What are the effects of elastic limit on a structure built on a fault line?

Answer:

c = 0.4356 J/gK

Explanation:

Given the following data;

Mass = 450 grams

Initial temperature, T1 = 150°C

Final temperature, T2 = 53°C

Quantity of heat = 34500 Joules

To find the specific heat capacity of the metal;

Heat capacity is given by the formula;

\( Q = mcdt\)

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 53 - 150

dt = -97°C

Converting the temperature in Celsius to Kelvin, we have;

dt = 273 + (-97) = 176 Kelvin

Making c the subject of formula, we have;

\( c = \frac {Q}{mdt} \)

Substituting into the equation, we have;

\( c = \frac {34500}{450*176} \)

\( c = \frac {34500}{79200} \)

c = 0.4356 J/gK

When an object is thrown upward, it loses 9.8 meters per second of speed each second due to gravity.

This is known as the acceleration due to gravity and is the same for all objects regardless of their mass.
When an object is thrown upward, it loses speed each second due to the force of gravity acting upon it. The rate at which it loses speed is called acceleration due to gravity, which is approximately 9.8 meters per second squared (m/s²) on Earth. This means that the object's upward speed decreases by 9.8 meters per second (m/s) each second, ignoring air resistance.

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The parachutist was in the air for approximately 1.09 seconds.

To calculate the time the parachutist was in the air, we can use the equations of motion.

First, let's find the initial velocity (u) of the parachutist before the parachute opens. We know that the parachutist falls 50.0 m without friction.

Using the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the displacement, we can substitute the given values: 14^2 = u^2 + 2(-62)(50). Solving this equation, we find u^2 = 14^2 + 2(62)(50). Taking the square root of both sides, we find u ≈ 74.99 m/s.

Now that we have the initial velocity, we can calculate the time (t) the parachutist was in the air using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

Substituting the known values, we have 14 = 74.99 + (-62)t. Solving for t, we get t = (14 - 74.99) / -62 ≈ 1.09 seconds.

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The final answer are:-

(a) Q = 1800C

(b) n = 1.125 × 10^22 electrons

The charge in c, which flows in the strike to the ground is 1800C and the number of electrons transferred to the ground is 1.125 × 10^22 electrons.

The current in a lightning strike is 7500A and the strike lasts for 240ms. We can calculate the charge in c, which flows in the strike to the ground, and the number of electrons transferred to the ground using the following formulas:

a) Charge (Q) = Current (I) × Time (t)
Q = 7500A × 240ms
Q = 7500A × 0.240s
Q = 1800C

b) Number of electrons (n) = Charge (Q) / Charge of an electron (e)
n = 1800C / 1.6 × 10^-19C
n = 1.125 × 10^22 electrons

Therefore, the charge in c, which flows in the strike to the ground is 1800C and the number of electrons transferred to the ground is 1.125 × 10^22 electrons.

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For the designing of differential amplifier following were found out :

the small-signal gain is zero.

the transconductance (gm) and output resistance (ro) of the NMOS transistors are  -640 * (W/L) μA/V and 1 / (8 * (W/L)) kΩ respectively.

the transconductance (gm) and output resistance (ro) of the PMOS transistors are -320 * (W/L) μA/V and  respectively.

NMOS transistor: Wn = 0.03 μm, L = 0.2 μm

PMOS transistor: Wp = 0.0075 μm, L = 0.2 μm

Bias current: Itail = 1 mA

Resistance: R = 0.3 kΩ

To design the differential amplifier according to the given specifications, we will follow these steps:

Step 1: Calculate the small-signal gain (Av)

Step 2: Determine the transconductance (gm) and output resistance (ro) of the NMOS transistors

Step 3: Determine the transconductance (gm) and output resistance (ro) of the PMOS transistors

Step 4: Calculate the tail current (Itail) based on the specified Iss

Step 5: Determine the resistance (R) value

Step 6: Calculate the width (Wp) of the PMOS transistor

Step 7: Calculate the width (Wn) of the NMOS transistors

Now let's go through each step in detail.

Step 1: Calculate the small-signal gain (Av)

Given: Av = 10, VOP = VON = 3.5V

Av = (vop - von) / (vip - vin)

10 = (3.5 - 3.5) / (0.1)

10 = 0 / 0.1

Since the numerator is zero, the small-signal gain is zero.

Step 2: Determine the transconductance (gm) and output resistance (ro) of the NMOS transistors

Given: unCox = 400 μA/V², Vtn = 0.8V, n = 0.02 V^(-1), L = 0.2 μm

gm = 2 * unCox * (W/L) * (Vgs - Vtn)

ro = 1 / (lambda * unCox * (W/L))

We need to design the amplifier for DC operation (Vin = Vbias), where the differential voltage (vgs = Vin - Vbias) should be zero to operate the transistors in the saturation region.

For the NMOS transistors:

Vgs = 0 (since Vin = Vbias)

gm = 2 * unCox * (W/L) * (Vgs - Vtn)

  = 2 * 400 μA/V² * (W/L) * (0 - 0.8)

  = -640 * (W/L) μA/V

ro = 1 / (lambda * unCox * (W/L))

  = 1 / (0.02 V^(-1) * 400 μA/V² * (W/L))

  = 1 / (8 * (W/L)) kΩ

Step 3: Determine the transconductance (gm) and output resistance (ro) of the PMOS transistors

Given: upCox = 200 μA/V², Vtp = -0.8V, p = 0.04 V^(-1), L = 0.2 μm

Similarly, for the PMOS transistors, we need to design the amplifier for DC operation (Vin = Vbias), where the differential voltage (vsg = Vbias - Vin) should be zero to operate the transistors in the saturation region.

For the PMOS transistors:

Vsg = 0 (since Vin = Vbias)

gm = 2 * upCox * (W/L) * (Vtp - Vsg)

  = 2 * 200 μA/V² * (W/L) * (-0.8 - 0)

  = -320 * (W/L) μA/V

ro = 1 / (lambda * upCox * (W/L))

  = 1 / (0.04 V^(-1) * 200 μA/V² *

  = 1 / (5 * (W/L)) kΩ

Step 4: Calculate the tail current (Itail) based on the specified Iss

Given: Iss = 2 mA

Itail = Iss / 2

= 2 mA / 2

= 1 mA

Step 5: Determine the resistance (R) value

Given: Vs = 0.3 V, VDD = 5 V

We can calculate the resistance (R) value using Ohm's Law:

Vs = Itail * R

0.3 V = 1 mA * R

R = 0.3 kΩ

Step 6: Calculate the width (Wp) of the PMOS transistor

To calculate Wp, we'll use the equation for the tail current:

Itail = 2 * upCox * (Wp/L) * (VDD - Vtp)^2

1 mA = 2 * 200 μA/V² * (Wp/0.2 μm) * (5 V + 0.8 V)^2

1 mA = 2 * 200 μA/V² * (Wp/0.2 μm) * (5.8 V)^2

Solving for Wp:

Wp = (1 mA * 0.2 μm) / (2 * 200 μA/V² * (5.8 V)^2)

Wp = 0.01 μm / (2 * 200 μA/V² * 33.64 V^2)

Wp ≈ 0.0075 μm

Step 7: Calculate the width (Wn) of the NMOS transistors

Given: Wn = 4 * Wp

Wn = 4 * 0.0075 μm

Wn = 0.03 μm

So, the design parameters for the differential amplifier are as follows:

the small-signal gain is zero.

the transconductance (gm) and output resistance (ro) of the NMOS transistors are  -640 * (W/L) μA/V and 1 / (8 * (W/L)) kΩ respectively.

the transconductance (gm) and output resistance (ro) of the PMOS transistors are -320 * (W/L) μA/V and  respectively.

NMOS transistor: Wn = 0.03 μm, L = 0.2 μm

PMOS transistor: Wp = 0.0075 μm, L = 0.2 μm

Bias current: Itail = 1 mA

Resistance: R = 0.3 kΩ

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The correct statement is D. The magnitude of the electric force exerted on B is doubled because the electric field at the position of A is doubled.

When two charged particles, such as A and B, are held some distance apart, they exert an electric force on each other due to their charges. The strength of this force is determined by the amount of charge on each particle and the distance between them. This force is called Coulomb force and it follows the Coulomb's law. The Coulomb's law states that the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

When the charge on A is doubled, the electric field at the position of A increases, and as a result, the force exerted on B also increases. This is because the electric field at the position of A is what causes the force on B. The magnitude of the electric force on B is proportional to the product of the charges of A and B, and inversely proportional to the square of the distance between them. So as the charge on A doubles, the force on B also doubles.

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Answer:B. Mountain Pose

Explanation:

Explanation:

a) Power = work / time = force × distance / time

P = Fd/t

P = (85 kg × 9.8 m/s²) (4.6 m) / (12 s)

P ≈ 319 W

b) P = Fd/t

0.70 (319 W) = (m × 9.8 m/s²) (4.6 m) / (9.6 s)

m = 47.6 kg

The man's power rating while doing the work will be 319 W and the mass of the girl will be 47.6 kg.

Power can be defined as the amount of work completed in a given amount of time. Watt (W), which is derived from joules per second (J/s), is the SI unit of power. Horsepower (hp), which is roughly equivalent to 745.7 watts, is a unit of measurement sometimes used to describe the power of motor vehicles and other devices.

Average power is calculated by dividing the total energy used by the total time required. The average quantity of work completed or energy converted per unit of time is known as average power.

According to the question,

a) Power = work / time

P = (force × distance) / time

P = Fd/t

P = (85 kg × 9.8 m/s²) × 4.6 m / 12 s

P = 319 W

Hence, the power rating while doing the work is 319 W.

b) P = Fd/t

0.70 × 319 W = (m × 9.8 m/s²) × 4.6 m / 9.6 s

m = 47.6 kg

Hence, the mass of the girl is 47.6 kg.

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Answer:

1. The distance of image from the plane mirror is same as the distance of object (person) from the plane mirror but the image is formed behind the mirror.

v=u=3 m

Thus distance between image and the person d=u+v=3+3=6 m

2.A concave mirror has a radius of curvature of 1.0 m. An object is placed 2.0 m in front of the mirror. Can you determine the location of the image (in cm)

1/v = 1/f - 1/u = 1/50 - 1/200 = 4/200 - 1/200 = 3/200

v = 200/3 c

NUMBER 3 Ans: 18.75 cm.

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Answer:

Not not all of the elements have been discovered.

The force acting on a moving charge is known as the magnetic force. The force acting on the charge will be 3.75 N.

Magnetic fields only exert a force on a moving electric charge. A moving charge generates a magnetic field. With an increase in charge and magnetic field strength, this force rises.

when charges have higher velocities, the force is stronger. However, the magnetic force is always perpendicular to the velocity.

Mathematically the force exerted on the charge will be

F=qvBsinα

F= force acting on the charge

v = velocity of charge

q = charge

F=qvBsinα

F=2.5×10⁻⁶×5.0×10³×3.0×10²

F=37.5 N

Hence The force acting on the charge will be 3.75 N.

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F = q V B sinα

Where F is the force applied to a moving charge.

V = charge velocity

q stands for charge.

α = angle between V and B directions

As a result, the moving charge is subjected to a force of 3.75 Newton.

Answer:

792J

Explanation:

Use the formula Force × Distance

With 110 newtons being the force and 7.2 meters being the distance

Which gives 792 and work us measured in joules therefore its joules

Work done is the dot product of force and displacement. The work done on the box to push across the surface for 7.2 m by applying a force of 110 N is 792 J.

Force is an external agent acting on a body tp change it from the state of motion or rest.  Force is a vector quantity thus, it is characterized by a magnitude and direction.

When force acting on a body results in displacement of the body, it is said to be work done on the body. The work done on the body is the product of force and displacement.

W = F d.

Given the force acting on the box = 110 N

 displacement d = 7.2 m

Work done w = 110 N × 7.2 m

                       = 792 J.

Therefore, the work done on the box is 792 J.

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Answer:

Explanation:

the fist one

believe in fairy stories. At first there were only a few, but in a week or two the country was simply running alive with dragons of all sizes, and in the air you could sometimes see them as thick as a swarm of bees. They all looked alike except as to size. They were green with scales, and they had four legs and a long tail.

Explanation:

YOUR WELCOME :)

Answer:

its "calm and curious"

Explanation:

hope tis helps!!!

We will have the following:

So, the nergy is 2.3 J.

The maximum allowable percentage change is 3.8% in the string tension

Length of the string lg as given in the question = 0.350m

frequency of concert G f_g as given in the question= 392 Hz

The maximum allowable percentage change in string tension for this frequency remains constant and the given allowed interval of the change of the length

Formulating the equation and solving:

Let f be the frequency, T be the tension and U be the length of the wave

f = 1/2L*\(\sqrt{} T/U\)

df = 1/2\(\sqrt{} U\)*\((1/2\sqrt{}T- Ldt - dL\sqrt{}T)/L^{2}\)

df = 0

dT/T = 2*(dL/L)

= 2*0.6/31.2

dT/T = 0.038

Percentage change in string tension 3.8%

The maximum percentage change in string tension is 3.8%

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The vertical height between the two climbers is approximately 5.15 meters.

To find the vertical height between the two climbers, we can analyze the vertical motion of the first aid kit.

Given:

Initial velocity of the kit (v₀) = 9.35 m/s

Launch angle (θ) = 56.4°

Vertical speed at the catching instant (vᵥ) = 0 m/s

We can break down the initial velocity into its vertical and horizontal components:

Vertical component: v₀ₓ = v₀ * sin(θ)

Horizontal component: v₀ᵧ = v₀ * cos(θ)

Since the vertical speed at the catching instant is zero, we can use the vertical component of the initial velocity and the acceleration due to gravity to calculate the vertical height.

The equation for vertical motion without considering air resistance is:

Δy = v₀ₓ * t + (1/2) * (-g) * t²

Where Δy is the vertical displacement, t is the time, and g is the acceleration due to gravity (approximately 9.8 m/s²).

At the instant of catching, the vertical displacement is equal to the vertical height between the climbers. Since the vertical speed is zero, the time taken for the kit to reach that point can be determined by dividing the vertical component of the initial velocity by the acceleration due to gravity:

t = v₀ₓ / g

Substituting the known values into the equation:

t = (v₀ * sin(θ)) / g

Now we can substitute the calculated time into the equation for vertical displacement to find the vertical height:

Δy = v₀ₓ * t + (1/2) * (-g) * t²

Substituting the known values into the equation:

Δy = (v₀ * sin(θ)) * [(v₀ * sin(θ)) / g] + (1/2) * (-g) * [(v₀ * sin(θ)) / g]²

Simplifying the expression:

Δy = [(v₀² * sin²(θ)) / g] - [(v₀² * sin²(θ)) / (2g)]

Calculating the numerical value using the given values:

Δy = [(9.35 m/s)² * sin²(56.4°)] / (2 * 9.8 m/s²)

Simplifying the expression and calculating the value:

Δy ≈ 5.15 m

Therefore, the vertical height between the two climbers is approximately 5.15 meters.

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Answer:

Eight planets.

1. Mercury

2. Venus

3. Earth

4. Mars

5. Jupiter

6. Saturn

7. Uranus

8. Neptune

The speed of light inside the plastic is approximately 2.00 x \(10^8\)  m/s.

To find the speed of light inside the plastic, we can use Snell's Law, which relates the angle of incidence and angle of refraction of a light ray to the indices of refraction of the two media through which the light is passing:

\(n_1\) × sin(θ1) = \(n_2\) × sin(θ2)

where n1 and \(n_2\) are the indices of refraction of the two media, and θ1 and θ2 are the angles of incidence and refraction, respectively.

In this case, the light is passing from air (with an index of refraction of approximately 1.00) into a block of plastic. We are given that the angle of incidence is 36.8 degrees and the angle of refraction is 22.9 degrees. We can therefore use Snell's Law to solve for the index of refraction of the plastic:

1.00 ×sin(36.8) = \(n_2\) × sin(22.9)

\(n_2\) = 1.50

This tells us that the index of refraction of the plastic is 1.50. We can then use the relationship between the speed of light and the index of refraction:

v = c/n

where v is the speed of light in the plastic, c is the speed of light in a vacuum (approximately 3.00 x \(10^8\) m/s), and n is the index of refraction of the plastic. Plugging in the values we have:

v = (3.00 x \(10^8\)m/s) / 1.50

v = 2.00 x \(10^8\) m/s

Therefore, the speed of light inside the plastic is approximately 2.00 x \(10^8\)  m/s.

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Answer:

E≅1.2×10^7 N/C

Explanation:

First off I'd like to say that I'm taking "net electric field" to mean that they don't want this answer to be put into vector component form and instead want magnitudes. Sometimes the wording of these questions throws me off, so sorry ahead of time if that's what they want from you!

Edit: I ended up adding it anyways ;P

Since we are observing the net electric field acting at q1, we need to use the formula:  \(E=k\frac{q}{r^{2} }\)

And since we are observing the effects of multiple charges at once...

E=ΣE, which just means wee need to add all the observed electric fields together:

ΣE= \(k\frac{q2}{r^{2} } +k\frac{q3}{r^{2} }\)

Since we are observing [static] electric fields here, we don't actually need q1's charge. (Though if you wanted to find the net force you would.) Now, before we start plugging values in, let's acknowledge what we know. We know that:

These are actually really nice to have, because now we can simplify our expression to:

\(E=k\frac{2q}{r^{2} }\)

Now let's plug in our values and get an answer out.

E= 2(8.99×10^9)(4×10^-5)/(0.24)

Plugging all that in, I get:

E≅1.2×10^7 N/C

If you end up needing the net force, F=(q1)(E). That is, you just multiply the electric field by the value of q1. And again, if your teacher wants the answer in vector component form, then the answer will look different.

Let me know what doesn't make sense, or if I got something wrong. Good luck with AP Phy.!

Edit: I put the component form for my answer in the attachment. I also noticed a small calculator related error in my original answer. I updated that to match the new one.

what a driver should do when they get to a speed bump is reduce to the speed that is suggested or go slower than the speed, so i would say d.

When a driver encounters a speed bump, the recommended action is to reduce speed to the suggested limit. Therefore, the correct option is (d). reduce speed to the suggested limit.

Speed bumps are designed to slow down traffic and improve safety in certain areas, such as residential neighborhoods, school zones, or parking lots. Approaching a speed bump at a reduced speed allows for better control of the vehicle and minimizes the impact on the suspension and passengers inside the vehicle.

It is important to adhere to any posted speed limit signs or recommendations in the area and adjust the speed accordingly to safely navigate the speed bump without causing damage to the vehicle or compromising safety.

Therefore, When a driver encounters a speed bump, the recommended action is to reduce speed to the suggested limit. the correct option is (d).

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Answer:

C. There is a difference in air pressure.

Explanation:

Well spring magma and  groundwater must be interacting beneath the surface which is why they geyser is erupting.

A scientist observes a geyser erupting. The two objects that must be interacting beneath the surface are well spring magma and groundwater.

When a geyser is erupting, it involves the interaction of groundwater and well spring magma. The groundwater seeps into the earth's crust, where it gets heated by the well spring magma. Once the water reaches a certain temperature, it turns into steam and expands, causing pressure to build up. Eventually, this pressure forces the heated water and steam to the surface, resulting in the eruption of the geyser.

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Answer:

21: Mass

22: Unbalanced Force

23: Friction

24: Balanced

Explanation:

Answer:inertia

Explanation:

A car hits a tree and doesn’t stop, but keeps going until severely damaged. This is because of the principle of Inertia.

It states that" When a body s at rest it remains at rest, and IF the body is in motion It remains in motion until an external force is applied to that object."

i.e

If F=0, Then v= constant

and when that constant =0 then the body is at rest.

Where F= force

v = velocity.

Inertia is the tendency of an object to resist changes in its state of motion. In this case, the car was moving at a certain speed before it hit the tree, and because of its inertia, it continued to move forward even after the collision with the tree.

The car only stopped when another force acted on it, such as the force of the tree, or the force of friction with the ground, which slowed it down and eventually brought it to a stop. The severe damage to the car was a result of the force of the impact, which was a combination of the car's speed and its mass.

Hence the car does not stop because of the principle of inertia.

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Most of the stars in the Sun's cosmic neighborhood would lie on the Main Sequence portion of the Hertzsprung-Russell (HR) diagram. This is because the majority of stars in the universe are made of hydrogen and helium, and have low mass and luminosity.

The Hertzsprung-Russell diagram (H-R diagram) is a graphical representation of stars that plots luminosity against surface temperature. In astronomy, the Hertzsprung-Russell diagram is widely utilized to classify stars according to their physical properties, such as mass, temperature, and luminosity. The majority of stars are located on the main sequence. The primary sequence refers to the region where stars burn hydrogen in their cores to produce energy. Main-sequence stars are characterized by their luminosity, mass, and surface temperature. When the mass of the star is known, its age and stage of life can be estimated based on its position on the main sequence. The Main Sequence refers to the swath of stars that spans from upper left to lower right on the HR diagram. These stars have a range of surface temperatures and masses, with their positions on the diagram determined by their luminosities and the temperature of their surfaces. The further a star lies to the upper left, the higher the temperature and the more massive the star. The further to the lower right, the cooler the temperature and the less massive the star.

Therefore, most stars in the Sun's cosmic neighborhood would be found on the Main Sequence.

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Answer:

definition of matter is that matter takes up space and has mass