True or false. test tubes, spot and/or well plate will be used to combine substances in bottles and form a reaction.

The concentration terms are molality, normality and mole fraction and percent by volume. Therefore, the proof of the ethanol in the solution is the percent by volume that is 45.4%.

The percent by volume formula calculates the concentration of the solution by using the volume of the solute (the dissolved content in the solvent) and the volume of the solution. It is represented as (v/v%).

Mathematically,

percent by volume=(volume of solute÷ volume of solution)×100

Volume of solute=56.2 ml

volume of solution=123.6 ml

Substituting all the given values in the given formula, we get

percent by volume=(56.2 ÷ 123.6)×100

                              =45.4%

Therefore, the proof of the ethanol in the solution is the percent by volume that is 45.4%.

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preferAnswer:

The octet rule refers to the tendency of atoms to prefer to have eight electrons in the valence shell. When atoms have fewer than eight electrons, they tend to react and form more stable compounds. Atoms will react to get in the most stable state possible

Explanation:

Hopefully this is what your looking for

Based on the atomic structure of the given elements, the atoms in each pair having the larger atomic radii are as follows:

The atomic radius of an atom is the radius of the atom of an element.

It is measured as half the distance between the nucleus of two covalently bonded atoms of the element.

The atomic radius of an atom increases with an increase in electron shells or orbital but decreases with an increase in atomic number in atoms with the same number of electron shells.

Comparing the atomic radii of the given elements:

1. Li or Cs - Cs has the larger atomic radii because of greater atomic orbitals

2. K or Br - K has a greater atomic radius because it has a smaller atomic number with the same number of orbitals as Br.

3. Li or Fluorine - Li has a greater atomic radius because it has a smaller atomic number with the same number of orbitals as Fluorine.

4. C or Pb - Pb has the larger atomic radii because of greater atomic orbitals

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Answer:

2.43 grams are needed

Explanation:

I did the test

Hope this helps :)

P(C|G) = P(C and G) / P(G)

Given that the probability of a student taking Chemistry AND Geology is 0.08 (P(C and G) = 0.08) and the probability of a student taking Geology is 0.45 (P(G) = 0.45), we can substitute these values into the formula:

P(C|G) = 0.08 / 0.45 ≈ 0.1778

Therefore, the probability that a student will choose Chemistry given that the student is taking Geology is approximately 0.1778, or 17.78%.

P(Disease|Positive) = (P(Positive|Disease) * P(Disease)) / P(Positive)

Given that the disease is common in 3% of the population (P(Disease) = 0.03), the error rate for people who are disease-free getting a positive reaction is 7% (P(Positive|Disease-free) = 0.07), and the error rate for people who have the disease getting a negative reaction is 2% (P(Negative|Disease) = 0.02), we can calculate the probability of a positive result (P(Positive)) as follows:

P(Positive) = (P(Positive|Disease) * P(Disease)) + (P(Positive|Disease-free) * P(Disease-free))

= (0.98 * 0.03) + (0.07 * 0.97)

≈ 0.0294 + 0.0679

≈ 0.0973

Now, we can substitute these values into Bayes' theorem:

P(Disease|Positive) = (0.98 * 0.03) / 0.0973

≈ 0.0294 / 0.0973

≈ 0.3026

Therefore, the probability that a person tested at random indeed has the disease given that the test result shows positive is approximately 0.3026, or 30.26%.

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The number of moles of gold deposited in 45 minutes by a constant current of 8.0 A can be calculated using the formula:

moles of gold deposited = (current x time) / (96500 x Faraday constant)

where the Faraday constant is 96485.33 C/mol.

Now, let's explain how to use this formula to calculate the number of moles of gold deposited. First, we need to convert the time of 45 minutes to seconds, which is 2700 seconds. Then, we can substitute the given values into the formula:

moles of gold deposited = (8.0 A x 2700 s) / (96500 C/mol x 96485.33 C/mol)

moles of gold deposited = 0.00202 mol

Therefore, the number of moles of gold deposited in 45 minutes by a constant current of 8.0 A is 0.00202 mol.

We used the formula that relates the amount of substance deposited during an electrolytic process to the current, time and Faraday constant. The Faraday constant is a conversion factor that relates the charge passed during the electrolytic process to the amount of substance deposited. We converted the time from minutes to seconds and substituted the given values into the formula to find the number of moles of gold deposited. This calculation assumes that the entire amount of AuCl3 is reduced to gold during the electrolytic process.

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Answer:

a) 1.567 x 10^9

b) 2.36 x 10^(-5)

Answer:

Ksp= 7.98 × 10^-13

Explanation:

According to the question, we are to calculate the solubility constant (Ksp) of Zinc carbonate (ZnCO3) in a dissolved solution.

The equilibrium of the reaction is:

ZnCO3 (aq) ⇌ Zn2+ (aq) + CO32- (aq)

According to this; 1 mole of Zinc carbonate (ZnCO3) dissolves to give 1 mole of Zinc ion (Zn2+) and 1 mole of carbonate ion (CO32-).

This illustrates that:

(Zn2+) = 1.12 x 10-4 g/L

(CO32-) = 1.12 x 10-4 g/L

However, 1.12 x 10-4 g/L is the solubility in mass concentration of ZnCO3, we need to convert it to molar concentration in mol/L by dividing by the relative molar mass of ZnCO3.

To calculate the molar mass of ZnCO3, we say:

Zn (65.4) + C (12) + 03 (16×3)

= 65.4+12+48

= 125.4g/mol.

Hence, molar concentration= 1.12 x 10-4 g/L / 125.4 g/mol

= 8.93 × 10^-7 mol/L.

Therefore;

Zn2+) = 8.93 x 10-7 mol/L

(CO32-) = 8.93 x 10-7 mol/L

Ksp = [Zn2+] [CO32-]

Ksp = (8.93 x 10-7) × (8.93 x 10-7)

Ksp = 7.98 × 10^-13

Answer:

D)

Explanation:

CH4 + 2O2 = CO2 + 2H2O

1 (L CO2)= 32.5(L CO2)

1 (CH4) = 32.5 (L CH4)

Equilibrium is a state in a chemical reaction where the rate of the forward reaction is equal to the rate of the reverse reaction, resulting in no net change in the concentrations of reactants and products. It is represented by a double arrow (⇌) in chemical equations. In the given equation: H₂O (g) + CO (g) ⇌ H₂(g) + CO₂(g) + 42 KJ

To shift the equilibrium to the right, one or more of the following could occur:

Increasing the concentration of H₂ or CO₂

Decreasing the concentration of H₂O or CO

Increasing the pressure

Removing some of the products (H₂ and CO₂)

Decreasing the temperature

To shift the equilibrium to the left, one or more of the following could occur:

Decreasing the concentration of H₂ or CO₂

Decreasing the pressure

Increasing the temperature

If pressure is increased, the equilibrium will shift in the direction that produces fewer moles of gas. In this case, since there are fewer moles of gas on the right side of the equation (H₂ and CO₂), the equilibrium will shift to the right. If heat is added, the equilibrium will shift in the endothermic direction to absorb the additional heat. In this case, the forward reaction is endothermic (42 KJ on the right side), so the equilibrium will shift to the right to consume the added heat.

If CO is added, the equilibrium will shift to the right to consume the additional CO.The concentration of H₂O and CO₂ will increase, while the concentrations of H₂ and CO will decrease until a new equilibrium is reached.

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When an organism's cells only have one set of chromosomes, the organism is said to be haploid. All organisms that reproduce sexually are diploid (having two sets of chromosomes, one from each parent). Only the egg and sperm cells in humans are haploid.

The term "diploid" describes an organism's cells having two full sets of chromosomes, with one chromosome from each parent present in each pair. Since humans are diploid, the majority of their cells have 23 pairs of chromosomes.

Distinguish between haploid and diploid.

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Answer:

Explanation:

3

Significant figures are the number of digits that add to the correctness of a value, frequently a measurement. The following numbers are three significant digits 876000, 1.20 x 10⁵, and 8.77 x 10⁻⁴.

The number of significant single digits (0 to 9 inclusive) in the coefficient of expression in the scientific notation is referred to as "significant figures" (SF). The expression's number of significant figures reveals the engineer's or scientist's level of assurance or precision when expressing a quantity.

When a number is rounded off, its value is maintained but is brought closer to the next number, simplifying the number. The crucial figures are preserved when numbers are rounded off.

The following numbers are rounded off:

1. 876000

2. 1.20 x 10⁵

3. 8.77 x 10⁻⁴

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There is the formation of intermolecular hydrogen bonding in ethanol as shown in the model below.

Intermolecular interactions can arise when ethanol, a common alcohol, is liquid. These interactions result from the ethanol molecule's polarity and hydrogen bonding propensity.

Two carbon atoms, five hydrogen atoms, and one oxygen atom make up the compound ethanol (C2H5OH). Because the oxygen atom is more electronegative than the carbon and hydrogen atoms, they are bound together by a polar covalent bond.

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The approximate concentration of reaction product in a solution that has an absorbance of 0.7 at ph 6.0 is based on the equation A = εbc given in the passage, the concentration c is the absorbance A divided by the absorptivity ε in a 1 cm path length cell. 0.7 divided by approximately 1400 gives 500 μM.

A = εbc

0.7 = 1400 x c

7/14000 = 1/2000 = 0.0005 = 5x10^-4 = 500 μM

1 μM = 1 x10 ^-6

The concentration of a substance is the amount of solute present in a given volume of solution. Concentration is usually expressed in molarity, defined as the number of solutes in 1 L of solution. Solution concentration is a measure of the amount of solute dissolved in a given amount of solvent or solution.

Concentrated solutions are solutions that contain relatively large amounts of solutes. Dilute solutions are solutions that contain relatively small amounts of solutes. The definition of concentration means the amount of an ingredient or part relative to other ingredients or parts. An example of concentration is the amount of salt to water in a brine solution.

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Minimum qualifications of Astronomer 4 year degree to get a postgraduate qualification like a master of physics.

2 or 3 A levels, or similar, in math and physics; 5 GCSEs at grades 9 to 4 (A* to C), or equivalent; and a degree in a field that is useful for postgraduate study.

Math and physics expertise, analytical thinking abilities, science knowledge, great verbal communication skills, the capacity to take initiative, and the capacity to think coherently utilizing logic and reasoning are all desirable. To be extremely knowledgeable about computer applications and systems.

A scientist who concentrates their research on a particular issue or area outside the purview of Earth is called an astronomer in the science of astronomy. In either observational or theoretical astronomy, they observe celestial bodies like stars, planets, moons, comets, and galaxies.

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Therefore, approximately 2.61 liters of the 0.325 M K2CrO4 stock solution are needed to prepare 4.00 L of the 0.212 M K2CrO4 solution.

To determine the volume of the stock solution needed to prepare the desired concentration, we can use the equation:

C1V1 = C2V2

Where:

C1 = concentration of the stock solution

V1 = volume of the stock solution

C2 = desired concentration

V2 = desired volume

Plugging in the given values:

C1 = 0.325 M

V1 = ?

C2 = 0.212 M

V2 = 4.00 L

Solving for V1:

C1V1 = C2V2

0.325 V1 = 0.212 * 4.00

0.325 V1 = 0.848

V1 = 0.848 / 0.325

V1 ≈ 2.61 L

Therefore, approximately 2.61 liters of the 0.325 M K2CrO4 stock solution are needed to prepare 4.00 L of the 0.212 M K2CrO4 solution.

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ANSWER

The number of moles of Pb(SO4)2 is 1.5 moles

EXPLANATION

Given that;

The mass of Li2SO4 is 330g

Follow the steps below to find the moles of Pb(SO4)2

Step 1; Write the balanced equation of the reaction

Step 2; Find the number of moles of Li2SO4 using the below formula

Recall, that the molar mass of Li2SO4 is 109.94 g/mol

The number of moles of Li2SO4 is 3.00 moles

Step 3; Find the number of moles of Pb(SO4)2 using a stoichiometry ratio

In the above equation of the reaction, 1 mole Pb(SO4)2 reacts to give 2 moles LiSO4

Let the number of moles of Pb(SO4) be x

Therefore, the number of moles of Pb(SO4)2 is 1.5 moles

Answer:

\(\boxed {\boxed {\sf 81.4 \ g\ KOH}}\)

Explanation:

We are asked to convert 1.45 moles of potassium hydroxide (KOH)  to grams.

The molar mass is the mass in grams of 1 mole of a substance. The values are found on the Periodic Table. They are the same as the atomic masses but the units are grams per mole (g/mol) instead of atomic mass units (amu).

We have the compound KOH. Look up the molar masses of the individual elements.

The formula for the compound has no subscripts, so there is 1 mole of each element in 1 mole of the compound. We can simply add the molar masses.

Based on the molar mass, there are 56.105 grams of KOH in 1 mole. Create a ratio using this information.

\(\frac {56.105 \ g\ KOH}{ 1 \ mol \ KOH}\)

We are converting 1.45 moles of KOH to grams, so we multiply by this value.

\(1.45 \ mol \ KOH *\frac {56.105 \ g\ KOH}{ 1 \ mol \ KOH}\)

The units of moles of KOH cancel.

\(1.45\ *\frac {56.105 \ g\ KOH}{ 1 }\)

\(81.35225 \ g\ KOH\)

The original measurement of moles has 3 significant figures, so our answer must have the same.

For the number we calculated, that is the tenths place. The 5 in the hundredths place (81.35225) tells us to round the 3 up to a 4.

\(81.4 \ g\ KOH\)

Approximately 81.4 grams of potassium hydroxide are represented by 1.45 moles.

The limiting reactant​ : Fe

Reaction

3Fe + 4H₂O ⇒ Fe₃O₄ + 4H₂

mass of H₂O = 10 g

mol H₂O (MW=18 g/mol) :

\(\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{10}{18}=0.56\)

mass of Fe = 16.8 g

mol Fe(MW=56 g/mol) :

\(\tt mol=\dfrac{16.8}{56}=0.3\)

Limiting reactant : the smallest ratio between mol : reaction coefficient

Fe :

\(\tt \dfrac{0.3}{3}=0.1\)

H₂O :

\(\tt \dfrac{0.56}{4}=0.14\)

Fe as limiting reactant

Answer:

A) Scandium

B)

C) Gallium

D

The following statements on HPLC modes are true is more polar compounds elute first in normal-phase HPLC (Option E).

The liquid chromatography (HPLC) is a technique in analytical chemistry employed for the separation, identification, and quantification of elements. It is considered a highly sensitive method, and it works by separating the components in a mixture with the assistance of a solvent under high pressure.

There are two modes of HPLC: Reversed-Phase HPLC (RP-HPLC) and Normal-Phase HPLC (NP-HPLC). In RP-HPLC, a nonpolar stationary phase, such as C18, is used, and polar solvents, such as water, are used as mobile phases. Polar stationary phases, such as silica gel, are used in NP-HPLC, while nonpolar solvents, such as hexane, are used as mobile phases.

More polar compounds have a greater affinity for the polar stationary phase than less polar compounds, which have a higher affinity for the nonpolar mobile phase in NP-HPLC. As a result, less polar compounds elute first in normal-phase HPLC.

Thus, the correct option is E.

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Answer:

1.44 L

Explanation:

If the temp does not change

P1V1 = P2V2

1 * 3.6   = 2.5 * V2

V2 = 1.44 L

Answer:

Nitrogen will called as atom or molecule or ion too in the state which it exist means in which form it is present . 

Answer:

steam and methane

Explanation:

The rate of decomposition of XO2 after 1 hour : \(\tt A=A_o.e^{-1.08}\)

Given

the half-life 38.6 min

time of decomposition = 1 hour

Required

the rate of decomposition

Solution

First-order reaction :

\(\tt A=A_o.e^{-kt}\)

the half life=t1/2 :

\(\tt t\frac{1}{2}=\dfrac{ln~2}{k}\)

so the rate constant (k) :

\(\tt k=\dfrac{ln~2}{38.6}=0.018\)

The rate after 1 hour=60 min :

\(\tt A=A_o.e^{-0.018\times 60}\\\\A=A_o.e^{-1.08}\)

Answer:

Nuclear scientists continue to expand the periodic table as they detect new elements. ... Scientists create heavy elements by bombarding two lighter elements that together add up to the mass of the desired new element. One of the elements is stationary and thus called the target.

Hydrochloric acid isa acid so color is red .

#2

Here is the balanced equation

\(\\ \rm\Rrightarrow Na_2CO_3+2HCl\longrightarrow 2NaCl+H_2CO_3\)

1 mol Na_2CO_3 takes 2mol HCL

1mol is 22.4L

moles of Na_2CO_3:-

Moles of HCl=0.36(2)=0.72mol