W-2 The diameter of a circle is 4 units.
What is the radius of the circle?



I don't understand but it's due today help

Multiple regression refers to a statistical technique that uses several explanatory variables to predict the outcome of a response variable. In this case, we will write the multiple regression model.

Multiple regression model for dependent variable Y that is related to the independent variables X₁ and the qualitative variable can be represented as;Y= β0 + β1X₁ + β2Qualitative Variable + Ɛwhere, β0 = intercept coefficientβ1 = slope coefficient for X₁β2 = slope coefficient for Qualitative VariableƐ = error terma) For category A, we have Qualitative Variable = 1.

Substituting in the model we get;Y= β0 + β1X₁ + β2(1) + ƐY = β0 + β1X₁ + β2For category A, the expected (mean) value of Y = β0 + β1X₁ + β2b) For category B, we have Qualitative Variable = 2. Substituting in the model we get;Y= β0 + β1X₁ + β2(2) + ƐY = β0 + β1X₁ + 2β2For category B, the expected (mean) value of Y = β0 + β1X₁ + 2β2c) For category C, we have Qualitative Variable = 3. Substituting in the model we get;Y= β0 + β1X₁ + β2(3) + ƐY = β0 + β1X₁ + 3β2For category C, the expected (mean) value of Y = β0 + β1X₁ + 3β2d) The differential intercept coefficient of Category B can be obtained as follows; β0 + 2β2 - β0 = 2β2

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11 is the distance between given two numbers.

To find the distance between 7 and -4,

we need to find the absolute value of the difference between them:

|7 - (-4)| = |7 + 4| = |11| = 11

Therefore, the distance between 7 and -4 is 11.

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Answer:

9,835

Step-by-step explanation:

The given statement exists true. A matrix is broken down into orthogonal (Q) and upper triangular (R) matrices in a process known as QR decomposition (factorization).

A matrix can be expressed as the union of two distinct matrices, Q and R, using the QR matrix decomposition. R is a square upper/right triangular matrix and Q is an orthogonal matrix. R is also invertible because it is square and doesn't have zeros in its diagonal entries.

A matrix is broken down into orthogonal (Q) and upper triangular (R) matrices in a process known as QR decomposition (factorization). Finding eigenvalues and solving linear least squares problems both use QR factorization.

A = QR. Be aware that the QR-factorization of a rectangular matrix A is sometimes understood with Q square and R rectangular rather than Q rectangular and R square, as with the MATLAB command qr.

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Answer:

Step-by-step explanation:

So this is a cylinder

R= 8.75in

h=43.12in

So it will be = 3.14x8.75²x43.12

=> 3.14x76.5625x43.12

3.14x 3301.375

i think it is correct

.

stay safe

.

have a nice TIME

Answer:

Step-by-step explanation:

You want to know the amount borrowed at 10%, 12%, and 14% if the total borrowed was $21000, the total interest was $2580, and the total of amounts borrowed at 10% and 14% was double the amount borrowed at 12%.

The relations give rise to three equations. If we let x, y, z represent the respective amounts borrowed at 10%, 12%, and 14%, we have ...

  x + y + z = 21000 . . . . . . total borrowed

  0.10x +0.12y +0.14z = 2580 . . . . . . total interest

  x + y = 2z . . . . . . . . . . . relationship between amounts

Writing the last equation as ...

  x -2y +z = 0

we can formulate the problem as a matrix equation and use a solver to find the solution. We have done that in the attachment. It tells us the amounts borrowed are ...

__

Additional comment

Recognizing that the amount at 12% is 1/3 of the total, we can use that fact to rewrite the other two equations. The interest on the $7000 at 12% is $840, so we have ...

These two equations have the solution shown above. (It is usually convenient to solve them by substituting for x in the second equation.)

<95141404393>

Answer:

25$ Each month

Step-by-step explanation:

Half of 1300$ is 650$  so add the 500$ and then subtract is from 1300$ you get 150$ needed, so across 6 months he needs to raise 25$

Batting common is the the wide variety of runs scored via way of means of the batsman withinside the wide variety of fits performed via way of means of him in that supply weeks Walk to strike out is the wide variety of wickets taken via way of means of the sports activities character withinside the wide variety of fits performed via way of means of him in that week Home runs are the house run hit via way of means of that participant in that 5 weeks throughout which the sports activities creator cited these types of happenings

The number of hits A got is 186 hits.

​A player's batting average is calculated by dividing the number of hits by the number of at-bats.

Player A batting average =  0.312

Number of at-bats A did =  596

We have to find the number of hits A got.

0.312 = Number of hits / 596

Number of hits = 0.312 x 596

                        = 185.952 hits.

Rounding to a whole number we get,

= 186 hits

Thus, the number of hits A got is 186 hits.

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QUËSTIONS:- find the slope of the line represented by the data

ANSWER:-

\(SLOPE = \frac{y2 -y1}{x2 - x1} \\ SLOPE = \frac{3 - 9}{4 - 2} \)

\(SLOPE = \frac{ - 6}{2} \\ SLOPE = - 3 \: \: ans\)

Answer:

-3

Step-by-step explanation:

Slope(m)=-6/2

=-3/1

=-3

Hope this helps!

Answer:

Option B is the best way to write the underlined parts of sentences 2 and 3.

Sentence 2: They have a special finish that helps.

Sentence 3: The finish helps the swimmer glide through the water.

Option B provides a clear and concise way to connect the two sentences and convey the idea that the special finish of the swimsuits helps the swimmer glide through the water. It avoids any ambiguity or redundancy in the language.

i) The dispersion relation for the given equation is ± (v / 6) * k.

ii) The group velocity for the given equation is ± v / 6.

iii) The phase velocity is ± v / 6.

To find the dispersion relation, as well as the group and phase velocities for the given equation, let's start by rewriting the equation in a standard form:

82y(x, t) - 8\(t^2\) + 84y(x,t) = -2 * 8\(x^4\)

Simplifying the equation further:

8(2y(x, t) - \(t^2\) + 4y(x,t)) = -16\(x^4\)

Dividing both sides by 8:

2y(x, t) - \(t^2\) + 4y(x,t) = -2\(x^4\)

Rearranging the terms:

6y(x, t) = \(t^2\) - 2\(x^4\)

Now, we can identify the coefficients of the equation:

Coefficient of y(x, t): 6

Coefficient of \(t^2\): 1

Coefficient of \(x^4\): -2

(i) Dispersion Relation:

The dispersion relation relates the angular frequency (ω) to the wave number (k). To determine the dispersion relation, we need to find ω as a function of k.

The equation given is in the form:

6y(x, t) = \(t^2\) - 2\(x^4\)

Comparing this with the general wave equation:

A * y(x, t) = B * \(t^2\) - C * \(x^4\)

We can see that A = 6, B = 1, and C = 2.

Using the relation between angular frequency and wave number for a linear wave equation:

\(w^2\) = \(v^2\) * \(k^2\)

where ω is the angular frequency, v is the phase velocity, and k is the wave number.

In our case, since there is no coefficient multiplying the y(x, t) term, we can set A = 1.

\(w^2\) = (\(v^2\) / \(A^2\)) * \(k^2\)

Substituting the values, we get:

\(w^2\) = (\(v^2\) / 36) * \(k^2\)

Therefore, the dispersion relation for the given equation is:

ω = ± (v / 6) * k

(ii) Group Velocity:

The group velocity (\(v_g\)) represents the velocity at which the overall shape or envelope of the wave propagates. It can be determined by differentiating the dispersion relation with respect to k:

\(v_g\) = dω / dk

Differentiating ω = ± (v / 6) * k with respect to k, we get:

\(v_g\) = ± v / 6

So, the group velocity for the given equation is:

\(v_g\) = ± v / 6

(iii) Phase Velocity:

The phase velocity (\(v_p\)) represents the velocity at which the individual wave crests or troughs propagate. It can be calculated by dividing the angular frequency by the wave number:

\(v_p\) = ω / k

For our equation, substituting the dispersion relation ω = ± (v / 6) * k, we have:

\(v_p\) = (± (v / 6) * k) / k

\(v_p\) = ± v / 6

Therefore, the phase velocity for the given equation is:

\(v_p\) = ± v / 6

To summarize:

(i) The dispersion relation is ω = ± (v / 6) * k.

(ii) The group velocity is \(v_g\) = ± v / 6.

(iii) The phase velocity is \(v_p\) = ± v / 6.

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Answer:

Step-by-step explanation:

The probability that a family with 4 children has no more than 3 boys is 15/16.

To find the probability that a family with 4 children has no more than 3 boys, we can use the binomial distribution.

The binomial distribution is used to calculate the probability of obtaining a certain number of successes (boys in this case) in a fixed number of trials (children in this case), where each trial has only two possible outcomes (boy or girl) and the trials are independent.

Let X be the number of boys in the family. We want to find P(X ≤ 3), which is the probability of having no more than 3 boys. Since the probability of having a boy is 1/2 and the trials are independent, we can use the binomial distribution formula:

P(X ≤ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

= (1/2)⁴ + 4(1/2)⁴ + 6(1/2)⁴ + 4(1/2)⁴

= 15/16

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Therefore, the answer is closest to option C: Experimental: 40%; theoretical: 37.5.

Probability is a measure of the likelihood of an event occurring. It is expressed as a number between 0 and 1, with 0 indicating that the event is impossible and 1 indicating that the event is certain to occur.

by the question.

Based on the table provided, the spinner landed on the red portion 8 times out of 20 spins.

To calculate the experimental probability of landing on a red portion, we can use the formula:

Experimental probability = (Number of times the event occurred) / (Total number of trials)

Experimental probability of landing on a red portion = 8/20 = 0.4 = 40%

To calculate the theoretical probability of landing on a red portion, we need to know the total number of red portions on the spinner and the total number of portions on the spinner.

From the table, we can see that there are 8 red portions out of a total of 21 portions on the spinner. Therefore, the theoretical probability of landing on a red portion can be calculated as:Theoretical probability of landing on a red portion = (Number of red portions) / (Total number of portions)

Theoretical probability of landing on a red portion = 8/21 ≈ 0.381 = 38.1% (rounded to one decimal place)

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(a) Example question: "How often do you look at social media while doing schoolwork?

(b) Sofie can select a simple random sample of students by using a random number generator to assign a unique identification number to each student in the online high school.

(c) The sample for Sofie's research is the 32 completed surveys she received. These surveys represent the responses of a subset of the population. The population, in this case, refers to all the students at the online high school.

(d) If Sofie uses only the completed surveys, she can conclude that approximately 50% (16 out of 32) of the students who completed the survey reported using social media while doing schoolwork.

(a) Please select one of the following options: never, rarely, occasionally, frequently, or always."

(b) She can then use the random number generator again to select a specific number of students from the entire population of students, ensuring that each student has an equal chance of being selected. For example, if there are 500 students in total and Sofie wants a sample size of 50, she can generate 50 random numbers and select the corresponding students based on their identification numbers.

(d) However, it is important to note that this conclusion is specific to the sample of completed surveys and cannot be generalized to the entire population of high school students.

To make an inference about the percent of all high school students who use social media while doing schoolwork, Sofie would need a larger and more representative sample that covers a wider range of students in the online high school.

Additionally, she should consider potential biases in the sample, such as non-response bias if the students who chose not to complete the survey have different social media usage patterns compared to those who did respond.

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Frequency tables are used to represent datasets and their frequencies

The average number of miles he drove per month is 1358.3 miles

From the frequency table, the total number of miles travelled in a year is:

Total = 16300 miles

There are 12 months in a year.

So, the average number of miles is:

\(Average = \frac{16300}{12}\)

Divide

\(Average = 1358.3\)

Hence, the average number of miles he drove per month is 1358.3 miles

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A provision that ensures performance fees are not earned until the value of a fund exceeds its previous highest level is referred to as High-water mark

A high-water mark is the highest peak in value that an investment fund or account has reached. This term is often used in the context of fund manager compensation, which is performance-based.

The high-water mark ensures the manager does not get paid large sums for poor performance. If the manager loses money over a period, he must get the fund above the high-water mark before receiving a performance bonus

With a high-water mark, the investor pays a fee that only covers the amount the fund earned between the point of entry and its highest level.

The high-water mark prevents this "double fee" from occurring.

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(L2) An inscribed circle is one that encompasses a polygon so that it passes by each of the polygon's vertices.

A circumcircle, not an inscribed circle, is a circle that encircles a polygon at each vertex. A circle that is enclosed within a polygon and intersects each side of the polygon exactly once is said to be inscribed. A circumcircle, on the other hand, is a circle that goes through every vertex of the polygon, with its center located at the point where the perpendicular bisectors of the polygon's sides converge. The greatest circle that can be drawn within a polygon is the circumcircle, while the largest circle that can be drawn inside a triangle is the inscribed circle.

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To divide the pizzas equally among 9 people, each person will get 3 slices of pizza, and there will be 3 leftover slices. This should be enough pizza to satisfy everyone at the teacher's pizza party!

To solve this problem, we need to first find out how many total slices of pizza we have. Since we have 3 pizzas and each pizza has 8 slices, we have a total of 24 slices of pizza.
Next, we need to figure out how many people will be sharing the pizzas. The teacher has 8 friends over, so there will be a total of 9 people (including the teacher) sharing the pizzas.
To divide the pizzas equally among the 9 people, we need to divide the total number of slices (24) by the number of people (9). Using division, we can see that each person will get about 2.67 slices of pizza.
However, since we cannot cut a pizza into thirds, we need to round this number to the nearest whole or half slice. In this case, we can round up to 3 slices of pizza per person. This means that each person will get 3 slices of pizza, and there will be 3 leftover slices.

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Answer:

if you are required to find the equation of a straight line use the formula y-y1= m (x-x1)

y+2=-3(x-1)

y+2=-3x+3

y= -3x+3-2

y -3x+1

hope this helps

Answer:

y = -3x + 1

Step-by-step explanation:

(y -(-2)) = -3(x-1)

y+ 2 = -3x+ 3

y = -3x + 1

The correct hypothesis statement for this golfer to prove his claim would be:

\(H_{0} :u\geq 90\)

\(H_{1} :u < 90\)

The golfer claims that his average score is less than 90.

Therefore, the null hypothesis is the opposite of what he claims

Null hypothesis \(H_{0}\) is average score \(u\) is greater than or equal to 90:

\(u \geq 90\)

\(H_{0} :u\geq 90\)

Alternative hypothesis \(H_{1}\) is then the opposite of null hypothesis.

Hence alternate hypothesis \(H_{1}\) is u< 90

\(H_{1} :u < 90\)

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Answer:

12 gallons/hour or 1 gallon/5 minutes (1/12 gallon)

Step-by-step explanation:

assuming gravity can capilary action can be ignored amd has nothing to do with it, 20 minutes is 4 gallons of water gone, so 5 minutes for 1 gallon of water gone. 60 minutes in an hour, so 12 gallons per 60 minutes

Answer:

52

Step-by-step explanation:

Answer:

Step-by-step explanation:

3 / 4 = 39 / x

4*39 = 3*x

x = 42

Answer:

x-intercept (3 ,0)

y-intercept ( 0, –4)

12x-9y=36 —> 12x-9(0)=36 —> 12x=36

x=36/12 —> x=3 —> So (x,y)=(3,0)

12(0)-9y=36 —> -9y=36 —> y=36/-9

y= –4 —> So (x,y) =(0,–4)

I hope I helped you ^_^

When interpreting the expression as \((tanx)^{(sinx)\), the limit using L'Hospital's Rule is -∞ as x approaches 0+. However, when interpreting the expression as\(tan(x^{sinx})\), the limit is not well-defined due to the indeterminate form of 0^0.

To calculate the limit using L'Hospital's Rule, let's consider both interpretations of the expression and find the limits for each case:

Case 1: lim\((tanx)^{(sinx)\) as x approaches 0+

Taking the natural logarithm of the expression, we have:

\(ln[(tanx)^{(sinx)}] = sinx * ln(tanx)\)

Now, we can rewrite the expression as:

\(lim [sinx * ln(tanx)]\)as x approaches 0+

Applying L'Hospital's Rule, we differentiate the numerator and denominator:

\(lim [(cosx * ln(tanx)) + (sinx * sec^{2}(x))] / (1 / tanx)\) as x approaches 0+

Simplifying the expression:

\(lim [cosx * ln(tanx) + sinx * sec^{2}(x)] * tanx\) as x approaches 0+

\(lim [cosx * ln(tanx) + sinx * sec^{2}(x)] * (sinx / cosx)\) as x approaches 0+

\(lim [(cosx * ln(tanx) + sinx * sec^{2}(x)) / cosx] * sinx\) as x approaches 0+

\(lim [ln(tanx) + (sinx / cosx) * sec^{2}(x)] * sinx\) as x approaches 0+

\(lim [ln(tanx) + tanx * sec^{2}(x)] * sinx\) as x approaches 0+

Since lim ln(tanx) as x approaches 0+ = -∞ and\(lim (tanx * sec^{2}(x))\) as x approaches 0+ = 0, we have:

\(lim [ln(tanx) + tanx * sec^{2}(x)] * sinx\) as x approaches 0+ = -∞

Therefore, the limit of \((tanx)^{(sinx)\) as x approaches 0+ using L'Hospital's Rule is -∞.

Case 2: lim\(tan(x^{sinx})\)as x approaches 0+

We can rewrite the expression as:

lim\(tan(x^{(sinx)})\) as x approaches 0+

This expression does not have an indeterminate form of \(0^0\), so we do not need to use L'Hospital's Rule. Instead, we can substitute x = 0 directly into the expression:

lim \(tan(0^{(sin0)})\) as x approaches 0+

lim\(tan(0^0)\)as x approaches 0+

The value of \(0^0\) is considered an indeterminate form, so we cannot determine its value directly. The limit in this case is not well-defined.

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Step-by-step explanation:

4(3x+2)-5(7x+5)

12x+8-35x-25

-23x-17 or,

-(23x+17

2x+x(x+6)

2x+x^2+6x

x^2+8x or,

x(x+8)

please mark me brainliest

Step-by-step explanation:

RF (green) = 34/(12+14+34) = 34/60 = 0.57

(a) By plugging in different values for x1, we can plot the indifference curves passing through the given points (2, 2), (1, 2), and (4, 2).

(b) The shape of the indifference curves shows convexity.

(c) The property used to determine this is the non-satiation property of preferences.

(d) The Walrasian demand may not always be single-valued.

(e) Receiving the voucher makes the consumer better-off .

(f) The cash payment allows the consumer to maximize utility by making trade-offs

For 4x1 + x2 = x1 + 2x2, rearranging the equation gives x2 = 3x1, representing the linear part of the indifference curves.

For x1 + 2x2 = 4x1 + x2, rearranging the equation gives x2 = 3x1, representing the kink in the indifference curves.

By substituting different values for x1, we can plot the indifference curves. They will be upward sloping straight lines with a kink at x2 = 3x1.

(b) Properties of the preferences deduced from the shape of indifference curves and utility function:

Diminishing Marginal Rate of Substitution (MRS): Indifference curves are convex, indicating diminishing MRS. The consumer is willing to give up less of one good as they consume more of it, holding the other good constant.

Non-Satiation: Indifference curves slope upwards, showing that the consumer prefers more of both goods. They always prefer bundles with higher quantities.

Convex Preferences: The kink in the indifference curves indicates convexity, implying risk aversion. The consumer is willing to trade goods at different rates depending on the initial allocation.

(c) UMP does not have a solution when Pk = 0 and X -> R2+. This violates the assumption of finite resources and prices required for utility maximization. The property used is non-satiation, as a consumer will always choose an infinite quantity of goods when they are available at zero price.

(d) Walrasian demand depends on relative prices:

If p1 = p2 > 4, the maximizing bundle lies on the linear portion of indifference curves, where x2 = 3x1.

If 4 < p1 = p2 < 1/2, the maximizing bundle lies on the linear portion of indifference curves but at lower x1 and x2.

If p1 = p2 < 1/2, the maximizing bundle lies at the kink point where x1 = x2.

Walrasian demand may not be single-valued due to the shape of indifference curves and the kink point, allowing for multiple optimal solutions based on relative prices.

(e) Given p1 = p2 = 1 and w = $60, the initial budget set is x1 + x2 = 60. With a $10 voucher for good 1, the new budget set becomes x1 + x2 = 70. Since p1 = 1, the consumer spends the voucher on good 1, resulting in x1 = 20 and x2 = 40. Receiving the voucher improves the consumer's welfare by allowing more consumption of good 1 without reducing good 2.

(f) If given the choice between a $10 cash payment and a $10 voucher for good 1 only, the consumer would choose the cash payment. It provides flexibility to allocate the funds based on individual preferences. The answer remains the same even if the assistance were $30, as the cash payment still allows optimal allocation based on preferences. Cash payment offers greater utility-maximizing options compared to the voucher, which restricts choices.

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