

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

y = 10x+b

Substitute the point into the equation

3 = 10*4+b

3 = 40+b

Subtract 40

3-40 = 40+b-40

-37 = b

y = 10x-37

Answer: y = 10x - 37

Step-by-step explanation:

Hope it helps <3

Total cost:-

\(\\ \sf\longmapsto 225/8(44.5)\)

\(\\ \sf\longmapsto 28.1(44.5)\)

\(\\ \sf\longmapsto 1251.5\$\)

Recheck the question options

Answer:

$2273.19

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Compound Interest Rate Formula: \(\displaystyle A = P(1 + \frac{r}{n})^{nt}\)

Step-by-step explanation:

Step 1: Identify Variables

P = $1900

r = 3% = 0.03

n = 4

Step 2: Solve for A

Step-by-step explanation:

x−7(x−2)=10x+9−x

Step 1: Simplify both sides of the equation.

x−7(x−2)=10x+9−x

x+(−7)(x)+(−7)(−2)=10x+9+−x(Distribute)

x+−7x+14=10x+9+−x

(x+−7x)+(14)=(10x+−x)+(9)(Combine Like Terms)

−6x+14=9x+9

−6x+14=9x+9

Step 2: Subtract 9x from both sides.

−6x+14−9x=9x+9−9x

−15x+14=9

Step 3: Subtract 14 from both sides.

−15x+14−14=9−14

−15x=−5

Step 4: Divide both sides by -15.

−15x−15=−5−15

x=13

Answer:

x=13