Answer:
C.) One mile
Step-by-step explanation:
9/10 ain less than 1/4
9/10 is wayyy more than 1/2
9/10 ain even one mile so how could it be more than a mile?
Work out the perimeter of this semicircle.
Take it to be 3.142 and write down all of the digits given by your calculator.
18 cm give your answer in cm
Answer:
46.278cm
Step-by-step explanation:
(π+2)r
=πr+d
=9π+18=46.278cm
Plzz help me
A tree grows three feet per year. What happens to the growth of the tree when the number of years changes?
O When the number of years increases, the number of feet decreases.
OWhen the number of years decreases, the number of feet stays the same.
O When the number of years increases, the number of feet increases.
O When the number of years decreases, the number of feet increases.
Answer:
C
Step-by-step explanation:
When the number of years increases, the number of feet increases.
Option C is the correct answer.
What is an equation?An equation contains one or more terms with variables connected by an equal sign.
Example:
2x + 4y = 9 is an equation.
2x = 8 is an equation.
We have,
Tree height = M
Now,
A tree grows = three feet per year
We can make an equation for the height of the tree in x years.
y = M + 3x
Where x is the number of years.
Now,
When x is increasing y will increase.
This means,
For x = 1, 2, 3 and M = 12
y = 12 + 3 = 15
y = 12 + 6 = 18
y = 12 + 9 = 21
We see that it is increasing.
Thus,
When the number of years increases, the number of feet increases.
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Help on this question #3 please
In Layla's case, her debt to income ratio is approximately 42.24%, which is within an acceptable range.
How to calculate the valueIn order to calculate Layla's DTI, we add up all her monthly debt expenses and divide them by her gross monthly income:
Total Monthly Debt Expenses = Car Loan + Credit Card + Mortgage
= $200 + $25 + $1000
= $1225
DTI = (Total Monthly Debt Expenses / Gross Monthly Income) * 100
= ($1225 / $2900) * 100
≈ 42.24%
Typically, lenders prefer a lower DTI, generally below 43% for most loan types. In Layla's case, her DTI is approximately 42.24%, which is within an acceptable range.
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how many are 4 x 4 ?
Answer:
16
Step-by-step explanation:
I buy 4 5/8 blue fabric and 2 1/8 green fabric how much blue than green did i buy
Answer:
2.5
Step-by-step explanation:
We Know
You buy 4 5/8 blue fabric and 2 1/8 green fabric .
4 5/8 = 37/8 = 4.625 blue fabric
2 1/8 = 17/8 = 2.125 green fabric
How much blue than green did you buy?
We Take
4.625 - 2.125 = 2.5
So, you buy 2.5 blue more than green.
What is the asymptote of the graph of f(x)=5x−1?
The asymptotes of the graph of \(f(x) = \frac{5}{x - 1}\) are as follows:
Vertical: x = 1.Horizontal: y = 0.What are the asymptotes of a function f(x)?The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.In this problem, the function is:
\(f(x) = \frac{5}{x - 1}\)
For the vertical asymptote, we have that:
\(x - 1 = 0 \rightarrow x = 1\).
For the horizontal asymptote, we have that:
\(y = \lim_{x \rightarrow \infty} f(x) = \frac{5}{\infty - 1} = 0\).
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5/2÷9/4_________________
Remember, the trick to dividing fractions is to use keep/change/flip.
First, keep your 5/2 the same. Second, change your division sign to a multiplication sign. Third, flip your 9/4 to get 4/9. Multiply!
Mixed number form: 1 1/9
Exact form: 10/9
Decimal form: 1.1 repeating
Hope this helps!
-abagalecoleman
Find all solutions to the equation x3 + 16x – 3x2 = 48.
–4, –3, 4
–4, 3, 4
3, –4i, 4i
–3, –4i, 4i
The solutions of the quadratic equation x³+ 16x -3x² = 48 are 3, –4i, 4i
What is a quadratic equation?A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.
A mathematical statement with two expressions that have the same value and the sign "equal to" between them is called an equation.
We are given the quadratic equation as;
x³+ 16x -3x² = 48
Subtract 48 from both sides;
x³+ 16x -3x² - 48= 48 -48
x³+ 16x -3x² - 48= 0
Factor left side of equation.
(x - 3)( x² + 16) = 0
Therefore, the roots are 3, –4i, 4i
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Calculate the value of x
Answer:
x = 30
Step-by-step explanation:
All the angles on a point add up to 360°. Thus, you can find 2x easily.
2x = 360° - 300°
= 60
x = 60 ÷ 2
= 30
Answer:
360-300=60
30
Step-by-step explanation:
All the angles on a point add up to 360°. Thus, you can find 2x easily.
2x = 360° - 300°
= 60
x = 60 ÷ 2
= 30
Diven {x) = 3x- 1 and 9(x) = 2x-3, for which value of x does g(X) = {2)?
The calculated value of x at g(x) = 2 is x = 2.5
How to determine the value of x at g(x) = 2from the question, we have the following parameters that can be used in our computation:
f(x) = 3x - 1
Also, we have
g(x) = 2x - 3
When g(x) - 2, we have
2x - 3 = 2
So, we have
2x = 5
Divide by 2
x = 2.5
Hence, the value of x at g(x) = 2 is x = 2.5
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At Priscilla's school, the final grade for her Calculus course is weighted as follows: Tests: 50% Quizzes: 30% Homework: 20% Priscilla has an average of 87% on her tests, 100% on her quizzes, and 20% on her homework. What is Priscilla's weighted average?
At Priscilla's school, the final grade for her Calculus course is weighted as follows: Tests: 50% Quizzes: 30% Homework: 20% Priscilla has an average of 87% on her tests, 100% on her quizzes, and 20% on her homework. What is Priscilla's weighted average?
Work:Weighted Average gives weights to each percent of the average as follows:
Weighted Average = Average * weighting percent
Weighted Average = Test Average * Test Weighting + Quiz Average. * Quiz Weighting + Homework Average * Homework Weighting
Weighted Average = 87% * 50% + 100% * 30% + 20% * 20%
Weighted Average = 43.5% + 30% + 4%
Weighted Average = 77.5%
Answer:
77.5%
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Graphing
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Converting fractions into decimals
Thank You!
Answered by: ms115
Which is the
4
graph of f(x) = 4[*?
-3-2--1₁-
-2-
2 3 4 5 6
4
1
1-2--11-
-2
2 3
56
4
2-11.
-2-
23
56
Option 2 is the correct graph for the function f(x) = \(4[(1/2)^{x}]\) .
Given ,
f(x) = \(4[(1/2)^{x}]\)
Mathematically the graph will of exponential in nature.
So,
Let us assume few values to understand the nature of graph.
Firstly,
Let x= 1
f(x) = \(4[(1/2)^{1}]\)
f(x) = 2
Let x = 2
f(x) = \(4[(1/2)^{2}]\)
f(x) = 1
Let x = 3
f(x) = \(4[(1/2)^{3}]\)
f(x) = 0.5
Thus from these values of f(x) corresponding to the values of x second graph will be correct .
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help with this too please
Answer:
11/61
Step-by-step explanation:
sin K = opp/hyp
sin K = 11/61
Answer: 11/61
Answer:
SinK=11/61
Step-by-step explanation:
The function sin can be found by looking for the side opposite of the angle over the hypotenuse.
In the figure below, point B is the corner of street ABC. If streetlights are to b
installed along one side of the street with equal distance between the lights, and a
treetlight must be installed at points A, B and C, at least how many streetlights
an be installed along the street?
A
1625 m
B
cli
1170 m
Therefore, at least 49 street lights can be installed along one side of the street with equal distance between the lights.
What is equation?An equation is a mathematical statement that shows that two expressions are equal. It consists of two parts: the left-hand side (LHS) and the right-hand side (RHS), separated by an equals sign (=). The equals sign indicates that the two expressions are equal, and the goal of solving the equation is to find the value of x that makes this statement true. Equations can be solved using various algebraic techniques, such as simplifying and rearranging the expressions, applying operations to both sides of the equation, and factoring or expanding expressions. Solving an equation involves finding the values of the variables that make the equation true.
Here,
The distance between point A and B is AB, and the distance between point B and C is BC. Let's assume that the distance between each street light is "d".
Since there must be a street light at points A, B, and C, there will be a total of two gaps between these three street lights, which are AB and BC. Thus, the number of street lights required is equal to the sum of the lengths of AB and BC, divided by the distance "d" between the street lights, plus 1 for the street light at point B.
So, the total number of street lights required is
Number of street lights = (AB + BC) / d + 1
We know that AB = 1170 m and BC = 1625 m, and the distance between each street light should be equal. Therefore, we need to find the greatest common factor (GCF) of 1170 and 1625 to determine the distance between each street light.
1170 = 2 x 3 x 3 x 5 x 13
1625 = 5 x 5 x 13
The GCF of 1170 and 1625 is 65, which means the distance between each street light should be 65 meters.
Now we can calculate the total number of street lights required:
Number of street lights = (1170 + 1625) / 65 + 1
= 49
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What is the slope of a line parallel to the line whose equation is 6x - y = 1. Fully
reduce your answer.
Verify that the indicated family of functions is a solution of the given differential equation. dP/dt = P(1-P); P = ce^t / 1+ ce^t?
The value for differential equation is found as -
\(\frac{dP}{dt} =\frac{d}{dt} (\frac{c_1e^t}{1+c_1e^t})\\\)
\(\frac{dP}{dt} - (\frac{c_1e^t}{(1+c_1e^t)} )(1-\frac{c_1e^t}{(1+c_1e^t)^2})\\ =(\frac{c_1e^t}{(1+c_1e^t)^2} )-(\frac{c_1e^t}{1+c_1e^t})(1-\frac{c_1e^t}{1+c_1e^t})=0\)
What is differential equation?
Any equation with one or more terms and one or more derivatives of the dependent variable with respect to the independent variable is referred to as a differential equation.
The equation given is - \(P=\frac{c_1e^t}{1+c_1e^t}\)
Take derivative with respect to t -
\(\frac{dP}{dt} =\frac{d}{dt} (\frac{c_1e^t}{1+c_1e^t})\\\frac{dP}{dt} =\frac{d}{dt}c_1 (\frac{e^t}{1+c_1e^t})\)
By Quotient rule \(\frac{d}{dt} \frac{u}{v} =\frac{v\frac{du}{dt}- u\frac{dv}{dt}}{v^2}\) -
\(\frac{dP}{dt} =c_1 (\frac{(1+c_1e^t)\frac{d}{dt}(e^t)-(e^t)\frac{d}{dt}(1+c_1e^t)}{(1+c_1e^t)} )\\\frac{dP}{dt} =c_1 (\frac{(1+c_1e^t)(e^t)-(e^t)(0+c_1e^t)}{(1+c_1e^t)} )\)
(\(\frac{d}{dx} e^t=e^t\) and \(\frac{d}{dx} c_1=0\) here \(c_1=\)constant)
\(\frac{dP}{dt} =c_1e^t (\frac{(1+c_1e^t-c_1e^t)}{(1+c_1e^t)^2} )\\\frac{dP}{dt} = (\frac{(c_1e^t)}{(1+c_1e^t)^2} )\)
Now, \(\frac{dP}{dt} =P(1-P)\) -
\(\frac{dP}{dt} - (\frac{c_1e^t}{(1+c_1e^t)} )(1-\frac{c_1e^t}{(1+c_1e^t)^2})\\ =(\frac{c_1e^t}{(1+c_1e^t)^2} )-(\frac{c_1e^t}{1+c_1e^t})(1-\frac{c_1e^t}{1+c_1e^t})\\\frac{dP}{dt} =(\frac{c_1e^t}{(1+c_1e^t)} )(\frac{1}{1+c_1e^t}-1+\frac{c_1e^t}{1+c_1e^t})\\\frac{dP}{dt} =(\frac{c_1e^t}{(1+c_1e^t)} )(\frac{1-(1+c_1e^t)+c_1e^t}{1+c_1e^t})\\\frac{dP}{dt} =(\frac{c_1e^t}{(1+c_1e^t)} )(\frac{1-1-c_1e^t+c_1e^t}{1+c_1e^t})\\\)
\(\frac{dP}{dt} =(\frac{c_1e^t}{(1+c_1e^t)} )(\frac{0}{1+c_1e^t})\\\frac{dP}{dt} =(\frac{c_1e^t}{(1+c_1e^t)} )(0)\\\frac{dP}{dt} =0\)
Therefore, the value is \(\frac{dP}{dt} =0\).
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In 2015, the average distance from Earth to the moon was about 3.74 x 105 km. The distance from Earth to Mars was about 9.25 x 107 km. How much farther is traveling from Earth to Mars than from Earth to the moon? Write your answer in scientific notation.
Traveling from Earth to Mars is approximately 9.249626 x 10^7 km farther than traveling from Earth to the moon.
Earth to Mars is compared to traveling from Earth to the moon, we need to calculate the difference between the distances.
The distance from Earth to the moon is approximately 3.74 x 10^5 km.
The distance from Earth to Mars is approximately 9.25 x 10^7 km.
To find the difference, we subtract the distance to the moon from the distance to Mars:
9.25 x 10^7 km - 3.74 x 10^5 km
To subtract these numbers, we need to make sure the exponents are the same. We can rewrite the distance to the moon in scientific notation with the same exponent as the distance to Mars:
3.74 x 10^5 km = 0.374 x 10^6 km (since 0.374 = 3.74 x 10^5 / 10^6)
Now we can perform the subtraction:
9.25 x 10^7 km - 0.374 x 10^6 km = 9.25 x 10^7 km - 0.374 x 10^6 km
To subtract, we subtract the coefficients and keep the same exponent:
9.25 x 10^7 km - 0.374 x 10^6 km = 9.25 x 10^7 - 0.374 x 10^6 km
Simplifying the subtraction:
9.25 x 10^7 - 0.374 x 10^6 km = 9.249626 x 10^7 km
Therefore, traveling from Earth to Mars is approximately 9.249626 x 10^7 km farther than traveling from Earth to the moon.
Scientific notation is a convenient way to express very large or very small numbers. It consists of a coefficient (a number between 1 and 10) multiplied by a power of 10 (exponent). It allows us to write and manipulate such numbers in a compact and standardized form.
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which value of x makes this inequality true? x+9<4x
Answer:
Step-by-step explanation:
x+9
Let x, be 4
4+9=13
given condition,
x+9<4x
4+9<4(4)
13<16
The answer is:
x > 3Work/explanation:
Our inequality is:
\(\sf{x+9 < 4x}\)
Flip it
\(\sf{4x > x+9}\)
Solve
\(\sf{4x-x > 9}\)
Combine like terms
\(\sf{3x > 9}\)
Divide each side by 3
\(\sf{x > 3}\)
Hence, x > 3What is the total number of digits required in numbering the pages of a book, which has 1,150 pages?
A house has decreased in value by 28% since it was purchased. If the current value is $90,000, what was the value when it was purchased?
Determine the percentile of 6.2 using the following data set.
4.2 4.6 5.1 6.2 6.3 6.6 6.7 6.8 7.1 7.2
Your answer should be an exact numerical value.
The percentile of 6.2 is |
%.
The percentile of 6.2 in the given data set is 40%.
To determine the percentile of 6.2 in the given data set, we can use the following steps:
Arrange the data set in ascending order:
4.2, 4.6, 5.1, 6.2, 6.3, 6.6, 6.7, 6.8, 7.1, 7.2
Count the number of data points that are less than or equal to 6.2. In this case, there are 4 data points that satisfy this condition: 4.2, 4.6, 5.1, and 6.2.
Calculate the percentile using the formula:
Percentile = (Number of data points less than or equal to the given value / Total number of data points) × 100
In this case, the percentile of 6.2 can be calculated as:
Percentile = (4 / 10) × 100 = 40%
The percentile of 6.2 in the sample data set is therefore 40%.
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AB and CD are straight lines. Find /n.
(help me pls)
Answer: 130°
Step-by-step explanation:
Since AB and CD are straight lines, we can use vertical angles theorem which tells us that angles that are on opposite sides of an intersection are congruent (equal in value).
Evaluate the given expression for x=5
x² + 3x - 2
(5)² + 3 × 5- 2
25 + 15 - 2
40 - 2
38...
Mr. and Mrs. Burnet's gross earnings total $5,825. How much of the amount earned is spent on
taxes and insurance?
Taxes, 15%
Entertainment,3%
Car/Gas, 9%
Insurance, 7%
College Fund,
10%
Utilities, 8%
Rent, 21%
Savings, 14%
Food, 8%
Clothing, 5%
Answer:
The Burnets spent .22 × $5,825 = $1,281.50 on taxes and insurance.
If p =(-4,6), find the image of p under the following rotation. 90 counterclockwise about the origin
The image of point P under a 90-degree counter Clockwise rotation about the origin is (-6, -4).
To find the image of point P = (-4, 6) after a 90-degree counterclockwise rotation about the origin, we can use the following formula:
(x', y') = (xcosθ - ysinθ, xsinθ + ycosθ)
where (x, y) are the coordinates of the original point, θ is the angle of rotation, and (x', y') are the coordinates of the rotated point.
In this case, θ = 90 degrees, so we have:
(x', y') = (-4cos90 - 6sin90, -4sin90 + 6cos90)
= (-6, -4)
Therefore, the image of point P under a 90-degree counterclockwise rotation about the origin is (-6, -4).
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If triangle ABC is reflected across the line y = x, are the pre-image and image congruent? Why, or why not?
OYes, distance and angle measure are preserved
OYes, angle measure is preserved and distance is not
O No, distance is preserved but angle measure is not
O No, neither distance nor angle measure are preserved
The correct answer is: O Yes, distance and angle measure are preserved.
When a triangle ABC is reflected across the line y = x, the pre-image and image are congruent.
This is because the line y = x is the perpendicular bisector of the segment joining each corresponding point of the pre-image and image.
Reflection across the line y = x is a type of transformation known as an isometry, which preserves both distance and angle measure.
Here's why:
Distance preservation:
When a point is reflected across the line y = x, the distance between the original point and its reflection remains the same.
This holds true for all corresponding points of the triangle.
Therefore, the distance between any two corresponding points in the pre-image and image triangle will be equal, resulting in distance preservation.
Angle preservation: When a line segment is reflected across the line y = x, the angle between the line segment and the line y = x is preserved. This means that the corresponding angles in the pre-image and image triangle will be congruent.
Since both distance and angle measure are preserved during reflection across the line y = x, the pre-image and image triangles are congruent.
It's important to note that congruence under reflection across a line holds only when the line of reflection is the same for both the pre-image and image.
If the line of reflection were different, the triangles would not be congruent.
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Zx and Zy are supplementary angles. Zy measures 116º.
What is the measure of Z?
The following outcomes were recorded when a dice was thrown 30 times
2,3,5,4,4,3,5,1,4,3,1,1,4,2,3,5,1,4,2,2,3,2,1,5,5,2,1,3,5,1
a. Prepare the frequency table for the data above
b.find the mean of the data
c.find the mode
The mean of the data is approximately 3.27, indicating the average value of the outcomes. The mode of the data is 1, 2, 3, and 5, representing the outcome(s) with the highest frequency.
a. To prepare the frequency table for the given data, we need to count the frequency of each outcome (numbers 1 to 6) in the list of outcomes.
Outcome | Frequency
--------|----------
1 | 6
2 | 6
3 | 6
4 | 5
5 | 6
6 | 1
b. To find the mean of the data, we sum up all the outcomes and divide by the total number of outcomes. In this case, we have 30 outcomes.
Mean = (2 + 3 + 5 + 4 + 4 + 3 + 5 + 1 + 4 + 3 + 1 + 1 + 4 + 2 + 3 + 5 + 1 + 4 + 2 + 2 + 3 + 2 + 1 + 5 + 5 + 2 + 1 + 3 + 5 + 1) / 30
= 98 / 30
≈ 3.27
Therefore, the mean of the data is approximately 3.27.
c. To find the mode of the data, we look for the outcome(s) with the highest frequency. In this case, outcomes 1, 2, 3, and 5 all have a frequency of 6, which is the highest frequency in the data set. Therefore, the mode of the data is 1, 2, 3, and 5.
In summary, the frequency table shows the frequency of each outcome from the data set.
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A mining company is considering two sites on which to dig, described as follows: Site A: Profit if diamonds are found: $80 million. Loss if no diamonds are found: $20 million. Probability of finding diamonds: 0.2 Site B: Profit if diamonds are found $140 million. Loss if no diamonds are found $17 million. Probability of finding diamonds: 0.1
The expected value is a weighted average generalization. The company must choose to mine on site A.
What is the expected value?The expected value is a weighted average generalization. Informally, the expected value is the arithmetic mean of a large number of independently chosen random variable outcomes.
To know on which site the company should mine, we need to calculate the expected profit that the company will get from each site. Therefore, the expected profit from each site will be,
Site A:
Expected profit = (0.2)($70 million) + (0.8)(-$15 million) = $2 million
Site B:
Expected profit = (0.1)($140 million) + (0.9)(-$21 million) = -$4.9 million
Since the value from Site B is negative, therefore, the company must choose to mine on site A.
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Pablo solved the polynomial equations given in the table. Determine whether each polynomial is correct. Select Correct or Incorrect for each equation.
Equation
(b²+7b-9)+(4b-6b²) = -8b² + 14b-9
(4a+6)-(3a²-9a+1)=-3a²+ 13a +5
(12c-8c²)+(5c²- 10c) = -3c²+2c
The first equation is incorrect.
The second equation is correct.
The third equation is correct.
Let's go through each equation and determine whether it is correct or incorrect:
(b²+7b-9)+(4b-6b²) = -8b² + 14b-9
To determine if this equation is correct, we need to simplify both sides and check if they are equal.
On the left side:
(b²+7b-9)+(4b-6b²) = b² - 6b² + 7b + 4b - 9 = -5b² + 11b - 9
On the right side:
-8b² + 14b - 9
Comparing both sides, we can see that -5b² + 11b - 9 is not equal to -8b² + 14b - 9. Therefore, the equation is incorrect.
(4a+6)-(3a²-9a+1)=-3a²+ 13a +5
Again, we need to simplify both sides of the equation and check if they are equal.
On the left side:
(4a+6)-(3a²-9a+1) = 4a + 6 - 3a² + 9a - 1 = -3a² + 13a + 5
On the right side:
-3a² + 13a + 5
Comparing both sides, we can see that -3a² + 13a + 5 is equal to -3a² + 13a + 5. Therefore, the equation is correct.
(12c-8c²)+(5c²- 10c) = -3c²+2c
Again, let's simplify both sides and compare them.
On the left side:
(12c-8c²)+(5c²- 10c) = 12c - 8c² + 5c² - 10c = -3c² + 2c
On the right side:
-3c² + 2c
Comparing both sides, we can see that -3c² + 2c is equal to -3c² + 2c. Therefore, the equation is correct.
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