Two plasticine balls have a mass of 30 g and 15 g. The balls inelastic collided, moving towards each other at speeds of 2 m / s and 3 m / s, respectively. Determine the speed of the balls after the collision. How much has the kinetic energy of the system changed after their collision?

Answer:

Explanation:

During an earthquake, there are both transverse and longitudinal wave. The answer is c.

Answer:

Explanation:

ans is c. Both transverse and longitudinal

The thermosphere experiences a temperature increase primarily due to the absorption of gamma rays.

The thermosphere is a layer of Earth's atmosphere that is directly above the mesosphere and below the exosphere.

The thermosphere is characterized by high temperature and large variability, in response to changes in solar ultraviolet radiation and solar activity.

Thus, the thermosphere experiences a temperature increase primarily due to the absorption of gamma rays.

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The steel ball in Challenge example 11.11 did not reach the full 45 degrees because of the air resistance.

When an object moves through the air, it has to overcome the force of air resistance, which opposes the motion of the object. This force is proportional to the surface area of the object and the speed at which it moves through the air. Therefore, the faster an object moves through the air, the more air resistance it experiences.

In the case of Challenge example 11.11, the steel ball was released at an angle of 45 degrees, but as it moved through the air, it experienced air resistance, which slowed it down. As a result, it did not reach the full 45 degrees and only reached an angle of 19 degrees. This is because the force of air resistance acting on the ball increased as it moved through the air, and this force eventually became greater than the force of gravity acting on the ball.

As a result, the ball slowed down and did not reach the full 45 degrees.

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Answer:

first one down second one up

Explanation:

Answer:

The answer is a controlled variable stays the same throughout an experiment, but a responding variable changes

Explanation:

just did it on apex

Answer:

1 law      the incident ray, the refracted ray and the normal at the point of incidence, all lie in the same plane

2 law     when light ray passes from denser medium to rarer medium it bends away from the normal

Explanation:

When a battery is used to charge a capacitor, does the battery's total charge get smaller.

A device without an element is referred to as a capacitor. The capacitance of a capacitor is defined as the ratio of the charge stored in either of its conductors to the potential difference between them. It is assumed that an earthed conductor's capacitance will visibly rise when it is moved close to another conductor in order for a capacitor to work. As a result, a capacitor has two plates with equal and opposing charges that are spaced apart from one another.

When a battery is used to charge a capacitor, electrons that will eventually gather on one plate and become negatively charged are given energy. The opposite plate then acquires a positive charge.

Additionally, this electron is not coming from a battery. When a battery is discharged, its energy has been consumed.

Therefore, while charging a capacitor, the battery's overall charge remains constant.

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The true power of the circuit is 840 watts.

The true power, also known as real power, is the actual power consumed or transferred by the circuit. It is calculated by multiplying the voltage (V) by the current (I) and the power factor (PF). In this case, the voltage is 240 volts and the current is 5 amperes.

The power factor is given as 70%, which can be expressed as 0.7. Therefore, the true power is calculated as follows:

True Power = Voltage (V) x Current (I) x Power Factor (PF)

True Power = 240 V x 5 A x 0.7

True Power = 840 watts

Therefore, the true power of the circuit is 840 watts.

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Answer:

the reaction is a physical reaction and it is exothermic as it releases heat to the sorrounding

Explanation:

because the mass of paper burnt is equal to the mass of products which are ashes

Answer:

180 [J].

Explanation:

1) the required work [W] can be calculated as difference of the energy: W=E₂-E₁, where E₁=mgh₁ - the energy before lifting, E₂=mgh₂ - the energy after lifting;

2) W=mgh₂-mgh₁, where m - mass; g=10 [N/kg], h - height;

3) then the required work [W]:

W=mg*(h₂-h₁)=30*6=180 [J].

Answer:

increase

Explanation:

guesshejwoowsnnsnakalalapqjhdjd

Answer:

our weight would decrease.

Explanation:

because of you burning all those calories and fat from hiking up the mountain.

ANSWER

False.

EXPLANATION

In radioactive decay (or nuclei decay), an unstable nucleus emits radiation into a nucleus that is table and has less energy and a lower mass.

Therefore, nuclei decay from a less stable form to a more stable form.

The answer is false.

Answer:

Jorge wanted to know where the apples were

Explanation:

Ya see, I don't want to explain, cuz I guessed. Also I'm on episode 499 of naruto so yeah

Answer:

B:Jorge wanted to know where the apples were.

Explanation:

(1) The magnitude and direction of the average acceleration of the baseball while it is in contact with the bat is 8,000 m/s² east.

(2) The magnitude of the average force the Bat exerts on the ball while they are in contact is 1,120 N.

The given parameters:

The magnitude and direction of the average acceleration of the baseball while it is in contact with the bat is calculated as follows:

\(a = \frac{v- u}{t} \\\\a = \frac{35 - (-45)}{0.01} \\\\a = \frac{80}{0.01} \\\\a = 8,000 \ m/s^2\)

The magnitude of the average force the Bat exerts on the ball while they are in contact is calculated as follows;

\(F = ma\\\\F = 0.14 \times 8,000\\\\F = 1,120 \ N\)

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The magnetic field tilts of Earth and Uranus are considered to be the most unusual when compared to other celestial bodies in our solar system. Earth's magnetic field tilts at an angle of approximately 11 degrees with respect to its rotational axis, which is quite significant. The magnetic field is generated by the motion of molten iron in the Earth's outer core, which creates a magnetic dipole that is tilted with respect to the planet's rotation axis.

Uranus, on the other hand, has an extremely tilted magnetic field that is almost perpendicular to its rotational axis. This is believed to be due to the planet's unique orientation, as Uranus rotates on its side compared to the other planets in our solar system. The magnetic field is thought to be generated by a layer of electrically conductive fluids deep within the planet's interior, which may be influenced by the unusual orientation of Uranus.

Overall, the magnetic field tilts of Earth and Uranus are intriguing and unique in their own ways, providing valuable insights into the magnetic processes that occur within these celestial bodies.

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The statement that is not correct is (c) the relative motion between an observer and a star does not change the observed frequency of light from the star.

This statement is incorrect because the relative motion between an observer and a star does affect the observed frequency of light from the star. This effect is known as the Doppler shift, which causes the observed frequency of light to shift towards the blue end of the spectrum when the star is moving towards the observer, and towards the red end of the spectrum when the star is moving away from the observer. This effect can be used to detect exoplanets using the Doppler-shift method. the relative motion between an observer and a star does not change the observed frequency of light from the star.
Both statement (a) and (b) are correct. The Doppler-shift effect can be used to detect exoplanets, by measuring the small changes in the star's radial velocity caused by the gravitational tug of the orbiting planet. Imaging can also provide direct evidence for the existence of exoplanets, by observing the faint light emitted by the planet itself or by the reflection of the star's light off the planet's atmosphere.
Statement (d) is also correct. Imaging exoplanets is better in infrared wavelengths than in visible wavelengths because most exoplanets emit more radiation at longer wavelengths due to their lower temperatures. Also, infrared light is less affected by scattering and absorption in the Earth's atmosphere, which makes it easier to detect faint signals from distant exoplanets.

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Spontaneous fission is a nuclear equation represents a spontaneous decay.

Spontaneous fission is another type of radioactive decay. In this process, the nucleus will split into two parts and free neutrons with the release of large amount of energy.

So we can conclude that spontaneous fission is a nuclear equation represents a spontaneous decay.

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The angular speed of the merry-go-round just after the ball is caught is 0.156 rad/s.

To solve this problem, we need to use the conservation of angular momentum, which states that the initial angular momentum of a system is equal to the final angular momentum of the system.

At the start, the merry-go-round and the child are both stationary, so their initial angular momentum is zero. The ball has an initial angular momentum given by:

L_i = r * p * sin(theta)

where r is the radius of the merry-go-round (2.2 m), p is the momentum of the ball (m * v), and theta is the angle between the tangent to the merry-go-round and the direction of the ball's velocity (37 degrees). Substituting in the values, we get:

L_i = 2.2 * 1.8 * 14 * sin(37) = 23.45 kg*m^2/s

Just after the ball is caught, the system consists of the merry-go-round, the child, and the ball, all rotating together. The final angular momentum of the system is given by:

L_f = I * w

where I is the rotational inertia of the merry-go-round (150 kg*m^2), and w is the angular speed of the merry-go-round after the ball is caught (what we're trying to find).

Since angular momentum is conserved, we can set L_i = L_f and solve for w:

L_i = L_f

23.45 = 150 * w

w = 0.156 rad/s

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Answer:

In most plants, the leaves are the main food factories. They capture the sun's energy with the help of chlorophyll in the leaf cells. The chlorophyll traps and packages the energy from the light of the sun in a process called photosynthesis. Leaves usually have a large surface so they can collect the most sunlight.

Explanation:

Hope this helps...maybe

Answer:

C

Explanation:

Answer:

Explanation:

The speed of the car can be found by using the formula

\(s = \frac{d}{t} \\ \)

d is the distance

t is the time

From the question we have

\(s = \frac{125}{2} = 62.5 \\ \)

We have the final answer as

Hope this helps you

When an electron in a hydrogen atom jumps from n = 3 to n = 2, the frequency of the emitted electromagnetic radiation is approximately 19.65 x 10^7 H

To calculate the frequency of electromagnetic radiation emitted when an electron in a hydrogen atom jumps from energy level n = 3 to n = 2, you can use the Rydberg formula:

1/λ = R_H × (1/n_final^2 - 1/n_initial^2)

where λ is the wavelength of the radiation, R_H is the Rydberg constant for hydrogen (approximately 1.097 x 10^7 m^-1), and n_final and n_initial are the final and initial energy levels, respectively.

To find the frequency (f) of the radiation, you can use the equation:

f = c / λ

where c is the speed of light in a vacuum (approximately 3.00 x 10^8 m/s).

Given:

n_final = 2

n_initial = 3

Let's calculate the frequency:

Using the Rydberg formula:

1/λ = R_H × (1/n_final^2 - 1/n_initial^2)

1/λ = 1.097 x 10^7 m^-1 × (1/2^2 - 1/3^2)

1/λ = 1.097 x 10^7 m^-1 ×(1/4 - 1/9)

Calculating the result:

1/λ = 1.097 x 10^7 m^-1 × (9/36 - 4/36)

1/λ = 1.097 x 10^7 m^-1 × (5/36)

1/λ = 0.1526 x 10^7 m^-1

Now, let's calculate the frequency using the equation f = c / λ:

f = c / λ

f = (3.00 x 10^8 m/s) / (0.1526 x 10^7 m^-1)

f = 19.65 x 10^7 Hz

Therefore, when an electron in a hydrogen atom jumps from n = 3 to n = 2, the frequency of the emitted electromagnetic radiation is approximately 19.65 x 10^7 Hz.

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EAC( Low-energy lightbulb )=18.47 EAC( Conventional lightbulb )=7.33 Conventional lightbulb is cheaper to operate. Option D

To calculate the Equivalent Annual Costs (EAC), we need to consider the initial cost, maintenance costs, and the present value of future costs, taking into account the discount rate.

The EAC (Equivalent Annual Cost) is calculated by summing up the annual costs of the lightbulb over its lifetime, discounted at the real discount rate of 4%.

For the low-energy lightbulb:

EAC = Cost of bulb + Present value of annual electricity cost

= $3.60 + ($2.00 / (1 + 0.04)^1) + ($2.00 / (1 + 0.04)^2) + ... + ($2.00 / (1 + 0.04)^9)

≈ $18.47

For the conventional lightbulb:

EAC = Cost of bulb + Present value of annual electricity cost

= $0.60 + ($7.00 / (1 + 0.04)^1) + ($7.00 / (1 + 0.04)^2) + ... + ($7.00 / (1 + 0.04)^1)

≈ $7.33

Since the EAC for the low-energy lightbulb is $18.47 per year and the EAC for the conventional lightbulb is $7.33 per year, the conventional lightbulb is cheaper to operate assuming a burnt-out bulb is replaced by an identical bulb.

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The percentage of the total initial kinetic energy that is lost during the impact is 11/17J. Because two bits of clay are travelling straight toward one another at a speed.

They stick together and move as a unit when they crash into each other. A moving object or particle's kinetic energy, which depends on both mass and speed, is one of its characteristics. The type of motion can be vibration, translation, rotation around an axis, or any combination of these. Kinetic energy is a type of energy that an item or particle possesses as a result of motion.

Piece weight is 300 g.

1 m/s for each piece's speed

The other portion weighs 600 g.

0.75 m/s is the speed of the other piece.

making use of the kinetic energy formula

K.E = 1/(m1+m2)v2 K.E = 1/(300*10-3+600*10-3)*(-0.5)2\s

K.E = 0.1125J

Energy wasted equals 11/17J - 0.1125/0.31875 energy lost

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The complete question is -

Two pieces of clay are moving directly toward each other. When they collide, they stick together and move as one piece. One piece having mass 300 g is moving to the right at a speed of 1 m/s. The other piece has mass 600 g and is moving to the left at a speed of 0.75 m/s. What fraction of the total initial kinetic energy is lost during the collision?

Answer:

2.05 Ω

Explanation:

We are here given that the

We need to find out the resistance of the given wire . As we know that,

\(\implies R = \rho \dfrac{l}{A} \\\)

\(\implies R =\rho \dfrac{ l}{\pi r^2} \\\)

\(\implies R =\rho \dfrac{l}{\pi \dfrac{d^2}{4}} \\\)

\(\implies R =\rho \dfrac{4l}{\pi d^2}\\\)

substitute the respective values,

\(\implies R = 1.720 \times 10^{-8}\times \dfrac{4\times 5000m}{3.14\times (0.74\times 10^{-2}} \\\)

\(\implies\underline{\underline{ R = 2.05 \Omega }} \\\)

and we are done!

Answer:

Período del tambor: \(T = 0.25\,s\), fuerza sobre la prenda: \(F \approx 80.852\,N\), velocidad lineal del tambor: \(v \approx 10.053\,\frac{m}{s}\), velocidad angular del tambor: \(\omega \approx 25.133\,\frac{rad}{s}\).

Explanation:

La expresión tiene un error por omisión, su forma correcta queda descrita a continuación:

"Una prenda de 320 gramos de ropa gira en el interior de una lavadora si dicha lavadora tiene un radio de 40 centímetros y gira con una frecuencia de 4 hertz. Halle a) el período, b) la velocidad angular, c) la fuerza con la que gira la prenda y d) la velocidad lineal de la lavadora."

El tambor gira a velocidad angular constante (\(\omega\)), en radianes por segundo, lo cual significa que la prenda experimenta una aceleración centrífuga (\(a\)), en metros por segundo al cuadrado. En primer lugar, calculamos el período de rotación del tambor (\(T\)), en segundos:

\(T = \frac{1}{f}\) (1)

Donde \(f\) es la frecuencia, en hertz.

(\(f = 4\,hz\))

\(T = \frac{1}{4\,hz}\)

\(T = 0.25\,s\)

Ahora determinamos la fuerza aplicada sobre la prenda (\(F\)), en newtons:

\(F = m\cdot a\) (2)

\(F = \frac{4\pi^{2}\cdot m \cdot r}{T^{2}}\) (2b)

Donde:

\(m\) - Masa de la prenda, en kilogramos.

\(r\) - Radio interior del tambor, en metros.

(\(m = 0.32\,kg\), \(r = 0.4\,m\), \(T = 0.25\,s\))

\(F = \frac{4\pi^{2}\cdot (0.32\,kg)\cdot (0.4\,m)}{(0.25\,s)^{2}}\)

\(F \approx 80.852\,N\)

La velocidad lineal de la lavadora es:

\(v = \frac{2\pi\cdot r}{T}\) (3)

(\(r = 0.4\,m\), \(T = 0.25\,s\))

\(v = \frac{2\pi\cdot (0.4\,m)}{0.25\,s}\)

\(v \approx 10.053\,\frac{m}{s}\)

Y la velocidad angular del tambor de la lavadora:

\(\omega = \frac{2\pi}{T}\)

(\(T = 0.25\,s\))

\(\omega = \frac{2\pi}{0.25\,s}\)

\(\omega \approx 25.133\,\frac{rad}{s}\)

Answer:

There would be complete destructive interference.

Explanation:

This is because since the waves are completely out of phase, the phase difference is half wavelength, that is the phase angle is 180°. The vibrating sources are 180° out of phase with each other.

Since this is the case, the crest of the one source meets the trough of the other, this causes the resultant vibrational wave to cancel out, thus producing a destructive interference pattern.

Since the vibrating sources are completely out of phase, every point they meet is completely out of phase, so the resultant interference pattern would produce a complete destructive interference pattern of no wave.

A multidimensional database (MDDB) is a type of database in which data can be viewed from multiple dimensions; commonly used with MOLAP.

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The multidimensional databases employ MOLAP (multidimensional on line analytical processing) to get entry to its records. They allow the customers to speedy get solutions to their requests through producing and studying the information as a substitute speedy. The information in multidimensional databases is saved in a statistics dice layout.

In a dimensional database, you've got rows and columns, represented by way of X and Y. In a multidimensional database, you've got were given X, Y, Z, etc. depending on the number of dimensions to your statistics. below is an example of a 3-Dimensional information Array represented in a relational desk and in three-D.

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The final speed of both players is 4.314 m/s

Both players will stick together and moves in the northwest direction due to the impact,

The mass of the first soccer player = 58 kg

The velocity of the first soccer player = 3.75 m/s

The mass of the second player = 56 kg

The velocity of the second player = 4.9 m/s

The final speed of both players can be found using the formula,

           m₁u₁ + m₂u₂ = (m₁ + m₂)v

where m₁,m₂ is the mass of the first and second player

           u₁,u₂ is the initial velocity of the first and second player

           v is the final velocity of both players

Let us substitute the known values in the above equation, we get

           58 x 3.75 + 56 x 4.9 = ( 58 + 56) v

                     217.5 +  274.4 = 114 v

                                  491.9 = 114 v

                          491.9 / 114 = v

                                         v = 4.314 m/s

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The light is at its lowest possible intensity.

The final intensity of the emerging light is (lo/2) × 0.75 = 0.375 × lo.

3. When the first polarizer is rotated clockwise to 90°, it becomes perpendicular to the incident unpolarized light. Therefore, no light can pass through the first polarizer. The intensity of the light is reduced to zero.

4. When the first polarizer is rotated clockwise to 45°, the intensity of the light passing through is reduced by cos²(45°) = 0.5.

This means the intensity becomes half of its original value (lo/2).

When the second polarizer is rotated anticlockwise to 30°, the intensity of the light passing through is further reduced by cos²(30°) = 0.75.

Therefore, the final intensity of the emerging light is (lo/2) × 0.75 = 0.375 × lo.

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