Two aliens in another universe travel in spacecrafts that start of moving perfectly parallel to each other. The spacecraft send signals to each other to measure the distance between them. After travelling for millions of years, the aliens observe that the spacecraft are getting further apart even though neither spacecraft has changed its direction. What can we conclude

Weight of the box 100 lbs.friction factor for the box onthe ground = 0.18.what tension t must becreated by motor m to startmotion. The tension created by motor M to start the motion must be 18 lbs.

To determine the tension required to start the motion of the box, we need to consider the forces acting on the box.

1. First, let's calculate the force of friction acting on the box. The frictional force can be found using the equation: Frictional Force = Friction Coefficient * Normal Force

 
Given that the friction factor for the box on the ground is 0.18 and the weight of the box is 100 lbs, we can calculate the normal force as the weight of the box, which is 100 lbs.
Frictional Force = 0.18 * 100 lbs
 
2. Now, we need to consider the force required to start the motion. This force is equal to the tension in the rope connected to the box. Let's call this force T.

3. Using the force equilibrium equation, we can set up the following equation:

T - Frictional Force = 0

Since the box is just about to start moving, the net force acting on it is zero. Therefore, the tension force must be equal to the frictional force for the motion to start.
T - (0.18 * 100 lbs) = 0

4. Solving for T, we have:
T = 0.18 * 100 lbs
T = 18 lbs
Therefore, the tension T required to start the motion is 18 lbs.

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Telomeres play a crucial role in the aging process by protecting the integrity of the chromosomes and regulating cellular lifespan.

Telomeres are repetitive DNA sequences at the ends of chromosomes that act as protective caps. With each cell division, telomeres gradually shorten, and when they reach a critically short length, cells enter a state of replicative senescence or undergo programmed cell death (apoptosis).

The progressive shortening of telomeres over time is associated with aging and age-related diseases. This is because shortened telomeres can lead to genomic instability, cellular dysfunction, and impaired tissue renewal. Cells with critically short telomeres may experience DNA damage, chromosomal abnormalities, and increased susceptibility to mutations.

Telomeres also play a role in regulating cell proliferation and tumor suppression. In some cases, cells can bypass the limitations imposed by telomere shortening through telomerase, an enzyme that can restore telomere length. However, excessive activation of telomerase is associated with cancer development.

Overall, telomeres contribute to the aging process by serving as a cellular clock and influencing cellular and tissue functions. Understanding telomere biology is important in unraveling the mechanisms of aging and exploring potential interventions for age-related diseases.

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Answer:

8360N

Explanation:

F = ma

= 2200kg × 3.8 m/s²

= 8360 N

The smallest angle at which you would get destructive interference when 550 nm light passes two slits 50 μm apart is 0.32°.

The condition for destructive interference is gotten  by:

Δϕ = 2πΔx/λ = π

where Δx=  path difference between the two slits,

λ =  wavelength of light,

and Δϕ =  phase difference.

λ/2 = Δx sinθ

Here, θ is the angle between the incident light and the line connecting the center of the slits to the point of interest on the screen.

sinθ = (λ/2) / Δx = (550 nm / 2) / (50 μm) = 0.0055

θ = sin⁻¹(0.0055) = 0.32°

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Answer:

the answer is (D) The number of atoms of each element in the protein

Explanation:

Answer:

Which information could a student determine from only the chemical formula of a protein

Which information could a student determine from only the chemical formula of a protein

Which information could a student determine from only the chemical formula of a protein

Explanation:

Which information could a student determine from only the chemical formula of a protein

Which information could a student determine from only the chemical formula of a protein

Which information could a student determine from only the chemical formula of a protein

Analytical maps can be created to depict historical ownership, paved areas for cars, parks, natural amenities, and community street design. Streets, being public spaces, require measurement to determine their intended beneficiaries.

Analytical maps offer a valuable tool for visualizing and understanding various aspects of urban planning. By creating maps that showcase historical ownership patterns, paved areas designated for cars, locations of parks and natural amenities, and community street design, it becomes easier to assess the distribution of resources and infrastructure within a city.

In this context, streets hold a significant role as public spaces. They are not solely meant for vehicular traffic but should also prioritize the needs and activities of pedestrians, cyclists, and the wider community. Analyzing street design through mapping can help evaluate whether streets are primarily designed to cater to cars or if they accommodate a balanced and inclusive approach that considers the needs of all users.

To achieve equitable urban environments, it is crucial to assess the intended beneficiaries of street design and identify any discrepancies or biases in the allocation of public space. By utilizing analytical maps, planners, policymakers, and communities can have a clearer understanding of the current state of street design and work towards creating more people-centric and sustainable cities.

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The three main approaches to the identification of unknown bacteria are as follows:Phenotypic identification, Molecular identification and Biochemical identification

1. Phenotypic identification

Phenotypic identification involves the physical and chemical characteristics of the bacterial colonies and cells. In this method, bacterial cells are studied through microscopy, their ability to grow on various types of media, cellular morphology, and other factors that are easy to observe.

2. Biochemical identification

Biochemical identification is based on the biochemical reactions of bacteria. This method involves the use of different chemical and biochemical tests to identify the bacteria. The tests are designed to identify specific enzymes or metabolic pathways. The results of the tests are then used to identify the bacteria.

3. Molecular identification

Molecular identification involves the use of DNA analysis to identify bacteria. In this method, the DNA of the bacterial cells is isolated and analyzed. This method has become popular in recent years due to its accuracy and speed.

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Answer:

The magnification of the spoon is approximately 0.39

Explanation:

To determine the magnification of the spoon, we can use the lens formula:

1/f = 1/v - 1/u

Where:

f = focal length of the lens (convex lens in this case)

v = image distance from the lens

u = object distance from the lens

Given:

f = -6.50 cm (negative because it is convex)

u = 5.00 cm

Substituting the given values into the lens formula:

1/-6.50 = 1/v - 1/5.00

Simplifying:

-1/6.50 = 1/v - 1/5.00

To solve for v, we need to find a common denominator:

-5/32.50 = (5 - 6.50)/ (5v)

-5/32.50 = (-1.50)/ (5v)

Cross-multiplying:

-5 * 5v = -32.50 * -1.50

-25v = 48.75

Dividing both sides by -25:

v = 48.75 / -25

v = -1.95 cm

Now, we have the image distance (v), which is approximately -1.95 cm. To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -(-1.95 cm) / 5.00 cm

M = 0.39

The One strategy implemented to address the drug epidemic in Philadelphia is the creation of Comprehensive User Engagement Sites (CUES). These sites aim to tackle the widespread issue of drug addiction and related energy health concerns.

The CUES are safe spaces where individuals battling addiction can energy access various harm reduction services, such as clean syringes, medical support, and overdose prevention. These sites provide connections to addiction treatment programs and mental health services, helping people on their path to recovery. By offering safe and supervised spaces, CUES work to reduce public drug use, discarded syringes, and other related issues in the community. CUES also serve as educational hubs, raising awareness and providing information about the dangers of drug addiction and available resources for support. Lastly, these sites foster community engagement and collaboration, uniting various stakeholders in the fight against the drug epidemic. In summary, Comprehensive User Engagement Sites play a significant role in addressing the drug epidemic in Philadelphia. They provide harm reduction services, treatment programs, and community support, all while promoting a safer and healthier environment for the city's residents.

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To find the least squares solution of the equation ax = b using the normal equations, we first construct the normal equations and then solve them.

The normal equations are given by:

A^T * A * x = A^T * b

where A is the coefficient matrix with dimensions m x n, x is the unknown vector of dimensions n x 1, and b is the vector of known values with dimensions m x 1.

To solve the normal equations, follow these steps:

1. Calculate the transpose of A: A^T.

2. Compute the matrix product of A^T and A: A^T * A.

3. Calculate the matrix product of A^T and b: A^T * b.

4. Solve the resulting system of equations A^T * A * x = A^T * b for x.

The solution vector x obtained from solving the normal equations will be the least squares solution of the equation ax = b.

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Part A:

The two smallest positive values of x for which the probability function |Ψ(x,t)|² is a maximum at t = 0 are x = π/k and x = 2π/k.

Part B:

The two smallest positive values of x for which the probability function |Ψ(x,t)|² is a maximum at t = 2π/ω are x = π/2k and x = 3π/2k.

Part C:

The average velocity, vav, can be calculated as the distance the maxima have moved divided by the elapsed time. Since the maxima occur at x = π/k and x = 2π/k, the distance traveled by the maxima is π/k - (2π/k) = -π/k. The elapsed time is t = 2π/ω - 0 = 2π/ω. Therefore, the average velocity can be calculated as:

vav = (distance traveled) / (elapsed time)

vav = (-π/k) / (2π/ω)

vav = -ω/(2k)

Part A:

To find the values of x for which the probability function |Ψ(x,t)|² is a maximum at t = 0, we need to maximize the expression |Ψ(x,0)|². The probability function is given by |Ψ(x,t)|² = |A[ei(kx) - ei(2kx)]|² = |A|² |ei(kx) - ei(2kx)|².

Using the identity |a - b|² = (a - b)(a* - b*), we can expand the probability function:

|Ψ(x,t)|² = |A|² [ei(kx) - ei(2kx)][ei(kx)* - ei(2kx)]

= |A|² [ei(kx)ei(kx) - ei(kx)ei(2kx)* - ei(2kx)ei(kx)* + ei(2kx)ei(2kx)]

= |A|² [1 - ei(kx)ei(2kx) - ei(2kx)ei(kx)* + 1]

= 2|A|² [1 - cos(kx)cos(2kx) + sin(kx)sin(2kx)].

To find the maximum values, we set the derivative of |Ψ(x,0)|² with respect to x equal to zero:

d/dx |Ψ(x,0)|² = 2|A|² [k sin(kx)cos(2kx) + 2k cos(kx)sin(2kx)] = 0.

Simplifying the equation gives:

k sin(kx)cos(2kx) + 2k cos(kx)sin(2kx) = 0.

Dividing both sides by kcos(kx)cos(2kx), we get:

tan(kx) = -2tan(2kx).

Using the trigonometric identity tan(2θ) = 2tan(θ)/(1 - tan²(θ)), we can rewrite the equation as:

tan(kx) = -4tan(kx)/(1 - tan²(kx)).

Simplifying further, we have:

tan(kx)[1 - 4/(1 - tan²(kx))] = 0.

Since tan(kx) ≠ 0, we have:

1 - 4/(1 - tan²(kx)) = 0.

Solving for tan²(kx), we get:

tan²(kx) = 4.

Taking the square root, we obtain:

tan(kx) = ±2.

From the properties of the tangent function, we know that the smallest positive values of kx for which tan(kx) = 2 are kx = π/4 and kx = 5π/4.

Therefore, the two smallest positive values of x for which |Ψ(x,t)|² is a maximum at t = 0 are x = π/k and x = 2π/k.

Part B:

To find the values of x for which the probability function |Ψ(x,t)|² is a maximum at t = 2π/ω, we follow a similar approach as in Part A.

The probability function at t = 2π/ω is given by:

|Ψ(x,t)|² = |A|² [ei(kx - 2ωt) - ei(2kx - 4ωt)][ei(kx - 2ωt)* - ei(2kx - 4ωt)*].

Expanding and simplifying, we find:

|Ψ(x,t)|² = 2|A|² [1 - cos(kx - 2ωt)cos(2kx - 4ωt) + sin(kx - 2ωt)sin(2kx - 4ωt)].

Setting the derivative of |Ψ(x,t)|² with respect to x equal to zero, we obtain:

k sin(kx - 2ωt)cos(2kx - 4ωt) + 2k cos(kx - 2ωt)sin(2kx - 4ωt) = 0.

Dividing by kcos(kx - 2ωt)cos(2kx - 4ωt) and simplifying, we get:

tan(kx - 2ωt) = -2tan(2kx - 4ωt).

Using the tangent identity, we have:

tan(kx - 2ωt) = -4tan(kx - 2ωt)/(1 - tan²(kx - 2ωt)).

Simplifying further, we obtain:

tan(kx - 2ωt)[1 - 4/(1 - tan²(kx - 2ωt))] = 0.

Since tan(kx - 2ωt) ≠ 0, we have:

1 - 4/(1 - tan²(kx - 2ωt)) = 0.

Solving for tan²(kx - 2ωt), we get:

tan²(kx - 2ωt) = 4.

Taking the square root, we have:

tan(kx - 2ωt) = ±2.

From the properties of the tangent function, we know that the smallest positive values of kx - 2ωt for which tan(kx - 2ωt) = 2 are kx - 2ωt = π/4 and kx - 2ωt = 5π/4.

Adding 2ωt to both sides, we find:

kx = π/4 + 2ωt and kx = 5π/4 + 2ωt.

At t = 2π/ω, we substitute the given value and simplify:

kx = π/4 + 2(2π/ω) = π/4 + 4π/ω = (4π + 16π)/(4ω) = 20π/(4ω) = 5π/(ω).

Similarly,

kx = 5π/4 + 2(2π/ω) = 5π/4 + 4π/ω = (5π + 16π)/(4ω) = 21π/(4ω).

Therefore, the two smallest positive values of x for which |Ψ(x,t)|² is a maximum at t = 2π/ω are x = π/(2k) and x = 5π/(2k).

Part C:

The average velocity, vav, can be calculated as the distance the maxima have moved divided by the elapsed time.

From Part A, we found that the maxima move from x = π/k to x = 2π/k in the elapsed time t = 2π/ω.

Therefore, the distance traveled by the maxima is given by:

distance traveled = (2π/k) - (π/k) = π/k.

The elapsed time is t = 2π/ω.

Hence, the average velocity, vav, is given by:

vav = (distance traveled) / (elapsed time)

= (π/k) / (2π/ω)

= (π/k) * (ω/(2π))

= ω/(2k).

Therefore, the average velocity vav is equal to ω/(2k).

In conclusion, the two smallest positive values of x for which the probability function |Ψ(x,t)|² is a maximum at t = 0 are x = π/k and x = 2π/k. At t = 2π/ω, the two smallest positive values of x for which |Ψ(x,t)|² is a maximum are x = π/(2k) and x = 5π/(2k). The average velocity, vav, is equal to ω/(2k).

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At the summit of the mountain, the mass is 60.18 kg, the weight is 600 N, and the mass is unaltered.

Let the mass on earth be m.

As we know:

Now, calculate as follows:

Therefore, at the summit of the mountain, the mass is 60.18 kg, the weight is 600 N, and the mass is unaltered.

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​

Answer:

repetitions of a certain exercise

Explanation:

Calculating this, we find that the electron is moving at approximately 1.50 × 10^6 m/s.

To find the speed of the electron, we can use the formula for the centripetal force in a magnetic field. The centripetal force is given by the equation:

F = qvB

Where F is the force, q is the charge of the electron, v is its velocity, and B is the magnetic field strength.

In this case, the electron is moving in a circle, so the centripetal force is provided by the magnetic force. Therefore, we can equate the two forces:

qvB = mv²/R

Where m is the mass of the electron and R is the radius of the circle.

Given:
Charge of the electron (q) = -1.6 × 10^-19 C (Coulombs)
Magnetic field strength (B) = 3.2 × 10^-2 T (Tesla)
Radius (R) = 0.40 cm = 0.004 m (converted to meters)

The mass of an electron (m) is approximately 9.11 × 10^-31 kg.

Now we can solve for v:

qvB = mv²/R
v = (qvBR/m)^(1/2)

Plugging in the values:

v = (-1.6 × 10^-19 C * 3.2 × 10^-2 T * 0.004 m / 9.11 × 10^-31 kg)^(1/2)

Calculating this, we find that the electron is moving at approximately 1.50 × 10^6 m/s.

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Complete question is;

An experiment is carried out to measure the extension of a rubber band for different loads.

The results are shown in the image attached.

What figure is missing from the table?

Answer:

17.3 cm

Explanation:

The image attached showed values for load, extension and initial length.

Now, the first length there is 15.2 cm and as such it's corresponding extension is 0 because it has no preceding measured length.

The second measured length is 16.2 cm. Since it's initial measured length is 15.2 cm, then the extension has a formula; final length - initial length.

This gives: 16.2 - 15.2 = 1 cm

This corresponds to what is given in the table.

For the next measured length, it is blank but we are given the extension to be 2.1 cm. Now, since the initial measured length is 15.2 cm.

Thus;

2.1 cm = Final length - 15.2 cm

Final length = 15.2 + 2.1

Final length = 17.3 cm

The banking angle of the curved part of the speedway is determined as 32⁰.

The banking angle of the curved part of the speedway is calculated as follows;

V(max) = √(rg tanθ)

where;

V² = rg tanθ

tanθ = V²/rg

tanθ = (34²)/(190 x 9.8)

tanθ = 0.62

θ = arc tan(0.62)

θ = 31.8

θ ≈ 32⁰

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The velocity of the big fish after eating the little fish is 7.75 m/s (to the right).

Mass of the big fish = 8 kg, Velocity of the big fish = 3 m/s, Mass of the small fish = 3 kg, Velocity of the small fish = 1 m/s.

Velocity is a vector quantity and its unit is m/s. In this case, since the velocity of the big fish is towards the right, we take it as positive. Similarly, since the velocity of the small fish is towards the big fish, we take it as negative. We can find the momentum of both the fishes using the formula:

p = mv

Where p is the momentum, m is the mass and v is the velocity.Let us first find the momentum of the big fish:

p₁ = m₁v₁ = 8 × 3 = 24 kg m/s.

The momentum of the small fish:

p₂ = m₂v₂ = -3 × 1 = -3 kg m/s (the negative sign is used because the velocity is in the opposite direction of the big fish)

After the big fish eats the small fish, the mass of the big fish will be:

m₁' = m₁ + m₂ = 8 + 3 = 11 kg

Similarly, the velocity of the big fish after eating the small fish will be:

v₁' = (m₁v₁ + m₂v₂) / (m₁ + m₂)= (24 - 3) / 11 = 21 / 11 = 1.91 m/s (to the right)

Again, using the formula:

p₁' = m₁'v₁'

we can find the momentum of the big fish after eating the small fish:

p₁' = m₁'v₁' = 11 × 1.91 = 21.01 kg m/s

Finally, we can find the velocity of the big fish using the formula:

v₁' = p₁' / m₁'v₁' = 21.01 / 11 = 1.91 m/s (to the right)

Therefore, the velocity of the big fish after eating the little fish is 7.75 m/s (to the right).

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Answer:

Explanation:

L = g·t² / 2 = 9.8·4.0² / 2 = 78.4 m

Today, astronomers can measure distances directly to worlds like Venus, mars, the moon, or the satellites of Jupiter by bouncing radar beams off them.

The reproduction and display of 3D pictures is another use for parallax. The secret is to take two 2D pictures of the subject from slightly different angles, just like human eyes do, and to show them so that each eye only sees one of the pictures.

For instance, a stereopticon, or stereoscope, a popular gadget from the 19th century, employs parallax to display images in three dimensions. Through a set of lenses, two photographs that have been put next to one another are seen. Each image is captured from a slightly varied angle that nearly resembles the distance between the eyes. The images on the left and right respectively depict what the left and right eyes would see.

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Answer:21

Explanation:every body said

Answer:

Explanation:

acceleration is rate of change of velocity

a=dv/dt =d/dt(4t^2+t) = 8t+1

Acceleration t=2 sec, =8(2)+1=17 m/s^2

Force = mass * acceleration = 5*17 = 85N

Answer:

66.86m

Explanation:

Velocity of ball thrown, u = 23.5 m/s

Initial height of the ball above the water, H = 11.5 m

Angle of projection, θ = 39.5°

Vertical components of veloclty = usinθ

Horizontal components of veloclty = ucosθ

The soft ball hits the water after time 't'

Considering the second equation of motion

S = ut + 1/2at^2........ 1

But since the ball went through motion under gravity ( free fall ) rather than linear motion, then equation 1 can be rewritten as:

H = ut +/- 1/2gt^2

H = - 11.5m

U = usinθ

θ = 39.5°

a = -g = -9.8m/s^2

- 11.5m = 23.5(sin39.5°)t + 1/2(-9.8)t^2

-11.5m = 23.5(0.6360)t - 4.9t^2

-11.5m = 14.946t - 4.9t^2

4.9t^2 -14.946t-11.5m = 0

Since the ball drifted horizontally

D = (Ucosθ)t

Where θ = 39.5°

U = 23.5m/s t=

Alternatively,

horizontal component of the velocity is 23.5 cos 39.5º = 18.1331 m/s

now how long does it take the ball to raise to a peak and fall to the water.

vertical component of velocity = 23.5 sin 39.5º = 14.947m/s

time to reach peak t = v/g = 11.947/9.8 = 1.5252 sec

peak reached above cliff top is

h = ½gt² = ½(9.8)(1.5252)²

= ½×22.797

= 11.3985m

now the ball has to fall 11.3985+ 11.5 = 22.8985m

time to fall from that height is

t = √(2h/g) = √(2• 22.8986/9.8) = 2.1617 sec

add up the two times to get time it is in the air, 2.1617 + 1.5252 = 3.6869

now haw far does the ball travel horizontally in that time

d = vt = 18.1331 ×3.6869= 66.856m

= 66.86m

Answer:

The reaction absorbs energy from its surroundings.

Explanation:

An endothermic reaction is any reaction in which energy is absorbed by the reaction system.Thus implies that energy is withdrawn from the environment A cold pack's function is based on an endothermic chemical reaction.

The absorption of energy by the reaction system means that the environment feels cool in an endothermic reaction.This manifests in a decrease in the temperature of the cold pack.

(a) If you double your driving speed,  time required to come to a stop will be halved (b) the distance needed to stop will be quadrupled.

Deceleration is defined as a decrease in velocity. Deceleration is slowing down. Negative acceleration is acceleration in the negative direction in the coordinate system. Negative acceleration may/ may not be deceleration and deceleration may /may not be negative acceleration.

If the brakes in a car create a constant deceleration, then time required to come to a stop is directly proportional to velocity, while the distance needed to stop is proportional to square of the velocity. So, if you double your driving speed, the time required to come to a stop will be halved, while the distance needed to stop will be quadrupled.

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Total 2.54 cm far below the interface between the two liquids is the bottom of the block.

Oil having a density of floats on water = 930 kg/m^3

A rectangular block of wood height = 4.19 cm

A rectangular block of wood having density of floats partly in the oil and partly in the water = 979 kg/m3

We have determine how far below the interface between the two liquids is the bottom of the block.

For the equilibrium:

ρ(wood)gh - ρ(oil)g(h−x) - ρ(water)gx = 0

ρ(wood)h - ρ(oil)(h−x) - ρ(water)x = 0

(974)(3.97) - 928(3.97−x)−1000x = 0

3866.78 - 3684.16 + 928x - 1000x = 0

Simplify

182.62 - 72x = 0

Add 72x on both side we get

72x = 182.62

Divide by 72 on both side, we get

x = 2.54 cm

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The complete question is:

Oil having a density of 930 kg/m^3 floats on water. A rectangular block of wood 4.19 cm high and with a density of 979 kg/m3 floats partly in the oil and partly in the water. The oil completely covers the block. How far below the interface between the two liquids is the bottom of the block?

The kinetic energy of the bullet-block system is equal to the potential energy of the bullet-block system when it reaches its maximum height.

According to the principle of conservation of linear momentum, momentum before collsion is equal to momentum after collision. Let us now answer the questions individually.

1) The momentum of the bullet before collsion = (0.001 Kg * 35 m/s) = 0.35 Kgms-1

2) The kinetic energy of the bullet before collision = 0.5 * 0.001 * (35 m/s)^2 = 0.6125 J

3) Velocity after collsion is obtained from;

(0.001 Kg * 35 m/s) + (2 kg * 0 m/s) = (0.001 Kg + 2 kg) v

v = 0.35/2.001 =

v=0.1749 m/s

4) Total kinetic energy after collison = 0.5 * (0.001 Kg + 2 kg) * (0.1749 m/s)^2

= 0.031 J

5) The maximum possible potential energy of the bullet-block system when it reaches its maximum height = Total kinetic energy after collison = 0.031 J

6) The  maximum possible height of the bullet-block system is obtained from;

PE = mgh

h = 0.031 J/(0.001 Kg + 2 kg) * 9.8 ms-2

h = 0.0015 m or 0.15 cm

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He is going at the velocity of 40m/s even though he started at rest.

What is acceleration?

Acceleration is the rate at which velocity changes with respect to both speed as well as distance. If an object speeds up or down and is moving in a straight line, then the object is said to be accelerated. In a circular motion, the speed remains constant but the body is accelerated as the direction keeps on changing. The SI Unit is meter per second m/s2

Acceleration= 10m/s2

Initial velocity= 0m/s as the body started at rest.

Distance = 80 m

v2= u2+ 2aS

  = 02+ 2 10 80

  = 1600

v= 40m/s

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