Two particles, one with charge −6.29 μC and one with charge 5.23 μC, are 5.09 cm apart. What is the magnitude of the force that one particle exerts on the other?

Answers

Answer 1

The force between the two particles is gotten from coulomb's law as 12.697 kN

What is coulomb's law?

Coulomb's law states that that the force between two charged bodies is directly proportional to the product of the two forces and inversely proportional to the square of the distance between the bodies.

Given data

q1 = −6.29 μC

q2 = 5.23 μC

r = 5.09 cm = 0.0509

Force (f) = ( q1 * q2 ) / r^2

solution

f = -(  6.29 * 5.23 ) / 0.0509^2

f = 12..697 kN

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Related Questions

Which correctly describes latent heat?

A. The heat of molecules that are under pressure
B. The heat held inside of ice crystals colder than -2°C
C. The heat absorbed or lost by a substance while it's changing state
D. The heat used to change the temperature of a liquid

Answers

Option C. The heat absorbed or lost by a substance while it's changing state  correctly describes latent heat

Latent heat is the heat absorbed or lost by a substance while it is changing state.

The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.

For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.

Latent heat is not associated with a temperature change; rather, it's associated with a change of state.

For instance, the temperature of water remains at 100°C while boiling.

When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.

When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.

Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.

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A rifle fires a bullet at a velocity of 78 m/s, 40 degrees above the horizontal. Determine the height (h) above the starting position of the bullet 6 s after it has been fired.

Answers

Answer:

H = Vy t - 1/2 g t^2  height of an object with an initial "vertical" velocity

                                 at t sec after firing

Vy = 78 m/s * sin 40 = .643 * 78 m/s = 50.1 m/s

H = 50.1 * 6 - 1/2 * 9.8 * 6^2 = 300 m - 176 m = 124 m

Electrical energy is sold by the kilowatt hour How much would it cost to heat a hot tub from 15 to 43

Answers

Answer:

hot tub is hot

Explanation:

dont get fried

you are given a mask with a circular hole that is 4 cm in diameter, a bulb and a screen. you must produce a bright spot on the screen that is 5 times as large as the circular hole in the mask. the distance from the bulb to the mask is 12 cm.a)sketch your set up with similar triangles (sketch proportional!)b)show mathc)label the sketch with numbers and units, include:i) the bright spot on the screenii) the distance from the bulb to the screen

Answers

The proportionality of the corresponding sides

What is the proportional equation?

A proportional equation has the formula y = kx. The variables of the equation are represented by the letters y and x. The letter k indicates the proportionality constant, which remains constant.

The dimensions of a composition and the connections between height, breadth, and depth are referred to as proportion. The use of proportion influences how realistic or stylized something seems. Proportion also defines how the sizes of various sections of an artwork or design relate to one another.

Alternatively, the percentage can be expressed with colons as a:

b = c:d. The words that are farthest apart on the exterior are the a and the d. The words on the inside are the means: b and c. According to this principle, the product of the means equals the product of the extremes: ad = bc.

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Answer

Explanation

Which of the following is a force acting between objects that do not touch? Pls answer in 5-10 min!
Normal force
Frictional force
Electrical force
Applied force

Answers

Answer:

Electrical force

Explanation:

The electrons aren't actually touching each other. Normal is something on something pushed by gravity by they are touching, frictional is rubbing, applied is pushing

What is the momentum of a 5 kg object that has a velocity of 1.2 m/s?
a) 3.8 kg • m/s
b) 4.2 kg • m/s
c) 6.0 kg • m/s
d) 6.2 kg • m/s

Answers

Explanation:

answer is 6.0Kg •m/s because

momentum= mass • velocity

that is 5 • 1.2 = 6

Convert 25miles/hour to kilometers/hour. Show your work

Answers

Using the conversion factor that we have seen in the solution, the value obtained is 40.25 kilometers per hours

How do you convert miles/hour to kilometers per hour?

To convert miles per hour (mph) to kilometers per hour (kph), you need to multiply the speed value in mph by a conversion factor of 1.61, which is the number of kilometers in one mile.

Given that;

1 miles/hour = 1.61 kilometer per hour

25 miles per hour = 25 * 1.61/1

= 40.25 kilometers per hours

Hence the value that we get is 40.25 kilometers per hours

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The convert unit of  25 miles per hour is equivalent to 40.2335 kilometers per hour

Convert units calculation.

Unit conversion is the process of converting a value expressed in one unit of measurement to another unit of measurement that is equivalent in terms of its value or quantity. This is done by using a conversion factor, which is a numerical factor that relates the two units of measurement.

To convert miles per hour (mph) to kilometers per hour (km/h), we need to multiply the speed in mph by 1.60934, which is the conversion factor from miles to kilometers.

So, to convert 25 mph to km/h:

25 mph × 1.60934 = 40.2335 km/h

Therefore, 25 miles per hour is equivalent to 40.2335 kilometers per hour.

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1. Two charges are separated by a distance of 1 cm. One charge has a value of 7 micro Coulombs. The other charge has a value of 10 micro Coulombs. What is the force between them, in pounds. Make sure to include the sign of the force which will be positive if the charges repel each other and negative if they attract each other.

2. 12 gauge copper wire is normally used in house wiring. When aluminum wire is used one needs to use a smaller gauge size to obtain the same resistance, 40 ft of 12 gauge copper wire was calculated. What would the resistance be if 10 gauge aluminum wire were used?

3. A 12 V automobile battery can supply 51 amps for one hour and cost $194. What is the cost of this electricity in cents per kWh?

4. Most of the body's resistance is in its skin. When wet, salts go into ion form, and the resistance is lowered. Thus, the resistance of the skin can go from 100,000 ohms when dry to 300 ohms when wet. What is the current that would be carried through the body, in milliAmperes, if you touched a 240 V power line while dry? Currents over 10 mA are almost always deadly.

Answers

1. The force between the two charges is 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of 10 gauge aluminum wire over a 40 ft distance would be 0.506 ohms.

3. The cost of electricity from the automobile battery is 38.6 cents per kWh.

4. The current that would be carried through the body is 0.8 mA if dry.

1. The force between two point charges can be calculated using Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.

Using the values given, the force can be calculated as F = (k * q1 * q2) / r², where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them. Plugging in the values, the force can be calculated as 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of a wire is determined by its length, cross-sectional area, and resistivity. The resistivity of aluminum is higher than that of copper, so a larger cross-sectional area is required to achieve the same resistance. Using the gauge size conversion chart, 10 gauge aluminum wire has a cross-sectional area of 5.26 mm², which is approximately 83% of the cross-sectional area of 12 gauge copper wire.

Thus, the resistance of 10 gauge aluminum wire over a 40 ft distance can be calculated as R = (rho * L) / A, where rho is the resistivity of aluminum, L is the length, and A is the cross-sectional area. Plugging in the values, the resistance can be calculated as 0.506 ohms.

3. To calculate the cost of electricity per kWh, the total cost and the total amount of energy supplied must be known. Since the battery supplies 12 V and 51 A for one hour, the total energy supplied can be calculated as E = V * I * t, where V is the voltage, I is the current, and t is the time.

Plugging in the values, the total energy supplied can be calculated as 612 watt-hours (Wh). Since one kWh is equal to 1000 Wh, the total energy supplied can be converted to 0.612 kWh. Dividing the total cost by the total energy supplied gives the cost per kWh, which is 38.6 cents.

4. The current through the body can be calculated using Ohm's law, which states that current is equal to voltage divided by resistance. Using the values given, the resistance can be either 100,000 ohms or 300 ohms depending on whether the skin is dry or wet.

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State the three rules of refraction for converging lenses

Answers

The three rules of refraction for converging lenses, also known as convex lenses, are as follows:

1. The incident ray parallel to the principal axis refracts through the lens and passes through the focal point on the opposite side of the lens.

2. The incident ray passing through the focal point refracts and emerges parallel to the principal axis.

3. The incident ray passing through the center of the lens continues undeviated.

The three rules of refraction for converging lenses, also known as convex lenses, are as follows:

1. The incident ray parallel to the principal axis refracts through the lens and passes through the focal point on the opposite side of the lens.

When a ray of light traveling parallel to the principal axis (the horizontal line passing through the center of the lens) enters a converging lens, it refracts and bends toward the principal axis. After refraction, the ray passes through the focal point on the opposite side of the lens. This rule is essential in understanding the behavior of light rays in converging lenses.

2. The incident ray passing through the focal point refracts and emerges parallel to the principal axis.

When a ray of light passes through the focal point before entering the lens, it refracts and emerges parallel to the principal axis. This rule implies that light rays that enter the lens at different angles converge and meet at the focal point on the opposite side.

3. The incident ray passing through the center of the lens continues undeviated.

When a ray of light passes through the center of a lens, it continues in a straight line without deviating from its path. This rule is derived from the fact that the refractive index of the lens material is the same throughout, resulting in no change in the direction of light passing through the center of the lens.

These rules of refraction for converging lenses help in understanding how light rays interact with the lens and how the lens focuses incoming light. By applying these rules, one can predict the behavior of light rays and determine the location and characteristics of images formed by converging lenses.

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Practice 4: Use the HR Diagram to match the descriptions with the correct stars
A.
Section Break
B. Main Sequence Stars
C. Super giants
D. Higher temperature stars
E. Red Stars

Answers

Answer:

Hertzsprung-Russell Diagram

The Hertzsprung-Russell diagram (HR diagram) is one of the most important tools in the study of stellar evolution. Developed independently in the early 1900s by Ejnar Hertzsprung and Henry Norris Russell, it plots the temperature of stars against their luminosity (the theoretical HR diagram), or the colour of stars (or spectral type) against their absolute magnitude (the observational HR diagram, also known as a colour-magnitude diagram).

Depending on its initial mass, every star goes through specific evolutionary stages dictated by its internal structure and how it produces energy. Each of these stages corresponds to a change in the temperature and luminosity of the star, which can be seen to move to different regions on the HR diagram as it evolves. This reveals the true power of the HR diagram – astronomers can know a star’s internal structure and evolutionary stage simply by determining its position in the diagram.

Explanation:

Hence the answer is C : Super Giants

laws of vector addition​

Answers

Answer:

laws ig .

Explanation:

Not quite sure what you’re looking for.

Triangle law of vector addition states that when two vectors are represented as two sides of the triangle with the order of magnitude and direction, then the third side of the triangle represents the magnitude and direction of the resultant vector.

A 60-kg patient about to have a brain scan is injected with 0.02 Ci of the radionuclide Technetium-99. Technetium-99 decays to the ground state with a half-life of 6.0 hours. The Technetium-99 nucleus decays by emitting a 143-keV photon. Assume that half of these photons escape the body without interacting. What biological equivalent dose does the patient receive? The relative biological effectiveness (RBE) for these photons is 0.97 Assume that all of the Technetium-99 decays while in the body. [10 marks)

Answers

u my CCTV camera for video

Explanation:

because I have a big deal for me

Compare and contrast position graphs and velocity graphs.

Answers

Answer:

The difference between them is that the velocity-time graph reveals the speed of an object (and whether it is slowing down or speeding up), while the position-time graph describes the motion of an object over a period of time.

Explanation:

can anyone heelp me plzz

can anyone heelp me plzz

Answers

Answer:

the ans is D... good luck

g A 150-kg object and a 450-kg object are separated by 4.90 m. (a) Find the magnitude of the net gravitational force exerted by these objects on a 39.0-kg object placed midway between them. 130000000000 Incorrect: Your answer is incorrect. Draw a picture of the three objects, including the forces exerted on the third. N (b) At what position (other than an infinitely remote one) can the 39.0-kg object be placed so as to experience a net force of zero from the other two objects

Answers

Answer:

BBbbb

Explanation:

B is the correct answer:))))

Help Me Please
8th grade science, one question ​

Help Me Please8th grade science, one question

Answers

You can make a laser go through someone’s skin in some circumstances you can’t do that with other light sources

"The diffusion coefficient D for Al in Al2O3 is 7.48 X 10^-23 m^2/s at 1000C and is 2.48 X 10^-14 m^2/s at 1500C. Calculate the activation energy for this diffusion process."

Answers

The activation energy for the diffusion process of Al in Al2O3 is approximately 225,744 J/mol.

To calculate the activation energy for the diffusion process of Al in Al2O3, we can use the Arrhenius equation:

D = D0 * exp(-Q/RT)

where D is the diffusion coefficient, D0 is a constant, Q is the activation energy, R is the gas constant, and T is the absolute temperature.

Taking the natural logarithm of both sides, we get:

ln(D/D0) = -Q/RT

We can then use the given diffusion coefficients and temperatures to obtain two equations:

ln(D1/D0) = -Q/RT1

ln(D2/D0) = -Q/RT2

where D1 and T1 are the diffusion coefficient and temperature at 1000C, and D2 and T2 are the diffusion coefficient and temperature at 1500C.

Taking the ratio of the two equations, we get:

ln(D2/D1) = Q/R * (1/T1 - 1/T2)

Solving for Q, we get:

Q = -R * ln(D2/D1) / (1/T1 - 1/T2)

Plugging in the given values, we get:

Q = -8.314 J/mol-K * ln(2.48 x 10^-14 m^2/s / 7.48 x 10^-23 m^2/s) / (1/1273 K - 1/1773 K)

Q ≈ 225,744 J/mol

Therefore, the activation energy for the diffusion process of Al in Al2O3 is approximately 225,744 J/mol.

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answer the question in the picture

answer the question in the picture

Answers

The option that represents what the magnetic field look like above the North pole is an arrow that decreases as we go up and points up (E)

How to explain the information

The magnetic field lines of a magnet point away from the north pole and towards the south pole. The field lines are strongest at the poles and weaken as you move away from the poles.

So, the arrow that represents the magnetic field above the north pole will be pointing up, but it will become smaller and smaller as you go up.

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A Ping-Pong ball is shot into a circular tube that is lying flat (horizontal) on a table-top.
Figure attached.

When the Ping-Pong ball exits the tube, which path will it follow in the figure?
d
a
c
b
e

Answers

Answer:

e

Explanation:

assignment questions

Answers

Answer:

which on a is the question

When you see yourself in a plane mirror the image is always

Answers

When you see yourself in a plane mirror, the image is always virtual, erect and the image formed has same size as that of the object

Besides that, the image will be at the same distance behind the mirror as the object is in the front of the mirror, so we can say that the image formed by the plane mirror is an exact copy of ourselves

Because the light does not actually pass through the image, that's why  the image formed by plane mirror is called a virtual image and the real images are formed by curved mirror and they are produced on the same side as that of the mirror

But the only difference is that the image formed by plane mirror is laterally inverted, means if raise our right hand then it would appear in the mirror as if we have raised our left hand

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your hand feels cold when you hold an ice cube because A. the ice radiates cold to your hand B. the ice conducts cold to your hand C. your hand cools down by convection. D.Your hand transfers thermal energy to the ice​

Answers

your hand feels cold when you hold an ice cube because D.Your hand transfers thermal energy to the ice

Is there a flow of cold from the ice to your hand?

The ice does not transfer cold to your hand. Heat is transferred from your hand to the ice. When you are transmitting heat to the metal, it feels chilly to the touch.

Heat energy constantly flows from high temperature to low temperature. The temperature of the fingers is higher than that of ice. As a result, energy will be transferred from the finger to the ice.

This is due to the larger quantity of heat from our body moving to the ice through our skin (through thermal conduction) in order to achieve thermal equilibrium between the ice and the body.

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Assuming birdman flies at a height of 78m, how fast should birdman fly to hit the bucket if the bucket is placed 75m from the start of the field?

Answers

The speed of how fast the birdman should be to hit the bucket is 18.8 m/s

The only force acting on the height at which birdman flies is the gravitational force field.

Suppose the initial velocity (u) is parallel to the ground when the time (t) hits the ground.

Then, we can use the second equation of motion to determine the time (t) when the bird hits the ground.

\(\mathbf{S = ut + \dfrac{1}{2}gt^2}\)

\(\mathbf{78 \ m =(0)t + \dfrac{1}{2}(9.8)t^2}\)

\(\mathbf{78 \ m =4.9 t^2}\)

\(\mathbf{t^2 = \dfrac{78 \ m}{4.9 m/s^2} }\)

\(\mathbf{t^2 = 15.918 \ s^2}\)

\(\mathbf{t =\sqrt{ 15.918 \ s}}\)

\(\mathbf{t =3.989\ s}}\)

Now, the speed of how fast the birdman should be to hit the bucket can be determined using;

\(\mathbf{Speed = \dfrac{Distance}{Time}}\)

\(\mathbf{Speed = \dfrac{75 \ m }{3.989\ s}}\)

\(\mathbf{Speed = 18.8 m/s}\)

Therefore, we can conclude that the speed of how fast the birdman should be to hit the bucket is 18.8 m/s

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A power plant running at 31 % efficiency generates 270 MW of electric power. Part A At what rate (in MW) is heat energy exhausted to the river that cools the plant

Answers

The rate of heat energy exhausted to the river is 600.96 MW.

What is efficiency?

The ratio of usable output to total input can be used to objectively measure efficiency. The efficiency of the device is defined as the ratio of energy converted to a useable form to the original amount of energy supplied.

Given parameters:

Efficiency of the power plant; η = 31 %

Output  electric power; O = 270 MW.

We know that, Efficiency of the power plant;

η  = (Output  electric power/ input power)× 100%

⇒ input power = (Output  electric power × 100)/η

⇒ input power = (270 × 100)/31 MW

= 870.96 MW.

So, the rate of heat energy exhausted to the river that cools the plant =  Input power- output power

= (870.96 - 270) MW

= 600.96 MW.

Hence, heat energy exhausted to the river that cools the plant  is 600.96 MW.

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what is a blue moon​

Answers

.
a phenomenon whereby the moon appears bluish owing to smoke or dust particles in the atmosphere

Help me in PE plzzzzzz

Help me in PE plzzzzzz

Answers

Answer:

Balance. Eyes. Elbow. Follow-Through

Explanation:

Answer:

you have to take 4 to 5 steps to do the step

Explanation:

A student is on a balcony 15.6 m above the street. She throws a ball vertically downward at 10.7 m/s.
What is the velocity of the ball as it strikes the ground?

Answers

Answer:

20.65 m/s

Explanation:

You are gonna wanna use a calculator for this one

so we will write all the known variables:

h = 15.6 m

initial velocity (u) = 10.7 m/s

acceleration (a) = 10 m/s/s (gravity)

From the third equation of motion:

v² - u² = 2ah

v² - (10.7)² = 2(10)(15.5)

v² - (10.7)² = 312

v² = 312 + 114.49

v² = 426.49

v = 20.65 m/s

một vật có khối lượng m=1kg trượt trên mặt phẳng nghiêng hợp mới mặt đất một góc a sao cho sina=0.1 .sau khi trượt hết mặt phẳng nghiêng vật tiếp tục chuyển động trên mặt phẳng ngang một đoạn l=10m rồi dừng lại . hệ số ma sát trong quá trình chuyển động k=0,05. tìm vận tốc của vật ở cuối mặt phẳng nghiêng lấy g=10m/s^2

Answers

Answer:

AnAnswer it

Explanation:

How much charge is on a segment ds ?
Express your answer in terms of some, all, or none of the variables Q, a, θ, dθ, and the constant π.

Answers

The charge on the segment ds is  \(dQ=\frac{Q}{\pi a}ds=\frac{Q}{\pi a}ad\theta= \frac{Q}{\pi} d\theta\)

As Q is uniformly distributed over semicircel so,charge density

\(\lambda=\frac{Q}{s}=\frac{Q}{\pi r}\)

so in ds region charge: \(dQ=\frac{Q}{\pi a}ds=\frac{Q}{\pi a}ad\theta= \frac{Q}{\pi} d\theta\)

In physics, a uniformly distributed charge refers to a charge distribution where the charge density is constant throughout the given volume or surface. In other words, the amount of charge per unit volume or unit area is the same everywhere within the region.

Uniformly distributed charge is an important concept in electrostatics, which is the study of the behavior of electric charges at rest. The electric field produced by a uniformly charged object has a particularly simple form, and this makes it easier to calculate the electric field at any point outside the charged object using Gauss's Law.

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the complete question is:

What is the charge on a segment ds?

Express your answer in terms of some, all, or none of the variables Q, a, θ, dθ, and the constant π.

How much charge is on a segment ds ?Express your answer in terms of some, all, or none of the variables

A 232g ball hangs on the end of a spring. When the spring is pulled down it oscillates with a period of .13s. When pull down too far to a point .56m below the equilibrium position, the ball flies off the spring when it reaches its equilibrium position, and flies into the air.

Find the spring constant
Find the height the ball reaches.

Answers

The spring constant is 542 N/m.

The height the ball reaches is 37.5 m.

Angular speed of the ball

The angular speed of the ball is calculated as follows;

ω = 2π/T

ω = (2π) / (0.13)

ω = 48.33 rad/s

Spring constant

The spring constant is calculated as follows;

ω = √(k/m)

ω² = k/m

ω²m = k

(48.33² x 0.232) = k

542 N/m

Linear speed of  ball

v = ωL

v = 48.33 x 0.56 m

v = 27.1 m/s

Height reached by the ball

h = v²/2g

h = (27.1²) / (2 x 9.8)

h = 37.5 m

Thus, the spring constant is 542 N/m.

The height the ball reaches is 37.5 m.

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