Two concrete spans of a 370 m long bridge are
placed end to end so that no room is allowed
for expansion. 370 mT T + 20◦Cy
If the temperature increases by 20◦C, what
is the height to which the spans rise when
they buckle? Assume the thermal coefficient
of expansion is 1.2 × 10−5(◦C)−1

Answer in units of m.

Patriarchy, which describes the oppression and marginalization that women face in communities where men hold the majority of the authority, is a term used to describe most modern societies.

Beyond purely economic, legal, or political means, there are numerous more ways that this dominance of men is perpetuated, including through language, stereotypes, religions, culture, traditions, and the media.

As patriarchy existed before capitalism and has continued to do so, they must be separate from one another. Defenders of this theory tend to investigate women's oppression separately and employ the same technique as studies of class oppression, despite the fact that they occasionally impact and benefit from one another.

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Explanation:

Formula:

F*255.92778=K

83 F *255.92778=301.48k

therefore the answer is:

301.48K

Refraction is the property of light that allows you to see a variety of colors in a spray of water on a sunny day.

Because a medium's refractive index depends on wavelength, light of various wavelengths is refracted at various angles, resulting in the splitting of the light beam into various colors.

Light waves are bent at different angles because they are slowed down at varying rates. For instance, the wavelengths of the rainbow are created when the entire visible light spectrum passes through the glass of a prism.

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The magnitude of electrical force on charge \(q_{3}\) due to the others is 0.102 newtons.

The vector position of each particle respect to origin are described below:

\(\vec r_{1} = (-0.500, 0)\,[m]\)

\(\vec r_{2} = (+0.500, 0)\,[m]\)

\(\vec r_{3} = (0, +0.500)\,[m]\)

Then, distances of the former two particles particles respect to the latter one are found now:

\(\vec r_{13} = (+0.500, +0.500)\,[m]\)

\(r_{13} = \sqrt{\vec r_{13}\,\bullet\,\vec r_{13}} = \sqrt{(0.500\,m)^{2}+(0.500\,m)^{2}}\)

\(r_{13} =\frac{\sqrt{2}}{2}\,m\)

\(\vec r_{23} = (-0.500, +0.500)\,[m]\)

\(r_{23} = \sqrt{\vec r_{23}\,\bullet \,\vec r_{23}} = \sqrt{(-0.500\,m)^{2}+(0.500\,m)^{2}}\)

\(r_{23} =\frac{\sqrt{2}}{2}\,m\)

The resultant force is found by Coulomb's law and principle of superposition:

\(\vec R = \vec F_{13}+\vec F_{23}\) (1)

Please notice that particles with charges of same sign attract each other and particles with charges of opposite sign repeal each other.

\(\vec R = \frac{k\cdot q_{1}\cdot q_{3}}{r_{13}^{2}}\cdot \vec u_{13} +\frac{k\cdot q_{2}\cdot q_{3}}{r_{23}^{2}}\cdot \vec u_{23}\) (2)

Where:

If we know that \(k = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}\), \(q_{1} = 2\times 10^{-6}\,C\), \(q_{2} = 2\times 10^{-6}\,C\), \(q_{3} = 2\times 10^{-6}\,C\), \(r_{13} =\frac{\sqrt{2}}{2}\,m\), \(r_{23} =\frac{\sqrt{2}}{2}\,m\), \(\vec u_{13} = \left(-\frac{\sqrt{2}}{2}, - \frac{\sqrt{2}}{2} \right)\) and \(\vec u_{23} = \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)\), then the vector force on charge \(q_{3}\) is:

\(\vec R = \frac{\left(8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot (2\times 10^{-6}\,C)\cdot (2\times 10^{-6}\,C)}{\left(\frac{\sqrt{2}}{2}\,m \right)^{2}} \cdot \left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right) + \frac{\left(8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot (2\times 10^{-6}\,C)\cdot (2\times 10^{-6}\,C)}{\left(\frac{\sqrt{2}}{2}\,m \right)^{2}} \cdot \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)\)

\(\vec R = 0.072\cdot \left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right) + 0.072\cdot \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)\,[N]\)

\(\vec R = 0.072\cdot \left(0, -\sqrt{2}\right)\,[N]\)

And the magnitude of the electrical force on charge \(q_{3}\) (\(R\)), in newtons, due to the others is found by Pythagorean theorem:

\(R = 0.102\,N\)

The magnitude of electrical force on charge \(q_{3}\) due to the others is 0.102 newtons. \(\blacksquare\)

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Answer:

W = 15,000 Joule

Explanation:

Mechanical Work

Mechanical work is the amount of energy transferred by a force. It's a scalar quantity, with SI units of joules.

If both the force and displacement are parallel, then we can use the scalar formula:

W=F.s

Where

F =Magnitude of the force

s = magnitude of the displacement

The tornado moved a trailer with a force of F=600 N for a distance of s=25 m. The work done was:

W = 600 N * 25 m

W = 15,000 Joule

Answer:

D

Explanation:

Answer:

Yes The stage of development was from birth to around 2.

Explanation:

On the moon you weigh 6 times lighter so for this problem you multiply 140n by 6.

Your weight on the Moon is 16.5% what you would experience on Earth. In other words, if you weighed 100 kg on Earth, you would weigh a mere 16.5 kg on the Moon. For you imperial folks, imagine you tipped the scales at 200 pounds.

It’s because of the lower gravity on the Moon. Objects on the surface of the Moon experience only 16.5% of the gravity they would experience on Earth.

The mass of the Moon is only 1.2% the mass of the Earth, so you might expect it to have only 1.2% of the gravity. But it’s only 27% of the size of the Earth, so when you’re standing on the surface of the Moon, you’re much closer to its center of gravity.

Therefore, On the moon you weigh 6 times lighter so for this problem you multiply 140n by 6.

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Answer:

mass

Explanation:

To increase the torque applied to a stubborn bolt, you would need more applied force and/or more lever-arm.

Option B is correct. By using a longer wrench or adding a cheater bar to the wrench, you can increase the lever-arm and therefore the torque applied. Additionally, using a breaker bar or impact wrench can increase the applied force and help to loosen the stubborn bolt.

Option A is not correct as only increasing the applied force may not be enough to break the bolt loose.

Option C is not correct as the applied torque can indeed be increased. Option D is not correct as reducing the applied force and lever-arm would decrease the torque applied.
To increase the torque applied to a stubborn bolt, you need both more applied force and more lever-arm. This is because torque is the product of force and lever-arm, and increasing both of these factors will result in a higher torque, making it easier to loosen the stubborn bolt.

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Cumulus clouds often indicate Optiion C. possible turbulence.

Turbulence, associated with thunderstorms, may be extremely risky, having the ability to motivate overstressing of the aircraft or lack of manipulation. Thunderstorm vertical currents can be sturdy sufficient to displace a plane up or down vertically as plenty as 2000 to 6000 ft.

Turbulence is only one type of alternate in the air around your aircraft. Air is not nothingness; it's a fluid, like water. Currents of airflow up and down, ripple out, trade direction, and change speed. some of the things that reason turbulence are simpler to expect.

Turbulence is an unexpected and every-so-often violent shift in airflow. the ones irregular motions within the atmosphere create air currents that may purpose passengers on an aircraft to enjoy stressful bumps throughout a flight, or it is able to be extremely sufficient to throw an airplane out of manage.

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Answer:

electromagnetic radiation

Explanation:

Answer:

No.

Explanation:

A feather is less dense and thus less force exerted while a rock is very dense thus exerting more force .

In a human centrifuge, the resultant normal force on the pilot from the bottom of the seat is nine times the pilot's weight when they pull 9g. The centrifuge has a constant angular acceleration of 1.5 rpm per second until the pilot pulls 9g. The centrifuge then continues with a constant angular velocity.

The question explains that when the aerospace physiologists state that the pilot is pulling 9g, it means that the normal force that acts on the pilot is nine times the pilot's weight. When using a human centrifuge, the centrifuge begins at rest and has a constant angular acceleration of 1.5 rpm per second until the pilot pulls 9g.

After that, the centrifuge maintains a constant angular velocity of 1.5 rpm. The resultant normal force on the pilot from the bottom of the seat is nine times the pilot's weight when they pull 9g. In human centrifuges, 9g's of force are produced on pilots, which aerospace physiologists calculate as the resultant normal force on the pilot from the bottom of the seat.

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Answer: When you change the direction of the current, you also change the direction of the magnetic field. Because the magnetic field created by the electric current in the wire is changing directions around the wire, it will repel both poles of the magnet by bending away from the wire.

Explanation:

Grant sprinted for 16.67 seconds when his average speed was 3.0 m/s.

With an average speed of 3.0 m/s, Grant sprints 50 meters to the right.

So, the distance covered (s)  = 50 m

Average speed (v) = 3.0 m/s

Now,

The formula for evaluating the time(t) is given by,

\(t = \frac{s}{v}\)

Now, Putting all the values in the formula to evaluate time, we get:

\(t = \frac{50}{3} = 16.67\)

Hence, Grant sprinted for 16.67 seconds.

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Answer:

2.5

Explanation:

A rabbit is trying to cross the street. Its velocity v as a function of time t is given in the graph below where rightwards is the positive velocity direction 2.5 m.

When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.

Rabbit displacement is 2.5 m.

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Thus, the maximum velocity of the shadow on the wall is 2(0.401 m/s) = 0.802 m/s or 2.38 m/s to two significant figures.

The problem involves a ladybug crawling on a turntable, and its shadow moving back and forth on a wall.

To determine the maximum speed of the shadow on the wall, we need to calculate the linear velocity of the ladybug as it moves on the turntable using the formula v = rω, where v is the linear velocity, r is the distance from the center of the turntable to the ladybug, and ω is the angular velocity of the turntable.

The distance from the center of the turntable to the ladybug is given, and we can calculate the angular velocity of the turntable using the formula ω = 2πf, where f is the frequency of the turntable in revolutions per minute (rpm).

Plugging in the values we know into the formula v = rω, we can determine the maximum speed of the shadow on the wall to be 0.802 m/s, taking into account the shadow's movement back and forth across the wall.

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The room temperature if the gas thermometer records a pressure of 234mmHg is 248.84 K.

The temperature of reading of the thermometer is calculated by applying interpolation method.

220 mmHg --------> 270 K

234 mmHg ----------> x

270 mmHg ------------ > 373 K

Now solve for x,

( 234 - 220 ) / ( 270 - 220 ) = ( x - 270 ) / ( 373 - 270 )

0.28 = ( x - 220 ) / 103

103 ( 0.28 ) = x - 220

x = 248.84 K

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Answer:

  4. none of the above

Explanation:

A "15 °C calorie" (with a lower-case 'c') is defined as the amount of energy required to raise 1 gram of water from 14.5 °C to 15.5 °C at standard atmospheric pressure. That definition is one of at least 7 different definitions of the "gram calorie".

A Calorie (with an upper-case 'C') is 1000 calories. So the choice "1 Calorie" is attractive, but incorrect. It is 1000 times the amount of heat described.

none of the Joule or Calorie choices is correct

Answer:

Angle of Refraction ?

Explanation:

My decided answer on this question

The gain in translational kinetic energy of the cylinder when it has rolled 5m down the incline of the plane is approximately 345.6 J.

Given data:

Diameter, d = 0.20 mRadius,

r = 0.10 mMass of cylinder,

m = 12 kgInclined angle, θ = 37°

Distance traveled by cylinder, s = 5m

We know that work done by the gravitational force is the change in potential energy.

W=Fhsinθ... (1)

The kinetic energy of rolling objects is equal to its rotational kinetic energy plus its translational kinetic energy.

K = 1/2Iω² + 1/2mv²... (2)

The moment of inertia of a solid cylinder I=mr²/2.

Using conservation of energy principle:

Gain in translational kinetic energy of the cylinder is equal to the loss in potential energy.

Thus,

½mv²=mgH-mgSins....(3)

When the cylinder rolls without slipping, its velocity is equal to its angular velocity multiplied by its radius

v=ωr

Therefore, the rotational kinetic energy can be expressed as

1/2Iω²=1/2mr²ω²/2.... (4)

Using equations (1), (2), (3), and (4),

we can find the gain in translational kinetic energy of the cylinder while it rolls 5m down the incline of the plane.

K=1/2mv²=1/2m(v=ωr)²=1/2mr²ω²/2=1/2Iω²=1/2(12)(0.10)²(2/2)=0.12J... (5)

Potential energy, P=mgh=mgSins=12(9.8)(5)sin37°=294.2 J... (6)

So, using equations (5) and (6), we can get the gain in translational kinetic energy of the cylinder to be approximately:

K = 294.2 J – 0.12 J = 294.08 J

Therefore, the gain in translational kinetic energy of the cylinder when it has rolled 5 m down the incline of the plane is approximately 345.6 J.

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Our "cosmic address" from small to large are earth, solar system, milky way galaxy, local group, local supercluster, universe (option A)

The "smallest" is earth, it is the planet where we live and the third of the eight planets in the solar system.

The solar system is a collection of celestial bodies consisting of a star called the sun and all the objects that are bound by its gravitational force. And the milky way galaxy is the galaxy that contains our solar system. It is a barred spiral galaxy 100,000-120,000 light years in diameter containing 100-400 billion stars.

The local group is the group of galaxies that includes the milky way among others. It consists of more than 54 galaxies, including dwarf galaxies.

The local supercluster is one of the largest known cosmic structures in the universe. They are large, threadlike formations, with a typical length of 50 to 80 megaparsecs h-1, which form the boundaries between the great voids in the universe.

The universe is isotropic, the distance to the edge of the observable universe is approximately the same in all directions. That is, the observable universe is a spherical (spherical) volume centered on the observer, regardless of the shape of the universe as a whole.

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Answer:

Our "cosmic address" from small to large are earth, solar system, milky way galaxy, local group, local supercluster, universe (option A)

The index of refraction that halves the wavelength that light has in a vacuum is 2.00. Therefore, the correct option is (d) 2.00.

When light passes from one medium to another, it changes its velocity, and thus its wavelength. The index of refraction is a measure of how much light is bent when passing through a medium and can be calculated using Snell's Law:n1sin θ1=n2sin θ2where n1 and n2 are the indices of refraction of the two media, and θ1 and θ2 are the angles that the light makes with the normal line in the first and second media, respectively.

For a given angle of incidence, we can see that the index of refraction is directly proportional to the sine of the angle of refraction, which means that as the angle of refraction increases, so does the index of refraction. Now, let's assume that light is passing from vacuum (with index of refraction n1=1) to a medium with an unknown index of refraction n2.

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Given :

Thin hoop with a mass of 5.0 kg rotates about a perpendicular axis through its center.

A force F is exerted tangentially to the hoop. If the hoop’s radius is 2.0 m and it is rotating with an angular acceleration of 2.5 rad/s².

To Find :

The magnitude of F.

Solution :

Torque on hoop is given by :

\(\tau =F\times R\\\\I\alpha = FR\\\\MR^2\alpha = FR\\\\F = MR\alpha\)( Moment of Inertia of hoop is MR² )

Putting  value of M, R and α in above equation, we get :

\(F=5\times 2\times 2.5\ N\\\\F = 25 \ N\)

Therefore, the magnitude of force F is 25 N.

Hence, this is the required solution.

Answer:

W = 882.9[J]

Explanation:

In order to be able to calculate the work, we must first calculate the force necessary to lift the box. Since the necessary force is equivalent to the weight of the box, we can determine the weight of the box by means of the product of mass by gravitational acceleration.

\(w = m*g\\\)

where:

w = weight [N]

m = mass = 30 [kg]

g = gravity acceleration = 9.81 [m/s²]

\(w = 30*9.81\\w = 294.3 [N]\)

Now, the work can be calculated multiplying the force (weight) by the distance [m]

\(W = w*d\\W = 294.3*3\\W=882.9[J]\)

The statement that is true about an orbit with an eccentricity of almost 1 is:

C) The orbit is a very long and narrow ellipse.

The eccentricity of an orbit is a measure of how elongated or stretched out the shape of the orbit is. The eccentricity of an orbit ranges from 0 to 1, with 0 representing a perfectly circular orbit and 1 representing a highly elongated or eccentric orbit.

When the eccentricity is almost 1, it indicates that the orbit is highly elongated or stretched out. This means that the orbit is no longer close to being circular but takes on the form of a long and narrow ellipse. The closer the eccentricity is to 1, the more elongated the orbit becomes. Therefore, option C, stating that the orbit is a very long and narrow ellipse, is the correct statement for an orbit with an eccentricity of almost 1.

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They have a limited supply in nature, therefore if they are used excessively, they will become exhausted.

Today, we recognise that using fossil fuels has a negative impact on the environment. Fossil fuels produce and utilise local pollutants, and their continued use permanently alters the temperature of our entire world.

Wastes from combustion sources are those that result from carbon pollution (i.e., coal, oil, natural gas). Included in this are all ash and particles taken out of the flue gas.

The fossile fuel is limited in nature. So, it should not waste energy from fossil fuels.

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Answer:

polar-molecule

Explanation:

a. The image includes galaxies that are elliptical, spiral, and irregular. b. Careful study of the image shows that the youngest galaxies were mostly irregular in shape.

e. We see the more distant galaxies as they were when they were quite young. c. The galaxies in this image are part of a large galaxy cluster, bound together by gravity is not a true statement. The Hubble Extreme Deep Field image is actually a composite of several images taken over a period of 10 years, capturing light from galaxies as far back as 13 billion years ago, showing a diverse range of galaxies in various stages of formation and evolution, but they are not part of a single galaxy cluster. d. Careful study of the image shows that all present-day galaxies are spirals is also not a true statement. While there are many spiral galaxies present in the image, there are also many elliptical and irregular galaxies, indicating a wide variety of galaxy types throughout the universe.

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