two uses of nitrogen gas​

The volume of 12 gas forms when 21 L Cl2 react at STP is 21 L.

To determine the volume of 12 gas (I assume you mean I2 gas) formed when 21 L of Cl2 reacts at STP (standard temperature and pressure), we need to use the ideal gas law equation.

The ideal gas law equation is given by:

PV = nRT

Where:

P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

At STP, the pressure is 1 atm, and the temperature is 273.15 K.

From the balanced equation, we can see that the molar ratio between Cl2 and I2 is 1:1. So, if 21 L of Cl2 reacts, it will produce an equal volume of I2 gas.

Given that the volume of Cl2 is 21 L, we can assume the volume of I2 gas formed will also be 21 L.

Therefore, the volume of I2 gas formed is 21 L.

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Answer:

Lightweight and wrinkle-free, sharkskin is ideal for curtains, tablecloths and napkins. Sharkskin fabric is popular for both men's and women's worsted suits, light winter jackets and coats. Sharkskin is commonly used as a liner in diving suits and wetsuits.

Answer:Electrical Conductivity,soluble

Explanation:

Salt is a non-magnetic solid and is soluble in water. Sand is a non-magnetic solid and is insoluble in water.

Electrical Conductivity: Salt is an electrolyte and conducts electricity when dissolved in water or in a molten state. This is because salt dissociates into ions (Na+ and Cl-) that can carry electric current. In contrast, sand is a covalent compound and does not conduct electricity, as it does not dissociate into ions in the same way as salt. Sand is considered an insulator in terms of electrical conductivity.

When hydrogen bromide (HBr) is added to 2-methylbut-2-ene ((CH3)2CCHCH3), an electrophilic addition reaction takes place, where the π bond of the alkene is broken, and the hydrogen and bromine atoms are added to the resulting carbocation.

The reaction proceeds through a Markovnikov addition, where the hydrogen atom attaches to the carbon atom with the greater number of hydrogen atoms.

In this case, the initial addition of HBr to 2-methylbut-2-ene leads to the formation of a primary carbocation, as the positively charged carbon atom only has one alkyl group attached to it. The primary carbocation is relatively unstable, and it can undergo a rearrangement to form a more stable secondary carbocation.

The major product that is typically obtained is the 2-bromo-2-methylbutane. The hydrogen atom from HBr adds to the carbon with three hydrogen atoms (the more substituted carbon), resulting in the formation of a secondary carbocation.

On the other hand, a minor product is also formed, which is 3-bromo-2-methylbutane. This product arises from the addition of HBr to the primary carbocation, which is less stable. Although the primary carbocation is less favored, it can still be formed and lead to the formation of the minor product.

In summary, the addition of HBr to 2-methylbut-2-ene yields two products: the major product is 2-bromo-2-methylbutane, resulting from the addition of HBr to the more stable secondary carbocation, and the minor product is 3-bromo-2-methylbutane, originating from the less stable primary carbocation.

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Answer:

3Fe + 4H₂O --> Fe3O4 + 4H2

Answer:

2.282 atm

P1V1/T1 = P2V2/T2

2.70atm / (50+273) = X/ 273

make x subject of formula

:. X = 2.28 atm

or 2.28 * 1.01 *10⁵ N/m²

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The number of moles of the excess reagent there would be is 3.9 moles

From the question,

We are to determine the number of moles of the excess reagent there would be.

The given balanced chemical equation is

N₂ + 4H₂O → 2H₂O₂ + N₂H₄

This means,

1 mole of N₂ is required to react completely with 4 moles of H₂O

Now,

If 1 mole of N₂ is required to react completely with 4 moles of H₂O

Then,

2.8 moles of N₂ will react completely with 11.2 moles of H₂O

∴ H₂O is the excess reagent

Number of moles of H₂O that would remain = 15.1 mol - 11.2 mol

Number of moles of H₂O that would remain = 3.9 mol

Hence, the number of moles of the excess reagent there would be is 3.9 moles

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Answer:

Magnesium

Explanation:

The answer is Magnesium

Answer:

9x4500=40,500. which is a little more then what you need but it will still be a little more but it will take around 40500 days to run around the world.

According to the question the reaction enthalpy is thus 10610 J / 0.278 moles = 38.3 kJ/mol.

Enthalpy is a thermodynamic property of a system that measures the total energy content of a system. It is a state function that is expressed in terms of internal energy, pressure, and volume of a system. Enthalpy represents the amount of energy that is associated with a chemical reaction or physical change.

The reaction is exothermic, meaning that heat is released during the reaction. The amount of heat released can be calculated with the equation q = mcΔT, where q is the heat released, m is the mass of the solution, c is the specific heat capacity of the solution, and ΔT is the change in temperature of the solution. Using the given data, the amount of heat released by the reaction can be calculated as q = (250 g)(4.184 J/g-K)(11.1 K) = 10610 J. The enthalpy change for the reaction can then be calculated by dividing the heat released by the number of moles of NaOH, which is 11.1 g / 40.00 g/mol = 0.278 moles. The reaction enthalpy is thus 10610 J / 0.278 moles = 38.3 kJ/mol.

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a)There are 0.45 moles of HNO₃ in the bottle.

b)Approximately 13 ml of the solution are required for the reaction.

a. To find the number of moles of HNO₃  in the bottle, we can use the formula:

moles = concentration (M) x volume (L)

Given that the concentration of the nitric acid solution is 6.0 M and the volume is 75.0 ml, we need to convert the volume to liters:

75.0 ml = 75.0 ml x (1 L/1000 ml) = 0.075 L

Now, we can calculate the number of moles:

moles = 6.0 M x 0.075 L = 0.45 moles

So, there are 0.45 moles of HNO₃  in the bottle.

b. To determine the volume of solution required for 5.00 g of HNO3, we need to use the molar mass of HNO3 to convert grams to moles:

moles = mass (g) / molar mass (g/mol)

Given that the molar mass of HNO₃  is 63.01 g/mol and the mass required is 5.00 g, we can calculate the number of moles:

moles = 5.00 g / 63.01 g/mol ≈ 0.079 moles

Now, we can use the concentration to find the volume:

volume (L) = moles / concentration (M)

volume (L) = 0.079 moles / 6.0 M ≈ 0.013 L

Finally, we need to convert the volume to milliliters:

volume (ml) = 0.013 L x (1000 ml/1 L) ≈ 13 ml

So, approximately 13 ml of the solution are required for the reaction.

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Answer:

1. Some combination of ions form a solid precipitate because it is not favorable for the ions to become solvated (dissolved). Large and lowly charged ions tend to form precipitates, especially metals such as lead, barium, and silver.

2.
a. Pb(NO3)2 + 2KI -> 2KNO3 + PbI2

b. PbI2 is a precipitate because no other combinations of cations and anions will make an insoluble compound. KI, KNO3, and Pb(NO3)2 are all soluble.

c.

\(Pb^{2+}(aq) + 2NO_3^{-}(aq) + 2K^+(aq) + 2I^-{aq} = > PbI_2(s) + 2NO_3^{-}(aq) + 2K^+{(aq)}\\\\\)

is the ionic equation. Spectator ions are NO3- and K+

d.

\(Pb^{2+}(aq)+ 2I^-{aq} = > PbI_2(s) \\\)  is the net ionic equation

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When the combined vapour pressure of a miscible liquid mixture reaches atmospheric pressure, the solution boils. This vapour pressure denotes the boiling pressure in a mixture.

The air pressure directly impacts a liquid's boiling point. The weight of the air molecules above the liquid is the factor putting more pressure on the liquid. This is considered to as atmospheric pressure in an open system. The higher the boiling point and the more energy needed to bring liquids to a boil, the higher the pressure.

Because volatile compounds regularly have different boiling points, when a mixture is distilled, the components commonly separate from the mixture. The temperature at which the external pressure operating on the surface of a liquid equals the vapour pressure of the liquid phase of a compound is termed as the boiling point.

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Answer:

The reactant that determines how much product can be made

Explanation:

The limiting reactant in a chemical reaction is the one that is consumed first and restricts the amount of product that may be produced (or limiting reagent).

In the electrical arrangement, the 6p subshell of the radon element contains 6 electrons.

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Answer:

A molecule made of two or more elements chemically combined is a compound.

A molecule made of two atoms of the same element is just that an element.

A molecule made of two ( or more) elements is a compound.

Explanation:

The statement that describes what makes a base weak is that the base will be unable to dissociate completely in water.

A base is any of a class of generally water-soluble compounds, having bitter taste, that turn red litmus blue, and react with acids to form salts.

Bases usually dissociate into hydroxide ions (OH-) when in an aqueous solution.

However, a base is termed weak or strong depending on it's ability to dissociate completely. A weak base does not dissociate completely into hydroxide ions when in an aqueous solution.

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Answer:

B.

Explanation:

Answer:

B is the correct answer

Explanation:

The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.

To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.

(a) MgCl2:

The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).

Mg: atomic mass = 24.31 amu

Cl: atomic mass = 35.45 amu

Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu

(b) SCl:

The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).

S: atomic mass = 32.07 amu

Cl: atomic mass = 35.45 amu

Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu

(c) BCl:

The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).

B: atomic mass = 10.81 amu

Cl: atomic mass = 35.45 amu

Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu

(d) AlCl3:

The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).

Al: atomic mass = 26.98 amu

Cl: atomic mass = 35.45 amu

Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D

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The two chemical compounds are not the same, because their ratio is not equal. In both samples the composition of lead and oxygen is different.

A chemical compound is a substance made of numerous similar molecules (or molecular entities) joined by chemical bonds and comprising atoms from various chemical elements. Therefore, a molecule made up of only one type of atom is not a compound. Chemical reactions, which may entail interactions with other molecules, can change a compound into a distinct substance. Atomic bonds may be broken or new ones created during this process.

sample 1 = mass of lead / mass of oxygen = 12.92g/2g = 6.46 .

sample 2 = mass of lead/ mass of oxygen = 34.27 - 14.39/14.39 = 1.38 .

so, the ratios are not the same.

Hence, the two chemical compounds are not the same, because their ratio is not equal. In both samples the composition of lead and oxygen is different.

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B. 0.66 atm.After the reaction is finished, the system's pressure will be 0.66 atm

The pressure of the reaction is determined by the ideal gas law, which states that the pressure of a gas is equal to the number of moles of the gas multiplied by the gas constant and temperature. Since the temperature of the system is constant, the pressure will be determined by the number of moles of gas in the system.

Given that 2.0 L of gas A and 4.0 L of gas B are present at 1.0 atm, the total number of moles in the system will be:

\(n =\frac{ (2.0 L)(1.0 atm)}{(0.08206 L atm/mol K)(273K) }+\frac{ (4.0 L)(1.0 atm)}{(0.08206 L atm/mol K)(273K) }= 0.742 mol\)

Since the two gases are reacting to form gas C, the total number of moles of gas in the system after the reaction will be 0.742 mol. Since the volume of the system is 6.0 L, the pressure of the system after the reaction will be:

\(P =\frac{ (0.742 mol)(0.08206 L atm/mol K)(273K)}{(6.0 L)} = 0.66 atm\)

Therefore, the pressure of the system after the reaction is complete will be 0.66 atm.

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IUPAC (International Union of Pure and Applied Chemistry) naming is also known as systematic naming.

It is a set of rules and guidelines used to name chemical compounds systematically. It provides a standardized method for naming organic and inorganic compounds based on their molecular structure and composition.

The longest continuous carbon chain in the compound is identified as the parent chain.

The IUPAC name of the given compounds are:

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Answer:

There are

Explanation:

There are 10 elements in CH3CH2COONa.

Answer:

By adding heat energy It became a gas Explanation:The molecules moving about another is a clear indicator that the substance is a liquid. In a liquid, the molecules stick together and move about one another. When the scientist increase the speed of the of substance, the kinetic energy increases. if this increase causes a phase change, then the substance becomes a gas. So, by adding heat energy a substance becomes gaseous if it is a liquid already.

Explanation:

Answer:

They contain different five-carbon sugars and a different nitrogenous base.

Explanation

Given:

Mass of the solute = 60 g

Volume of the solution = 270 mL

Required: mass/volume %

Solution

To solve this problem: Percent (m/v) is the mass of solute divided by the volume of the solution, multiplied by 100 %.

Percent (m/v) = mass of solute volume of solution × 100 %

Percentage (m/v) = (60g/270 mL) x 100

Percentage (m/v) = 22.2%

Answer

% (m/v) = 22.2%

The energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

To calculate the energy of combustion for one mole of butane (C4H10), we need to use the information provided and apply the principle of calorimetry.

First, we need to convert the mass of the butane sample from grams to moles. The molar mass of butane (C4H10) can be calculated as follows:

C: 12.01 g/mol

H: 1.01 g/mol

Molar mass of C4H10 = (12.01 * 4) + (1.01 * 10) = 58.12 g/mol

Next, we calculate the moles of butane in the sample:

moles of butane = mass of butane sample / molar mass of butane

moles of butane = 0.367 g / 58.12 g/mol ≈ 0.00631 mol

Now, we can calculate the heat released by the combustion of the butane sample using the equation:

q = C * ΔT

where q is the heat released, C is the heat capacity of the calorimeter, and ΔT is the change in temperature.

Given that the heat capacity of the bomb calorimeter is 2.36 kJ/°C and the change in temperature is 7.73 °C, we can substitute these values into the equation:

q = (2.36 kJ/°C) * 7.73 °C = 18.2078 kJ

Since the heat released by the combustion of the butane sample is equal to the heat absorbed by the calorimeter, we can equate this value to the energy of combustion for one mole of butane.

Energy of combustion for one mole of butane = q / moles of butane

Energy of combustion for one mole of butane = 18.2078 kJ / 0.00631 mol ≈ 2888.81 kJ/mol

Therefore, the energy of combustion for one mole of butane is approximately 2888.81 kJ/mol.

In conclusion, by applying the principles of calorimetry and using the given data, we have calculated the energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

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Answer:

Substance C

Explanation:

Substance C would be the answer because Substance C has a lower attraction level. Because of this, it takes more energy to take out of in order to become a liquid.