Two blocks are enclosed in a perfectly insulated box. Block 1 at 90 c has mass of 10 kg, specific heat of 1. 0 j/k/m. Block 2 at 0 c has a mass of 40 kg, specific heat of 0. 5 j/k/m. What is the final temperature of the two blocks in equilibrium?.

Answers

Answer 1

Answer:

\(30\; {\rm ^{\circ} C}\).

Explanation:

Let \(T\; {\rm ^{\circ} C}\) denote the equilibrium temperature of the two blocks. By the time the two blocks reached this temperature:

Temperature of block \(1\) would have changed by \(\Delta T_{1} = (T - 90)\) (degrees kelvin.)Temperature of block \(2\) would have changed by \(\Delta T_{2} = (T - 0) = T\) (degrees kelvin.)

(Note that the temperature change of one degree celsius is equivalent to a temperature change of one degree kelvin.)

Let \(c_{1}\) and \(c_{2}\) denote the specific heat of the two blocks. Let \(m_{1}\) and \(m_{2}\) denote the mass of the two blocks. Energy change of the two blocks would be:

\(Q_{1} = c_{1}\, m_{1}\, \Delta T_{1} = (1.0)\, (10)\, (T - 90) = 10\, T - 900\) (joules) for block \(1\).\(Q_{2} = c_{2}\, m_{2}\, \Delta T_{2} = (0.5)\, (40)\, (T) = 20\, T\) (joules) for block \(2\).

Under the assumptions, energy should be conserved. Hence, the total energy change should be \(0\). Therefore:

\(Q_{1} + Q_{2} = 0\).

\((10\, T - 900) + (20\, T) = 0\).

\(T = 30\) (degrees celsius.)

In other words, the temperature of the two blocks would be \(30\; {\rm ^{\circ} C}\) when the system reached equilibrium.


Related Questions

An atom of xenon has a mass number of 127 amu. How many neutrons
does it contain? *

An atom of xenon has a mass number of 127 amu. How many neutronsdoes it contain? *

Answers

Answer:

73 neutrons.

Explanation:

Data obtained from the question:

Mass number of Xenon = 127.

Neutron number =...?

We can obtain the number of neutron present as follow:

Atomic number of Xenon = 54

Recall:

Atomic number = proton number = 54

Mass number = proton + neutron

127 = 54 + Neutron

Neutron = 127 – 54

Neutron = 73.

Therefore, 73 neutrons are present in the Xenon atom.

Which of the following wave on the electromagnetic spectrum has more energy? Ultraviolet or x-rays?

Answers

Answer:  ultraviolet

Explanation:

guys please help me i need to get this done

my teacher wants me to find the total distance and the displacement please give explanation also ty

guys please help me i need to get this done my teacher wants me to find the total distance and the displacement

Answers

I think it’s 59.5

c = a2 + b2
45^2 + 39^2 = 3546
square root 3546 = 59.54

A michelson interferometer is shown at right. The moving mirror is displaced a distance d. During this displacement, 250 interference fringe shifts are counted. The light being used has a wavelength of 632. 8 nm. Determine the mirror displacement d in nm.

Answers

The mirror displacement d is 317.12 nm. In a Michelson interferometer, interference fringes are created due to the interference of two beams of light.



A Michelson interferometer is a device used to measure small changes in the distance between two mirrors. It consists of a beam splitter, two mirrors, and a detector. One beam of light is split into two and travels to the mirrors, where they are reflected back towards the beam splitter. The two beams of light then recombine at the detector, creating an interference pattern.

When one of the mirrors is moved, the interference pattern shifts. The amount of shift depends on the distance moved and the wavelength of the light being used. By measuring the shift in the interference pattern, we can determine the displacement of the mirror.

In this problem, we are given that 250 interference fringe shifts were counted when the mirror was moved a distance d. The wavelength of the light being used is 632.8 nm.

Each interference fringe shift corresponds to a change in the path difference between the two beams of light by one wavelength. So, the total change in the path difference is 250 times the wavelength of the light:

250 × 632.8 nm = 158,200 nm

Therefore, the mirror displacement d is 158,200 nm. However, this displacement is in both directions (i.e., the mirror moved back and forth). To find the displacement in just one direction, we divide by 2:

d = 158,200 nm / 2 = 79,100 nm

Therefore, the mirror displacement d is 79,100 nm in one direction.

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1. A force acting on an object in the upward direction is 3 N. The force that would
balance this force could be written as
will balance because 3 N + (____
-) =
acts in the
direction.
You that know these forces
The balancing force

Answers

Answer:

See the explanation below

Explanation:

We must perform a sum of forces on the body, that sum of forces is equal to zero. That is, the body is in balance and does not move.

ΣF = 0

3 - 3 = 0

This force is negative and acts by pointing downwards.

Answer: ow consider a book sliding from left to right across a tabletop. Sometime in the prior history of the book, it may have been given a shove and set in motion from a rest position. Or perhaps it acquired its motion by sliding down an incline from an elevated position. Whatever the case, our focus is not upon the history of the book but rather upon the current situation of a book sliding to the right across a tabletop.

Explanation:

HELP ME WITH THIS FOR A BRAINLIEST

HELP ME WITH THIS FOR A BRAINLIEST

Answers

Option C: Runs up the slipway 5 s

hope this helped :)

two parallel conducting plates are connected to a constant voltage source. the magnitude of the electric field between the plates is 2227 n/c. if the voltage is doubled and the distance between the plates is reduced to 1 4 the original distance, what is the magnitude of the new electric field? answer in units of n/c.

Answers

The magnitude of the electric field between two parallel conducting plates is given by the equation E = V/d, where E is the electric field, V is the voltage, and d is the distance between the plates.

In the given scenario, the initial electric field is 2227 n/c, and the voltage is constant. If the voltage is doubled, the new voltage is 2 times the initial voltage. If the distance between the plates is reduced to 1/4 the original distance, the new distance is 1/4 times the initial distance.

Using the equation for electric field, the new electric field can be calculated as follows:

E' = (2V) / (d/4)

E' = 8V / d

E' = 8 x 2227 / d (since V is constant)

E' = 17,816 / d

Therefore, the magnitude of the new electric field is 17,816 / d n/c.

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When candle wax is heated enough, it becomes a liquid and flows. However, if it isn't heated, candle wax is a solid. Which of the following explains why liquid candle wax flows but solid wax does not?​

○ the molecules of the Liquid wax are softer than the molecules of the solid matte wax.

○ The molecules of the liquid wax have less mass than the molecules of the solid wax.

○ The molecules of the liquid wax can easily move past one another but the molecules of the solid wax cannot.

Answers

Answer:

C

Explanation:

At X-Band the one-way clear air absorption is 0.004 dB/km. Five km from a radar, there is a 3 km wide rain cell (spanning 5 km to 8 km) of 2 mm/hr with one-way absorption of 0.02 dB/km. Ten km from that same radar there is another 3 km wide rain cell of 4 mm/hr with one-way absorption of 0.05 dB/km. Plot the propagation factor, F2, as a function of range. What is the total propagation factor seen by the radar for a target at 12 km?

Answers

Rain cell 1: 2 mm/hr, 3 km wide, absorption = 0.02 dB/km, Rain cell 2: 4 mm/hr, 3 km wide, absorption = 0.05 dB/km. The total propagation factor seen by the radar for a target at 12 km is 0.048 dB.

To calculate the total propagation factor (F2) at a range of 12 km, we need to consider the clear air absorption and the absorption due to the rain cells at different ranges.

Given information:

Clear air absorption at X-Band: 0.004 dB/km

Rain cell 1: 2 mm/hr, 3 km wide, absorption = 0.02 dB/km

Rain cell 2: 4 mm/hr, 3 km wide, absorption = 0.05 dB/km

To plot the propagation factor as a function of range, we'll calculate the contributions from each component and sum them up.

Clear Air Absorption:

At 12 km range, the clear air absorption factor is:

Clear air absorption = Clear air absorption coefficient * Range

= 0.004 dB/km × 12 km

= 0.048 dB

Rain Cell 1:

The rain cell 1 is located between 5 km to 8 km. Within this range, the absorption factor is constant at 0.02 dB/km.

We need to calculate the fraction of the rain cell coverage within the range of interest.

Fraction of rain cell 1 coverage = (Coverage within range of interest) / (Total rain cell width)

= (min(8 km, 12 km) - max(5 km, 12 km)) / 3 km

Since the range of interest is 12 km, the coverage within the range is:

Coverage within range of interest = min(8 km, 12 km) - max(5 km, 12 km)

= min(8 km, 12 km) - 12 km

= min(8 km, 12 km) - 12 km

= 8 km - 12 km

= -4 km (No coverage within the range)

Since there is no rain cell coverage within the range of interest, the propagation factor due to rain cell 1 is 0 dB.

Rain Cell 2:

The rain cell 2 is located between 8 km to 11 km. Similar to rain cell 1, we calculate the fraction of rain cell coverage within the range of interest.

Fraction of rain cell 2 coverage = (Coverage within range of interest) / (Total rain cell width)

= \(\frac{ (min(11 km, 12 km) - max(8 km, 12 km))}{3 km}\)

Within the range of interest, the coverage is:

Coverage within range of interest = min(11 km, 12 km) - max(8 km, 12 km)

= min(11 km, 12 km) - 12 km

= 11 km - 12 km

= -1 km (No coverage within the range)

Since there is no rain cell coverage within the range of interest, the propagation factor due to rain cell 2 is 0 dB.

Now, we can calculate the total propagation factor (F2) at 12 km by summing up the contributions:

F2 = Clear air absorption + Rain Cell 1 + Rain Cell 2

= 0.048 dB + 0 dB + 0 dB

= 0.048 dB

Therefore, the total propagation factor seen by the radar for a target at 12 km is 0.048 dB.

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State and explain the effect of this fault on the linearity of the thermometer

Answers

Explanation:

if the temperature changes , the liquid in the thermometer expands by a certain fixed amount, independent on the shape and the diameter of the capillary, only dependent on the amount of liquid. You can imagine but we'll see height difference upon a temperature changes if diameter is not constant

hope it helps you like me plz

12. Water at 25°C is heated and changed to gas at 100°C. What happened to the water molecules? It ___ A. stop moving B. move farther apartC. move more slowly D. move closer together

Answers

Answer:

B. move farther apart

Explanation:

Note that:

• The higher the temperature of a substance, the higher the kinetic energy possessed by its molecules

,

• The higher the kinetic energy possessed by the molecules, the higher their speed of motion

,

• The molecules of a gas have higher kinetic energy, hence they collide with each other and with the wall of the container.

When water is heated from 25°C to a gas at 100°C, the molecules posses higher kinetic energy(due to increase in temperature). Therefore, they move farther apart.

5. In an emergency, the driver of a 1.3 x 10³-kg car slams on the brakes, causing the car to skid forward on the road. The coefficient of kinetic friction between the tires and the road is 0.97, and the car comes to a stop after travelling 27 m horizontally. Determine the work done by the force of friction during the skidding.​

Answers

The work done by the force of friction during the skidding, given that the car comes to a stop after travelling 27 m horizontally is 333660.6 J

How do I determine the work done?

We'll begin by obtaining the frictional force. This can be obtained as follow:

Mass (m) = 1.3 x 10³ KgAcceleration due to gravity (g) = 9.8 m/s²Normal reaction (N) = mg = 1.3 x 10³ × 9.8 = 12740 NCoefficient of kinetic friction (μK) = 0.97Frictional force (F) = ?

F = μKN

F = 0.97 × 12740

Frictional force = 12357.8 N

Finally, we shall determine the work done by the force of friction. This is illustrated below:

Frictional force = 12357.8 NDistance (d) = 27 mWorkdone (Wd) =?

Work done (Wd) = force (F) × distance (d)

Wd = 12357.8 × 27

Wd = 333660.6 J

Thus, we can conclude that the work done by the force of friction is 333660.6 J

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When a skateboarder rides down a hill, the normal force exerted on the skater by
the hill is

When a skateboarder rides down a hill, the normal force exerted on the skater bythe hill is

Answers

Newton's second law allows us to find that the correct answer is:

Less than weight of the skater

Newton's second law states that the net force and is propositional to the mass and acceleration of the body

For these problems it is essential to set a reference system, with respect to which to carry out the measurements, in this case we set a coordinate system with the x axis parallel to the plane and positive in the direction of movement and the y axis perpendicular to the plane.

In the attachment we can see a free-body diagram of the problem, let's work each axis separately

x-axis

         Wₓ -fr = m a

y-axis

         N - \(W_y\) = 0

         N = \(W_y\)

Where Wₓ and W_y are the components of the weight, fr the friction force that opposes the movement, m the mass and the acceleration of the body

let's use trigonometry to find the components of the weight

        cos θ = \(\frac{W_y}{W}\)

        sin θ = \(\frac{W_x}{W}\)

         \(W_y\) = W cos θ

         Wₓ = W sin θ

we substitute

          N = mg cos θ

From this equation we can see that the normal is less than the weight of the body.

In conclusion using Newton's second law we find that the correct answer is:

Less than th weight of the skater

 

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When a skateboarder rides down a hill, the normal force exerted on the skater bythe hill is

The reason that worlds like the Earth are differentiated is that Group of answer choices the heat of the Sun vaporized much of their solid material early on the heaviest chunks that hit early on were able to bore through solid rock to the center the continuing impacts on a growing protoplanet eventually melted the entire body large amounts of hydrogen and helium collect around such planets a little later in their history planetesimals with different types of composition hit at different times, with the heaviest ones hitting first

Answers

Answer:

A differentiated body is a body that has been heated to the point where it is are further from the sun larger have no solid surface and have many more moons  Smaller chunks of material vaporize completely as they pass through its atmosphere

Explanation:

Hope it helps..

A body is said to be differentiated when it has been heated to the extent where it is bigger, farther from the sun, has no hard surface, and has a lot more moons. Smaller pieces of the materials entirely evaporate as they pass through their environment.

What is Planet?

An enormous, spherical celestial object known as a planet is neither a star nor a remain. The nebular theory, which states that an interstellar cloud collapses out of a nebula to form a young protostar that orbits the sun by a protoplanetary disk, is now the best argument for planet formation. By slowly accumulating material under the influence of gravity, or accretion, planets form in this disk.

The terrestrial planets Mercury, Venus, Earth, and Mars, as well as the planetary nebulae Jupiter, Saturn, Uranus, and Neptune, total at least eight planets in the Solar System. These planets all rotate around axes that seem to be inclined relative to their corresponding polar axes.

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9. two solid spheres, both of radius 5 cm, carry identical total charges of 2 !c. sphere a is a good conductor. sphere b is an insulator, and its charge is distributed uniformly through- out its volume. (i) how do the magnitudes of the electric fields they separately create at a radial distance of 6 cm compare?(a)ea.eb 50(b)ea.eb.0(c)ea5eb.0 (d)0,ea,eb (e)05ea,eb (ii)howdothemagnitudes of the electric fields they separately create at radius 4 cm compare? choose from the same possibilities as in part (i).

Answers

(i) The magnitudes of the electric fields they separately create at a radial distance of 6 cm is \(E_{a}\)=\(E_b}\). and (ii) The magnitudes of the electric fields they separately create at radius 4 cm is \(E_{a} =E_{b}\), so the correct option is option b.

What do you mean by conductor?

A conductor refers to a material that allows an electric current to flow through it with ease. In other words, it has a low electrical resistance. Conductors are materials that have a high number of free electrons that are able to move freely through the material. Examples of conductors include copper, aluminum, gold, and silver. These materials are commonly used in the electrical industry to make wires and other electrical components that need to conduct electricity. In addition to materials, a conductor can also refer to a person or an organization that is responsible for directing or leading an orchestra or a choir. In this context, a conductor is in charge of maintaining the ensemble's rhythm and intonation, and interpreting the score in a way that brings out the music's emotional content and intended meaning.

(i) The magnitude of the electric field created by a charged conductor is given by the formula E = \(\frac{kq}{r}\), where k is the Coulomb constant, q is the charge, and r is the distance from the center of the sphere.

For a good conductor, like sphere A, the charge will be distributed evenly on the surface of the sphere. So, the electric field at a radial distance of 6cm will be Eₐ = \(\frac{kq}{r^{2} }\) = \(k\frac{210^{-6} }{(619^{-2} )}^{2} =\frac{k}{72}\)

For an insulator, like sphere B, the charge is distributed uniformly throughout its volume. The electric field at a radial distance of 6cm will be \(E_{b}\)=  \(\frac{kq}{r^{2} }=k\frac{210^{-6} }{(619^{-2} )}^{2} =\frac{k}{72}\)

As we can see, the magnitudes of the electric fields created by both spheres are equal, so the answer is (b) \(E_{a} =E_{b}\)

(ii) For the radius of 4cm, the electric field created by sphere A and sphere B will

\(E_{a} =\frac{kq}{r^{2} }=k\frac{210^{-6} }{(410^{-2} )^{2} } =\frac{k}{16}\\E_{b} =\frac{kq}{r^{2} }=k\frac{210^{-6} }{(410^{-2} )^{2} } =\frac{k}{16}\\\)

As we can see, the magnitudes of the electric fields created by both spheres are equal at a radius of 4cm, so the answer is (b) \(E_{a} =E_{b}\)

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which component of the homemade spectrometer plays the critical role in creating the colorful spectrum?

Answers

The prism is the component of the homemade spectrometer that plays the critical role in creating the colorful spectrum.

In a homemade spectrometer, the prism is the key component responsible for creating the colorful spectrum. When white light passes through the prism, it undergoes refraction and dispersion. The prism bends different wavelengths of light by different amounts, separating them into their individual colors and creating a spectrum. This phenomenon is known as dispersion. The prism's ability to refract and disperse light is what allows us to see the range of colors in a spectrum, from red to violet.

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You are gardening in the peak of summer, it hasn't rained in a week, and your plants are looking rough. You decide to water the plants for an hour. The next day you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. With what you know from class, please try and explain what is happening to your plants.

Answers

In the peak of summer, it hasn't rained in a week, and the plants are looking rough, so watering the plants for an hour is a good idea.

However, the next day, you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. Plants absorb water through their roots. The root system of a plant is responsible for drawing water and nutrients from the soil. A plant's root system must be able to absorb water quickly in order for the plant to grow and thrive. When the soil around the root system is dry, the roots will stop growing and will not be able to absorb water.

It may even start to die. Watering plants during the peak of summer is important because it will help keep the soil moist and prevent the roots from drying out. However, watering a plant too much can be harmful. If a plant is overwatered, the water may not be able to penetrate the soil and reach the roots. Instead, it may just sit on top of the soil, causing the roots to rot and die. This can cause the plant to wilt and die.To summarize, if the soil around the plant is too dry, the roots may not be able to absorb the water you gave them, causing the plant to look worse than before. Conversely, overwatering can also be harmful because the water may not be able to penetrate the soil and reach the roots, causing the roots to rot and die.

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Explain why an open umbrella will hit the ground after a closed umbrella

Answers

Answer:

An open umbrella would not hit the ground before the closed one.   Explanation: The closed umbrella would hit first because it doesn't have as much air pressure hitting it. The open one has air pushing against it making it to where the open umbrella floats but falls slowly.    

An open umbrella will hit the ground after a closed umbrella because it has

a larger surface area and more air pressure and resistance.

An open umbrella has more surface araea which means more air particles

interacting with it. This slows it down and is the reason it hits the ground

after the closed umbrella.

Closed umbrella on the other hand have a smaller surface area and less air

resistance which is why it hits the ground faster.

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1.29 An objects average density P is defined as the ratio of its mass to its volume. P = M/V. The earth's mass is 5.94 X 10^24 ks and its volume is 1.08 X 10^12 km^3. What is the earth's average density?
A 5.50 X 10^3 Kg/M^3
B 5.50 X 10^6 Kg/M^3
C 5.50 X 10^9 Kg/M^3
d 5.50 X 10^12 Kg/M^3

Answers

The Earth's average density is 5.50 x \(10^3\) kg/\(m^3,\) which is option A.

We can use the formula for average density, P = M/V, to find the Earth's average density, where M is the mass of the Earth and V is its volume.

We are given that the mass of the Earth is 5.94 x\(10^24\) kg and its volume is 1.08 x \(10^{12} km^3\). However, we need to ensure that the units are consistent before we calculate the average density.

First, we convert the volume from km^3 to m^3 since the mass is given in kilograms:

V = 1.08 x\(10^{12} km^3\) x (\(10^3\) m/km)\(^3\) = 1.08 x \(10^{21} m^3\)

Now we can calculate the average density:

P = M/V = 5.94 x \(10^{24}\) kg / 1.08 x\(10^{21} m^3\) = 5.50 x \(10^3 kg/m^3\)

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- Show the motion of a car that travels
for 30 seconds on a highway at a speed
of 2 km/h, pulls off on the shoulder
and stops for half a minute, and then
resumes its trip at half its previous
speed.

- Show the motion of a car that travelsfor 30 seconds on a highway at a speedof 2 km/h, pulls off on

Answers

The motion of the car in each interval of time are:

Δt(1) from 0 to 30 s and Δx(1) from 0 to 0.02 km

Δt(2) from 30 to 60 s and Δx(2) from 0.02 to 0.02 km

Δt(3) from 60 to 120 s and Δx(3) from 0.02 to 0.04 km  

We know that car has a speed of 2 km/h in 30 seconds, we can use this information to find the distance in this interval of time.

Let's use the definition of speed.

\(v=\frac{\Delta x}{\Delta t}\) (1)

Before finding the distance we need to convert the units of velocity, from km/h to km/s.

\(2\frac{km}{h}*\frac{1\: h}{3600\: s}=5.56*10^{-4}\: km\)

Now we can use the equation (1) and solve it for Δx

\(\Delta x_{1}=v\Delta t\)

\(\Delta x_{1}=5.56*10^{-4}*30\)  

\(\Delta x_{1}=0.02\: km\)

Then, the car stops 30 seconds, and finally, it returns its travel at half its previous speed, which means at 1 km/h.

\(1\frac{km}{h}=2.78*10^{-4}\frac{km}{s}\)

We calculate the final distance using \(t_{3} = 60 s\) because the plot shows this value as the maximum interval of time.

\(\Delta x_{3}=2.78*10^{-4}*60=0.02\: s\)

We can resume all the trajectories in the following list.

Δt(1) from 0 to 30 s and Δx(1) from 0 to 0.02 km

Δt(2) from 30 to 60 s and Δx(2) from 0.02 to 0.02 km

Δt(3) from 60 to 120 s and Δx(3) from 0.02 to 0.04 km  

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- Show the motion of a car that travelsfor 30 seconds on a highway at a speedof 2 km/h, pulls off on

The polar jet stream flows from west to east, under the influence of the Earth's rotation, in _________

Answers

The polar jet stream flows from west to east, under the influence of the Earth's rotation, in the upper troposphere.

It is a fast-moving, narrow band of strong winds that is located around 30,000 to 40,000 feet above the Earth's surface. The polar jet stream forms due to the temperature difference between the polar regions and the mid-latitudes. As the cold polar air meets the warmer air from the mid-latitudes, it creates a boundary known as the polar front.

The polar jet stream then forms along this boundary, acting as a sort of "river of air" that separates the colder air to the north from the warmer air to the south. The speed and position of the polar jet stream can vary throughout the year, influencing weather patterns and the movement of storms.

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Akito pushes a wheelbarrow with 800 W of power. How much work is required to get the wheelbarrow across the yard in 12 s? Round your answer to the nearest whole number.

It takes
J of work to get the wheelbarrow across the yard.

Answers

Answer:

9600

Explanation:

Answer:

Hey... your answer is 9,600

Explanation:

Hope this helps :)

Here is prove just in case...

Best of luck <3

Akito pushes a wheelbarrow with 800 W of power. How much work is required to get the wheelbarrow across

mix 4 L of 30°C water is 6 L of 40°C water and you’ll have water at what temperature?

Answers

Answer:

dont know

Explanation:

need points

Describe and explain how energy is transferred in the bulbs. Use scientific ideas to support your answer

Answers

Answer:

In the light bulb, the flow of charge through the filament heats it up and causes it to glow. In this way, the light bulb converts electrical energy to heat energy and light energy.

Explanation:

In the light bulb, the flow of charge through the filament heats it up and causes it to glow. In this way, the light bulb converts electrical energy to heat energy and light energy.

USE THE DEFLECTON EQUATIONS TO FIND THE REACTIONS AT THE SUPPORTS.

Answers

Answer: To find the reactions at the supports, you need to use the deflection equations.

ΣM = 0, which means that the sum of the moments of the forces acting on the beam is zero.

ΣF = 0, which means that the sum of the forces acting on the beam is zero.

To do this, follow the steps below:

Step 1: Draw the free-body diagram (FBD) of the structure.

Step 2: Determine the forces acting on the beam, which includes the load (w) and the reactions at the supports (RA and RB).

Step 3: Use the equation of deflection (δ) to find the reactions at the supports.

The equation of deflection is:

δ = wx² / (24EI) for a simply supported beam with a uniform load,

where w is the load,

x is the distance from the left end of the beam,

E is the modulus of elasticity of the beam material, and

I is the moment of inertia of the beam.

Step 4: Apply the boundary conditions to find the values of the reactions at the supports.

The boundary conditions are:

δ(0) = 0, which means that the deflection at the left end of the beam is zero.

δ(L) = 0, which means that the deflection at the right end of the beam is zero.

ΣM = 0, which means that the sum of the moments of the forces acting on the beam is zero.

ΣF = 0, which means that the sum of the forces acting on the beam is zero.

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An acceptable charging circuit voltage on a 12 volt system is
13.5 to 15 volts
13.5 to 16 volts
13.5 to 17 volts
13.5 to 18 volts

Answers

An acceptable charging circuit voltage for a 12-volt system typically ranges from 13.5 to 15 volts. The correct option is A.

This voltage range is crucial for maintaining the battery's health and ensuring that it operates efficiently. The charging circuit, which consists of the alternator, voltage regulator, and wiring, maintains the battery's charge and provides electrical power to the vehicle's systems.

The alternator, driven by the engine, generates electrical power, while the voltage regulator controls the output voltage to prevent overcharging or undercharging.

When the engine is running, the charging circuit must supply enough voltage to recharge the battery after starting and provide power to the vehicle's electrical systems without overloading the battery.

A voltage range of 13.5 to 15 volts ensures that the 12-volt battery is sufficiently charged, and its capacity is maintained at an optimal level.

Overcharging (above 15 volts) can cause excessive heat, leading to battery damage or failure, while undercharging (below 13.5 volts) can result in reduced battery life and inadequate power for the vehicle's electrical systems.

To summarize, for a 12-volt system, the acceptable charging circuit voltage is 13.5 to 15 volts, as this range allows for efficient battery charging, optimal performance, and extended battery life.

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The tallest volcano on Mars

A
is three times the height of Mt. Everest.

B
is almost as tall as Mt. Everest.

C
has been visited 44 times.

D
is wet, rocky and cold.

Answers

Answer: Is three times the height of Mt. Everest

Explanation:

Using the process of elimination we can rule out “D” Because its a volcano, C because it says we have visited mars 44 times not the volcano, B because in the passage is literally says “3 times the size of Mt. Everest”.

Answer A is correct

Mars features the tallest volcano in the solar system, which is three times the
height of Mt. Everest and approximately the size of New Mexico. And It's a dry, rocky, cold planet situated
fourth from the Sun. It's called the red planet because of its red hue. Mars has two moons
called Phobos and Deimos.
The tallest volcano on Mars

A scientist tests what change would add the most energy to a moving ball. Which of these would add the most energy?
Tripling the speed of the ball.

Doubling the mass of the ball.

Doubling the speed of the ball.

Tripling the mass of the ball.

Answers

Tripling the speed because it’s giving off more energy

reselasie3. An object of mass 900 kg is hanging from a ceilingby means of two strings. The first string (7₁) makes anangle of 40 degree with the horizontal-right. The second string(T₂) makes an angle of 20 degree with the horizontal-left.Calculate the tension in the first string (7₁) (2 point)A. O12034.001 NB. O14675.062 NC. 5790.32 ND. 09570.261 NE. 13316.872 N

reselasie3. An object of mass 900 kg is hanging from a ceilingby means of two strings. The first string

Answers

First, find the weight of the object.

W = m g = 900 x 9.8 = 8,820 N

T2x = -t2 cos 20

t1 x = t1cos 40

mgx= 0

T2y= t2 sin 20

t1y= t1 sin 40

mgy= - mg

X and y components of resultant (R)

Rx = t1x -t2x + mgx

Rx= -t2 cos 20 + t1cos 40 (3)

Ry = t2 sin 20 + t1 sin 40 - mg(2)

Rx, and Ry = 0

0 = -t2 cos 20 + t1cos 40 (3)

0= t2 sin 20 + t1 sin 40 - mg (4)

Solve (3)

0 = -t2 cos 20 + t1cos 40

t2 cos 20 = t1 cos 40

t2 = t1 cos40/cos20

t2 = 0.815 t1

Substitute t2 in 4

0 = t2 sin 20 + t1 sin 40 - mg

0 = (0.815 t1) sin 20 + t1 sin 40 - 8,820

0= t1 ( 0.815 sin 20 + sin 40 ) -8820

0 = 0.921 t1 -8820

8820 = .921 t1

t1 = 8820/0.921

t1= 9570.261N (option D)

reselasie3. An object of mass 900 kg is hanging from a ceilingby means of two strings. The first string

Which of these equations will you used to find the final velocity if the initial
velocity and time is given? *

Which of these equations will you used to find the final velocity if the initialvelocity and time is

Answers

Answer:

2.77 would be the answer for this

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