V = r2h what is the equation for h?

The completed sentence is as follows:

For √3.5:

It is to be noted that in the right angled triangle named OBD:

In right ΔOBD,

BD² = OD² – OB²  

= OC² – (OC – BC)²  this is because OD = OC

BD² = 2OC x BC – (BC)²  

= 2 x 2.25 x 1 – 1

= 3.5  => BD

= √3.5

For √9.4

Enumerate a line segment labelled AB = 9.4 units; then

Repeat the same steps that were given above.

BD² = 2OC x BC – (BC)²  

= 2 x 5.2 x 1 – 1

= 9.4

=> BD = √9.4

For √10.5

Enumerate a line segment AB = 10.5 units.

Repeat steps 2-6 above;

B²2 = 2OC x BC – (BC)²  

= 2 x 5.75 x 1 – 1

= 10.5

=> BD = √10.5

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Answer:

last option, x = -1

Step-by-step explanation:

\(x^{2} + 2x + 1 = 0\\x_{1} = \frac{-2 + \sqrt{2^{2} - 4(1)(1) } }{2(1)}\\x_{2} = \frac{-2 - \sqrt{2^{2} - 4(1)(1) } }{2(1)}\\x_{1} = \frac{-2 + \sqrt{0} }{2}\\x_{2} = \frac{-2 - \sqrt{0} }{2}\\x = \frac{-2}{2} \\x = -1\)

The value of x by using the Quadratic Formula is,

⇒ x = - 1

An algebraic equation with the second degree of the variable is called an Quadratic equation.

Given that;

Equation is,

⇒ x² + 2x + 1

Now, We can use the Quadratic Formula for x as;

⇒ x² + 2x + 1

⇒ x = - 2 ± √2² - 4×1×1 / 2

⇒ x = - 2 ± √4 - 4 / 2

⇒ x = - 2 / 2

⇒ x = - 1

Thus, The value of x by using the Quadratic Formula is,

⇒ x = - 1

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The number of times both services left the interchange together from 9am to 12 noon is 0.

Let's call the number of 15-minute intervals that have passed since 9 am "t".

So, the time that bus number 801 leaves the interchange after t intervals is 9am + 15t minutes.

Similarly, the time that bus number 802 leaves the interchange after t intervals is 9 am + 20t minutes.

For both services to leave the interchange at the same time, the number of 15-minute intervals that have passed since 9 am must be the same for both buses.

In other words, 15t must equal 20t.

Dividing both sides of this equation by 5, we get 3t = 4t.

This equation has no solution, which means that bus number 801 and bus number 802 never leave the interchange at the same time from 9am to 12 noon.

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From the computation done, it can be denoted that the total price that will be paid will be $12.90.

1 Krispy Kosmos at $2.89 = $2.89

2 Chewy Chocos at $3.19 each = 2 × $3.19 = $6.38

1 Gooey Globs at $2.99 = $2.99

Total = $2.89 + $6.38 + $2.99 = $12.26

We'll then add the sales tax of 5.2%, therefore, the total value will be:

= $12.26 + (5.2% × $12.26)

= $12.26 + $0.638

= $12.90

In conclusion, the correct option is $12.90.

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Answer:

C

Step-by-step explanation:

Edg 2022

The p-value statistic to test the claim that the average weight of all babies is greater than 7.5 lbs. is 7.293.

a) Data set : 9.2, 6.5, 4.3, 5.5, 7.2, 9.5, 11.2, 8.5, 5.2, 4.7, 11.0, 7.4, 8.2, 6.9, 4.1

mean of the data set = sum / frequency

mean = 7.293.

Standard deviation

=  √(871.96-797.98)/14

= 2.3001

Hence the point of estimate = 7.293

b) Using p-value> q(.80)

p> 1.282

And the sample average is just mean(x)

p>7.2933

So our margin of error is

e <- 1.282*(2.3001/sqrt(15))

e<0.7614

The lower and upper bounds are:

= mean(x) - e = 6.5319

= mean(x) + me = 8.0547

Hence the lower and upper bounds for the p-value will be 6.5319 and 8.0547 .

A statistical calculation known as a p-value is employed to assess the applicability of a hypothesis to the data. A p-value establishes the likelihood that the outcomes that were observed would occur if the null hypothesis were true. The found difference becomes statistically more significant as the p-value decreases.

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1. Average of the entire data set: 15.47 ounces

  Standard deviation of the entire data set: 1.51 ounces

2. American League:

  Average of drink sizes: 16.8 ounces

  Standard deviation of drink sizes: 2.26 ounces

1. Computing the average and standard deviation of the entire data set:

  Average = (14 + 18 + 20 + 16 + 16 + 12 + 14 + 16 + 14 + 16 + 16 + 16 + 14 + 32 + 16 + 20 + 12 + 16 + 20 + 12 + 16 + 16 + 24 + 16 + 16 + 14 + 14 + 12 + 14 + 20) / 30

          = 464 / 30

          ≈ 15.47 ounces

  Standard deviation = √[((14 - 15.47)² + (18 - 15.47)² + (20 - 15.47)² + ... + (14 - 15.47)²) / 30]

                    ≈ √(68.71 / 30)

                    ≈ √2.29

                    ≈ 1.51 ounces

2. Computing the average and standard deviation for the American League and the National League:

  American League:

  Average (AL) = (14 + 18 + 20 + 16 + 16 + 12 + 14 + 16 + 14 + 16 + 16 + 16 + 14 + 32 + 16) / 15

               = 252 / 15

               ≈ 16.8 ounces

  Standard deviation (AL) = √[((14 - 16.8)² + (18 - 16.8)² + (20 - 16.8)² + ... + (32 - 16.8)²) / 15]

                         ≈ √(76.8 / 15)

                         ≈ √5.12

                         ≈ 2.26 ounces

  National League:

  Average (NL) = (20 + 12 + 16 + 20 + 12 + 16 + 16 + 14 + 14 + 12 + 14 + 20) / 15

               = 200 / 15

               ≈ 13.33 ounces

  Standard deviation (NL) = √[((20 - 13.33)² + (12 - 13.33)² + (16 - 13.33)² + ... + (20 - 13.33)²) / 15]

                         ≈ √(40 / 15)

                         ≈ √2.67

                         ≈ 1.63 ounces

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Answer:

1/25

Step-by-step explanation:

Answer:

Step-by-step explanation: The absolute value of 58 is the distance between 58 and 0 on a number line. See illustration below where x is 58: Since the distance between 58 and 0 on a number line is 58, we get the answer as follows: |58| = 58. Note that the absolute value of 58 can also be written as abs (58) which may be useful to know if you have a good calculator.

The ordered pair of the inequality will be (9,-3).

The inequality expressions are the mathematical equations related by each other by using the signs of greater than or less than. All the variables and numbers can be used to make the equation of inequality.

Given that inequality is given as y ≤ 1/3x−6.

The ordered pair can be calculated as:-

y ≤ 1/3x−6

Substitute the value of x equal to 9 and get the value of y,

y ≤ 1/3(9) - 6

y ≤ 3 - 6

y ≤ -3

Hence, the ordered pair will be (9,-3).

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Answer:

8 has to be included in the data set. Since 8 is the mode, and the mode is the number that is seen the most in a set of numbers, 8 has to be in the data set for it to be the mode. Therefore, the answer is 8.

Answer:

domain [-1, ∞)

range [ -3, ∞)

Step-by-step explanation:

Brainliest?

Answer:

7a

Step-by-step explanation:

we know this, because there is no b in the second polynomial. Therefore, there cannot be a b in the answer. There is also no b^3 in the second polynomial, so there cannot be a ^3

The final solution of the given problem is X = 2.82, Y = 1.04 for an Optimal solution Value of -16.93.

Given the optimization problem in 2X2 – 14X + 2XY + Y2 – 18Y + 50s.t. X + 4Y ≤ 8, we have to find the minimum solution to the given problem.

Solution To find the solution to the given optimization problem, we need to use the Lagrange multiplier method. Using this method, we have the following system of equations: 2x - 14 + 2y = λ4y - λ = 0x + 4y ≤ 8Solving the above equations, we get the following solutions:x = 3, y = 1, λ = 6

The optimal solution is X = 3, Y = 1, for an optimal solution value of -17. If the right-hand side of the constraint is increased from 8 to 9, the objective function would change by -2.29. (Decrease by 2.29)Now, we have to resolve the problem with a new right-hand side of 9.

The new optimization problem will be in 2X2 – 14X + 2XY + Y2 – 18Y + 50s.t. X + 4Y ≤ 9

Using the same method as above, we have the following system of equations:2x - 14 + 2y = λ4y - λ = 0x + 4y ≤ 9Solving the above equations, we get the following solutions:x = 2.82, y = 1.04, λ = 6.07

The objective function value is -16.93 so the actual increase/decrease is only -0.07 rather than -2.29. Hence, the actual change is very different from the estimated change.

Therefore, the final solution of the given problem is X = 2.82, Y = 1.04 for an optimal solution value of -16.93.

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The equation of the function g(x) is g(x) = (x -4)/(x + 8)

The complete question is given as:

if g(x + h) = (x + h - 4)/(x + h + 8), determine the function g(x)

So, we have:

The function is given as:

g(x + h) = (x + h -4)/(x + h + 8)

To determine the function g(x), we simply substitute x + h for x in the equation g(x + h) = (x + h -4)/(x + h + 8)

So, we have

g(x) = (x -4)/(x + 8)

The above equation cannot be further simplified

Hence, the equation of the function g(x) is g(x) = (x -4)/(x + 8)

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Complete question

if g(x + h) = (x + h - 4)/(x + h + 8), determine the function g(x)

Answer:

The length of the banner is 24 inches and its width is 4 inches.

Step-by-step explanation:

Let the length of the banner be L.

Let the width of the banner be W.

The length is 6 times greater than the width. This means that:

L = 6W

The area of the banner is:

A = L * W = 6W * W = \(6W^2\)

The are of the banner is 96 square inches. This implies that:

\(6W^2\) = 96

=> \(W^2\) = 96 / 6 = 16

W = \(\sqrt{16}\)

W = 4 inches

The length, L, will be:

L = 6 * 4 = 24 inches

The length of the banner is 24 inches and its width is 4 inches.

The matrix of the relation r={(1,2),(2,3),(3,4),(4,5)} on the set x={1, 2, 3, 4, 5}; ordering of x:1,2,3,4,5 is as follows.

\($$\begin{pmatrix} 0 & 1 & 0 & 0 & 0 \\ 0 & 0 & 1 & 0 & 0 \\ 0 & 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 0 & 1 \\ 0 & 0 & 0 & 0 & 0 \end{pmatrix}$$\)

A relation is a set of ordered pairs.

The matrix of a relation is constructed by using its ordered pairs with their respective values as its entries, and its rows and columns by its domain and range, respectively.

So, the relation r is given as{(1,2),(2,3),(3,4),(4,5)}

The elements in the rows of the matrix correspond to the elements of x, while the elements in the columns of the matrix correspond to the elements of x as well, in that order.

So, the matrix of r on x can be written as:

\($$\begin{pmatrix} 0 & 1 & 0 & 0 & 0 \\ 0 & 0 & 1 & 0 & 0 \\ 0 & 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 0 & 1 \\ 0 & 0 & 0 & 0 & 0 \end{pmatrix}$$\)

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Answer:

speed

Step-by-step explanation:

speed is the right answer hope its right

Answer:

x = -1 y = 3 and z =2

Step-by-step explanation:

that is the solution above

The total distance from Nina's house to the school to the community center (20 units) is greater than the total distance from Nina's house to the school to the grocery store (18 units).

Part a: To calculate the distance in units from Nina's house to her school using absolute values, we need the coordinates of both locations. Let's assume Nina's house is located at point A (x1, y1) and her school is located at point B (x2, y2). The distance between these two points can be calculated using the distance formula:

Distance = |x2 - x1| + |y2 - y1|

Let's say Nina's house is at coordinates (3, 5) and her school is at coordinates (-2, -1). Plugging these values into the formula:

Distance = |(-2) - 3| + |(-1) - 5|

        = |-5| + |-6|

        = 5 + 6

        = 11 units

Therefore, the distance from Nina's house to her school is 11 units.

Part b: To determine whether the total distance from Nina's house to the school to the grocery store is greater than the total distance from Nina's house to the school to the community center, we need the distances between these locations. Let's assume Nina's house is point A, her school is point B, the grocery store is point C, and the community center is point D.

Let's say the distance from Nina's house to the school is 11 units, the distance from the school to the grocery store is 7 units, and the distance from the school to the community center is 9 units.

Total distance from Nina's house to the school to the grocery store = 11 + 7 = 18 units

Total distance from Nina's house to the school to the community center = 11 + 9 = 20 units

Therefore, the total distance from Nina's house to the school to the community center (20 units) is greater than the total distance from Nina's house to the school to the grocery store (18 units).

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The surface with the given vector equation, r(s, t) = (s cos(t), s sin(t), s), is a circular cone.

The vector equation r(s, t) = (s cos(t), s sin(t), s) represents a surface in three-dimensional space. Let's analyze the equation to determine the nature of the surface.

In the equation, we have three components: s, cos(t), and sin(t). The presence of s indicates that the surface expands or contracts radially from a central point. The trigonometric functions cos(t) and sin(t) determine the angle at which the surface extends in the x and y directions.

By observing the equation closely, we can see that as s increases, the radius of the surface expands uniformly in all directions, while the height remains constant. This behavior is characteristic of a circular cone. The circular base of the cone is defined by s cos(t) and s sin(t), and the vertical component is determined by s.

Therefore, the surface described by the vector equation r(s, t) = (s cos(t), s sin(t), s) is a circular cone.

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Based on time conversion, the age of a teacher who is 50 years old in seconds is 1577880000 seconds.

The age of the teacher in years is converted to seconds as follows:

Thus:

50 years to seconds will be:

50 × 365.25 × 24 × 60 × 60 = 1577880000 seconds.

Therefore, the age of a teacher who is 50 years old in seconds is 1577880000 seconds.

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The total distance travelled by the boat is 12 miles

Distance 1 = 8 mph × 3/4 h

= (8 × 3) / 4

= 24/3

= 8 miles

Distance 2 = 12 mph × 1/3 h

= (12 × 1) / 3

= 12/3

= 4 miles

Total distance = Distance 1 + Distance 2

= 8 miles + 4 miles

= 12 miles

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The answer is b.) -2

Answer:

slope would be -2

Step-by-step explanation:

slope formula

\( \frac{ {y}^{2} - {y}^{1} }{ {x}^{2} - {x}^{1} } \)

We know: (1, 9) and (4, 3)

plug in the numbers

\( \frac{9 - 3}{1 - 4} \)

subtract

\( \frac{6}{ - 3} \)

divide

\( - 2\)

Tadaaaa

To prove that triangles ABC and ADC are tangent, use tangents and properties of tangential quadrilaterals. ABCD is tangential, so there is a circle tangent to all four sides. Triangles ABC and ADC share a common tangent line, with points P, A, and Q lying on a circle with diameter AB.

To prove that the circles inscribed in triangles ABC and ADC are tangent to each other, we can use the concept of tangents and properties of tangential quadrilaterals.

Given that ABCD is tangential, it means that there exists a circle that is tangent to all four sides of the quadrilateral ABCD. Let's call this circle O.

Now, let's focus on triangles ABC and ADC. The circles inscribed in these triangles are tangent to their respective sides. Let's call the circle inscribed in triangle ABC as O1, and the circle inscribed in triangle ADC as O2.

To prove that O1 and O2 are tangent to each other, we can show that they share a common tangent line.

1. Firstly, note that the common side AD is shared by both triangles. This means that the circle O1 is tangent to AD at a point, let's call it P. Similarly, circle O2 is also tangent to AD at a point, let's call it Q.

2. Next, consider the angles ∠APB and ∠AQB. Since circle O1 is inscribed in triangle ABC, the angle ∠APB is a right angle. Similarly, since circle O2 is inscribed in triangle ADC, the angle ∠AQB is also a right angle.

3. Now, since both ∠APB and ∠AQB are right angles, it means that points P, A, B, and Q all lie on a circle with diameter AB. Let's call this circle X.

4. Now, let's consider the line passing through the points P, A, and Q. Since P and Q lie on the same side of line AB, it means that this line intersects circle X at two distinct points, which are A and P.

5. Therefore, the line passing through points P, A, and Q is the common tangent to circles O1 and O2.

Hence, we have proved that the circles inscribed in triangles ABC and ADC are tangent to each other.

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Answer:

602.9 cm²

Step-by-step explanation:

==>Given:

A hemisphere with radius of 8cm

π = 3.14

==>Required:

Total surface area of hemisphere

==>Solution:

The total surface area of the hemisphere (TSA) = Curved surface area of hemisphere (CSA)+ base area (BA)

If surface area of a sphere is given as 4πr², therefore, the area of a hemisphere would be ½ of 4πr² = 2πr²

CSA = 2πr²

Base area (BA) = area of circle = πr²

Thus, TSA = 2πr2 + πr2 = 3πr2

TSA of hemisphere = 3 × 3.14 × 8²

TSA = 3 × 3.14 × 64

TSA = 602.88

TSA of hemisphere = 602.9 cm² (approximated to 1 decimal place)

Answer:

a= 1 b= 0.0625 c= 0.0039 d= 1 e=0.4444 f= 0.1975

Step-by-step explanation:

Plug the x into the equation

Answer: 0.15

Step-by-step explanation:

The sample proportion is 0.15 for an 80% confidence interval option (B) is correct.

It is defined as the sampling distribution following an approximately normal distribution for known standard deviation.

We have an 80% confidence interval for a proportion.

Proportions are 0.12, 0.18

Since for the given sample, the confidence interval is symmetric to the mean value.

Mean of the 0.12 and 0.18

\(=\rm \frac{0.12+0.18}{2}\)

\(=\rm \frac{0.30}{2}\)

= 0.15

Thus, the sample proportion is 0.15 for an 80% confidence interval.

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Using the information provided in the table, The total holding cost is  $547.50, the total setup cost is $600 and the total cost is  $1,147.50.

To develop a POQ (Periodic Order Quantity) solution use a lot-for-lot solution, which means that we will order exactly what we need for each period.

The missing values can be found on the attached table.

From the table, the total holding cost which is the sum of the holding costs for all periods is $547.50 while the total setup cost which is the sum of the setup costs for all periods is $600.

Therefore, the total cost is the sum of the holding cost and the setup cost and it is calculated as $1,147.50.

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Answer:

Well, for (D), the answer would be 32.

Step-by-step explanation:

Because, 20 +12 =32. And 32 - 12 = 20. With the other ones that add, its the same way. You can just for example, if its -5 + b = -40, you can just go 5 - 40= which equals 35. Which should give you 40 if you add 35 and 5 together.