Water is flowing in a pipe with a varying cross-sectional area, and at all points, the water completely fills the pipe. At point 1 the cross-sectional area of the pipe is 0.070 m^{2}0.070m 2, and the magnitude of the fluid velocity is 3.50 m/s.
(a) What is the fluid speed at points in the pipe where the cross-sectional area is (a) 0.105 m and (b) 0.047m^2?
(c) Calculate the volume of water discharged from the open end of the pipe in 1.00 hour.
Answers
The fluids speed at a) 0.105m² and b) 0.047m² are 2.33m/s² and 5.21 m/s² respectively
For solving a) and b) we should use flow continuity for ideal fluids:
ΔQ = 0 ----1
With Q the flux of water, but Q is Av using this on (1) we have:
A2v2-A1v1 = 0---2
With A the cross sectional areas and v the velocities of the fluid.
a) Here, we use that point 2 has a cross-sectional area equal to A2 = 0.105m2 , so now we can solve (2) for :
v2= 2.33 m/s
b) Here we use point 2 as A2 = 0.047m² :
v2 = 5.21 m/s
c) Here we need to know that in this case the flow is the volume of water that passes a cross-sectional area per unit time, this is Q= V/t , so we can write:
A1v1 = V/t , solving for V:
V = A1v1t = (0.070m2)(3.5m/s)(3600s) = 882 m³
What is Bernoulli's theorem?
According to Bernoulli's principle, which governs fluid dynamics, a fluid's speed increases concurrently with a reduction in pressure or potential energy. The mathematical concept is named after Swiss mathematician Daniel Bernoulli, who first published it in his book Hydrodynamics in 1738.
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Related Questions
A bar of mass M and length L = 4 meters is pivoted on a fulcrum that is d = 1.8 meters away from the left end. Attached to the left end, a mass m = 5 kg hangs at rest and keeps the system in equilibrium. What is the mass of the bar?
Answers
The given problem can be exemplified in the following diagram:
The weight of the bar is concentrated in its center of mass which is located in the middle of the longitude of the bar. We can add the total torques at the point where the pivot touches the bar and we get:
\(\Sigma T=(5\operatorname{kg})(g)(1.8m)-(2m-1.8m)(Mg)\)Here we have used momentum counter-clockwise as positive. Since the system is in equilibrium the sum of the torques must be equal to zero:
\((5\operatorname{kg})(g)(1.8m)-(2m-1.8m)(Mg)=0\)Now we solve the operations, we will use for the acceleration of gravity 9.8 meters per second squared:
\(88.2Nm-1.96M=0\)Now we solve for the mass "M" first by subtracting 88.2Nm from both sides:
\(-1.96M=-88.2Nm\)Now we divide both sides by -1.96:
\(M=\frac{-88.2Nm}{1.96m\frac{m}{s^2}}\)Solving the operations we get:
\(M=45\operatorname{kg}\)Therefore, the mass of the bar is 45 kg.
Choose the correct answer for a 16-ampere electric motor, single-phase. Branch-circuit protection, non-time-delay fuses: Normal size _______________ A.
Answers
For a 16-ampere electric motor, single-phase will need a Normal size fuses.
Normal size fuse explained.
Fuses are electrical devices use to protect electrical appliances from excess electric current flow. They are dresigned to break the circut and allow normal electruc flow. The main purpose of fuse is to prevent damage of lectrical appliances or equipment.
Normal size fuses include 5A, 10A, 20A are normal sizes use for electricals work. They are used to prevent damage to electric circuits and overcurrent.
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Force acts on a pebble with position vector , relative to the origin. What is the resulting torque acting on the pebble about (a) the origin and (b) a point with coordinates (8.62 m, 0, -2.93 m)
Answers
Answer:
Incomplete question, but let analyse generally a torque acting on a rotating body
Explanation
Toque is given as
τ = r × F
Where
τ is the torque (Nm)
r is the position vector (m)
F is the force (N).
Let assume we have the following data
F= x•i + y•j + z•k
Also let assume the position vector is
r'= a•i + b•j + c•k
a. The first question, torque at the origin
The origin will have a position vector of r1(0,0,0)
Then, the displacement is
r=AB=AO+OB=-OA+OB
r = r'-r1 = (a, b, c)-(0,0,0)
r=(a, b, c)
Then, the torque is given as
τ = r×F
τ = (a, b, c) × (x, y, z)
Note that
i×i=j×j=k×k=0
i×j=k, j×i=-k
j×k=i, k×j=-i
k×i=j, i×k=-j
τ = (a•i + b•j + c•k) × (x•i + y•j + z•k)
τ = a•i×(x•i + y•j + z•k) + b•j×(x•i + y•j + z•k) + c•k×(x•i + y•j + z•k)
τ = (a•i × x•i)+ (a•i × y•j) + (a•i × z•k) + (b•j × x•i) + (b•j × y•j) + (b•j × z•k) + (c•k × x•i) + (c•k × y•j) + (c•k × z•k)
Now, using the above law.
τ = 0 + ay•k - az•j - bx•k + 0 + bz•i + cx•j - cy•i + 0
τ= ay•k - az•j - bx•k + bz•i + cx•j -cy•i
Then, rearranging
τ = (bz - cy)•i + (cx - az)•j + (ay - bx)•k
This is general formula for the torque at the origin, so you can apply it to the given values in your question because the question given is not complete.
b. Now let, analyse at the position vector (2.61 m, 0, -8.03 m)
Using the same analysis
position vector of r1(2.61, 0, -8.03)m
Then, the displacement is
r=AB=AO+OB=-OA+OB
r = r'-r1 = (a, b, c)-(2.61,0,-8.03)
r=(a-2.61, b, c+8.03)
Then, the torque is given as
τ = r×F
τ = (a-2.61, b, c+8.03) × (x, y, z)
Note that
i×i=j×j=k×k=0
i×j=k, j×i=-k
j×k=i, k×j=-i
k×i=j, i×k=-j
τ =([a-2.61]•i, b•j, [c+8.03]•k) × (x•i + y•j + z•k)
τ = (a-2.61)•i×(x•i + y•j + z•k) + b•j×(x•i + y•j + z•k) + (c+8.03)•k×(x•i + y•j + z•k)
τ = ((a-2.61)•i × x•i)+ ((a-2.61)•i × y•j) + ((a-2.61)•i × z•k) + (b•j × x•i) + (b•j × y•j) + (b•j × z•k) + ((c+8.03)•k × x•i) + ((c+8.03)•k × y•j) + ((c+8.03)•k × z•k)
Now, using the above law.
τ = 0 + (a-2.61)y•k - (a-2.61)z•j - bx•k + 0 + bz•i + (c+8.03)x•j - (c+8.03)y•i + 0
τ= (a-2.61)y•k - (a-2.61)z•j - bx•k + bz•i + (c+8.03)x•j -(c+8.03)y•i
Then, rearranging
τ = (bz - cy - 8.03y)•i + (cx + 8.03x - az - 2.61z)•j + (ay - 2.61y - bx)•k
This is general formula for the torque at the point (2.61 m, 0, -8.03 m), so you can apply it to the given values in your question because the question given is not complete.
(a) Torque acting on the pebble about the origin is (-1.5i - 4j - 1k) Nm.
(b) Torque acting on the pebble about the given coordinate is 20j Nm.
What is meant by torque ?Torque is defined as the rotational analogue of force. It is the cross product of force and the perpendicular distance.
Here,
The position coordinates of the pebble, r = (0.5 m)j - (2 m)k
Force acting on the pebble, F = (2 N)i - (3 N)k
(a) About the origin
Torque acting on the pebble, τ = r x F
τ = (0.5j - 2k) x (2i - 3k)
τ = (0.5j x 2i) + (0.5j x -3k) + (-2k x 2i) + (-2k x -3k)
τ = -1k - 1.5i - 4j + 0
τ = (-1.5i - 4j - 1k) Nm
(b) At a point with coordinates (8.62m, 0, -2.93m)
Torque acting on the pebble,
τ = r x F
τ = (8.62i - 2.93k) x (2i - 3k)
τ = (8.62i x 2i) + (8.62i x -3k) + (-2.93k x 2i) + (-2.93k x -3k)
τ = 25.86j - 5.86j
τ = 20j Nm
Hence,
(a) Torque acting on the pebble about the origin is (-1.5i - 4j - 1k) Nm.
(b) Torque acting on the pebble about the given coordinate is 20j Nm.
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Your question was incomplete, but most probably your question was:
Force (2 N)i - (3 N)k acts on a pebble with position vector (0.5 m)j - (2 m)k, relative to the origin. What is the resulting torque acting on the pebble about (a) the origin and (b) a point with coordinates (8.62 m, 0, -2.93 m)
if peter expends 2,000 calories running a mile in one hour and samantha burns 1000 calories riding a bike in thirty minutes. who exerted the greatest amount of power?
Answers
Peter expended more power than Samantha, as he expended 2,000 Joules of energy in one hour, while Samantha expended only 33.33 Joules of energy in thirty minutes.
In order to calculate the power expended by Peter and Samantha, we need to use the formula:
Power = Work / Time
where Work is the amount of energy expended and Time is the duration of the activity.
For Peter, the Work done is:
Work = 2,000 calories / 1 hour = 2,000 Joules
For Samantha, the Work done is:
Work = 1,000 calories / 30 minutes = 33.33 Joules
Therefore, Peter expended more power than Samantha, as he expended 2,000 Joules of energy in one hour, while Samantha expended only 33.33 Joules of energy in thirty minutes. So, Peter exerted the greatest amount of power.
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What is sedimentary rock?
Answers
What volume of silver metal will have a mass of exactly 2500.0 g? The density of silver is 10.50 g/cm3.
*Include your units!
Round your answer to the nearest tenth.
Answers
Explanation:
The density of silver is 10.5g/cm3
=2500.0g/10.5g/cm3
=238.09cm3
238.1cm3 to nearest tenth.
I hope my answer helps. Please mark as brainliest.
.Which of the following describes a difference in the behavior of an electrically conducting sphere and that of an insulating sphere?
A conducting sphere can be charged by friction, but an insulating sphere cannot.
An uncharged object can be charged by touching it to a charged conducting sphere, but not by touching it to a charged insulating sphere.
When a conducting sphere is brought near a positively charged object, some of the sphere’s electrons move closer to that object. No polarization occurs in the atoms of an insulating sphere.
Excess charge placed on a conducting sphere becomes distributed over the entire surface of the sphere. Excess charge placed on an insulating sphere can remain where it is placed.
Answers
There are several differences in behavior between an electrically conducting sphere and an insulating sphere.
Firstly, a conducting sphere can be charged by friction, whereas an insulating sphere cannot. This is because the conducting sphere allows electrons.
Secondly, an uncharged object can be charged by touching it to a charged conducting sphere, but not by touching it to a charged insulating sphere. This is because the conducting sphere allows charge to flow easily between objects, while an insulating sphere does not.
Excess charge placed on a conducting sphere becomes distributed over the entire surface of the sphere. Excess charge placed on an insulating sphere can remain where it is placed. conducting spheres have mobile electrons that can move freely, allowing the charge to distribute evenly over the surface Insulating spheres have electrons that are not as mobile, which means the charge cannot move as freely and tends to remain where it was placed. the fact that polarization occurs in conducting spheres when brought near a charged object, while insulating spheres do not experience this effect.
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As thermal energy is added to a sample of water, the kinetic energy of its
molecules increases, but the particles remain close together. Which part of
the heating curve illustrates this process?
Answers
Answer:
B
Explanation:
Answer:
B. C
Explanation:
took the test :V
Which of the following would increase the elastic force acting on that object
Answers
Answer:
Which of the following would increase the elastic force acting on that object? Moving a spring to an unstretched position. Compressing a spring twice as much as its starting position.
Explanation:
A) Formulate the problem of two bodies of masses m1 and m2 subjected to a central attractive force:
and show that the center of mass of the system moves with
constant velocity and the relative coordi
Answers
The question involves formulating the problem of two bodies with masses m1 and m2 subjected to a central attractive force. It also requires demonstrating that the center of mass of the system moves with a constant velocity and exploring the relative coordinates of the bodies.
The problem presented pertains to a system of two bodies with masses m1 and m2 that experience a central attractive force. To formulate the problem, one needs to consider the motion of each body under the influence of the attractive force and the resulting dynamics of the system as a whole. The formulation should include the masses of the bodies, the nature of the attractive force, and the initial conditions of the system.
By analyzing the problem, it can be shown that the center of mass of the system moves with a constant velocity. The center of mass represents the average position of the two bodies and is unaffected by the internal forces between them. The constant velocity of the center of mass arises due to the conservation of momentum in the system.
The relative coordinates of the bodies are also important in understanding the dynamics of the system. The relative coordinates describe the position of one body with respect to the other. By examining the relative coordinates, one can analyze the relative motion of the bodies and gain insights into their interaction and behavior.
The unique keywords in the explanation are "central attractive force," "center of mass," "constant velocity," and "relative coordinates." These terms highlight the central concepts in formulating and analyzing the problem of two bodies subjected to an attractive force, focusing on the motion of the center of mass and the relative positions of the bodies.
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If acceleration of a body starting from the rest is 0.5m/s^2 how long will it take the body to travel 400m(if u are genius answer this)
Answers
Answer:
pls I don't understand it
Explanation:
can you follow me pleaee??
How to integrate 1/ 1 + x2
Answers
The integral of 1/(1 + x²) is (1/2)ln|1 + x²| + C where C is the constant of integration.
Integration is a mathematical process of finding the antiderivative of a function. To integrate the given expression 1/(1 + x²), we will use the substitution method.
Let u = 1 + x², du/dx = 2x dx, then dx = du/2x and the integral becomes:
∫1/(1 + x²) dx = ∫1/u * (1/2x) du= (1/2)∫1/u du
The antiderivative of 1/u is ln|u| + C, where C is the constant of integration.
Therefore, the final solution of the integral is (1/2)ln|1 + x²| + C.
Let us work through the steps:
Step 1:Let u = 1 + x² and then differentiate both sides with respect to x to obtain du/dx. du/dx = 2x
Substitute 2x dx = du into the integral ∫1/(1 + x²) dx to get the integral in terms of u:∫1/u * (1/2x) du = (1/2) ∫1/u du
Step 2:Calculate the antiderivative of 1/u, which is ln|u|. Thus, the final solution is (1/2)ln|1 + x²| + C, where C is the constant of integration. The constant C will vary depending on the initial conditions of the problem.
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PLEASE HELP WILL GIVE 20 POINTS TO THE ANSWER!!! A 3000 kg car is moving east at 15 m/s with
another 2200 kg car moving west at 10 m/S
If the 2 cars collide and stick together, what speed and direction will they travel?
Answers
Answer:
4.42 m/s EAST
Explanation:
Conservation of Momentum Law: total momentum before the collision must equal the total momentum after the collision.
Momentum = P = mv
East is the positive direction.
(3000 kg)(15 m/s) - (2200 kg)(10 m/s) = (3000 kg + 2200 kg)v
45,000 kg·m/s - 22,000 kg·m/s = (5200 kg)v
23,000 kg·m/s = (5200 kg)v
v = (23,000 kg·m/s) / 5200 kg = 4.42 m/s EAST
The direction is east because the final velocity is (+)
select all the correct answers:what happens to water when it changes to icea: density increasesb: density decreasesc: mass increasesd: mass decreasese: volume increases f: volume decreases
Answers
Answer:
b: density decreases
e: volume increases
Explanation:
When the water changes to ice, there won't be a loss of water, so the mass will be the same. However the ice will occupy more space, so the volume will increase. Then, since density is the mass divided by the volume, if the volume increase and the mass stays the same, the density decreases.
So, the answers are:
b: density decreases
e: volume increases
Which of the following types of mirrors refracts light rays that pass through it outward and away from the optical axis?
convex mirrors
plane mirrors
concave mirrors
All of the choices are correct.
Answers
Answer:
convex mirror
Explanation:
A convex mirror or diverging mirror is a curved mirror in which the reflective surface bulges towards the light source. Convex mirrors reflect light outwards, therefore they are not used to focus light.
what advantage is there to making graduated cylinders tall and thin rather
Answers
The thin and tall design of graduated cylinders allows for improved precision at smaller volumes. The volume markers on the glass would be incredibly close together and challenging to read for lesser volumes if the cylinder was short and fat.
A graduated cylinder, also known as a measuring cylinder, is typically employed in laboratories where reasonably accurate volume measurements are needed. It has volume measuring indications and is cylindric and thin. It is employed to measure the mass of a solid in addition to the volume of a liquid. A succession of lines will be drawn on the graduated cylinder to indicate various measurement intervals. While intermediate markings won't have numbers, some lines will be marked with them. Since the measurement intervals on smaller graduated cylinders are often narrower, they measure more precisely.
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What electromotive force would cause 200 mA of current to flow through a 500ohm resistor? 250 V (B) 10kV 2. 5kV (D) 100 V
Answers
The electromotive force would cause 200 mA of current to flow through a 500ohm resistor is (D) 100 V.
The electromotive force that would cause 200 mA of current to flow through a 500 ohm resistor is 100 V. This can be determined using Ohm's law.Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them. Mathematically, Ohm's law is represented by the equation V = IR, where V is voltage, I is current, and R is resistance.To find the electromotive force, we can rearrange Ohm's law to be E = IR, where E is electromotive force. Substituting the given values, we have:E = (0.2 A)(500 Ω)E = 100 V .
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A 7.50 kg bowling ball moving6.42 m/s strikes a 1.60 kg bowlingpin at rest. After, the pin moves14.8 m/s at a -47.0° angle. Whatis the y-component of the ball'sfinal velocity?y-component (m/s)Enter
Answers
let the bowling ball initially is moving along the x-axis,
The whole process can be represented as,
Before the collision the net kinetic energy of the balls is,
\(K_{iy}=\frac{1}{2}\times m_1\times(v_1\cos (90^o))^2+\frac{1}{2}\times m_2\times(0)^2\)where the values of the variables are given as,
\(\begin{gathered} m_1=7.5\text{ kg} \\ v_1=6.42ms^{-1} \\ m_2=1.6\text{ kg} \end{gathered}\)As the value of cos(90) is zero.
Substituting the known values,
The value of the net kinetic energy with the velocity along the y-axis before the collision is,
\(K_{iy}=0\)The velocity of the second ball is at rest in the initial state, thus its value is taken as zero.
After the collision of the balls, the net kinetic energy is,
\(\begin{gathered} K_{fy}=\frac{1}{2}\times m_1\times(v^{\prime}_1\sin (\alpha))^2+\frac{1}{2}\times m_1\times(v^{\prime}_2\sin (-47^o))^2 \\ K_{fy}=\frac{1}{2}\times m_1\times(v_{1fy})^2+\frac{1}{2}\times m_1\times(v^{\prime}_2\sin (-47^o))^2 \end{gathered}\)Negative sign here indicating the direction of the final balls motion will be opposite to the each other.
The values of the variables are given as,
\(v^{\prime}_2=14.8ms^{-1}\)Substituting the known values,
The value final kinetic enegry of the balls with velocity along the y-axis is,
\(\begin{gathered} K_{fy}=\frac{1}{2}\times7.5\times(v_{1fy})^2+\frac{1}{2}\times1.6\times(14.8\times\sin (360^o-47^o)^2 \\ K_{fy}=3.75\times(v_{1fy})^2-93.72 \end{gathered}\)Here 360 degree is used because the pin ball direction is downward of the positive x-axis.
Then by the law of conservation of energy along the y-axis,
\(\begin{gathered} K_{iy}=K_{fy} \\ 0=3.75\times(v_{1fy})^2-93.72 \\ (v_{1fy})^2=\frac{93.72}{3.75} \\ (v_{1fy})^2=25 \\ v_{1fy}=5ms^{-1} \end{gathered}\)Thus, the y component of the final velocity of the bowling ball of mass m1 is 5 meter per second.
An appliance is in a room repeatedly making the same sound all day. As the room heats up from 25 degrees Celsius to 35 degrees Celsius, what changes?
A. The sound wave's velocity decreases
B. The sound wave's frequency decreases
C. The sound wave's frequency increases
D. The sound wave's velocity increases
Answers
An appliance is in a room repeatedly making the same sound all day. As the room heats up from 25 degrees Celsius to 35 degrees Celsius is
B) The sound wave's frequency decreases
As the temperature of the room increments, the speed of sound waves within the discussed increments.
In any case, the recurrence of the sound wave created by the machine remains steady. This implies that the wavelength of the sound wave changes as the speed of the wave changes.
Agreeing with the wave condition, the speed of a wave is rise to its recurrence increased by its wavelength.
Subsequently, in the event that the speed of the wave increments and the recurrence remains steady, the wavelength must diminish. This results in a diminish within the recurrence of the sound wave, making it lower pitched.
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Answer:
Its A the other person is wrong
Explanation:
Give two examples of common units for each of the above measurements 3cm, 5cm, 10cm, and the mass is 180g
Answers
Answer:
rrrrrrrrrrrr42rtwqr
Explanation:
ddddddddddddddddddddddddddeqret
how would you use measure the length of a shoe
Answers
Have a good day
Kinetic energy can be used to drive motors and do other useful things. If a mole of hydrogen and a mole of deuterium underwent this fusion reaction, how much kinetic energy would be generated?.
Answers
The total amount of kinetic energy would be 9 x 10^10 J. The difference in mass between the reactants and productd is Δm = 2.04539/1000 kg/mol.
The amount of energy generated per mole of the substance can be determined by the formula, E = Δmc².
Here, Δm is the difference in mass between the reactants and products. In this case, the reactants are one mole of hydrogen and one mole of deuterium.
The products are one mole of helium and energy.
The difference in mass between the reactants and products is given by,Δm = (mass of one mole of hydrogen + mass of one mole of deuterium) - (mass of one mole of helium)= (2.01588 + 4.03211) g/mol - 4.00260 g/mol= 2.04539 g/mol.
Therefore, Δm = 2.04539/1000 kg/mol.
Using this value and the speed of light, c = 3 x 10^8 m/s, the amount of energy generated per mole of the substance can be calculated as,
E = Δmc²= (2.04539/1000) x (3 x 10^8)²= 1.84185 x 10^14 J/mol.
The amount of kinetic energy generated can be determined by multiplying this value with the Avogadro's number, N_A = 6.022 x 10^23, which gives,Energy generated = E x N_A= 1.84185 x 10^14 J/mol x 6.022 x 10^23= 9 x 10^10 J
if a mole of hydrogen and a mole of deuterium underwent this fusion reaction, the total amount of kinetic energy would be 9 x 10^10 J.
If one mole of hydrogen and one mole of deuterium undergo fusion, the amount of kinetic energy generated is 9 x 10^10 J.
The amount of energy generated per mole of the substance is determined by calculating the difference in mass between the reactants and products using the formula, E = Δmc².
The kinetic energy generated can be used to drive motors and do other useful things.
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The uniform rods AB and BC weigh 24 ky and kg, respectively,and the small wheel at C is of negligible weight. If the wheel ismoved slightly to the right and then released, determine the veloc-360 mimity of pin B after rod AB has rotated through 90*.
Answers
The velocity of pin B after rod AB has rotated through 90* is vb = 3.2549 m/s.
What is Potential and Kinetic energy?
Potential energy is the energy that is stored in any item or system as a result of its location or component arrangement. The environment outside of the object or system, such as air or height, has no impact on it. In contrast, kinetic energy refers to the energy of moving particles inside a system or an item.
mass of rod, mab = 2.4kg
mass of rod, mbc = 4kg
conservation of energy
\(T_{1} + V_{1} = T_{2} + V_{2}\)
\(h_{ab} = h_{bc} = 0.18m\)
potential energy at position 1,
\(V1 = m_{ab} gh_{ab} + m_{bc} gh_{bc}\)
V1 = 2.5 * 9.81 * 0.18 + 4 * 9.81 * 0.18
V1 = 11.30112
kinetic energy T1 at position 1 is zero
potential energy at position 2 is zero
K.E at position 2,
\(T_{2} = \frac{1}{2} l_{ab} w^{2}_{ab} + \frac{1}{2} m_{bc} v^{2}_{G} + \frac{1}{2} lw^{2}_{bc}\)
\(l_{ab} =\frac{m_{ab} l^{2}_{ab} }{3}\)
= 1/3 *4 * (0.36)²
=0.10368kg m²
\(l =\frac{m_{bc} l^{2}_{bc} }{12}\)
= 1/12 *4 * (0.6)²
=0.12kg m²
on putting the values in above equation we get,
T₂ = 1.0667vb²
0 + 11.30112 = 1.0667vb² + 0
vb = 3.2549 m/s
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if thermonuclear fusion starts, then the protostar becomes group of answer choices a main sequence star a binary system a white dwarf and then a red giant star. coal and carbon sink
Answers
If thermonuclear fusion starts, the protostar becomes a main sequence star, then eventually a red giant.
When thermonuclear fusion starts in the core of a protostar, the intense heat and pressure cause it to begin emitting light and energy. This marks the protostar's transformation into a main sequence star. The star will continue fusing hydrogen into helium in its core for billions of years, until it exhausts its hydrogen fuel.
At this point, the star will expand into a red giant, burning through its outer layers before eventually shedding them. Depending on the mass of the star, it may undergo further stages of evolution, such as becoming a planetary nebula or even a white dwarf. The terms "coal and carbon sink" are not directly related to this process, but may refer to geological or environmental processes involving carbon storage.
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When negative charges concentrate at one end of an object that is made of a conducting material, the object is
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ANSWER:
polarized
STEP-BY-STEP EXPLANATION:
When negative charges are concentrated at one end of an object that is made of a conductive material, this happens when the object is polarized.
In Material Science, If The Material Is Linearly Elastic, The Stress And Strain Are Directly Related To The Equation Below: E=Εσ
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As long as the applied stress is removed, a material that is linearly elastic experiences stress and strain that are directly proportional within the elastic limit.
In a material that is linearly elastic, the Young's modulus (E), stress, and strain are all related by the equation you supplied, E =. Here is a quick definition of each phrase:
(E) Young's modulus It is a way to gauge how hard or stiff a material is. Within the elastic limit of the material, it indicates the stress to strain ratio. The stiffer the material, the higher the Young's modulus.
Stress (): The force exerted to a material's surface area is called stress. The internal resistance of a material to deformation under an applied force is measured by stress.
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117. an am radio transmitter radiates 500 kw at a frequency of 760 khz. how many photons per second does the emitter emit?
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At a frequency of 760 kHz, an AM radio transmitter emits 500 kilowatt of energy. Therefore, the AM radio transmitter produces about 9.927 x 10²⁴ photons per second.
To determine the number of photons emitted per second by an AM radio transmitter, we can use the relationship between power and energy of a photon.
The energy of a photon (E) can be calculated using Planck's equation:
E = hf
where h is Planck's constant (approximately 6.626 x 10⁻³⁴ J·s) and f is the frequency of the radiation.
In this case, the frequency is given as 760 kHz, which can be converted to Hz:
f = 760 kHz = 760,000 Hz
Now we can calculate the energy per photon:
E = (6.626 x 10⁻³⁴ J·s) * (760,000 Hz)
E = 5.036 x 10⁻²⁵ J
Now we can determine the number of photons emitted per second by dividing the power radiated by the energy per photon:
Power radiated = 500,000 W
\(\begin{equation}\text{Number of photons emitted per second} = \frac{500,000 \text{ W}}{5.036 \times 10^{-25} \text{ J}}\)
Number of photons emitted per second ≈ 9.927 x 10²⁴ photons/s
Therefore, the AM radio transmitter emits approximately 9.927 x 10²⁴ photons per second.
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A car of mass 800 kg goes round a corner of radius 65 m at a
speed of 10 m/s
b) Suggest how this force is likely to be obtained.
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Answer:
Centrifugal force = 1230.77 Newton.
Explanation:
The force associated with the car is generally referred to as centrifugal force and it can be calculated using the formula;
Centrifugal force = mv²/r
Given the following data;
Mass = 800kg
Radius = 65m
Velocity = 10m/s
To find the force;
Centrifugal force = (800*10²)/65
Centrifugal force = (800*100)/65
Centrifugal force = 80000/65
Centrifugal force = 1230.77 Newton.
A BUS TRAVELING AT 60KMHR-1 ACCELERATE UNIFORMLY AT 5MS-2 CALCULATE IT VELOCITY AFTER 2MINUTES
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The velocity after two minutes is v = 616.67 m/s
Using the equation final velocity = beginning velocity + acceleration * time, the final velocity of this bus after two minutes is determined. Symbolically, v is represented as follows: vi = 60 km/h, a = 5 m/s2, and t = 2 minutes. First, we must translate 60 km/h into m/s. 50/3 m/s is equal to 60 km/h or 60,000 m/36 seconds.
When determining the final velocity, v
v = vi + a * t
120 seconds at v = 50/3 m/s + 5 m/s2
v = 50/3 m/s + 600 m/s
v = 16.67 m/s + 600 m/s
v = 616.67 m/s
After two minutes, the bus's speed is 616.67 m/s. For a bus, it is a pretty implausible velocity. The speed of this object is 2,220 km/h, exceeding the speeds of both air and jet aircraft. Your acceleration time should have been capped at 20 seconds or less.
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do you think humans might be useful as index fossils in the future. Explain.
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Index fossils are fossils that are used to help determine the relative age of rock layers and sedimentary strata. They are typically small, widely distributed organisms that lived for a relatively short period of time and are characteristic of a specific geological period. Index fossils are useful because they can help geologists and paleontologists to determine the relative age of rock formations and to understand the Earth's geological history.
It is unlikely that humans would be useful as index fossils in the future, as the time period during which humans have existed on Earth is relatively short compared to the age of the Earth as a whole. In addition, humans are not small, widely distributed organisms like many of the commonly used index fossils. Instead, humans are large, highly adapted organisms that have a wide range of habitats and are found on most of the continents.
However, it is possible that artifacts or other remains associated with human activity could be used as index fossils in the future. For example, the presence of certain types of tools or other materials might be used to help determine the relative age of a site or to understand the environmental conditions and human activity in a particular region at a specific point in time.
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