We have seen that an electric fi eld must exist inside a conductor that carries a current. How is that possible in view of the fact that in electrostatics we concluded that the electric fi eld must be zero inside a conductor

Answers

Answer 1

An electric field exists inside a current-carrying conductor due to electromagnetism.

How does electromagnetism create electric fields in conductors?

Inside a conductor that carries a current, the existence of an electric field is possible due to the principles of electromagnetism, which differ from those of electrostatics. In electrostatics, the electric field inside a conductor is zero because any electric field that initially exists inside the conductor will induce charges to redistribute until an equilibrium is reached, canceling out the electric field.

However, when a current flows through a conductor, the motion of charged particles creates a magnetic field around the conductor, according to Ampere's law. This changing magnetic field, in turn, induces an electric field within the conductor, according to Faraday's law of electromagnetic induction. Therefore, inside a conductor carrying current, the electric field is no longer zero but exists due to the interplay of electric and magnetic fields.

In electromagnetism, the presence of an electric field inside a conductor carrying current can be explained by the interplay between electric and magnetic fields. Understanding the concept of electromagnetic induction and the laws governing the behavior of electric and magnetic fields within conductors can provide further insight into this phenomenon.

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Related Questions

How long will it take for a body
accelerating by 2 m/s² to gain a
velocity of 10 m/s, starting from rest.

Answers

We are given:

Initial velocity (u) = 0 m/s            [starting from rest]

Final velocity (v) = 10 m/s

Acceleration (a) = 2 m/s²

Time taken = t

Solving for time taken:

v = u + at             [first equation of motion]

10 = 0 + (2)(t)       [plugging the values]

10 = 2t

t = 5 seconds

BRAINLIEST : A car starts from rest and accelerates at a rate of 40 m/s2 over a time if 2.4 s. How fast is the car going at the end of this time interval?

Please explain

Answers

Answer:

\(\boxed {\boxed {\sf 96 \ m/s}}\)

Explanation:

We are asked to find the final velocity of the car given the acceleration and time. We can use the following kinematics equation to calculate the final velocity.

\(v_f=v_i+(a \times t)\)

The car starts from rest, so the initial velocity is 0 meters per second. It accelerates a rate of 40 meters per square second over a period of time of 2.4 seconds.

\(v_i\)= 0 m/s a= 40 m/s²t= 2.4 s

Substitute the values into the formula.

\(v_f= 0 \ m/s + ( 40 \ m/s^2 \times2.4 \ s)\)

Solve inside the parentheses.

40 m/s/s * 2.4 s = 40 m/s * 2.4=96 m/s

\(v_f= 0 \ m/s + (96 \ m/s)\)

Add.

\(v_f= 96 \ m/s\)

The final velocity of the car is 96 meters per second.

is the bulk mean temperature of 25°c for air a good assumption?

Answers

A bulk mean temperature of 25°C for air can be considered a reasonable assumption in many cases, but it depends on the specific context and location.

The assumption of a bulk mean temperature of 25°C for air can be a reasonable approximation in certain scenarios. However, it is important to note that air temperatures vary significantly based on factors such as geographic location, time of year, and local climate patterns. In some regions and during certain seasons, an average temperature of 25°C might be quite accurate.

For example, in tropical regions or during summer months in temperate areas. However, in other locations or during different seasons, this assumption may not hold true. In colder climates or during winter months, the average air temperature could be significantly lower than 25°C. Similarly, in hotter regions or during heatwaves, the average temperature might be considerably higher. Therefore, when considering the bulk mean temperature of air, it is essential to take into account the specific circumstances and obtain accurate data for the particular location and time period of interest.

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How long indicates your looking for what?
O distance
O speed
time

Answers

We are looking for Distance. Distance in physics is understood as the speed of an object multiplied by the total time taken by the object to travel the length of its path.

What is Distance?

The units for each variable must be consistent with one another in order to accurately calculate the distance. For instance, if the distance is being calculated in terms of meters, the speed should be recorded in meters per unit of time.

Without taking into account direction, distance measures the length between two points or objects. Distance is a scalar property, which means it simply considers the overall magnitude and does not take start or endpoints into account.

The meter (m) is the commonly used unit of measurement for distance, but greater distances can also be expressed in kilometers (km), and smaller distances can be expressed in centimeters (cm) or millimeters (mm).

Therefore, We are looking for Distance. Distance in physics is understood as the speed of an object multiplied by the total time taken by the object to travel the length of its path.

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In beams with circular cross sections, transverse shear stress acts parallel to the y axis over the entire depth of the shape.
a. true
b. false

Answers

The given statement is that in beams with circular cross-sections, transverse shear stress acts parallel to the y axis over the entire depth of the shape.

The tension that develops as a result of the internal shearing of a beam as a result of a shear force applied to the beam is known as shearing stress.

One-half of the difference between the primary stresses is the maximum shear stress. It should be noticed that the primary planes equation, 2p, results in two angles between 0° and 360°.

The primary stresses brought on by bending are typical tension and compression stresses. However, the state of stress within the beam also includes large normal stresses caused by bending in addition to shear stresses caused by the shear force, even though the former is often of a lesser order than the latter.

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What is the only force that can act on an object in free fall? gravity friction air resistance speed

Answers

Answer: Gravity

Explanation:When the only force acting on an object is gravity, so no air resistance. the constant speed that a freely falling object eventually reaches when the resistance of the medium through which it is falling prevents further acceleration.

Answer: It is gravity!

Explanation:

how many types of classifications are there for a lunar eclipse?

Answers

There are three types of lunar eclipses: total, partial, and penumbral.

During a total lunar eclipse, the moon is completely shadowed by the Earth, resulting in a reddish-brown color. In a partial lunar eclipse, only a portion of the moon is shadowed, while in a penumbral lunar eclipse, the moon passes through the Earth's outer shadow, resulting in a subtle darkening of the moon's surface. These classifications are based on the degree to which the moon passes through the Earth's shadow during the eclipse.

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how do combination lens systems, such as compound microscopes and refracting telescopes, operate?

Answers

The combination of the compound microscopes and refracting telescopes, operate by magnifying the image.

How do they operate?

High levels of magnification are produced by the objective lens and eyepiece lens working together. Multiplying the objective lens' and the eyepiece lens' individual magnifications yields the microscope's overall magnification.

In a refracting telescope, the objective lens and eyepiece lens work together to produce high magnification, which makes distant objects look larger and more distinct to the spectator.

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A long, horizontal wire Ab rests on the surface of a table and carries a current I. A horizontal wire CD is vertically above wire AB , and is free to slide up and down on the two vertical metal guides C and D ( as shown in Fig) .Wire CD is connected through the sliding contacts to another wire that also carries a current I , opposite in direction to the current in wire AB . The mass per unit length of the wire CD is λ. To what equilibrium height h will the wire CD rise. assuming that magnetic force on it is wholly due to current in wire AB ?

Answers

The equilibrium height to which the wire CD will rise is given by the expression h = μ₀I² / 2π λg

What is magnetic field ?

A region in which the force of magnetism acts is known as the magnetic field, and it surrounds magnetic materials or a moving electric charge. Moving magnetic dipoles and electric charges produce a magnetic field, which acts as a force field on other nearby magnetic dipoles and moving charges.

Magnetic field at a distance h produced by a current carrying wire

B = μ₀I/ 2πh

Magnetic force due to the present current carrying wire can be calculated by the formula

F = B I  L

And we also know that F = mg

On equating these mg = B I L

( μ₀I/ 2πh ) I = ( m/ I ) g = λg

thus we get the value of h as

h = μ₀I² / 2π λg

Thus, the equilibrium height to which the wire CD will rise is given by the expression h = μ₀I² / 2π λg .

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Find the center of mass of the region bounded by y=9-x^2 y=5/2x , and the z-axis. Center of Mass = __?
Note: You can earn partial credit on this problem.

Answers

The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.

The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].

Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.

Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).

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Arun walked to his school which is at a distance of 3 km from his home in 35 min. On reaching, he finds that the school is closed and comes back by a bicycle with his friend and reaches home in 25 min. His average speed in km/h is ________. *​

Answers

Arun's average speed through out his journey is 6km/h.

Given the data in the question;

Distance from home to school; \(d_{hs} = 3km\)Time taken on foot; \(t_f = 35m = 0.583333hr\)Time taken on bike; \(t_b = 25min = 0.416667hr\)

Average speed = ?

Speed

When an object or particle moves along a path, the time rate at which that particle makes that movement is called speed.

Speed is expressed as:

\(Speed = \frac{distance\ traveled }{time\ elapsed}\)

Now, Total distance traveled by Arun will be;

Distance covered from home to school + school to home

\(d_T = 3km + 3km\\ \\d_T = 6km\)

Total time elapsed will be;

Time taken on foot + time taken on bike

\(t_T = 0.583333hr + 0.416667hr\\\\t_T = 1hr\)

We substitute our values into the expression

\(Speed = \frac{total\ distance\ traveled }{total \ time\ elapsed}\\\\Speed = \frac{6km}{1hr} \\\\Speed = 6km/hr\)

Therefore, Arun's average speed through out his journey is 6km/h.

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is nucleus found in animal cells

Answers

Answer:

yes nucleus is found in plant and animal cells.

Hope this helps :)

Se dispara una bala con una velocidad de v = 300[m/s] contra un cascarón esférico de papel que gira con MCU respecto a un eje vertical. Sabiendo que el radio del cascarón es de 10[cm]. Calcular la rapidez angular mínima que deberá girar el cascarón para que el proyectil haga únicamente un agujero. La dirección del movimiento de la bala pasa por el centro de la esfera.

Answers

Answer:

 w = 4.712 10⁻³ rad / s

Explanation:

For this exercise, the time it takes for the bullet to travel the distance of 2R must be equal to the time that the hole must travel half a circle.

Let's start by calculating the time it takes for the bullet, which is going at constant speed.

         v = x / t

         t = x / v

         t = 2R / v

         t = 2 0.10 / 300

         t = 6.666 10⁻⁴ s

As they ask that a single hole is formed in this time, it must be rotated half a circle, that is, θ =π rad, for which we use the angular scientific relations, where the shell has constant angular velocity

          w = θ / t

          w = π / 6,666 10⁻⁴

          w = 4.712 10⁻³ rad / s

can a fire have shadow?if it can how?​

Answers

Answer:

Explanation:

Note that fire can have a shadow not because the incoming light beam scatters off the light in the flame. On the fundamental level, one beam of light cannot directly interact with another beam of light. ... Fires can have shadows because they contain hot air and soot, and not because they contain light.

Answer:

it can,t for a fire creates light so it destroyed its shadow

Which property of a transverse wave stays the same even as the wave's
energy and other properties change?
Wavelength
Frequency
Rest position
Amplitude
ent
1 of 8 QUESTIONS
SUBMIT

Answers

The property of a transverse wave that stays the same even as the wave's energy and other properties change is the wavelength.

The correct option to the given question is option a.

The wavelength is the distance between two successive points of the wave that are in phase. As the wave's energy and amplitude change, the distance between two successive points of the wave that are in phase remains the same.

This is because wavelength is determined by the frequency of the wave and the speed of propagation. The frequency of the wave is the number of cycles of the wave that occur in one second, while the speed of propagation is the rate at which the wave travels through a medium.

If the frequency of the wave and the speed of propagation remain the same, then the wavelength will also remain the same even as the wave's energy and other properties change. This property is known as the characteristic of the wave.The amplitude is the maximum displacement of a point on the wave from its rest position. The frequency is the number of cycles of the wave that occur in one second. The rest position is the position of the medium when it is not disturbed.

Hence, wavelength of a transverse wave remains same even as the wave's energy and other properties change.

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You are playing tennis and return a volley. Identify a force pair.

Answers

During a tennis volley, the force pair involved is the action-reaction forces.

When playing tennis and returning a volley, the force pair involved is the action and reaction forces. In the process of hitting the ball, the tennis racket exerts a force on the ball, which is the action force.

The ball, in turn, exerts an equal and opposite force on the racket, which is the reaction force.Both the racket and the ball experience the force of impact during the volley.

The force applied by the racket causes the ball to move forward, while the equal and opposite force applied by the ball pushes the racket back.

These two forces are referred to as action-reaction forces or force pairs. A force pair refers to a pair of forces that are equal in magnitude but opposite in direction.

These forces always act on different objects and occur simultaneously. In this scenario, the action force was exerted by the tennis racket while the reaction force was exerted by the ball.

Therefore, during a tennis volley, the force pair involved is the action-reaction forces.

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4. Describe the appearance of the leaves in Figure 1.
5. Describe the appearance of the leaves in Figure 2.

(Ps, it’s not actually a test lol)

4. Describe the appearance of the leaves in Figure 1.5. Describe the appearance of the leaves in Figure

Answers

In figure 1, the leaves are repelling whereas in figure 2, the appearance of leaves is still and are not repelling.

Explain how the charge on the comb effects the leaves of an electroscope?

When a charged comb is brought near the top of an electroscope, it induces a separation of charges within the metal leaves of the electroscope.

If the comb is negatively charged, it will attract positive charges in the metal leaves and repel negative charges to the bottom. This will cause the metal leaves to acquire a net positive charge, which will cause them to repel each other and stand apart.

If the comb is positively charged, it will attract negative charges in the metal leaves and repel positive charges to the bottom. This will cause the metal leaves to acquire a net negative charge, which will also cause them to repel each other and stand apart.

In either case, the charge on the comb will cause a temporary separation of charges within the metal leaves of the electroscope, which will cause them to stand apart and indicate the presence of a charge.

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_____ associated by microscopic comparison are examined by the FBI’s _____ Unit.

A.
Hairs, Mitochondrial DNA

B.
Rock samples, Anthropology

C.
Fibers, Mineralogy

D.
Skeletal remains, Fabrics

Answers

The FBI's Mitochondrial DNA Unit looks at hairs connected by microscopic comparison.

What is quantity and unit?

Quantity: A measurable quality, such as mass, length, time, volume, or pressure. Unit: A reference unit used to measure other quantities. Chemists use a variety of measurements. if 6.0 grams of a substance's bulk were discovered.

What are 3 types of units?

These are the three basic units: Mass: The body's mass is used to calculate how much matter it contains. The kilogram, or Kg, seems to be the basic unit of mass. Time is a quantifiable length of time. Seconds (s) are the fundamentally important unit of time. The length separating an object's two ends is known as its length.

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A locomotive's "adhesion" is the locomotive's pulling force as a multiple of its weight. This is an important performance measure of a locomotive. A diesel locomotive model has adhesion which varies in actual use according to a Normal distribution with mean 0.37 and standard deviation 0.04.
A) The percent of adhesions measured in use that are higher than 0.40 is closest to
22.66%

Answers

The percentage of adhesions measured in use that are higher than 0.40 is approximately 22.66%.

For finding the percentage of adhesions that are higher than 0.40, need to calculate the area under the normal distribution curve to the right of 0.40. First, need to standardize the value of 0.40 using the Z-score formula:

Z = (X - μ) / σ

Where X is the value (0.40), μ is the mean (0.37), and σ is the standard deviation (0.04).

Z = (0.40 - 0.37) / 0.04 = 0.03 / 0.04 = 0.75

Next, look up the Z-score of 0.75 in the standard normal distribution table for finding the corresponding cumulative probability. The Z-table tells that the cumulative probability to the left of 0.75 is approximately 0.7734.

Since want the percentage to the right of 0.40, subtract the cumulative probability from 1:

1 - 0.7734 = 0.2266

Therefore, the percentage of adhesions measured in use that are higher than 0.40 is approximately 22.66%.

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what are some features that you would expect to see in the design of a high-quality experiment?

Answers

Scientific experiments follow principles called the scientific method that ensure that accurate tests are performed, reliable results are collected, and reasonable conclusions are drawn. Scientific experiments must follow the basic principles of good research so that the final presented results can be believed to be reliable.

Observations of new physical processes or phenomena occur infrequently, but there are areas of science that are not fully understood. Scientists must verbalize their observations in order to formulate meaningful hypotheses.

It's not enough to just guess why something happens. Scientists must prove their theories to be correct. Predictions are made to test observations under different circumstances. The aim is to learn more about this phenomenon and prove its existence. One of his ways of improving the scientific method is by creating 'models'. Models can be used to infer difficult and unobservable concepts.

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Low-energy lightbulbs currently cost $3.60, have a life of 9 years, and currently use $2.00 of electricity per year. Conventional lightbulbs are cheaper to buy; they currently cost only $0.60. On the other hand, they last only 1 year and currently use $7.00 of electricity per year. If the real discount rate is 4%, what are the EACs for each lightbulb? Which lightbulb is cheaper to operate assuming a burnt-out bulb is replaced by an identical bulb? a. EAC( Low-energy lightbulb )=2.48 EAC( Conventional lightbulb )=7.62 Low-energy lightbulb is cheaper to operate b. EAC( Low-energy lightbulb )=3.60 EAC( Conventional lightbulb )=0.60 Conventional lightbulb is cheaper to operate c. EAC( Low-energy lightbulb) =2.00 EAC( Conventional lightbulb )=7.33 Low-energy lightbulb is cheaper to operate d. EAC( Low-energy lightbulb )=18.47 EAC( Conventional lightbulb )=7.33 Conventional lightbulb is cheaper to operate

Answers

EAC( Low-energy lightbulb )=18.47 EAC( Conventional lightbulb )=7.33 Conventional lightbulb is cheaper to operate. Option D

Energy cost calculation

To calculate the Equivalent Annual Costs (EAC), we need to consider the initial cost, maintenance costs, and the present value of future costs, taking into account the discount rate.

The EAC (Equivalent Annual Cost) is calculated by summing up the annual costs of the lightbulb over its lifetime, discounted at the real discount rate of 4%.

For the low-energy lightbulb:

EAC = Cost of bulb + Present value of annual electricity cost

= $3.60 + ($2.00 / (1 + 0.04)^1) + ($2.00 / (1 + 0.04)^2) + ... + ($2.00 / (1 + 0.04)^9)

≈ $18.47

For the conventional lightbulb:

EAC = Cost of bulb + Present value of annual electricity cost

= $0.60 + ($7.00 / (1 + 0.04)^1) + ($7.00 / (1 + 0.04)^2) + ... + ($7.00 / (1 + 0.04)^1)

≈ $7.33

Since the EAC for the low-energy lightbulb is $18.47 per year and the EAC for the conventional lightbulb is $7.33 per year, the conventional lightbulb is cheaper to operate assuming a burnt-out bulb is replaced by an identical bulb.

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What defines a mixture?
for sience

Answers

In chemistry, a mixture is a material made up of two or more substances which are not chemically combined.

Hope this helps :)

Stars which can be seen all year long are called___.

Answers

Answer:

you can see them in the night

Explanation:

also in the day they are there but you can't see it

Answer:

Hey!

Your answer is Circumpolar Stars!

Explanation:

These are stars which appear to revolve (spin/turn) around the polar axis (N and S) and do not set below the horizon.

Hope this helps!

consider a hypothetical planet with a radius of 162 million meters and a mass of 1027 kg. what is the density of this planet, in kg/m3? round to the nearest integer.

Answers

The density of the hypothetical planet, in kg/m3, is 6,246 kg/m3

Calculate the volume of the planet in m3

V = (4/3)πr3

V = (4/3)π(162 x 106 m)3

V = 9.30 x 1018 m3

The density of the planet in kg/m3

We know that Density is given as

D = Mass ÷ Volume

D = 1027 kg ÷ 9.30 x 1018 m3

D = 6,246 kg/m3

Density is a measure of mass per unit of volume. It is expressed in terms of mass per volume and is typically measured in kg/m3 or g/cm3. Density is an important physical property of matter as it allows us to compare the mass of different substances at the same volume.

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PLEASE HELP! A 0.423 kg object carries a +11.5 uc
charge. It is 0.925 m from a -7.55 C
charge. What is the magnitude of the
object's acceleration?
(u stands for micro. Remember, magnitudes
are positive.)
[?] m/s2

PLEASE HELP! A 0.423 kg object carries a +11.5 uccharge. It is 0.925 m from a -7.55 Ccharge. What is

Answers

Answer:

2.15 m/s²

Explanation:

We'll begin by calculating the force of attraction between two charges. This can be obtained as follow:

Charge of 1st object (q₁) = +11.5 μC = +11.5×10¯⁶ C

Charge of 2nd object (q₂) = –7.55 μC = –7.55×10¯⁶ C

Electrical constant (K) = 9×10⁹ Nm²/C²

Distance apart (r) = 0.925 m

Force (F) =?

F = Kq₁q₂ / r²

F = 9×10⁹ × 11.5×10¯⁶ × 7.55×10¯⁶/ 0.925²

F = 0.781425 / 0.855625

F = 0.91 N

Finally, we shall determine the acceleration of the object. This can be obtained as follow:

Mass of object (m) = 0.423 Kg

Force (F) = 0.91 N

Acceleration (a) =?

F = ma

0.91 = 0.423 × a

Divide both side by 0.423

a = 0.91 / 0.423

a = 2.15 m/s²

Thus, the magnitude of the object's acceleration is 2.15 m/s²

Answer:

2.15

Explanation:

Acellus

Design a safety restraint or device for a motorcycle 4-wheeler or go-kart. Design may be drawn or describe. Be sure to explain how your devices protects the driver against collision forces.
this is very urgent, please help!!

Answers

Answer:

Explanation:

One possible safety restraint or device for a motorcycle 4-wheeler or go-kart could be a roll cage. A roll cage is a structure that surrounds the driver and is designed to protect them in the event of a rollover or collision.

The roll cage would be made of strong, lightweight material such as steel or aluminum tubing. It would be attached to the frame of the 4-wheeler or go-kart and would extend upward to surround the driver's head and shoulders. The roll cage would also have additional bracing to provide additional support and protection in the event of a collision.

In the event of a rollover or collision, the roll cage would help to distribute the forces of the impact evenly around the driver, protecting them from the full force of the collision. The additional bracing would also help to prevent the roll cage from collapsing or deforming, providing additional protection for the driver.

In addition to the roll cage, the driver could also wear a safety harness or seat belt to help keep them securely attached to the vehicle and prevent them from being thrown out in the event of a collision. This would provide additional protection against the forces of a collision.

based on your reading "take a closer look" what can you say about the image that forms on the retina of your eye?

Answers

Answer:

it is an upside-down image but the brain realizes it and corrects it in its orientation so we see it in right direction.

Answer:

The lens of the eye is a convex lens. The image that it forms on the retina is upside down.

Explanation:

The eye makes an image, but it is upside down, the brain corrects the image and turns it right side up

Why is a spherical bob preferred to bobs of other shapes for use in simple pendulum experiments​

Answers

Answer

A spherical bob creates more control for the simple pendulum experiment. An irregular bob like a large piece of paper for instance, will create too much air resistance for a basic classical experiment to yield predictable results within the academic lab.

A _____ is a series of events and activities with no slack time. a. risk path b. foundation path c. baseline path d. critical path.

Answers

The D. critical path is a series of events and activities with no slack time.

It is a path that defines the longest duration required to complete a project. It is significant in the project management methodology as it helps the project manager establish a timeline for the project while also identifying the activities that are most critical to the project's completion. If an activity on the critical path takes longer than anticipated, the whole project will be delayed, and if an activity is completed earlier than expected, then it might not be worth it to continue the project, and the client might not be willing to pay for it.

The critical path analysis allows managers to identify and control the critical factors that can impact a project's success, enabling them to focus on the most important areas and make informed decisions about the project. So the correct answer is D. critical path, is a series of events and activities with no slack time.

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What factors affect an objects kinetic energy?

Answers

Answer:

friction

air drag

every thing that opposes the motion affects kinetic energy

Explanation:

kinetic energy is a energy which is increase with increase in motion and potential energy is energy stored while the object is at rest

potential energy ∝ 1/(kinetic energy)

as kinetic energy increases potential energy decreases

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