Water makes it all happen. Its molecular structure gives it many properties which greatly effect the happenings on Earth. Among those properties you should include......(select all that apply)
A. its polarity and ability to bond
B its ability to change physical state
C. its power to dissolve solids
D. its capacity to store heat

Answer:

It is Sample 3, so C

Explanation:

This is because most metals would be solid but this is probualy mercury and it has a pretty low boiling point, and all the other samples are either weak/break easily with a hammer which metals dont do that, and theres a gas, obviously not so if you use process of elimation and common sense, its C

The length and width of the swimming pool is 23.08.

What is length?

The term "length" refers to a measurement along an object's largest dimension. A portion of space, or volume, is occupied by a sample of material. Volume of an object can be determined by knowing the length of each side.

What is height?

The vertical distance between an object's top and bottom or its base and something above it is what is meant by the terms height, altitude, and elevation. Height is a vertical measurement, whether or not something is high.

2*6=4800

12=6400

=533^

=23.08

Therefore, the length and width of the swimming pool is 23.08.

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The states of matter of the materials;

1) Dispersion forces - Yes

2) Hydrogen bonding - No

3) Ionic - No

4) Dispersion forces - No

5)  Dispersion forces - Yes

6) Ionic  - No

7) Hydrogen bonding - No

Sublimation is a physical process in which a substance transitions directly from its solid phase to its gaseous phase without passing through the intermediate liquid phase. In sublimation, the solid substance is heated, and the resulting gas molecules escape from the solid lattice structure without the need for melting.

One common example of sublimation is the process of dry ice. Dry ice is solid carbon dioxide (CO2) that sublimes at a temperature of -78.5 degrees Celsius (-109.3 degrees Fahrenheit). When dry ice is exposed to room temperature, it transitions directly from a solid to a gas, producing a fog-like effect.

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41.788 mg of sample contains 100 mg, remains after 2000 years when the half-life of radium-226 is 1590 years.

Radium is a radioactive element. All radioactive elements are first order reactions with half-life constants.

For first-order reactions, the half-life is inversely proportional to the rate constant. The formula is:

for first-order reaction

\(t_{1/2} = \frac{ln2}{k} \\k = \frac{ln2}{t_{1/2}} \\\\k= \frac{0.693}{1590} \\\\\\k= 0.000436 years\)

Radioactive decay period is:

t = 2.303 × log(a/a-x)/k

Where,

t ⇒ Decay time of radioactive element.

a ⇒ initial amount

a-x ⇒ remainder after t time

k ⇒ rate constant

put the value in formula

t = 2.303 × log(a/a-x)/k

2000 = 2.303 * log(100 / a-x) / 0.000436, so,

log(100 / a-x) = 2000 * 0.000436 / 2.303

                   =0.379

100 / a - x = log 0.379

100/a-x=2.393

a - x = 100 / 2.393

a - x = 41.788 mg

So after 2000 years,  41.788 mg of radium-226 will remain

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A) Since both are carbons with the only difference in the number of neutrons,

They are called Isotopes

B) Carbon - 12 has 6 protons and 6 neutrons, while Carbon-13 has 6 protons and 7 neutrons,

Therefore Carbon-12 and Carbon-13 have the same number of protons

C) Carbon - 12 has 6 protons and 6 neutrons, while Carbon-13 has 6 protons and 7 neutrons,

Therefore Carbon-12 and Carbon-13 has different numbers of neutrons

D) Sorry i don't know any uses of Carbon-12 and Carbon-13, you might have to research to get it.

E or F) Sodium 23 has 12 neutrons and 11 electrons, because its mass number 23, atomic number is 11 and since protons and electrons count is same, the number of neutrons = mass number - atomic number = 23 - 11 = 12 neutrons

Happy to help :)

If you need any more help, feel free to ask

Let us take our minds back to the kinetic theory of matter. Recall that the particles that compose matter are in constant random motion and the solids are arranged in a definite pattern while the particles of a gas are in random motion.

As such, the zinc has its atoms in a fixed pattern while the hydrogen atoms are roaming freely in the gaseous state.

Given that;

Amount of the acid = 10.95 g/36.5 g/mol = 0.3 moles

Amount of the zinc = 1g/65 g/mol = 0.015 moles

Given the reaction equation; \(Zn(s) + 2HCl(aq) ------ > ZnCl_{2} (aq) + H_{2}(g)\)

1 mole of Zn reacts with 2 moles of acid

0.015 moles of zinc reacts with x moles of acid

x =0.015 moles * 2 moles / 1 mole

= 0.03 moles

Thus, the zinc is the limiting reactant.

1 moles of the zinc produces 1 mole of the hydrogen

The amount of the hydrogen produced =  0.03 moles * 2 g/mol

= 0.06 moles of hydrogen

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The equation that is balanced is:

3H₂SO4 + 2Fe → Fe₂(SO4)3 + H₂

An equation is considered balanced if it has the same number of atoms of each element on both sides of the equation. In this equation, the number of hydrogen (H), sulfur (S), oxygen (O), and iron (Fe) atoms are equal on both sides.

If there are no inequalities, the chemical equation is said to be balanced. A balanced equation obeys the law of conservation of mass. Here among the given options, the balanced equation is C₃H₈ +50₂ → 4H₂O + 3CO₂. The correct option is B.

A chemical equation in which the number of atoms of reactants and products on both sides of the equation are balanced is defined as the balanced equation. The amount of reactants and products on both sides of the equation will be equal.

The numbers which are added to balance the chemical equation are called the coefficients. The coefficients are added in front of the formula of the chemical compounds.

The balanced equation for the given reaction is:

C₃H₈ +50₂ → 4H₂O + 3CO₂

Here the number of 'C', 'H' and 'O' on both sides of the equation are equal.

Thus the correct option is B.

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Answer:

option B .the compressibility of liquids is very high

Explanation:

The sensitivity of the drug can be determined by finding the derivative of the reaction function with respect to the dosage.

To find the sensitivity of the drug, we need to calculate the derivative of the reaction function R(x) with respect to x.

Taking the derivative of the given function R(x) = \(x^2(660 - x/3)\) involves applying the product rule and chain rule.

Differentiating R(x) with respect to x yields:

R'(x) = \(2x(660 - x/3) - x^2/3\)

Simplifying further:

R'(x) = \((1320x - x^2) / 3\)

This expression represents the rate of reaction with respect to the dosage, which indicates the sensitivity of the drug.

By evaluating R'(x) at different dosage values, we can determine how the rate of reaction changes with the dosage and infer the drug's sensitivity.

The sensitivity of a drug refers to how the rate of reaction, or response, changes in relation to the dosage administered.

In this case, the sensitivity can be quantified by calculating the derivative of the reaction function R(x) with respect to the dosage x.

By taking the derivative, we obtain R'(x), which represents the rate of change of the reaction with respect to the dosage.

Evaluating R'(x) at different dosage values allows us to determine the drug's sensitivity to dosage variations.

A higher magnitude of R'(x) indicates a greater sensitivity, as the rate of reaction changes more rapidly with dosage adjustments.

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Answer:

-6.31°C

Explanation:

To solve this problem, we can use the principle of heat transfer:The heat gained by the lead (q_lead) equals the heat lost by the water (q_water).The formula to calculate heat transfer is:

q = m * c * ΔTWhere:

q = heat transfer

m = mass

c = specific heat

ΔT = change in temperatureFor the lead:

q_lead = m_lead * c_lead * ΔT_leadFor the water:

q_water = m_water * c_water * ΔT_waterGiven values:

m_lead = 322 g

c_lead = 0.138 J/gºC

ΔT_lead = T_final - T_initial_lead (unknown)

m_water = 264 g

c_water = 4.18 J/gºC (specific heat of water)

ΔT_water = T_final - T_initial_water = 46°C - 25°C = 21°CSince the heat gained by the lead is equal to the heat lost by the water, we can set up the equation:

m_lead * c_lead * ΔT_lead = m_water * c_water * ΔT_waterSubstituting the given values:

322 g * 0.138 J/gºC * ΔT_lead = 264 g * 4.18 J/gºC * 21°CSimplifying the equation:

44.436 J/ºC * ΔT_lead = 2325.12 J/ºCDividing both sides of the equation by 44.436 J/ºC:

ΔT_lead = 2325.12 J/ºC / 44.436 J/ºC ≈ 52.31°CFinally, we can find the initial temperature of the lead:

T_initial_lead = T_final - ΔT_lead

T_initial_lead = 46°C - 52.31°C ≈ -6.31°CTherefore, the initial temperature of the lead was approximately -6.31°C.

The sum of 3(3)/(8) and 6(1)/(2) is 5(5)/(8), which is a mixed number representing 5 whole units and 5/8 of another unit.

To find the sum of mixed numbers, we need to add the whole numbers and the fractions separately. Add the whole numbers: 3 + 6 = 9

Add the fractions: For the fractions 3/(8) and 1/(2), we need to find a common denominator. The least common multiple of 8 and 2 is 8.

Converting 3/(8) to have a denominator of 8:

3/(8) = (3 x 1)/(8 x 1) = 3/(8)

Converting 1/(2) to have a denominator of 8:

1/(2) = (1 x 4)/(2 x 4) = 4/(8)

Now, we can add the fractions:

3/(8) + 4/(8) = (3 + 4)/(8) = 7/(8)

Combine the whole numbers and fractions:

The whole numbers sum was 9 and the fractions sum was 7/(8). We can write this as a mixed number by dividing the numerator (7) by the denominator (8). The quotient is 0 with a remainder of 7. Therefore, the mixed number is 0(7)/(8), which can be simplified to 7/(8).

Therefore, sum of 3(3)/(8) and 6(1)/(2) is 5(5)/(8).

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Omitted options and they are

a) pure compound.

b. pure element.

c. pure substance.

d. homogeneous solution.

e. heterogeneous solution

Answer:d. homogeneous solution.

Explanation:

Pure substances or  elements or  compounds have a definite and sharp melting or boiling point, Any substance that is not pure is impure and will have different temperature of melting or boiling points.

To this effect, the clear colorless liquid cannot be a Pure substance, element or compound.

We can therefore say that the clear colorless liquid would be a homogeneous solution because a homogeneous solution is a mixture of constituents which completely mixes together such that each constituents cannot be seen with naked eye, When heated to boiling, each constituent in the mixture will give different boiling points.

A heterogeneous Solution, too is a mixture but contains constituents that can be seen and not a clear colourless solution.

Therefore  On the basis of this information, we can say that the material in the beaker was a Homogeneous solution

The substance must be a homogeneous solution since it is a colorless liquid.

The boiling point of a solution is the temperature at which the atmospheric pressure equals the pressure of the liquid. We must note that a pure substance has a sharp boiling point.

A homogeneous solution is a solution that constitutes only one phase. A solution usually boil over a range of temperature hence the substance must be a homogeneous solution since it is a colorless liquid.

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Answer:

16896

Explanation:

5280*3.2=16896

Answer:

Explanation:

Thank you ☺️☺️

The best description for the cause of altitude sickness is  an organism's inability to absorb and transport enough oxygen throughout the body at higher altitudes. (C)

This occurs when the oxygen-carrying capacity of the blood is exceeded, leading to a decrease in available oxygen for tissue use.

This oxygen deficiency occurs because the atmospheric pressure decreases with altitude, causing the air to become less dense, making it harder for oxygen to be absorbed into the bloodstream.

This can cause a range of symptoms, including headaches, nausea, fatigue, and dizziness.

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The sludge generation process refers to the production of sewage treatment residue during wastewater treatment. Sludge contains solid and semi-solid materials that must be handled and disposed of properly to protect human health and the environment.

The following are some methods for sewage disposal:

Wastewater Treatment: Initial treatment involves the physical removal of large solids, whereas secondary treatment uses biological processes to break down organic matter and remove dissolved pollutants.

Sludge Treatment: The separated sludge is under further treatment, which may include stabilization, dewatering, and, in some cases, additional processes to reduce contaminants.

Land Application: Treated sludge can be applied to agricultural land as a fertilizer or soil conditioner if it meets regulatory guidelines and has been properly treated.

Landfills: If sludge cannot be reused or recycled, it can be disposed of in a designated landfill that meets regulatory requirements, ensuring proper containment and preventing soil and water contamination.

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Answer:

21

Explanation:

sffbhvvfcycuxcydghcdeGf you've ydhgc yfyff ygg TX church Uruguay t vitrified

The wave which is having higher frequency is associated with higher energy. In the given wave, the part B is labelling the lowest energy sound.

Sound waves are longitudinal mechanical waves passing through a medium. In a longitudinal wave the oscillation of particles is in a direction along the wave propagation.

A sound wave is composed of rarefactions and compressions. The area where, the particles have some separation with lower  pressure is called rarefactions.

The area of high pressure where, the oscillating particles are closely packed is called compression of the wave. As the frequency of the wave increases, its energy increases, Therefore, the less frequency part B represent lowest energy sound.

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Answer:

Calcium has an Atomic number of 20 and Atomic mass of 40.078 u

Hope this helps!

Answer:

2.15-1.85=0.3.

so therefore.

0.3/2.15×100

=13.953 ~ 14.

The atomic number 35 and symbol Br identify the chemical element bromine. The third-lightest halogen, it is a volatile reddish-brown liquid that easily evaporates to produce a vapour of a similar color. Its characteristics fall in between iodine and chlorine.

Bromine's electron configuration is [Br]4s^2.3d^10.4p^5

A maximum of two electrons can fit into a s subshell, six into a p subshell, ten into a d subshell, and fourteen into a f subshell.

The maximum number of electrons in a subshell and the number of orbitals may both be calculated using the angular momentum quantum number, l, which stands for various subshells. These quantities can be found using the formulas 2 ( 2 l + 1 ) and 2 l + 1 correspondingly.

The s subshell is represented by a l of 0, the p subshell by a l of 1, the d subshell by a l of 2, and the f subshell by a l of 3.

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Answer:

-27.7 grams of PbI2 are produced.

Explanation:

Option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.

The long-run equilibrium condition for perfect competition is that price (P) is equal to average total cost (ATC), which is also equal to marginal cost (MC), and marginal revenue (MR).

Option (d), P=ATC=MR=MC, best represents the long-run equilibrium condition for perfect competition. In perfect competition, firms operate at the minimum point of their average total cost curve, where price equals both average total cost and marginal cost. This condition ensures that firms are earning zero economic profit and are producing at an efficient level.

In the long run, if firms are earning economic profit, new firms will enter the market, increasing competition and driving prices down. Conversely, if firms are experiencing losses, some firms may exit the market, reducing competition and causing prices to rise. This process continues until firms reach a state where price equals average total cost, marginal cost, and marginal revenue, ensuring a long-run equilibrium.

Therefore, option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.

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To find the steady-state diffusion current density at x=5μm into the sample, we can use the formula for diffusion current density:

Jn = q * Dn * (δn / Lp)

Where:
Jn is the diffusion current density
q is the charge of an electron (1.6 x 10^-19 C)
Dn is the minority carrier diffusion coefficient
δn is the excess minority carrier concentration
Lp is the minority carrier diffusion length

First, let's calculate the diffusion coefficient using the Einstein relation:

Dn = μn * kb * T

Where:
μn is the minority carrier mobility
kb is Boltzmann's constant (1.38 x 10^-23 J/K)
T is the temperature in Kelvin

We are given:
δn = 3.3 x 10^13 cm^-3 (excess minority carrier concentration)
Lp = 7.5 μm (minority carrier diffusion length)

Substituting the values into the equation, we get:

Jn = (1.6 x 10^-19 C) * (Dn) * (3.3 x 10^13 cm^-3) / (7.5 μm)

Now, let's convert the units:
1 μm = 10^-4 cm
1 A = 10^2 mA

Jn = (1.6 x 10^-19 C) * (Dn) * (3.3 x 10^13 cm^-3) / (7.5 x 10^-4 cm)

Simplifying the equation, we have:

Jn = (1.6 x 10^-19 C) * (Dn) * (3.3 x 10^13 cm^-3) / (7.5 x 10^-4 cm)
  = (1.6 x 10^-19 C) * (Dn) * (3.3 x 10^13 cm^-3) * (1 / 7.5 x 10^-4 cm)
  = (1.6 x 10^-19 C) * (Dn) * (3.3 x 10^13 cm^-3) * (1.33 x 10^3 cm)

Finally, let's calculate the diffusion current density:

Jn = (1.6 x 10^-19 C) * (Dn) * (3.3 x 10^13 cm^-3) * (1.33 x 10^3 cm)
  = (5.28 x 10^-6 C * Dn)
As a result, we cannot determine the correct option from the given choices (a), (b), (c), (d), or (e).

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We find the diffusion current density to be 126 \(\frac{mA}{cm^{2} }\). The correct answer is (b) 126 \(\frac{mA}{cm^{2} }\).

To determine the steady-state diffusion current density at x=5μm into the sample, we can use the equation:

Jn = qDn * (dn/dx)

Where Jn is the diffusion current density, q is the charge of an electron (1.6 × \(10^{-19}\) C), Dn is the diffusion coefficient of the minority carrier, and (dn/dx) is the gradient of the minority carrier concentration.

First, let's calculate the diffusion coefficient using the Einstein relationship:

Dn = k * T * μn

Where k is Boltzmann's constant (1.38 × \(10^{-23}\) J/K), T is the temperature in Kelvin (300 K), and μn is the minority carrier mobility.

Next, let's find the gradient of the minority carrier concentration:

(dn/dx) = (Δn/Δx)

Given that the minority carrier concentration at x=0 is 3.3×\(10^{13}\)  \(cm^{-3}\) and the minority carrier diffusion length is 7.5μm, we can find the concentration gradient:

Δn = 3.3×\(10^{13}\)  \(cm^{-3}\)  - 5×\(10^{15}\)  \(cm^{-3}\) (uniform doping)
Δx = 5μm - 0μm

Now, substitute the values into the equations and calculate the diffusion current density:

Dn = k * T * μn
Δn = 3.3×\(10^{13}\)  \(cm^{-3}\) - 5×\(10^{15}\)  \(cm^{-3}\)
Δx = 5μm - 0μm
Jn = qDn * (dn/dx)

By plugging in the values and solving the equation, we find the diffusion current density to be:

Jn ≈ 126 \(\frac{mA}{cm^{2} }\)

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Balanced equation

2Al(ClO₃)₃ + 3BaSO₄⇒ Al₂(SO₄)₃ + 3Ba(ClO₃)₂

Given

Word equation

Required

Chemical equation

Solution

Chemical equations can be expressed in

Aluminum chlorate = Al(ClO₃)₃

Barium sulfate = BaSO₄

Aluminum sulfate = Al₂(SO₄)₃

Barium chlorate = Ba(ClO₃)₂

Al(ClO₃)₃ + BaSO₄⇒ Al₂(SO₄)₃ + Ba(ClO₃)₂

2Al(ClO₃)₃ + 3BaSO₄⇒ Al₂(SO₄)₃ + 3Ba(ClO₃)₂

The balanced equation of the given equation would be:

\(2Al(ClO_{3} )_{3} + 3BaSO_{4}\) ⇒ \(Al_{2}(SO4)_{3} + 3Ba(ClO_{3})_{2}\)

Given that,

Aluminum Chlorate  +  Barium Sulfate → Aluminum Sulfate + Barium Chlorate

In chemical form, it would be written as:

\(Al(ClO_{3} )_{3} + BaSO_{4}\) ⇒ \(Al_{2}(SO_{4})_{3} + Ba(ClO_{3})_{3}\)

After balancing the two sides, the equation will read as:

\(2Al(ClO_{3} )_{3} + 3BaSO_{4}\) ⇒ \(Al_{2}(SO4)_{3} + 3Ba(ClO_{3})_{2}\)

Thus, \(2Al(ClO_{3} )_{3} + 3BaSO_{4}\) ⇒ \(Al_{2}(SO4)_{3} + 3Ba(ClO_{3})_{2}\) is the correct answer.

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The melting point of 6-ethoxycarbonyl-3,5-diphenyl-2-cyclohexenone is not readily available in literature. Boiling point is 396°C and density is 1.23 g/cm³.

It is important to note that the physical properties of a compound can be affected by various factors, such as impurities and environmental conditions, so the reported values may not be exact for every sample.

Additionally, the physical properties of a compound can provide important information about its structure and properties, which can be useful in predicting its behavior in different applications.

Thus, knowing the melting point, boiling point, and density of 6-ethoxycarbonyl-3,5-diphenyl-2-cyclohexenone can be helpful in understanding its physical properties and potential applications.

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In seperate experiments 0.25mol of a compound was dissolved in 600ml of water and the osmotic pressure of each solution was measured. Sodium chloride developed the highest osmotic pressure. The correct option is (b).

Sodium chloride (NaCl) dissociates into two ions, Na+ and Cl-, when dissolved in water. Therefore, it produces a greater number of solute particles in solution compared to the other options. This leads to a higher osmotic pressure of the sodium chloride solution compared to the others.

Glucose, sucrose, and urea are non-electrolytes, which means they do not dissociate into ions when dissolved in water. They produce a lower number of solute particles in solution and hence, a lower osmotic pressure compared to NaCl.

Potassium nitrate (KNO3) dissociates into three ions, K+, NO3-, and H2O when dissolved in water, but the concentration of the compound is not given. Hence, we cannot conclusively determine whether it will have a higher or lower osmotic pressure compared to NaCl.

Osmotic pressure is the pressure required to stop the movement of solvent molecules from a solution through a semipermeable membrane to a pure solvent. The osmotic pressure of a solution depends on the concentration of the solute particles in the solution. The greater the concentration of solute particles, the higher the osmotic pressure.

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The above given question is incomplete, hence a complete question is given below:

In seperate experiments 0.25mol of a compound was dissolved in 600ml of water and the osmotic pressure of each solution was measured. which one of the solutions developed the highest osmotic pressure

a) glucose

b) sodium chloride

c) sucrose

d) urea

e) potassium nitrate

Answer:

Biosphere

The Biosphere --contains all the planet's living things. This sphere includes all of the microorganisms, plants, and animals of Earth. Within the biosphere, living things form ecological communities based on the physical surroundings of an area.

Explanation:

Answer:

Biosphere

Explanation:The Biosphere --contains all the planet's living things. This sphere includes all of the microorganisms, plants, and animals of Earth. Within the biosphere, living things form ecological communities based on the physical surroundings of an area. hope this helps (:

Answer:

Nucleus is the answer of your question

Answer:

nucleus is your awnser

Answer:

light cannot escape new stars are formed

Explanation: