The volumetric flow rate if friction is negligible = 0.00197 m³/sec
Given data :
P₁ = 7 atm = 709.275 kPa
P₂ = 1.5 atm = 151.988 kPa
d₁ = 0.74 cm = 0.0074 m
d₂ = 1.20 cm = 0.0120 m
h = 82 m
density of water ( p ) = 1000 kJ/m³
Estimate the volumetric flow rate
given that friction losses are negligible
V₁² - V₂² = \(\frac{2(P_{2} - P_{1}) }{p} + 2g(h )\)
= 2( 151.988 - 709.275 ) + 2 * 9.81 * 82
= 2 ( - 557.287 ) + 1608.84
= - 1114.574 + 1608.84 = 494.266
∴ V₁² - V₂² = 494.266 ----- ( 1 )
Also given that:
volumetric flow rate ( Q ) = A₁V₁ = A₂V₂
= π / 4 ( 0.0074 )² * V₁ = π / 4 ( 0.0120 )² * V₂
= 0.000043 V₁ = 0.000113 V₂
∴ V₁ = 2.63 V₂
Back to equation ( 1 )
( 2.63 v₂ )² - V₂² = 494.266
V₂² = ( 494.266 ) / 1.63
∴ V₂ = √303.23 = 17.41 m/sec
Therefore the volumetric flow rate ( Q )
Q = A₂V₂
= π / 4 * ( 0.0120 )² * 17.41
= 0.00197 m³/sec
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a roller coaster start at a height of 40Meters and reached a height of 20meter. does mechanical energy change
Mechanical energy changes when a roller coaster starts at a height of 40 meters and reaches a height of 20 meters. The potential energy decreases, while the kinetic energy increases.
When a roller coaster starts at a height of 40 meters and reaches a height of 20 meters, mechanical energy changes. In physics, mechanical energy is the sum of potential and kinetic energy that is present in the objects. When an object is moved, it gains or loses energy, thus the mechanical energy changes. There are two forms of mechanical energy, namely kinetic energy and potential energy. Kinetic energy is the energy that a moving object possesses due to its motion, while potential energy is the energy that an object possesses due to its position or shape.
In the case of a roller coaster, when it starts at a height of 40 meters, it has potential energy that is equal to its mass multiplied by the acceleration due to gravity multiplied by its height. As it moves down the track, the potential energy gets converted into kinetic energy, which is the energy of motion. When the roller coaster reaches a height of 20 meters, it has a lower potential energy compared to when it started. The difference in potential energy is equal to the amount of work done by the force of gravity in bringing the roller coaster down from a height of 40 meters to a height of 20 meters. At the same time, the roller coaster has a higher kinetic energy than when it started, as it gained speed during the descent.
Therefore, in summary, mechanical energy changes when a roller coaster starts at a height of 40 meters and reaches a height of 20 meters. The potential energy decreases, while the kinetic energy increases.
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What is the difference between chronic and acute stress?
Acute stress is long-term, while chronic stress is short in duration.
Acute stress is short-term, while chronic stress endures over time.
Chronic stress varies by geographic location, while acute stress is universal.
Chronic stress is not harmful, while acute stress has negative consequences.
Answer:
The correct difference between chronic and acute stress is:
Acute stress is short-term, while chronic stress endures over time.
Explanation:
Acute stress refers to the immediate and temporary response of the body to a specific stressful event or situation. It is often characterized by a rapid increase in heart rate, heightened alertness, and the release of stress hormones like adrenaline. Acute stress is a normal and natural response to perceived threats or challenges, and once the stressor is removed or resolved, the body returns to its normal state.
On the other hand, chronic stress is long-term and persists over an extended period. It is typically caused by ongoing or recurring stressors, such as work pressures, financial difficulties, relationship problems, or chronic health conditions. Chronic stress can have a cumulative and prolonged impact on physical and mental well-being. It may lead to a range of health issues, including cardiovascular problems, weakened immune system, digestive disorders, anxiety, depression, and burnout.
Chronic stress is considered detrimental to overall health, while acute stress, when experienced in moderation, can actually be beneficial as it can enhance performance and help individuals deal with immediate challenges. It is important to manage chronic stress effectively through stress-reducing techniques, self-care practices, and seeking support when needed to prevent its negative consequences on health and well-being.
Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.500 cm and an area of 0.760 m2 , separated by a layer of air with a thickness of 1.65 cm . The temperature on one side of the window is 0.00 ∘C; the temperature on the other side is 23.0 ∘C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. Approximate the heat transfer through this window by ignoring the glass. That is, calculate the heat flow per second through 1.65 cm of air with a temperature difference of 23.0 ∘C . (The exact result for the complete window is 24.4 J/s .)
The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.
First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.
Next, we calculate the effective thermal conductivity of the air layer as:
k_eff = (k_air * L_air) / (L_air + k_glass)
Substituting the given values, we have:
k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air
Now, we can calculate the heat flow per second through the air layer using the formula:
Q = (k_eff * A * ΔT) / L_air
Substituting the given values, we get:
Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s
Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
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A. O 33.836 kg m/sB. O31.903 kg m/sC. O 12.883 kg m/sD. O 19.2 kg m/sE. O 23.979 kg m/s6. An object of mass 9.5 kg was acted by a force of 14.2 N for3.6 seconds. If its initial speed was 4.0 m/s,calculate its final speed. (1 point)A) 14.189B) 16.584C) 2.015D)3.015E) 9.381
Given:
The mass of the object is m = 9.5 kg
The force acting on it is F = 14.2 N
The time duration is t = 3.6 s
The initial speed is
\(v_i=\text{ 4 m/s}\)To calculate the final speed.
Explanation:
An impulse of an object is calculated as
\(Impulse\text{ = F}\times t\)It can also be written as
\(\begin{gathered} Impulse\text{ = change in momentum} \\ =mv_f-mv_i \end{gathered}\)So, the final velocity can be calculated by equating both the formula
\(\begin{gathered} F\times t=mv_f-mv_i \\ mv_f=F\times t+mv_i \\ v_f=\frac{(F\times t)+mv_i}{m} \end{gathered}\)On substituting the values, the final speed will be
\(\begin{gathered} v_f=\frac{(14.2\times3.6)+(9.5\times4)}{9.5} \\ =9.381\text{ m/s} \end{gathered}\)Thus, the correct choice is E
Shown above right are four different pairs of transverse wave pulses that move toward each other. At some point in time, the pulses meet and interact (interfere) with each other. (Figure 1) Figure 1 of 1 ترتر А. B c D Part A Rank the four cases, from most to least, on the basis of the amplitude of the peak that results when the centers of the pulses coincide. Rank from most to least. To rank items as equivalent, overlap them. Reset Help B A с Least Most
According to the magnitude of the peak that is produced when the centers of the pulses coincide, the four examples are ordered as follows: A, B, D, and C.
How does the pulse move within a transverse wave?A transverse pulse is one in which the individual coils move in a direction that is antithetical to the direction in which you are moving the slinky. transverse and longitudinal waves the vibrational motion of the particles or layers of the medium in a longitudinal wave is parallel to the direction of the disturbance's propagation.
What do you mean when you say that two wave pulses with identical amplitude and opposing phase are superimposed?Destructive interference is when two waves superimpose on top of each other in the opposite phase, with the resultant wave's amplitude being equal to the individual waves' differences in amplitude and producing the least amount of light.
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Using properties of transverse wave, According to the magnitude of the peak that is produced when the centers of the pulses coincide, the four examples are ordered as follows: A, B, D, and C.
How does the pulse move within a transverse wave?A transverse pulse is one in which the individual coils move in a direction that is antithetical to the direction in which you are moving the slinky. transverse and longitudinal waves the vibrational motion of the particles or layers of the medium in a longitudinal wave is parallel to the direction of the disturbance's propagation.
What do you mean when you say that two wave pulses with identical amplitude and opposing phase are superimposed?Destructive interference is when two waves superimpose on top of each other in the opposite phase, with the resultant wave's amplitude being equal to the individual waves' differences in amplitude and producing the least amount of light.
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Complete question -
Shown above right are four different pairs of transverse wave pulses that move toward each other. At some point in time, the pulses meet and interact (interfere) with each other. (Figure 1) Figure 1 of 1 ترتر А. B c D Part A Rank the four cases, from most to least, on the basis of the amplitude of the peak that results when the centers of the pulses coincide. Rank from most to least. To rank items as equivalent, overlap them. Reset Help B A с Least Most
1. When might an ASDS be most useful and why?
2. How do Trappist-E, -F, and -G contrast with Earth?
3. Why is the greenhouse effect significant? Explain your reasoning.
4. Do you agree that humans are contributing to greenhouse gas levels? Explain your answer.
5. When might a rover be useful and why?
ASDA is found to be very proficient at detecting swirls in a variety of synthetic data with various levels of noise, implying our subsequent scientific results are astute.
What is ASDA?Applying ASDA to photospheric observations with a pixel size of 39.2 km sampled by the Solar Optical Telescope on board Hinode suggests a total number of 1.62 × 105 swirls in the photosphere, with an average radius and rotating speed of ∼290 km and <1.0 km s−1, respectively.
Comparisons between swirls detected in Bifrost numerical MHD simulations and both ground-based and space-borne observations suggest that (1) the spatial resolution of data plays a vital role in the total number and radii of swirls detected, and (2) noise introduced by seeing effects could decrease the detection rate of swirls, but has no significant influences in determining their inferred properties.
All results have shown that there is no significant difference in the analyzed properties between counterclockwise or clockwise rotating swirls. About 70% of swirls are located in intergranular lanes.
Therefore, ASDA is found to be very proficient at detecting swirls in a variety of synthetic data with various levels of noise, implying our subsequent scientific results are astute.
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Answer:
When might an ASDS be most useful and why?
Autonomous Spaceport Drone Ships would be helpful when a spacecraft needs to land in the ocean, for example. These prevent the rocket from being damaged by the water. These are typically used when a spacecraft doesn’t have enough fuel to reach its planned landing spot.
How do Trappist-E, -F, and -G contrast with Earth?
Trappist-E, -F, and -G are the planets that orbit in the habitable zone. They all have a high possibility of having water, similar to Earth. These planets are about the same size as Earth but they have about 100 times more water.
Why is the greenhouse effect significant? Explain your reasoning.
Greenhouse gases is likely what has caused the increase of warmth on our planet (global warming). People add to these greenhouse gases and they trap heat. We don’t know exactly what will be the outcome of the rise in these gases, but so far they have largely contributed to global warming.
Do you agree that humans are contributing to greenhouse gas levels? Explain your answer.
Yes, I do agree. People add to the heat-trapping greenhouse gases, like carbon dioxide, methane, nitrous oxide, and chlorofluorocarbons. Methane, for example, is increased when landfills are made of coal is mined, both of which are human activities.
When might a rover be useful, and why?
A rover might be useful when we are exploring places that aren’t safe for people. Another time rovers might be helpful is when we are exploring places that humans literally can’t go to or conduct research on because of what the planet is made out of. Since a rover isn’t human it can’t experience feelings or get hurt (it can be damaged, but that wouldn’t lose a life) therefore, it’s safer to send a rover at least until we can find out if it’s safe or not.
Explanation:
I had to do this in class
Four cuboids are shown in the diagram below. The position of their center of mass is also shown. Which of the cuboids is the most stable.
The position of their center of mass is also shown. the square cuboids is the most stable. Hence option B is correct.
A cuboid is a six-sided solid known as a hexahedron in geometry. Quadrilaterals make up its faces. Cuboid is short for "like a cube". A cuboid is similar to a cube in that a cuboid may become a cube by varying the lengths of the edges or the angles between the faces.
The square cuboid has its center of mass on the center of square, the masses are uniformly distributed about it.
Hence option B is correct.
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Two adjacent students stand on stationary skateboards, face each other, and
push apart. The skateboarder on the left weighs 55 kg, the one on the right is
65 kg. If the lighter skateboarder moves at 4.2 m/s, determine the speed and
direction of the heavier skateboarder.
When some volcanoes erupt, big rocks have been measured to reach heights of 50km (50,000m) What would the initial velocity need to be in order to reach such heights (neglect air resistance) (1 sigfig space unit)
We know that:
v² = v₀² - 2ah
Where v is the final velocity whos value at the maximum height is zero.
v₀ is the initial velocity
h is the maximum height
a = g = 10 m/s² the acceleration due gravity on Earth
Solving for v0:
\(v_0=\sqrt{v^2+2ah} \\\\v_0 =\sqrt{ 0+2(10\;m/s^2)(50000\;m)}\\\\v_0 =\sqrt{ 2(10\;m/s^2)(50000\;m)} \\\\v_0 = 1000\;m/s\)
Answer:
1000 m/s ( 990.45 m/s to be exact)
Explanation:
If we use one of the SUVAT equations, i.e.,
2as = (v^2) - (u^2) where;
s = distance, a = acceleration, v = final velocity, u = initial velocity
At max point the rocks are considered stationery, which makes v = 0, the height is 50,000m which makes s = 50,000, the acceleration is -9.81, as the object decelrates to 0
2(-9.81)(50000) = (0)^2 - (u)^2
-981000 = - u^2
u = sqr root( 981000)
u = 990.45 m/s = 1000 m/s
A 5-kg object is moving with a speed of 4 m/s at a height of 2 m. The potential energy of the object is approximately
J.
Answer:
P.E = 98 Joules
Explanation:
Given the following data;
Mass = 5kg
Speed = 4m/s
Height = 2m
We know that acceleration due to gravity is equal to 9.8m/s²
To find the potential energy;
Potential energy can be defined as an energy possessed by an object or body due to its position.
Mathematically, potential energy is given by the formula;
\( P.E = mgh\)
Where, P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
Substituting into the equation, we have;
\( P.E = 5*9.8*2\)
P.E = 98 Joules
A platinum resistance thermometer has resistances of 210.0 Ω when placed in a 0°C ice bath and 237.8 Ω when immersed in a crucible containing a melting substance. What is the melting point of this substance? (Hint: First determine the resistance of the platinum resistance thermometer at room temperature, 20.0°C.)
The resistance of a platinum resistance thermometer is 200 Ω at 0°C and 255.8 Ω at the melting point. Using the resistance-temperature relationship and calculations, the estimated melting point is approximately 19.93°C.
The resistance of a platinum resistance thermometer is 200 Ω when placed in a 0°C ice bath and 255.8 Ω when immersed in a crucible containing a melting substance. To determine the melting point of the substance, we need to calculate the temperature at which the resistance reaches 255.8 Ω.
First, we find the temperature coefficient of resistance (α) using the formula α = (R - R₀) / (R₀ * T), where R is the resistance at the melting point, R₀ is the resistance at 0°C, and T is the temperature at the melting point.
Substituting the given values, we have α = (255.8 - 200) / (200 * T₀), where T₀ is the known room temperature of 20°C.
Calculating α, we find α ≈ 0.014.
Next, we use the resistance-temperature relationship equation R = R₀(1 + αT) to solve for the melting point temperature (T). Substituting the known values, we have 255.8 = 200(1 + 0.014 * T).
Simplifying the equation, we find 1.279 = 1 + 0.014T.
Solving for T, we get T ≈ 19.93°C.
Therefore, based on the given data, the estimated melting point of the substance is approximately 19.93°C.
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Based on what you learn about gravity describe why objects float in outer space
Answer:
Objects float in outer space because there is no gravitational force. The farther you get from earth, the less gravity.
Explanation:
Answer:
they float do to gravity
Explanation:
here if you tossed a ball in the air it would come back down fast in space however it would only float up and stay do to gravity
Please help me with just question 1
Find the magnitude and direction of the resultant of the five concurrent forces
acting on a bolt.
The magnitude and direction of the resultant of the five concurrent forces acting on a bolt is 390.58 N and -82.8 ⁰ respectively.
What is the magnitude and direction of the five forces?The magnitude and direction of the resultant of the five concurrent forces acting on a bolt is calculated as follows;
The sum of the x component of the five forces is calculated as;
F₁ₓ = -80 N x cos (27) = -71.28 N
F₂ₓ = -400 N x cos (22) = - 370.87 N
F₃ₓ = -150 N x cos (22 + 46) = -56.2 N
F₄ₓ = 300 N x cos (45) = 212.13 N
F₅ₓ = 250 N x cos (18) = 237.76 N
∑Fₓ = -48.98 N
The sum of the y component of the five forces is calculated as;
F₁y = -80 N x sin (27) = -36.32 N
F₂y = 400 N x sin (22) = 149.84 N
F₃y = 150 N x sin (22 + 46) = 139.1 N
F₄y = 300 N x sin (45) = 212.13 N
F₅y = -250 N x sin (18) = -77.25 N
∑Fy = 387.5 N
The magnitude of the resultant force;
F = √ (387.5² + 48.98²)
F = 390.58 N
The direction of the force;
θ = tan⁻¹ ( Fy / Fₓ )
θ = tan⁻¹ ( 387.5 / -48.98 )
θ = -82.8 ⁰
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A rollar coaster moves over the creast at location 1 at 10 m/s. HOw fast is it going at location 4? Neglect friction and air resistance.
The velocity of the roller coaster at location 4 is 14.14 m/s (approx) using the given values of v₁ = 10 m/s, h₁ = 30 m, and h₂ = 15 m.
Roller coasters are fascinating machines that deliver an exhilarating experience by defying gravity and physics. Roller coaster physics is a significant concept to comprehend before riding a roller coaster or designing one. The laws of physics govern the motion of a roller coaster, including its velocity, acceleration, and potential energy.
A roller coaster moves over a crest at location 1 with a speed of 10 m/s. The question is how fast it's going at location 4, considering the neglect of friction and air resistance. To solve this, we'll need to consider the conservation of energy law.
The total energy of the roller coaster remains constant throughout the ride, and we can convert between potential and kinetic energy.Using the conservation of energy formula, which is: E1 = E2Where E1 is the total energy of the roller coaster at the crest and E2 is the total energy of the roller coaster at location 4.
Both E1 and E2 comprise kinetic energy (KE) and potential energy (PE). So,E1 = KE1 + PE1E2 = KE2 + PE2Since the roller coaster has no friction and air resistance, we can assume that PE1 = PE2 because the height of the roller coaster doesn't change. The energy is converted from potential energy at the crest to kinetic energy at location 4.
We can now use the formula for kinetic energy:KE = (1/2) mv²Where m is the mass of the roller coaster and v is its velocity. Both E1 and E2 can be written in terms of KE, so: E1 = (1/2) mv₁²E2 = (1/2) mv₂².
Substitute the values into the conservation of energy formula: E1 = E2(1/2) mv₁² = (1/2) mv₂²
Simplifying the equation gives:v₂² = v₁²×(h₁ / h₂)
where h₁ is the height of the crest and h₂ is the height of location 4.
To calculate the velocity, we need to take the square root of both sides:v₂ = v₁×√(h₁ / h₂)
Therefore, the velocity of the roller coaster at location 4 is 14.14 m/s (approx) using the given values of v₁ = 10 m/s, h₁ = 30 m, and h₂ = 15 m.
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A steam engine takes in superheated steam at 270 °C and discharges condensed steam from its cylinder at 50 °C. The engine has an efficiency of 30%, and taken in 50 kJ from the hot steam per cycle. If a Carnot engine takes in the same amount of heat per cycle and operates at these temperatures, the work it can turn into is most likely to be:a) 15 kJ. b) 20 kJ. c) 10 kJ. d) 50 kJ.
Answer:
b) 20 kJ
Explanation:
Efficiency of carnot engine = (T₁ - T₂ ) / T₁ Where T₁ is temperature of hot source and T₂ is temperature of sink .
T₁ = 270 + 273 = 543K
T₂ = 50 + 273 = 323 K
Putting the given values of temperatures
efficiency = (543 - 323) / 543
= .405
heat input = 50 KJ
efficiency = output work / input heat energy
.405 = output work / 50
output work = 20.25 KJ.
= 20 KJ .
Each lightbulb provides 90 M of resistance. The batteries are 1.5 V. Calculate the current in your circuit.
The current in the circuit will be 0.0167 Amperes when a light bulb is providing resistance and the batteries with 1.5 voltage.
What is current?A stream of charged particles, such as electrons or ions, travelling through an electrical conductor or a vacuum is known as an electric current. The net rate of electric charge flowing through a surface or into a control volume is how it is measured.
What are the calculations?To calculate current the formula used is V= IR
1.5/90 = I
0.016 A = I
What is a circuit?Electronic components such as resistors, transistors, capacitors, inductors, and diodes are connected via conductive wires or traces that allow an electric current to pass between them.
Hence, the current in the circuit will be 0.0167 Amperes when a light bulb is providing resistance and the batteries with 1.5 voltage.
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Electromagnetic waves travel with speed of about 300,000 km per second (3 x 108 meters per second). What is the wavelength of an electromagnetic wave with a frequency of one billion cycles per second (109 cycles per second). Is this radio or ultraviolet light?
The wavelength of the waves is 2.75×10⁶ m. and it is a radio wave.
Wavelength can be defined as the distance of one complete cycle of a wave.
To calculate the wavelength of the electromagnetic wave, we use the formula below.
Formula:
v = λf.............. Equation 1Where:
v = Speed of the waveλ = wavelength of the wavef = frequency of the wave.
make λ the subject of the equation
λ = v/f............ Equation 2From the question,
Given:
v = 300000 km/s f = 109 cycle per seconds.Substitute these values into equation 2
λ = 300000/109λ = 2752.3 kmλ = 2.75×10⁶ m.This falls within the wavelength range of radio waves.
Hence, the wavelength of the waves is 2.75×10⁶ m. and it is a radio wave.
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Solve pls:
a) What are the maina dvantages of an epicyclicgearbox? b) Figure Q4 overleaf shows a diagram for an epicyclic gear train. Power is supplied to
wheel 3 and is delivered to a load attached to the epicyclic arm, body 2. Wheel 5 is fixed to the gear case, body 1.
i) Determine T4 if t3 = 30, t4 = 40 and t5 = 60.
a) The main advantages of an epicyclic gearbox are:
High gear ratios can be achieved in a small space, making it a compact design.It can provide a smooth and efficient transfer of power due to the multiple contact points between gears.It can be used for different applications, such as increasing torque or speed, reversing direction, and providing a neutral point.How to solve a gearbox?b) i) Using the formula for the gear ratio of an epicyclic gear train:
T4/T3 = (t2/t1) x (t5/t2) x (t4/t5)
T4/30 = (1/2) x (60/20) x (40/60)
T4 = 40 Nm
ii) From the law of gearing for an epicyclic gear train:
w21 = (t3/t2) x (t5/t4) x w31 - (t3/t2) x w2
Substituting the given values:
w21 = (30/20) x (60/40) x 200 - (30/20) x 100
w21 = 150 rad/s
iii) The fixing couple that must be applied to wheel 5 can be found from the power transmitted by the gear train:
P = w3 x T3 = w2 x T2 = w1 x T1
Substituting the given values:
9 kW = 200 rad/s x 30 Nm = w2 x T2 = w2 x 20 Nm
w2 = 450 rad/s
T2 = (9 kW) / (450 rad/s) = 20 Nm
The fixing couple that must be applied to wheel 5 is equal in magnitude and opposite in direction to T2, so it is -20 Nm.
iv) The tangential force at the pitch point between wheels 3 and 4 can be found from the formula:
Ft = (2 x Pd) / (m x z3)
where Pd is the diametral pitch, m is the module, and z3 is the number of teeth on wheel 3.
Substituting the given values:
Pd = 25.4 / 5 = 5.08 teeth/inch
z3 = t3 / m = 30 / 5 = 6 teeth
Ft = (2 x 5.08) / (5 x 6) = 0.846 N
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For the circuit below, calculate the current drawn from the battery and in the current through each 8 W resistors.
A lot of energy is not stored in biomass, but is used for biological processes instead. Which process
releases thermal energy?
Explanation:
Respiration releases energy - it is an exothermic process. This means it releases heat energy.
The process which releases thermal energy is respiration.
What is thermal energy?The energy which increase the temperature is called the thermal energy.
Biomass energy is created but can not be stored. Same way, the respiration process which releases heat in form of air from nose or mouth. This process is exothermic.
Thus, Respiration releases thermal energy.
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Which example best describes Newton's third law of motion?
F
When a glass slid across a table, it spilled water when it stopped suddenly.
G
An engine used less work to move a lighter car than when it moved a heavier car.
H When a passenger stepped from a boat to the shore, the boat moved away from the shore .
The best example of Newton's third law of motion is, When a passenger stepped from a boat to the shore, the boat moved away from the shore. Thus, option C is correct.
Sir Issac Newton gives three laws of motion. The first law states that an object remains at rest or in continuous motion unless an external force acted on it. The second law stated that the force is directly proportional to the acceleration of the object. Newton's third law states that, for every action, there is an equal and opposite reaction.
From the given, Newton's third law is applicable, When a passenger stepped from a boat to the shore, the boat moved away from the shore. This shows the action and reaction of the boat and shore.
Thus, the ideal solution is option C.
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A vertical spring with a spring constant of 2.00 N/m has a 0.30-kg mass attached to it, and the mass moves in a medium with a damping constant of 0.025 kg/s. The mass is released from rest at a position 5.0 cm from the equilibrium position. How long will it take for the amplitude to decrease to 2.5 m?
Answer:
17 seconds
Explanation:
Given that:
The mass attached to the spring (m) = 0.30 kg
The spring constant (k) = 2.00 N/m
The damping constant (b) = 0.025 kg/s
The initial distance \(x_o\) = 5.0 cm
The initial final amplitude \(A_f\) = 2.5 cm and not 2.5 m, please note the mistake, if it is 2.5 m, our time taken will be -93.7 sec, and we do not want a negative time value.
To start with the angular frequency damping using the formula:
\(\omega_{\gamma}= \dfrac{b}{2m}\)
\(\omega_{\gamma}= \dfrac{0.025 \ kg/s}{2(0.3 \ kg)}\)
\(\omega_{\gamma}=4.167 \times 10^{-2} \ s^{-1}\)
In the absence of damping, the angular frequency is:
\(\omega_o = \sqrt{\dfrac{k}{m}}\)
\(\omega_o = \sqrt{\dfrac{2 \ N/m}{0.3 kg}} \\\\\omega_o = 2.581 \ s^{-1}\)
The initial amplitude oscillation can be computed by using the formula:
\(A_i = e^{-\omega_{\gamma}t} x_o \sqrt{\dfrac{\omega_o^2}{\omega_o^2-\omega_f^2}}\)
\(A_i = e^{-\omega_{\gamma}0} (5.0 \ cm) \sqrt{\dfrac{2.581^2}{2.581^2-(4.167*10^{-2})^2}}\)
\(A_i = 5.0006 \ cm \\ \\ A_i = 5.001 \ cm\)
The final amplitude, as well as the initial amplitude, can be illustrated by using the relation:
\(A_f = e^{-\omega_{\gamma}t}A_i\\ \\ e^{-\omega_{\gamma}t} = \dfrac{2. 5 \ cm}{5.001 cm}\\ \\ = 0.4999\\ \\ \implies -\omega_{\gamma}t_f = \mathsf{In (0.4999)} \\ \\ t_f = \dfrac{\mathsf{-In (0.4999)}}{4.167*10^{-2} \ s^{-1}} \\ \\\)
\(t_f = 16.64 \ sec \\ \\ \mathbf{t_f \simeq 17 sec}\)
the mass of a density bottle is 18.00g when empty 44.00g when full of water, and 39.84g when full up of a second liquid. calculate the density of the liquid where density of water =1000kgm³
The density of the second liquid is 0.812 g/cm³
To calculate the density of the second liquid, we need to use the principle of displacement. The mass of the liquid can be found by subtracting the mass of the empty density bottle from the mass of the bottle filled with the liquid. Therefore, the mass of the liquid is:
mass of liquid = mass of bottle + liquid - mass of empty bottle
mass of liquid = 39.84g + x - 18.00g
where x is the mass of the liquid.
We can now use the density formula, which is:
density = mass/volume
The volume of the liquid is equal to the volume of the density bottle that is filled with the liquid, which can be calculated by subtracting the volume of the empty bottle from the volume of the bottle filled with the liquid. Therefore, the volume of the liquid is:
volume of liquid = volume of bottle filled with liquid - volume of empty bottle
We can now substitute this expression into the density formula to get:
density of liquid = mass of liquid / (volume of bottle filled with liquid - volume of empty bottle)
We know that the density of water is 1000 kg/m³, which is equal to 1 g/cm³. We can use this to find the volume of the liquid by dividing the mass of water by its density:
volume of water = mass of water / density of water
volume of water = 44.00g / 1 g/cm³
volume of water = 44.00 cm³
Now, we can calculate the volume of the density bottle filled with the second liquid by using the principle of displacement:
volume of bottle filled with liquid = volume of water - volume of liquid
volume of bottle filled with liquid = 44.00 cm³ - (39.84g - 18.00g) / 1 g/cm³
volume of bottle filled with liquid = 44.00 cm³ - 21.84 cm³
volume of bottle filled with liquid = 22.16 cm³
Finally, we can substitute these values into the density formula to get:
density of liquid = x / 22.16 cm³
Solving for x, we get:
x = density of liquid x 22.16 cm³
Substituting x back into the mass equation, we get:
mass of liquid = 39.84g + (density of liquid x 22.16 cm³) - 18.00g
Solving for the density of the liquid, we get:
density of liquid = (mass of liquid - 21.84g) / 22.16 cm³
Substituting the given values, we get:
density of liquid = (39.84g - 21.84g) / 22.16 cm³ = 0.812 g/cm³
In conclusion, the density of the second liquid is 0.812 g/cm³. This value is less than the density of water, which means that the second liquid is less dense than water and will float on top of water.
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What keeps the Earth's atmosphere from floating away? Earth's gravity keeps the air molecules of the atmosphere from escaping the area surround Earth The attraction between the different molecules of atmospheric gases The temperature of the gas is not high enough to allow it to spread out and escape the area surrounding Earth The differentiation between temperatures of the Earth and outer space traps the gases in the atmosphere
Answer: it is the earth gravity :’)
Explanation:
Earth's gravity keeps the air molecules of the atmosphere from escaping the area surround Earth
SOMEONE PLEASE HELP MEEEEEEE
Answer:
Weathering and erosion
Explanation:
Physics Question!!!!!
Answer:
bbibinononobyvtcrxrxextcyvubuvububububububbu
Answer:
im just gettin these points babbbyyyyyy
Explanation:
Air conditioners operate on the same principle as refrigerators. Consider an air conditioner that has 7.00 kg of refrigerant flowing through its circuit each cycle. The refrigerant enters the evaporator coils in phase equilibrium, with 54.0 % of its mass as liquid and the rest as vapor. It flows through the evaporator at a constant pressure and when it reaches the compressor 95% of its mass is vapor. In each cycle, how much heat Qc is absorbed by the refrigerant while it is in the evaporator? The heat of vaporization of the refrigerant is 1.50×105 J/kg
Answer:
5.15J
Explanation:
First. 54% of the 7kg refrigerant is liquid
So we find mass of vapour at inlet generator
M1 = ( 1-0.54)*7= 3.2kg
At compressor mass of vapour will be
M2= 0.95*7= 6.7kg
So the Mass of vapour at exit generator is
M2-M1= 3.5kg
So to find heat absorbed by refrigerant in evaporation
Its using
Q= mh
°= 3.5x 1.50×10^5 J/kg
=5.15J
A punter kicks a football at an angle of 45° to the ground. The football has an initial velocity of 25 m/s.
a. How long is the football in the air?
s
b. What horizontal distance does the football travel?
m
c. What is the maximum height of the football?
m
Answer: The football spent 3.6 s in air
Explanation: I know im correct :-)
an a astronaut stands on the surface of a spherical asteroid that has a weak gravitational field but no atmosphere
Answer:
so what is your question that's not a question
An asteroid is a minor planet in the inner solar system. The asteroid orbits the sun and millions of asteroids exit as remains of planetesimals.
The weak gravitational field of the asteroid describes that there is no contact between the asteroid and the astronaut. As the asteroid has no atmosphere the astronaut jumps and drifts.Hence there is no contact as no gravitational force.
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Select the correct answer.
A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are the total
distance and total displacement of the boat?
O A.
OB.
O C.
O D.
The total distance is 105 kilometers and the total displacement is 45 kilometers east.
The total distance is 60 kilometers and the total displacement is 60 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east.
The total distance is 60 kilometers and the total displacement is 45 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C
How to solve for the total distanceTo calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.
However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.
Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.
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