High temperature gives the hydrogen atoms enough energy to overcome the electrical repulsion between the protons. Fusion requires temperatures of about 100 million Kelvin (approximately six times hotter than the sun's core).
\(study \: well\)
someone help please !!
Answer:
c.
is the answer please brainliest
What name did marie curie give to the process by which materials give off rays capable of fogging photographic plates?
The study of radioactivity by Marie Curie marked a significant turning point in the realm of physics and had a significant influence on scientific knowledge. Now let's get into the specifics.
"Radioactivity" is the term Marie Curie coined to describe the phenomenon whereby materials emit radiation that can fog photographic plates. During her uranium investigation in 1896, she made this discovery. This game-changing discovery opened the door for more research into and comprehension of radioactivity, which resulted in important developments in the field of nuclear physics.
Marie Curie's research on radioactivity served as a springboard for additional nuclear physics research and has profound ramifications for other fields of science and medicine. It resulted in improvements in our knowledge of atomic structure, the creation of radiation therapy for the treatment of cancer, and the eventual exploitation of nuclear energy.
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A beaker containing 400g of water has 1200J of work done on it by stirring and 200cal of heat added to it from a hot plate.8.What is the temperature change of the water?A.1.2°C B.2.1°C C.1.4°C D.4.1°C
A.1.2°C
ExplanationThe First Law of Thermodynamics states that heat is a form of energy, and thermodynamic processes are therefore subject to the principle of conservation of energy.
To find internal energy, you have to add the heat added in the system and work done in the system because the work done is not lost but rather it is added in the system.
\(\begin{gathered} \Delta U=q+W \\ where\Delta U\text{ is the change in the internal energy} \\ q\text{ the heat added to the system} \\ W\text{ is the work done by the systeme} \end{gathered}\)Step 1
a)let
\(q=200\text{ cal}\)to add the energy it must have the same measure unit, so let's convert calories into Julies
remember that
\(\begin{gathered} 1\text{ cal}\Rightarrow4.184\text{ J} \\ so \\ 200\text{ cal}\Rightarrow200(4.814\text{ J})\Rightarrow836.8\text{ J} \end{gathered}\)b) now, replace in the formula
\(\begin{gathered} \Delta U= q+W \\ \Delta U=836.8\text{ J+1200 J} \\ \Delta U=2036.8\text{ J} \end{gathered}\)now, we have the change of internal energy
Step 2
now, let's find the change in temperature
Use the calorimetry formula.
\(\begin{gathered} Q=mc∆T \\ \end{gathered}\)where m is the mass, Q = heat energy, c = specific heat capacity, and ∆T = change in temperature
a)
let
\(mass=\text{ 0.4 kg}\)now,
\(\begin{gathered} Q=mC\Delta T \\ 2036.8\text{ j=0.4 kg*4184 }\frac{J}{Kg}|C*\Delta T \\ 2036.8=1673.6\Delta T \\ divide\text{ both sides by 1673.6} \\ \frac{2,036.8}{1673.6}=\frac{1,673.6\text{ }\Delta T}{1673.6} \\ 1.21=\Delta T \\ rounded \\ \Delta T=1.2\text{ \degree C} \end{gathered}\)so, the answer is
A.1.2°C
Which object has the HIGHEST mass?
A. A gold ring
B. An empty water bottle
C. A pillow
D. A balloon filled with air
a 2.5 kg mass is attached to the 0 cm mark on a 1 kg meter stick. a mass of 0.5 kg is attached to the 100 cm mark of the meter stick. the stick is rotated around an axle that is attached at the 20 cm mark. what is the moment of inertia of the system?
The definition of moment of inertia allows to find the results for the with respect to each axis are:
1-Iₓ = m r²
2-Iy=9m r²
3-Iz=10m r².
What is moment of inertia ?
The moment of inertia is a scalar quantity is obtained by the expression.
Sol-
I =∫ r² dm
Where I is the moment of inertia , m the mass of the body and r the distance from the axis of rotation.
In the case of point particles, the expression reduces to
I = m r²
In this case we calculate with respect to each coordinate axis.
a) With respect to the x axis the distance is x = r, the moment of inertia is
Iₓ = m r²
with respect to the y-axis, indicate that the distance is y = 3 r.
We calculate
I_y = m (3r) ²
I_y = 9 m r²
c) Regarding the z-axis.
We look for the distance.
z =√x^2+y^2
z = √ 1^2+3^2
We calculate the moment of interia Iz = m (10r²)
Iz = 10 m r²
In conclusion using the definition of moment of inertia we can look for the results of the moment of inertia for each axis are:
a) Iₓ = m r²
b) I_y = 9 m r²
c) I_z = 10 m r²
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what is another word for technology
Answer:
ELECTRONICS
Explanation:
Answer:
Technological
Explanation:
An airplane from rest accelerates on a runway at 7.25 m/s² for 35 seconds until it finally takes off the ground. Solve the distance covered by the airplane.
G:
R:
E:
S:
A:
2.How long will it take for a car to travel from 37 m/s to 60 m/s that accelerates at 3.68m / s²
G:
R:
E:
S:
A::
It will take the car 6.25 seconds to travel from 37 m/s to 60 m/s with an acceleration of 3.68 m/s².
For the first question, we can use the equation:
distance = 0.5 x acceleration x time^2
We know the acceleration (7.25 m/s²) and the time (35 seconds), so we can plug those in:
distance = 0.5 x 7.25 m/s² x (35 s)^2
distance = 0.5 x 7.25 m/s² x 1225 s²
distance = 4448.125 meters
Therefore, the airplane covered a distance of 4448.125 meters before taking off the ground.
For the second question, we can use the equation:
final velocity = initial velocity + acceleration x time
We know the initial velocity (37 m/s), the final velocity (60 m/s), and the acceleration (3.68 m/s²), so we can rearrange the equation to solve for time:
time = (final velocity - initial velocity) / acceleration
time = (60 m/s - 37 m/s) / 3.68 m/s²
time = 6.25 seconds
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A projectile is thrown with velocity v at an angle θ with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is ____?
\(\purple{ \longrightarrow \bf{h_m = \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} }} \)
Projectile is thrown with a velocity = v Angle of projection = θVelocity of projectile at a height half of the maximum height covered be \( \sf{v_0}\)\(\qquad\)______________________________
Then –
\(\qquad\) \(\pink{ \longrightarrow \bf{ \dfrac{h_m}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }}\)
\(\qquad\) \( \longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} \times \dfrac{1}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }\)
\(\qquad\)\(\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{4g} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }\)
\(\qquad\)\(\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2} = {v_0}^{2} \: {sin}^{2} \theta }\)
\(\qquad\)\( \longrightarrow \sf{ \dfrac{ {v}^{2} }{2} = {v_0}^{2} }\)
\(\qquad\)\( \longrightarrow \bf{v_0 = \sqrt{ \dfrac{ {v}^{2} }{2} } = \dfrac{v}{ \sqrt{2} } }\)
Now, the vertical component of velocity of projectile at the height half of \( \sf{h_m}\) will be –\(\qquad\) \(\longrightarrow \bf{v_{(y)}=v_0 \: sin \theta }\)
\(\qquad\) \( \longrightarrow \bf{v_{(y)} = \dfrac{v}{ \sqrt{2} } \: sin \theta = \dfrac{v \: sin \: \theta}{ \sqrt{2} } }\)
Therefore, the vertical component of velocity of projectile at this height will be–
☀️\(\qquad\)\( \pink {\bf{ \dfrac{v \: sin \: \theta}{ \sqrt{2} }} }\)
Answer:
A projectile is thrown with velocity v at an angle θ with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is v sintheta / √2
The density of pure diamond is 3.5 g/cm3. what is the volume of a diamond with a mass of 0.25 g?
The volume is 0.21 cm³.
The density of the pure diamond is: ρdiamond = 3.5g/cm³
The mass of the diamond is: m = 0.75g
Write the expression for the density of the diamond.
ρdiamond = m/V
Here, the volume is V.
Substitute the known values.
(3.5g/cm³) = 0.75gV
V = 0.75g/3.5g/cm³
V = 0.2142857143cm³
V ≃ 0.21cm³
Thus, the volume is 0.21 cm³.
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A stone is thrown vertically upwards with an initial velocity of 20m/sec. Find the maximum height ot reaches and the time taken by it to reach the height. (g=10m/s2)
plz short numerical ASAP
Answer:
The height reached is 20m, The time taken to reach 20m is 2 seconds
Explanation:
Observing the equations of motion we can see that the following equation will be most helpful for this question.
\(v^{2} = u^{2} + 2as\)
We are given initial velocity, u
We know that the stone will stop at its maximum height, so final velocity, v
Acceleration, a
And we are looking for the displacement (height reached), s
Substitute the values we are given into the equation
\(0^{2} = 20^{2} + 2(10)s\)
Rearrange for s
\(0^{2} -20^{2} =20s\)
\(-400=20s\)
\(\frac{-400}{20} =s\)
s = -20 (The negative is just showing direction, it can be ignored for now)
The height reached is 20m
Use a different equation to find the time taken
\(s = vt - \frac{1}{2} at^{2}\)
Substitute in the values we have
\(-20=(0)t - \frac{1}{2} (10)t^{2}\)
Rearrange for t
\(-20 =0 -5 t^{2}\)
\(\frac{-20}{-5} =t^{2}\)
\(4 = t^{2}\)
t = 2s
The time taken to reach 20m is 2 seconds
A large truck is moving at 22.0 m/s. if its momentum is 125,000 kg • meters per second, what is the truck's mass? 176 kg 2750 kg 5680 kg 11,400 kg
The mass of the large truck is determined as 5680 kg.
Mass of the truck
The mass of the truck is calculated as follows;
P = mv
where;
P is momentumm is massv is velocitym = P/v
m = 125000/22
m = 5680 kg
Thus, the mass of the large truck is determined as 5680 kg.
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Answer:
C. 5680
Explanation:
edg2023
A sound wave traveling through dry air has a frequency of 16 Hz, a wavelength of 22 m, and a speed of 350 m/s. When the sound wave passes through a cloud of nitrous oxide, its wavelength changes to 16 m, while its frequency remains the same. What is its new speed? (The equation for the speed of a wave is v= f x 1.)
A. 350 m/s
B. 16 m/s
C. 5,600 m/s
D. 256 m/s
It's D
Answer:
D. 256 m/s
Explanation:
\(f\) = Frequency of the wave = \(16\ \text{Hz}\)
\(\lambda\) = Wavelength = \(16\ \text{m}\)
Speed of a wave is given by
\(v=f\lambda\)
\(\Rightarrow v=16\times 16\)
\(\Rightarrow v=256\ \text{m/s}\)
The speed of the wave as it passes through the cloud of nitrous oxide is \(256\ \text{m/s}\).
Answer:
D. 256 m/s
Explanation:
d. d as in dog
1. In a discussion, outline elaboratively 5 of the 10 major external forces that affect organizations: economic, social, cultural, demographic, environmental, political, governmental, legal, technological, and competitive. (You may choose any 5 ) 2. I want you to tell me CONVINCINGLY, the importance of gathering competitive intelligence. 3. In business we are aware that economic factors have tremendous impacts in the various strategy applications. Name a few economic variables that we need to monitor. 4. Social, cultural, demographic, and environmental changes have a major impact on virtually all products, services, markets, and customers, that's a given, in your own opinionated words why is this so. 5. List 5 key external factors of your choice including both opportunities and threats you believe affect the firm and its industry. List the opportunities first and then the threats. 6. Explain your opinion on how to prioritize and determine a firm's internal weaknesses and strengths. 7. What do you understand about financial ratio analysis, what is it, and why is it so important in business. 8. A major responsibility of strategists is to ensure development of an effective external audit system. Why do you think this is so? Explain your opinion in this.
1. Five major external forces that affect organizations are economic, social, cultural, demographic, and technological. Economic factors such as inflation and interest rates can impact a company's profitability and purchasing power. Social factors like changing consumer preferences and lifestyles can influence demand for products and services.
Cultural factors like values and beliefs can shape consumer behavior and market trends. Demographic factors such as population size and age distribution can affect target markets.
Technological factors like advancements in automation or digitalization can disrupt industries and create new opportunities. These external forces shape the business environment and organizations must monitor and adapt to them to stay competitive.
2. Gathering competitive intelligence is crucial for businesses because it provides valuable insights about their competitors' strategies, strengths, weaknesses, and market position.
By understanding the competitive landscape, businesses can identify opportunities and threats, make informed decisions, and develop effective strategies.
Competitive intelligence helps businesses stay ahead of their competitors, anticipate market trends, identify emerging technologies, and improve their own products or services. It allows businesses to benchmark their performance, evaluate their competitive advantage, and identify areas for improvement.
Ultimately, gathering competitive intelligence empowers businesses to make proactive and strategic decisions that can lead to sustainable growth and competitive advantage.
3. In business, various economic variables need to be monitored as they have significant impacts on strategy applications. Some important economic variables include GDP (Gross Domestic Product), inflation rate, exchange rates, interest rates, consumer spending, unemployment rate, and industry-specific factors like raw material prices or energy costs.
Monitoring these variables helps businesses understand the overall economic conditions, identify market opportunities, and assess potential risks. For example, a high inflation rate may impact pricing strategies, while a favorable exchange rate can benefit export-oriented businesses.
By monitoring economic variables, businesses can adapt their strategies accordingly and make informed decisions to navigate the dynamic business environment.
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1. Hypothesis - formulate a hypothesis and create a strategy
2. Experiment - carry out the strategy, collect measurements
3. Analysis - draw graphs, evaluate the hypothesis
4. Report - document results
The scientific method is a systematic approach to solving problems in science. It involves formulating a hypothesis, designing experiments to test it, analyzing the data collected, and reporting the results.
The hypothesis is a testable assertion that foretells how an experiment will turn out. In order to collect data and test the theory, experiments are conducted. The data is then examined in order to make inferences and assess the hypothesis. Finally, the findings are presented in clear and plain terms to the scientific community.The scientific method is a methodical approach to problem-solving and decision-making in science. This is a general explanation of the process. It entails the following actions:
Create a verifiable hypothesis.Create and execute experiments to verify the theory.Analyze the information and make judgements.Deliver the results in a clear, succinct manner.you can learn more about hypothesis at:
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Which statement correctly describes the relationship between a blackbody radiator, its temperature, and the electromagnetic radiation it gives off? A. As the blackbody radiator becomes warmer, it emits light of shorter wavelengths.
B. As the blackbody radiator becomes warmer, it reflects different wavelengths of light.
C. As the blackbody radiator becomes warmer, it emits random wavelengths of light.
D. As the blackbody radiator becomes cooler, it emits light of shorter wavelengths.
It's A
Answer:
A. As the blackbody radiator becomes warmer, it emits light of shorter wavelengths.
The temperature, and electromagnetic radiation has a relationship where blackbody radiator becomes warmer, it emits light of shorter wavelengths.
What is radiation?radiation can be regarded as the process of heat dissipation without contact with a body.
Therefore , temperature, and electromagnetic radiation of a black body works in the sense that
blackbody radiator becomes warmer during emissions.
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In all collisions, both elastic and inelastic, which quantity must be conserved?
momentum
velocity
kinetic energy
mechanical energy
Answer:
Momentum is conserved.
All of the others are not conserved because of heat loss caused by deformation, etc.
Which of these examples is NOT a functional group?
Question 5 options:
alkenes
alcohols
esters
salts
Answer: Salt
Explanation: Alkenes, esters, and salts are all functional groups either containing or being functional groups.
The option that is not an example of functional group is salts.
WHAT IS FUNCTIONAL GROUP?A functional group is a moiety in a molecule or compound that causes the molecule's characteristic chemical reactions.
Organic compounds possess specific functional groups that is responsible for their uniqueness in chemical reactions. These organic compounds include;
Alkene - C=HAlkane - C-HAlcohol - C-OHEsters - COOTherefore, the option that is not an example of functional group is salts.
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Two double bonds means that the total number of electrons being shared in the molecule is
One double bond consists 4 electrons, so 2 double bonds means 8 electrons
Answer: 8 electrons
Explanation:edg
Which of the following statements are true?Check all that applyFor the gas to do positive work, the cycle must be traversed in a clockwise manner.Positive heat is added to the gas as it proceeds from state C to state D.The net work done by the gas is proportional to the area inside the closed curve.The heat transferred as the gas proceeds from state B to state C is greater than the heat transferred as the gas proceeds from state D to state A.
Out of the given statements, the true statements are that positive work occurs when the cycle is traversed in a clockwise manner, and the net work done by the gas is proportional to the area inside the closed curve.
1. For the gas to do positive work, the cycle must be traversed in a clockwise manner.
2. The net work done by the gas is proportional to the area inside the closed curve.
In a thermodynamic cycle, positive work is done when the cycle proceeds in a clockwise manner.
Additionally, the net work done by the gas in a cycle is proportional to the area enclosed by the cycle on a pressure-volume diagram.
Hence, Out of the given statements, the true ones are that positive work occurs when the cycle is traversed in a clockwise manner, and the net work done by the gas is proportional to the area inside the closed curve.
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A cannonball of mass m is launched at a speed v 0 from the bottom of a frictionless cannon of length L that makes an angle θ with respect to the horizontal. Q1.1 Part a 1 Point a. What is the maximum height reached by the cannonball during its subsequent trajectory? Q1.2 Part b 1 Point b. What is the cannonball's speed at its point of maximum height?
a. At maximum height, the cannonball's speed will be equal to its horizontal component of the initial velocity.
b. The cannonball's speed at its point of maximum height is v0x = v0 * cos(θ).
Q1.1 Part a: To find the maximum height reached by the cannonball during its subsequent trajectory, follow these steps:
1. First, we need to find the vertical component of the initial velocity (v0).
To do this, use the formula: v0y = v0 * sin(θ).
2. Now, we'll use the following kinematic equation to find the maximum height (h) reached by the cannonball:
\(v^2 = u^2 + 2as,\)
where v is the final vertical velocity, u is the initial vertical velocity,
a is the acceleration,
and s is the displacement.
At maximum height, the final vertical velocity (v) will be 0.
3. Plug in the values and solve for s (displacement):\(0 = (v0 * sin(θ))^2 - 2 * g * h\),
where g is the acceleration due to gravity (approximately 9.81 m/s²).
4. Rearrange the equation to solve for h (maximum height): h = (\(v0^2\) * sin(θ\()^2\)) / (2 * g).
Q1.2 Part b:
To find the cannonball's speed at its point of maximum height, follow these steps:
1. As mentioned earlier, at maximum height, the final vertical velocity (v) will be 0.
2. Now, we need to find the horizontal component of the initial velocity (v0).
To do this, use the formula: v0x = v0 * cos(θ).
3. Since there's no air resistance, the horizontal component of the velocity remains constant throughout the trajectory.
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Which statement BEST explains why you should not walk on a pond even if the ground near the pond is frozen solid?
Describe the distinguishing features between mechanical waves.
Mechanical waves require a medium to propagate and can be transverse or longitudinal. Transverse waves move perpendicular to the wave direction, while longitudinal waves move parallel.
Mechanical waves are waves that require a medium through which to travel. There are two types of mechanical waves, and they are transverse and longitudinal waves. Transverse waves are the waves in which the motion of the medium is perpendicular to the direction of wave propagation. On the other hand, longitudinal waves are waves in which the motion of the medium is parallel to the direction of wave propagation. The distinguishing features between mechanical waves are that transverse waves are characterized by the crest and trough, whereas longitudinal waves have rarefactions and compressions. Also, in transverse waves, the particles move up and down to the motion of the wave, whereas in longitudinal waves, the particles move back and forth. Additionally, transverse waves can travel through solid and liquid media, while longitudinal waves can travel through gases and solids.In conclusion, mechanical waves require a medium to travel, and the two types of mechanical waves are transverse and longitudinal. The distinguishing features between the two waves are the direction of wave propagation, the motion of the medium, and the type of medium through which the waves can travel.For more questions on Mechanical waves
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Which type.of diversity is being lost as the population of rhinoceros become very small
I think all Rhino species are being lost plz let me know if I am wrong thank u bro I am glad to help any time.
What is the wavelength in nanometers of light when the energy is 3. 29 × 10-19 j for a single photon?.
The wavelength is 6.04 nm.
since
λ=hc/E
λ=6.626×10^ −34×3×10 ^8/(3.29×10−19)
λ=6.04nm
The distance between identical points (adjacent crests) in adjacent cycles of a waveform signal carried in space or down a wire is defined as the wavelength. This length is often defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm) (mm).
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Find the magnitude of the sum
of these two vectors:
B
3.14 m
2.71 m
30.0°
-60.0°
The magnitude of the sum of two vectors A and B is 4.13 m and the angle of the resultant vector is 10.86°.
From the given,
A = 3.14 m
B = 2.71 m
The resultant vector C= A + B
Vector A is resolved into its vertical and horizontal components,
Aₓ = 3.14 cos(30) = 2.71 m
Ay = 3.14 sin (30) = 1.57 m
Vector B is resolved into its vertical and horizontal components,
Bx = 2.71 cos(60) = 1.355 m
By = ₋2.71 sin (60) = -2.35 m
C = A + B
= (2.71+1.355) x + (1.57 -2.35) y
= 4.064 i - 0.78 j
the magnitude of C = √(4.06)² + ( 0.78)² = 4.13 m
The angle, tan α = 0.78 / 4.06
α = 10.8°
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A wheel of mass 50 kg has a radius of 0.4 m. It is making 480 rpm. What is the
torque necessary to bring it to rest in 40 seconds?
Solution:
Answer:
The torque necessary to bring the wheel to rest in 40 seconds is 10.4 N·m
Explanation:
The question is with regards to rotational motion
The rotary motion parameters are;
The mass of the wheel = 50 kg
The radius of the wheel = 0.4 m
The rate of rotation of the wheel = 480 rpm
The time in which the wheel is to be brought to rest = 40 s
The rotational rate of the wheel in rotation per second is given as follows;
480 r.p.m = 480 r.p.m × 1 minute/(60 seconds) = 8 revolution/second
1 revolution = 2·π radians
Therefore, we have the angular velocity, ω, given as follows;
ω = 2·π × 8 revolutions/second ≈ 50.3 rad/s
The angular acceleration, α, is given as follows;
\(\alpha = \dfrac{\Delta \omega}{\Delta t} = \dfrac{\omega _2 - \omega_1}{t_2 - t_1}\)
Whereby the wheel is brought to rest from its initially constant rotational motion in 40 seconds, we have;
ω₁ ≈ 50.3 rad/s, ω₂ = 0 rad/s, and t₂ - t₁ = 40 seconds
Plugging in the values for the variables of the equation for the angular acceleration, "α", we get;
\(\alpha = \dfrac{0 - 50.3 \ rad/s}{40 \ s} \approx 1.3 \ rad/s^2\)
The torque on the wheel, τ, is given as follows;
τ = m·r²·α
Where;
m = The mass of the object = 50 kg
r = The radius of the wheel = 0.4 m
α = The acceleration of the wheel ≈ 1.3 rad/s²
Therefore;
τ = 50 kg × (0.4 m)² × 1.3 rad/s² ≈ 10.4 N·m
The torque necessary to bring the wheel to rest in 40 seconds = τ ≈ 10.4 N·m.
Answer:
-10.048 N m
Explanation:
A pendulum is swinging next to a wall. The distance from the bob of the pendulum to the wall varies in a periodic way that can be modeled by a trigonometric function.
The formula of the trigonometric function that models the distance HHH from the pendulum's bob to the wall after t seconds is
H(t) = 15 -6sin(2.5π(t -0.5))
Detailed explanation:
The function can be expressed as the following for the midline M, amplitude A, period T, and time t0 at which the function deviates from the midline:
H(t) = M -Asin(2π/T(t -t0))
The equation is based on the parameters M=15, A=6, T=0.8, and t0 = 0.5.
H(t) is equal to 15 -6sin(2.5π(t -0.5))
What is function?The trigonometric functions in mathematics are real functions that connect the right-angled triangle's angle to the ratios of its two side lengths .In all areas of study that involve geometry, such as geodesy, solid mechanics, celestial mechanics, and many others, they are widely used.
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The correct question is:
A pendulum is swinging next to a wall. The distance from the bob of the swinging pendulum to the wall varies in a periodic way that can be modeled by a trigonometric function.
The function has period 0.80.80, point, 8 seconds, amplitude 6 \text{ cm}6 cm6, start text, space, c, m, end text, and midline H = 15 \text{ cm}H=15 cmH, equals, 15, start text, space, c, m, end text. At time t = 0.5t=0.5t, equals, 0, point, 5 seconds, the bob is at its midline, moving towards the wall.
Find the formula of the trigonometric function that models the distance HHH from the pendulum's bob to the wall after t seconds. Define the function using radians.
PLEASE HELP ME
A boulder is raised above the ground so that the gravitational potential energy relative to the ground is 310 J. Then it is dropped. What is its kinetic energy just before it hits the ground?
Answer:
try this
Explanation:
The energy of a falling object when it hits the ground is equaled to the energy it starts with because the potential energy is converted into kinetic energy entirely with the height at 0. This means the energy would be 200 J.
RESULT
a car is travelig at 20.0 m/s when the driver applies the brakes and comes to a stop. if the car slows down uniformly with an acceleration of -4.20 m/s, about how far does the car travel before coming to a rest
Since acceleration is constant, we can use the formula
v² - u² = 2a ∆x
where v = final velocity, u = initial velocity, a = acceleration, and ∆x = displacement. Then
0² - (20.0 m/s)² = 2 (-4.20 m/s²) ∆x
⇒ ∆x = (20.0 m/s)² / (8.40 m/s²) ≈ 47.6 m
The people who write computer programs
Answer:
Someone who writes software or programs for computers is called a programmer.
Explanation: