Use the frequency transformation to find the parameters a, b, c, d, e € Z so that the transfer function: asbetc corresponds to a high-pass filter with cutoff frequency (lower limit for the passband) wi = 2/2 rad/s. H(s) = 1 +dste a: b: c: d: e:

A Flotilla Vice Commander (VFC) is a Flotilla-level Vice Commander under the Flotilla Commander (FC). The correct answer for this question is A.

VFC is responsible for assisting FC in the overall direction and management of the fleet. The other options listed are not the correct titles for elected officers at the platoon level.

Therefore, we conclude that the correct answer is A. At the Fleet level, the appropriate titles for elected officers are Fleet Commander (FC) and Fleet Vice Commander (VFC).

The Fleet Commander is responsible for managing the entire fleet, while the Deputy Fleet Commander supports the FC and takes over FC duties when necessary.

Other options (B. Commodore, C. Flotilla Staff Officer, D. Division Commander) represents a variety of roles within the organization and is not an officer position elected at the fleet level. 

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Answer:

y'(x) = 7 ;

y'(x) = 15x²

Explanation:

Differentiation from first principle :

y = 7x

Formula to obtain derivative from first principle:

y'(x) = lim(h - - > 0) : [y(x + h) - y(x)] / h

Obtain : y(x + h)

y(x) = 7x

y(x + h) = 7(x + h)

Substitute into formula :

y'(x) = lim(h - - > 0) : [7(x + h) - 7x] / h

Expand :

y'(x) = lim(h - - > 0) : [7x + 7h - 7x] / h

y'(x) = lim(h - - > 0) : 7h/ h

y'(x) = 7

2.)

y = 5x³

y'(x) = lim(h - - > 0) : [y(x + h) - y(x)] / h

Obtain : y(x + h)

y(x) = 5x³

y(x + h) = 5(x + h)³

Substitute into formula :

y'(x) = lim(h - - > 0) : [5(x + h)³ - 5x³] / h

Expand :

y'(x) = lim(h - - > 0) : [5(x³ + 3x²h + 3xh² + h³) - 5x³] / h

y'(x) = lim(h - - > 0) : [5x³ + 15x²h + 15xh² + 5h³ - 5x³] / h

y'(x) = lim(h - - > 0) : [15x²h + 15xh² + 5h³] / h

y'(x) = lim(h - - > 0) : h(15x² + 15xh + 5h²) / h

y'(x) = lim(h - - > 0) : (15x² + 15xh + 5h²)

y'(x) = 15x²

The Poisson's ratio for a cast iron with a modulus of elasticity (E) of 110 Gpa and a modulus of rigidity (G) of 44 Gpa is 0.42.

Poisson's ratio is the ratio of transverse strain to corresponding axial strain on a material stressed along one axis. The Poisson's ratio for a cast iron with a modulus of elasticity (E) of 110 Gpa and a modulus of rigidity (G) of 44 Gpa can be calculated as follows:

Poisson's ratio (ν) = (E/2G)-1

ν = (110/2(44))-1

ν = 0.42

Therefore, the answer from the above calculation is 0.42.

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Answer:

Explanation:

The temperature difference used for calculation would depend on the desired indoor temperature, the outdoor temperature, and the desired level of energy efficiency. A professional heating system designer would be able to provide a more accurate answer based on the specific requirements of the building and the heating system being designed.

Answer:

Trade association.

Explanation:

I'm thinking it is as it represents contractors who design, install, inspect and maintain amongst other activities electrical and electronic equipments or service.

In Scheme, let, let*, and letrec are all used to define local variables. However, they differ in the scope of the variables and the order of evaluation.

The let form defines all variables in parallel, meaning that each variable can reference any previously defined variable. However, the scope of these variables is limited to the body of the let expression.

The let* form defines variables one at a time, with each variable being able to reference only previously defined variables. This means that the scope of each variable is limited to the expression that follows its definition.

The letrec form is similar to let, but it allows the variables to reference each other within the same expression. This is useful for defining mutually recursive functions. However, unlike let and let*, all the variables are defined before any of them are evaluated.

In summary, the main difference between let, let*, and letrec is the scope and order of evaluation of the variables. Let defines all variables at once, let* defines them one at a time in order, and letrec allows them to reference each other but must define them all before evaluating any.

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This question is incomplete, the missing diagram is uploaded along this answer below.

Answer:

- The mass flow rate of air is 4.59 kg/s

- Area of the exit turbine is 0.066 m²

Explanation:

 Given the data in the question;

Using air as an ideal gas.

Turbine;

state 1: p₁ = 8 bar, T₁ = 960 K

state 2: p₂ = 1 bar, T₂ = 450 K

The inlet velocity is small compared to the exit velocity of 90 m/s

V₁ < V₂ = 90 m/s

Power of turbine W' = 2500 kW

Now, lets assume Q = 0 and ΔPE = 0

we know that; R = 0.2870 kJ/kg-K

Also. \(C_p\) at 700K = 1.075 kJ/kg-K

Now, using ideal gas law;

STATE1

v₁ = RT₁/p₁

so we substitute

v₁ = [(0.2870 kJ/kg-K)(960 K)/(8 bars )]|\(\frac{bar}{10^5N/m^2}\)||\(\frac{1000N.m}{kJ}\)| =  0.344 m³/kg

STATE2

v₂ = RT₂/p₁

we substitute

v₂ = [(0.2870 kJ/kg-K)(450 K)/(1 bars )]|\(\frac{bar}{10^5N/m^2}\)||\(\frac{1000N.m}{kJ}\)| =  1.2915 m³/kg

Now, from energy balance steady state;

0 = Q" - W" + \(m"_i\)( \(h_i\) + \(\frac{V_i^2}{2}\) + \(gz_i\)) - \(m"_B\)( \(h_B\) + \(\frac{V_B^2}{2}\) + \(gz_B\))

since we initially assume Q = 0 and ΔPE = 0

hence;

0 = \(-\frac{W"}{m"}\) + h₁ + \(\frac{V_1^2}{2}\) -  h₂ + \(\frac{V_2^2}{2}\)

\(\frac{W"}{m"}\) = h₁ + \(\frac{V_1^2}{2}\) -  h₂ + \(\frac{V_2^2}{2}\)

⇒  \(\frac{W"}{m"}\) = \(C_p\)(T₁ - T₂) + \(\frac{1}{2}\)( V₁² - V₂²)

we solve for m"

m" = W" / (\(C_p\)(T₁ - T₂) + \(\frac{1}{2}\)( V₁² - V₂²))

so we substitute;

m" = {[2500 kW] / [(1.075kJ/kg-K(960K - 450k) + \(\frac{1}{2}\)( (0)² - (90 m/s)²)) |kJ/1000N.m| |N/kg.m/s²|]} | kJ/s / kW|

m" = 4.59 kg/s

Therefore, the mass flow rate of air is 4.59 kg/s

From the mass body steady state;

0 = m"₁ - m"₂

so

m"₁ = m"₂ = 4.59 kg/s

now, the volumetric flow rate V"₂ will be;

V"₂ = m" × v₂

we  substitute

V"₂ =  4.59 kg/s × 1.2915 m³/kg = 5.93 m³/s

and

the volumetric flow rate V"₂ = A₂V₂

so;

Exit Area A = V"₂ / V₂

we substitute

A = (5.93 m³/s ) / (90 m/s)

A = 0.06589 ≈ 0.066 m²

Therefore, Area of the exit turbine is 0.066 m²

A 1500 kg crate is pulled along the ground with a constant speed of a distance for 25m , using a cable that makes a horizontal angle of 15 ° . Determine the tension in the cable . The coefficient of kinetic friction between the ground and the crate is H4 = 0.55

Answer: s = 1.05 ft

In this case, the timebase control is set to 2.5 ms per division, so the frequency of the sine wave is 40 Hz. (Opton A)

Frequency = (Number of divisions * Vertical sensitivity control) / (Timebase control)

Hence,

Frequency = (10 divisions * 0.5 volts per division) / (2.5 ms per division)

= 40 Hz

Time base control refers to the regulation and adjustment of the timing or speed of a process or system to ensure synchronization or accuracy based on a reference time or desired timeframe.

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Answer: Kristin is currently modifying a newly discovered plastic material to work on a new lightweight lacrosse stick.

Explanation:

The main function of a materials engineer is to develop, study and test materials that are used on order to make different products.

Material engineer solve problems in other engineering fields, like electrical, aerospace, civil, mechanical, chemical, and nuclear.

From the information given in the question, the correct option is "Kristin is currently modifying a newly discovered plastic material to work on a new lightweight lacrosse stick."

Answer:

nice

Explanation:

Answer:

  (a)  -55.6%, -31.25 V

  (b) -11.1%, -6.25 V

  (c) -0.93%, -0.52 V

Explanation:

The open-circuit voltage is (75V)(750/(250+750)) = 56.25 V.

The circuit to which the meter is connected has a Thevenin equivalent impedance of 1/(1/250 +1/750) = 187.5 kΩ. So, the relative error for a given meter impedance of R (in kΩ) is ...

  (R/(R +187.5) -1) × 100% = -187.5/(R +187.5) × 100%

(a) For a meter impedance of (1 kΩ/V)×150V = 150 kΩ, the error is ...

  -187.5/(150 +187.5) × 100% ≈ -55.6%

The voltage error is (56.25 V)(-55.6%) = -31.25 V.

__

(b) For a meter impedance of (20 kΩ/V)×75V = 1500 kΩ, the error is ...

  -187.5/(1500+187.5) × 100% ≈ -11.1%

The voltage error is (56.25 V)(-5.88%) = -6.25 V.

__

(c) For a meter impedance of 20,000 kΩ, the error is ...

  -187.5/(20000+187.5) × 100% ≈ -0.93%

The voltage error is (56.25 V)(-0.93%) = -0.52 V.

i] The density of the pellet is 0.977 g/cm^{3}. ii] The macropore volume in cm^{3}/g is 0.205 cm^{3}/g. iii] The macropore void fraction in the pellet is 25.1%.iv] The micropore void fraction in the pellet is 49.0%. v] The solid fraction of the pellet is 25.9%. vi] The density of the particles is 1.222 g/cm^{3}.

i] To determine the density of the pellet, we can use the formula:

Density = Mass / Volume

Given that the mass of the pellet is 3.15 g and the volume is 3.22cm^{3}, we can calculate the density as follows:

Density = 3.15 g / 3.22 cm^{3}≈ 0.977 \(g/cm^{3\)

ii] The macropore volume in cm3/g can be calculated by dividing the macropore volume of the pellet (0.645 cm3) by the mass of the pellet (3.15 g):

Macropore volume = 0.645 cm^{3} / 3.15 g ≈ 0.205 \(cm^{3} /g\)

iii] The macropore void fraction in the pellet can be calculated using the formula:

Macropore void fraction = Macropore volume / Total volume of the pellet

Total volume of the pellet = Volume - Macropore volume = 3.22 cm^{3}- 0.645 cm^{3} = 2.575 cm^{3}

Macropore void fraction = 0.645 cm^{3} / 2.575 \(cm^{3}\)≈ 0.251 or 25.1%

iv] The micropore void fraction in the pellet can be calculated using the given micropore volume of the particles (0.40 cm^{3} /g) and the mass of the pellet (3.15 g):

Micropore volume in the pellet = Micropore volume/g x Mass

Micropore volume in the pellet = 0.40 \(cm^{3} /g\) x 3.15 g = 1.26 cm3

Micropore void fraction = Micropore volume in the pellet / Total volume of the pellet

Micropore void fraction = 1.26 \(cm^{3}\) / 2.575 \(cm^{3}\) ≈ 0.490 or 49.0%

v] The solid fraction of the pellet can be calculated by subtracting the sum of macropore and micropore void fractions from 1:

Solid fraction = 1 - (Macropore void fraction + Micropore void fraction)

Solid fraction = 1 - (0.251 + 0.490) ≈ 0.259 or 25.9%

vi] The density of the particles can be determined using the mass of the pellet (3.15 g) and the total volume of the particles:

Total volume of the particles = Volume - Macropore volume = 3.22 \(cm^{3}\)- 0.645 \(cm^{3}\) = 2.575\(cm^{3}\)

Density of the particles = Mass / Total volume of the particles

Density of the particles = 3.15 g / 2.575\(cm^{3}\) ≈ 1.222 \(g/cm^{3}\)

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(a) The probability that at least 1 in 10 successive sections signal a problem when in fact the sections are intact is 26.26%.

(b) The probability that at least 1 in 20 successive sections signal a problem when in fact the sections are intact is 50.16%.

Ultrasonic pulse velocity testing is a non-destructive test used to assess the integrity of concrete structures. The test can indicate whether a concrete section is intact or if there is a problem. However, even when a section is intact, there is a small probability that the test equipment may signal a problem, known as a "false positive." In this case, the probability of a false positive is 0.03.

(a) To calculate the probability that at least 1 in 10 successive sections signal a problem when the sections are actually intact, we can use the formula:

P(getting at least 1 false positive) = 1 - P(getting no false positive).

Assuming independence between successive sections, the probability of getting no false positive in one section is (1 - p)^10. Therefore,

P(getting at least 1 false positive) = 1 - (1 - 0.03)^10

P(getting at least 1 false positive) = 0.2626 or 26.26%.

(b) Similarly, to calculate the probability that at least 1 in 20 successive sections signal a problem when the sections are intact, we use the same formula. The probability of getting no false positive in one section is (1 - p)^20. Therefore,

P(getting at least 1 false positive) = 1 - (1 - 0.03)^20

P(getting at least 1 false positive) = 0.5016 or 50.16%.

Therefore, the probability that at least 1 in 10 successive sections signal a problem when the sections are intact is 26.26%, while the probability that at least 1 in 20 successive sections signal a problem when the sections are intact is 50.16%.

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Answer:

The golfer is at greater risk.

Explanation:

The golfer is holding a metal club. Metal is a good conductor for electricity (lightning), meaning electrons can pass through easily. Her caddy is at lesser risk because she is holding a plastic handled umbrella. Plastic is an insulator, which does not easily allow the movement of electrons to pass.

Answer:

This is not an engineering question.

Explanation:

Answer:

provides the Organization with accurate data analytics ,

provides/ensures strict compliance in the organization,

helps in lowering the cost of managing data in the organization and

provides the data scientists access to the exact data they require to work with

Explanation:

The adoption of a data platform by an organization for the purpose of  handling Data, helps to simplify data governance by :

i)provides the Organization with accurate data analytics ,

ii) provides/ensures strict compliance in the organization,

iii) It helps in lowering the cost of managing data in the organization and

iv) provides the data scientists access to the exact data they require to work with

A true statement about the seal between the respirator and the wearer's face is: D. facial hair can prevent a respirator from properly sealing to the wearer’s face.

A respirator can be defined as a personal protective equipment that is typically worn over the face to protect the mouth and nose, while protecting the wearer from inhaling smoke, dust, or other toxic chemical substances.

In this context, a true statement about the seal between the respirator and the wearer's face is that facial hair has the ability to prevent a respirator from properly sealing to the wearer’s face.

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The modulus of elasticity of concrete increases in proportion to the magnitude of the material's compressive strength. This can be explained by a higher coefficient (correlation) between the compressive strength (square root) and modulus of elasticity of concrete.

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The basic requirement of measurements is to have a standard or reference point against which to compare the quantity being measured. This standard or reference point should be well-defined and stable, and the measurement process should be repeatable and consistent. Additionally, it is important to ensure that the measurement equipment is calibrated and in good working condition.

Answer:

The most basic requirement for measurements is the presence of a standard or reference point against which the quantity being measured can be compared. The measurement process should be repeatable and consistent, and the standard or reference point should be well-defined and stable. Furthermore, ensure that the measurement equipment is calibrated and in good working order.

Explanation:

Answer:

Explanation:

To determine the required size of standard schedule 40 steel pipe to carry 192 m³/hour of water with a minimum velocity of 6.0 m/sec, we can use the following formula:

Q = A × v

where Q is the volumetric flow rate of water, A is the cross-sectional area of the pipe, and v is the velocity of water.

First, we need to convert the volumetric flow rate from m³/hour to m³/sec.

192 m³/hour = 0.0533 m³/sec

Next, we can rearrange the formula to solve for the cross-sectional area:

A = Q / v

A = 0.0533 m³/sec / 6.0 m/sec

A = 0.0089 m²

The cross-sectional area of the pipe is 0.0089 m².

Standard schedule 40 steel pipe has a nominal inside diameter (ID) of 1.049 inches, which is approximately 0.0266 meters. The cross-sectional area of the pipe can be calculated using the formula for the area of a circle:

A = π × (ID/2)²

A = 3.14 × (0.0266/2)²

A = 5.58×10^-4 m²

To determine the required size of the pipe, we can rearrange the formula for the area of a circle to solve for the diameter:

ID = 2 × √(A/π)

ID = 2 × √(0.0089/π)

ID = 0.106 meters

Therefore, the required size of standard schedule 40 steel pipe to carry 192 m³/hour of water with a minimum velocity of 6.0 m/sec is a nominal size of 4 inches, with an inside diameter of 0.102 meters (or 102 millimeters).

Answer:

B) Minimum voltage drop across meter

Explanation:

An ammeter is a measuring instrument device that is used to measure small currents flowing through a circuit in milli-ampere. The internal resistance of the milli ammeter is very low so that there would be a minimum voltage drop across the meter causing a minimum effect of the current in the circuit, this results to a measurement closer to the original value. If a high resistance is place, there would be large voltage drop therefore the current measured would be lesser than the original value.

The fundamental principle is that two force systems are equal if they produce the same resultant force and resultant moment.

A force can be moved along its line of action to create a new force system that is comparable to the original force system. The Pythagorean theorem is used to calculate the resultant force when two forces are acting perpendicularly to one another. The formula for the resultant force is FR = F1 + F2 + F3. Where. The three forces that are acting on an object in the same direction are F1, F2, and F3. In other words, the forces of action and reaction work in tandem. Therefore, the outcome is zero if action and reaction are applied to the same body.

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The correct option for the implication of low variety is B) Flexibility needed. Variety refers to the number of different products, services, or activities that an organization offers. High variety means that a company offers a wide variety of products or services, while low variety means that a company provides a limited range of products or services.

One of the implications of low variety is that customers have limited options. They are restricted to purchasing only those goods and services that the company offers, which may not match their requirements or preferences. This may lead to losing customers to rivals who offer a greater variety of goods and services.

In the case of low variety, it is critical to have the required flexibility. Customers may ask for certain specific goods or services that are not provided by the company. To meet customer requirements, the company should be adaptable and able to rapidly respond to customer requests by expanding its product line. As a result, low variety necessitates the need for flexibility.

The other given options are not valid. Low unit cost is not related to low variety. Unit cost may be affected by economies of scale and other factors, but it is not directly related to variety. High complexity is not related to low variety as well. As the range of goods and services offered by the company increases, the complexity of the company's operations and management also increases. Matching customers' specific needs is partially correct because the company cannot match customer specific needs in low variety. In low variety, the company has a limited range of goods and services, so it is not possible to fulfill all the customers’ specific needs.

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The option that is not a requirement for open yard storage driveways is C. Paved surface. This surface type is optional.

Open yard storage driveway is an area used to keep vehicles and equipment in open yards that have driveways. This is not a warehouse or other enclosed structure. In order to create an effective open yard storage driveway, you must comply with several rules. These standards may vary depending on your area, but they are often mandated by local zoning and permitting agencies.

Let's go over the given options and identify the one that is not a requirement for open yard storage driveways.

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Answer:

Sum.

Explanation:

An electric motor can be defined as a machine which is typically used for the conversion or transformation of electrical energy into mechanical energy.

Basically, the mode of operation of an electric motor is simply to supply the motor with an alternating current (AC) voltage to one end, which is then used to power the axle (metal rod) at the other end of the motor.

Two motors can be made to run simultaneously in a synchronous manner through the use of a standby power system that provides the required level of power (alternating current and voltage).

Thus, if two motors are to be started at the same time, the standby power system must have the capacity to provide the sum of the starting kilovolt-ampere (KVA) values for the TWO motors.

Answer:

Crude

Explanation:

Answer:

Creating an app is both an expression of our self and a reflection of what we see is missing in the world. We find ourselves digging deep into who we are, what we would enjoy working on, and what needs still need to be fulfilled. Generating an app idea for the first time can be extremely daunting. Especially with an endless amount of possibilities such as building a church app.

The uncertainty has always spawned a certain fear inside creators. The fear of creating something no one will enjoy. Spending hundreds of dollars and hours building something which might not bring back any real tangible results. The fear of losing our investment to a poor concept is daunting but not random. But simple app ideas are actually pretty easy to come by.

Great app idea generation is not a gift given to a selected few, instead, it is a process by which any of us are able to carefully explore step by step methods to find our own solution to any problem. Whether you are a seasoned creator or a novice, we have provided a few recommendations to challenge and aid you as you create your next masterpiece.

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