what do elements have to do with geology?

Answer:

Shortcoming:-After some time cell stops working because + electrolyte becomes more + and - ve electrolyte become more -ve with time.So there is difficulty in flowing of current.So it stops working after some time.

This Problem can be solved by using a u shaped tube salt bridge.Salt bridge completes the circuit and will maintain liquid liquid junction potential.And now there will be countinuous flow of e- or current.

Answer: Microphones are a type of transducer - a device which converts energy from one form to another. Microphones convert acoustical energy (sound waves) into electrical energy (the audio signal). Different types of microphone have different ways of converting energy but they all share one thing in common! Furthermore, Example 1: Crushing a can.

Type of change:

Developmental – May be either planned or emergent; it is first order, or incremental. ...

Transitional – Seeks to achieve a known desired state that is different from the existing one. ...

Transformational – Is radical or second order in nature.

Answer:

so so

Explanation:

this your question?? <_>

a) In 25 grams of water, the solubility is 92/4 = 23 grams, so adding 24 grams will produce a supersaturated solution.

b) In 50 grams of water, the solubility is 92/2 = 46 grams, so adding 47 grams will produce a supersaturated solution.

c) In 150 grams of water, the solubility is 92(1.5) = 138 grams, so adding 127 grams will produce an unsaturated solution.

Adding a catalyst will not cause the equilibrium of the reaction to shift towards the products.

A catalyst is a substance that speeds up the rate of a chemical reaction without being consumed in the reaction. It does not affect the position of the equilibrium or the relative amounts of reactants and products at equilibrium.

In the given reaction, Si(s) + 2Cl₂(g) + heat ↔ SiCl₄(g), the forward reaction is exothermic, which means it releases heat. According to Le Chatelier's principle, an increase in temperature will shift the equilibrium towards the reactants side in order to counteract the increase in heat. Therefore, increasing the temperature will shift the equilibrium towards the left, reducing the yield of silicon tetrachloride.

Increasing the pressure of the system will also shift the equilibrium towards the side with fewer gas molecules, which is the products side. In this case, increasing the pressure will shift the equilibrium towards the products, increasing the yield of silicon tetrachloride.

Increasing the mass of both reactants and products by 20% will not affect the position of the equilibrium either, as it does not change the ratio of the concentrations of the reactants and products.

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Answer:

C

Explanation:

A is the independent variable

D and B are control variables

When 7.524 is rounded to 3 significant figures, it will be 7.52.

The process of changing a number to a nearby number with fewer significant digits is known as rounding.

Rounding can be done to the nearest integer, the nearest tenth, the nearest hundredth, and so on.

Here are some pointers on rounding numbers to a certain number of significant digits:If the digit following the last significant digit is less than 5, simply drop it and all following digits.

(round down)For example, 2.832 rounded to two significant digits is 2.8 since the 3 is followed by a 2 which is less than 5.

If the digit following the last significant digit is greater than 5, add 1 to the last significant digit, then drop all of the digits that follow it.

(round up)For example, 4.673 rounded to two significant digits is 4.7 since the 3 is followed by a 7 which is greater than 5.

If the digit following the last significant digit is exactly 5, the preceding digit is odd, and no other digits follow, increase the last significant digit by 1.

If the digit following the last significant digit is exactly 5, the preceding digit is even, and no other digits follow, simply leave the last significant digit alone.

For example, 2.875 rounded to two significant digits is 2.9 since the 5 is followed by an odd number, which means that the 8 should be rounded up, while 2.765 rounded to two significant digits is 2.8 since the 5 is followed by an even number, which means that the 6 should be left alone.

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A leather jacket and printer paper are examples of items that can be made from renewable resources, while plastic forks, metal cans, and electronics are not considered renewable due to their reliance on non-renewable materials and processes. Option  C, E

The two correct answers that are made from renewable resources are:

C) Leather jacket: Leather is derived from animal hides, which are a byproduct of the meat industry. As long as there is a sustainable and responsible approach to animal farming, the production of leather can be considered renewable. The hides are obtained from animals that are raised for meat consumption, and their use in leather production helps reduce waste.

E) Printer paper: Printer paper can be made from various sources, including trees, bamboo, and recycled paper fibers. If the paper is sourced from sustainably managed forests or from fast-growing plants like bamboo, it can be considered renewable. Additionally, the use of recycled paper fibers reduces the demand for materials and promotes a more circular economy.

The other options, A) plastic fork, B) metal can, and D) electronics, are not made from renewable resources:

A) Plastic fork: Plastics are typically derived from fossil fuels, which are non-renewable resources. The production of plastic involves the extraction and processing of petroleum or natural gas, both of which are finite resources.

B) Metal can: Metal cans are predominantly made from aluminum or steel. While these metals can be recycled, their initial production requires the extraction of raw materials from the Earth, which is not a renewable process.

D) Electronics: Electronics are made from a wide range of materials, including metals, plastics, and various chemical compounds. The production of electronics involves the extraction of raw materials, many of which are non-renewable resources.

Option C and E.

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Sulphur (S) is the species that has the greatest rate of appearance in the given reaction.

2 H₂S + O₂ → 2 S + 2 H₂O

Sulphur (S) is the species that has the greatest rate of appearance in the given reaction . This can be determined by analysing the reaction's stoichiometry. Two molecules of sulphur (S) are created for each O2 molecule that interacts. The reactant species, H₂S and O₂, on the other hand, have coefficients of 2 and 1, respectively.

Therefore, the rate at which sulfur (S) appears is twice the rate of appearance of any other species in the reaction.

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Answer:

0.509 (to 3dp)

Explanation:

The formula for moles is:

moles = mass ÷ molar mass

The molar mass of NaCl can be calculated by adding the relative atomic masses of each element in the compound, which you can find in a periodic table:

molar mass = 23.0 + 35.5 = 58.5

Now, we can find the number of moles of NaCl in 29.8g:

moles = 29.8 ÷ 58.5 = 0.509 (to 3dp)

Answer:

Explanation:

250 L of 5.0% w/v glucose solution can be prepared using 125 g of glucose.

w/v = [ mass of solute (g) / volume of solution (mL) ] × 100

5.0 % w/v = [ 125 g / volume of solution (mL) ] × 100

volume of solution (mL) = [ 125 g / 5.0 % w/v ] x 100

volume of solution (mL) = [ 125 g / (5.0 / 100) ] x 100

volume of solution (mL) = [ 125 g / 0.05 ] x 100

The result of an increase in temperature at constant pressure will (1) The equilibrium will shift to the left, and the concentration of NO2(g) will decrease.

To determine the effect of an increase in temperature on the given equilibrium reaction, we need to analyze the reaction's heat as well as its stoichiometry.

The given reaction is an endothermic reaction as it absorbs heat (58.1 kJ) on the product side. According to Le Chatelier's principle, an increase in temperature will cause the equilibrium to shift in the direction that absorbs heat, i.e., to the left in this case.

Option 1 states that the equilibrium will shift to the left, which is correct. As the temperature increases, the equilibrium will shift to counteract the increase in heat. This means that more reactants, N₂O₄(g), will be formed, and the concentration of NO₂(g) will decrease.

Option 2 incorrectly suggests that the concentration of NO₂(g) will increase. However, since the equilibrium is shifting to the left, the concentration of NO₂(g) will actually decrease.

Option 3 correctly states that the equilibrium will shift to the right. This is an incorrect answer because an increase in temperature causes the equilibrium to shift in the direction that absorbs heat, which is to the left in this case.

Option 4 incorrectly mentions CO₂(g), which is not present in the given reaction. Therefore, this option is incorrect.

In summary, the correct answer is option 1: The equilibrium will shift to the left, and the concentration of NO₂(g) will decrease when the temperature is increased at constant pressure.
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Answer:

A will float on top of B.

Explanation:

B is more dense. example A is oil and B is water.

Answer:

Oxygen has 8 protons in the nucleus while nitrogen only has 7. A bonding pair will experience more attraction from the oxygen's nucleus than from nitrogen's, and so the electronegativity of oxygen is greater.

Answer:

During the evaporation of water sprayed in the driveway on a hot day, the air surrounding the sprayed water supplies heat. From the perspective of sprayed water, it loses heat to the air during the evaporation process. Thus the air temperature drops and thus we feel fresh.

. During the evaporation of water sprayed in the driveway on a hot day, the air surrounding the sprayed water supplies heat. From the perspective of the environment, the air loses heat through the evaporation process. Thus the air temperature drops and thus we feel fresh.

Explanation:

I consider that the two options are true, since when cooling the earth with cold water, this surface loses heat by yielding to the cold aqueous medium, and in addition to that, the air that surrounds the water particles are hotter than these, it is As well as the evaporation is fulfilled and the environment loses or gives up heat to the aqueous particles in order to be able to give up energy and that the evaporation is fulfilled.

Answer:

Assuming 20.0 mL of 0.2 M NaOH is used to neutralize 30 mL of the HCl of unknown concentration, the concentration of the hydrochloric acid is 0.133 M.

Note: The volume of NaOH used isnot given and issp to be determined by titration.

Explanation:

The question is a lab activity. Therefore, the volume of 0.2 M NaOH required for the neutralization of 30.0 mL of hydrochloric acid of unknown concentration is to be determined from titration. However, assuming a certain volume of the base is used for the complete neutralization of the acid, the concentration of the acid can be calculated.

Assuming 20.0 mL of 0.2 M NaOH is used to neutralize 30 mL of the HCl of unknown concentration, the concentration of the hydrochloric acid can be calculated thus:

Step 1: Balanced chemical equation of reaction:

HCl + NaOH ---> NaCl + H₂O

From the equation of the reaction, 1 mole of NaOH reacts with 1 mole of HCl to produce 1 mole of NaCl and water.

Step 2: Determine the number of moles of NaOH in 20.0 mL of 0.200 M solution

Molarity = number of moles/volume in Litres

Number of moles = molarity × volume in litres

Volume of NaOH in litres = 20 ml × 1 litre/1000ml = 0.02 litres

Number of moles NaOH = 0.02 L × 0.2 M = 0.004 moles

Therefore, 0.00 M of NaOH reacted with 0.004 moles of HCl

Step 3: Determine concentration of HCl

Molarity or concentration = number of moles / volume in litres

Number of moles of HCl = 0.004 moles

Volume of HCl in litres = 30.0 mL × 1 L/1000 mL = 0.03 L

Concentration of HCl = 0.004 moles / 0.03 L = 0.133 M

Therefore, assuming 20.0 mL of 0.2 M NaOH is used to neutralize 30 mL of the HCl of unknown concentration, the concentration of the hydrochloric acid is 0.133 M.

Answer: Adenosine 5'-triphosphate, or ATP

Explanation:

Based on the charge on the aluminium ion, 0.9 g of aluminium are deposited by 0.1 F of electricity.

Electrolysis is the decomposition of a substance known as an electrolyte when electric current is passed through it.

The mass and hence moles an electrolyte deposited when current is passed through it depends on the charge on the ion.

Aluminium ion has a charge of +3 and requires 3F of electricity to deposit 1 mole or 27 g of aluminium

0.1 F will discharge = 0.1/3 × 27 g of aluminium

mass of aluminium deposited = 0.9 g of aluminium.

Therefore, 0.9 g of aluminium are deposited by 0.1 F of electricity.

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Reagents that are entirely consumed by a chemical reaction are known as limiting reagents.

Thus, They are additionally known as limiting reactants or limiting agents. A predetermined quantity of reactants are necessary for the reaction to be completed, according to the stoichiometry of chemical reactions.

In the aforementioned reaction, 2 moles of ammonia are created when 3 moles of hydrogen gas react with 1 mole of nitrogen gas.

In most cases, this reactant dictates when the reaction will end. The reaction stoichiometry can be used to determine the precise quantity of reactant that will be required to react with another element. The limiting agent is determined by the mole ratio rather than the mass of the reactants.

Thus, Reagents that are entirely consumed by a chemical reaction are known as limiting reagents.

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The molecules in a copper penny is closely packed and and has no space to move apart thus the material will be denser than that in the molten state. That's why the penny sink in the molten copper.

Copper is a transition metal exhibiting all the metallic properties. The molten state of metals is the fluid state where the molecule are not strongly held by the metallic bonds.

Molten material is made by melting them and the liquid like state contains molecules with some space to move apart. Whereas, in solid state as in a copper penny, the molecules are closely packed and have no space to move apart.

An object will sink in a liquid if it is less dense than the liquid. Copper penny is denser than the molten copper because the molecules are densely packed and it will sink on to it.

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The possible combinations are;

1) n = 5, l = 2, ml = 0, ms = -1/2

2) n = 3, l = 1, ml = -1, ms = +1/2

We know that quantum numbers are used to show the position of the electron in an atom. The quantum number shows us the position or the place that we could be able to locate a particular electron that is under study. Recall that the region in space where there is a high probability of finding the electron is called the orbital.

The following are the possible combinations of quantum numbers for a given electron;

1) n = 5, l = 2, ml = 0, ms = -1/2

2) n = 3, l = 1, ml = -1, ms = +1/2

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Copper atoms (Cu) were created by reducing copper ions (Cu2+). An illustration of a reduction reaction is this. (Mg2+).To create Mg2+ ions, Mg atoms lost their electrons. An example of an oxidation reaction is this.

Oxidation and reduction occurred in test tube 5. Here is the equation for the reaction that took place:MgSO4 (aq) + Cu (s) CuSO4 (aq) + MgCuSO4's blue hue was neutralised to a solid copper hue. Copper atoms (Cu) were created by reducing copper ions (Cu2+). An illustration of a reduction reaction is this. Cu atoms are created when Cu2+ gains electrons. Due to the presence of magnesium ions (Mg2+), the solution was greenish-yellow.To create Mg2+ ions, Mg atoms lost their electrons. An example of an oxidation reaction is this. Two electrons were lost by the magnesium atom, leaving two electrons behind.

As a result, test tube 5 experienced both oxidation and reduction.It is possible to prove that oxidation, reduction, or both took place through the reaction's electron transfer and colour changes. A reduction reaction was seen when copper ions transformed into copper atoms. An oxidation reaction was evident when magnesium atoms transformed into magnesium ions.

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Type #1 Flame symbols are among the WHMIS emblems.

Type 2: Symbols with a flame above a circle.

Exploding bomb symbols are of type 3.

Compressed gas symbols are of type 4.

Corrosion symbols are type #5.

Skull and water the water symbols are type #6.

Exclamation mark symbols are type #7.

Health hazard symbols are type #8.

Because workplaces require a defined technique to detect hazardous items, WHMIS labels are crucial.

The national ’s hazard standard for Canada is the Health And Safety At work System (WHMIS). Hazard categorization, cautionary container labeling, the distribution of safety data sheets, and worker information and training programs are the system's main components.

The U.S. Ohs Hazard Identification Standard and WHMIS are quite similar.

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Answer:

The chemical reaction identified is:

2Al + 3CuCl2 → 2AlCl3 + 3Cu

In this reaction, aluminum (Al) reacts with copper chloride (CuCl2) to form aluminum chloride (AlCl3) and copper (Cu). The coefficients in front of the chemical formulas indicate the stoichiometric ratio of the reactants and products, which means that two moles of Al react with three moles of CuCl2 to produce two moles of AlCl3 and three moles of Cu.

Answer :

When the combined vapour pressure of a miscible liquid mixture reaches atmospheric pressure, the solution boils. This vapour pressure denotes the boiling pressure in a mixture.

The air pressure directly impacts a liquid's boiling point. The weight of the air molecules above the liquid is the factor putting more pressure on the liquid. This is considered to as atmospheric pressure in an open system. The higher the boiling point and the more energy needed to bring liquids to a boil, the higher the pressure.

Because volatile compounds regularly have different boiling points, when a mixture is distilled, the components commonly separate from the mixture. The temperature at which the external pressure operating on the surface of a liquid equals the vapour pressure of the liquid phase of a compound is termed as the boiling point.

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