Use the follow step as a guide to solve the following equation.

3x - 4 = 2(5x + 5)

Answer: d. No, because the study was not taken from a random sample of scholarship athletes.

Step-by-step explanation:

Since the study only focuses on basketball players, the sample may not be representative of all scholarship athletes in the university. This can cause bias in the results and make it difficult to generalize the findings to the larger population of scholarship athletes. Therefore, the university administration should not fully trust the results of this study.

Answer:

C, F

Step-by-step explanation:

Answer:

256

Step-by-step explanation:

Rule:*4

1*4=4

4*4=16

16*4=64

64*4=256

I hope this helps!

Answer:

x-2

Step-by-step explanation:

(x+2)× ___=(x+2)(x-2)

___=(x+2)(x-2)/(x+2)

___=x-2

The polynomial which should be filled in the blank is (x - 2).

Polynomials are mathematical expressions which consist of one or more terms involving variables and coefficients connected with operations like multiplication, subtraction, addition and natural number powers of variables.

Given that,

x² - 4 = (x + 2) (x - 2).

We have to find the blank space.

By commutative property, the other side is also equal.

That is,

(x + 2) (x - 2) = x² - 4

Hence the correct option is (x - 2).

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To model the decrease in the value of the car over time, we can use an exponential function of the form:

V(t) = V(0) * e^(-rt)

where:

V(0) is the initial value of the car (in this case, $20,000).

r is the annual rate of depreciation, expressed as a decimal (in this case, 0.103).

t is the number of years since the car was purchased.

Plugging in the given values, we get:

V(t) = $20,000 * e^(-0.103t)

This is the exponential function that models the value of the car in t years.

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The probability of the event E or F, denoted as P(E or F), is 0.75.

To find the probability of the event E or F (denoted as P(E or F)), we need to consider the probabilities of E, F, and the intersection of E and F.

We are given:

P(E) = 0.40

P(F) = 0.55

P(E and F) = 0.10

The probability of the union of two events (E or F) can be calculated using the formula:

P(E or F) = P(E) + P(F) - P(E and F)

Substituting the given values into the formula, we have:

P(E or F) = 0.40 + 0.55 - 0.10

Simplifying the expression:

P(E or F) = 0.85 - 0.10

P(E or F) = 0.75

Therefore, the probability of the event E or F, denoted as P(E or F), is 0.75.

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Answer:

Step-by-step explanation:

You didn't give your options, but it doesn't matter. We'll find all the possibilities and then you can pick it from your list.

When I teach this in Algebra 2, I call it the "the c over d thing" and all my students know EXACTLY to what I am referring. "c" is the constant and "d" is the leading coefficient. The combination of c/d give you the possibilities of roots for the polynomial. There are no real roots that a polynomial can have other than the possibilities we find when we do the c/d thing.

Our c is a 20.  All the factors of 20 are as follows (notice that we have both the positive and negative factors):

20: ±1, ±2, ±4, ±5, ±10, ±20

Our d is a 3.  All the factors of 3 are as follows (again, both the + and the -):

3: ±1, ±3 and that's it for 3.

c/d is as follows. Make sure you put ever c over every d!!!:

c/d: ±\(\frac{1}{1}\), ±\(\frac{2}{1}\), ±\(\frac{4}{1}\), ±\(\frac{5}{1}\), ±\(\frac{10}{1}\), ±\(\frac{20}{1}\), ±\(\frac{1}{3}\), ±\(\frac{2}{3}\), ±\(\frac{4}{3}\), ±\(\frac{5}{3}\), ±\(\frac{10}{3}\), ±\(\frac{20}{3}\)

Those are all the possibilities for your roots for that polynomial. As long as the roots are real (and they won't always all be real!), there are no roots but these.

Answer:

its D on edge

Step-by-step explanation:

In Option 1, the arrival rate remains constant at 13 customers per hour. This means that, on average, 13 customers arrive at the checkout lane every hour, following a Poisson probability distribution.

However, the service rate in Option 1 increases to 30 customers per hour. This improvement is achieved by hiring a second person to assist the cashier in bagging groceries while the main cashier is occupied with entering cost data and collecting money from the customer. This essentially speeds up the overall service process, allowing more customers to be served within the same time frame.

The service rate of 30 customers per hour indicates that, on average, the cashier and the assistant can complete the checkout process for 30 customers in an hour. The service times still follow an exponential probability distribution, but with a faster rate of service compared to the initial service rate of 20 customers per hour.

By implementing Option 1, the manager aims to reduce the waiting time prior to the checkout process to no more than five minutes, thereby improving overall customer satisfaction and efficiency at Pete's Market.

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Answer: 6,440

                                                2

Step-by-step explanation:    230

                                               x 28

                                            ————-

                                            1

                                              1,840

                                            + 4,600

                                           —————

                                              6,440    

Answer:

Step-by-step explanation:

left skewed

Explanation

We can solve the question using the formula below

Therefore;

The probabilty of those that eat one or more of both foods

Hence, we can find the probability of those that do not like both ham and vegetable

Answer: 0.12

Answer:

0 and 1123

Step-by-step explanation:

Answer:

156 sq. units is the answer

Answer:

I think the answer is (v+2) x (v-6)

f(x) is increasing on the intervals (−∞, π/4) and (5π/4, ∞), and decreasing on the interval (π/4, 5π/4).

To determine the intervals on which f(x) = 3sin(x) + 3cos(x) is increasing and decreasing, we need to find the derivative of f(x) and examine its sign.

f'(x) = 3cos(x) - 3sin(x)

To find where f'(x) = 0, we set the derivative equal to zero and solve:

3cos(x) - 3sin(x) = 0

cos(x) - sin(x) = 0

From this equation, we can see that it is satisfied when x = π/4 and x = 5π/4.

Now, we analyze the sign of f'(x) in different intervals:

For x < π/4: f'(x) > 0, so f(x) is increasing.

For π/4 < x < 5π/4: f'(x) < 0, so f(x) is decreasing.

For x > 5π/4: f'(x) > 0, so f(x) is increasing.

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Answer:

my guess would be the first bubble, however i could be wrong.

Answer:

d that the answer my guy and ask something these

The answers for the function → y = \($a(0.5)^{\frac{t}{12} }\) are given above.

For y = aˣ -

We can write -

y' = dy/dx = aˣ log(x)

y' = aˣ log(x)

Given is the expression as -

y = \($a(0.5)^{\frac{t}{12} }\)

The given expression is -

y = \($a(0.5)^{\frac{t}{12} }\)

We can rewrite the expression as -

y = a\((1-0.5)^{t/12}\)

We can write -

dy/dt = d/dt { a\((1-0.5)^{t/12}\)}

dy/dt = a\((1-0.5)^{t/12}\) log(t/12)

It is a logarithmic rate.

Therefore, the answers for the function → y = \($a(0.5)^{\frac{t}{12} }\) are given above.

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Answer:

The first one is correct

Step-by-step explanation:

3(4+n)=n+18

The answer is option (C), that is, the events of rolling a fair die two times are independent. The events are neither disjoint nor exclusive.

When rolling a fair die two times, one can get any one of the 36 possible outcomes equally likely. Let A be the event of obtaining an even number on the first roll and let B be the event of getting a number greater than 3 on the second roll. Let’s see how the outcomes of A and B are related:

There are three even numbers on the die, i.e. A={2, 4, 6}. There are four numbers greater than 3 on the die, i.e. B={4, 5, 6}. So the intersection of A and B is the set {4, 6}, which is not empty. Thus, the events A and B are not disjoint. So option (A) is incorrect.

There is only one outcome that belongs to both A and B, i.e. the outcome of 6. Since there are 36 equally likely outcomes, the probability of the outcome 6 is 1/36. Now, if we know that the outcome of the first roll is an even number, does it affect the probability of getting a number greater than 3 on the second roll? Clearly not, since A∩B = {4, 6} and P(B|A) = P(A∩B)/P(A) = (2/36)/(18/36) = 1/9 = P(B). So the events A and B are independent. Thus, option (C) is correct. Neither option (A) nor option (C) can be correct, so we can eliminate options (D) and (E).

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Answer:

800

Step-by-step explanation:

Answer:

3/36

Simplified=1/12

Answer:

360-540 calories

Answer:

Similar by SAS.

Step-by-step explanation:

SSS - sides proportional.

AA -Same angles and sides should be proportional. In this case, the angles are different, so they are not similar by sss.

SAS - One equal angle, and sides proportional. Happens here. So the answer is similar by SAS.

Answer:

The average yearly change in the value of the card is $15/year

Step-by-step explanation:

Here in this question, we are interested in calculating the average yearly change in the value of the card.

From the question, we can see that the value of the baseball card has depreciated by $120, thus we simply want to calculate the average yearly charge in the card value.

Mathematically, that would be ;

the total depreciation value/ number of years

From the question, the total depreciation value is $120 while the number of years is 8

Thus; the average yearly change in value of the card = 120/8 = $15/year

The value of s for the given value is 24.05.

Given is an equation v² = u²+2gs, we need to find the value of s if v = 25, u = 12 and g = 10,

So,

25² = 12² + 2(10)s

625 = 144 + 20s

20s = 481

s = 24.05

Hence the value of s for the given value is 24.05.

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Answer:

Step-by-step explanation:

the first graph has points (-1, -1) and (2, -2)

slope m = (y2-y1) / (x2-x1) = (-1+2)/ (-1-2) = 1/-3 = -1/3

the second graph has points (0, -3) and (2, 0)

slope m = (y2-y1) / (x2-x1) = (-3-0)/ (0-2) = -3/-2 = 3/2

for the table

x.         y

-3.        4

0.        1

slope m = dierence in y /diference in x = 4-1 / -3-0 = 3/-3= -1

Answer:

Step-by-step explanation:

depends how much money is deposited, however, the choices can be just D or E

Answer:

B,D,E

Step-by-step explanation:

Does it say how much was deposited? Ok so deposit means your bank gets bigger so it cannot be less than -28.

My guess is that it will be either B,D,E

The reason I say my guess is because I think the question should have given you an amount of how much was deposited.

The required answer is the annual cost saved by shifting from the 500-bag lot size to the EOQ is $1,059.92.

Explanation:-

a. Economic order quantity (EOQ) is defined as the optimal quantity of inventory to be ordered each time to reduce the total annual inventory costs.

It is calculated as follows: EOQ = sqrt(2DS/H)

Where, D = Annual demand = 100 x 52 = 5200S = Order cost = $57 per order H = Annual holding cost = 0.30 x 10.75 = $3.23 per bag per year .Therefore, EOQ = sqrt(2 x 5200 x 57 / 3.23) = 234 bags. The average time between orders (TBO) can be calculated using the formula: TBO = EOQ / D = 234 / 100 = 2.34 weeks ≈ 2 weeks (rounded to nearest whole number).

Hence, the EOQ is 234 bags and the average time between orders is 2 weeks (approx).b. R is the reorder point, which is the inventory level at which an order should be placed to avoid a stockout.

It can be calculated using the formula:R = dL + zσL

Where,d = Demand per day = 100 / 5 = 20L = Lead time = 1 week (5 working days) = 5 day

z = z-value for 92% cycle-service level = 1.75 (from standard normal table)σL = Standard deviation of lead time demand = σ / sqrt(L) = 16 / sqrt(5) = 7.14 (approx)

Therefore,R = 20 x 5 + 1.75 x 7.14 = 119.2 ≈ 120 bags

Hence, the reorder point R should be 120 bags.c. An inventory withdraw of 10 bags was just made. Is it time to reorder?The current inventory level is 310 bags, which is greater than the reorder point of 120 bags. Since there are no open orders or backorders, it is not time to reorder.d. The store currently uses a lot size of 500 bags (i.e., Q = 500).What is the annual holding cost of this policy.

Annual ordering cost. Without calculating the EOQ, how can you conclude the lot size is too large?Annual ordering cost = (D / Q) x S = (5200 / 500) x 57 = $592.80 per year.

Annual holding cost = Q / 2 x H = 500 / 2 x 0.30 x 10.75 = $806.25 per year. Total annual inventory cost = Annual ordering cost + Annual holding cost= $592.80 + $806.25 = $1,399.05Without calculating the EOQ, we can conclude that the lot size is too large if the annual holding cost exceeds the annual ordering cost.

In this case, the annual holding cost of $806.25 is greater than the annual ordering cost of $592.80, indicating that the lot size of 500 bags is too large.e.

The annual cost saved by shifting from the 500-bag lot size to the EOQ can be calculated as follows:Total cost at Q = 500 bags = $1,399.05Total cost at Q = EOQ = Annual ordering cost + Annual holding cost= (D / EOQ) x S + EOQ / 2 x H= (5200 / 234) x 57 + 234 / 2 x 0.30 x 10.75= $245.45 + $93.68= $339.13

Annual cost saved = Total cost at Q = 500 bags - Total cost at Q = EOQ= $1,399.05 - $339.13= $1,059.92

Hence, the annual cost saved by shifting from the 500-bag lot size to the EOQ is $1,059.92.

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