using arrows to designate the flow of electrons, provide a detailed reaction mechanism for the synthesis of dibenzalacetone as performed in this lab. show all the reactive intermediates and the major and minor products.

The concentration of the reactant after 30 seconds is 0.109 M. In a first-order decomposition reaction, the rate of the reaction depends only on the concentration of the reactant.

The rate constant (k) for a first-order reaction is a constant that describes the proportionality between the rate of the reaction and the concentration of the reactant. The equation for a first-order reaction is ln([A]t/[A]0) = -kt, where [A]t is the concentration of the reactant at time t, [A]0 is the initial concentration of the reactant, k is the rate constant, and t is time.

In this case, we are given the rate constant (k) of 0.0147 s^-1 and the initial concentration of reactant ([A]0) of 0.178 M. We are asked to find the concentration of reactant ([A]t) after 30 seconds (t=30). Plugging these values into the first-order equation, we get:
ln([A]t/0.178) = -0.0147 x 30
ln([A]t/0.178) = -0.441
[A]t/0.178 = e^-0.441
[A]t = 0.178 x e^-0.441
[A]t = 0.109 M

Therefore, the concentration of the reactant after 30 seconds is 0.109 M.

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Answer:

D. tap water

keep on learning!

Answer: ethanol

Explanation: as it is a pure compound and can sometimes be a mixture while all the rest are mixtures.

Answer:

Earthquakes are more intense the faster the planet's crust slams together, which explains why the shaking causes so much damage in some of the most populated areas around mountain chains. ... One reason for this connection is that when two plates come together quickly, the area over which an earthquake occurs is larger.Explanation:

One of the reactions they would have observed that would push the reaction either in the forward or reverse direction is NaCl (aq) ⇌ Na+ (aq) + Cl- (aq)

Cobalt chloride system described on page 60 of the lab manual consist of cobalt chloride solution containing 0.20 M CoCl2 in 4.0 M NaCl. When one of the reagents listed in part b of the lab is added, there will be a change in the reaction system and this will push the reaction either in the forward or reverse direction.Reaction that would push the reaction either in the forward or reverse direction by filling in the blanks in the statement given below is shown below;NaCl (aq) ⇌ Na+ (aq) + Cl- (aq)When a small quantity of NaCl is added to the Cobalt chloride solution, the concentration of Cl- ions increases. According to Le Chatelier's principle, the equilibrium will shift towards the left in order to counteract the increase in Cl- ions. This is because by reducing the amount of Cl-, the equilibrium system will try to balance the added NaCl. So, the phenomenon that occurred that caused the equilibrium to shift was the addition of NaCl to the cobalt chloride solution.

Therefore, we can say that the addition of NaCl to the cobalt chloride system described on page 60 of the lab manual will cause the equilibrium to shift towards the left.

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Glycolysis, the splitting of glucose into two 3-carbon molecules.

The citric acid or Krebs cycle, which produces CO2, NADH, FADH2, and ATP.

The concentration of hydroxide ions in the solution is also 1.67 M.

To determine the concentration of hydroxide ions in the solution, we need to first calculate the number of moles of sodium hydroxide (NaOH) present in the solution, and then use stoichiometry to determine the concentration of hydroxide ions.

The formula for sodium hydroxide is NaOH, which contains one sodium ion (Na+) and one hydroxide ion (OH-). The molar mass of NaOH is 40.00 g/mol (sodium: 22.99 g/mol, oxygen: 15.99 g/mol, hydrogen: 1.01 g/mol).

First, we need to convert the mass of NaOH to moles:

moles of NaOH = mass of NaOH / molar mass of NaOH

moles of NaOH = 10.0 g / 40.00 g/mol

moles of NaOH = 0.250 mol

Next, we need to calculate the final concentration of NaOH in the solution:

concentration of NaOH = moles of NaOH / volume of solution

concentration of NaOH = 0.250 mol / 0.150 L

concentration of NaOH = 1.67 M

Since sodium hydroxide is a strong base, it completely dissociates in water to produce one mole of hydroxide ions for every mole of sodium hydroxide:

NaOH(s) → Na+(aq) + OH-(aq)

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The initial concentration in the reaction mixture will contain [A] = 0.1 M and [B] = 1.0 M

Below is the reaction

A(g) → B(g)

And the equilibium constant will be explained in terms of [A] and [B]:

Keq = 10 = [B]/[A]

If the first conditions are that [A] = 1.1 M and [B] = 0.0 M, the conditions at equilibrium is:

[A] = 1.1M - x

[B] = 0.0M + x

Now we rewrite Keq:

Keq = 10 = [0.0 +x] / [1.1 -x]

at the end we got it  for x:

10 = [0.0 +x] / [1.1 -x]

10 * (1.1-x) = x

11 - 10x = x

11 = 11x

x = 1

equilibrium, the concentrations are:

[A] = 1.1 M - 1 = 0.1 M

[B] = 0.0 M + 1 = 1.0 M

Thus, the concentration of A is 0.1 M and the concentration of B is 1M.

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Answer:

The balanced equation is:

2NaCl + F₂ → 2NaF + Cl₂

Explanation:

Balancing an equation is a bit like playing musical chairs.  There is no quick formula for success, but a little trial and error will lead to the solution.  And a little practice goes a long way.

      NaCl + F₂ → NaF + Cl₂

Check how many times an element appears on each side of the equation:

Element   Reactants   Products    Balanced?

    Na                1                1                  Yes

    Cl                 1                2                   No

    F                  2                1                   No

The equation has two elements not balanced.  Lets start with the Cl.  Each molecule of Cl2 has 2 Cl atoms, but there is only 1 brought in by the NaCl.  We can't use Cl as a product, since it does not exist under normal conditions.  So lets make the coefficient for the NaCl 2, instead of 1.

2NaCl + F₂ → NaF + Cl₂

Element   Reactants   Products    Balanced?

    Na                2                1                  No

    Cl                 2                2                  Yes

    F                  2                1                   No

Now the sodium is unbalanced due to this change.  Add a coefficient of 2 to the NaF to accomodate the extra sodium atom:

2NaCl + F₂ → 2NaF + Cl₂

Element   Reactants   Products    Balanced?

    Na                2                2                  Yes

    Cl                 2                2                  Yes

    F                  2                2                   Yes

The equation is now balanced.  Each atom can be accounted for.

 2NaCl + F₂ → 2NaF + Cl₂

====

This process may seem a bit tedius, but it becomes easier with practice:  Some points that can help:

              NaCl + F₂ → NaF + (1/2)Cl₂

Element   Reactants   Products    Balanced?

    Na                1                1                  Yes

    Cl                 1                2                  Yes

    F                  2                1                   No

Now do the same for the F2 on the reactant side:

NaCl + (1/2)F₂ → NaF + (1/2)Cl₂

Element   Reactants   Products    Balanced?

    Na                1                1                  Yes

    Cl                 1                2                  Yes

    F                  2                2                  Yes

The equation is now balanced.  But there is no such thng as 1/2 of a molecule (except, perhaps, in politics).

So multiply all the coefficients by a facor that makes them whole numbers.  We can use 2, in this case.

2NaCl + 2(1/2)F₂ → 2NaF + 2(1/2)Cl₂

2NaCl + 1F₂ → 2NaF + 1Cl₂

This is the correct equation.  The point is that a non-whole coefficient may be used to start, as long as they are all whole numbers at the conclusion.

A sample of gas occupies a volume of 70.3 ml as it expands, it does 140.6 j of work on its surroundings at a constant pressure of 783 torr and the final volume of the gas is 11.12L

A gas is a sample of matter that conforms to the shape of a container in which it is held and acquires a uniform density inside the container and even in the presence of gravity and regardless of the amount of substance in the container

Here given data is 11.12L

V₁ = Initial volume = 70.3 ml = 0.0703ml =  (1L=1000ml)

w = 140.6 J = 1.387 J = (1Latm=101.3J)

Pressure =  783 torr = 1.03 atm  = (1atm=760 torr)

V₂ = final volume = ?

1.387Latm = 1.03 atm × (V₂ - 0.0703ml)

(V₂ - 0.0703ml) = 11.05

V₂ = 11.12L

The final volume of the gas is 11.12L

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Answer:

114.818 amu.x(112.9041) + (1 - x)

(114.9039) = 114.818Solving for xx=0.043 or 4.3%

Explanation:

The average atomic mass written in the periodic table is determined from the relative abundances of the element's isotopes. The equation would be:Average Atomic Mass = ∑(Relative Abundance×Mass)Let be the relative abundance of Indium-113. Because there are only 2 isotopes, their relative abundances should equal to 1, such that the relative abundance for Indium-15 is (1-x). The atomic mass of indium is 114.818 amu.x(112.9041) + (1 - x)(114.9039) = 114.818Solving for x,x = 0.043 or 4.3%

You'll have 20.5 g of hydrochloric acid (HCl) left, which is the answer to your query.

Data

HCl = 31.4 g

NaOH = 12 g

insufficient HCl =?

equilibrium in a chemical reaction

NaCl and H2O are produced from HCl and NaOH.

HCl's molar mass is equal to 1 + 35.5 = 36.5 g.

NaOH's molar mass is 40 g (23 + 16 + 1)

Figure out the limiting reactant.

Theoretical yield: 36.5/40 = 0.9125 for HCl/NaOH.

Research yield: HCl/NaOH = 31.4/12 = 2.62

Conclusion

Because of the increasing experimental yield, NaOH is the limiting reactant.

The excess reactant's mass should be determined.

35. 5 g of HCl ———————— NaOH weight 40 g

x ———————— NaOH in 12 g

x = (12 x 36.5) / 40

x = 438 / 40

x = 10.95 grams of HCl

Surplus HCl = 31.4 - 10.95

= 20.5 g

You'll have 20.5 g of HCl left, which is the answer to your query.

The complete question is,

To create aqueous sodium chloride and liquid water, aqueous hydrochloric acid must be combined with solid sodium hydroxide. Consider combining 12.g of sodium hydroxide with 31.4g of hydrochloric acid. Determine the smallest amount of hydrochloric acid that could possibly remain after the reaction. The quantity of significant digits in your response must be accurate.

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Answer:

b

Explanation:

because hahamaskdjdjskskskskkssksksks

Whenever there is a reaction between CoBr2 and LiPO4 then the precipitate that is formed will be Co3(PO4)2 so, the correct option is (4).

This is because the reaction that takes place is a double displacement reaction between CoBr2 and Li3PO4, where the Co2+ and PO43- ions exchange partners to form Co3(PO4)2 and 6LiBr:

CoBr2 + Li3PO4 -> Co3(PO4)2 + 6LiBr

Co3(PO4)2 is insoluble in water, and thus forms a precipitate. The other products, LiBr, remains in solution because they are soluble salts.

Therefore, the correct answer is option 4 - Co3(PO4)2 precipitate.

Co3(PO4)2 is a chemical compound with the formula Co3(PO4)2. It is also known as cobalt(II) phosphate, and is a grayish-white solid that is insoluble in water. It is an ionic compound that contains Co2+ and PO43- ions, and forms a crystalline lattice structure.

Co3(PO4)2 is commonly used in the production of ceramics and glass, as a catalyst in certain chemical reactions, and as a pigment in paints and coatings. It also has potential applications in the field of energy storage, particularly in the development of new battery materials.

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Methylamine could be said to be a Brownstead Lowry base because of 3.

A Brnsted-Lowry base is a type of organism or molecule with the capacity to bind to or take a proton from an acid. A base transforms into its conjugate acid when it takes a proton. This hypothesis is based on the notion that protons are transferred across species during an acid-base reaction.

In contrast to the Arrhenius theory, which defines bases as chemicals that create hydroxide ions, the Brnsted-Lowry base idea offers a broader and more encompassing definition of bases.

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Answer:

Difference between concentrated acid and weak acid :---

While,

Answer:separate cabbage from liquid

Explanation:

Just trust me lol

Answer:

Its D - separate cabbage from liquid

Explanation:

On Edge 2021

The formula of the hydrate when 54.3% of its mass is lost upon heating is Na₂CO₃.7H₂O.

When a hydrate of Na₂CO₃ is heated until all the water is removed, it loses 54.3 percent of its mass. This means that 54.3 percent of the original mass of the hydrate was water. To determine the formula of the hydrate, we need to find the number of moles of water that were present in the original hydrate. We can do this by using the formula:

mass of water/molar mass of water = moles of water

                                      54.3/18.015 = 3.01 moles of water

Since the molar mass of Na₂CO₃ is 105.99 g/mol, we can calculate the number of moles of Na₂CO₃ in the original hydrate:

mass of Na₂CO₃ /molar mass of Na₂CO₃ = moles of Na₂CO₃

                                               45.7/105.99 = 0.431 moles of Na₂CO₃

Now we can determine the formula of the hydrate by dividing the moles of water by the moles of Na₂CO₃:

3.01/0.431 = 6.98 ≈ 7

Therefore, the formula of the hydrate is Na₂CO₃.7H₂O.

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The Ka for the acid is approximately 1.3 x 10⁻⁵.

The first step in solving this problem is to use the pH of the solution to calculate the concentration of hydronium ions, [H3O+].

pH = -log[H3O+]

2.73 = -log[H3O+]

[H3O+] = 5.0 x 10⁻³ M

Since the acid is monoprotic, the concentration of the acid is equal to the concentration of hydronium ions, [HA] = [H3O+] = 5.0 x 10⁻³ M.

The next step is to use the equilibrium expression for the dissociation of the acid to calculate the acid dissociation constant, Ka.

HA + H2O ⇌ H3O+ + A-

Ka = [H3O+][A-] / [HA]

At equilibrium, the concentration of the acid that has dissociated is equal to the initial concentration of the acid minus the concentration of the acid that remains undissociated. Since the acid is weak, we can assume that the change in concentration of the acid due to dissociation is small compared to the initial concentration of the acid.

Let x be the concentration of acid that has dissociated. Then the concentration of undissociated acid is (0.005 - x).

Substituting these values into the equilibrium expression and simplifying:

Ka = (5.0 x 10⁻³ - x)(x) / (5.0 x 10⁻³)

Since x is small compared to 5.0 x 10⁻³, we can assume that (5.0 x 10⁻³ - x) ≈ 5.0 x 10⁻³, and simplify the expression further:

Ka ≈ x² / 5.0 x 10⁻³

Ka ≈ 1.3 x 10⁻⁵

Therefore, the acid dissociation constant, Ka, for the monoprotic acid is approximately 1.3 x 10⁻⁵.

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Calcium carbonate is neither acid nor base, it's a SALT.

Answer:

none,It is a salt of the calcium, ion a strong base and carbonic acid, a very weak acid. Answer: calcium carbonate is a salt, it is neither acid nor base

Answer:

b

Explanation:

Answer:

b

Explanation:

b

Answer:

A. its reactive

Explanation

Answer:

The youth is the indicator of how developed a country is, and they determine how fast or slow the economy grows

Explanation:

If the youth don’t get employed, the level of poverty increases due to the constantly increasing number of youths and this means that even if the working population generates capital, on one hand, the youth will be negating its effect on the other hand, and therefore at the end of the day, there will be no significant economic growth.

Glucose will dialyze from a 0.050 M solution to a 0.010 M solution, glucose molecules will diffuse through the semipermeable membrane, from the higher concentration.

Dialysis is a process in which solute molecules selectively pass through a semipermeable membrane from a region of higher concentration to a region of lower concentration. In this scenario, glucose is the solute and solutions A and B represent different concentrations of glucose.

Since the concentration of glucose in solution B (0.050 M) is higher than in solution A (0.010 M), glucose molecules will dialyze from solution B to solution A. This movement occurs because dialysis allows for the equalization of concentrations, with solute molecules moving from regions of higher concentration to regions of lower concentration.

As a result, solution B to the lower concentration solution A, until the concentration becomes equalized or reaches equilibrium. Therefore, the glucose will dialyze from the 0.050 M solution to the 0.010 M solution.

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Answer:

39.6 g

Explanation:

The equation of the reaction is;

2Mg(s) + O2(g) --------> 2MgO(s)

To obtain the limiting reactant;

Number of moles in 26.4 g of Mg = 26.4g/24 g/mol = 1.1 moles

If 2 moles of Mg yields 2 moles of MgO

1.1 moles of Mg yields 1.1 * 2/2 = 1.1 moles of MgO

Number of moles in 26.4 g of O2 = 26.4 g/32g/mol = 0.825 moles

If 1 mole of O2 yields 2 moles of MgO

0.825 moles of O2 yields 0.825 moles * 2/1 = 1.65 moles of MgO

Hence Mg is the limiting reactant.

Theoretical yield of MgO = 1.1 moles of MgO * 40 g/mol = 44 g

Percent yield = 90%

Percent yield = actual yield/theoretical yield * 100

Actual yield = Percent yield * theoretical yield/100

Actual yield = 90 * 44/100

Actual yield = 39.6 g

Answer:

A nucleic acid

Explanation: A nucleic acid is a polymeric macromolecule made up of repeated units of monomeric 'nucleotides' composed of a nitrogenous heterocyclic base which is either a purine or pyrimidine, a pentose five-carbon sugar either ribose or 2′-deoxyribose, and one to three phosphate groups.

The atomic ratio of carbon to oxygen in carbon monoxide (CO) is 1:1, and the atomic ratio of carbon to oxygen in carbon dioxide (CO₂) is 2:1.

Firstly, we can analyze the decomposition of carbon monoxide (CO) and carbon dioxide (CO₂) to determine the atomic ratios involved.

Let's denote the atomic ratio of carbon to oxygen in carbon monoxide as x, and the atomic ratio of carbon to oxygen in carbon dioxide as y.

According to the given data;

Decomposition of carbon monoxide (CO);

Oxygen produced = 3.36 g

Carbon produced = 2.52 g

We know that the atomic mass of carbon is 12 g/mol, and the atomic mass of oxygen is 16 g/mol. Using these values, we can calculate the number of moles for each element;

Number of moles of oxygen = mass / atomic mass = 3.36 g / 16 g/mol = 0.21 mol

Number of moles of carbon = mass / atomic mass = 2.52 g / 12 g/mol = 0.21 mol

Since the atomic ratio of carbon to oxygen in carbon monoxide is x, we can write the following equation;

0.21 mol C / (0.21 mol O) = x

Simplifying the equation, we have;

x = 1

Therefore, the atomic ratio of carbon to oxygen in carbon monoxide is 1:1.

Decomposition of carbon dioxide (CO₂);

Oxygen produced = 9.92 g

Carbon produced = 3.72 g

Following the same calculations as before;

Number of moles of oxygen = mass / atomic mass = 9.92 g / 16 g/mol = 0.62 mol

Number of moles of carbon = mass / atomic mass = 3.72 g / 12 g/mol = 0.31 mol

Since the atomic ratio of carbon to oxygen in carbon dioxide is y, we can write the following equation;

0.31 mol C / (0.62 mol O) = y

Simplifying the equation, we have;

y = 0.5

Therefore, the atomic ratio of carbon to oxygen in carbon dioxide is 1:0.5, which can be simplified to 2:1.

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--The given question is incomplete, the complete question is

"Missed this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your text. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon. Calculate the atomic ratio of carbon to oxygen in carbon monoxide, and carbon dioxide."--