Using MO theory, explain the difference between a conducting metal, a semiconductor, and an insulator. Drawing MO diagrams may help

Answers

Answer 1


In a conducting metal, the valence electrons are delocalized and can  The conduction band is partially filled with electrons, allowing them to move and conduct electricity. The valence band, which is formed by the lower energy atomic orbitals, is either completely filled or partially filled.

A semiconductor has a smaller energy gap between the valence band and the conduction band compared to an insulator. This smaller energy gap allows some electrons to move from the valence band to the conduction band when energy is supplied. In a semiconductor, the valence band is usually filled, while the conduction band is either empty or only partially filled.


In an insulator, the energy gap between the valence band and the conduction band is larger than that of a semiconductor. This large energy gap makes it difficult for electrons to move from the valence band to the conduction band, resulting in very limited conductivity.

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Related Questions

A model stands on a scale and finds her weight to be 105 pounds. If
the pressure exerted by her feet on the scale is 2.16 pounds per
square inch, what is the area of her feet in cubic centimeters?
__cm2

Answers

The area = 313.612 cm²

Further explanation

Force (F) can cause objects to move

While pressure (P)is the force per unit area

\(\tt P=\dfrac{F}{A}\)

weight=force=105 pounds(lb)⇒english units

pressure = 2.16 lb/in²

Thea are (A)

\(\tt A=\dfrac{F}{P}=\dfrac{105}{2.16}=48.61~in^2\\\\1~in^2=6,4516~cm^2\\\\48.61~in^2=313,612~cm^2\)

How do valence electrons affect ion formation?

Answers

Valence electrons affects ion formation by transferring from one atom to another atom.

Valence electrons are the outermost electrons in an atom and are involved in the formation of ions. Ions are atoms or molecules that have a net electric charge due to a surplus or deficiency of electrons. When an atom forms an ion, it either gains or loses electrons to achieve a more stable electron configuration. The number of valence electrons in an atom determines how easily it can gain or lose electrons to form ions. Atoms with few valence electrons, such as alkali metals, tend to lose those electrons easily to form positive ions. Atoms with many valence electrons, such as halogens, tend to gain electrons easily to form negative ions. The number of valence electrons also affects the charge of the ions that are formed. Atoms with fewer valence electrons will form ions with a higher charge, while atoms with more valence electrons will form ions with a lower charge.

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I'm giving the brainliest if it's correct thank you
An ammonia (NH3) sample occupies a volume of 6.00 L at TPN. Calculate its mass.

Answers

Answer:

Explanation:

Now, you know that this solution has a molarity of 6.00 M, which basically means that every liter, which is the equivalent of 1000 mL, will contain 6.00 moles of ammonia. Since we've picked a sample of 1000 mL, you can say that it will contain 6.00 moles of ammonia. To convert this to grams, use the compound's molar mass

A 23.7 g piece of iron at 54.9 C is cooled and releases 338 J of heat. The specific heat of iron is 0.450 J/gC. What is the final temperature of the iron?

Answers

Answer:

39

Explanation:

cux it is

Answer: 23.3 °C

Explanation: The one above is wrong

Determine the molar concentration of each ion present in the solutions that result from each of the following mixtures: (Disregard the concentration of H+ and OH from water and assume that volumes are additive:)
(a) 54.1 mL of 0.33 M NaCl and 76.0 mL of 1.33 M NaCl M Na M Cl" (b) 134 mL of 0.66 M HCI and 134 mL of 0.17 M HCI MhT M Cl- (c) 36.3 mL of 0.340 M Ba(NO3)2 and 25.5 mL of 0.211 M AgNO3 M Ba M Ag NO3 (d) 13.6 mL of 0.650 M NaCl and 22.0 mL of 0.131 M Ca(CzH302)2 M Na + M Cl- Ca2+ M CzH302

Answers

To determine the molar concentration of each ion present in the solutions, we need to calculate the total moles of each ion and divide it by the total volume of the resulting solution.

(a) Mixture: 54.1 mL of 0.33 M NaCl and 76.0 mL of 1.33 M NaCl

For NaCl, the number of moles (n) can be calculated using the formula:

n = M * V

n(NaCl) = 0.33 M * 54.1 mL + 1.33 M * 76.0 mL

Next, we need to determine the concentration of each ion. Since NaCl dissociates into Na+ and Cl- ions in solution, the molar concentration of each ion is the same as that of NaCl.

M(Na+) = M(Cl-) = n(NaCl) / (V1 + V2)

Where V1 and V2 are the volumes of the solutions used.

M(Na+) = M(Cl-) = n(NaCl) / (54.1 mL + 76.0 mL)

(b) Mixture: 134 mL of 0.66 M HCl and 134 mL of 0.17 M HCl

Similarly, we calculate the moles of HCl:

n(HCl) = 0.66 M * 134 mL + 0.17 M * 134 mL

The concentration of each ion is the same as that of HCl:

M(H+) = M(Cl-) = n(HCl) / (V1 + V2)

Where V1 and V2 are the volumes of the solutions used.

M(H+) = M(Cl-) = n(HCl) / (134 mL + 134 mL)

(c) Mixture: 36.3 mL of 0.340 M Ba(NO3)2 and 25.5 mL of 0.211 M AgNO3

For Ba(NO3)2, we calculate the moles:

n(Ba(NO3)2) = 0.340 M * 36.3 mL

For AgNO3, we calculate the moles:

n(AgNO3) = 0.211 M * 25.5 mL

The concentration of each ion is determined as follows:

M(Ba2+) = n(Ba(NO3)2) / (V1 + V2)

M(Ag+) = n(AgNO3) / (V1 + V2)

M(NO3-) = 2 * M(Ba2+) + M(Ag+)

Where V1 and V2 are the volumes of the solutions used.

M(Ba2+) = n(Ba(NO3)2) / (36.3 mL + 25.5 mL)

M(Ag+) = n(AgNO3) / (36.3 mL + 25.5 mL)

M(NO3-) = 2 * M(Ba2+) + M(Ag+)

(d) Mixture: 13.6 mL of 0.650 M NaCl and 22.0 mL of 0.131 M Ca(C2H3O2)2

For NaCl, we calculate the moles:

n(NaCl) = 0.650 M * 13.6 mL

For Ca(C2H3O2)2, we calculate the moles:

n(Ca(C2H3O2)2) = 0.131 M * 22.0 mL

The concentration of each ion is determined as follows:

M(Na+) = n(NaCl) / (V1 + V2)

M(Cl-) = n(NaCl)

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can you change the subscripts when balancing a chemical equation

Answers

No, the subscripts in a chemical formula cannot be changed when balancing a chemical equation.

The subscripts in a chemical formula represent the ratio of atoms or ions in a compound and are determined by the chemical composition of the substance. Changing the subscripts would alter the identity of the compound and its chemical properties.

When balancing a chemical equation, the coefficients in front of the chemical formulas are adjusted to ensure that the number of atoms of each element is equal on both sides of the equation. Coefficients represent the relative number of molecules or formula units involved in the reaction.

The process of balancing a chemical equation involves applying the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction. By adjusting the coefficients, the number of atoms of each element on the reactant side is made equal to the number of atoms on the product side.

It's important to note that while coefficients are changed to balance the equation, the subscripts remain the same. This is because the subscripts represent the specific arrangement and composition of atoms within a compound and cannot be altered without changing the substance being represented.

In summary, when balancing a chemical equation, the subscripts in the chemical formulas should not be changed. Only the coefficients are adjusted to ensure that the number of atoms of each element is balanced on both sides of the equation.

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I need helps plss!!!!

I need helps plss!!!!

Answers

Answer:

Copper = 2 Boron = 12 (copper and boron combined = 14)

Explanation:

the number after the element is the amount of atoms there is

5.50 ml of h2o and 3.00 ml of an aqueous 0.030 m i- solution were added to 12.75 ml of an aqueous 0.025 m fe3 solution. the total volume of the solution is 21.25 ml. what is the diluted fe3 concentration?

Answers

The total volume of the solution is the 21.25 ml. The diluted Fe³⁺ concentration is 0.0097 M.

The volume of  the water  = 5.50 mL

The molarity of the solution = 0.030 M

The volume = 3 mL

The moles = molarity × volume

The moles = 0.030 × 0.003

The moles = 0.00009

The concentration of solution  = moles / volume

The concentration of solution  = 0.00009 / 0.00550

The concentration of solution  = 0.0163 M

The final volume = 21.25 mL

The diluted Fe³⁺ concentration = ( 0.0163 × 12.75 ) / 21.25

The diluted Fe³⁺ concentration = 0.0097 M

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a sample of unknown material weighs 500 n in air and 200 n when immesersed in alcholol with a specfic gravity of 0.7 what is the mass density

Answers

Answer: The mass density is 1166.36 \(kg/m^{3}\).

Explanation:

Given: Weight of sample in air \((F_{air})\) = 500 N

Weight of sample in alcohol \((F_{alc})\) = 200 N

Specific gravity = 0.7 = \(0.7 \times 1000 = 700 kg/m^{3}\)

Formula used to calculate Buoyant force is as follows.

\(F_{B} = F_{air} - F_{alc}\\= 500 - 200 \\= 300 N\)

Hence, volume of the material is calculated as follows.

\(V = \frac{F_{B}}{\rho \times g}\)

where,

\(F_{B}\) = Buoyant force

\(\rho\) = specific gravity

g = acceleration due to gravity = 9.81

Substitute the values into above formula.

\(V = \frac{F_{B}}{\rho \times g}\\= \frac{300}{700 \times 9.81}\\= \frac{300}{6867}\\= 0.0437 m^{3}\)

Now, mass of the material is calculated as follows.

\(mass = \frac{F_{air}}{g}\\= \frac{500 N}{9.81}\\= 50.97 kg\)

Therefore, density of the material or mass density is as follows.

\(Density = \frac{mass}{volume}\\= \frac{50.97 kg}{0.0437 m^{3}}\\= 1166.36 kg/m^{3}\)

Thus, we can conclude that the mass density is 1166.36 \(kg/m^{3}\).

1.Peptide bond formation is accomplished as the amine nitrogen of the an-tRNA in the ____ carries out a _____ of the amino acid bound to the _____. a.A site, nucleophilic attack on the carbonyl carbon, tRNA of the P site b.P site, nucleophilic attack on the carbonyl carbon, tRNA of the A site c.A site, acidophilic attack on the carbonyl carbon, tRNA of the P site d.A site, electrophilic attack on the carbonyl carbon, tRNA of the P site e.P site, electrophilic attack on the carbonyl carbon, tRNA of the A site

Answers

Answer:

A

Explanation:

A site, nucleophilic attack on the carbonyl carbon, tRNA of the P site

In the cases where no electric current flowed, do compounds form atoms, molecules or lattices in solution?

Answers

Answer: 28

Explanation:a=d+a

In the cases where no electric current flowed, do compounds form atoms, molecules or lattices in solution?

Which of the following are examples of plasmas?

Answers

Answer:

i will tell some examples of plasmas they are:

1.lightning

2.solar wind

3.welding arcs

4.stars(including the sun)

5.the earths's ionosphere

Answer: which of the following are examples of plasmas?

Choices: 1. Ice cubes 2. Tails of comets 3. A gas fire 4. The ionosphere 5. A neon sign 6. A flashlight

Explanation:

The Answer: is 2. Tails of comets 4. The ionosphere 5. A neon sign

1. How many moles are in 4.5 x 1022 atoms of Cu?


2. How many moles are in 8.5 x 1024 molecules of Nz?


3. How many molecules are in 0.025 moles of CH4?


4. How many atoms are contained in 1.26 moles of Pb?


5. How many molecules are in 0.56 moles of CO2?

Answers

Answer:

Know this

(i) 1mole of a substance contains 6.022 x 10^23atoms

(ii) 1mole of a substance contains 6.022x10^23molecules

Now

1.) 4.5x10²²atoms of Cu x 1mole of Cu/6.022x10²³atoms of Cu

=0.075moles of Cu.

2.) 8.5x10²⁴molecules of N2 x 1mole of N2/6.022x10²³molecules

=14.11moles of N2

3.) 0.025moles of CH4 x 6.022x10²³molecules/1mole of CH4

=1.51x10²²molecules of CH4

4.)1.26moles of Pb x 6.022x10²³atoms/1mole of Pb

=7.59x10²³atoms of Pb

5.) 0.56moles of CO2 x 6.022x10²³molecules/1mole

=3.37x10²³molecules.

That's pretty Much Everything

Plz plz help
Which model shows 5 electrons in the outer shell of the atom?
A.2
B.3
C.4
D.1

Plz plz helpWhich model shows 5 electrons in the outer shell of the atom?A.2B.3C.4D.1

Answers

Answer:

D

Explanation:

there are 5 electrons in the outer shell of the first picture

According to electronic configuration, model 1 shows 5 electrons in the outer shell of the atom.

What is electronic configuration?

Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.

Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.

Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.

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A plane’s average speed between two cities is 600 km/hr. If the trip takes 2.5 hrs. how far does the plane fly?

Answers

Answer:

1500 km

Explanation:

its 600x2.5 devided by 1

In the Virtual ChemLab experiment called "Names and Formulas of Ionic Compounds," what color was each of the sulfide compounds?
a. yellow
b. white
c. black
d. pink

Answers

The correct answer to the question, "In the Virtual ChemLab experiment called 'Names and Formulas of Ionic Compounds,' what color was each of the sulfide compounds?" is option c. black.

What are sulfide compounds?

Sulfide compounds are a type of ionic compound that contains the element sulfur in its anionic form. These compounds are typically black in color, which is why option c is the correct answer.

It is important to note that different ionic compounds can have different colors, depending on the elements that they are composed of. For example, some ionic compounds may be yellow, white, or pink, as indicated by the other answer options. However, in the case of sulfide compounds, the correct answer is black.

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Boojho wants to separate the following materials as combustible and non-combustible. Can you help him?
Charcoal, chalk, stone, iron rod, copper coin, straw, cardboard, glass, paper, candle, wood​

Answers

Combustible: Charcoal, straw, cardboard, paper, candle, wood.

Non-combustible: Chalk, stone, iron rod, copper coin, glass.

1H nuclei located near electronegative atoms tend to be __________ relative to 1H nuclei which are not.

Answers

1H nuclei located near electronegative atoms tend to be de-shielded relative to 1H nuclei which are not.

Deshielding refers to the reduction in the electron density around a particular atom or group of atoms in a molecule or compound. It's a process that occurs when a group of atoms are exposed to a powerful electric or magnetic field. This results in a change in the chemical shifts of the nucleus. The nucleus shifts downfield, resulting in a signal that appears at a higher frequency. This process is also known as "decreasing shielding.

"Electronegativity is a measure of how much an atom attracts electrons to itself. A highly electronegative atom is one that is extremely effective at attracting electrons. The electronegative atom causes the electron density around the hydrogen atom to shift away, resulting in deshielding.

The more electronegative the atom, the more powerful the deshielding impact on the nearby 1H nuclei, which causes them to appear at a higher frequency. As a result, 1H nuclei located near electronegative atoms are de-shielded relative to 1H nuclei which are not.

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Answers

Answer:

lol good luck

Explanation:

u need it

Question 21 of 25
Which of the following are elements in this equation:
2Mg(s) + O2 (9) ► 2Mgo (s)?
Check all that apply.
A. g
B. Mg
C. O
D. S

Answers

Answer: Mg and O

Explanation: just took the test. Trust

Q36. Fluidisation A packed bed consisting of 1.96 kg of solids of density 2.8 g/cm' is contained in a cylindrical vessel of 10 cm internal diameter, and the bed height is 20 cm. (1) What is the volume of the vessel occupied by the bed is (mL)? (2) What is the volume of the solids in the vessel (mL)? (3) What is the porosity of the bed? (4) The particle size is 500 um, and the liquid density and viscosity are 1000 kg/m' and 0.001 Pa's, what is the minimum fluidising velocity (m/s)? (5) Was the use of the Kozeny-Carman equation justified? (6) What type of fluidisation likely to occur?

Answers

The volume of the vessel occupied by the bed is 1570 mL. The volume of the solids in the vessel is 700 mL. The porosity of the bed is approximately 0.554. The minimum fluidizing velocity is approximately 0.139 m/s.

1. Calculate the volume of the vessel occupied by the bed:

The internal diameter of the vessel is 10 cm, so the radius (r) is 5 cm = 0.05 m.

The height of the bed is 20 cm = 0.2 m.

The volume of the vessel occupied by the bed is the volume of the cylinder with radius r and height 0.2 m.

V = π * r^2 * h = π * (0.05 m)^2 * 0.2 m = 0.00157 m³ = 1570 cm³.

Therefore, the volume of the vessel occupied by the bed is 1570 mL.

2. Calculate the volume of the solids in the vessel:

The mass of the solids is given as 1.96 kg.

The density of the solids is given as 2.8 g/cm³.

To find the volume of the solids, we can use the formula:

Volume = Mass / Density = 1960 g / (2.8 g/cm³) = 700 cm³.

Therefore, the volume of the solids in the vessel is 700 mL.

3. Calculate the porosity of the bed:

Porosity (ε) is defined as the ratio of the void volume to the total volume of the bed.

The void volume is the volume of the vessel occupied by the bed minus the volume of the solids.

Void volume = Volume of the vessel occupied by the bed - Volume of the solids = 1570 mL - 700 mL = 870 mL.

Total volume of the bed = Volume of the vessel occupied by the bed = 1570 mL.

Porosity (ε) = Void volume / Total volume of the bed = 870 mL / 1570 mL ≈ 0.554.

Therefore, the porosity of the bed is approximately 0.554.

4. Calculate the minimum fluidizing velocity:

The minimum fluidizing velocity can be determined using the Ergun equation, which is based on the Kozeny-Carman equation.

The Kozeny-Carman equation relates the pressure drop across a packed bed to the fluid velocity and the bed properties.

The Ergun equation is a modification of the Kozeny-Carman equation for fluidized beds.

The formula for the minimum fluidizing velocity (Umf) in a fluidized bed is given by:

Umf = [150 * (1 - ε)² * (ρ * g * dp) / (ε³ * μ)]^(1/3),

where ε is the porosity, ρ is the density of the fluid, g is the acceleration due to gravity, dp is the particle diameter, and μ is the viscosity of the fluid.

Given:

ε = 0.554,

ρ = 1000 kg/m³ = 1 kg/dm³,

g = 9.8 m/s²,

dp = 500 μm = 0.5 mm = 0.0005 m,

μ = 0.001 Pa·s.

Substituting these values into the formula:

Umf = [150 * (1 - 0.554)² * (1 kg/dm³ * 9.8 m/s² * 0.0005 m) / (0.554³ * 0.001 Pa·s)]^(1/3)

≈ 0.139 m/s.

Therefore, the minimum fluidizing velocity is approximately 0.139 m/s.

5. Determine if the use of the Kozeny-Carman equation is justified:

The use of the Kozeny-Carman equation is justified in this case because it is commonly used to estimate the pressure drop and fluid flow properties in packed beds, including fluidized beds.

6. Determine the likely type of fluidization:

The type of fluidization that is likely to occur depends on the fluid velocity relative to the minimum fluidizing velocity (Umf).

If the fluid velocity is below Umf, the bed will be in a fixed or settled state.

If the fluid velocity is slightly above Umf, the bed will be in a bubbling or incipient fluidization state.

If the fluid velocity is significantly above Umf, the bed will be in a fully fluidized state.

Since the given fluid velocity is not provided, it is not possible to determine the exact type of fluidization likely to occur based on the information provided.

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I will give brainliest to whoever is first ❗️❕❗️❕❗️❕❗️
Which diagram best represents the reflection of the light from an irregular surface

I will give brainliest to whoever is first Which diagram best represents the reflection of the light

Answers

3rd Answer. Rays reflect in random directions
C.Light that bounces off a smooth surface bounces down and back up.

But, an irregular surface, for every bump, the light bounces down up down up down up.

In conclusion, C is the best answer.

I hope this helped! +*♡

A sample of milk is found to have arsenic at a concentration of 3.57 ug/L. What is the concentration in ounces per gallon? 1 qt 946.4 mL 1 gal 4 qt 16 oz- 1 lb 1 lb- 0.4536 kg A) 2.68 x 103 oz/gal B) 4.77 x 10-7 oz/gal C) 2.46 ozlgal D) 3.84 x 104 oz/gal E) 3.32 x 108 oz/gal

Answers

The concentration of arsenic in milk, which is 3.57 μg/L, can be converted to ounces per gallon. The correct answer is option D) 3.84 x 10^4 oz/gal.

To convert the concentration of arsenic from micrograms per liter (μg/L) to ounces per gallon (oz/gal), we need to follow a series of conversion steps. First, we need to convert micrograms (μg) to grams (g). There are 1,000 micrograms in a milligram (mg) and 1,000 milligrams in a gram, so 3.57 μg is equivalent to 0.00357 mg. Next, we need to convert milliliters (mL) to gallons (gal). Since 1 liter (L) is equal to 1,000 milliliters (mL) and 1 gallon is approximately 3,785.41 milliliters, we can calculate that 946.4 mL is approximately 0.25 gallons. Now, we can calculate the concentration in ounces per gallon. One pound (lb) is equal to 16 ounces (oz), and we know that 1 lb is approximately 0.4536 kg. Since 1 gallon is equal to 4 quarts (qt), and 1 quart is equal to 32 ounces, we can multiply all the conversion factors together:

0.00357 mg/L * 0.25 gal * 16 oz/lb * (1 lb/0.4536 kg) = 3.84 x 10^4 oz/gal

Therefore, the concentration of arsenic in ounces per gallon is approximately 3.84 x 10^4 oz/gal, which corresponds to option D).

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For the reaction 2 NOCl --> 2 NO + Cl2; the rate constant is 2.6 x 10-8 at 300.0 K and the activation energy is 164 kJ/mol. If the temperature is raised to 310K, what would be the ratio of k at 310 to k at 300 (to the nearest whole number) for this reaction? R = 8.314 J/ mol K

Answers

The ratio of k at 310 K to k at 300 K for the reaction 2 NOCl --> 2 NO + Cl2 is approximately 1 (to the nearest whole number).

To solve this problem, we can use the Arrhenius equation:
k = Ae^(-Ea/RT)

where k is the rate constant, A is the pre-exponential factor (or frequency factor), Ea is the activation energy, R is the gas constant (8.314 J/mol K), and T is the temperature in Kelvin.

We are given the rate constant (k) and activation energy (Ea) for the reaction 2 NOCl --> 2 NO + Cl2 at 300 K. We want to find the ratio of k at 310 K to k at 300 K.

To find the value of A for the reaction at 300 K:

\(k = Ae^(-Ea/RT)2.6 x 10^-8 = A e^(-164000/(8.314*300))A = (2.6 x 10^-8) / e^(-164000/(8.314*300))A = 1.28 x 10^12\)

Now, we can use the Arrhenius equation again to find the rate constant (k) at 310 K:

\(k = Ae^(-Ea/RT)k(310) = (1.28 x 10^12) e^(-164000/(8.314*310))k(310) = 3.29 x 10^-8\)

Finally, we can find the ratio of k at 310 K to k at 300 K:

\(k(310) / k(300) = (3.29 x 10^-8) / (2.6 x 10^-8)k(310) / k(300) = 1.26\)

Therefore, the ratio of k at 310 K to k at 300 K is approximately 1 (to the nearest whole number).

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the atoms of an element, x, has the electron configuaration below. what compound would element x most likely form with magnesium

Answers

MgX₃ has the same configuration as shown 1s2 2s2 2p6 3s2 3p6. So  the correct option is D.

The branch of science which deals with chemicals and bonds is called chemistry.

The representation of electrons in their shell is called electronic configuration. To find the element we have to count the electrons in it.

The total number of electrons is 2+2+6+2+6 = 18 which is argon a noble gas element.

The valency of the magnesium is 3, Hence the compound they will make is MgAr₃

Hence the correct option is D that is MgX₃.

Your question is incomplete most probably your full question was

1s2 2s2 2p6 3s2 3p6 Atoms of an element, X, have the electronic configuration shown above. The compound most likely formed with magnesium, Mg, is..... (a) MgX (b) Mg2X (c) MgX2 (d) MgX3 (e) Mg3X2

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Part B Change the distance of the electron from the center position as it moves up and down. What relationship do you notice between the distance from the center position and the amplitude of the wave?

Answers

Answer:

The movement of the electron changes the amplitude of the wave. The farther the electron moves from the center position, the greater the amplitude.

Explanation:

Answer:

The movement of the electron changes the amplitude of the wave. The farther the electron moves from the center position, the greater the amplitude.

Explanation:

Edmentum Sample Answer.

Radioactivity is the -------------- disintegration of an atomic nucleus that releases energy to become stable *

a. Extraordinary

b. Normal

c. Ordinary

d. Spontaneous​

Answers

Spontaneous, as it happens randomly

Answer:

The answer is spontaneous.

What happens to the surroundings during an endothermic reaction?

Answers

Answer: The surroundings will lower in temperature.

Explanation:

Endothermic reactions draw heat from the surroundings in order to occur. So the surroundings will feel cold, as the heat is being used as energy in the reaction.

6. A sealed flask filled with an ideal gas is moved from an ice bath into a hot water bath. The initial temperature is 273K and
the final temperature is 350 K. The initial pressure is 100kPa. The volume does not change. What is the final pressure of the flask? Name the gas law.

Answers

Answer:

Explanation:

Since the volume of the gas does not change, we can use the Gay-Lussac's law (also known as Pressure-Temperature law), which states that the pressure of an ideal gas is directly proportional to its absolute temperature when the volume is kept constant. Mathematically, this can be expressed as:

P1/T1 = P2/T2

where P1 and T1 are the initial pressure and temperature, respectively, and P2 and T2 are the final pressure and temperature, respectively.

Substituting the given values in the above equation, we get:

P2 = (P1/T1) × T2

   = (100 kPa/273 K) × 350 K

   = 128.83 kPa (approx.)

Therefore, the final pressure of the flask is approximately 128.83 kPa.

at what temperature (in k) would 0.0134650.013465 moles of ch4 in a container with a volume of 972.9972.9 ml have a pressure of 0.9220.922 atm?

Answers

At a temperature of 68.07 K, a container with a volume of 972.9 ml containing 0.013 moles of CH₄ would have a pressure of 0.922 atm.

To find the temperature in Kelvin (K) at which 0.013 moles of CH₄ in a container with a volume of 972.9 ml have a pressure of 0.922 atm, we can use the ideal gas law equation:

PV = nRT

Where:

P = Pressure (in atm)

V = Volume (in liters)

n = Number of moles

R = Ideal gas constant (0.0821 L·atm/(mol·K))

T = Temperature (in Kelvin)

First, we need to convert the volume from milliliters to liters:

V = 972.9 ml * (1 L / 1000 ml) = 0.9729 L

Now we can rearrange the ideal gas law equation to solve for temperature:

T = PV / (nR)

T = (0.922 atm) * (0.9729 L) / (0.013 moles * 0.0821 L·atm/(mol·K))

T = 68.07 K

Therefore, at a temperature of 68.07 K, the given amount of CH₄ in the specified container would have a pressure of 0.922 atm.

To know more about the CH₄ refer here :

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