Complete Question
The complete quetion is shown on the first uploaded image
Answer:
Explanation:
From the question we are told that
The mass of the fly is \(m_f = 11 mg = 11*10^{-3} g = 1.1*10^{-5} \ kg\)
The extension of the web is \(e= 4.00 \ mm = 0.004 \ m\)
The spring constant is mathematically evaluated as
\(k = \frac{mg}{e}\)
substituting values
\(k = \frac{1.1 *10^{-5} *9.8}{0.004}\)
\(k = 0.027 \ N/m\)
The frequency of vibration is
\(f = \frac{1}{2 \pi} \sqrt{\frac{k}{m} }\)
substituting values
\(f = \frac{1}{2 * 3.142 } \sqrt{\frac{0.027}{1.1*10^{-5}} }\)
\(f = 7.9 Hz\)
Which statement is true about the theory of plate tectonics and the theory of continental drift?
A) The theory of plate tectonics proves the theory of continental drift completely wrong.
B) The theory of plate tectonics tells exactly where the continents were before Pangaea divided.
C) The theory of plate tectonics gives the method by which continents can move as part of plates.
D) The theory of plate tectonics does not explain how continental movements could occur.
The statement that is true about the theory of plate tectonics and the theory of continental drift C. The theory of plate tectonics gives the method by which continents can move as part of plates .
What is theory of plate tectonics and the theory of continental drift ?According to the scientific hypothesis of plate tectonics, the underground movements of the Earth create the primary landforms. By explaining a wide range of phenomena, including as mountain-building events, volcanoes, and earthquakes, the theory, which became firmly established in the 1960s, revolutionized the earth sciences.
The scientist Alfred Wegener is most closely connected with the concept of continental drift. Wegener wrote a paper outlining his notion that the continents were "drifting" across the Earth, occasionally crashing through oceans and into one another, in the early 20th century.
According to tectonic theory, the Earth's surface is dynamic and can move up to 1-2 inches every year. The numerous tectonic plates constantly move and interact. The outer layer of the Earth is altered by this motion. The result is earthquakes, volcanoes, and mountains.
Therefore, option C is correct.
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Highschool Physics
1. The driver of a car traveling at 9.0m/s is honking their horn. The horn has a frequency of 625 Hz. If the car is moving toward a person waiting at the crosswalk, what frequency of the horn does the person hear?
2. As the same car from question#1 passes the person, what frequency of the horn does the person hear as the car moves away from them?
Using the formula for the Doppler effect:
f' = (v + vr) / (v + vs) * f
Given:
Source frequency (horn): f = 625 Hz
Speed of sound: v = 343 m/s (approximate value at room temperature)
The velocity of the receiver, vr, is zero because the person waiting at the crosswalk is stationary.
The velocity of the source, vs, is the speed of the car, which is given as 9.0 m/s.
Thus:
f' = (v + vr) / (v + vs) * f
= (343 m/s + 0) / (343 m/s + 9.0 m/s) * 625 Hz
= (343 m/s) / (352 m/s) * 625 Hz
≈ 609 Hz
Therefore, the person waiting at the crosswalk hears a frequency of approximately 609 Hz.
(2)Using the same Doppler effect formula:
f' = (v - vr) / (v - vs) * f
In this case, the velocity of the receiver, vr, is still zero because the person remains stationary.
The velocity of the source, vs, is now negative, indicating that the car is moving away from the person.
Thus:
f' = (v - vr) / (v - vs) * f
= (343 m/s + 0) / (343 m/s - (-9.0 m/s)) * 625 Hz
= (343 m/s) / (352 m/s) * 625 Hz
≈ 609 Hz
In other words, as the car moves away from the person, they would still hear a frequency of approximately 609 Hz.
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A ball is thrown up into the air for a total of 1.25 s before it is caught at its original position . How high did the ball go
so:
The initial speed is given by:
\(\begin{gathered} v=v_o+at \\ _{\text{ }}where\colon \\ v=-v_o \\ a=g=-9.8 \\ t=1.25 \\ so\colon \\ -v_o=v_o+(-9.8)\cdot1.25 \\ -2v_o=-12.25 \\ v_o=\frac{-12.25}{-2} \\ v_o=6.125 \end{gathered}\)Therefore:
\(\begin{gathered} y_o=0 \\ v_{}=0 \\ v_o=6.125 \\ so\colon \\ y=\frac{-v^2_o}{2g} \\ y=\frac{-6.125^2}{2(-9.8)} \\ y=1.91m \end{gathered}\)Answer:
1.91m
A substance takes three minutes in cooling from 50°C to 45°C and takes five minutes and cooling from 45°C to 40°C what is the temperature of the surrounding how much time will it take to cool the substances from 40°C to 35°C
Answer:
The ambient temperature is 35°C.
It takes 15 minutes to cool the substance from 40°C to 35°C.
Explanation:
Using Newton's Law of Cooling to answer the given problem.
\(\boxed{\left\begin{array}{ccc}\text{\underline{Newton's Law of Cooling:}}\\\\ \frac{dT}{dt} =-k(T-T_a)\end{array}\right}\)
Given:
The time it takes to cool from 50°C to 45°C = 3 minutes
The time it takes to cool from 45°C to 40°C = 5 minutes
Find:
Time ambient temperature and the time it takes to cool the substance from 40°C to 35°C
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
(1) - Using first initial condition:
\(\text{Avg temp =} \ \frac{50+45}{2}=\boxed{47.5 \textdegree C}\\\\\Longrightarrow \frac{50-45}{3}=-k(47.5-T_a) \\\\\Longrightarrow \boxed{ \frac{5}{3}=-k(47.5-T_a)}\)
(2) - Using the second initial condition:
\(\text{Avg temp =} \ \frac{45+40}{2}=\boxed{42.5 \textdegree C}\\\\\Longrightarrow \frac{45-40}{5}=-k(42.5-T_a) \\\\\Longrightarrow \boxed{1=-k(42.5-T_a)}\)
(3) - Now we have a system of equations.
\(\left \{ \frac{5}{3}=-k(47.5-T_a)}} \atop {1=-k(42.5-T_a)}}} \right.\)
(4) - Solve the system by dividing the top equation by the bottom equation.
\(\Longrightarrow \frac{\frac{5}{3}=-k(47.5-T_a)}{1=-k(42.5-T_a)} \\\\\Longrightarrow\frac{5}{3}=\frac{47.5-T_a}{42.5-T_a}\\ \\ \Longrightarrow 5(42.5-T_a)=3(47.5-T_a)\\\\\Longrightarrow 212.5-5T_a=142.5-3T_a\\\\\Longrightarrow 2T_a=70\\\\\therefore \boxed{T_a=35 \textdegree C}\)
Thus, the ambient temperature is 35°C.
(5) - Find the value of "k" using either of the two previous equations
\(1=-k(42.5-T_a)\\\\\Longrightarrow 1=-k(42.5-35)\\\\\Longrightarrow 1=-7.5k\\\\\Longrightarrow \boxed{ k \approx -0.133}\)
(6) - Now finding "dt"
\(\text{Avg temp =} \ \frac{40+35}{2}=\boxed{37.5 \textdegree C}\\\\\Longrightarrow \frac{40-35}{dt}=0.133(37.5-35) \\\\\Longrightarrow \frac{5}{dt}=0.3325\\\\\therefore \boxed{dt \approx15 \ min}\)
Thus, it take 15 minutes to cool the substance from 40°C to 35°C.
What type of force is jumping a trampoline?
Answer:
Tension
Explanation:
Which layer of the atmosphere is most likely to protect life on Earth from ultraviolet radiation
Answer:
ozone layer
Explanation:
The ozone layer forms a thin shield in the upper atmosphere protecting life on earth from UV rays. Ozone is a naturally occurring gas that is found in two layers of the atmosphere
a vertical air current that is generated by temperature-induced density differences (e.g., hot air rising) is an example of heat transfer by
Convection When a fluid, such as air or water, is heated and starts to circulate, heat transfer through convection takes place.
A cooler area is left behind when the hot fluid rises, carrying the heat energy it contains with it. As a result, energy is transferred from one place to another through a cycle of air or water currents. Convection is characterised by the vertical air current produced by temperature-induced density differences, such as hot air rising. Thermal convection is a crucial component of the climate system on Earth and is a type of convection. Convections always need a medium for the transfer of energy.
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1. Calculate the increase in length of an iron wire that is 30m long at 20°c when it is warmed to 45°c (take airon 1.1x10³J/k)
2. If 2200 Joule of heat is added to a 190 g object its temperature increases by 12°c.W hat is
a. specific heat capacity
b. heat capacity of the object
The increase in length of the iron wire when warmed from 20°C to 45°C is approximately 8.25 millimeters. The specific heat capacity of the object is approximately 9.62 J/kg°C. The heat capacity of the object is approximately 1.83 J/°C.
ΔL = L × α × ΔT
Where:
ΔL is the change in length
L is the original length of the wire
α is the coefficient of linear expansion for iron
ΔT is the change in temperature
The coefficient of linear expansion for iron is typically 1.1 x \(10^(^-^5^)\) °\(C^(^-^1^)\).
Given:
L = 30 m (original length of the wire)
α = 1.1 x \(10^(^-^5^)\) °\(C^(^-^1^)\) (coefficient of linear expansion)
ΔT = 45°C - 20°C = 25°C (change in temperature)
ΔL = 30 m × (1.1 x \(10^(^-^5^)\) °\(C^(^-^1^)\)) × 25°C
= 30 m × 1.1 x\(10^(^-^5^)\) × 25
= 8.25 x \(10^(^-^3^)\) m
2) Q = mcΔT
Where:
Q is the heat energy transferred
m is the mass of the object
c is the specific heat capacity
ΔT is the change in temperature
Given:
Q = 2200 J (heat energy transferred)
m = 190 g (mass of the object)
ΔT = 12°C (change in temperature)
a. Specific heat capacity (c):
one need to rearrange the formula to solve for c:
c = Q / (m × ΔT)
Substituting the given values:
c = 2200 J / (190 g × 12°C)
First, need to convert the mass to kilograms:
m = 190 g = 190 g / 1000 = 0.19 kg
Now can calculate the specific heat capacity:
c = 2200 J / (0.19 kg × 12°C)
= 9.62 J/(kg°C)
b. Heat capacity (C):
The heat capacity is the amount of heat energy required to raise the temperature of the object by 1 degree Celsius.
C = mc
Substituting the given values:
C = 0.19 kg × 9.62 J/(kg°C)
= 1.83 J/°C
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Identify the labeled parts in the figure.
i. Which of the labeled parts is a chemical symbol?
ii. Which of the labeled parts is a coefficient?
iii. Which of the labeled parts is the number of atoms of the element?
iv. Which of the labeled parts indicates that only one atom of the element is present in the substance?
Answer:
I. a, c, f and h
II. e
III. b, d, g and i
IV. i
Explanation:
I. Chemical symbols are simple abbreviations used to represent various elements or compound. They consist entire of alphabet.
For the diagram given above, the labelled parts which represent chemical symbol are: a, c, f and h
II. Coefficients are numbers written before the chemical symbol of elements or compound.
For the diagram given above, the labelled part which represent Coefficient is: e
III. Number of atoms of element present in a compound is simply obtained by taking note of the numbers written as subscript in the chemical formula of the compound.
For the diagram given above, the labelled part which represent the number of atoms of the element are: b, d, g and i
IV. When no number is written as subscript in the formula of the element in the compound, it means the element has just 1 atom in the compound.
For the diagram given above, the labelled part which indicates that only 1 atom of the element is present is: i
Answer:
i. a, c, f, h
ii. e
iii. b, d, g, i
iv. i
can someone help me pleaseenkwnsn
If a third resistor is added in SERIES, what changes happens to the....
a. Total Voltage - stay the same b. Total Current - decrease c. Total Resistance - increase d. Voltage through resistor 1 - decrease e. Current through resistor 1 - decreaseWhat happens in a circuit?When you add a third resistor in series, the total resistance of the circuit increases. This is because the current has to flow through all three resistors, so it has to overcome more resistance. The total voltage across the circuit stays the same, because the voltage of the battery is constant. However, the current decreases, because the same amount of current is now flowing through a larger resistance.
The voltage across each resistor also decreases, because the total voltage is divided among the three resistors. The current through each resistor also decreases, because the same current is now flowing through a larger resistance.
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A crane lifts a load of 1000 N through a vertical height of 3.0 min 10 s. The input power to the Crane is 500J/s. What is the efficiency of the crane?
Based on the calculations, the efficiency of the crane is equal to 60%.
Given the following data:
Weight = 1000 Newton.Height = 3.0 meters.Time = 10 seconds.Input power = 500J/s.To calculate the efficiency of the crane:
How to calculate efficiency.Mathematically, the efficiency of an object is given by this formula:
\(Efficiency = \frac{Out\;power}{In\;power} \times 100\)
Next, we would determine the work done by the crane by using this formula:
\(Work\;done= weight \times height\\\\Work\;done=1000 \times 3.0\)
Work done = 3000 J
For the output power:
\(Out\;power = \frac{work\;done}{time} \\\\Out\;power = \frac{3000}{10}\)
Output power = 300 J/s.
Substituting the parameters into the formula, we have:
\(Efficiency = \frac{300}{500}\times 100\\\\Efficiency = 0.6 \times 100\)
Efficiency = 60%.
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Answer:
0.6
Explanation:
We already have Weight and time and the input energy First we would find work done than divide by 10 (time) then we would have output energy after this apply efficiency formula output over input and then you would have the answer 0.6
Please help me with this question.
With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.
When you increase the number of wire windings in the generator from 5 to 20, the effect on the light bulb will be a brighter illumination. The brightness of the light bulb is directly proportional to the number of windings in the generator.
By increasing the number of windings, you are increasing the amount of wire wrapped around the magnet. This results in a higher number of turns per unit length, leading to an increased magnetic flux passing through the wire coils.
According to Faraday's law of electromagnetic induction, a change in magnetic flux induces an electromotive force (EMF) in a conductor, which in this case is the copper wire. The induced EMF causes electric current to flow through the wire, creating a flow of electrons.
The 30-W light bulb requires a certain amount of electrical power to produce its specified brightness. With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.
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what heavy element was the chernobyl nuclear accelarators supposed to make?
Answer
plutonium
Explanation:
brainliest please
**NEED ANSWER ASAP**
Identify the constellation, label any of the names stars or asterisms that were covered in class
Answer: I believe this constellation is cygnus, the swan. The brightest star is Deneb at the tail. The bright double star at the head of the swan is Albireo.
Explanation:
5 waves with a length of 4m hit the shore every 2 seconds, what is the frequency?
The frequency of the 5 waves with a length of 4m hit the shore every 2 seconds is 2.5 Hz.
What is frequency?This is the number of cycles completed by a wave in one second. The s.i
unit of frequency is Hert (Hz).
From the question, to calculate the frequency of 5 waves with length of 4 m that hit the shores every 2 seconds, we use the formula below.
Formula:
F = n/t........... Equation 1Where:
n = Number of waveF = Frequencyt = timeFrom the question,
Given:
n = 5 waves t = 2 secondsSubstitute these values into equation 1
F = 5/2F = 2.5 Hz.Hence, The frequency of the wave is 2.5 Hz.
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Use the graph one more time to help you with this question. Changes in both the North and South occurred due to the .
Answer:
industrial revolution
Explanation:
examples of ohmic conductors
The examples of ohmic conductors are :
Silver(Ag), copper(Cu), aluminium(Al) etc.
How can we conclude that these are ohmic conductors?Ohmic conductors means which conductors strictly obey the Ohm's law, are known as Ohmic conductors.
Resistance= \(\frac{Voltage}{Current}\)
In other words there is a linear relationship between voltage and current for all values. That means all the ohmic conductor materials shows a linear character in the V-I characteristic graph.
So, the examples of ohmic conductors are:
Silver(Ag), copper(Cu), aluminium(Al) etc.
All the conductors we mentions here, they all show a linear line in the V-I characteristic graph.
From the above discussion we can conclude that, Silver(Ag), copper(Cu), aluminium(Al) etc. these are the ohmic conductors.
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How do atomic and molecular interactions explano the properties of matter that we see and feel?
Answer:
The atomic and molecular interactions unveil the bulk properties of matter in our environment by ways of the fact that everything in the whole universe is made of either atoms, molecules or even ions
How matter is made up of atoms and molecules?
It has been proven practically everything in the whole universe is matter and everything which interact with matter is also matter. This explains to us the reasons why matter could be atoms, molecules or ions.
That being said, some substances (matter) is made up of atoms of elements, some made up of molecules or atoms and molecules and others ions or both. However, matter is anything which has mass and occupies space.
In conclusion, we can now conclude from the explanation above that the properties of matter are as a result of the interaction which exists between matter at the atomic and molecular level.
Explain how you can use aspects of Newton's second law to improve your car.
Answer:
here ya go
Explanation:
When a force is applied to a car, the change in motion is proportional to the force divided by the mass of the car.
Greg paid $3.60 for a package of 8 nails at the home store. John paid $3.18 for a package of 6 nails at the hardware store. How much more did John pay per nail than Greg?
(PLS HELP ( . *)^( . *)
Answer:
8 cents extra.
Explanation:
First find out how much one nail is for each of them. So, divide.
3.60 divided by 8 is 0.45.
3.18 divided by 6 is 0.53.
Subtract 0.45 from 0.53 and voila you have 0.08.
Answer:
5
Explanation:
76789967
Using the right-hand rule, in which direction will the single wire move, and in which direction will the loop rotate?
Single Wire moves down, loop rotates left.
About single wireA single-wire system is a method of transmitting power or signals using only a single conductor. This is in contrast to the usual use of a pair of wires to provide a complete circuit, or an electrical cable containing (at least) two conductors for this purpose.
A single-wire transmission line is not the same as a single-wire earth return system. This is beyond the scope of this article. The latter system relies on reverse current flow through earth, using earth as a second conductor between earth terminal electrodes. A single-wire transmission line does not have a second conductor of any kind.
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A 1.3-kg book rests on a table. A downward force of 15 N is exerted on the top of the book by a hand pushing down on the
book
What is the net force on the book?
Answer:
The net force will be:
\( F_{net} = 142.53\: N\)
Explanation:
The net force is given by:
\( F_{net} = W_{b}+F\)
\( F_{net} = m_{b}g+15\)
\( F_{net} = 142.53\: N\)
I hope it helps you!
Does fg increase or decrease when one mass increases
Answer:
It increases because fg means Force of gravity so When the mass of the two objects increases with mass and increases the distance between an object
There you go!!!
PLEASE HELP
Why are the outer planets sometimes called gas giants?
A) The outer planets are called gas giants because they have volcanos that give off gas.
B) The outer planets are called gas giants because they are named after giant beings from Greek mythology.
C) The outer planets are often called gas giants because they are very large and emit gases from their cores.
D) The outer planets are often called gas giants because they are composed almost entirely of gas and are much larger than any of the four inner planets.
Answer:
D) The outer planets are often called gas giants because they are composed almost entirely of gas and are much larger than any of the four inner planets.
Explanation:
sing the superposition principle find the magnitude ofthe electric field at point P in the gap.1. E =5Q / εoA2. E = 4Q/εoA3. E =3Q/ εoA5. E =Q/ εoA6. E =2Q/ εoA
The superposition principle used to calculate the electric field's strength at point P, which comes out to be 15 Q/oA.
The superposition principle states that the total electric field at a point is equal to the vector sum of the electric fields due to each individual charge at that point.
In this case, we have five charges, each producing an electric field at point P, so the total electric field at P is:
E = (E1 + E2 + E3 + E4 + E5) = (5Q/εoA + 4Q/εoA + 3Q/εoA + Q/εoA + 2Q/εoA) = (15Q/εoA)
So the magnitude of the electric field at point P is 15 times the magnitude of the electric field due to a single charge.
If the magnitude of the electric field due to one charge is given by
E = Q/εoA,
then the magnitude of the electric field at point P is:
E = 15 * (Q/εoA) = 15Q/εoA
So the magnitude of the electric field at point P is 15Q/εoA.
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An object's speed is 3.6 m/s with a momentum of 180 kgm/s. What is the mass of the object?
Answer:
To solve the problem we must know the concept of momentum.
What is Momentum?
Momentum is defined as the product of the mass of an object and the velocity of an object. It is a vector quantity.
$$\rm{Momentum = velocity \times Mass$$
The mass of the object is 50 kg.
Given to us
velocity of the object = 3.60 m/s
momentum of the object = 180 kg m/s
Mass of the object
We know that momentum is the product of the mass of the object and the velocity of the object,
$$\rm{Momentum = velocity \times Mass$$
Substitute the values,
180 = 3.60 \times \rm Mass180=3.60×Mass
\rm Mass = \dfrac{180\ kg\ m/s}{3.6\ m/s}Mass=
3.6 m/s
180 kg m/s
\rm Mass = 50\ kgMass=50 kg
Hence, the mass of the object is 50 kg.
Select the correct answer.
A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are the total
distance and total displacement of the boat?
O A.
OB.
O C.
O D.
The total distance is 105 kilometers and the total displacement is 45 kilometers east.
The total distance is 60 kilometers and the total displacement is 60 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east.
The total distance is 60 kilometers and the total displacement is 45 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C
How to solve for the total distanceTo calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.
However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.
Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.
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A spring scale hung from the ceiling stretches by 5.9 cm
when a 1.6 kg
mass is hung from it. The 1.6 kg
mass is removed and replaced with a 2.1 kg
mass.
Part A
What is the stretch of the spring?
Express your answer with the appropriate units.
The stretch of the spring is proportional to the weight of the mass hung from it. Since the spring stretches by 5.9 cm when a 1.6 kg mass is hung from it, we can use this information to find the stretch when a 2.1 kg mass is hung from it.
The stretch of the spring is given by:
stretch = (mass x gravity x length) / (spring constant)
where mass is the mass hung from the spring, gravity is the acceleration due to gravity (9.81 m/s^2), length is the stretch of the spring, and the spring constant is a measure of the stiffness of the spring (measured in N/m).
We can rearrange this equation to solve for the stretch of the spring:
stretch = (mass x gravity x length) / (spring constant)
length = (spring constant x stretch) / (mass x gravity)
Substituting the given values, we get:
length = (spring constant x 0.059 m) / (1.6 kg x 9.81 m/s^2)
Simplifying, we get:
length = 0.236 m
Therefore, the stretch of the spring when a 2.1 kg mass is hung from it is 0.236 m.
A resistor, an ideal capacitor, and an ideal inductor are connected in parallel to a source of an alternating voltage of 160 V at a frequency of 250 Hz. A current of 2 A flows through the resistor and a current of 0.8 A flows through the inductor. The total current through the circuit is 2.5 A. Assess the resistance of the resistor, the capacity of the ideal capacitor, and the inductance of the ideal inductor (presume that IC > IL).
Answer:
R = 46,25 (Ω)
L = 0,07363 (H)
C = 2,7 *10⁻⁶ (F)
Explanation:
Statement problem does not specify if 160 (V) is peak voltage or RMS value. If 160 (V) is the peak value then for a sinusoidal wave, RMS value is V(rms) = 160 /√3
V(rms) = 92,49 (V)
In each branch: we have
V = I*Z V = voltage through the impedance in (V) , I current in (A)
and Z impedance in Ω
Resistor case Z = R then V = 92,49 = 2 * R
R = 92,49/2 R = 46,25 (Ω)
Inductor case |Z| = wL Then Z = 2*π*f*L V = 0,8 * |wl|
Inductor L in (H) |wL| * 0,8 = 92,49 |wL| = 92,5/0,8 w = 2*π*f 2*3,14*250= 1570
1570*L = 92,49/0,8
L = 0,07363 (H)
In the case of the capacitor
|Z| = 1/wc = 1/1570*c
The current is 2 + 0,8 = 2,8 2,8 - 2,5 = 0,3 (A)
Again V = I*Z 92,49 = 0,3 /1570*C
C = 0,3 / 1570*92,49
C = 2,7 *10⁻⁶ (F)
During a testing process, a worker in a factory mounts a bicycle wheel on a stationary stand and applies a tangential resistive force of 125 N to the tire's rim. The mass of the wheel is 1.50 kg and, for the purpose of this problem, assume that all of this mass is concentrated on the outside radius of the wheel. The diameter of the wheel is 60.0 cm. A chain passes over a sprocket that has a diameter of 8.50 cm. In order for the wheel to have an angular acceleration of 4.50 rad/s2, what force, in Newtons, must be applied to the chain
Answer:
896.647 N
Explanation:
Given data:
Tangential resistive force ( Fr )= 125 N
mass of the wheel ( M ) = 1.50 kg
diameter of wheel ( D1 )= 60 cm
R1 = 30 cm = 0.3 m
diameter of chain ( D2 ) = 8.5 cm
R2 = 0.0425 m
Angular acceleration ( ∝ ) = 4.50 rad/s^2
Determine the Force to be applied to Chain
First ; calculate for the moment of Inertia of the wheel
I = M*R1 ^2 = 1.50 * (0.3)^2 = 0.135 kg*m^2
Next determine the net force on the wheel due to torque
τ = F*R2 - Fr *R1 = F (0.0425) - 125 * 0.3 ---- ( 1)
note that Torque ( τ ) = I * ∝ ----- ( 2 )
Equate; equation ( 1 ) and equation ( 2 )
F( 0.0425 ) - 37.5 = 0.135 * 4.5
∴ F = 38.1075 / 0.0425 = 896.647 N ( force to be applied to chain )