Systems of linear equations in two variables can be solved in one of four ways: by graphing; by the substitution approach; or by the elimination method and by matrix approach.
Define linear equation.A linear equation is an algebraic equation of the form y=mx+b, where m is the slope and b is the y-intercept, and only a constant and a first-order (linear) term are included. The variables in the preceding equation are y and x, and it is occasionally referred to as a "linear equation of two variables." Because a straight line emerges when we attempt to display the graph of the provided linear function, a linear equation is known as linear.
Given,
The four methods of solving linear equations are:
The Substitution Method
The Graphing Method.
The Addition Method, also known as the Linear Combination Method, and the Elimination Method.
The Matrix Approach
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charles owns a catering business. the amount his 10 most recent clients spent is shown in the histogram below. a bar graph is entitled cost per event. the event cost is on the x-axis and the number of events is on the y-axis. there are 2 events with a cost of 1,000-1,499; 4 with a cost of 1,500 to 1,999; 3 with a cost of 2,000 to 2,499; 1 with a cost of 3,000 to 3,499. why is the graph misleading?
The graph is misleading because the x-axis scale shows that the given data is more clustered than it actually is.
What is a misleading graph?
A misleading graph, sometimes referred to as a distorted graph, misrepresents data, amounts to statistical abuse, and may lead to the drawing of an inaccurate conclusion.
What is a data set?
A data set is a grouping of connected, discrete pieces of connected data that can be viewed separately, together, or handled as a single unit. A data structure of some kind is used to arrange a data set.
Here, we have
2 events with a cost of 1,000-1,499;
4 events with a cost of 1,500 to 1,999;
3 events with a cost of 2,000 to 2,499;
1 event with a cost of 3,000 to 3,499
We concluded from the given dataset that the cost of the event is plotted on the x-axis.
In a given dataset, the entry from 2500 to 2599 is missing.
The graph generates a point cluster that isn't actually displayed on the data components because of the missing item.
Hence, the graph is misleading because the x-axis scale shows that the given data is more clustered than it actually is.
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Refer to Table S6.1- Factors for Computing Control Chart Limits (3 sigma) for this problem. Sampling 4 pieces of precision-cut wire (to be used in computer assembly) every hour for the past 24 hours has produced the following results Hour X R Hour x R Hour x R Hour x 1 3.35" 0.76" 2 3.00 1.23 3 3.32 1.43 4 3.49 1.21 5 3.17 1.17 6 2.96 0.42 7 2.95" 0.58" 13 3.21 0.90" 194.51" 1.56" 8 2.55 1.13 14 2.83 1.36 20 2.89 1.09 9 2.92 0.66 15 3.12 1.11 21 2.65 1.08 10 2.95 1.33 16 2.74 0.50 22 3.38 0.46 11 2.83 117 17 2.96 1.4323 12 2.97 0.40 18 2.74 1.3424 3.04 2.64 1.63 1.02 Based on the sampling done, the control limits for 3-sigma x chart are (round all intermediate calculations to three decimal places before proceeding with further calculations): Upper Control Limit (UCLinches (round your response to three decimal places). Lower Control Limit (LCL?)-inches (round your response to three decimal places). Based on the x-chart, the wire cutting process has been The control limits for the 3-sigma R-chart are (round all intermediate calculations to three decimal places before proceeding with further calculations) Upper Control Limit (UCLR)inches (round your response to three decimal places).
The control limits for 3-sigma x chart are
Upper Control Limit - 3.807 inches
Lower Control Limit - 2.291 inches
The control limits for the 3-sigma R-chart are Upper Control Limit- 2.373 inches
X-double bar = Sum of observations (x-bar) / Total number of observations
X-double bar = 73.17 / 24
X-double bar = 3.049
R-bar = Sum of observations (R) / Total number of observations
R-bar = 24.97 / 24
R-bar = 1.040
(a) The Upper Control Limit (UCLx) and Lower Control limit (LCLx) for the 3-sigma x-bar chart is calculated as,
UCLx = X-double bar + (A2 x R-bar)
LCLx = X-double bar - (A2 x R-bar)
From the table of factors for computing the control chart limits (3-sigma),
For n = 4 (4-pieces of precision cut wire)
A2 = 0.729
Putting these values in the above formulas, we get,
UCLx = 3.049 + (0.729 x 1.040)
UCLx = 3.807 inches
LCLx = 3.049 - (0.729 x 1.040)
LCLx = 2.291 inches
Based on the x-bar chart, the wire cutting process has been out of control, because the observation at 19th hour (4.51) lie outside the computed upper control limit and lower control limit.
(b) The Upper Control Limit (UCLr) and Lower Control limit (LCLr) for the 3-sigma R-chart is calculated as,
UCLr = D4 x R-bar
LCLr = D3 x R-bar
From the table of factors for computing the control chart limits (3-sigma),
For n = 4 (4-pieces of precision cut wire)
D3 = 0, D4 = 2.282
Putting these values in the above formulas, we get,
UCLr = 2.282 x 1.040
UCLr = 2.373 inches
LCLr = D3 x R-bar
LCLr = 0 x 1.040
LCLr = 0 inches
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PLEASE HELP I KNOW I DONT HAVE THAT MUCH POINTS BUT NOBODY HAS HELPED ME WITH THIS :C I'LL GIVE BRAINLIEST 5 STARS AND A THANKS ITS DUE SOON SO THANKS IF U HELPED :C
Answer:
A
Step-by-step explanation:
rise/run, so the slope would be 3/2, but since the graph is a negative it would be -3/2
and the y-intercept is 130
if the marks of students in a class are [110,70,30,80,90,64] then what is the median of these marks?
Answer:
The Median is 75
Step-by-step explanation:
Medianmedian is the middle number in a set of given numbers
arranging in order will be
30,64,70,80,90,110
the middle numbers are 70 and 80
Median=80+70/2
=150/2
Median=75
There are 580 students at Alejandro’s school. He surveys a random sample of 60 students and finds that 21 of them regularly bring their lunch. Based on these results, estimate how many students at Alejandro’s school regularly bring their lunch.
Answer:
63
Step-by-step explanation:
If you have the total number of students at the school, you can divide that by 60 and you get 3. You make 21 and 60 a fraction to get you 21/60. You then multiply 21 by 3 to get 63. 63 kids pack lunch.*
*not sure if this is correct or not?
The measure of an angle is 1.6°. What is the measure of its complementary angle?
Step-by-step explanation:
From the image, let Angle 1 be x, and angle 2 be 16°
\({ \tt{x + 16 = 180}} \\ { \tt{x = 164 \degree}}\)
If the value of a $29,575car decreases by 25% each year due to depreciation, how much will the car be worth after 14 years? Round your answer to the nearest dollar (whole number). Do not enter the dollar sign. For example, if the answer is $5500, type 5500 .
The value worth of the car after 14 years will be $38,259 (Rounded to the nearest dollar).
Given information:Value of a $29,575 car decreases by 25% each year due to depreciation. We need to find how much will the car be worth after 14 years using the above information.Therefore,To find out how much the car will worth after 14 years, we can use the below formula:P = (1-r/n)^nt × P₀Where,P₀ = Initial value of the carP = Worth of the car after n yearsr = Annual depreciation rate (0.25) or 25%t = Number of years elapsedWe can substitute the given values in the above formula:P = (1-0.25/1)^14 × 29,575= (0.75)^14 × 29,575= 1294.632 × 29,575= 38,258.97 (Rounded to the nearest whole number)= $38,259 (Rounded to the nearest dollar)Hence, the worth of the car after 14 years will be $38,259 (Rounded to the nearest dollar).
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2) A data packet consists of 10,000 bits, where each bit is a 0 or a l with equal probability. Estimate the probability of having at least 5200 ones in terms of the Q-function. Show your work.
The estimated probability of having at least 5200 ones in the data packet is close to 1 or is approximately equal to Q(1).
To estimate the probability of having at least 5200 ones in a data packet consisting of 10,000 bits with an equal probability of 0 or 1, we can use the Q-function.
The Q-function is defined as the probability that a standard normal random variable is greater than a given value. In other words, it tells us the probability that a random variable falls in the tail of the normal distribution.
Step 1:
To apply the Q-function to this problem, we can use the fact that the number of ones in the data packet follows a binomial distribution with n=10,000 and p=0.5. The Q-function can then be used to find the probability of having at least 5200 ones:
Calculate the mean (µ) and standard deviation (σ) of the binomial distribution.
In this case, since each bit has an equal probability of being 0 or 1, the mean (µ) is n * p, where n = 10,000 and p = 0.5. So, µ = 10,000 * 0.5 = 5000.
P(X ≥ 5200) = 1 - P(X < 5200)
P(X < 5200) = Σi=0^5199 (n choose i) * p^i * (1-p)^(n-i)
P(X < 5200) = Q((5200 - np)/√(np(1-p)))
P(X ≥ 5200) = 1 - Q((5200 - np)/√(np(1-p)))
Step 2: Standardize the number of ones (5200) to a z-score.
Using the binomial distribution formula, we can calculate P(X < 5200) to be approximately 0.0515. Substituting this value into the Q-function formula, we get:
P(X ≥ 5200) = 1 - Q((5200 - 10000*0.5)/√(10000*0.5*0.5))
P(X ≥ 5200) = 1 - Q(-28.28)
P(X ≥ 5200) ≈ 1
Step 3: Estimate the probability using the Q-function.
The probability of having at least 5200 ones is equal to the probability of having a z-score greater than or equal to 1. This probability can be estimated using the Q-function, denoted by Q(z).
Therefore, the estimated probability of having at least 5200 ones in the data packet is close to 1 or is approximately equal to Q(1).
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A sample of adults was asked to choose their favorite sport to watch from a list of four sports. Age range 18-30 31-50 51+ total sport football 15 19 17 51 baseball 7 12 18 37 basketball 15 8 11 34 soccer 12 9 6 27 total 49 48 52 149 what proportion of those surveyed chose basketball as their favorite sport?.
The percentage of respondents who selected basketball as their favorite sport is 12/149
The proportion of respondents who like soccer who are adults between the ages of 18 and 30 is equal to this proportion of respondents overall.
In general, the term "proportion" refers to a part, share, or amount that is compared to a total. According to the concept of proportion, two ratios are in proportion when they are equal. Two ratios or fractions are equal when an equation or a statement to that effect is used.
A mathematical comparison of two numbers is called a proportion. According to proportion, two sets of provided numbers are said to be directly proportional to one another if they increase or decrease in the same ratio. "::" or "=" are symbols used to indicate proportions.
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Answer:
Step-by-step explanation:
SOMEONE PLZZZ HELP ME PLZZZZZZ
Answer:
hiii
Step-by-step explanation:
=-8
Answer:
x = -5
Step-by-step explanation:
Jimmy ran 20 meters west from home and then turned north to jog 25 meters. jimmy ran 45 meters, but could have arrived at the same point by jogging in a straight line. how many meters could he have jogged using a straight line distance? responses 3.5 meters 3.5 meters 7 meters
Using the Pythagorean Theorem, it is found that using a straight line distance, he could have jogged 32 meters.
What is the Pythagorean Theorem?The Pythagorean Theorem relates the length of the legs \(l_1\) and \(l_2\) of a right triangle with the length of the hypotenuse h, stating that the hypotenuse squared is the sum of the legs squared, according to the equation presented as follows:
\(h^2 = l_1^2 + l_2^2\)
In the context of this problem, the sides of the triangle are given as follows:
20 meters west = 20 meters to the left.25 meters north = 25 meters up.Hence the distance that he could have jogged is the hypotenuse of the right triangle, calculated as follows:
d² = 20² + 25²
d = sqrt(20² + 25²)
d = 32 meters.
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The area of a rectangle is changing as its side length ( in inches) changes and is represented as a function of the length, f (Z) = 2² + 20%. Determine the average rate of change (AROC) of area with respect to side length as the side length increases from 2 inches to 4 inches. AROC is Determine the AROC of area with respect to side length as the side length increases from 4 inches to 6 inches. AROC is The function has positive concavity over the interval from 2 inches to 6 inches because the AROC is (increasing or decreasing) and a/an (increasing or decreasing) rate.
The function has positive concavity over the interval from 2 inches to 6 inches because the AROC is increasing and an increasing rate.
The average rate of change (AROC) of the area with respect to the side length can be found by calculating the change in the area divided by the change in the side length.
To determine the AROC of the area as the side length increases from 2 inches to 4 inches, we need to calculate the change in area and the change in side length over that interval. Let's denote the initial side length as Z1 and the final side length as Z2.
Initial side length (Z1) = 2 inches
Final side length (Z2) = 4 inches
Change in side length = Z2 - Z1 = 4 - 2 = 2 inches
Now, we need to calculate the corresponding change in the area. Using the given function f(Z) = 2Z² + 20%, we can find the area at Z1 and Z2.
Area at Z1: f(Z1) = 2(2)² + 20% = 8.8 square inches
Area at Z2: f(Z2) = 2(4)² + 20% = 32.8 square inches
Change in area = f(Z2) - f(Z1) = 32.8 - 8.8 = 24 square inches
The function has positive concavity over the interval from 2 inches to 6 inches because the AROC is increasing and an increasing rate.AROC of area with respect to side length from 2 inches to 4 inches = Change in area / Change in side length = 24 square inches / 2 inches = 12 square inches per inch.
To determine the AROC of the area as the side length increases from 4 inches to 6 inches, we repeat the same process.
Initial side length (Z1) = 4 inches
Final side length (Z2) = 6 inches
Change in side length = Z2 - Z1 = 6 - 4 = 2 inches
Area at Z1: f(Z1) = 2(4)² + 20% = 32.8 square inches
Area at Z2: f(Z2) = 2(6)² + 20% = 72.8 square inches
Change in area = f(Z2) - f(Z1) = 72.8 - 32.8 = 40 square inches
AROC of area with respect to side length from 4 inches to 6 inches = Change in area / Change in side length = 40 square inches / 2 inches = 20 square inches per inch.
The function has positive concavity over the interval from 2 inches to 6 inches because the AROC is increasing and an increasing rate.
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What is the slope of the line with equation y−3=(x−2)?
A coordinate plane with a line passing through the points at (2, 3) and (4, 2).
–2
–negative StartFraction one-half EndFraction.
StartFraction one-half EndFraction
2
Mark
Answer:
The correct answer is slot one/1... Have great day :)
Step-by-step explanation:
Answer:
Step-by-step explanation:
assume you purchased some corporate stock 4 years ago for $7,500. You received quarterly dividends of 875 ; your dividends total $1,200 (16 dividend checks ×$75=$1,200). You sold the stock today for $8,050. 6. The PV is $8,050 because that is the amount you received today (in the present). (T or F ) 7. $1,200 represents which variable (PV, PMT, or FV)? 8. What is the FV amount? Unit 12.2 Financial calculators 9. When is it not necessary to clear the TVM registers? 10. By setting our "periods per year" register at 1 we must enter the periodic rate in the i-register. (T or F)
6. False. The present value (PV) is the initial investment or the amount invested in the stock, which is $7,500, not the amount received today ($8,050).
7. $1,200 represents the variable PMT (Payment). It represents the total dividends received over the four-year period.
8. The future value (FV) amount is $8,050, which is the amount received from selling the stock today.
9. It is not necessary to clear the TVM (Time Value of Money) registers when the calculations are completed, and you don't need to perform any further calculations.
10. True. When the "periods per year" register is set to 1, the periodic rate (interest rate) should be entered directly into the i-register as a decimal value, such as 0.05 for 5%.
Therefore, the PV is not $8,050 but $7,500, representing the initial investment. The variable $1,200 represents the PMT (payment) or the total dividends received. The FV amount is $8,050, the selling price of the stock. Clearing the TVM registers is not necessary after completing calculations, and when "periods per year" is set to 1, the periodic rate is entered directly into the i-register.
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Tamar's house is greater than 472 and less than 500 which number can be on Tamar's house?
490
472 <490<500
it fits the criteria
List 5 Characteristics of a Quadratic function
Quadratic equation properties are described below:
1) A parabola that opens upward ( depends on the coefficient of x² ) contains a vertex that is a minimum point.
2) Standard form is y = ax² + bx + c, where a≠ 0.
a, b, c = coefficients .
3)The graph is parabolic in nature .
4)The x-intercepts are the points at which a parabola intersects the x-axis either positive or negative x -axis .
5)These points are also known as zeroes, roots, solutions .
Hence quadratic equation can be solved with the help of these properties.
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Please answer correctly !!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!!
Answer:
222 okkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk
Answer:
138°.
Step-by-step explanation:
Extend one of the lines that forms the angle. You should get a triangle. Because the topmost and bottoms lines are straight, one of the angles has to equal 180-111, which is 69°(nice). The opposite angle to that has to also be that size. Since the topmost and bottomost lines are parallel the alternate interior angle to the 111° outside of the triangle would also equal 111°. So, because it's a straight line, the angle next to it, which is inside the triangle, is once again 69°(nice). Then, since you have 2 angles of the triangle you can add them together and subtract their sum from 180°, that should be 42°. One of the lines that 42° is on is also one x is on, so 42°+x=180°. Using this, you can find that x should be about 138°, I think.
I=?. P=$475.00,r=4%,t = 3 years Find the missing value
Answer:
I=$57.00
I=Prt
I=(475)(.04)(3)
I= $57.00
I need an answer immediately!!!!!!!
Answer:
y = 3x - 8
Step-by-step explanation:
_______________
I NEED THIS NOWW HELPP REAL ANSWERS ONLY WILL GRANT BRAINLIEST
Answer:
Reflect over the y-axis, vertically stretch by a factor of 3, and then shift down 1 unit
Step-by-step explanation:
The general form of the straight line equation is, y = m·x + c
Where;
m = The slope
c = The y-intercept
The parent function is, f(x) = x
The slope of the parent function, m₁ = 1
The y-intercept of the parent function, c₁ = 0
The x-intercept of the parent function = 0
The equation of the given function g(x) is derived as follows;
Two points on the line g(x) are (-2, 5) and (1, -4)
The slope of g(x), m₂ = (-4 - 5)/(1 - (-2)) = -3
The equation of g(x) is therefore;
y - 5 = -3 × (x - (-2)) = -3·x - 6
∴ y = -3·x - 6 + 5 = -3·x - 1
y = -3·x - 1
The slope of the given function, m₂ = -3
The y-intercept of the given function, c₂ = -1
The x-intercept of the function = -1
We have that a reflection of (x, y) across the y-axis gives (-x, y)
Therefore, the function g(x) is a reflection of f(x) across the y-axis
The slope of g(x) = -3 × The slope of f(x), therefore, g(x) is obtained by a vertical stretch of of f(x) by a factor of 3
The y-intercept of g(x) is lower than the y-intercept of g(x) by -1, therefore, f(x) is shifted down vertically by 1 unit to obtain g(x)
Therefore, the sequence of transformation that can be used to obtain g(x) from the parent function f(x) are;
Reflect over the y-axis, vertically stretch by a factor of 3, and then shift down 1 unit
The PTA has 180 packs of soda to sell. Each pack of soda cost $9.99. The PTA sold 95 packs of soda before school. The remaining packs of sodas were sold after school. How much money did the PTA collect when selling sodas after School?
Let's begin by listing out the information given to us:
PTA has 180 soda packs to sell = 180 soda packs
Each pack of soda cost $9.99 = $9.99 /soda
PTA sold 95 packs of soda before school = 95 soda packs
To find how much money the PTA collected after school, we will have to find the number of soda packs sold after school
To get the number of soda packs sold after school, subtract the number of soda packs sold before school from the total number of soda packs.
Mathematically,
Number of soda packs sold after school = 180 - 95 = 85 soda packs
How much money did the PTA collect when selling sodas after School = Number of soda packs sold after school * Cost of each soda pack
= 85 * 9.99 = $849.15
2/63 as a percentage round to the nearest tenth of a percent
2/63 as a percentage round to the nearest tenth of a percent can be written as 31.7%
Fractions refer to a part of a whole. The word fraction comes from Latin word Fractus meaning broken. A percentage is a number that can be expressed as a fraction of 100. The word percent means per 100. It is represented by the symbol %.
Fractions can be converted into percentages by the following steps:
1. Convert the fraction into decimals.
Therefore, on converting 2/63 to decimal we get 0.317
2. Multiply the given decimal by 100 to get a percentage
Hence, the percentage we get after multiplication is 31.7%.
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Math 2 Homework Mod 2.1 (Day 2) Absolute Value Functions
Per 5
Name
1. Describe transformations, graph, and state domain & range using any notation
a) f(x) = -2x+6
Describe transformations in words:
Vertex:
Stretch factor
Domain:
Range:
The descriptions of the transformations are:
Vertex: (-6, 0)Stretch factor: 2Domain: set of all real numbersRange: set of real numbers greater than or equal to 0How to describe transformations, graph, and state domain & range using any notation?The function is given as:
f(x) = -2|x + 6|
The above function is an absolute value function, and an absolute value function is represented as:
f(x) = a|x - h| + k
Where
Vertex = (h, k)
Scale factor = a
So, we have:
a = -2
(h, k) = (-6, 0)
There is no restriction to the input values.
So, the domain is the set of all real numbers
The y value in (h, k) = (-6, 0) is 0
i.e.
y = 0
Because the factor is negative (-2), then the vertex is a minimum
So, the range is all set of real numbers greater than or equal to 0
Hence, the descriptions of the transformations are:
Vertex: (-6, 0)Stretch factor: 2Domain: set of all real numbersRange: set of real numbers greater than or equal to 0Read more about absolute value function at
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what is equivelant to the ratio 2;9
Answer:
4;18 , 6:27, 8;36 and so on
Step-by-step explanation:
just multiply both components with the same number. for eg : 2;9 = 2×2;9×2= 4;18
Answer:
4:18
Step-by-step explanation:
To get this Answer I Started by multiplying 2 by 2 then 9 by 2 beacuse when finding an equivalent ratio you multiply whatever number you have by whatever number you want ( 2x2) then multiply whatever number you multiplied it by (9x2) to find your equivalent ratio!
Hope this helps!
Make sure to take notes and practice! :)
So far in math you have taken 10 quizzes this semester. The mean of the scores is 88.5 what is the sum
Answer:
Use M a t h w a y it helps. Trust me.
The sum of scores in quizzes of math is \(\boldsymbol{885}\).
"To understand the calculation, check below."
What is mean?Mean is calculated by dividing sum of all the observations by number of observations.
For a data collection containing numbers that are close together, the mean is the best option.
Total number of quizzes in math \(=10\)
Mean scores \(=88.5\)
Therefore,
Sum of all scores \(=10 \times 88.5\) \(=\boldsymbol{885}\)
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WILL GIVE BRAINLIST TO BEST ASNWER
Find the measure of each angle indicated
Answer:
66°
Step-by-step explanation:
Can someone help me please
Suppose you have an urn (a large vase for which you cannot see the contents) containing 4 red balls and 7 green balls. 1. You pick a ball from the urn and observe its color, and return it to the urn (i.e sample with replacement). Then, you do this again. Consider the events A = {first ball is red}, B = {second ball is green}. (1) Are A and B independent events? Use the mathematical definition of independent events to justify your answer.
No, events A and B are not independent.
Events A and B are not independent because the occurrence of event A (first ball is red) affects the probability of event B (second ball is green). In order for two events to be independent, the probability of the second event must remain the same regardless of whether the first event occurs or not.
Let's consider the probabilities involved. Initially, the urn contains 4 red balls and 7 green balls, making a total of 11 balls. When we pick a ball from the urn and observe its color, there is a probability of 4/11 that the first ball is red. After observing the color and returning the ball to the urn, the urn still contains 4 red balls and 7 green balls.
Now, for event B, the probability of drawing a green ball on the second pick depends on the outcome of the first pick. If the first ball is red, then the probability of the second ball being green is 7/11, since there are still 7 green balls remaining out of the total 11 balls. However, if the first ball is green, then the probability of the second ball being green becomes 6/11, as there are now 6 green balls left out of the total 11 balls.
Since the probability of event B changes depending on whether event A occurs or not, events A and B are not independent.
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At a sporting goods store, the price of a bicycle is $650. During a sale, this price is marked down 45%. What is the sale price of the bicycle? Enter your answer in the box. $
Answer:
$357.5
Step-by-step explanation:
Answer:
347.50
Step-by-step explanation:
you have to put the 0 at the end i didnt and got it wrong.
Help pls thank you!!!!!!!!!!!! First to answer it RIght will receive Brainliest!!!!!!!!!!!!!!!!!!!
Answer:
C
Step-by-step explanation:
hope this helps!
have a great day :)