Answers
Answer:
The astronauts are separated by 28 m.
Explanation:
The separation of the astronauts can be found by conservation of linear momentum:
\( p_{i} = p_{f} \)
\( m_{1}v_{1i} + m_{2}v_{2i} = m_{1}v_{1f} + m_{2}v_{2f} \)
\( m_{1}*0 + m_{2}*0 = m_{1}v_{1f} + m_{2}v_{2f} \)
\( m_{1}v_{1f} = -m_{2}v_{2f} \)
\( v_{1f} = -\frac{m_{2}v_{2f}}{m_{1}} = -\frac{80v_{2f}}{60} \)
Now, the distance (x) is:
\( x = \frac{v}{t} \)
The distance traveled by the astronaut 1 is:
\( x_{1} = v_{1f}*t = -\frac{80v_{2f}}{60}*t \) (1)
And, the distance traveled by the astronaut 2 is:
\( x_{2} = v_{2f}*t \) (2)
From the above equation we have:
\( t = \frac{x_{2}}{v_{2f}} \) (3)
By entering equation (3) into (1) we have:
\( x_{1} = -\frac{80v_{2f}}{60}*(\frac{x_{2}}{v_{2f}}) \)
\( x_{1} = -\frac{4*12}{3} = -16 m \)
The minus sign is because astronaut 1 is moving in the opposite direction of the astronaut 2.
Finally, the separation of the astronauts is:
\( x_{T} = |x_{1}| + x_{2} = (16 + 12)m = 28 m \)
Therefore, the astronauts are separated by 28 m.
I hope it helps you!
The total separation between the two astronauts is 28m.
The given parameters:
masses of the astronauts, = 60 kg and 80 kgApply the principle of conservation of momentum to determine the final velocity of each astronauts as follows;
\(m_1u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2\\\\60(0) + 80(0) = 60(v_1) + 80(v_2)\\\\0 = 60v_1 + 80v_2\\\\-60v_1 = 80v_2\\\\v_1 = \frac{-80v_2}{60} \\\\v_1 = -1.333v_2\)
Let the time when astronaut 2 moved 12 m = t
The distance traveled by astronaut 1 is calculated as;
\(x_1 = v_1 t\\\\x_1 = -1.333v_2t\)
The distance traveled by astronaut 2 is calculated as;
\(x_2 = v_2 t\\\\12 = v_2t\\\\t = \frac{12}{v_2}\)
Now solve for the distance of astronaut 1
\(x_1 = - 1.333v_2 \times t\\\\x_1 = -1.333 v_2 \times \frac{12}{v_2} \\\\x_1 = -16 \ m\)
The total separation between the two astronauts is calculated as follows;
\(d = |x_1| + x_2\\\\d = 16 + 12\\\\d = 28 \ m\)
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Related Questions
What is the potential energy of a 2500 g object suspended 5 kg above the earth's surface?
kilograms.
Answers
Answer:
\(potential \: energy = mgh \\ = ( \frac{2500}{1000} ) \times 10 \times 5 \\ = 125 \: newtons\)
if height is 5 m
a child holds a 10N toy car for 30 seconds. what is the net work done on the toy car?
Answers
If the child is holding the toy car still for 30 seconds, then net work done on the car is zero.
What is meant by work done?Work is defined as the product of force and displacement in the direction of force. In this case, the force and displacement are perpendicular to each other, so no work is being done. Therefore, net work done on the toy car is zero.
If the child is holding the toy car still, then net work done on the car is zero. This is because the force exerted by the child is equal in magnitude and opposite in direction to the force of gravity acting on the car and car is not moving, so there is no displacement.
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When Simon grows (let’s say he doubles his mass) what happens to his GPE when he is at the balcony?
Answers
Answer:
His gravitational potential energy will increase as well.
Explanation:
Let gpe represent gravitational potential energy.
gpe = mass × gravitational field strength × height
From the formula above, we can conclude that as the mass of a body increases, it's gpe increases too.
Why are S-H bonds longer than O-H bonds?
Answers
Answer: S-H bonds are typically longer than O-H bonds because sulfur is larger than oxygen. The size difference between the two atoms means that the electrons in the bond are farther apart in an S-H bond, resulting in a longer bond length. Additionally, sulfur is less electronegative than oxygen, which means that the electrons in the bond are less strongly attracted to the sulfur atom and are therefore more likely to be found in the region between the two atoms, further increasing the bond length.
Explanation:
Answer:
Describe the differences between the O-H and S-H bond lengths. Due to its stronger shielding, which lessens the nuclear pull for the bonding electrons and causes a longer bond length, sulfur is a bigger atom than oxygen.
Explanation:
1.
A car is driving on a circular track tha has a diameter of 6km and
traveled across the black shaded region in 1 hour. What will the
cars velocity be in meters/seconds. 1 km= 1000 meters
6 km
V=²& D=vt T = ²
Answers
The velocity of the car moving in the circular path is determined as 1.67 m/s.
What is linear velocity?Linear velocity is the measure of the rate of change of displacement with respect to time when the object moves along a straight path.
v = d/t
where;
d is the distance of the objectt is time of motionv = (6 x 1000 m) / (1 x 3600 s)
v = 1.67 m/s
Thus, the velocity of the car moving in the circular path is determined as 1.67 m/s.
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a ball hits the wall and reverses courses. According to newtons 3rd law which of these must be true
Answers
The ball exerts a force on the wall, and the wall exerts an equal and opposite force on the ball. So, the correct answer is A.
Newton's 3rd law of motion states that for every action, there is an equal and opposite reaction. The action is the force that the ball exerts on the wall, and the reaction is the force that the wall exerts back on the ball. When the ball hits the wall, it exerts a force on the wall. This force is equal in magnitude but opposite in direction to the force that the wall exerts back on the ball. This is why the ball reverses course. Therefore, option A is correct.
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--The complete Question is, Which of the following statements is true according to Newton's 3rd law when a ball hits a wall and reverses course?
A) The ball exerts a force on the wall, and the wall exerts an equal and opposite force on the ball.
B) The ball exerts a force on the wall, but the wall does not exert a force on the ball.
C) The wall exerts a force on the ball, but the ball does not exert a force on the wall.
D) The ball and the wall do not exert any forces on each other. --
When carbon bonds with oxygen,
what
gas is formed?
When carbon bonds with oxygen, what gas is formed?
Answers
Answer:
Carbon dioxide
Explination:
I remember it from biology.
I hope this helps ^-^
In a chemical reaction, carbon combines with oxygen to form carbon dioxide gas.
What is a chemical reaction?A chemical reaction can be defined as a process that causes the chemical transformation of one chemical substance to another. The chemical reactions accompany chemical changes that involve the rearrangement of electrons in the forming and breaking of bonds between atoms, with no change to the nuclei.
The substances which are primarily involved in a reaction are known as reactants or reagents. Chemical reactions are commonly characterized by a chemical change, and yield products, which exhibit properties different from the reactants.
Chemical reactions take place at a characteristic rate of reaction at a given temperature, pressure, and chemical concentration. The rates increase with the increasing temperature of the reaction when more thermal energy is available to achieve the activation energy for breaking bonds between atoms.
The combustion reaction takes place when carbon combines with oxygen to produce carbon dioxide gas.
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How are magnetic fields like vectors?
Answers
Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.
Explanation:
A man pushing a crate of mass
m = 92.0 kg
at a speed of
v = 0.855 m/s
encounters a rough horizontal surface of length
ℓ = 0.65 m
as in the figure below. If the coefficient of kinetic friction between the crate and rough surface is 0.359 and he exerts a constant horizontal force of 289 N on the crate.
A man pushes a crate labeled m, which moves with a velocity vector v to the right, on a horizontal surface. The horizontal surface is textured from the right edge of the crate to a horizontal distance ℓ from the right edge of the crate.
(a) Find the magnitude and direction of the net force on the crate while it is on the rough surface.
magnitude
N
direction
Opposite Direction or Same Direction
(b) Find the net work done on the crate while it is on the rough surface.
J
(c) Find the speed of the crate when it reaches the end of the rough surface.
m/s
Answers
(a) The magnitude and direction of the net force on the crate while it is on the rough surface is 34.7 N in opposite direction.
(b) The net work done on the crate while it is on the rough surface is -22.6 J.
(c) The speed of the crate when it reaches the end is 0.5 m/s.
What is the net force on the crate while it is on the rough surface?
The magnitude and direction of the net force on the crate while it is on the rough surface is calculated as follows;
F (net) = F - Ff
where;
F is the applied forceFf is the frictional force on the crateF (net) = F - μmg
where;
μ is the coefficient of frictionm is massg is gravityF (net) = 289 N - (0.359 x 92 X 9.8)
F (net) = -34.7 N
The negative sign indicates opposite direction to the applied force.
The net work done on the crate while it is on the rough surface is calculated as follows;
W = F(net) x L
where;
L is the distance travelled by the crateW = -34.7 x 0.65
W = -22.6 J
The speed of the crate when it reaches the end is calculated as follows;
acceleration of the crate = F(net) / m
a = -34.7 N / 92 kg
a = -0.377 m/s²
v² = u² + 2aL
v² = ( 0.855)² + ( 2 x -0.377 x 0.65)
v² = ( 0.855)² - ( 2 x 0.377 x 0.65)
v² = 0.24
v = √ 0.24
v = 0.5 m/s
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An object traveling a circular path of radius 5 m at constant speed experiences an acceleration of 3 m/s2. If the radius of its path is increased to 10 m, but its speed remains the same, what is its acceleration?
Answers
Answer:
New acceleration = 1.5 m/s²
Explanation:
The acceleration of an object when it moves in a circular path is given by :
\(a=\dfrac{v^2}{r}\)
Where
v is speed of an object
r is radius of path
If v remains constant,
\(a\propto \dfrac{1}{r}\)
or
\(\dfrac{a_1}{a_2}=\dfrac{r_2}{r_1}\)
Put r₁ = 5 m, a₁ = 3m/s², r₂ = 10 m
\(a_2=\dfrac{a_1r_1}{r_2}\\\\a_2=\dfrac{3\times 5}{10}\\\\a_2=1.5\ m/s^2\)
Hence, if the radius of its path is increased to 10 m, its acceleration will be 1.5 m/s².
Consider a series of motion scenarios. Each scenario is accompanied by a short description and an arrow indicating the instantaneous velocity. Assume that air resistance is negligible in every scenario. The only forces present in each scenario are gravity, surface (or normal) forces, and friction if indicated. Place the appropriate arrow, or zero, next to each scenario to indicate the direction of the net force acting on the block.
Answers
The resultant force is obtained by taking into account the magnitude and direction of all the forces involved.
What is motion?Motion refers to change in position with respect to time. The instantaneous velocity is the velocity at a given time during motion.
Since force is a vector quantity, we must note that the net force will point in a given direction after taken all other forces into account. The net/resultant force is the force tat will have the same effect in magnitude and direction as all the forces taken together.
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BERE
Which describes the positions on a horizontal number line?
0
O All points to the left of one are positive.
O All points to the right of one are positive.
O All points to the left of zero are negative.
O All points to the right of zero are negative.
Mark this and return
Save and Exit
Next
Submit
Answers
Answer:
All points to the left of zero are negative
Explanation:
Answer:
C
Explanation:
on edge
When using a pulley with a mechanical advantage of 1.5, a worker applies 255 N to the pulley. The pulley is used to lift a heavy crate. How much force does the pulley apply to the crate?
Answers
The force applied to the crate by the pulley is 382.5 N.
What is force?Force is the product of mass and accleration.
To calculate the force the pulley applied to the crate, we use the formula below
Formula:
L = E×M.A....................... Equation 1Where:
L = Force applied to the crate by the pulleyE = Force applied to the pulley by the workerM.A = Mechanical advantage of the pulleyFrom the question,
Given:
E = 255 NM.A = 1.5Substitute these values into equation 1
L = 1.5×255L = 382.5 NHence, the force is 382.5 N.
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an 8.3 kg mass is attached to a string that has a breaking strength of 1500 N. If the mass is whirled in a horizontal circle of radius 80 cm, what maximum speed can it have?
Answers
Answer:
To determine the maximum speed that the 8.3 kg mass can have without breaking the string, we need to consider the tension in the string when it reaches its maximum. At maximum speed, the tension in the string will be equal to the breaking strength of the string.
Given:
Mass (m) = 8.3 kg
Breaking strength of the string (Tension) = 1500 N
Radius of the circle (r) = 80 cm = 0.8 m
The centripetal force required to keep an object moving in a circular path is given by the formula:
F = m * v² / r
Where:
F = Centripetal force
m = Mass
v = Velocity
r = Radius
In this case, the centripetal force is provided by the tension in the string. So we have:
Tension = m * v² / r
Plugging in the values:
1500 N = (8.3 kg) * v² / 0.8 m
To find the maximum speed (v), we can rearrange the equation and solve for it:
v² = (1500 N * 0.8 m) / 8.3 kg
v² ≈ 144.58 m²/s²
v ≈ √(144.58 m²/s²)
v ≈ 12.03 m/s
Therefore, the maximum speed that the 8.3 kg mass can have without breaking the string is approximately 12.03 m/s.
Explanation:
A cylindrical water tank open to the atmosphere, 10 m tall and 6 m in diameter, is mounted with its base 25 m above ground level, and filled with water. Calculate a) the water pressure and force at the base of the tank?
Answers
The water pressure at the base is 98,000 Pa, and the force exerted at the base of the tank is 2,768,460 N.
To find the water pressure at the base of the tank, take the formula:
Pressure = density × gravity × height
In which
Density = density of water (1000 kg/m³)
Gravity = acceleration due to gravity (9.8 m/s²)
Height = height of the column
According to question:
Height of the water column = 10 m
Take the formula:
P = 1000 kg/m³ × 9.8 m/s² × 10 m
= 98,000 Pa
To find the force at the base of the tank, take the formula:
Force = Pressure × Area
In which
Pressure = pressure at the base of the tank
Area = base area of the tank
The base area of a cylindrical tank can be found by the formula:
Area = π × r²
In which:
Diameter of the tank = 6 m
To find the radius, divide the diameter by 2:
Radius = 6 m ÷ 2
= 3 m
Put the values into the formula:
Area = π × (3 m)²
= 28.27 m²
Now, find the force:
Force = 98,000 Pa × 28.27 m²
= 2,768,460 N
Thus, the water pressure at the base is 98,000 Pa, and the force exerted at the base of the tank is 2,768,460 N.
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A vehicle, starting from rest, accelerates on a circular track with a 335m diameter.
Answers
The distance travelled by the vehicle around the circular track is 1,052.4 m.
What is the distance travelled by the vehicle in one complete cycle?
The distance travelled by the vehicle in one complete cycle is calculated by using the following equation as show below.
d = 2πr
d = πd
Where;
r is the radius of the circular trackd is the diameter of the circular trackIn one complete cycle, the vehicle will travel the circular track only once.
d = π(335 m)
d = 1,052.4 m
Thus, the distance travelled by the vehicle around the circular track is a function of the diameter of the circular track.
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The complete question is below:
A vehicle, starting from rest, accelerates on a circular track with a 335m diameter. What is the distance travelled by the vehicle when it makes one complete cycle?
A woman walks a distance of 504m, with and average speed of 1.4m/s. What time was required to walk this distance ?
Answers
A woman walks a distance of 504m, with an average speed of 1.4m/s. Therefore, 360 second time was required to walk this distance.
What is do you mean by speed ?The term speed is defined as the rate of change of position of an object in any direction.
The formula of speed is Speed = Distance / Time. The formula of time is Time = Distance / Speed. The formula of distance is Distance = Speed x Time.
Given:
Speed = 1.4m/s
Distance = 504m
Time = ?
Time = distance/ speed
Time = 504m / 1.4m/s
Time = 360 second
Thus, 360 second time was required to walk this distance.
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a vertical solid steel post 29cm in diameter and 2.0m long is required to support a load of 8200kg, ignore the weight of the post. determine the stress in the post
Answers
Answer:
The stress is \(\sigma = 1.218*10^{6} \ N/m^2\)
Explanation:
From the question we are told that
The diameter of the post is \(d = 29 \ cm = 0.29 \ m\)
The length is \(L = 2.0 \ m\)
The weight of the loading mass
Generally the radius of the post is mathematically represented as
\(r = \frac{0.29}{2}\)
=> \(r = 0.145 \ m\)
Generally the area of the post is
\(A = \pi r^2\)
=> \(A = 3.14 * 0.145 ^2\)
=> \(A = 0.066 \ m^2\)
Generally the weight exerted by the load is mathematically represented as
\(F = m * g\)
=> \(F = 8200 * 9.8\)
=> \(F = 80360 \ N\)
Generally the stress is mathematically represented as
\(\sigma = \frac{F}{A}\)
=> \(\sigma = \frac{80360 }{0.066}\)
=> \(\sigma = 1.218*10^{6} \ N/m^2\)
Mixed powders may be categorized as
Answers
Answer:
on flow properties and free-flowing and cohesive.
Explanation:
the power Free flowing powders do not cling together, as cohesive powders stick to each other and form that do not disperse well during mixing
An object with a mass of 300 kg is
observed to accelerate at the rate of
4m/s ? Calculate the total force
required
Answers
Answer:
m= 300
a= 4ms
f = ma
= 300×4
= 1200N
Answer: F = 1200 N
Explanation:
Hey there!
It is given that,
Mass of the object, m = 300 kg
Acceleration of the object when it is moving, \(a = 4m/s^{2}\)
If F is the force required to produce this acceleration. It is given by using the second law of motion as :
Calculations
F = m × a
F = 300 kg × \(4m/s^{2}\)
F = 1200 N
So, the force required to produce this acceleration is 1200 N. Hence, this is the required solution.
~I hope I helped you! :)~
Which statement best describes the positions of the two elements in the periodic table?
Answers
a plane wall is 250mm thick and it's wall area is 4.5m^2. if the thermal conductivity is 9.35w/m°c and surface temperature are steady at 150°c and 40°c. calculate the heat flow across the plane wall and the temperature gradient in the flow direction
Answers
The temperature gradient in the flow of direction is 294525 W.
What is Temperature gradient?A temperature gradient is the gradual variance in temperature with distance. The slope of the gradient is consistent within a material. A gradient is established anytime two materials at different temperatures are in physical contact with each other.
Q= T/( L/ KA)
Q= ( 1500 − 450) / 0.15 / 9.35v * 4.35)
= 294525 W
Units of measure of temperature gradients are degrees per unit distance, such as °F per inch or °C per meter.
Many temperature gradients exist naturally, while others are created. The largest temperature gradient on Earth is the Earth itself. Q= T/Ka.
Therefore, The temperature gradient in the flow of direction is 294525 W.
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Please help
4. What are the lowest points on a transverse wave called?
a. Crests
b. troughs
C. compressions
d. rarefractions
5. Any substance that a wave moves through is called a
a. medium
b. vibrate
C. crest
d. frequency
Answers
Answer:
Explanation:
the lowest points of a transverse wave are called the troughs what is the wavelength of a wave traveling through a rope if the distance from one crest to the next is 1 meter a. 2 m
4. Low points are called troughs
5. Medium: substance through which a wave can travel
HELP ME ASAPPPPPPPPPPP
A penny sinks to the bottom of a wishing well
What type of frictional force is that?
Answers
The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.
Answers
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.
To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.
Given:
Resistance of the coil, R1 = 4 ohm
Resistance of the other resistor, R2 = 8 ohm
Current passing through the 8-ohm resistor, I = 2A
First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.
The total resistance of two resistors in parallel can be calculated using the formula:
1/Rp = 1/R1 + 1/R2
Substituting the given values, we have:
1/Rp = 1/4 + 1/8
1/Rp = 2/8 + 1/8
1/Rp = 3/8
Rp = 8/3 ohm
Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).
R_total = R_internal + Rp
R_total = 0.5 + 8/3
R_total = 1.833 ohm
Now, we can find the emf of the cell using Ohm's Law:
emf = I * R_total
emf = 2 * 1.833
emf ≈ 3.667 volts
Therefore, the emf of the cell is approximately 3.667 volts.
However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.
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A 0.0400 kg meter stick is placed on a thin rod at the 30.0 cm mark. What is the minimum mass required to be placed on the 0.00 cm mark on the stick to maintain equilibrium?
Answer in kg
Answers
The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.
To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:
τ = r * F * sin(θ)
where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.
In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.
Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:
τ_M = r_M * F_M * sin(θ)
where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.
Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:
τ_M = τ_stick
r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)
Substituting the given values:
30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)
Solving for F_M:
F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)
F_M = 0.0264 kg * 9.8 m/s^2
F_M = 0.25872 N
Finally, we can convert the force into mass using the formula:
F = m * g
0.25872 N = M * 9.8 m/s^2
M = 0.0264 kg
Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.
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What method could I use to test this hypothesis? If the mass and the volume of and object are known, then its density can be calculated dividing the object's mass by its volume.
Answers
Answer:
The scientific method
Explanation:
One mole of a substance contains 6.02 × 1023 protons and an equal number of electrons. If the protons could somehow be separated from the electrons and placed in very small, individual containers separated by a million meters, what would be the magnitude of the electrostatic force exerted by one box on the other?
Answers
Explanation:
it is almost zero .this is because the distance and the electrostatic force are inversely proportional
How many nodes are on this standing wave? *
Answers
The number of nodes present in this standing wave is 6
How many nodes are on this standing wave?A standing wave is a type of wave that remains in a constant position and does not propagate through a medium. Instead, it oscillates in place between two fixed points, creating a pattern of constructive and destructive interference.
In a standing wave, nodes are the points along the medium that remain stationary, with no displacement or movement of the medium. These nodes occur at locations where the displacement of the medium is always zero, meaning that the amplitude of the wave is zero at those points.
In other words, nodes are the points of minimum energy in the standing wave. They are the points where the crest of the wave meets the trough of the wave, resulting in the cancellation of the wave's amplitude. The distance between two adjacent nodes is half of the wavelength of the standing wave.
In this standing wave, the number of nodes present is 6
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A parallel-plate capacitor, with air dielectric, is charged by a battery, after which the battery is disconnected. A slab of glass dielectric is then slowly inserted between the plates. As it is being inserted:
Answers
Complete Question
A parallel-plate capacitor, with air dielectric, is charged by a battery, after which the battery is disconnected. A slab of glass dielectric is then slowly inserted between the plates. As it is being inserted,
A :
a force repels the glass out of the capacitor.
B :
a force attracts the glass into the capacitor.
C :
no force acts on the glass.
D :
a net charge appears on the glass.
E :
the glass makes the plates repel each other.
Answer:
The correct option is B
Explanation:
Generally when the glass dielectric is slowly inserted between the plated,
The positive plate of the capacitor will induce a negative charge on the glass while the negative plate of the capacitor will induce a positive charge on glass which a electric field that posses an electric force that will attract the glass
B: a force attracts the glass into the capacitor.
A parallel-plate capacitor, with the air dielectric, is charged from a battery, after which the battery is disconnected. A slab of glass dielectric is then slowly inserted between the plates.
How is a dielectric slab inserted in a capacitor?
The dielectric slab is slowly inserted between the plates to a parallel plate capacitor while the capacitor is connected with a battery. As it is being inserted: 57. A parallel-plate capacitor, with air dielectric, is charged by the battery, after which the battery is the disconnected. A slab of glass dielectric is then slowly inserted between the plates. A parallel-plate capacitor, with the air dielectric, is charged from a battery, after which the battery is disconnected. A slab of glass dielectric is then slowly inserted between the plates.
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