Using the information in the table to the right, calculate the average atomic mass of strontium. Report to two decimal places.
A 3-column table with 4 rows titled Strontium. Column 1 is labeled Isotope with entries upper S 4 84, upper S r 86, upper S r 87, upper S r 88. Column 2 is labeled Mass in atomic mass units with entries 83.913428, 85.909273, 86.908902, 87.905625. Column 3 is labeled abundance with entries 0.56 percent, 9.86 percent, 7.00 percent, 82.58 percent.

According to the explanation given in a previous session, now we have the same type of question but in a different situation, we still can use the same formula and change what we are looking for now, let's set up the Dilution formula again:

M1V1 = M2V2

We have:

M1 = 0.87 M

V1 = 0.30 L

M2 = 0.30 M

V2 = ?

Now we add the values into the formula:

0.87 * 0.30 = 0.30 * V2

0.261 = 0.30V2

V2 = 0.87 L, this will be the new volume

The sample response is : how do mass and the type of material affect thermal energy transfer?

So one need to have include the below factors in your answer:

The mass of an object influences allure thermal strength transfer traits. Generally, objects accompanying best public have greater warm strength depository volume.

They can absorb more heat strength before experience a meaningful change in hotness. If an equal amount of heat is used to both objects, the object accompanying better mass will demand more heat strength to raise allure temperature distinguished to the object accompanying tinier mass .

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. In this experiment, you need to examine the idea of the thermal energy transfer. Using a controlled experiment, what might a good question about the variables that affect thermal energy transfer be? Thermal energy transfer depends on many properties, be limit your question to only two. What did you include in your question?

Answer: I, II, V

Explanation:

the IUPAC name of  4 tert butyl 3 chlorophenol will be given as

3-chloro-4-(1,1-dimethylethyl)phenol.

And the structure for the compound can be given as shown in figure.

IUPAC (International Union of Pure and Applied Chemistry), serves the international scientific endeavor in the dual function of a fundamental science and mission-oriented Union.

Naming according to IUPAC is based on naming a molecule's longest chain of carbons connected via single bonds forming alkane, whether in a continuous chain or in a ring.

All other deviations, either multiple bonds or atoms other than carbon and hydrogen, are indicated by prefixes or suffixes according to a specific set of priorities.

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Answer:

Explanation:

It can be written as: V = nRT/P. "P" is pressure, "V" is volume, n is the number of moles of a gas, "R" is the molar gas constant and "T" is temperature. Record the molar gas constant "R". R = 8.314472 J/mole x K.

Additional gold(III) chloride is added to the beaker. This would cause the concentration of the solution to increase. Therefore, the correct option is option A.

Concentration in chemistry refers to the quantity of a material in a certain area. The ratio of the solute within a solution to the solvent or whole solution is another way to define concentration. In order to express concentration, mass / unit volume is typically used.

The solute concentration can, however, alternatively be stated in moles or volumetric units. Concentration may be expressed as per unit mass rather than volume. Although concentration is typically used to describe chemical solutions, it may be computed for any mixture. Additional gold(III) chloride is added to the beaker. This would cause the concentration of the solution to increase.

Therefore, the correct option is option A.

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Answer:

Please find the solution in the attached file.

Explanation:

Structure A represents the arrangement of atoms in pure copper because  copper is a solid and only made of one type of atom.

The chemical element copper has the atomic number 29 and the symbol Cu. Copper, a transition metal, is a solid at ambient temperature.

Pure copper has a low hardness, is exceedingly ductile, and is malleable. For electrical applications, a number of reasonably pure Cu grades are produced, with small variances in deoxidation.

Solid copper is defined as a face-centered-cubic (fcc) arrangement of copper atoms.

Thus, structure A correctly represents the arrangement of atoms in pure copper.

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Answer:

\(\Delta S_{source}>-1.204\frac{kJ}{K}\)

Explanation:

Hello!

In this case, given the initial conditions, we first use the 10-% quality to compute the initial entropy:

\(s_1=s_{f,175kPa}+q*s_{fg,175kPa}\\\\s_1=1.4850\frac{kJ}{kg*K} +0.1*5.6865\frac{kJ}{kg*K}=2.0537\frac{kJ}{kg*K}\)

Now the entropy at the final state given the new 40-% quality:

\(s_2=s_{f,150kPa}+q*s_{fg,150kPa}\\\\s_2=1.4337\frac{kJ}{kg*K} +0.4*5.7894\frac{kJ}{kg*K}=3.7495\frac{kJ}{kg*K}\)

Next step is to compute the mass of steam given the specific volume of steam at 175 kPa and the 10% quality:

\(m_1=\frac{0.028m^3}{(0.001057+0.1*1.002643)\frac{m^3}{kg} } =0.274kg\\\\m_2=\frac{0.028m^3}{(0.001053+0.4*1.158347)\frac{m^3}{kg} } =0.0603kg\)

Then, we can write the entropy balance:

\(\Delta S_{source}+\frac{Q}{T_1} -\frac{Q}{T_2} +s_2m_2-s_1m_1-s_{fg}(m_2-m_1)>0\)

Whereas sfg stands for the entropy of the leaving steam to hold the pressure at 150 kPa and must be greater than 0; thus we plug in:

Which is such minimum entropy change of the heat-supplying source.

Best regards!

Answer:

(b) When 20.0 g of nitrogen and 32.0 g of oxygen are combined and allowed to react in two separate experiments, both times the product isolated from reaction contains 14.0 g of nitrogen and 32.0 g of oxygen.

Explanation:

The law of definite proportion states that a gen chemical compound always contains its constituent elements in a fixed ratio by mass, independent on the method of preparation.

The molar mass of Nitrogen and Oxygen would always remain the same, allowing for exact reactant masses (or mole ratio) irrespective of the given amount of sample.

Answer:

The waters' temp increased

Explanation:

The temperature of the water in the swimming pool has increased due to the heat from the Sun. As a result, the particles in the water are moving faster and have a higher kinetic energy than in the morning.

Answer:

6.2 × 10^-2

Explanation:

Given the reaction:

------------2N2O(g) N2H4(g) <---> 3N2(g) 2H2O(g)

Initial: N2O = 0.1, N2H4 = 0.25-- 0 - - - - - 0

Then: N20 = -2x, N2H4= - x - - - +3x, +2x

Equ : 0.1 - 2x ; 0.25 - x ; +3x ; +2x

At equilibrium :

Add both:

N2O = 0.1 - 2x ;

N2H4 = 0.25 - x;

3N2 = 3x

2H2O = 2x

Moles of N2O at equilibrium = 0.059

Then;

0.1 - 2x = 0.059

-2x = 0.059 - 0.1

-2x = - 0.041

x = 0.041 / 2

x = 0.0205

Moles of N2 present at equilibrium ;

3N2 = 3x

3N2 = 3(0.0205)

= 0.0615

= 0.062 = 6.2 × 10^-2

The branch of chemistry dealing with the physical changes associated with chemical reactions

Answer:

Physical chemistry is the part of chemistry that has to do with the physical structure of compounds, and how they react with other matters and bonds that hold atoms together.

Explanation:

Hope that helps.

Taking into account the definition of molarity, the number of moles of MgCl₂ present in 60.0 mL of 0.100 M MgCl₂ solution is 0.006 moles.

Molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by:

molarity= number of moles of solute÷ volume

Molarity is expressed in units moles/L.

In this case, you have:

Replacing in the definition of molarity:

0.100 M=number of moles of MgCl₂÷ 0.06 L

Solving:

0.100 M × 0.06 L= number of moles of MgCl₂

0.006 moles= number of moles of MgCl₂

Finally, the number of moles of MgCl₂ is 0.006 moles.

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1. The amount of water produced by the reaction is 0.359 g.

2. The amount of water produced by the reaction is 0.219 g.

To calculate the number of moles of acid neutralized by the tablet, subtract the number of moles of acid neutralized in the titration from the initial solution's moles of acid. Understand and explain standardization in the context of acidic and basic solutions used as reagents in experiments.

1. The neutralization reaction,

HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l)

we have to calculate the number of moles of HCl that react,

moles of HCl = volume of HCl x concentration of HCl

= 7.98 mL x 2.50 mol/L / 1000 mL/L

= 0.01995 mol

Since NaOH is in excess,

As a result, the amount of water produced will be equal to the amount of HCl that reacts:

moles of water = moles of HCl = 0.01995 mol

we can use the molar mass of water (18.015 g/mol)

mass of water = moles of water x molar mass of water

= 0.01995 mol x 18.015 g/mol

= 0.359 g

2. The neutralization reaction between H2SO4 and NaOH is:

H2SO4 (aq) + 2 NaOH (aq) → Na2SO4 (aq) + 2 H2O (l)

we have to calculate the number of moles of H2SO4 that react,

moles of H2SO4 = volume of H2SO4 x concentration of H2SO4

= 2.43 mL x 2.50 mol/L / 1000 mL/L

= 0.00608 mol

Now, we have to calculate the number of moles of NaOH that react:

moles of NaOH = volume of NaOH x concentration of NaOH

= 2.51 mL x 3.00 mol/L / 1000 mL/L

= 0.00753 mol

we need to use the stoichiometry of the balanced equation,

moles of water = moles of H2SO4 x (2 moles of water / 1 mole of H2SO4)

= 0.00608 mol x 2

= 0.01216 mol

we can use the molar mass of water (18.015 g/mol)

mass of water = moles of water x molar mass of water

= 0.01216 mol x 18.015 g/mol

= 0.219 g

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Answer:

7%

Explanation:

I'd you have $44.79 you put the decimal next to the first 4 so 10% would be $4 and 20% would be $8 so 18% will be like 7

Answer:

3.16mL of glacial acetic acid must be added

Explanation:

The mixture of acetic acid with sodium acetate produce a buffer. The buffer follows the H-H equation:

pH = pKa + log [A⁻] / [HA]

Where pH is the pH of the buffer: 5.0

pKa is pKa of the buffer = 4.74

[A⁻] could be taken as moles of acetate ion = 0.500L * (0.20mol/L) = 0.100mol

And [HA] are moles of acetic acid.

Replacing:

5.0 = 4.74 + log [0.100mol] / [HA]

0.26 = log [0.100mol] / [HA]

1.8197 = [0.100mol] / [HA]

[HA] = 0.100mol / 1.8197

[HA] = 0.05495 moles of acetic acid

As the glacial acetic acid is 17.4M, the volume we must add to prepare the buffer is:

0.05495 mol * (1L / 17.4mol) = 3.16x10⁻³L =

Explanation:

Observe the units of all of the prameters to solve this problem

m  *  (28.5-21.5)C  * .450 J/(gC)  = 67.5 J

m * 7 * .450 = 67.5

m = 67.5/(7 * .450) = 21.4 grams

Answer:

Potassium phosphide (K3P)

Answer:

The answer is "\(20 \ mL\)"

Explanation:

Given:

Molarity= number of moles

because it is 1 Liter

\(\to \frac{0.03\ moles}{1.5 moles}=0.02\ L= 20 \ mL \ of\ Tris\\\\\)

therefore,

it takes 20 mL of Tris.

\(\to \frac{0.150 \ moles}{5\ moles} =0.03\ L\\\\\)

                     \(= 30 \ mL \ of\ Nacl\)

So, take \(20 \ mL\ of\ NaCl.\)

Answer: Cells

Explanation:

Answer:

5 significant figures.

Explanation:

The decimal place makes the zeros significant.

Answer:

The wavelength of the wave in the diagram is 6 meters. This can be calculated by measuring the distance between points A and B and dividing it by the number of waves. In this case, there is one wave, so the wavelength is equal to the distance between points A and B, which is 6 meters.

The "alum" used in cooking is potassium aluminum sulfate hydrate, KAl(SO4)2·x H2O and the value of x calculated is 12.

Alum is a type of chemical compound, usually hydrated double sulfate salt of aluminum having general formula X Al ₂·12 H ₂O, where X is  monovalent cation such as potassium or ammonium.

Given mass of KAl(SO₄)₂.XH₂O = 4.74 g

and mass of water = 2.16 g

So, mass of KAl(SO₄)₂ = 4.74 – 2.16 = 2.58 g

Molar mass of KAl(SO₄)₂ ;

= 39 + 27 + 2[32 + (4×26)]

Now, molar mass of KAl(SO₄)₂ = 258 g/mol

Molar mass of H₂O ;

= (2×1) + 16

Now, molar mass of H₂O = 18 g/mol

Hence, KAl(SO₄)₂ = 2.58 / 258 = 0.01

and H₂O = 2.16 / 18 = 0.12

KAl(SO₄)₂ = 0.01 / 0.01 = 1

H₂O = 0.12 / 0.01 = 12

The formula of the compound is obtained as KAl(SO₄)₂.12H₂O

Comparing KAl(SO₄)₂.12H₂O with KAl(SO₄)₂.XH₂O,  value of X is 12.

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Answer:

Composition: All hydrocarbons are made up of only two types of atoms: carbon and hydrogen. They are like building blocks that contain carbon and hydrogen stuck together.

Organic Nature: Hydrocarbons are special because they are part of a group of compounds that come from living things or things that were once alive. They have carbon and hydrogen in them, which is what makes them different from other types of compounds.

Explanation:

The equation C2H4(g) + H2(g) + C2H6(g) → Caco3(s) + Cao(s) + CO2(g) shows an increase in entropy due to the formation of a gas as a product. Option A

In this equation, the reactants on the left-hand side consist of gases (C2H4 and H2), while the products on the right-hand side include a solid (Caco3) and a gas (CO2).

When a reaction involves a change from gaseous to solid or liquid states, there is typically a decrease in entropy because the particles become more ordered and constrained in the solid or liquid phase.

Conversely, when a reaction involves the formation of gases, there is generally an increase in entropy because gases have higher degrees of molecular motion and greater freedom of movement compared to solids or liquids.

In the given equation, the reactants include three gaseous compounds (C2H4, H2, and C2H6), and one of the products is a gas (CO2). Therefore, the overall entropy of the system increases during this reaction.

The equation Fe(s) + S(s) → FeS(s) does not show an increase in entropy. Both the reactants (Fe and S) and the product (FeS) are solids. Since solids have lower entropy compared to gases or liquids, the entropy of the system does not increase in this reaction. Option A

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The boiling point of water is 100.0 °C, the boiling point of the solution will be : 101.49 °C.The correct answer is option (a) 100.00049 °C.

Ideal Solution : An ideal solution is a homogeneous mixture of two or more components that obeys Raoult's law, which states that each component's vapor pressure is proportional to its mole fraction.The boiling point of a solution depends on the solvent's properties and the solute's concentration. It's dependent on the mole fraction of the solvent and solute, as well as the total concentration of the solution. The change in boiling point of a solution is given byΔTb = Kb × m × i, whereKb = ebullioscopic constant, m molarity of the solution, and i = van't Hoff factor.Assuming that the solution's behavior is ideal, we may use the molality of the solution to compute the boiling point elevation of the solution.The molality of the solution is given by the following formula:m = (n₂ / m₂) ÷ (n₁ / m₁), where n is the number of moles, m is the mass, and the subscripts 1 and 2 refer to water and non-volatile solute sucrose, respectively.The molar mass of sucrose (C₁₂H₂₂O₁₁) is342.3 g/mol; therefore, the number of moles of sucrose is115.0 g ÷ 342.3 g/mol = 0.335 mol.m₁ = mass of water = 350.0 g, and m₂ = mass of sucrose = 115.0 g, as given in the problem.Therefore, the molality of the solution is given by:m = (0.335 mol / 0.115 kg) ÷ (1 mol / 1 kg) = 2.91 mol/kg.Substituting these values in the formula for ΔTb, we get:ΔTb = Kb × m = 0.512 °C m⁻¹ × 2.91 mol/kg = 1.49 °C.100.0 °C + 1.49 °C = 101.49 °C.

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Answer:

4.90

Explanation:

10- 5.0