Static electricity is a controlled burst of energy.
Answer:
True
a good ____ does not transfer heat easily
Answer:
a good insulator does not transfer heat easily.
An insulator does not conduct heat easily and does not leave the heat energy or else say transfer the heat quickly; also referred as poor conductors of heat.
Answer:
good insulater
Explanation:
Insulater just less transfers the heat and stores the heat in itself.All non metals are good insulaters and poor conductorsOnly graphite is a non metal which conduct electricity100 POINTS FOR THE CORRECT ANSWER/ EXPLANATION.
Answer:
d) 15.12 N
e) 15.12 N
Explanation:
Draw a free body diagram of the each block.
Block A has three forces on it: weight force mAg pulling down, normal force N pushing up, and tension force T pulling down.
Block B has two forces on it: weight force mBg pulling down, and tension force T pulling up.
Sum of forces on A in the y direction:
∑F = ma
T + N − mAg = mAa
N = mAa + mAg − T
N = mA (a + g) − T
Sum of forces on B in the y direction:
∑F = ma
T − mBg = mBa
T = mBa + mBg
T = mB (a + g)
Plug in values:
T = (1.80 kg) (-1.60 m/s² + 10 m/s²)
T = 15.12 N
N = (3.60 kg) (-1.60 m/s² + 10 m/s²) − 15.12 N
N = 15.12 N
So the answers to (d) and (e) are both 15.12 N.
A butcher grinds 5 and 3/4 lb of meat then sells it for 2 and 2/3 pounds to the customer what is the maximum amount me that the butcher can sell to the next customer
Answer:
The maximum amount of meat that the butcher can sell is \(3\frac{1}{12}\:lb\)
Explanation:
The maximum amount can be found by taking the difference of mixed numbers.
\(5\frac{3}{4}-2\frac{2}{3}\\\\\mathrm{Subtract\:the\:numbers:}\:5-2=3\\\\\mathrm{Combine\:fractions:\:}\frac{3}{4}-\frac{2}{3}=\frac{1}{12}\\\\=3\frac{1}{12}\\\)
Best Regards!
Eli is a 9-year-old and his friend has asked him to share his test answers. Eli refuses to let his friend cheat off his paper because he does not want to get in trouble with the teacher Given Eli’s age and response, which stage of moral development did he demonstrate:
Group of answer choices
Preoperational
Conventional
Preconventional
Postconventional
The stage of moral development Eli demonstrated is Preconventional.
The early stage of moral development can be seen in preconventional morality. Up until about age nine, it persists. Children's decisions at this age are mostly influenced by what adults expect of them and the repercussions of disobeying them.
Morality is externally regulated at the preconventional level. In order to avoid punishment or gain rewards, people abide by the rules that are set forth by authority figures. According to this viewpoint, what is morally correct depends on one's ability to get away with it or what will make them feel good about themselves.
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What is the “time constant” for a capacitor, and why is it important?
We know that in a RC circuit the voltage in the capacitor when is charging is given by:
\(V_C(t)=V_0(1-e^{-\frac{t}{RC}})\)when this is happening the voltage in the resistor is given by:
\(V_R(t)=V_0e^{-\frac{t}{RC}}\)In both equations V0 denotes the voltage given by the source, R is the resistance of the resistor and C is the capacitance of the capacitor.
We notice that in both expressions the product RC appear, this product is what we call the time constant of the capacitor; and it is important since it determines the time intervals in which the voltage, charges and currents chage in a RC circuit. This means that while the capacitor is charging or discharging the variables mentioned will always have the time constant in their expressions.
After coming down a slope, a 60-kg skier is coasting northward on a level, snowy surface at a constant 15 m>s. Her 5.0-kg cat, initially running southward at 3.8 m>s, leaps into her arms, and she catches it. (a) Determine the amount of kinetic energy converted to internal energy in the Earth reference frame. (b) What is the velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat’s kinetic energy does not change?
The velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat's kinetic energy does not change is equal to the velocity of the skier before the collision. The velocity of the skier before the collision is 15 m/s.
What is law of conservation of momentum?According to the law of conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision. This can be expressed as m1*v1 + m2*v2 = (m1 + m2)*vf, where m1 and m2 are the masses of the skier and the cat respectively, v1 is the velocity of the skier, and vf is the velocity of the skier and the cat after the collision.
The kinetic energy converted to internal energy in the Earth reference frame can be determined by applying the law of conservation of momentum.
The amount of kinetic energy converted to internal energy can be calculated as follows:
m1*v1 = (m1 + m2)*vf
vf = (m1*v1)/(m1 + m2)
KE = (1/2)*m2*v2²
KE converted = KE initial - KE final
KE converted = (1/2)*m2*v2² - (1/2)*m2*((m1*v1)/(m1 + m2))²
KE converted = (1/2)*m2*v2² - (1/2)*m2*((60*15)/(60 + 5))²
KE converted = (1/2)*5*3.8² - (1/2)*5*(15²/65)
KE converted = 28.8 - 22.15
KE converted = 6.65 J
The velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat's kinetic energy does not change is equal to the velocity of the skier before the collision.
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what would happen if both dogs pulled the rope with a force of 85 N?
the rope wouldnt move, the force of both dogs pulling us also called tension
Find the work done when the speed of a 3.00 kg object increases from rest to 23.0 m/sec.
Answer:
793.5 Joules
Explanation:
The work–energy theorem states that the net work done on an object equals the object’s change in kinetic energy.
So we can say W=ΔKE.
The equation for kinetic energy is
\(KE=\frac{1}{2}mv^2\)
Therefore
\(W=\frac{1}{2}mv_f^2-\frac{1}{2}mv_i^2\)
\(W=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}\)
We are given
\(m=3\)
\(v_i=0\)
\(v_f=23\)
Lets solve for \(W\).
\(W=\frac{3*23^2}{2}-\frac{3*0^2}{2}\)
\(W=\frac{3*23^2}{2}\)
\(W=\frac{3*529}{2}\)
\(W=\frac{1587}{2}\)
\(W=793.5\)
Help!!
A horse does 860 J of work in 420 seconds while pulling a wagon. What is the power output of the horse? Round your answer to the nearest whole number.
The power output of the horse is [???] W.
A 800-w iron is left on the ironing board with the base exposed to the air. About 85 percent of the heat generated by iron dissipate through its base with surface area of 0.15 ft2 . Calculate the amount of heat the iron dissipates in 2 hours, the heat flux on the surface of iron and total cost of electricity wasted in 2 hours if unit cost of electricity to be $0.11kwh.
Answer:
ΔQ = 4896 KJ
Heat Flux = 57407.55 W/m²
Cost = $ 0.176
Explanation:
The amount of heat dissipated in two hours can be given as:
\(Heat\ Dissipation = \Delta Q = Pt\eta\)
where,
P = Power of Iron = 800 W
t = time taken = 2 hrs
η = Conversion efficiency = 85% = 0.85
\(\Delta Q = (800\ W)(7200\ s)(0.85)\\\\\)
ΔQ = 4896 KJ
Now, for heat flux:
\(Heat\ Flux = \frac{P}{Surface\ Area}\\\\Heat\ Flux = \frac{800\ W}{0.15\ ft^{2}}\frac{1\ ft^{2}}{0.092903\ m^{2}}\)
Heat Flux = 57407.55 W/m²
Now, for total heat energy in KWhr in two hours:
\(Heat\ Energy = (Power)(Time)\\\\Heat\ Energy = (0.8\ KW)(2\ hr)\\\\Heat\ Energy = 1.6\ KWh\)
Now, for the cost:
\(Cost = (Heat\ Energy)(Unit\ Cost)\\Cost = (1.6\ KWh)(\$ 0.11\ /KWh)\)
Cost = $ 0.176
When a 5 kg object is converted to pure energy, how many times larger is this than the amount of energy the Earth receives from the Sun every second? A. 3 times as much B. 2 times as much C. 4 times as much D. Same amount of energy
The answer is energy 3 times as much. option A.
To calculate the amount of energy released when a 5 kg object is converted to pure energy, we can use Einstein's famous equation: E = mc². In this equation, E represents energy, m represents mass, and c represents the speed of light.
Given that the mass of the object is 5 kg, we can calculate the energy using the equation:
E = (5 kg) * (c²)
Now, to compare this energy with the amount of energy the Earth receives from the Sun every second, we need to determine the Earth's solar energy input.
The solar constant is the amount of solar radiation received per unit area at the Earth's distance from the Sun. Its average value is approximately 1361 Watts per square meter (W/m²). Multiplying this value by the surface area of the Earth (approximately 510 million square kilometers), we can estimate the total energy received by the Earth from the Sun every second.
Energy from the Sun = (1361 W/m²) * (510,000,000,000 m²)
To compare the energy released from converting a 5 kg object to energy with the energy received from the Sun, we divide the former by the latter:
Energy conversion / Energy from the Sun = [(5 kg) * (c²)] / [(1361 W/m²) * (510,000,000,000 m²)]
Simplifying the equation, we find:
Energy conversion / Energy from the Sun = (5 kg * c²) / (1361 W/m² * 510,000,000,000 m²)
The value of c² is approximately (3x10^8 m/s)² = 9x10^16 m²/s².
Plugging in the values, we get:
Energy conversion / Energy from the Sun = (5 kg * 9x10^16 m²/s²) / (1361 W/m² * 510,000,000,000 m²)
Simplifying further:
Energy conversion / Energy from the Sun ≈ 3.52
Therefore, the amount of energy released when a 5 kg object is converted to pure energy is approximately 3.52 times larger than the amount of energy the Earth receives from the Sun every second.
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An accelerating truck moves away from a motion detector. What is the shape of the d/t graph?
The shape of the acceleration - time graph will be linear.
What is acceleration of an object?The acceleration of an object is the rate of change of velocity with time.
a = Δv/Δt
where;
Δt is change in time of the object's motionΔv is change in velocity of the objectWhen the velocity of the object is constant, the acceleration of the object becomes zero.
When the velocity of the object is uniform, the object accelerates at a constant rate.
Shape of graph of acceleration vs timeIf the truck accelerates at a constant rate from the motion detector, the shape of the graph will be linear.
Thus, the shape of the acceleration - time graph will be linear.
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Select the correct answer.
What is the force that can cause two pieces of iron to attract each other?
A.
gravitational force
B.
magnetic force
C.
elastic force
D.
electrostatic force
Answer:
A. gravitational force always true.
B, C and D could be true under the correct conditions
In the diagram, R₁ = 40.0 , R2= 25.4 , and R3 = 70.8 . What is the equivalent resistance of the group?
According to the diagram the equivalent resistance of the group is
40.05 ohms
How to find the equivalent resistanceThe equivalent resistance is calculated by investigating the diagram to note that R2 and R3 are in parallel and both are in series to R1
Resistors in parallel is solved by
Resistors in parallel = 1/25.4 + 1/70.8
Resistors in parallel = 0.0535 ohms
Equivalent resistance
Equivalent resistance = Resistors in parallel + Resistor in series
Equivalent resistance = 0.0535 + 40
Equivalent resistance = 40.0535
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proof(how this formula comes )
vector
u.v=|u||v|cosβ
The formula you mentioned is known as the dot product formula or the scalar product formula. It is used to find the angle between two vectors u and v.
Let's start by defining the vectors u and v. Suppose we have two vectors u and v in a two-dimensional space.
u = (u1, u2)
v = (v1, v2)
The dot product of these vectors is defined as:
u . v = |u| |v| cos(β)
where |u| and |v| are the magnitudes of the vectors u and v respectively, and β is the angle between the vectors u and v.
Now, let's derive this formula. The dot product of two vectors u and v is given by:
u . v = (u1 × v1) + (u2 × v2)
The magnitude of a vector is given by:
|u| = sqrt(u1² + u2²)
|v| = sqrt(v1² + v2²)
We can use the dot product and magnitude equations to obtain:
cos(β) = (u . v) / (|u| × |v|)
Multiplying both sides by |u| × |v| gives us:
|u| × |v| × cos(β) = u . v
Therefore, we have derived the dot product formula:
u . v = |u| × |v| × cos(β)
This formula can be used to find the angle between two vectors u and v in any two-dimensional or three-dimensional space.
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The complete question is-
Write the proof of the formula
u.v=|u||v|cosβ
Earth's core is the source of the energy that drives the movement of tectonic
plates. Which two processes help transfer this energy outward to Earth's
crust?
D A. Subduction
DB. Convection
I C. Solar radiation
OD. Conduction
Answer:
B. Convection
D. Conduction
Explanation:
Conduction and convection are the two most prominent processes that helps transfer energy outward to the earth's crust.
Energy within the core is a function of the radioactive decay and frictional heating. Also, heat that accreted during the formation of the earth is a significant source of internal energy. The heat is conducted away by the process of convection. This is possible due to temperature differences between different parts of the earth Conduction is made made possible due to the metallic bodies in the core and other part of the inner earth.Answer:
B and D
Explanation:
I just did it on a p e x. In case your not sure
what kind of soil is most likely found in the desert
You and some friends are loading a moving truck. You get a heavy box to the top of the loading ramp which is angled at 15 degrees from the ground. The high end (top) of the ramp is 12.5 m above the ground. You accidently make the assumption that your friends had the box secure and stop pushing. The box begins to move down the ramp.
How long does it take to reach the bottom of the ramp?
Answer:
The time is \(t = 6.17 \ s \)
Explanation:
From the question we are told that
The angle is \(\theta = 15^o\)
The height is \(h = 12.5 \ m\)
Generally from SOHCAHTOA the length of the ramp can be evaluated as
\(L = \frac{h}{sin (\theta)}\)
=> \(L = \frac{12.5}{sin (15)}\)
=> \(L = 48.3 \ m \)
Generally fro kinematic equation this length is mathematically represented as
\(L = ut + \frac{1}{2} * g* sin (\theta )t^2\)
Here u = 0 m/s since the box started from rest
So
\( 48.3 = 0 + \frac{1}{2} * 9.8 * (sin(15))* t^2\)
\(t = \sqrt{ \frac{2 * 48.3 }{ 9.8 * sin (15)} }\)
\(t = 6.17 \ s \)
FM radio stations use radio waves with frequencies from 88.0 to 108 MHz to broadcast their signals. Assuming that the inductance in Figure 24.4 has a value of 6.00 × 10-7 H, determine the range of capacitance values that are needed so the antenna can pick up all the radio waves broadcasted by FM stations.
The range of capacitance values that are needed so the antenna can pick up all the radio waves broadcasted by FM stations is from 5.45 x 10⁻¹² H to 3.62 x 10⁻¹² H.
Resonance frequencyThe frequency at which the antenna can pick the radio waves broadcasted is known as resonance frequency.
At resonance frequency, the capacitive reactance is equal to inductive reactance.
Xc = Xl
\(\frac{1}{2\pi fC} = 2\pi fL\\\\4\pi^2 f^2 LC = 1\\\\C = \frac{1}{4\pi^2 f^2L}\)
where;
C is the capacitanceL is the inductancef is the frequencyWhen the frequency is 88 MHz, the capacitance is;
\(C = \frac{1}{4\pi^2 \times (88 \times 10^6)^2 \times (6\times 10^{-7})} \\\\C = 5.45 \times 10^{-12} \ H\\\\\)
When the frequency is108 MHz, the capacitance is;
\(C = \frac{1}{4\pi^2 \times (108 \times 10^6)^2 \times (6\times 10^{-7})} \\\\C = 3.62\times 10^{-12} \ H\\\\\)
Thus, the range of capacitance values that are needed so the antenna can pick up all the radio waves broadcasted by FM stations is from 5.45 x 10⁻¹² H to 3.62 x 10⁻¹² H.
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The answer by onyebuchinnaji is correct, except for the fact that the final answer is in Farad (F), not H.
On top labeled A 2 waves 1 above the other, with crests and troughs that line up. On bottom labeled B 2 waves, 1 above the other, so that the crests of the top wave line up with the troughs of the bottom wave.
Will there be noise cancellation in example A or example B?
Answer:
b
Explanation:
Answer:
B B*
Explanation:
B BBBBB
BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB
Scientists seek to acquire knowledge and understanding of the real world through the formulation, testing, and evaluation of what?
A. technology
B. scientific method
C. scientific hypothesis
D. deductive reasoning
Scientists seek to acquire knowledge and understanding of the real world through the formulation, testing, and evaluation of scientific hypotheses (Option C).
What are scientific hypotheses?Scientific hypotheses are explanations about questions of the real world that can be used to test them by using the scientific method, i.e., by testing them to confirm or reject their assumptions through experimental and observation procedures.
Therefore, with this data, we can see that a scientific hypothesis is formulated and tested by using the scientific method in order to confirm or reject its assumptions and thus build scientific knowledge.
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Answer:
Scientific hypothesis
Explanation:
Some dragonflies splash down onto the surface of a lake to clean themselves. After this dunking, the dragonflies gain altitude, and then spin rapidly at about 1100 rpm to spray the water off their bodies. When the dragonflies do this "spin-dry," they tuck themselves into a "ball" with a moment of inertia of 2.0×10−7kg⋅m2 . How much energy must the dragonfly generate to spin itself at this rate?
The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.
Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:
Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)
ω ≈ 115.28 rad/s
The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².
Use the formula for rotational kinetic energy:
Rotational Kinetic Energy (KE_rot) = (1/2) I ω²
Substituting the given values:
KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²
Calculate the value inside the parentheses:
KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)
KE_rot ≈ 1.331 × 10^-3 J
Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.
KE_rot ≈ 4.8 × 10^-4 J
Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.
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a) A ball is kicked with an initial velocity of 22 m/s at 35° degree angle. For how long does the ball remain in the air? b) What maximum height is attained by the ball
The time of flight is 2.57 s
The maximum height is 8.12 m
What is projectile motion?Projectile motion refers to the motion of an object that is launched into the air and then moves under the influence of gravity. A projectile is any object that is given an initial velocity and then moves freely under the influence of gravity, without any additional propulsion or guidance.
For the time of flight;
T = 2u sinθ/g
T = 2 * 22 * sin35/9.8
T = 2.57 s
Then the maximum height is;
H = u^2sin^2θ/2g
H = (22)^2 (sin 35)^2/2 * 9.8
H = 8.12 m
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What does a notational analysis do
Answer:
In professional sports, notational analysis is the study of movement patterns, strategy and tactics in team sports. Successful patterns of play can be identified and used in subsequent matches. Notational analysis has a history in dance and music notation.
A mother (mass 60.0 kg) skates across an ice rink with negligible friction toward her child (mass 20.0 kg), who is standing still on the ice. If the mother moves at 4.0 m/s before she picks up her child, what is her new speed after she picks up her child and holds onto him
We have that the new speed after she picks up her child is mathematically given as
V2=3m/s
SpeedThe speed of a body is simply the rate at which the body moves or functions, the speed of a body is measured with an SI unit of m/s.
Generally the equation for the Velocity is mathematically given as
m1v1=m2v2
Therefore
\(v2=\frac{60*4}{60+20}\)
V2=3m/s
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1. An object 2.25 mm high is 8.5 cm to the left of a convex lens of 5.5-cm focal length.
According to problem ( considering sign convention for convex lens)
height of object = 2.25 mm;
object distance(u)= - 8.5 cm
focal length (f)= 5.5 cm
image distance(v)= ?
Using lens formula
\(\begin{gathered} \frac{1}{f}=\text{ }\frac{1}{v}-\frac{1}{u}; \\ \therefore\frac{1}{5.5}=\text{ }\frac{1}{v}\text{ -}\frac{1}{-8.5} \\ \frac{1}{5.5}=\frac{1}{v}\text{ +}\frac{1}{8.5}; \\ \frac{1}{v}=\frac{1}{5.5}-\frac{1}{8.5}=\frac{3}{5.5\times8.5}=\frac{3}{46.75} \\ v=\frac{46.75}{3}=15.58\text{ cm} \end{gathered}\)a) Answer is :- Location of image = 15.58cm
Using magnification formula
\(\begin{gathered} Magnification\text{ =}\frac{height\text{ }of\text{ }image}{height\text{ of object}}=\frac{v}{u} \\ \therefore Magnification=\text{ }\frac{15.58}{8.5}\text{ =1.83} \\ \therefore\frac{height\text{ }ofimage}{2.25}\text{ =1.83;} \\ \therefore height\text{ of image = 1.83}\times2.25=4.12\text{ mm} \end{gathered}\)b) Height of image = 4.12 mm
C) Magnification= 1.83
The model shows the star Wolf 359, the sun, and Star X. It takes 7.8 years for light produced on Wolf 359 to reach the sun.
If Star X is 50 times as far from the sun as Wolf 359 is, how far is Star X from the sun, to the nearest light-year?
Answer:
390 light-years
Explanation:
50 x 7.8 =390
If you stand on a trampoline, it depresses under your weight. When you stand on a hard stone floor, __________. If you stand on a trampoline, it depresses under your weight. When you stand on a hard stone floor, __________. the floor deforms very slightly under your weight only if you are heavy enough does the floor deform at all under your weight the floor does not deform at all under your weight
Answer:
the floor deforms very slightly under your weight
Explanation:
A trampoline is made up of a large piece of strong cloth held by springs on which you jump up and down as a sport. So, If you stand on a trampoline, it depresses under your weight. However, the floor does not deform under your weight as it is too stiff.
Therefore,
when you stand on a hard stone floor, the floor deforms very slightly under your weight.
when an object (like a ball) falls, some of its _____ energy changes to _____ energy, due to the law of conservation of energy
a.) kinetic, potential
b.) kinetic, motion
c.) potential, kinetic
d.) motion, potential
Answer:
c ) potential your welcome heheThe half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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