urgent help please
Consider the following SQA model, where the defect removal activities and effectiveness rates are list in the following table:
No. Quality assurance activity Defect removal effectiveness rate
1-SRR Specification Requirement Review 70%
2-DIR Design Inspection and Review 50%
3-CIUT Code Inspection and Unit Test 50%
4-IST Integration and System Test 40%
5-OPD Operation Phase Detection 100%
The software development process consists of four activities: Requirement specification, Design, Implementation, and Deployment. The representative average relative defect-removal costs are illustrated in the following table:
No. Requirement Design Implementation Deployment
1-SRR 1 2-DIR 6 1 3-CIUT 12 5 1 4-IST 20 10 10 1
5-OPD 35 25 20 10
Assume that there are 20, 40, 30, and 20 defects originated in Requirement specification, Design, Implementation, and Deployment, respectively. Find the total costs according to above SQA model. Show your calculation process.

To find a subset of vectors that forms a basis for the subspace of R4 spanned by S, we need to determine which vectors in S are linearly independent.

Let's write the vectors in S as columns of a matrix:

S = [2, 3, 3, -8; V2, V3, -5, 25; -1, 26, 2, -8; -6, 0, 0, 0]

To find the linearly independent vectors, we can perform row reduction on the matrix to obtain its row-echelon form.

After performing row reduction, we get:

[1, 0, 0, -2; 0, 1, 0, 5; 0, 0, 1, 1; 0, 0, 0, 0]

The row-echelon form shows that the first three rows are linearly independent, while the last row is a zero row. Therefore, the corresponding vectors in S form a basis for the subspace of R4 spanned by S.

The subset that forms a basis for the subspace is: { [2, 3, 3, -8], [V2, V3, -5, 25], [-1, 26, 2, -8] }

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To answer this question, we'll use the exponential distribution and the concept of the probability density function (pdf). Let X be the time until failure of a single device, with a mean lifetime of 20 months. The exponential distribution has the following pdf:

f(x) = (1/μ) * e^(-x/μ),

where μ is the mean lifetime (20 months in this case).

Now, let's find the probability that the first failure occurs at w months among the 5 independent devices. For this, we need to calculate the probability that none of the other 4 devices fail before w months and that the first device fails at w months.

The probability that a single device does not fail before w months is given by the complementary cumulative distribution function (ccdf) of the exponential distribution:

P(X > w) = e^(-w/μ).

Since the devices are independent, the probability that all 4 devices do not fail before w months is:

P(All 4 devices survive > w) = (e^(-w/μ))^4.

Now, the probability that the first device fails at w months is given by the pdf of the exponential distribution:

P(X = w) = (1/μ) * e^(-w/μ).

Finally, we multiply the two probabilities to find the chance that the first failure occurs at w months:

P(First failure at w) = P(All 4 devices survive > w) * P(X = w)
= (e^(-w/μ))^4 * (1/μ) * e^(-w/μ)
= (1/20) * e^(-5w/20).

Thus, the chance that the first failure will occur at w months is given by the expression (1/20) * e^(-5w/20).

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Answer:

see explanation

Step-by-step explanation:

consecutive even numbers have a difference of 2

let the consecutive even numbers be n and n + 2, thus

(n + 2)² - n² ← expand (n + 2)² using FOIL

= n² + 4n + 4 - n² ← collect like terms

= 4n + 4

= 4(n + 1) ← which results in a multiple of 4

At the instant when the bottom of the ladder is 6 ft from the wall and sliding away at a rate of 1 ft/sec, the top of the ladder is sliding down the wall at a rate of -3/4 ft/sec.

Let's denote the distance between the top of the ladder and the ground as y and the distance between the bottom of the ladder and the wall as x. We are given that dx/dt = 1 ft/sec and want to find dy/dt when x = 6 ft.

According to the Pythagorean theorem, we have the equation

\(x^2\) + \(y^2\) = \(10^2\).

Differentiating both sides with respect to time (t), we get:

2x(dx/dt) + 2y(dy/dt) = 0.

Substituting the given values, we have:

2(6)(1) + 2y(dy/dt) = 0.

Simplifying the equation, we get:

12 + 2y(dy/dt) = 0.

Now, we can solve for dy/dt:

2y(dy/dt) = -12,

dy/dt = -6/y.

To find dy/dt when x = 6 ft, we substitute x = 6 into the equation:

dy/dt = -6/y = -6/8 = -3/4 ft/sec.

Therefore, the top of the ladder is sliding down the wall at a rate of -3/4 ft/sec when the bottom of the ladder is 6 ft from the wall.

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Answer:

Step-by-step explanation:

it will be 10

Answer:

slope trend: - 1/4

y intercept : 85

Hope it Helps!

Step-by-step explanation:

The pseudocode provided has a time complexity of \( \Theta(n^3) \).

The outermost loop iterates from \( i = 1 \) to \( n \), resulting in \( n \) iterations.

The second loop iterates from \( j = 1 \) to 1, which means it has a constant number of iterations, independent of \( n \).

Inside the second loop, there is a nested loop that iterates from \( k = 1 \) to \( i^2 \), resulting in \( i^2 \) iterations.

Within the innermost loop, there is a constant-time operation of \( x = x + 1 \).

Considering the total number of iterations, the outermost loop has \( n \) iterations, the second loop has a constant number of iterations, and the innermost loop has \( i^2 \) iterations.

Thus, the overall time complexity is \( \Theta(n^3) \) because the dominant factor in terms of growth is \( n \) raised to the power of 3 (from the nested loop).

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Answer:

-2c + 8d - 6

-6 + 5d - 2c + 3d

Step-by-step explanation:

When multiplying terms in a bracket, you need to multiply the term outside the bracket to all the terms in the bracket.

-\(\frac{2}{5}\)(15-20d+15c) = (-\(\frac{2}{5}\) × 15) + (-\(\frac{2}{5}\) × -20d) + (-\(\frac{2}{5}\) × 15c)

Two minuses make a plus. One minus and one plus make a minus.

(-\(\frac{2}{5}\) × 15) + (-\(\frac{2}{5}\) × -20d) + (-\(\frac{2}{5}\) × 15c) = (-6) + (8d) + (-2c)

Note that the terms can be presented in any order and still be correct.

(-6) + (8d) + (-2c) = -6 + 8d - 2c

Let us go through the options to see which ones are correct:

-2c + 8d - 6: Since all the terms are there, this option is correct!

-c + 40d - 8: Since none of the terms is there, this option is wrong.

-4c + 40d - 8: Since none of the terms is there, this option is wrong.

-3c + 8d - 3: Since (-3c) and (-3) are not the correct terms, this option is wrong.

-6 + 5d - 2c + 3d: If we evaluate the like terms (5d and 3d), the final answer would be -6 + 8d - 2c so this option is also correct!

(a)The volume generated by revolving the region bounded by the curve y = 1 + x² about the x-axis is \(3\pi /2\) cubic units.

(b)The distance of the centroid from the x-axis is 3 units

(a) To find the volume generated by revolving the region bounded by the curve y = 1 + x² about the x-axis, we use the method of cylindrical shells.

We consider a vertical strip of width dx at a distance x from the y-axis. The height of the strip is y = 1 + x², and its circumference is \(2\pi x\).

The volume of the shell generated by revolving the strip about the x-axis is given by:

\(dV = 2\pi x(1 + x^2) dx\)

To find the total volume, we integrate \(dV\) from x = 0 to x = 1:

\(V = \int\limits^1_0 {2\pi x(1 + x^2)} \, dx\\= 2\pi \int\limits^1_0 {(x + x^3)} \, dx \\= 2\pi [(x^2/2) + (x^4/4)] from\ 0\ to\ 1\\= 2\pi (1/2 + 1/4)\\= 3\pi /2\)

Therefore, the volume generated by revolving the region bounded by the curve y = 1 + x² about the x-axis is \(3\pi /2\) cubic units.

(b) To find the distance of the centroid from the x-axis for the area bounded by the curves y² = 4x, x = 0, and y = 4, we use the formula:

\(y-bar = (1/A) \int\limits^1_0 {y} \, dA\)

where A is the area of the region, y is the vertical coordinate of the centroid, and \(dA\) is the area element.

Since the region is symmetric about the y-axis, the x-coordinate of the centroid is zero.

To find the area A, we solve y² = 4x for x:

x = y²/4

The range of y is from y = 0 to y = 4. Therefore, the area of the region is:

\(A = \int\limits^4_0 {y^2/4} \, dy\)

= (1/4) [y³/3] from 0 to 4

= 64/3

To find the y-coordinate of the centroid, we use the formula:

\(y-bar = (1/A)\int\ {y} \, dA\)

\(y-bar = (1/(64/3)) \int\limits^4_0 { (y^2/4)}\, dy\\= (3/64) \int\limits^4_0 {y^3} \, dy\)

= (3/64) [y⁴/4] from 0 to 4

= 3

Therefore, the distance of the centroid from the x-axis is 3 units.

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Answer:

81.7

Step-by-step explanation:

I did the math.

Good luck (:

Answer:

Steven needs a total score of 320 to have a mean of 80 and Steven has obtained 245 so far. So, he needs atleast 75 more to qualify for the maths team.

There are six different positive integers divisible by 4 that can be formed using each of the digits 1, 2, 3, and 4 at most once and no other digits: 12, 24, 32, 42, 43, and 124.

1. 12: 1 and 2

2. 24: 2 and 4

3. 32: 3 and 2

4. 42: 4 and 2

5. 43: 4 and 3

6. 124: 1, 2 and 4

The six different positive integers divisible by 4 that can be formed using each of the digits 1, 2, 3, and 4 at most once and no other digits are 12, 24, 32, 42, 43, and 124. To find these numbers, we begin by examining all the possibilities that can be formed using the digits 1, 2, 3, and 4. We can form 12, 24, 32, 42, 43 and 124 by combining different combinations of the digits. For example, 12 is made up of the digits 1 and 2. 24 is made up of 2 and 4. 32 is made up of 3 and 2. 42 is made up of 4 and 2.

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Answer:

100m by 50m.

Step-by-step explanation:

Let the dimension of the rectangular pen be x and y

Area, A(x,y)=xy

Let the side opposite her barn = x

Since she wants to fence only three side

Perimeter = x+2y

Length of Fencing Available = 200m

Therefore: \(x+2y=200 \implies x=200-2y\)

We want to maximize the area of the pen, A(x,y).

Substituting x=200-2y into A(x,y)=xy

\(A(y)=y(200-2y)\\A(y)=200y-2y^2\)

To maximize A(y), we find its derivative and solve for the critical points.

\(A'(y)=200-4y\\$Setting $A'(y)=0\\200-4y=0\\200=4y\\y=50\)

To ensure that this is a maximum, we use the second derivative test.

\(A''(y)=-4\)

This is negative and thus, y=50 is a maximum point.

Recall:

x=200-2y

x=200-2(50)

x=200-100

x=100m

Therefore, the dimensions of the pen that has the largest area are 100m by 50m.

In a linear time-invariant system, the zero-state response (ZSR) is the output of the system when the input is zero, assuming all initial conditions (such as initial voltage or current) are also zero.

(a) For H1(s) = 1, the zero-state response Yzs(s) is simply the product of the transfer function H1(s) and the input Ei(s):

Yzs(s) = H1(s) * Ei(s) = (45+2)

To find the time-domain zero-state response yzs(t), we need to take the inverse Laplace transform of Yzs(s):

yzs(t) = L^-1{Yzs(s)} = L^-1{(45+2)} = 45δ(t) + 2δ(t)

where δ(t) is the Dirac delta function.

(b) For H2(s) = 45+1, the zero-state response Yzs(s) is again the product of the transfer function H2(s) and the input E2(s):

Yzs(s) = H2(s) * E2(s) = (45+1)E2(s)

To find the time-domain zero-state response yzs(t), we need to take the inverse Laplace transform of Yzs(s):

yzs(t) = L^-1{Yzs(s)} = L^-1{(45+1)E2(s)} = (45+1)e^(t/2)u(t)

where u(t) is the unit step function.

(c) For H3(s) = ns, the zero-state response Yzs(s) is given by:

Yzs(s) = H3(s) * E3(s) = ns * 542

To find the time-domain zero-state response yzs(t), we need to take the inverse Laplace transform of Yzs(s):

yzs(t) = L^-1{Yzs(s)} = L^-1{ns * 542} = 542L^-1{ns}

Using the inverse Laplace transform from problem 1, we have:

yzs(t) = 542 δ'(t) = -542 δ(t)

where δ'(t) is the derivative of the Dirac delta function.

(d) For H4(s) = 2e^(-4s) / (s+3)(4s+1), the zero-state response Yzs(s) is given by:

Yzs(s) = H4(s) * E4(s) = (2e^(-4s) / (s+3)(4s+1)) * (1/(s+3))

Simplifying the expression, we have:

Yzs(s) = (2e^(-4s) / (4s+1))

To find the time-domain zero-state response yzs(t), we need to take the inverse Laplace transform of Yzs(s):

yzs(t) = L^-1{Yzs(s)} = L^-1{(2e^(-4s) / (4s+1))}

Using partial fraction decomposition and the inverse Laplace transform from problem 1, we have:

yzs(t) = L^-1{(2e^(-4s) / (4s+1))} = 0.5e^(-t/4) - 0.5e^(-3t)

Therefore, the zero-state response for each of the four LTIC systems is:

(a) Yzs(s) = (45+2), yzs(t) = 45δ(t) + 2δ(t)

(b) Yzs(s) = (45+1)E2(s), yzs(t) = (45+1)e^(t/2)u(t)

(c) Yzs(s) = ns * 542, yzs(t) = -542 δ(t)

(d) Yzs(s) = (2e^(-4s) /

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Answer:

Integers

Multiplying & Dividing

RULE EXAMPLES

1. Multiply or divide.

2. The answer is positive if

the signs are the same

(both positive or both negative);

negative if the signs are different

(one positive and one negative).

–5 x ( –8) = 40

40  4 = 10

16 x ( –3) = –48

–20  10 = –2

Find each product or quotient.

1. –3 x (–8) 2. –5 x (–5) 3. –15 x 3

24 25 –45

Step-by-step explanation:

Answer:

10%×110

10/100×110

11

Answer:

Click at the above pic and the ans will appear.

Hope it helps :)

Answer:

1 meter :))) yeah points pls

Answer:

0.75 ounce

Step-by-step explanation:

64 candles= 16 ounce

3 candies= x ounce

(cross multiplication)

x= (3×16)÷64= 0.75 ounce

hope it helps

Answer:

Y- intercept is 0,3

Slope is 3/2

Step-by-step explanation:

Option B is correct, the solution of the inequality  d-9≥4 is d≥13

The given inequality is d-9≥4

We have to find the solution of the inequality

Add 9 on both sides of the inequality

d-9+9≥4+9

d≥13

In the graph we have to select in which the arrow is showing to right side as the value is increasing and the starting point is a solid dot as there is a greater than or equal to symbol

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Answer:

b

Step-by-step explanation:

Answer:

8x^2

Step-by-step explanation:

Volume = (base area x heigh)/3

base area = 160m x 160m

base area = 25600 m²

Volume = (25600 m² x 91 m) / 3

Volume = 776533.333 m³

the volume is 776533.333 m³

Answer: First, calculate for the rate at which you walk by dividing the distance by time in the first set of given. This gives us the rate of 4 miles/hour. To determine the time it takes to walk 3 miles, divide 3 by 4 which gives us 0.75 hours or 45 minutes.

Step-by-step explanation:

The dilation scaling factor that would map ΔABC to ΔADE is \(k = \dfrac{5}{3}\)

A dilation transformation is one in which the size of the object enlarged or reduced by a scale factor.

Possible parts of the question obtained from a similar question, found online are;

Triangle ΔABC is similar to triangle ΔADE

ΔABC ~ ΔADE

The triangle ΔABC is inscribed in the triangle ΔADE, such that the vertex B is located on the side AD and the vertex C is located on the side AE

The similar relationship between the two triangles indicates that the ratio of the corresponding sides on each triangles have the same values, therefore;

\(\dfrac{AD}{AE}\) = The ratio of the corresponding sides on the triangle ΔABC

\(\dfrac{AD}{AE} = \dfrac{12+8}{18+12} = \dfrac{2}{3} = \dfrac{12}{18} = \dfrac{AB}{AC}\)

Therefore, the corresponding side to AD is AB, and the corresponding side to AE is AC

The scale factor, k, that maps ΔABC to ΔADE, produce the length of AD from AB, or AE from AC as follows;

AD = k × AB

20 = k × 12

Therefore; \(k = \dfrac{20}{12} = \dfrac{5}{3}\)

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Answer:

1,136 calories.

Step-by-step explanation:

1. Considering that there are 16 ounces in one pound, and the question is asking for one pound, I would think that there would only need to be 16 ounces observed.

2. Through calculations of the given number of oz, there are 71 calories per oz. By multiplying that by 16 (the number of oz in a lb), there are a total of 1,136 calories in a lb.

Answer:

-2

Step-by-step explanation:

Answer:

-2

Step-by-step explanation:

I dont have an explanation, sorry

Answer:

  f(x) = (x -6)² +14

Step-by-step explanation:

Completing the square involves writing part of the function as a perfect square trinomial.

The square of a binomial results in a perfect square trinomial:

  (x -h)² = x² -2hx +h²

The constant term (h²) in this trinomial is the square of half the coefficient of the linear term: h² = ((-2h)/2)².

One way to "complete the square" is to add and subtract the constant necessary to make a perfect square trinomial from the variable terms.

Here, we recognize the coefficient of the linear term is -12, so the necessary constant is (-12/2)² = 36. Adding and subtracting this, we have ...

  f(x) = x² -12x +36 +50 -36

Rearranging into the desired form, this is ...

  f(x) = (x -6)² +14

__

Additional comment

Another way to achieve the same effect is to split the given constant into two parts, one of which is the constant necessary to complete the square.

  f(x) = x² -12x +(36 +14)

  f(x) = (x² -12x +36) +14

  f(x) = (x -6)² +14

Answer:

75

Step-by-step explanation:

Mean = sum of all numbers / how many of numbers

=> 50 + 60 + 70 + 80 + 90 + 100 / 6

=> 450 / 6

=> 75

So, the mean of this data is 75.

Answr :

I hope my answer is correct

m<Jmk = m<HML. m<HJL=m<KHJ

m<JKH=m<JHL m<LHK=m<JLH

m<HLK = m<HJK. m<JLK= m< HJL

The sign of the expression f³·(-g)³ is negative. Therefore, the option B is the correct answer.

Given that, f³·(-g)³.

Functions are the fundamental part of the calculus in mathematics. The functions are the special types of relations. A function in math is visualized as a rule, which gives a unique output for every input x.

Now, f³·(-g)³

The simplified form of the expression is

-f³g³

So, the sign of the expression is negative.

The sign of the expression f³·(-g)³ is negative. Therefore, the option B is the correct answer.

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