Answer:
1: Killing a specific gene.
2: augmentation of a gene.
3: Inserting a new dominant gene.
Explanation:
Identify what the conjugate acid/base would be. FOR H3PO4?
Suppose you need to prepare 128.2 ml of a 0.364 m aqueous solution of nacl. what mass, in grams, of nacl do you need to use to make the solution?
To prepare 128.2ml of a 0.364 M aqueous solution of NaCl.the mass in grams, of NaCl need to use to make the solution is 2.723 gm.
Molarity is defined as the no. of moles of solute per liter of solution.
Here,
Molarity = moles of solute / Liter of solution
0.36 M solution will contains 0.364 moles of NaCl.
therefore, volume of solution in L = ( 128.2 / 1000 ) L × 1 L
= 0.1282 L
that means, it will contain, no. of moles of NaCl
= (0.1282 L of solution × 0.364 ) / 1 L of solution
= 0.0466 moles of NaCl
now, molar mass of NaCl = 58.44 g/mol
so, 1 mol of NaCl has a mass of 58.44 g/mol
therefore, 0.0466 moles of NaCl will have mass of
= ( 0.0466 moles of NaCl × 58.44 g ) / 1 mole of NaCl
= 2.723 g
Thus,To prepare 128.2ml of a 0.364 M aqueous solution of NaCl .the mass in grams, of NaCl need to use to make the solution is 2.723 gm.
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how many grams of nickel(ii) nitrate, ni(no3)2 , must be dissolved to prepare 200. ml of a 0.233 m aqueous solution of the salt? g
Mass of nickel(ii) nitrate ni(no3)2 must be dissolved is 8.48 gram
It is given that
Volume of solution = 200 ml
Molarity of solution = 0.233 m
We have to find mass of nickel(ii) nitrate ni(no3)2
The concentration of a solute in a solvent (at a definite temperature and pressure condition) may be expressed using the unit molality (m) as per the type of the solution need to be produced. It is defined as the number of moles of the solute present in 1 kg of the solution.
Molarity = moles of solute/volume of solution
0.233 = Given mass/182 x 1000/200
0.233 = Given mass/182 x 5
Given mass = 0.233 x 182/5 = 8.48 gram
Hence, Mass of nickel(ii) nitrate ni(no3)2 must be dissolved is 8.48 gram
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How many moles are in 55g of NH3(g)?
Answer:
1 grams NH3 is equal to 0.058718113128665 mole. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between grams NH3 and mole.
Explanation:
Use the balanced equation to solve the problem.C3H8 +502 3CO2 + 4H₂O-4.16L O₂ gas react with C3H8 at STP.How many grams of H₂O are made?g
Step 1
It is known that at STP:
1 mole of any gas = 22.4 L
--------------------
Step 2
Information provided:
4.16 L of O2
------
Information needed:
The molar mass of H2O = 18.0 g (please, the periodic table is useful here)
-------------------
Step 3
By stoichiometry,
C3H8 + 5 O2 => 3 CO2 + 4 H2O (the reaction is completed and balanced)
5 x 22.4 L O2 ------------ 4 x 18.0 g H2O
4.16 L O2 ------------ X
X = 4.16 L O2 x 4 x 18.0 g H2O/5 x 22.4 L O2
X = 2.67 g H2O
Answer: 2.67 g H2O
Choose the answer that is not correct: RER is: Group of answer choices The ratio of carbon dioxide produced to oxygen consumed An indication of the percentage of carbohydrate metabolized An indication of the percentage of lipid metabolized An approximation of kilocalories obtained per liter of oxygen consumed An indication of calories consumed during anaerobic energy production
Answer:
An indication of calories consumed during anaerobic energy production
Explanation:
RER stands for respiratory exchange ratio, which is the ratio of the volume of carbon dioxide, CO₂, produced to the volume of oxygen, O₂ used in metabolism. RER is used in determining the respiratory quotient during aerobic exercise and rest, from which it can be determined if carbohydrate or fat is the source of fuel consumed in the production of energy for the body through metabolism
Therefore, the answer that is not correct is an indication of calories consumed during anaerobic energy production
6. A diamond contains 5.0 ×10^21 atoms of carbon. What amount(moles) of carbon and what mass (grams) of carbon are in this diamond? *
a. 0.008303 and 0.0997
b. 0.008303g and 0.0997mol
c. 0.008303amu and 0.0997
d. 0.008303 and 0.0997amu
Answer:
0.008303 mol and 0.0997 g
Explanation:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.022×10²³ atoms.
This implies that 1 mole of carbon also contains 6.022×10²³ atoms.
Next, we shall determine the mole of carbon that contains 5.0×10²¹ atoms. This can be obtained as follow:
1 mole of carbon contains 6.022×10²³ atoms.
Therefore, Xmol of carbon will contain 5.0×10²¹ atoms i.e
Xmol of carbon = 5.0×10²¹ / 6.022×10²³
Xmol of carbon = 0.008303 mole
Therefore, 0.008303 mole of carbon contains 5.0×10²¹ atoms.
Finally, we shall determine the mass of carbon. This can be obtained as follow:
Mole of carbon = 0.008303 mole
Molar mass of carbon = 12.01 g/mol
Mass of Carbon =.?
Mole = mass /Molar mass
0.008303 = mass of carbon/12.01
Cross multiply
Mass of Carbon = 0.008303 x 12.01
Mass of Carbon = 0.0997 g.
5.25 calories are absorbed by an iron nail. How many joules is this?
a) 1.07
b) 9.43
c) 12.6
d) 21.9
* I NEED EXPLANATION!!! *
Answer:
D) 21.9
Explanation:
1 kilocalorie is equal to 4184 joules
0.001 kilocalorie is equal to 1 calorie
so 5.25 calorie=21.966 joules
A mixture of gases contains 0.320 mol CH4, 0.240 mol C2H6, and 0.300 mol C3H8. The total pressure is 1.45 atm. Calculate the partial pressures of the gases.
Answer:
pCH₄ = 0.540 atm
pC₂H₆ = 0.405 atm
pC₃H₈ = 0.505 atm
Explanation:
Step 1: Calculate the total number of gaseous moles
n = n(CH₄) + n(C₂H₆) + n(C₃H₈)
n = 0.320 mol + 0.240 mol + 0.300 mol = 0.860 mol
Step 2: Calculate the partial pressure of each gas
We will use the following expression.
pi = P × Χi
where,
pi: partial pressure of the gas "i"P: total pressureΧi: mole fraction of the gas "i"pCH₄ = 1.45 atm × 0.320 mol/0.860 mol = 0.540 atm
pC₂H₆ = 1.45 atm × 0.240 mol/0.860 mol = 0.405 atm
pC₃H₈ = 1.45 atm × 0.300 mol/0.860 mol = 0.505 atm
Please help with this question
Choose the common intermolecular forces involved between dye molecules and fabric fibers. Dipole-dipole interactions London forces Hydrogen bonding Olonic interactions Question 3 6 pts Identify the fibers you are analyzing in your test fabric Bamboo Wool Linen O Cotton 0 Nitrile Silk Polyester 0 Tencel O etate Nylon Rayon 그 Acrylic
The common intermolecular forces involved between dye molecules and fabric fibers include dipole-dipole interactions, London forces, and hydrogen bonding.
The fibers that are mentioned in the test fabric are bamboo, wool, linen, cotton, nitrile, silk, polyester, Tencel, acetate, nylon, rayon, and acrylic. However, it is not specified which fibers are being analyzed for the intermolecular forces.
Intermolecular forces are the forces of attraction or repulsion that occur between molecules. These forces determine many of the physical properties of materials, including their melting and boiling points, viscosity, and solubility. When dyes are applied to fabric, the intermolecular forces between the dye molecules and the fabric fibers play a critical role in determining how well the dye adheres to the fibers and how well it resists fading.
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which of these pieces of equipment would be the most appropriate for precisely measuring 29 mL of liquid? Explain your reasoning, citing evidence related to the divisions on each tool and the concept of an estimated digit.
Answer:
The best equipment would be the graduated cylinder. Why?
Firstly, the smallest marking on the graduated cylinder is 2 mL, while on all the others the smallest marking is way above that, like 25 mL and 100 mL.
Without even going into the details, we can first rule out the volumetric flask, since its smallest marking is 100 mL and even that is already bigger than our sample size, hence we would have no markings to accurately measure out 29 mL of our sample had we used the volumetric flask.
Next to be ruled out would be the Erlenmeyer flask, as you can see in the image, it only has three marking, and as the smallest marking is 25 mL, each marking is at least 25 mL, and even so far as going up to 50 mL. This cannot let us accurately measure 29 mL out at all, due to the markings being way too big to do that. Hence, the Erlenmeyer flask is ruled out.
Finally, the beaker seems to be a worthy candidate! Unfortunately, for the same reason as the Erlenmeyer flask, as you can see in the image each marking represents 10 mL. We cannot measure 9 mL in the beaker accurately, and hence the beaker is ruled too.
We are left with the graduated cylinder, and that is our answer.
Explanation:
Hope this helped!
Answer:
This is the sample answer (assignment's correct answer):
The graduated cylinder is most appropriate. Because its smallest divisions are 2 mL, increments between each 2-mL division are estimated. Measurements can therefore be stated to a single milliliter.
Just make some changes to the writing and youre good to go.
Which of the following compounds is considered to be "free" chlorine in its present state?
A) Chlorine gas (Cl2)
B) Sodium hypochlorite (NaOCl)
C) Calcium hypochlorite (Ca(ClO)2)
D) Potassium hypochlorite (KClO)
E) HOCL
The compound considered to be "free" chlorine in its present state is chlorine gas (Cl2).
Chlorine gas (Cl2) is the only compound listed that consists solely of chlorine atoms. It exists as a diatomic molecule, with two chlorine atoms bonded together through a covalent bond. In this form, chlorine is in its elemental state and is commonly referred to as "free" chlorine.
On the other hand, sodium hypochlorite (NaOCl), calcium hypochlorite (Ca(ClO)2), potassium hypochlorite (KClO), and HOCl (hypochlorous acid) are all compounds that contain chlorine but are chemically bonded with other elements.
Sodium hypochlorite, calcium hypochlorite, and potassium hypochlorite are examples of hypochlorites, which are chlorine compounds commonly used as disinfectants or bleaching agents. These compounds release hypochlorous acid (HOCl) when dissolved in water, which is an effective oxidizing agent with antimicrobial properties.
HOCl, also known as hypochlorous acid, is a weak acid that is formed when chlorine gas dissolves in water. It is the active form of chlorine in many disinfectants and sanitizers, including bleach. While HOCl contains chlorine, it is not considered "free" chlorine in the same sense as chlorine gas (Cl2).
In summary, among the listed compounds, only chlorine gas (Cl2) is considered to be "free" chlorine in its present state.
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Question 13
5 pts
For questions 10-13 refer to the following reaction:
2H₂ + O2-----> 2H₂O
If 10.0 g of H₂ reacts with 10.0 g of O2,
how many grams of excess reactant are remaining after the reaction goes
to completion?
When 10.0 g of H₂ reacts with 10.0 g of O₂, the limiting reactant is O₂, and 8.75 grams of excess H₂ are remaining after the reaction is complete.
In chemical reactions, reactants combine to form products. However, sometimes there may be an excess of one reactant, which means that it is present in greater quantity than required for a complete reaction with the other reactant.
In such cases, the excess reactant is not completely consumed and remains unused after the reaction reaches completion.
The balanced chemical equation given for the reaction is:
2H₂ + O₂ → 2H₂O
From the equation, we can see that 2 moles of hydrogen gas react with 1 mole of oxygen gas to produce 2 moles of water.
To find the number of moles of each reactant, we need to convert the given masses to moles using the molar mass of each substance. The molar mass of hydrogen gas (H₂) is 2 g/mol, and the molar mass of oxygen gas (O₂) is 32 g/mol.
For hydrogen gas (H₂):
Number of moles = Mass / Molar mass
Number of moles = 10.0 g / 2 g/mol
Number of moles = 5.0 mol
For oxygen gas (O₂):
Number of moles = Mass / Molar mass
Number of moles = 10.0 g / 32 g/mol
Number of moles = 0.3125 mol
From the balanced chemical equation, we can see that the ratio of hydrogen gas to oxygen gas is 2:1. Therefore, for a complete reaction, 2 moles of hydrogen gas react with 1 mole of oxygen gas.
Since the mole ratio is 2:1, we can conclude that oxygen gas is the limiting reactant because we have 0.3125 mol of oxygen gas, which is less than 5.0 mol of hydrogen gas.
Since 1 mole of oxygen reacts with 2 moles of hydrogen, we can determine the amount of hydrogen gas required by multiplying the number of moles of oxygen gas by 2:
Amount of hydrogen gas required = 2 * 0.3125 mol
Amount of hydrogen gas required = 0.625 mol
Since we have an excess of hydrogen gas (5.0 mol), we can subtract the amount of hydrogen gas required (0.625 mol) from the total amount of hydrogen gas (5.0 mol) to find the remaining excess:
Excess reactant remaining = Total amount of reactant - Amount of reactant required
Excess reactant remaining = 5.0 mol - 0.625 mol
Excess reactant remaining = 4.375 mol
To convert the remaining moles of hydrogen gas to grams, we can use the molar mass of hydrogen gas:
Mass of excess reactant remaining = Moles * Molar mass
Mass of excess reactant remaining = 4.375 mol * 2 g/mol
Mass of excess reactant remaining = 8.75 g
Therefore, after the reaction goes to completion, there will be approximately 8.75 grams of excess hydrogen gas remaining.
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ANSWER AS SOON AS POSSIBLE PLEASE!!!! Which type of water represents the largest percentage of earths water?
Answer:
im pretty sure its groundwater just read this and see the answer
Explanation:
The ocean holds about 97 percent of the Earth's water; the remaining three percent is found in glaciers and ice, below the ground, in rivers and lakes. Of the world's total water supply of about 332 million cubic miles of water, about 97 percent is found in the ocean.
why was heat important when performing the modified schaeffer-fulton method?
The modified Schaeffer-Fulton method is a staining technique used to visualize bacterial endospores. Heat is an essential component of this method because it helps to drive the malachite green stain into the endospores, making them visible under a microscope.
The modified Schaeffer-Fulton method involves several steps. First, a heat-fixed bacterial smear is flooded with malachite green stain and heated for several minutes over a Bunsen burner or in a water bath. The heat helps to soften the endospore wall and allows the stain to penetrate the tough, resistant endospore coat. The spores are then cooled and washed with water to remove any excess stain.
Next, the smear is counterstained with safranin, which stains any vegetative cells that are present. The safranin does not stain the endospores because they have already been stained with malachite green.
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Calculate the surface area of one molecue if we assume the molecule is shaped like a cylinder that the hight is 10x larger than the radius.
The surface area of one molecule shaped like a cylinder whose height is 10 times larger than its radius is 69.08r².
The molecule is shaped like a cylinder and its height is 10 times larger than its radius.
Let's assume that the radius of the cylinder be r. Hence, the height of the cylinder will be 10r.
Therefore, the surface area of the cylinder can be determined using the formula `
Surface area = 2πrh + 2πr²`.Where r = radiush = heightπ = 3.14
∴ Surface area = 2πrh + 2πr²= 2 × 3.14 × r × 10r + 2 × 3.14 × r²= 62.8r² + 6.28r²= 69.08r²
Therefore, the surface area of one molecule shaped like a cylinder whose height is 10 times larger than its radius is 69.08r².
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who was the person to receive corona
Answer:
uh a Chinese person.....srry for da blonde answer...
Explanation:
Answer:
A 55-year-old individual from Hubei
Explanation:
Which of the following statements are true of the maintenance of blood pressure (BP)?
C. If blood pressure decreases, filtration in the kidneys decreases.
D. If more blood returns to the heart, the ventricles contract more forcefully to pump it out, and this raises blood pressure.
What is the maintenance of blood pressure?The maintenance of blood pressure is defined as the high use of sodium in your diet and the low use of potassium in your diet can cause hypertension. It is also important to use those foods which are free from fats. It is also important that we should use fruits, vegetables, and grains in excessive amounts for the maintenance of blood pressure and for a healthy diet.
High blood pressure 190/110 mm Hg can cause the main vital organs of the body like the brain, heart, and kidney too. There are three factors that contribute to blood pressure which are resistance, blood viscosity, and blood vessel diameter.
So we can conclude that blood pressure is the pressure of circulating blood against the walls of the blood vessels.
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Which of the following statements are true of the maintenance
of blood pressure (BP)? (Read carefully and select all of the correct statements.)
A. Norepinephrine stimulates vasoconstriction in skin, viscera, and skeletal muscles, all of which lower BP.
B. Aldosterone stimulates the reabsorption of Na+ ions by the kidneys, which lowers BP.
C. If BP decreases, filtration in the kidneys decreases.
D. If more blood returns to the heart, the ventricles contract more forcefully to pump it out, and this raises BP.
E. If BP decreases, the kidneys secrete the enzyme renin, which stimulates the secretion of epinephrine to prevent a further decrease.
F. The hormone ANP increases the excretion of K+ ions by the kidneys, which helps conserve water and raise BP.
G. The hormone ADH helps the kidneys conserve water and helps prevent a decrease in BP.
H. The elasticity of the large arteries helps decrease diastolic BP.
write the chemical formula for the ligand in the coordination compound tetracarbonylplatinum(iv) chloride.
The ligand in the coordination compound tetracarbonylplatinum(IV) chloride is carbonyl. A ligand is a molecule or ion that binds to a central metal atom or ion to form a coordination complex.
Tetracarbonylplatinum(IV) chloride is a coordination compound that consists of a platinum(IV) ion coordinated with four carbonyl ligands and one chloride ion. The chemical formula of the carbonyl ligand is CO, which represents a carbon atom bonded to an oxygen atom through a double bond.
In this compound, each platinum atom is surrounded by four carbonyl ligands, which means there are four CO ligands attached to the central platinum(IV) ion. The coordination number of the platinum(IV) ion is four, indicating that it forms four bonds with the carbonyl ligands.
Additionally, there is one chloride ion present as a counterion to balance the charge of the complex. Therefore, the chemical formula for the ligand in tetracarbonylplatinum(IV) chloride is CO.
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what is the ph at the equivalence point in the titration of a 26.1 ml sample of a 0.496 m aqueous hydrocyanic acid solution with a 0.331 m aqueous potassium hydroxide solution?
The pH at the equivalence point of titration of the 26.1 mL sample of the 0.496 M of the aqueous hydrocyanic acid solution is 0.70.
The chemical equation for the titration is :
HCN + KOH --> H₂O + KCN
The moles of the HCN = 0.496 x 0.0261
The moles of the HCN = 0.010 moles of HCN = moles of the KOH at the equivalence point = 0.010/ 0.331
= 0.0246 L of KOH
At the equivalence point,
The molarity of the solution = 0.010/(0.0261 + 0.0246)
The molarity of the solution = 0.199 M
pH = - log(0.199)
pH = 0.70
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The haber process can be used to produce ammonia (nh3) from hydrogen gas (h2) and nitrogen gas (n2). the balanced equation for this process is shown below. 3h2 n2 right arrow. 2nh3 the molar mass of nh3 is 17.03 g/mol. the molar mass of h2 is 2.0158 g/mol. in a particular reaction, 0.575 g of nh3 forms. what is the mass, in grams, of h2 that must have reacted, to the correct number of significant figures? 0.1 grams 0.102 grams 0.10209 grams 0.1021 grams
The mass of hydrogen reacted with nitrogen to give ammonia is 0.1 grams.
How we calculate the mass from moles?
Mass of any substance will be calculated by using the moles as:
n = W/M, where
W = required mass
M = molar mass
Given chemical reaction is:
3H₂ + N₂ → 2NH₃
Moles of 0.575 g of NH₃ will be calculated as:
n = 0.575g / 17.03g/mol = 0.033 moles
From the stoichiometry of the reaction, it is clear that:
2 moles of NH₃ = produced by 3 moles of H₂
0.033 moles of NH₃ = produced by 3/2×0.033=0.0495 moles of H₂
Now we calculate the mass of hydrogen from the given moles and molar mass as:
W = (0.0495mol)(2.0158g/mol) = 0.09 grams = 0.10 grams
Hence, option (a) is correct i.e. 0.1 grams.
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how many moles of silver nitrate are needed to produce 6.75 moles of copper (II) nitrate upon reacting with excess copper?
Answer:
13.50 moles of AgNO₃ are needed to produce 6.75 moles of Cu(NO₃)₂
Explanation:
We state the reactants:
AgNO₃
Cu
Then, the products are:
Cu(NO₃)₂
Ag
The reaction is: 2AgNO₃ + Cu → 2Ag + Cu(NO₃)₂
Ratio is 1:2.
The copper is in excess, so the limiting reactant is the silver nitrate:
1 mol of Cu(NO₃)₂ is produced by 2 moles of AgNO₃
Then, 6.75 moles of copper (II) nitrate would be produced by, the double of moles
(6 75 . 2) /1 = 13.50 moles
Does anyone know what 5.7365 x 10^-5 + 3.4891 x 10^-8 is? in scientific notation preferably?
Answer:
5.7400 × 10⁻⁵
Explanation:
Hydrogen bonding is a type of intermolecular force between polar covalent molecules, one of which has a hydrogen atom bonded to a small and extremely electronegative element, specifically an N, O, or Falom, on the other molecule. Hydrogen banding is a subset of dipole-dipole forces identify the correct conditions for forming a hydrogen bond. The CH molecule exhibits hydrogen bonding. O A hydrogen atom acquires a partial positive charge when it is covalently bonded to an atom. Hydrogen bonding docurs when a hydrogen atom is covalently bonded to an N O or F alom. A hydrogen bond is possible with only certain hydrogen-containing compounds. A hydrogen bond is equivalent to a covalent band.
To form a hydrogen bond, there are a few conditions that need to be met. Firstly, there must be a hydrogen atom bonded to a small and highly electronegative element such as N, O or F.
To form a hydrogen bond, there are a few conditions that need to be met. Firstly, there must be a hydrogen atom bonded to a small and highly electronegative element such as N, O or F. This creates a polar covalent bond between the hydrogen and the other element. Secondly, there must be another polar covalent molecule that contains a lone pair of electrons on the same N, O or F atom that is capable of attracting the hydrogen atom's partial positive charge. When these two conditions are met, a hydrogen bond can form between the two molecules.
It is important to note that not all hydrogen-containing compounds exhibit hydrogen bonding. The CH molecule, for example, does not have a highly electronegative element that can form hydrogen bonds.
Overall, hydrogen bonding is a type of intermolecular force that is a subset of dipole-dipole forces. It occurs when a hydrogen atom is covalently bonded to an N, O or F atom and is attracted to another polar covalent molecule with a lone pair of electrons on the same highly electronegative element.
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which isotope, when bombarded with oxygen-18, yields the artificial isotope seaborgium-263 plus 4 neutrons?
Californium -249 is the isotope, when bombarded with oxygen-18, yields the artificial isotope seaborgium-263 plus 4 neutrons.
Californium is a radioactive chemical element with the symbol Cf and atomic number 98. The element was first synthesized by bombarding curium with alpha particles (helium-4 ions).
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Hi, I need help please :)
the sds for 1-octanol is provided here. (links to an external site.) is 1-octanol a combustible liquid?
True. 1-octanol is a combustible liquid with a flashpoint of 86°C and an auto-ignition temperature of 258°C, according to the provided SDS.
The SDS (Safety Data Sheet) for 1-octanol indicates that it is a combustible liquid. According to the SDS, 1-octanol has a flashpoint of 86°C (187°F) and an auto-ignition temperature of 258°C (496°F). These values suggest that 1-octanol can easily ignite in the presence of an ignition source and may burn at relatively low temperatures. Additionally, the SDS provides information on the fire and explosion hazards associated with 1-octanol and recommends appropriate handling procedures and precautions to minimize the risk of fire or explosion. Therefore, it is important to handle 1-octanol with care and follow appropriate safety protocols when working with this substance.
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The complete question is:
the SDS for 1-octanol is provided here. (links to an external site.) is 1-octanol a combustible liquid? True or False.
17. How many joules of heat are absorbed to raise the
temperature of 435 grams of water at 1 atm from
25°C to its boiling point, 100.°C?
A) 4.5 X 10^4 J
C) 2.5 X 10^7 J
B) 1.4 X 10^5 J
D) 7.4 X 10^7 J
The amount of heat absorbed to raise the temperature of 435 grams of water at 1 atm from 25°C to its boiling point, 100°C, is approximately 1.4 × 10^5 joules
What is specific heat?
Specific heat is the amount of heat energy required to raise the temperature of a substance by one unit of temperature per unit of mass. It is a physical property that helps to characterize a substance and is typically measured in units of joules per gram per degree Celsius (J/g°C) or calories per gram per degree Celsius (cal/g°C).
The amount of heat absorbed to raise the temperature of a substance can be calculated using the formula:
Q = mcΔT
where Q is the amount of heat absorbed (in joules), m is the mass of the substance (in kilograms), c is the specific heat capacity of the substance (in joules per kilogram per degree Celsius), and ΔT is the change in temperature (in degrees Celsius).
Substituting the given values, we get:
m = 435 grams = 0.435 kg
ΔT = 100°C - 25°C = 75°C
The specific heat capacity of water is 4.184 J/g°C. We can convert this to joules per kilogram per degree Celsius (J/kg°C) by dividing by 1000:
c = 4.184 J/g°C ÷ 1000 = 4.184 J/kg°C
Substituting these values, we get:
Q = (0.435 kg) × (4.184 J/kg°C) × (75°C)
Q = 140,089.2 J
Therefore, the amount of heat absorbed to raise the temperature of 435 grams of water at 1 atm from 25°C to its boiling point, 100°C, is approximately 1.4 × 10^5 joules. The answer closest to this value is option (B).
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What reaction is depicted by the given equation: Au3+ + 3e− Au
A. oxidation B. reduction C. combustion D. replacement E. neutralization
Answer:
The answer is option B.
Reduction
Hope this helps you
Answer:
plato answer b
Explanation: