Interference and diffraction are both phenomena that occur when waves interact with each other or with obstacles.
Interference refers to the phenomenon where two or more waves meet and interact with each other, resulting in a change in the amplitude of the resulting wave.
Diffraction refers to the bending and spreading out of waves as they encounter an obstacle or pass through a narrow opening.
Both interference and diffraction occur under a variety of circumstances, such as when waves encounter obstacles, pass through narrow openings, or interact with other waves.
Interference refers to the phenomenon where two or more waves meet and interact with each other, resulting in a change in the amplitude of the resulting wave. Interference can be constructive, where the waves reinforce each other and create a larger amplitude wave, or destructive, where the waves cancel each other out and create a smaller amplitude wave.
Diffraction refers to the bending and spreading out of waves as they encounter an obstacle or pass through a narrow opening. This occurs because waves tend to spread out in all directions when they encounter an obstacle or opening that is smaller than their wavelength. Diffraction can cause patterns of interference, such as the alternating light and dark bands seen in a double-slit experiment.
Both interference and diffraction occur under a variety of circumstances, such as when waves encounter obstacles, pass through narrow openings, or interact with other waves. They are particularly important in the study of light and sound waves, and have many practical applications in fields such as optics and acoustics.
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What is the angle formed between the vectors of centripetal acceleration and centripetal force?.
Angle formed between the vectors of centripetal acceleration and centripetal force is 0°.
Centripetal force is a pressure that acts on an object with a view to direct it closer to a center of curvature. The force generated by means of your arm puts the yo-yo itself in movement, and the tension on the string continues it moving in a circular direction as you twirl it.
One common place instance concerning centripetal pressure is the case wherein a body actions with uniform pace along a circular route. The centripetal force is directed at proper angles to the movement and also alongside the radius closer to the centre of the round route.
Centripetal force is a force on an object directed to the center of a round path that maintains the object at the route. Its price is based totally on three factors:
1) The speed of the item because it follows the round route;
2) The object's distance from the center of the route;
3) The mass of the object.
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What is your hypothesis (or hypotheses) for this experiment?
(physically science lab report)
Answer:The hypothesis (or hypotheses) for this experiment would be :
1) Experiment of motion( movement) can be performed in this lab.
2) Experiment of motion( movement) can be performed better in this lab.
3) Only experiments of motion( movement) can be performed in this lab.
4) Experiment of motion( movement) can be performed more accurately in this lab.
5) No experiment of motion( movement) can be performed in this lab.
Explanation:
The hypothesis (or hypotheses) for this experiment would be :
Experiment regarding motion( movement) can be performed in this lab.
And Conclusion would be:
This lab is for motion.
We can only conclude that this lab is for motion when we find out that the motion experiments can be performed better or with higher accuracy or none other experiment can be carried out as easily as the motion experiment.
We only conclude when we test the hypothesis .
The hypothesis can be tested in a number of ways such as showing better results, or showing negative results of the said statement.
So there can be a few hypotheses as follows.
1) Experiment of motion( movement) can be performed in this lab.
2) Experiment of motion( movement) can be performed better in this lab.
3) Only experiments of motion( movement) can be performed in this lab.
4) Experiment of motion( movement) can be performed more accurately in this lab.
5) No experiment of motion( movement) can be performed in this lab.
Explanation:
If an object that was held steady (0 speed) and then dropped, how many meters would it fall in one second?
Answer:
h = 4.905 m
Explanation:
In order to find the distance covered by the object in 1 second, we can use the second equation of motion:
\(h = v_i t + \frac{1}{2}gt^2\\\)
where,
h = distance covered = ?
vi = initial speed = 0 m/s
g = acceleration due to gravity = 9.81 m/s²
t = time = 1 s
Therefore,
\(h = (0\ m/s)(1\ s)+\frac{1}{2}(9.81\ m/s^2)(1\ s)^2\\\\\)
h = 4.905 m
Which of the following statements is true?
Observations are often used to form questions about the world.
The dependent variable is changed by the experimenter.
The best hypotheses are written as answers to a question.
A hypothesis is created at the end of an experiment.
Answer:
The answer is B.
Explanation:
They are in control of the experiment, they can change it the variables to better help the experiment.
Answer:
b
Explanation: its b
Plz help with these 5 The backbone is made up of 26 small bones called ___________. What are the characteristics of bones? (list 7) What role do joints play? What are the two types of joints? What are ligaments?
Answer:
The backbone, spine or vertebral column is made up of 26 small bones called the vertebrae.
The characteristics of bones include:
1. They are strong and rigid
2. They are composed of bone cells called osteocytes.
3. They are lightweight
4. They have a honeycomb-like matrix internally, which helps to give them rigidity.
5. They exist in various types and shapes.
6. They have the ability to grow and repair when damaged
7. They contain inorganic minerals such as calcium and phosphate
The two types of joints are the movable and immovable joints.
Ligaments are bands of tough elastic fibrous tissue around that found around the joints whose function is to link bone to bone, give support to joints as well as limit their movement.
Explanation:
The backbone, spine or vertebral column is made up of 26 small bones called the vertebrae. The 26 small bones include 24 separate vertebrae interspaced with cartilage, and then additionally the sacrum and coccyx. The vertebral column is divided into five regions: cervical, thoracic, lumbar, sacral and coccygeal regions.
A bone is a rigid tissue that is part of the skeleton in vertebrate animals. The characteristics of bones include:
1. They are strong and rigid
2. They are composed of bone cells called osteocytes.
3. They are lightweight
4. They have a honeycomb-like matrix internally, which helps to give them rigidity.
5. They exist in various types and shapes.
6. They have the ability to grow and repair when damaged
7. They contain inorganic minerals such as calcium and phosphate
Joints are the junctions where two bones meet. They serve various functions which include allowing for movement of the body and binding the skeleton together.
The two types of joints are the movable and immovable joints.
Ligaments are bands of tough elastic fibrous tissue around that found around the joints whose function is to link bone to bone, give support to joints as well as limit their movement.
Answer:
5. Vertebrae
Explanation:
A back bone made up of 26 small bones is called a vertebrae.
i need help asap!!!!!!!!
The Answer should most likely be A
Explanation:
you see B and C are pretty much the same but A has more weight and more wheels (sorry been a while sense I did this so I am calling the wheel and axel points what they look like to me) with having more wheels and axels and more weight it should have a higher force advantage.
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Hope it helps, and have a good day!
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1. A car has a total mass of 1200 kg and is traveling at 100 km per hour when the driver experience is a brake failure and collides with the barrels. Calculate the change in momentum it will experience whilst coming to a standstill.2. According to GSU's HyperPhysics Project this crash would have been fatal for an average 80 kg person. The safety zone in terms of momentum, ranges from 0 to 1,000 kg per metre per second. Determine the minimum velocity the car can slow down to during a collision with the barrels without the crash being fatal.
Question 1.
Given:
Mass = 1200 kg
Velocity = 100 km per hour.
Let's find the change in momentum it will expperience.
To find the change in momentum, apply the formula:
\(\Delta p=mv_f-mv_i\)Where:
Δp is the change in momentum
m is the mass of the car = 1200 kg
vf is the final velocity
vi is the initial velocity.
Here, the final velocity is = 0 m/s
The initial velocity is = 100 km/h
Let's convert the initial velocity to m/s.
Where:
1 m/s = 3.6 km/h
100 km/h = 100/3.6 = 27.78 m/s
Input the values into the formula and solve for Δp.
We have:
\(\begin{gathered} \Delta p=(1200\times0)-(1200\times27.78) \\ \\ \Delta p=0-3333.33 \\ \\ \Delta p=-33333.33kg.m\text{ /s} \end{gathered}\)Therefore, the change in momentum is 33333.33 kg.m/s
Question 2.
Since the safety zone for momentum is 0 to 1000 kg.m/s, to find the minimum velocity of the car, substitute 1000 kg.m/s for Δp and solve for the final velocity vf
We have:
\(\begin{gathered} \Delta p=m_{}v_f-mv_i \\ \\ 1000=(1200v_f)-(1200\times27.78) \\ \\ 1000=1200v_f-33333.33_{} \\ \\ v_f=\frac{1000-33333.33}{1200} \\ \\ v_f=-26.94\text{ m/s} \end{gathered}\)Therefore, the minimum velocity the car can slow down to a velocity is 26.94 m/s.
ANSWER:
(a). 33333.33 kg/m.s
(b). 26.94 m/s
A ball rolls off a level table with a speed of 2.2 m/s. The table is 1.2 meters high. How far away from the base of the table does the ball land?
The base of table is "1.08856 m" far away from the ball land.
Given:
Distance travelled by ball,
S = 1.2 mInitial velocity,
u = 0 m/sAcceleration,
a = 9.8 m/s²Constant speed,
2.2 m/sAs we know the formula,
→ \(S = ut+\frac{1}{2}at^2\)
By substituting the values, we get
→ \(1.2=\frac{1}{2}\times 9.8t^2\)
→ \(1.2 = 4.9 t^2\)
→ \(t = \sqrt{\frac{1.2}{4.9} }\)
→ \(= 0.4948 \ seconds\)
Let,
Horizontal distance will be "x".Time = t→ \(x = 2.2\times t\)
\(= 2.2\times 0.4948\)
\(= 1.08856 \ m\)
Thus the solution above is right.
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a wave where particles move perpendicular to its energy isa. longitudinal waveb. transverse wavec. both A and Bd. neither A and B
A wave where particles move perpendicular to its energy is a transverse wave. In a transverse wave, the particles of the medium vibrate or oscillate perpendicular to the direction of energy propagation.
This means that the disturbance in the medium is perpendicular to the direction of the wave's motion. Examples of transverse waves include light waves, water waves, and seismic S waves.
In contrast, longitudinal waves are waves where the particles of the medium vibrate or oscillate parallel to the direction of energy propagation. The disturbance in the medium is parallel to the direction of the wave's motion. Examples of longitudinal waves include sound waves and seismic P waves.
Therefore, a wave in which the particles move perpendicular to its energy is a transverse wave.
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which two criteria are least important for engineers to consider when developing a process to produce an important chemical
Answer:
Chemical engineering is a multi-disciplinary branch of engineering that combines natural and experimental sciences such as chemistry and physics, along with life sciences such as biology, microbiology and biochemistryplus mathematics and economics to design, develop, produce, transform, transport, operate
Explanation:
Answer:
A. the process needs to produce significant amounts of ammonia
C. the process needs to be able to be performed safely
Explanation:
a p e x
The temperature of water in a beaker is 25 celcius. After adding a piece of magnesium to the water, the temperature increases to 28 celcius. Is this an exothermic or endothermic.
Answer:
exothermic
Explanation:
A person walks forwards 3 steps in 1 second. Then, the person walks backwards 3 steps in 1 second. Sketch the position-time graph for his movement.
1 What was his distance travelled?
2What was his displacement?
please with your graph
Answer:
Traveled = 6 steps displacement = 0
Explanation:
see attached 'sketch'
if a washing machine draws 8.5 A when connected to a 240 V supply, what is the internal resistance of the machine
The internal resistance of the washing machine is 28.24 Ω.
Current drawn by the washing machine, I = 8.5 A
Voltage of the supply, V = 240 V
Internal resistance of the washing machine = ?
We know that Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.
Mathematically, it is represented as:
V = IR
Where,
V = Voltage
I = Current
R = Resistance
Here, the current drawn by the washing machine, I = 8.5 A
And, the voltage of the supply, V = 240 V
Let us assume the internal resistance of the washing machine is Rᵢ.
Using Ohm's law:
V = IR
⇒ R = V / I
⇒ R = 240 V / 8.5 A = 28.24 Ω
Therefore, the internal resistance of the washing machine is 28.24 Ω.
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PLEASE HELP: A planet has an average distance to the sun of 3.36AU. In two or more complete sentances, explain how to calculate the orbital peroid of the planet and calculate it.
Answer:
Use the AU formula
Explanation:
1 astronomical unit = 149597871 kilometer
1. A train is traveling on a straight section of track at constant speed. In 60
seconds it covers a distance of 1800 meters. What is the speed of the
train?
Answer:
30 mph
Explanation:
1800 divided by 60
When an object travels at a constant speed with zero acceleration it is known as uniform rectilinear motion. Then its velocity is given by:
v = d / t
Where d is distance and t is time. Evaluating:
v = 1800 m / 60 s
v = 30 m/sIf you were to a derail an 8,000,000 kg train that is traveling 10 m/s, how long will it take to bring it to a stop if a 2 kN frictional force is applied?
Answer:
40,000 s
Explanation:
Find the acceleration of the train given the mass and the force applied.
Convert 2 kN to N --> 2000 N.
Substitute the train's mass and applied force into Newton's 2nd Law:
F = ma 2000 = 8,000,000 * a a = 0.00025 m/s²SInce the train is slowing down, the acceleration should be negative.
Using the acceleration, initial velocity, final velocity, we can solve for time using this kinematic equation:
v = v₀ + at 0 = 10 + (-.00025)t -10 = -.00025t t = 40000 sIt will take 40,000 seconds to bring the train to a stop if a 2 kN frictional force is applied.
How does Kirchhoff's Junction Rule apply to series circuits?(1 point) Responses It states that the current can be calculated at any part of the circuit by using V = IR. It states that the current can be calculated at any part of the circuit by using , V, = , IR, . It states that the voltage is the same at all points in the circuit. It states that the voltage is the same at all points in the circuit. It states that the current is the same throughout the entire circuit. It states that the current is the same throughout the entire circuit. It states that the voltage drop across any component of the circuit is equal to V = IR.
The Moon is much smaller than Earth but is still made of rock that you could walk on. However, you would need a spacesuit to do this. Why
a solid sphere or radius 2 cm is concentric with a sperical conducting shell of inner radius 2a and outer radius 2.4a. what is the magntude of the eltric field at radial distances
Magntude of the eltric field at radial distances is 12.8a^2.
What is a spherical shell's volume determined?V = 4/3 r3, where V stands for volume and r for radius, is the equation for a sphere's volume. Half the diameter makes up a sphere's radius.
A conducting sphere has no electric field inside of it. In the same way as a point charge, the electric field outside the sphere is determined by the equation E = kQ/r2. On the outside of the sphere, there is an extra charge.
The curved surface area of the sphere is equal to its entire area because it has a completely curved shape. Alternatively, it is known as lateral surface area. Sphere's radius (r) and its surface area (a) are both expressed as 4r2.
Explanation:
2*2a*2.4a =r =9.6a^2
V = 4/3 *9.6a^2 = 1.3334 * 9.6a^2 = 12.8a^2.
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A copper wire has a square cross section 2.7 mm on a side. The wire is 3.9 m long and carries a current of 4.0 A . The density of free electrons is 8.5×1028m^−3.
Part A Find the magnitude of the current density in the wire.
Part B Find the magnitude of the electric field in the wire.
Part C How much time is required for an electron to travel the length of the wire?
Part A) The magnitude of the current density in the wire is 5.48×10⁵ A/m².
Part B) The magnitude of the electric field in the wire is 0.00916 V/m.
Part C) The time required for an electron to travel the length of the wire is approximately 9.51×10⁴ seconds or 264 hours.
Part A:
The current density, J, is defined as the amount of current per unit area perpendicular to the direction of current flow. For a wire with square cross section, the current density can be found as:
J = I / A
where
I is the current flowing through the wire and
A is the cross-sectional area of the wire.
The cross-sectional area of the wire is given by:
\(A = (2.7 mm)^2\)
= 7.29×10⁻⁶ m²
Substituting the given values, we get:
J = 4.0 A / 7.29×10⁻⁶ m²
= 5.48×10⁵ A/m²
Therefore, the magnitude of the current density in the wire is 5.48×10⁵ A/m².
Part B:
The electric field in the wire, E, can be found using Ohm's law, which relates the electric field, current density, and the conductivity of the material:
J = σE
where
σ is the electrical conductivity of the material.
The electrical conductivity of copper is 5.96×10⁷ S/m.
Substituting the values, we get:
E = J / σ
= (5.48×10⁵ A/m²) / (5.96×10⁷ S/m)
= 0.00916 V/m
Therefore, the magnitude of the electric field in the wire is 0.00916 V/m.
Part C:
The time required for an electron to travel the length of the wire can be found using the formula:
t = l / v
where l is the length of the wire and v is the drift velocity of electrons.
The drift velocity of electrons can be found using the relation:
J = nev
where
n is the number density of free electrons and
e is the charge of an electron.
Rearranging this equation for v, we get:
v = J / (ne)
Substituting the given values, we get:
v = (5.48×10⁵ A/m²) / (8.5×10²⁸ m⁻³ × 1.6×10⁻¹⁹ C)
= 4.1×10⁻⁵ m/s
Substituting this value and the given length of the wire into the formula for time, we get:
t = 3.9 m / 4.1×10⁻⁵ m/s
= 9.51×10⁴ s
Therefore, the time required for an electron to travel the length of the wire is approximately 9.51×10⁴ seconds or 264 hours.
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an ideal fluid flows through a horizontal pipe whose diam-eter varies along its length. measurements would indicate that the sum of the kinetic energy per unit volume and pres-sure at different sections of the pipe would (a) decrease as the pipe diameter increases, (b) increase as the pipe diam-eter increases, (c) increase as the pipe diameter decreases, (d) decrease as the pipe diameter decreases, or (e) remain the same as the pipe diameter changes.
Answer:
(e) remain the same as the pipe diameter changes.
In an ideal fluid, the sum of kinetic energy per unit volume (also known as the velocity head) and pressure is known as the total head and is a constant along a streamline. This is described by the Bernoulli's equation, which states that the total head is constant along a streamline as long as the fluid is incompressible and frictionless. Therefore, if the pipe diameter varies along its length, the total head would remain the same at different sections of the pipe, even though the kinetic energy and pressure would change.
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A 0.66 kg block is suspended from the middle of a 1.56 m long string. The ends of the string are attached to the ceiling at points separated by 1 m, and the block can slip along the long string. The acceleration of gravity is 9.81 m/s 2 . What is the tension in the string? Answer in units of N.
The tension in the string suspending the weight of the block is determined as 6.47 N.
What is force of tension?Tension is defined as the force transmitted through a rope, string or wire when pulled by forces acting from opposite sides.
The tension in the rope used in towing the car up hill is calculated as follows;
T = ma
where;
m is mass of the carg is the acceleration due to gravitySubstitute the given parameters and solve for the tension in the string suspending the weight of the block.
T = 0.66 kg x 9.8 m/s²
T = 6.47 N
Thus, the tension in the string suspending the weight of the block is determined as 6.47 N.
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David drove the first 6 hours of his journey at 65 km / hour and the last 3 hours of his journey at 80 km / hour . How far is the whole journey in km ?
Answer:
630 km.
Explanation:
To obtain the total distance travelled by David, we shall calculate the distance travelled in each, then sum them together.
Case 1:
Speed 1 (S₁) = 65 km / hour
Time 1 (t₁) = 6 hours
Distance 1 (d₁) =?
Speed = Distance /time
S₁ = d₁ / t₁
65 = d₁ / 6
Cross multiply
d₁ = 65 × 6
d₁ = 390 Km
Case 2:
Speed 2 (S₂) = 80 km / hour
Time 2 (t₂ ) = 3 hours
Distance 2 (d₂) =?
Speed = Distance /time
S₂ = d₂ / t₂
80 = d₂ / 3
Cross multiply
d₂ = 80 × 3
d₂ = 240 Km
Finally, we obtained the total distance travelled by David as follow
Distance 1 (d₁) = 390 Km
Distance 2 (d₂) = 240 Km
Total Distance travelled (dₜ) =?
Total distance = distance 1 + distance 2
dₜ = d₁ + d₂
dₜ = 390 + 240
dₜ = 630 km
Therefore, the total distance travelled by David is 630 km
Calculate the kinetic energy of a 40 kg rock if the rock rolls down the hill with a velocity of 8 m/s.
Answer:
1280 J
Explanation:
see pic
How do plates move in relation to each other at convergent boundaries?
When plates commute in the exact direction it collides, and the plates move to other at convergent boundaries.
The lighter, dense, and much more elastic oceanic plate dips underneath the thicker, more stiff continental plate whenever a continental plate encounters a marine plate.
It's known as subduction. Deep ocean trenches, like the one that runs down South America's west coast, are created by subduction.
The continent's undercut rocks start to melt. On occasions, a chain of eruptions forms as the hot magma rises to the surface and travels through the continent.
Nearly 80% of earthquakes happen along convergent borders when plates are being pushed together.
Destruction, when two continental plates crashes, is just another kind of convergent boundary. The plates collapse and are propelled upward since neither is heavier compared to the other.
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A steel railroad track has a length of 25 m
when the temperature is 0°C.
What is the increase in the length of the
rail on a hot day when the temperature is
30°C? The linear expansion coefficient of
steel is 11 x 10-6 (°C) -¹
Answer in units of m
The length of the rail will rise by 0.00825 meters, or 8.25 millimeters, on a hot day with a temperature of 30°C.
What is temperature?Temperature is a unit of measurement for how hot or cold an object or system is. The average kinetic energy of the particles in a substance or system is expressed by this physical quantity.
How do you determine it?The following formula can be used to determine the lengthening of the rail:
ΔL = αLΔT
where L is the length that has been added, is the linear expansion factor, L is the initial length, and T is the temperature change.
Given:
L = 25 m (original length)
ΔT = 30°C - 0°C = 30°C (change in temperature)
α = 11 x 10^(-6) (°C)^(-1) (linear expansion coefficient)
In the formula, changing the values:
ΔL= (11 x 10(-6) (°C)(-1)) x (25 m) x (30°C).
ΔL = 0.00825 m
Consequently, the length of the rail will rise by 0.00825 meters, or 8.25 millimeters, on a hot day with a temperature of 30°C (rounded to two decimal places).
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A force of 10 pounds acts north and a force of 20 pounds acts west. Find the resultant force
Answer:
oi
Explanation:
In a region of free space, the electric field at an instant of time is E→=(80.0^i + 32.0^j - 64.0^k) N/C and the magnetic field is B→ = (0.200^i + 0.0800^j + 0.290^k)µT. (b) Determine the Poynting vector for thesaurus
The Poynting vector for the given electric and magnetic fields is S = 33.12^i - 57.84^j + 2.56^k (units: W/m²).To determine the Poynting vector, we can use the formula:
S = E x B
where S is the Poynting vector, E is the electric field vector, and B is the magnetic field vector.
Given:
E→ = (80.0^i + 32.0^j - 64.0^k) N/C
B→ = (0.200^i + 0.0800^j + 0.290^k) µT
Let's convert the magnetic field from µT to T by multiplying it by 10^-6.
B→ = (0.200^i + 0.0800^j + 0.290^k) T
Now we can calculate the cross product of E→ and B→ to find the Poynting vector:
S = E x B
Expanding the cross product, we get:
S = (E_y * B_z - E_z * B_y) i + (E_z * B_x - E_x * B_z) j + (E_x * B_y - E_y * B_x) k
Plugging in the given values, we have:
S = (32.0 * 0.290 - (-64.0) * 0.0800) i + ((-64.0) * 0.200 - 80.0 * 0.290) j + (80.0 * 0.0800 - 32.0 * 0.200) k
Simplifying the calculations, we find:
S = 33.12 i + (-57.84) j + 2.56 k
Therefore, the Poynting vector for the given electric and magnetic fields is S = 33.12^i - 57.84^j + 2.56^k (units: W/m²).
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pls help i’ll give brainliest if you give a correct answer!!
The fact that quasars can be detected from distances where even the biggest and most luminous galaxies cannot be seen means that Select one: A. they must be in directions where intergalactic absorption by dark matter is minimum, allowing us to see them. B. they must be intrinsically far more luminous than the brightest galaxies. C. they have not been as redshifted by their motion as have galaxies, and hence they can still be seen. D. they must be in directions where gravitational focusing by the masses of nearer galaxies makes them visible from Earth.
Answer:
B. they must be intrinsically far more luminous than the brightest galaxies.
Explanation:
Quasar is famous for being an intergalactic object which is billions of years away from the earth yet can still be seen, unlike the other star body, unlike giant galaxies.
Hence, the fact that quasars can be detected from distances where even the biggest and most luminous galaxies cannot be seen means that "they must be intrinsically far more luminous than the brightest galaxies."
This condition, including other related evidence gotten in recent years concerning our galaxy, has shown that quasars are probably the central nuclei of very distant, very active galaxies.