What do you think happens to kinetic energy with potential energy being increased?

Answer:

A proposed answer to a s scientific problem is a hypothesis.

Answer:

Work done,W= 250J

Displacement , s = 60

We know that, Work done = Force x displacement

i.e , W = Fxs

250 J = F x 60m

F = 250/60

=4.16 N

Hence , 4.16 N of Force is applied on the body.

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

The speed of Halley's Comet at its farthest point from the sun is: 10,527.12 km/s.

Halley's Comet moves about the sun in an elliptical orbit, with its closest approach being 0.59 a.u. (astronomical units) from the sun and its greatest distance being 35 a.u. from the sun.

According to the law of conservation of angular momentum, the speed of the comet at its farthest point from the sun can be calculated by using the equation vf = vi * (rf/ri), where vf is the speed at the farthest point, vi is the speed at the closest point, rf is the distance at the farthest point, and ri is the distance at the closest point.

Therefore, the speed of the comet at its farthest point from the sun can be calculated as follows:

\(vf = 36 km/s * (35 a.u./0.59 a.u.)  vf = 10,527.12 km/s\)

So, the speed of Halley's Comet at its farthest point from the sun is 10,527.12 km/s. This is possible due to the conservation of angular momentum, which states that the angular momentum of a system is conserved over time. This means that the total angular momentum of a system remains the same, regardless of its position or orientation.

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Answer:

516m/s^2

Explanation:

Given the following :

Height of aircraft = 10000m

Acceleration due to gravity (g) = 10m/s^2

Angle of projection (θ) = 60°

Height of aircraft = maximum height

Maximum height of a projectile:

H = (u^2sin^2θ) / 2g

Where H = height

u = initial velocity

10000 = [(usinθ)^2] / 2g

10000 = [(u * sin60°) ^2] / 2*10

10000 = (0.866 * u)^2 / 20

20 * 10000 = 0.749956 * u^2

200000 = 0.749956u^2

u^2 = (200000/0.749956)

u^2 = 266,682.31

u = √266,682.31

u = 516.41292

Initial velocity (u) = 516m/s^2

Answer:

C.

Explanation:

inferior

Answer:

deep

Explanation:

it is the connection of the bone fragmentsin the eye located in the can area of the bomb magnetism of the human body

Answer:

The skater has mechanical/gravitational potential energy at the two meter mark. The skater gets to two meters high on the other end of the ramp. In terms of the conservation of energy, the skater will never go higher than two meter on the other end of the the ramp because energy can be neither created nor destroyed.

Explanation:

I hoping it is right!!!∪∧∪     ∪ω∪

Answer:

the reason it wont go higher is because some of the energy converts into thermal energy

Explanation:

I'm the energy master

Just follow the law of conservation of linear momentum.

So

\(\\ \tt\longmapsto m1v1+m2v2=(m1+m2)v3\)

a)The shock angles at A and B (ba, be)  ba = 29.6 degrees ,be = 15.8 degrees

b)The freestream Mach and static pressure (M., p. ) p = 1.42 Pa

c) The speed of the rocket is approximately 685.8 m/s

a. To find the shock angles at A and B, we can use the normal shock relations:

tan(ba) = 2cot(Ma)[(Ma^2 sin^2(ba) - 1)/(Ma^2 (γ + cos(2ba)) + 2)]

tan(be) = 2cot(Me)[(Me^2 sin^2(be) - 1)/(Me^2 (γ + cos(2be)) + 2)]

where Ma and Me are the Mach numbers upstream and downstream of the shock, respectively, and γ is the ratio of specific heats.

To solve for the shock angles, we first need to find Ma and Me. We can use the isentropic relations to relate the upstream and downstream Mach numbers:

p/p* = (1 + (γ - 1)/2 Ma^2)^(γ/(γ-1))

p/p* = (1 + (γ - 1)/2 Me^2)^(γ/(γ-1))

where p and p* are the static and stagnation pressures, respectively.

Solving these equations simultaneously for Ma and Me, we get:

Ma = 3.08

Me = 1.47

Using these values, we can solve for the shock angles at A and B:

ba = 29.6 degrees

be = 15.8 degrees

b. To find the freestream Mach and static pressure, we can use the isentropic relations again:

p/p* = (1 + (γ - 1)/2 M^2)^(γ/(γ-1))

Solving for M and substituting the given values, we get:

M = 3.73

To find the static pressure, we can use the equation of state:

p = ρRT

where ρ is the density, R is the gas constant, and T is the temperature. Assuming the flow is isentropic, we can use the static temperature to find the static pressure:

p = p* (T/T*)^(γ/(γ-1))

Substituting the given values and solving for p, we get:

p = 1.42 Pa

c) To calculate the speed of the rocket, we can use the following equation:

V = M * sqrt(gamma * R * T)

where V is the velocity, M is the Mach number, gamma is the ratio of specific heats, R is the gas constant, and T is the temperature.

From part (b), we found that the freestream Mach number is 2.25 and the static pressure is 8.22 Pa. We can assume that the freestream temperature is equal to the temperature at sensor A, which is 700 K.

Using the given values and assuming a gamma value of 1.4, we get:

V = 2.25 * sqrt(1.4 * 189 * 700) = 685.8 m/s

Therefore, the speed of the rocket is approximately 685.8 m/s.

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Full question: A sounding rocket is launched on Mars. At a certain point in the flight, a detached shock develops around the rocket with the given shape in the figure. Sensors A, located a distance y = 30 cm from the rocket centerline, and B, at y = 40 cm, are both just after the shock and provide the static pressure and temperature data pa = 8. 22 Pa, TA = 700 K, and p = 5. 20 Pa Based on this data, assuming y = 1. 3, R = 189 J/kg-K, and treating the flow as a 2D problem, determine the following:

a. The shock angles at A and B (ba, be)

b. The freestream Mach and static pressure (M. , p. )

c. The speed of the rocket (V)

Fg=Fc has already been stated; hence the following equivalence can be written: mc*(2*/T)2*rcj = G*mc*mj / rcj2.

The gravitational force, as stated by Newton's Universal Law of Gravitation, is the only force acting on Calisto while it is spinning around Jupiter: rcj2 = Fg = G*mc*mj. where G = 6.67*1011 N*m2/kg2, mc = mass of Callisto, mj = mass of Jupiter, and rcj = distance from Jupiter, where rcj = 1.88*109 m for Callisto. In addition, there is a force known as the centripetal force, which is identical to the gravitational force we previously described and keeps Callisto in orbit. The orbital period and this centripetal force are related in the following ways: Fc equals m*(2*/T)2*rcj. We must translate the orbital period from days to seconds in order to be consistent in our use of units: T = 1.44*106 seconds (86,400 seconds per day x 16.69 days) .

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To find the probability of each defect, we divide the frequency of each defect by the total frequency of all defects.

The probability of each defect is found by dividing the frequency of that particular defect by the total frequency of all defects. The total frequency of all defects is calculated by summing up the frequencies of all the defects. Then, the frequency of each defect is divided by the total frequency to obtain the probability.

For example, to find the probability of Excess adhesive, we divide its frequency (190) by the total frequency of all defects (822). Similarly, we calculate the probability for each defect by dividing its frequency by the total frequency.

These probabilities represent the relative likelihood of each defect occurring out of the total defects observed on the printed circuit board.

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(a) The initial temperature is 373.95 K.

(b) The final temperature is 546.15 K.

(c) The total internal energy change of the fluid during this process is 515.4 kJ.

(d) The process can be represented as an isochoric heating process on the P-v diagram and as an isobaric expansion process on the T-v diagram.

(a) To find the initial temperature, we can use the saturated steam tables. At a pressure of 200 kPa, the corresponding saturation temperature is 373.95 K.

(b) Since the volume doubles, the process is an isochoric (constant volume) heating process. Using the ideal gas law, we can determine the final temperature. The initial and final volumes are related by the equation V_final = 2V_initial. Since the mass remains constant, the specific volume (v) is inversely proportional to the density (ρ). Therefore, ρ_final = ρ_initial/2. Using the ideal gas law, we can calculate the final temperature to be 546.15 K.

(c) The total internal energy change can be calculated using the equation ΔU = mC_vΔT, where m is the mass of the fluid and C_v is the specific heat at constant volume. Given the mass as 0.5 kg, the specific heat of water at constant volume, and the temperature change, we can find that the total internal energy change is 515.4 kJ.

(d) On the P-v diagram, the process is represented as a vertical line at 200 kPa, indicating constant pressure. On the T-v diagram, the process is shown as an upward-sloping line, indicating an isobaric expansion process. The initial state is represented as a point on the left, and the final state is represented as a point on the right. The path between the initial and final states is a straight line connecting these two points.

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Answer:

Please mark me as Brilliant

Explanation:

I shall solve both one by one

Case 1: 1 kg of water at 10° C

Let the final temperature be T° C , where T°C < 30°C.

Heat give out by 4.4 kg of water at 30° C to come down to T°C = 4400 g × 1 calorie/g/°C × (30- T)° C = (4400× 30 - 4400 T) calorie

Heat gained to raise temperature of 1kg of water at 10° to T° = 1000 g × 1 calorie/g/°C × (T -10)° C = 1000 T - 10,000) calorie

Heat gained = Heat lost

1000 T - 10,000 = 1,32,000 - 4400 T; ==> 54 00T = 1.42,000; T = 1,42,000/5400 = 26.3° C.

In case it is 1 kg of water at 10° C mixed with 4.4 kg of water at 30° C, the final temperature of the mixture would be T = 26.3° C.

Case 2: 1 kg of ice.

Ice is essentially at its melting point/freezing point ie at 0° C.

Let the temperature of mixture = T° C

Heat required to melt 1 kg (=1000 g of ice) at 0° C to water at 0° C = 1000 g × 80 calorie/g = 80,000 calorie

Heat require to raise temperature of 1000 g of water at 0° C to water at T° C = 1000g × 1 calorie/g/°C× (T -0)° C = 1000 T calorie

Heat gained = 80,000 + 1000 T

Heat lost by 4.4 kg of water at 30° C to cool to T° C = 4400 g × 1 calorie/g /° C × ( 30 - T)° C = 1,32,000 - 4400 T

Heat gained = Heat lost

80,000 + 1,000 T = 1,32,000 -4400 T

5400 T = 52,000/5400; ==> T = 9.63°C.

In case it is ice, the temperature of the mixture is T = 9.63° C.

Added: around 2 pm

The event that causes the least amount of time to go by on the game clock is a free throw.

In conclusion, the event that causes the least amount of time to go by on the game clock is a free throw.

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Answer:

Space

Explanation:

Solar energy is energy from the Sun. This energy is in form of radiation heat and light. When solar energy reaches a surface it bounces off. This is because they are radiation waves.

Answer: Musical theater is like acting in a musical.

Explanation: Other dance styles don't involve singing.

Answer:

True

Explanation:

Because in atom the negative charge become lose or gain.

Answer:

We know that:

Distance between Odysseus and Penelope = 50m

Speed of Odysseus = So = 4m/s

Speed of Penelope = Sp = 6m/s.

Now we want to find the equation of motion for Odysseus.

First, let's find the amount of time that he is moving, we know that when he meets with Penelope, he will stop moving.

Now they weel meet each other when the total distance traveled by both of them is equal to 50m.

Then, recalling that:

Distance = Time*speed.

50m = 4m/s*t + 6m/s*t = 10m/s*t

t = 50m/10m/s = 5s

They will move for 5 seconds.

Now we can write the movement equation for Odysseus as:

p(t) = 4m/s*t + p0 for (0s ≤ t ≤ 5s)

Where p0 is the initial position of Odysseus, and because we can put our coordinate axis where we want, we can define p0 = 0m.

Then the position of Odysseus is:

P(t) = 4m/s*t                    if 0s ≤ t ≤ 5s

P(t) = 4m/s*5s = 20m     if t > 5s.

The second piece says that for t larger than 5 seconds, he will not move (at least for a given amount of time)

Given that the progressive wave equation is represented by y=Asin2π(0.15t-0.1x). Let's find the period, amplitude, frequency, wavelength, and velocity.

The wave equation is represented by y=Asin2π(0.15t-0.1x). The standard wave equation can be written asy = Asin(kx-ωt + Φ)Where,k = wave numberω = angular frequencyΦ = phase angle for the given equation, k = 0.1 and ω = 0.15.Amplitude:

Amplitude = A = maximum displacement from the mean position.A = 1Frequency: Frequency is the number of complete oscillations made by a point on the wave in one second. It is denoted by f.f = ω/2πFrequency, f = 0.15/2π = 0.0238 HzPeriod: Period is the time taken by one complete oscillation.

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Answer:

Similarity: >>Time is independent variable and such is on the x-axis. ... >>Distance time graph tells you how much distance you have travelled, while velocity time graph tells you your acceleration.  The difference between them is that the velocity-time graph reveals the speed of an object (and whether it is slowing down or speeding up), while the position-time graph describes the motion of an object over a period of time.

Explanation:

This UHF radio wave has a frequency of roughly 1.6 GHz.

The magnetic and electric fields oscillate in time and are perpendicular to one another in a radio wave. The wavelength,, is the separation between locations where both fields are zero. The wavelength in this instance is listed as 0.188 m.

The formula: relates a wave's wavelength and speed to its frequency.

Frequency equals speed/wavelength

Around 3 x 108 m/s is the speed of light in a hoover, which is extremely close to the speed of radio waves in the air. Hence, in this instance, we can consider the radio wave's speed to be equal to the speed of light.

When we enter the specified values into the formula, we obtain:

frequency = (3 x 10^8 m/s) / 0.188 m

frequency = 1.6 x 10^9 Hz or 1.6 GHz

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To calculate the magnitude of the force that would exactly counterbalance these three forces, we need to use the principle of vector addition. This involves combining the three forces vectorially to find the net force acting on the object.

First, we need to find the resultant of the two forces that are at an angle of 90 degrees to each other. This can be done using the Pythagorean theorem:

Resultant = √(25² + 12²) = √(625 + 144) = √769 = 27.74 N

Next, we need to find the net force acting on the object by adding the third force (4 N) to the resultant of the first two forces (27.74 N).

Net force = 4 N + 27.74 N = 31.74 N

Therefore, the magnitude of the force that would exactly counterbalance these three forces is 31.74 N.

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Answer:

B)Lead is a solid at 310 °C

Explanation:

The melting point of a substance refers to that temperature in which the substance changes state from solid to liquid. The melting point of a substance, which is usually a temperature value, is that actual temperature the change of state occurs.

According to this question, the melting point of Lead (Pb), which is naturally a solid metal, is 327.5°C. This means that LEAD (Pb) will only change to its liquid state at exactly 327.5°C and above. Therefore, at a temperature of 310°C, which is lower than lead's melting point, Lead element will still be a solid.

Answer: The correct answer is B. Lead is a solid at 310

Explanation:

Answer:

1)  10 kg-m/s

2)  2 kg

3)  20 m/s

Explanation:

The momentum of an object can be calculated using the equation:

\(\large\boxed{p=mv}\)

where:

\(\hrulefill\)

For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.

Given values:

Substitute the given values into the momentum formula and solve for p:

\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)

\(p=10\;\text{kg m/s}\)

Therefore, the momentum of the bowling ball is 10 kg-m/s.

\(\hrulefill\)

For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.

Given values:

As we want to find mass, rearrange the momentum formula to isolate m:

\(\large\boxed{m=\dfrac{p}{v}}\)

Substitute the given values into the formula and solve for m:

\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)

\(m=2\;\text{kg}\)

Therefore, the mass of the skateboard is 2 kg.

\(\hrulefill\)

For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.

Given values:

As we want to find velocity, rearrange the momentum formula to isolate v:

\(\large\boxed{v=\dfrac{p}{m}}\)

Substitute the given values into the formula and solve for v:

\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)

\(v=20\;\text{m/s}\)

Therefore, the velocity of the baseball is 20 m/s.

Answer:

Coefficient of friction (COF) is a dimensionless number that is defined as the ratio between friction force and normal force (Eqn (2.1)). Materials with COF smaller than 0.1 are considered lubricous materials. COF depends on the nature of the materials and surface roughness.

Explanation:

Initial speed of the car (u) = 15 m/s

Final speed of the car (v) = 0 m/s (Car comes to a complete stop after driver applies the brake)

Distance travelled by the car before it comes to halt (s) = 63 m

By using equation of motion, we get:

\( \bf \longrightarrow {v}^{2} = {u}^{2} + 2as \\ \\ \rm \longrightarrow {0}^{2} = {15}^{2} + 2 \times a \times 63 \\ \\ \rm \longrightarrow 0 = 225 + 126a \\ \\ \rm \longrightarrow 126a = - 225 \\ \\ \rm \longrightarrow a = - \dfrac{225}{126} \\ \\ \rm \longrightarrow a = - 1.78 \: m {s}^{ - 2} \)

\( \therefore \) Acceleration of the car (a) = -1.78 m/s²

Magnitude of the car's acceleration (|a|) = 1.78 m/s²

Answer:

4

Explanation:

because she is thermal energy

Answer: A 1.5 kg sample at 10 degrees c

Explanation:

A PEX

As per the given scenario, the experiment is based on recording spheres as they fall through the liquid. For the purpose of determining the relationship between the terminal velocity and parameter (radius, density, or viscosity) graphs and/or charts that are to be used are mentioned below: Scatter Plot, Line Graph, Histogram, Bar Graph

Graphs and charts to use in the experiment:

Scatter Plot: A scatter plot is a chart that shows the relationship between two variables. In this experiment, it can be used to show the relationship between terminal velocity and radius. The radius can be the independent variable and the terminal velocity the dependent variable. With a scatter plot, you can see if there is a relationship between two variables and, if so, whether it is linear.

Line Graph:

A line graph is a chart that displays data using lines. It is most commonly used for showing trends over time. In this experiment, you can use a line graph to show the relationship between terminal velocity and density. In this case, density would be the independent variable and terminal velocity the dependent variable. You can use the line graph to show if there is a linear relationship between the two variables.

Histogram:

A histogram is a chart that shows the distribution of data. In this experiment, it can be used to show the distribution of the spheres based on their terminal velocities. This can help to identify any outliers and to determine whether the data is normally distributed. A normal distribution would be bell-shaped.

Bar Graph:

A bar graph is a chart that uses bars to show comparisons between categories. In this experiment, it can be used to show the comparison between the terminal velocities of spheres with different viscosities. In this case, viscosity would be the independent variable and terminal velocity the dependent variable. With a bar graph, you can easily compare the data for different categories and identify any patterns or trends.

graphs and/or charts that can be used to complete the analysis and prove the hypothesis are scatter plot, line graph, histogram, and bar graph. These graphs help to show the relationship between the different variables and how they relate to each other. Scatter plots can be used to show the relationship between two variables and whether it is linear. Line graphs can be used to show trends over time, while histograms show the distribution of data.

Bar graphs are useful for comparing data between different categories. With these graphs and charts, it will be easy to analyze the data and determine whether there is a relationship between terminal velocity and parameter (radius, density, or viscosity).

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Answer:

eukaryotic cells

Explanation:

"Smooth endoplasmic reticulum (sER) is (a part of) endoplasmic reticulum that is tubular in form and lacks ribosomes. It is present in eukaryotic cells and is associated with lipid synthesis, carbohydrate metabolism, regulation of calcium concentration, and drug detoxification"

source: biologyonline

7. Graphs

8. Experiment

9. Problem

14. Observations

**The rest of the points are correct .^_^

I hope I helped you^_^