URGENT PLS HELP

An open system starts with 276 J of mechanical energy. The energy changes
to 267 J of mechanical energy and 8 J of thermal energy. What is the final
total energy of the system?

Answers

Answer 1

answer: 275 Joule ...


Related Questions

If everyone on the planet used the same amount of resources as an average American, what percent of the Earth would need to be used to support everyone?

Answers

Answer:

540% according to an article I read on BBC

Explanation:

Identify the correct description for each part labeled on the diagram
A
B
C
D
E
F

Answers

Answer:

No Specific question

Explanation:

Answer:

A: heating solid

B: melting

C: heating liquid

D: boiling

E: heating gas

F: melting point

Explanation: got it right

A donut has a density of 0.75 g/cm cubed and a mass of 100.0g. What is the volume of the donut?

Answers

Answer:

133.333333333 cm^3

Explanation:

Volume = Mass/Density

which of the following physical properties does not generally increase with increasing strength of intermolecular forces?

Answers

Among various physical properties, vapor pressure does not generally increase with increasing strength of intermolecular forces.

Intermolecular forces refer to the forces between molecules that hold them together. When the strength of intermolecular forces increases, physical properties such as boiling point, melting point, and viscosity typically increase. However, vapor pressure behaves differently.

Vapor pressure is the pressure exerted by a vapor in equilibrium with its liquid or solid phase at a given temperature. When intermolecular forces are stronger, it becomes harder for molecules to escape the liquid or solid phase and enter the gas phase. Therefore, fewer molecules transition to the gas phase, resulting in a lower vapor pressure.

In summary, vapor pressure does not increase with stronger intermolecular forces, but rather decreases.

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"The Periodic Table Turns 150: Is the Best Yet to Come?" ChemMatters, February/March 2019
Student Reading oilesu
Comprehension Questions
Name
Directions: Use the article to answer the questions below.
1. What was Dmitri Mendeleev's dream that reportedly was the start of his periodic table?
2. What is periodicity?
3. How did (a) Antoine Lavoisier, (b) Johann Döbereiner, and (c) John Newlands attempt to
organize the elements?

Answers

1) The dream of Mendeleev concerned the arrangement of the elements by mass

2) Periodicity is the changing properties of the elements

3)

Antoine Lavoisier - Arranged the elements by their properties

Johann Döbereiner - Arranged the elements into triads

John Newlands - Arranges the elements according to the order of increasing atomic mass

What is the periodic table?

We define the periodic table as the arrangement of the elements in order of increasing atomic numbers. We know can see that several attempts have been made at the systematization of the elements and the approaches to the problem have taken different dimensions. In a dream, Mendeleev saw the elements line up in order of atomic masses and there was a visible pattern.

The term periodicity has to do with the regular repeating property of the elements and this can be seen when we follow the properties of the elements as they change down the group and across the period.

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How many moles of ammonia will be formed from the complete reaction of 45.0 g of h2? n2 3 h2 ---> 2 nh3
a. 11.1 mol
b. 14.9 mol
c. 16.7 mol
d. 7.43 mol
e. 22.3 mol

Answers

The answer is 11.1 mol

The reaction is N2+3H2→2NH3

On reaction here, three moles of hydrogen form two moles of ammonia is formed.

45 g of H2 is equivalent to 45/2=22.5 moles

So the number of moles of ammonia formed is 22.5/2=11.1 mol

What is a mole?

Mole is used for measuring large quantities.It is calculated by given mass by molecular mass.The mole is widely used in chemistry as a convenient way to express amounts of reactants and products of chemical reactions. It is used to measure the amount of a substance and has the SI unit as mol.The elementary quantity is known as the Avogadro number.

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what are the 5 benefits of changing colour/paint of the
laboratories and auditoriums?

Answers

Answer:

AestheticsImproved Focus and ConcentrationStress ReductionPositive ImpressionIncreased Creativity

Explanation:

Sucrose: density = 1.59 g/cm³. Your experiment showed a density of 1.68 g/cm³. What is the percent error *

Answers

Answer:

The answer is

5.66 %

Explanation:

The percentage error of the density can be found by using the formula

\(Percentage \: \: error(\%) = \frac{error}{actual \: \: number} \times 100 \\ \)

From the question

actual density = 1.59 g/cm³

error = 1.68 - 1.59 = 0.09

The percentage error is

\(P(\%) = \frac{0.09}{1.59} \times 100\% \\ = 5.66037735...\)

We have the final answer as

5.66 %

Hope this helps you

Calculate the number of NaBr formula units formed when 50 NBr3 molecules and 57 NaOH formula units react? 2NBr3 + 3NaOH ---> N2 + 3NaBr + 3HOBr

Answers

When 50 NBr3 molecules and 57 NaOH formula units react according to the given balanced equation, the result is the formation of 150 NaBr formula units.

According to the balanced equation provided:

2 NBr3 + 3 NaOH -> N2 + 3 NaBr + 3 HOBr

From the equation, we can see that 2 moles of NBr3 react with 3 moles of NaOH to form 3 moles of NaBr.

To determine the number of NaBr formula units formed, we need to convert the given quantities into moles.

Given:

Number of NBr3 molecules = 50

Number of NaOH formula units = 57

To convert the number of NBr3 molecules to moles, we need to divide the given quantity by Avogadro's number. Similarly, for NaOH formula units, we can directly consider them as moles.

Using Avogadro's number (6.022 x 10^23 molecules/mol), we can calculate the number of moles for NBr3 and NaOH:

Number of moles of NBr3 = 50 / (6.022 x 10^23)

Number of moles of NaOH = 57

Now, we can use the mole ratios from the balanced equation to determine the number of moles of NaBr formed. From the equation, we know that 2 moles of NBr3 react to form 3 moles of NaBr.

Number of moles of NaBr = (Number of moles of NBr3) x (3 moles of NaBr / 2 moles of NBr3)

Finally, we can convert the number of moles of NaBr to the number of NaBr formula units using Avogadro's number:

Number of NaBr formula units = (Number of moles of NaBr) x Avogadro's number

Calculating these values, we find that 50 NBr3 molecules and 57 NaOH formula units react to form 150 NaBr formula units.

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Please help How many moles of a gas sample are in 5.0 L container at 215 K and 342 kPa(The gas constant is 8.31 L kPa/mol K) Round your answer to one decimal place and enter the number only with no units.

Please help How many moles of a gas sample are in 5.0 L container at 215 K and 342 kPa(The gas constant

Answers

Answer

1.0 mol

Explanation

Given:

Volume, V = 5.0 L

Temperature, T = 215 K

Pressure, P = 342 kPa

The gas constant, R = 8.31 L kPa/mol K

What to find:

The number of moles of the gas sample.

Step-step-solution:

The number of moles of the gas can be determine using the ideal gas equation formula:

\(PV=nRT\)

Put the given values into the formula and calculate for n:

\(\begin{gathered} 342\times5.0=n\times8.31\times215 \\ 1710=1786.65n \\ \text{Divide both sides by 1786.65} \\ \frac{1710}{1786.65}=\frac{1786.65n}{1786.65} \\ n=0.9571\text{ mol} \\ To\text{ one decimal place,} \\ n=1.0\text{ mol} \end{gathered}\)

The number of moles of the gas sample is 1.0 mol.

I need help please please please

I need help please please please

Answers

The toxic chemicals is different from the safe chemical because the stronger attraction between it's molecule than the safe chemical.it molecule now move away from each. The correct option is C

What is toxic chemical?

Toxic chemical can be defined as a substance that can be poisonous or cause health effects. Some examples of toxic chemical include ammonia, acid, bleach, chlorine, and carbon monoxide.

Therefore toxins are substances created by plants and animals that are poisonous to humans. Toxins may also include some medicines that are helpful in small doses but poisonous in large amounts.

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Balance the ionic equation
Cr

Answers

An ionic equation is balanced when the number of atoms of each element and the total charge is the same on both sides of the equation.

How do you balance ionic equation?

The question is incomplete but I will show you how to balance ionic equation.

Write the unbalanced ionic equation, including the charges of the ions.

Identify the species that are present on both sides of the equation and cancel out any ions that appear on both sides of the equation.

Balance the atoms of each element in the equation, using coefficients as needed to make sure that the same number of atoms appears on both sides of the equation.

Check that the overall charge is balanced by adding or removing electrons as needed. If electrons are added, they should be added to the side of the equation where the total charge is more positive, and if electrons are removed, they should be removed from the side of the equation where the total charge is more negative.

Check that the equation is fully balanced by making sure that the number of atoms of each element and the total charge is the same on both sides of the equation.

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A rock collection comes from which part of Earth?

A. atmosphere
B. biosphere
C. geosphere
D. hydrosphere

Answers

Answer:

c

Explanation:

I looked the answer up it said it was geosphere

Answer:

the answer is geosphere

Explanation:

i hope it helps you

Fluorine-18 undergoes positron emission as shown:
18 F + 4x +48
Enter the appropriate values for A and Z and the chemical
symbol for X
A:
Z:
83
1
X:

Answers

Answer:Answer:

40-18 fl =>40-cl+cl+0-1e sorry if im rong

Explanation:

When \(^1^8F\) undergoes positron emission, the product nucleus is, \(^1^8O\).

What is a positron emission?

In positron emission, also called positive beta decay (β+ decay), a proton in the parent nucleus decays into a neutron that remains in the daughter nucleus, and the nucleus emits a neutrino and a positron, which is a positive particle like an ordinary electron in mass but of opposite charge.

When a proton is converted into a neutron then the positron emission takes place as follows.

\(^1_1p\;\rightarrow\;^1_0n\;+\;^0_+1e\)

A positron is represented by the symbol. Therefore, when a positron emission occurs then the resultant nuclei atomic number decreases by a unit mass.

The general equation representing positron emission is as follows.

\(^M_ZA\;\rightarrow\;^M_Z_-_1 B\;+\;^0_+1e\)

Hence, fluorine-18 decays by positron emission as follows.

\(^1^8_9F\;\rightarrow\;^1^8_8n\;+\;^0_+1e\)

Therefore, when \(^1^8F\) undergoes positron emission, the product nucleus is, \(^1^8O\).

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What MASS of NaCl are required to make 2.69L of a 0.14M solution?Use the correct abbreviation for the UNITS

Answers

To solve this problem, let's use the definition for molarity:

Replacing the values of the problem:

Now, to find the mass, we multiply by the molecular weight of NaCl. (Which is about 58.44g/mol)

The answer is approximately 22.2g of NaCl

What MASS of NaCl are required to make 2.69L of a 0.14M solution?Use the correct abbreviation for the
What MASS of NaCl are required to make 2.69L of a 0.14M solution?Use the correct abbreviation for the
What MASS of NaCl are required to make 2.69L of a 0.14M solution?Use the correct abbreviation for the

Consider the reaction for the formation of aluminum oxide from aluminum and oxygen.
4Al(s)+3O2(g)⟶2Al2O3(s) ΔH1
1. Express the enthalpy of the following reaction, ΔH2, in terms of ΔH1.
2Al2O3(s)⟶4Al(s)+3O2(g) ΔH2
ΔH2=
2. Express the enthalpy of the following reaction, ΔH3, in terms of ΔH1.
12Al(s)+9O2(g)⟶6Al2O3(s)ΔH312Al(s)+9O2(g)⟶6Al2O3(s) ΔH3
ΔH3=
3. Express the enthalpy of the following reaction, ΔH4, in terms of ΔH1.
2Al(s)+32O2(g)⟶Al2O3(s)ΔH42Al(s)+32O2(g)⟶Al2O3(s)ΔH4
ΔH4=

Answers

1- ΔH2 = -ΔH1 (The enthalpy change for the reverse reaction is the negative of the enthalpy change for the forward reaction.)

2- ΔH3 = 3ΔH1 (The enthalpy change for the reaction involving the formation of 6 moles of Al2O3 is three times the enthalpy change for the formation of 2 moles of Al2O3.)

3- ΔH4 = 0.5ΔH1 (The enthalpy change for the reaction involving the formation of one mole of Al2O3 is half the enthalpy change for the formation of 2 moles of Al2O3.)

To express the enthalpy of a reaction in terms of another reaction, we can use the concept of Hess's law. Hess's law states that the overall enthalpy change of a reaction is independent of the pathway taken and depends only on the initial and final states of the reaction.

Expressing ΔH2 in terms of ΔH1:

The reaction (ΔH2) is the reverse of the formation of aluminium oxide from aluminium and oxygen (ΔH1), so the enthalpy change for the reverse reaction will have the opposite sign. Therefore, we have:

ΔH2 = -ΔH1

Expressing ΔH3 in terms of ΔH1:

The reaction (ΔH3) involves the formation of 6 moles of Al2O3, whereas the formation of Al2O3 in ΔH1 involves the formation of 2 moles of Al2O3. Therefore, the enthalpy change for ΔH3 will be three times that of ΔH1. Hence:

ΔH3 = 3ΔH1

Expressing ΔH4 in terms of ΔH1:

The reaction (ΔH4) involves the formation of one mole of Al2O3, whereas the formation of Al2O3 in ΔH1 involves the formation of 2 moles of Al2O3. Therefore, the enthalpy change for ΔH4 will be half that of ΔH1. Hence:

ΔH4 = 0.5ΔH1

In summary:

ΔH2 = -ΔH1

ΔH3 = 3ΔH1

ΔH4 = 0.5ΔH1

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surface tension occurs water molecules form a weak bond with each other allowing a small bug to walk across the surface of a puddle.these bonds are rferred to as

Answers

The bonds when surface tension occurs, water molecules form a weak bond with each other allowing a small bug to walk across the surface of a puddle. are referred to as hydrogen bonds.

Surface tension is the energy, often denoted as γ, necessary to increase the surface area of a liquid by a unit of area. Surface tension is a result of the cohesive forces that arise between the liquid's atoms and molecules. It's a property of liquids that makes them behave like an elastic sheet or membrane on their surface.

Hydrogen bonds are a type of chemical bond that occurs between a hydrogen atom bonded to an atom such as oxygen, nitrogen, or fluorine and another atom or electronegative group in a different molecule or chemical group.

The hydrogen bond is a type of dipole-dipole interaction that occurs when an electronegative atom or molecule attracts the positively charged hydrogen atom of another molecule or group. The hydrogen bond is a result of the difference in electronegativity between the hydrogen and the electronegative atom or group.

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Earth's polar regions have cold, dry climates because the sun's rays are at a ?

Answers

Answer:

not reaching to the poles

Explanation:

Answer:

the rays strike at a low level in the polar region

Explanation:

okay so since the polar zones lie between 66.50 north or south the polar regions are always so cold is because strike the low parts

hope this helped!

When compared to sulfuric acid, how strong are carboxylic acids? stronger just as strong weaker not acidic at all

Answers

We can see here that when compared to sulfuric acid, carboxylic acids are weaker acids.

What is sulfuric acid?

Sulfuric acid is a strong, highly corrosive acid with the chemical formula \(H_{2} SO_{4}\). It is one of the most important and widely used industrial chemicals. Sulfuric acid is known for its strong acidic properties and is often referred to as the "king of chemicals" due to its widespread applications in various industries.

Sulfuric acid is a dense, oily liquid that is colorless when pure. It is soluble in water, and when dissolved, it releases hydrogen ions (H+) to make the solution highly acidic.

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Discuss the similarities and differences in the behavior of the metals tested with water relative to their positions in the periodic table. Compare behavior within a family and in the same period. What would you predict to be the relative reactivities of cesium and lithium with water? Compare the reactivities of Groups IIA and IIIA with dilute acids.

Answers

Discuss the similarities and differences in the behavior of metals tested with water relative to their positions in the periodic table.

The periodic table is organized by increasing atomic number and is divided into groups (vertical columns) and periods (horizontal rows). Metals in the same group have similar properties, while metals in the same period show varying properties.

The reactivity of metals with water generally increases as you move down a group and across a period from left to right. This trend is due to the increasing size of the atoms and the ease with which they lose electrons, as well as the relative reactivities of the metals.

Within a family (group), the reactivity with water increases as you move down the group. For example, in Group IA (alkali metals), lithium reacts with water relatively slowly, while cesium reacts explosively. Similarly, in Group IIA (alkaline earth metals), magnesium reacts with water slowly, whereas barium reacts more vigorously.

When comparing the same period, metals on the left side of the periodic table are more reactive with water than those on the right. For instance, sodium (Group IA) reacts more vigorously with water than magnesium (Group IIA).

Based on these trends, cesium, being lower in Group IA than lithium, is predicted to be much more reactive with water, potentially resulting in an explosive reaction.

Comparing the reactivities of Groups IIA and IIIA with dilute acids, Group IIA metals are generally more reactive due to their higher tendency to lose electrons and form positive ions. As a result, Group IIA metals will typically react more vigorously with dilute acids than Group IIIA metals.

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A student collects petals from six plant species. Describe how he could find out which species' petals
make good indicators. In your answer ph indicators
, describe the stages of the process and explain how the student
would know which species' petals are suitable.

Answers

Answer:

thallophyta and bryophyte sometimes pteridophyta mark as brainliest please

Students in a high school Marine Science class are learning about the scientific process. Four students were asked to write a testable prediction about deep-sea vents found in the ocean. Their responses are shown in the chart. Student Response Jin Deep-sea vents are too deep. Elizabeth Deep-sea vents are more interesting than caves. Carly Interest in deep-sea vents will decrease in the future. Raymond Ocean surface temperatures are warmer than water at deep-sea vents. Which student's prediction is the most testable using the scientific process? Jin Elizabeth Carly

Answers

The predication that is testable here is that of Raymond. Option D

What is a testable predication?

We have to keep it at the back of our minds that science deals with data that is testable. In other words, science is an empirical discipline. What we mean by this is that we must be able to get at knowledge by testing the data that we have in controlled experiments.

Now, if we look at the responses of the students, we can see that the only one that has to do with something that we can test is the one that said that Ocean surface temperatures are warmer than water at deep-sea vents.

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Physical and chemical changes and properties are observed and tested in order to confirm the identity of a substance or how a substance may act in certain condition. The image below is a rock that, based on its bright yellow color, scientists believe to be sulfur. However, they would like to use a test to confirm this prediction.

Which procedure would you recommend the scientists use?

(A) Use volume displacement and the mass of the rock to calculate density.

(B) Measure volume in centimeters cubed and add to mass to determine density.

(C) Find the weight and volume of the rock then multiply to calculate density.

(D) Dissolve the rock in water, then find the mass and volume needed to calculate density.

Answers

Answer:

(A) Use volume displacement and the mass of the rock to calculate density.

Explanation:

Molarity of Kool Aid solutions can be calculated by comparing the concentrations of Kool Aid powder and sugar added to a given volume of water. The molar mass of Kool Aid will be the same as that of sugar for our purpose. The molecular formula for sugar is C12H22O11- Your objective for this lab will be to calculate the molarity of Kool Aid desired based on package directions. You will then be provided two concentrated Kool Aid solutions. You will use dilution calculations to determine the amount of water and concentrated solution you will need in order to prepare 65 mL of the desired molarity.

Calculate the molarity of Kool Aid desired based on the following information from the package directions.

1 package Kool Aid powder = 4. 25 grams 1 cup sugar = 192. 00 grams
2. 00 quarts of water (1. 06 quarts = 1 liter) ​

Answers

The amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.

To calculate the molarity of Kool Aid desired, we need to determine the number of moles of Kool Aid powder and sugar in the package. Since the molecular formula for sugar is C12H22O11, we can calculate its molar mass as follows:

Molar mass of C12H22O11 = (12 * 12.01) + (22 * 1.01) + (11 * 16.00)

= 144.12 + 22.22 + 176.00

= 342.34 g/mol

Given that the package contains 4.25 grams of Kool Aid powder, we can calculate the number of moles of Kool Aid powder using its molar mass:

Number of moles of Kool Aid powder = Mass / Molar mass

= 4.25 g / 342.34 g/mol

≈ 0.0124 mol

Similarly, for the sugar, which has a molar mass of 342.34 g/mol, we can calculate the number of moles of sugar using its mass:

Number of moles of sugar = Mass / Molar mass

= 192.00 g / 342.34 g/mol

≈ 0.5612 mol

Now, to calculate the molarity of the desired Kool Aid solution, we need to determine the volume of water. Given that 1.06 quarts is equal to 1 liter, and we have 2.00 quarts of water, we can convert it to liters as follows:

Volume of water = 2.00 quarts * (1.06 liters / 1 quart)

= 2.12 liters

To find the molarity, we use the formula:

Molarity (M) = Number of moles / Volume (in liters)

Molarity of Kool Aid desired = (0.0124 mol + 0.5612 mol) / 2.12 L

≈ 0.286 M

To prepare 65 mL of the desired molarity, we can use dilution calculations. We need to determine the volume of concentrated solution and the volume of water needed.

Let's assume the concentration of the concentrated Kool Aid solution is C M. Using the dilution formula:

(C1)(V1) = (C2)(V2)where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Given that C1 = C M and V1 = V mL, and we want to prepare a final volume of 65 mL (V2 = 65 mL) with a final concentration of 0.286 M (C2 = 0.286 M), we can rearrange the formula to solve for the volume of the concentrated solution:

(C M)(V mL) = (0.286 M)(65 mL)

V mL = (0.286 M)(65 mL) / C M

So, the amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.

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What is a saturated solution that cannot dissolve any more solute because it is too concentrated?

Answers

Answer: A saturated solution, by definition, contains an amount of solute equal to the amount of dissolved solute in equilibrium with an undissolved solute. We could, however, make a supersaturated solution in which the solvent contains more solute than would be in equilibrium with undissolved.

Explanation:   More solute cannot be dissolved at a given temperature in a saturated solution. This is because the solute dissolves in a solvent due to the space between the solvent particles, but with the continuous addition of solute, the space between the solvent particles is filled. As a result, no more solute particles can dissolve in the solvent.

Answer:

saturated

Explanation:

4. A 0.50 M solution of sodium thiosulfate, Na2S2O3 is used to create a more dilute solution. If 250 mL of the concentrated solution is diluted to a volume of 2.5 L, determine the concentration of the new solution.​

Answers

The concentration of the new solution if 0.50 M solution of sodium thiosulfate is used to create a more dilute solution is 0.05M.

How to calculate concentration?

Molarity refers to the concentration of a substance in solution, expressed as the number moles of solute per litre of solution.

The concentration of a solution can be calculated using the following formula:

CaVa = CbVb

Where;

Ca = initial concentrationCb = final concentrationVa = initial volumeVb = final volume

According to this question, if 250 mL of the concentrated solution is diluted to a volume of 2.5 L, the new concentration can be calculated as follows:

0.250 × 0.5 = 2.5 × Cb

0.125 = 2.5Cb

Cb = 0.05M

Therefore, 0.05M is the new concentration of the solution.

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For the reaction CH4 2O2 ---> CO2 2H2O, how many moles of carbon dioxide are produced from the combustion of 100. g of methane

Answers

Therefore, 5 moles of CO2 are produced from the combustion of 100 g of methane (CH4).Hence, the answer is 5.

For the reaction CH4 2O2 ---> CO2 2H2O, how many moles of carbon dioxide are produced from the combustion of 100. g of methane?

Explanation:

The balanced chemical reaction for the combustion of methane (CH4) in the presence of oxygen (O2) is given by the chemical equation,

CH4 + 2O2 → CO2 + 2H2O

This chemical equation means that for every one mole of methane gas that undergoes combustion, two moles of oxygen gas are required, and this will produce one mole of carbon dioxide gas and two moles of water vapor.

So from the equation, we can see that the stoichiometric coefficients of methane and carbon dioxide are equal, which means that one mole of methane will produce one mole of carbon dioxide.

Therefore, the molecular weight of CH4 is 16 g/mol + 1 g/mol x 4 = 16 + 4 = 20 g/mol.

Using the atomic weights, we can find out the molecular weight of CO2, which is 12 g/mol + 16 g/mol x 2 = 44 g/mol.

So, one mole of methane is 20 g and from the balanced chemical equation, it produces one mole of carbon dioxide.

To find out the number of moles of carbon dioxide produced from 100 g of methane, we will use the following formula:

Moles = mass / molar mass= 100 / 20= 5 moles

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PLEASE HELP, I REALLY NEED HELP WITH THIS!!!​

PLEASE HELP, I REALLY NEED HELP WITH THIS!!!

Answers

Answer:

Explanation:

There are 6 32S atoms and 2 36S atoms

Their respective contributions to the average aomic mass is (6*32)=192, and (2*36)=72.  Added together, this makes 264 total.  Divide by the total number of atoms, 8.  (264/8) = 33.00

The weighted atomic mass of these S atoms is 33.00 amu (atomic mass units)

How does anaerobic respiration occur in yeast ?

Answers

When there isn't enough oxygen for Oxidative Phosphorylation to occur, anaerobic respiration occurs. You can't produce ATP across the inner of the mitochondrial membrane or in the Krebs cycle if you don't have Oxidative Phosphorylation. As a result, the yeast employs anaerobic respiration to keep Glycolysis running, resulting in 4 ATP molecules (Net: 2) each Glucose molecule that is converted to Pyruvate.

Allowing NADH to lose hydrogen allows it to be converted to NAD, which can then be utilized to oxidize glucose to pyruvate, which produces ATP, and so on. This is best illustrated in a diagram, in my opinion.

A 50.0 mL unknown aqueous sample was tested in the laboratory. The unknown sample was identified
to be lead (II) ions by a precipitation reaction with sodium iodide. Since the unknown was identified to
have lead (II) ions in it, a student added excess sodium chloride (NaCl) to the 50.0 mL sample. A white
precipitate was made and was subsequently filtered, washed, and dried to completion. The precipitate
was measured to have a mass of 2.350 grams.

Answers

The student added sodium chloride in order to precipitate lead II chloride because this is a positive test for lead II ions.

What is a precipitate?

Some times when we carry out an aqueous phase reaction, the products of the reaction would be found to be in the solid phase. This implies that one of the products of the reaction is insoluble in water and separates out of the solution.

In this case, the student knows that lead II chloride is insoluble in water thus it is obtained upon the addition of sodium chloride. This informed the addition of the sodium chloride solution.

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Missing parts;

A 50.0 mL unknown aqueous sample was tested in the laboratory. The unknown sample was identified

to be lead (II) ions by a precipitation reaction with sodium iodide. Since the unknown was identified to

have lead (II) ions in it, a student added excess sodium chloride (NaCl) to the 50.0 mL sample. A white

precipitate was made and was subsequently filtered, washed, and dried to completion. The precipitate

was measure to have a mass of 2.350 grams.

(a) How did the students determine through the addition of sodium iodide that the sample had lead (II)

ions in it?

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