Using the provided table and the equation below, determine the heat of formation (in kJ/mol) for CuBr₂.
CuCl₂ (s) + Br₂(l) → CuBr₂ (s) + Cl₂ (g) ∆H° = 64.1 kJ/mol

CuCl2= -205.9 kJ/mol
Br2= 0 kJ/mol
Cl2= 0 kJ/mol

The molecule or ion that is being oxidized in the reaction is TeO2. Ceramics may occasionally be colored using tellurium dioxide.

TeO2 is soluble in strong acids, alkali metal hydroxides, and only very little water. Due to its amphoteric nature, it can operate as either an acid or a base depending on the solution it is in. It interacts with bases to form tellurites and acids to create tellurium salts.

Due to the presence of 6 e-pairs surrounding the center atom, 6 atoms bound to it, and 0 lone pairs, this molecule is octahedral.

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The complete question is:

A sample of ore containing the mineral tellurite, TeO2 , was dissolved in acid. The resulting solution was then

reacted with a solution of K2Cr2O7 to form telluric acid, H2TeO4 . The unbalanced chemical equation for the

reaction is given below.

. . . TeO2(s) + . . . Cr2O72−(aq) + . . . H+(aq) → . . . H2TeO4(aq) + . . . Cr3+(aq) + . . . H2O(l)

(a) Identify the molecule or ion that is being oxidized in the reaction.

Answer:

Scatter plot

Explanation:

Because the plot is scattered all over the place

Answer: NaCl

Explanation:

Table salt is made up of 1 atom of sodium (Na) and 1 atom of chlorine (Cl)

An unknown substance and it is green-blue in color, it is a solid, and is not malleable. The volume of this unknown sample if you have 14.5 grams is 2.75 × 10⁶ ml.

The properties of the substance is : green-blue in color, it is  solid, and is not malleable.

The formula for the density is given as :

The density = mass / volume

where,

The density = 5.621 g/m³ = 5.261 × 10⁻⁶ g/ml

The mass = 14.5 g

The volume is = mass / density

The volume = 14.5 / 5.261 × 10⁻⁶

The volume = 2.75 × 10⁶ ml

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Answer:true

Explanation:

The molecules in which the central atom has an expanded octet is BrF₃ ans SF₆.

Hypervalent compound is the compound in which central atom contains more than 8 electrons or expanded octet.  Hypovalent is the compound in which atom posses less than eighth electron in the valence shell. in  In  BrF₃ , Bromine has 7 valence electron and fluorine seven electrons . the three F atom complete their octet after the bonding with Br but In Br there are 10 electrons in valence shell . so,  BrF₃ has expanded octet. SF₆, the sulfur , sulfur has 6 valence electron and Fluorine has 7 valence electron F atom complete there octet with sulphur but S atom has 12 valence electrons that is expanded octet.

Thus, The molecules in which the central atom has an expanded octet is BrF₃ ans SF₆.

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The ionization energy will increase substantially when 11th electron is removed compared to when the 10th electron is removed.

Ionization energy is the energy required to remove one or more electrons from a neutral atom in its gaseous state to form a positively-charged ion.

The ionization energy increases steadily as successive electrons are removed from an atom. A substantial increase in ionization energy occurs with the removal of an electron from a filled inner shell.

The 10th electrons is the last electron in the L shell of atoms. The 11th electron is the first electron in a  filled inner shell.

Therefore, ionization energy will increase substantially when 11th electron is removed compared to when the 10th electron is removed.

Note that there was no attached graph and the answer was given based on the general trend observed in ionization energies.

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Answer:

B

Explanation:

Elements in a group are determined by the number of valence electrons

Elements in a period are determined by the number of electrons shell

The electronic configuration of the element is

2,8,8

the number of valence electron is 8 that means it is in Group 8/O

the number of electron shell is 3 that means it is in period (row) 3

Group 8/O elements are called Noble gases

Answer:

pH = 3.49

Explanation:

We have a buffer system formed by a weak acid (HNO₂) and its conjugate base (NO₂⁻ coming from KNO₂). We can calculate the pH  of a buffer ssytem using the Henderson-Hasselbach equation.

pH = pKa + log [base] / [acid]

pH = -log Ka + log [NO₂⁻] / [HNO₂]

pH = -log 4.50 × 10⁻⁴ + log 0.290 M / 0.210 M

pH = 3.49

The pH of the solution containing 0.210 M nitrous acid (HNO₂) and 0.290 M potassium nitrite (KNO₂) is 3.49

We'll begin by calculating the the pKa of acid. This can be obtained as follow:

Acid dissociation constant (Ka) = 4.50×10¯⁴

pKa = –Log Ka

pKa = –Log 4.50×10¯⁴

pKa = 3.35

Concentration of HNO₂, [HNO₂] = 0.210 M

Concentration of KNO₂, [KNO₂] = 0.290 M

The pH of the solution can obtain by using the Henderson-Hasselbach equation as illustrated below:

pH = pKa+ log [NO₂⁻] / [HNO₂]

pH = 3.35 + log (0.290 / 0.210)

Thus, the pH of the solution is 3.49

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Answer:

From 22.9 g of HF 0.575  moles of tin(II) fluoride are produced.

Explanation:

Given data:

Moles of tin(II) fluoride produced = ?

Mass of hydrogen fluoride react = 22.9 g

Solution:

Chemical equation:

SnO + 2HF    →    SnF₂ + H₂O

Number of moles of HF:

Number of moles = mass/ molar mass

Number of moles = 22.9 g/ 20 g/mol

Number of moles = 1.15 mol

Now we will compare the moles of SnF₂ with HF.

              HF           :             SnF₂

               2             :               1

            1.15            :             1/2×1.15 = 0.575 mol

Thus, from 22.9 g of HF 0.575  moles of tin(II) fluoride are produced.

Answer:

B. Chemically reactive

Explanation:

A Chemically reactive element is an element that is likely to combine with another element to form new substances

The reactivity of the element depends on the number of electrons in the outermost energy level and even the distance of the outermost energy level from the nucleus.  From the periodic table, Fluorine is the most reactive non-metal while francium is the most chemically reactive metal

To solve this problem, we can use the coefficients in the balanced chemical equation to determine the ratio of the amounts of each reactant and product. This will allow us to determine the amount of cesium fluoride needed to produce a given amount of cesium xenon heptafluoride.

In the given equation, we can see that for every 1 molecule of cesium fluoride, we get 1 molecule of cesium xenon heptafluoride. This means that the ratio of cesium fluoride to cesium xenon heptafluoride is 1:1.

We are given that we want to make 73.1 g of cesium xenon heptafluoride. Since the ratio of cesium fluoride to cesium xenon heptafluoride is 1:1, we can use the mass of cesium xenon heptafluoride to determine the mass of cesium fluoride needed. Specifically, we can set up the following equation:

CsF mass = CsXeF7 mass

Substituting the given values into this equation, we get:

CsF mass = 73.1 g

Solving this equation gives us a mass of 73.1 g of cesium fluoride.

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Acetic acid has a 4.76 pH value. In order to create a buffer with a pH of 5.20, it is necessary to have a ratio of 2.75 of acetic acid and acetate ions.

The amount of a substance's solute in a specific amount of solution is how concentrated it is. Molarity, or the number of moles of solute in one liter of solution, is a common unit of measurement for concentrations.

Since the Great Salt Lake has a high concentration of salt, there aren't many fish there. A high concentration of a material in a solution simply implies that there is a lot of it there in relation to the volume. It signifies you pay attention properly to state that you have high focus skills.

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Answer:

A. CODIS

Explanation:

The Combined DNA Index System (CODIS), administered by the FBI, maintains DNA profiles obtained through federal, state, and local DNA sample collection programs, and makes this information available to law enforcement agencies across the country for law enforcement identification purposes.

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\(\small\mathbb\red{physical \: properties \: of \: potassium}\)

1) potassium are soft silvery white metal with a Boling point of 63°C (145°F) and a boling point are 770°C (1,420°F)

2) It's density is 0.862 grams per cubic centimeter less than that of water (1.00 grams per cubic centimetrer that potassium metal float in water

\(\small\mathbb\green{physical \: properties \: of \: vanadium}\)

1) vanadium is a silvery white, ductile, metallic looking solid. they capable of the being drawn into a thin wires

2) It melting point Is about 1,900°C (3,500°F) and its boiling point is about 3,000°C (5,400°F). the density is 6.11 grams per cubic centimeter

\(\small\mathbb\orange{hope \: it's \: helpful \: to \: you}\)

Answer:

(a) The moles of CuSO₄ is 3.125 × 10⁻³ moles.

(b) The moles of Cu is 3.125 × 10⁻³ moles.

(c) The mass of Cu is 0.2 g.

Explanation:

Given:

Mass of CuSO₄ = 0.5 g

Molar mass of CuSO₄ = 160 g/mol

The given balanced chemical equation is:

\(2Al+3CuSO_4\rightarrow 3Cu+Al_2(SO_4)_3\)

Part (a):

Calculating the moles of CuSO₄.

\(\text{Moles of } CuSO_4=\frac{\text{Mass of }CuSO_4}{\text{Molar mass of }CuSO_4}\\\\\text{Moles of } CuSO_4=\frac{0.5g}{160g/mol}\\\\\text{Moles of } CuSO_4=3.125\times 10^{-3}mol\)

Thus, the moles of CuSO₄ is 3.125 × 10⁻³ moles.

Part (b):

Calculating the moles of Cu.

From the balanced chemical equation, we conclude that:

As, 3 moles of CuSO₄ reacts to give 3 moles of Cu

So, 3.125 × 10⁻³ moles of CuSO₄ reacts to give 3.125 × 10⁻³ moles of Cu

Thus, the moles of Cu is 3.125 × 10⁻³ moles.

Part (c):

Calculating the mass of Cu.

Mass of Cu = Moles of Cu × Molar mass of Cu

Molar mass of Cu = 64 g/mol

Mass of Cu = (3.125 × 10⁻³ mole) × (64 g/mol)

Mass of Cu = 0.2 g

Thus, the mass of Cu is 0.2 g.

Answer:

follow me and pm and I answer your question

If an equation includes 7(CrO₄)₂, the numbers of Cr's and O's atoms that are there are 14 and 56 respectively.

The number of atoms present in a chemical compound can be calculated by multiplying the subscript of the particular element by any coefficient.

According to this question, 7 moles of chromate with the chemical formula; (CrO₄)₂ is given. The number of oxygen and chromium atoms in this compound can be calculated as follows:

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The pressure in the cylinder must have been 919.5 kPa.

The pressure in the cylinder is calculated by applying general gas equation as follows;

P₁V₁/T₁ = P₂V₂/T₂

where;

P₂ = (P₁V₁T₂/T₁V₂)

The initial temperature of the cylinder = 12⁰C = 285 K

The final temperature of the cylinder = 21⁰C = 294 K

P₂ = (95.5 x 14 x 294/285 x 1.5)

P₂ = 919.5 kPa

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Answer:

H2SO4(acid), NaOH(base)

Explanation:

Answer:

Electron configuration is the structural arrangement notation of electrons in the shells or energy levels of an atom.

Explanation:

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The number of electrons on a neutral atom is equal to the number of protons in the atom's nucleus, hence the answer is protons. This is referred to as the Z atomic number.

Atoms are neutral, hence there are exactly as many protons as electrons in each atom. All hydrogen atoms contain one electron, which is located outside the nucleus.

The number of protons and electrons in an atom's stable state is always equal to the atomic number. for a steady atom

Protons are positively charged and electrons are negatively charged. The number of electrons and protons in a neutral atom are always equal. The quantity of protons is constant.

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Answer: Warm Water and powdered lemonade.

Explanation: Water is faster at dissolving something and powder takes a smaller effort to dissolve.

Answer:

C

Explanation:

Answer:

41.43 mL

Explanation:

First we calculate the mass of NaOH in the original solution:

Then we calculate the volume of the diluted solution, using the grams of NaOH (that remain the same throughout the dilution process):

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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