Turbine blades are generally more susceptible to operating damage than compressor blades because of Question 2 options: exposure to high temperatures less exposure to solution during engine pressure wash the high probability of carbon deposits

A) 3/4 ÷ 5 1/5.

Answer:

\( \frac{15}{104} \)

B) 3/7 ÷ 2 1/2.

Answer:

\( \frac{6}{35} \)

C) 5/8 ÷ 6 5/6.

Answer:

\( \frac{15}{164} \)

D) 8 3/10 ÷ 5/8.

Answer:

\(13 \frac{7}{25} \)

Answer:

B, D

Step-by-step explanation:

answer is BC=4

notice that the starting point is A and the endpoint is C, it stated that from A to B the value is 7 and from A to C the value is 11 we just need to subtract AC-AB to find the third value of it

AC-AB= 11-7 =4

Answer:

21/50, 42%

Step-by-step explanation:

The total times the coin was flipped is 50 and the number of times it landed on tails is 50-29=21. So we need to divide 21 by 50, which gives us 42%.

Since all three principles of experimental design are likely to have been used in the study described, Therefore option D is correct.

All of the above are principles of experimental design. Randomization helps to ensure that groups are similar in all aspects except for the treatment received, reducing the effects of confounding variables. Replication allows for assessing the variability and consistency of results. Blinding reduces the risk of bias by preventing participants or researchers from knowing which treatment was received. The study described in the question uses all of these principles of experimental design.

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The use of semaphores ensures that no thread starts ordering before everyone has arrived. This solution ensures that the three people are synchronized and avoids any potential ordering conflicts or confusion.

To implement this scenario using threads and semaphores, we can create three threads representing each person and use a semaphore to ensure they wait for the last person to arrive before they start ordering.

Initially, the semaphore is set to zero, which means all threads will be blocked until the semaphore value is incremented to three, indicating that all three people have arrived.

Each thread will decrement the semaphore value upon arrival, and then wait for the semaphore to be incremented back to three before continuing with the order. Once the semaphore value reaches three, all threads can proceed with ordering

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Answer:

C. 5.25 cups

Step-by-step explanation:

There are 8 fluid oz in 1 cup. Simply divide 42 by 8 to find you number of cups!

Answer:

g(3) = 4

Step-by-step explanation:

The question means what is the value of y when x = 3

Locate x = 3 on the x- axis. Go vertically up until the dot is met and read off the corresponding value on the y- axis, that is y = 4

Thus when x = 3 then y = 4, or

g(3) = 4

The value of g(3) from the graph given is 4

The given diagram is a graph in the xy-plane with different coordinate points.

Hence we can conclude that the value of g(3) is 4

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Answer:

See answers below

Step-by-step explanation:

Given the function:

f(x) = 0.15x + 900

a) f(80) = 0.15(80) + 900

f(80) = 12 +  900

f(80) = 912

b)  f(120) = 0.15(120) + 900

f(120) = 18 +  900

f(120) = 918

c) f(200) = 0.15(200) + 900

f(200) = 30 +  900

f(200) = 930

d)  f(56) = 0.15(56) + 900

f(56) = 8.4 +  900

f(56) = 908.4

Answer:

A = 56 Sq.in

Step-by-step explanation:

A = H x B/2

A = 8 x 14

= 112/2

= 56

THank you!!

Answer:

i don't know sorry

Answer:

See below.

Step-by-step explanation:

There is an infinite n umber of systems of equations that has (1, 4) as its solution. Are you given choices? Try x = 1 and y = 4 in each equation of the choices. The set of two equations that are true when those values of x and y are used is the answer.

Hello! My name is Chris and I’ll be helping you with this problem.

Date: 9/28/20 Time:  11:06 am CST

Answer:

-6.2

Explanation:

-2 (3.1) = -6.2

I hope this helped answer your question! Have a great rest of your day!

Furthermore,

Chris  

An expression for the given model can be simplified as -x - 2.

Given a model.

The model consists of 2 times x and 3 times -x.

This can be written as 2x + (3 × -x) = 2x - 3x = -x

It also consists of some 1's and '-1's.

In the first column, there are 3 1's = 3

Next, there are 2 1's and 1 '-1' = 2 + -1 = 1

Next, there are 3 '-1's = -1 + -1 + -1 = -3

Next also = -1 + -1 + -1 = -3

So summing up all these,

Expression is -x + 3 + 1 - 3 - 3 = -x - 2

Hence the required expression is -x - 2.

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Answer:

S = {1, 2, 3, 4, 5, 6, 7, 8} this is the answer

The system of linear inequalities to model the situation is 10x + 20y ≤ 100 and y > 2x

From the question, we have the following parameters that can be used in our computation:

Using the following representations:

We have the following system of inequalities from the given statements

10x + 20y ≤ 100

y > 2x

Hence, the system of inequalities is 10x + 20y ≤ 100 and y > 2x

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Answer: 1 and 7/15

Step-by-step explanation:

I made the common donominator 15 and then did the problem but the donominator stays the same

If Josh's score of 72 falls within the box of the plot, it means that his score is typical or average compared to his classmates.

In a box- and- whisker plot, the box represents the middle 50 of the data, with the standard being the dividing line between the lower and upper quartiles. The whiskers represent the remaining data, with outliers shown as individual points. Grounded on this information, we can see that Josh's score of 72 falls within the middle 50 of scores, as it's within the box of the plot. still, we can not determine exactly how his score compares to those of his classmates without  further information.  

Minimum score: 50

Lower quartile (Q1): 65

Median (Q2): 75

Upper quartile (Q3): 85

Maximum score: 95

Josh's score: 72

Using the steps outlined previously:

Q1 = 65, Q2 = 75, Q3 = 85

IQR = Q3 - Q1 = 85 - 65 = 20

Minimum score = 50, Maximum score = 95

Since Josh's score (72) falls within the IQR (65 ≤ 72 ≤ 85), we compare it to the median:

Josh's score is less than the median, so approximately 50% of his classmates scored higher than Josh, and approximately 50% scored lower.

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The value of the expression (3x - 12) + (xy - 10) is 14.

One mathematical expression makes up a term. It might be a single variable (a letter), a single number (positive or negative), or a number of variables multiplied but never added or subtracted. Variables in certain words have a number in front of them. A coefficient is the number used before a phrase.

Given expression:

(3x - 12) + (xy - 10).

To find the value of expression when x = 4 and y = 6:

Substitute the value of x and y to the expression,

(3x - 12) + (xy - 10)

= {3(4) - 12} + {(4)(6) - 10}

First, we solve the parenthesis.

= {12 - 12} + {24-10}

= {0} + {14}

= 0 + {14}

=  {14}

= 14

Therefore, the value is 14.

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Answer:

i think the answer is $270.00 if this is right mark me brainlist

Answer:

G(x) = 3x +2

Step-by-step explanation:

I do not know what the problem is asking for, but if it's asking for the function, here you go.

Answer:

shbdhsjdcjsvdbssegehehhehehejrjehe

Answer:

15, 17, 19, 21, 23

Step-by-step explanation:

First, let the lowest odd integer be x

When I see the word "is" in any question, it implies an equal sign.

So,

sum of the first 3 integers = 7 more than the sum of the last two

I also see the word "more", which implies that you have to add.

sum of the first 3 integers = 7 + the sum of the last two

As well, "sum" implies addition, so I know I have to add the first three integers. We know that x is the first one, so if I add two, I will get the next odd integer, and so on. (I put brackets to make it easier to see the three different numbers)

(x) + (x+2) + (x+4) = 7 + (x+6) + (x+8)

I knew to add 2 because it is a consecutive odd integer, so adding two will skip the even number and give me the next odd number.

Now, I can add like terms:

3x + 6 = 2x + 21

3x - 2x = 21 - 6

x = 15

x is the first number so, I just put down the next 4 odd integers after 15.

15, 17, 19, 21, 23

Answer:

A rational number

Step-by-step explanation:

A rational number is a number that can be made by dividing two integers (an integer is a number with no fractional part). The word comes from "ratio". A fraction can be divided and when it is it is a rational number.

No, there is no commutative property of subtraction for rational numbers. The commutative property, which states that the order of operands does not affect the result of an operation, does not apply to subtraction for rational numbers.

The commutative property states that the order of the operands does not affect the result of an operation. For addition and multiplication, the commutative property holds true. However, for subtraction, the order of the operands does matter, and thus, the commutative property does not apply.

Let's consider an example to demonstrate this:

Take the rational numbers 3/4 and 1/2.

If we subtract 3/4 from 1/2, we have: 1/2 - 3/4 = (2/4) - (3/4)

= -1/4.

If we subtract 1/2 from 3/4, we have: 3/4 - 1/2 = (3/4) - (2/4)

= 1/4.

As you can see, the results are different when the order of subtraction is changed, indicating that subtraction does not follow the commutative property for rational numbers.

The commutative property, which states that the order of operands does not affect the result of an operation, does not apply to subtraction for rational numbers. Changing the order of subtraction changes the result, making subtraction non-commutative for rational numbers.

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The commutative property does not apply to the operation of subtraction with rational numbers. This is because changing the order of the numbers in a subtraction operation will give a different result.

In mathematics, the commutative property refers to the idea that the order in which numbers are used in an operation does not change the result of that operation. This property holds true for addition and multiplication but, unfortunately, it does not hold true for subtraction and division. For example, in subtraction, if we take two rational numbers such as 5 and 3, 5 - 3 is equal to 2, but 3 - 5 equals to -2. As you can see, changing the order of the numbers gives us different results, demonstrating that there is no commutative property of subtraction for rational numbers.

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Answer:2693

Step-by-step explanation:

The drive-thru is able to estimate their wait time more consistently will be A. Burger Quick, because it has a smaller IQR.

The range of values in the middle of the scores is known as the interquartile range, or IQR. The appropriate measure of variability is the interquartile range when a distribution is skewed and the median is used instead of the mean to show a central tendency.

The correct option here is Burger Quick, because it has a smaller IQR (Interquartile Range). IQR is the difference between the third quartile and the first quartile, which is represented by the box in the box plot. In this case, the IQR for Burger Quick is 24 - 9.5 = 14.5, while the IQR for Fast Chicken is 14.5 - 10 = 4.5. A smaller IQR indicates that the data is more consistent and less spread out.

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One box of oaties will be enough for two groups of children.

We can state the box of oaties is enough for everyone, if the amount required by number of children in each group is less than or equal to 12.

So, amount of cereal required by younger/older children = amount required by one child × number of children

Amount of cereal required by younger children = 1/3 × 11

Amount of cereal required by younger children = 11/3 cups of cereal

Amount of cereal required by older children = 3/4 × 10

Amount of cereal required by younger children = 15/2 cups of cereal

Amount of cereal = 12 - (11/3 + 15/2)

Taking LCM in the bracket, we get 6

Amount of cereal = 12 - (11×2 + 15×3/6)

Solving the bracket

Amount of cereal = 12 - (22 + 45/6)

Performing addition = 12 - (67/6)

Amount of cereal = (12×6 - 67)/6

Amount of cereal = 72 - 67/6

Performing subtraction in numerator

Amount of cereal = 5/6

As 5/6 cups of cereal is remaining, thus, a box of oaties will be enough for 11 younger children and 10 older children.

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The complete question is -

Diane serves breakfast to two groups of children at a daycare center. One box of oaties contains 12 cups of cereal. She needs 1/3 cup for each younger child and 3/4 cup for each older child. Todays group includes 11 younger children and 10 older children. Is one box of oaties enough for everyone?

The first two numbers in each row of the relative frequency table represent the percentage of cars and trucks of a particular color out of the total number of vehicles in the parking lot.

To create a relative frequency table, we need to divide the frequency of each color by the total number of vehicles (65) and then multiply by 100 to get a percentage.

Relative Frequency Table by Color:

The first two numbers in each row must add up to 100% because we are calculating the relative frequency of each color with respect to the total number of vehicles (65). Therefore, the percentage of cars and trucks of each color must add up to 100% of that color's total frequency. The total row must also add up to 100% because it represents the entire population of vehicles.

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The given question is incomplete, the complete question is:

There are 65 vehicles in a parking lot. The frequency table shows data about the types and colors of the vehicles. Complete a relative frequency table to show the distribution of the data with respect to color. Use pencil and paper. Explain why the first two numbers in each row must add up to 100%. Frequency Table Type of Vehicle Color Car Truck Total Blue 22 14 36 Red 12 17 29 Total 34 31 65

The solution to the differential equation D²y(t) + 12 Dy(t) + 36y(t) = 2 \(e^{(-5t)}\), with initial conditions y(0) = 1 and Dy(0) = 0, is \(y(t) = (1 + 6t) e^{(-6t)}\).

To solve the given differential equation using the classical method, we can assume a solution of the form \(y(t) = e^{(rt)}\) and find the values of r that satisfy the equation. We then use these values of r to construct the general solution.

Using the classical method:

Substitute the assumed solution \(y(t) = e^{(rt)}\) into the differential equation:

D²y(t) + 12 Dy(t) + 36y(t) = \(2 e^{(-5t)}\)

This gives the characteristic equation r² + 12r + 36 = 0.

Solve the characteristic equation for r by factoring or using the quadratic formula:

r² + 12r + 36 = (r + 6)(r + 6)

= 0

The repeated root is r = -6.

Since we have a repeated root, the general solution is y(t) = (c₁ + c₂t) \(e^{(-6t)}\)

Taking the first derivative, we get Dy(t) = c₂ \(e^{(-6t)}\)- 6(c₁ + c₂t) e^(-6t).\(e^{(-6t)}\)

Using the initial conditions y(0) = 1 and Dy(0) = 0, we can solve for c₁ and c₂:

y(0) = c₁ = 1

Dy(0) = c₂ - 6c₁ = 0

c₂ - 6(1) = 0

c₂ = 6

The particular solution is y(t) = (1 + 6t) e^(-6t).

Using the Laplace transform method:

Take the Laplace transform of both sides of the differential equation:

L{D²y(t)} + 12L{Dy(t)} + 36L{y(t)} = 2L{e^(-5t)}

s²Y(s) - sy(0) - Dy(0) + 12sY(s) - y(0) + 36Y(s) = 2/(s + 5)

Substitute the initial conditions y(0) = 1 and Dy(0) = 0:

s²Y(s) - s - 0 + 12sY(s) - 1 + 36Y(s) = 2/(s + 5)

Rearrange the equation and solve for Y(s):

(s² + 12s + 36)Y(s) = s + 1 + 2/(s + 5)

Y(s) = (s + 1 + 2/(s + 5))/(s² + 12s + 36)

Perform partial fraction decomposition on Y(s) and find the inverse Laplace transform to obtain y(t):

\(y(t) = L^{(-1)}{Y(s)}\)

Simplifying further, the solution is:

\(y(t) = (1 + 6t) e^{(-6t)\)

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