What do you think would happen to the force of attraction of two interacting charges if their distance apart is halved?

Comparing the speeds of the moon and the GPS satellite, we see that the moon travels at a much slower speed than the GPS satellite relative to its distance from the Earth. This suggests that the orbital speed of an object around Earth is inversely proportional to its distance from Earth - that is, the farther an object is from Earth, the slower it needs to travel in order to maintain a stable orbit around Earth.

The GPS satellite orbits Earth at an altitude of about 20,200 km above the Earth's surface. Let's assume that the distance between the center of the Earth and the GPS satellite is approximately 20,200 km + the radius of the Earth (6,371 km), or about 26,571 km.

Since we know that the moon travels at a speed of about 3,600 km/hour and is about 19 times farther from Earth than the GPS satellite, we can calculate the moon's distance from the Earth using the ratio of distances:

Moon's distance from Earth = 19 x GPS satellite's distance from Earth

Moon's distance from Earth = 19 x 26,571 km

Moon's distance from Earth = 504,249 km

Now, we can calculate the moon's orbital speed using the formula:

Orbital speed = 2 x pi x orbital radius / time period

where pi is approximately 3.14, the orbital radius is the distance from the moon to the center of the Earth (504,249 km), and the time period is the time it takes the moon to complete one orbit around the Earth (27.3 days, or about 655.2 hours).

Orbital speed of the moon = 2 x 3.14 x 504,249 km / 655.2 hours

Orbital speed of the moon = 3,683 km/hour (rounded to the nearest km/hour)

Therefore, Orbital speed refers to the speed at which an object is moving in its orbit around another object. It is the velocity at which the object moves around the other object under the influence of the gravitational force between them.

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Answer:

Distance and Mass

Explanation:

25  m/s² is the object's acceleration

m1a1=m2a2

m1=5kg

m2=3 kg

a1= 15 m/s²

a2=?

m1a1=m2a2

a2=m1a1/m2

a2=5×15÷3

a2= 25  m/s²

Acceleration is a vector variable that describes the rate at which an object changes its velocity.

An object is said to be accelerating if its velocity is changing. Occasionally, a moving object can change its velocity by the same amount each second. a moving object whose speed fluctuates by 10 m/s every second. This is referred to as a constant acceleration since the velocity is changing by a fixed amount each second.

The difference between an object with a constant acceleration and one with a constant velocity must be understood. Do not be fooled! If an object's velocity changes, whether it does so by a constant amount or a variable amount, then it is accelerating. Furthermore, something that is travelling at a steady speed is not accelerating.

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The missing species of the nuclear reaction obtained is ³⁰₁₅P

The missing species of the equation can be obtain as follow:

Now, we can obtain the value of x, y and Z as follow:

²⁷₁₃Al + ⁴₂He -> ʸₓZ + ¹₀n

For x

13 + 2 = x + 0

15 = x

x = 15

For y

27 + 4 = y + 1

31 = y + 1

Collect like terms

y = 31 - 1

y = 30

For Z

ʸₓZ => ³⁰₁₅Z

From the period table, the element with atomic number of 15 is phosphorus, P. Thus, we have

ʸₓZ => ³⁰₁₅Z => ³⁰₁₅P

Therefore, we can write the complete equation as:

²⁷₁₃Al + ⁴₂He -> ³⁰₁₅P + ¹₀n

Thus, the missing species is ³⁰₁₅P

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Answer: hello question b is incomplete attached below is the missing question

a) attached below

b) V = 0.336 ft/s

Explanation:

Elongation ( Xo)  = 16/ 7 feet

mass attached to 4-foot spring = 16 pounds

medium has 9/2 times instanteous velocity

a) Find the equation of motion if the mass is initially released from the equilibrium position with a downward velocity of 2 ft/s

The motion is an underdamped motion because the value of β < Wo

Wo = 3.741 s^-1

attached below is a detailed solution of the question

The statement that is true about the theory of plate tectonics and the theory of continental drift C. The theory of plate tectonics gives the method by which continents can move as part of plates .

According to the scientific hypothesis of plate tectonics, the underground movements of the Earth create the primary landforms. By explaining a wide range of phenomena, including as mountain-building events, volcanoes, and earthquakes, the theory, which became firmly established in the 1960s, revolutionized the earth sciences.

The scientist Alfred Wegener is most closely connected with the concept of continental drift. Wegener wrote a paper outlining his notion that the continents were "drifting" across the Earth, occasionally crashing through oceans and into one another, in the early 20th century.

According to tectonic theory, the Earth's surface is dynamic and can move up to 1-2 inches every year. The numerous tectonic plates constantly move and interact. The outer layer of the Earth is altered by this motion. The result is earthquakes, volcanoes, and mountains.

Therefore, option C is correct.

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The displacement of the object after 1 second, is 3 m.

The displacement of the object after 3 seconds, is 9 m.

The displacement of the object after 5 seconds, is 15 m.

The displacement of an object is the change in the position of the object.

The displacement of the object after 1 second, x = 3 m/s x 1 second = 3 m

The displacement of the object after 1 second, x = 3 m/s x 3 s = 9 m

The displacement of the object after 1 second, x = 3 m/s x 5 s = 15 m

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Answer:

Friction and Air resistence

Explanation:

i already passed this grade years ago...

The forces responsible for exerting forces to the left on a cyclist are -

Air resistance describes the forces that are in opposition to the relative motion of an object as it passes through the air. We can write air resistance as -

\($F_{D}=\frac{1}{2} \rho v^{2} C_{D} A\)

where -

F{D} = drag

{ρ} = density of fluid

{v} = speed of the object relative to the fluid

C{D}  = drag coefficient

{A} = cross sectional area

Given is to find what 2 forces would be responsible for exerting forces to the left on a cyclist that is already in motion moving to the right.

The forces responsible for exerting forces to the left on a cyclist are -

Therefore, the forces responsible for exerting forces to the left on a cyclist are -

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Answer:

7.97 N

Explanation:

\(f = m g sin(\alpha) = 2 * 9.8 * sin(24) = 7.97 N\)

Answer:

\(\mathbf{F_{thrust} \simeq 2.3 \times 10^4 \ N}\)

Explanation:

For a lunar lander acceleration in an upward direction, the net force that acts on it can be expressed as:

\(F_{net} = F_{thrust} - F_{g(moon)}\)

The equation for the net force that acts on the lunar lander is:

\(F_{net} = m_La\)

For the lander touch down to be zero acceleration, it implies that the acceleration of the moving rocket is zero(a free body fall)

i.e. a = 0

We can now regard the Apollo 12 lunar as a freely falling body

However; the force of gravity as a result of the moon acting on the lunar rocket is:

\(F_{g(moon)} = m_Lg_m\)

Then; the equation for the thrust force of the lunar rocket is:

\(F_{net} = F_{thrust} - F_{g(moon)}\)

\(m_La = F_{thrust}-m_Lg_m\)

\(m_L(0)= F_{thrust}-m_Lg_m\)

\(0= F_{thrust}-m_Lg_m\)

\(-F_{thrust}= -m_Lg_m\)

\(F_{thrust}= m_Lg_m\)

Finally; the thrust force of the lunar rocket can be determined as:

\(F_{thrust}= m_Lg_m\)

Acceleration due to gravity ot the surface of the moon = 1.625 m/s²

\(F_{thrust}=(1.4 \times 10^{4} \ kg) (1.625 \ m/s^2)\)

\(F_{thrust}=2.275 \times 10^4 \ N\)

\(\mathbf{F_{thrust} \simeq 2.3 \times 10^4 \ N}\)

A thrust force of 22680N will be necessary to  to have the lander touch down with zero acceleration.

Given the data in the question;

Mass of Apollo 12 lunar lander; \(m_L = 1.4 * 10^4 kg\)

Using the expression for the net-force that acts on the lander when it is accelerated in the upward direction:

\(F_{net} = F_{thrust} - F_{g(moon)}\) ------- Let this be equation 1

Also, the net-force that acts on the lunar lander can be expressed as:

\(F_{net} = m_L*a\) ------- Let this be equation 2

Where \(m_L\) is the mass of the lunar lander and a is the acceleration ( 0 ),

( the acceleration of the moving rocket is zero and its freely falling )

Also, Force of gravity due to moon that acts on the lunar lander is expressed as:

\(F_{g(moon)} = m_L * g_m\)  ------- Let this be equation 3

Where \(m_L\) is the mass of the lunar lander and \(g_m\) is the moon's gravity ( \(1.62m/s^2\) )

Lets substitute equation 2 and 3 into 1

\(m_L * a = F_{thrust} - (m_L * g_m)\\\\m_L * 0= F_{thrust} - (m_L * g_m)\\\\0=F_{thrust} - (m_L * g_m)\\\\ F_{thrust} = m_L * g_m\)

We substitute our values into the equation

\(F_{thrust} = (1.4*10^4kg) * 1.62m/s^2\\\\F_{thrust} = 22680 kg.m/s^2\\\\F_{thrust} = 22680N\)

Therefore, a thrust force of 22680N will be necessary to  to have the lander touch down with zero acceleration.

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Answer:It is a combination reaction; nitrogen and hydrogen combine to form ammonia

Explanation:

This is the reaction that is used to make ammonia from hydrogen and nitrogen. In this reaction, only one product is formed. Therefore, this reaction is known as a combination reaction.

Based on the information, it should be noted that the resistance R is 0.5 Ω.

When S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:

Z = jωL - 1/(jωC)

Since i leads e by 30°, we can express the phasor relationship as:

I = k * e^(j(ωt + θ))

Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)

Re(Z) = 0

By equating the real parts, we get:

0 = 0 - 1/(120πC)

Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:

Z = R + jωL - 1/(jωC)

Z = R + jωL

Im(Z) = ωL > 0

Substituting the angular frequency and rearranging the inequality, we have:

120πL > 0

L > 0

This condition implies that the inductance L must be greater than zero.

When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:

Z = R + jωL - 1/(jωC)

Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:

I = 0.5 * e^(j(ωt + θ))

By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:

Re(Z) = R

Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R

Therefore, the resistance R is 0.5 Ω.

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Technically, ALL of the planets do.

The effect is greatest inside Mercury, because Mercury is the one closest to the Sun.

Answer:

Below

Explanation:

0-1 sec descends at constant rate from 10 to 6 m

1-2 sec stops at 6m

2-3 sec descends at constant rate to 2 m

3-4 sec stops at 2 m

4-5 sec descends at another constant rate to 0 m

Answer:

The kinetic theory of matter -all matter consists of many, very small particles which are constantly moving or in a continual state of motion. The degree to which the particles move is determined by the amount of energy they have and their relationship to other particles.Explanation:

Answer:

1080J

Explanation:

Given parameters:

Mass of object  = 2kg

Velocity  = 10m/s

Height  = 50m

Unknown:

Total energy  = ?

Solution:

The total energy of the moving object is obtainable by summing the kinetic and potential energy;

       Total energy  = P.E + K.E

P.E is the potential energy  = mgh

K.E is the kinetic energy = \(\frac{1}{2}\)mv²

 Now insert the parameters and solve;

    Total energy  = mgh +  \(\frac{1}{2}\)mv²

m is the mass

g is the acceleration due to gravity

h is the height

v is the velocity

  Total energy  = (2 x 9.8 x 50) +  ( \(\frac{1}{2}\) x 2 x 10²)

  Total energy  = 980 + 100 = 1080J

This angle is negative, which means that the wire is bent to the left instead of to the right, as shown in the diagram.

The electrostatic force on the charged insulator is given by Coulomb's law as:

F_electric = k * (q1 * q2) / r²

where k is the Coulomb constant (9 x 10⁹ N*m²/C²), q1 and q2 are the charges of the two objects, and r is the distance between them.

In this case, q1 = 0.400 uC and q2 = -0.220 uC. The distance between them is given as 0.290 m.

F_electric = (9 x 10⁹) * (0.400 x 10⁻⁶) * (-0.220 x  10⁻⁶) / (0.290)²

F_electric = -1.19 x 10⁻⁵ N

Since the insulator is in equilibrium, the electrostatic force must be balanced by the tension in the wire.

Let T be the tension in the wire, and θ be the angle that the wire makes with the vertical.

The horizontal component of the tension in the wire is given by T * sin(θ), and the vertical component is given by T * cos(θ).

Since the insulator is in equilibrium, the sum of the forces in the vertical direction must be zero:

T * cos(θ) - m * g = 0

where m is the mass of the insulator (6.00 x 10⁻² kg), and g is the acceleration due to gravity (9.8 m/s²).

Solving for T, we get:

T = m * g / cos(θ)

The sum of the forces in the horizontal direction must also be zero:

T * sin(θ) = F_electric

Substituting T and F_electric from the above equations, we get:

(m * g / cos(θ)) * sin(θ) = -1.19 x 10⁻⁵

Simplifying, we get:

tan(θ) = -1.19 x 10⁻⁵ / (m * g)

Substituting the given values, we get:

tan(θ) = -1.19 x 10⁻⁵ / (6.00 x 10⁻² kg * 9.8 m/s²)

tan(θ) = -2.06 x 10⁻⁵

Taking the inverse tangent, we get:

θ = -0.00118 degrees

However, this angle is negative, which means that the wire is bent to the left instead of to the right, as shown in the diagram.

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Answer:

1 436 000 000 hrs     163 814 .7 years

Explanation:

40208000000000 km  / 28000 km/hr  =

The Space shuttle's speed is 28,000 km/hr, and the time it will take to get you there is 1436000000 hours or 163814.7 years.

Although Proxima Centauri cannot be seen normally with eyes, it is one of the most famous stars in the sky. This is because it is a member of the Alpha Centauri star system, which is the nearest stellar system to our sun and is home to three known stars.

Proxima, with a distance of 4.22 light-years from our sun, is thought to be the star in Alpha Centauri that is nearest to our sun of the three. For Proxima, astronomers have so far found two planets. It also produces large solar flares, and a strange radio signal may come from it.

According to the question :

The given distance is 4.3 light-years or,

Distance = 40,208,000,000,000 km

Given speed is 28,000 km/hr.

So the time it will take to get you up there is:  Distance/speed

Time = 40,208,000,000,000 km/28,000 km/hr

Time = 1436000000 hours or,

Time = 163814.7 years

Hence, the time taken to get you there will be 163814.7 years.

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Answer:

30 km/h

Explanation:

V=S:t

speed=length:time

150:5=30

Apply Ohm's Law:

V = I x R

Where:

V = potential difference = 1.8v

I = current = 0.5 A

R = resistance

Isolate R:

R = V/I

R = 1.8 / 0.5 = 3.6 Ohm

Answer:

To calculate the voltage, current, power and energy for an inductor and also to examine the behavior of an inductor under dc conditions.

an inductor is a passive circuit element that stores energy in its magnetic field.

Explanation:

An inductor has been described as a passive electronic component that stores electrical energy in a magnetic form.  It uses a conductor that is wound into a coil to produce DC current, acting as a short circuit when direct current is applied.  When electricity flows into the coil from the left to the right, a current is generated through a magnetic field in the clockwise direction.  It is also called a choke because of its frequency regulation.

We can start by finding the acceleration of the car:a = Δv/Δt = (96.5 km/h)/(2.4 s) = 40.21 m/s^2

Next, we can find the force required to accelerate the car:F = ma = (1961 kg)(40.21 m/s^2) = 78914.81 N

Finally, we can find the power of the car:P = Fv = (78914.81 N)(96.5 km/h) = 2.84 x 10^6 W

Therefore, the power of the car is approximately 2.84 megawatts.

The number of turns determines the strength; whether the core is made of soft or hard magnetic material. Soft iron is more easily magnetized than steel. As a result, using a soft core increases the electromagnet's strength.

The magnetic field is mathematically described as a vector field. This vector field can be directly plotted as a grid of many vectors. Each vector points in the same direction as a compass and has a length proportional to the strength of the magnetic force. This technique is demonstrated by arranging many small compasses in a grid pattern and placing the grid in a magnetic field. The only difference is that a compass does not indicate field strength. Field lines are another way to represent the information contained within a vector field. We remove the grid pattern and connect the vectors with smooth lines. We are free to draw as many lines as we want.

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a) The thermal energy in Joules, W¹ = 45000 Joules

The thermal energy in kWh, W¹ = 0.0125 kWh

b) The electrical energy consumed by this conductor for the same duration = 0.0125 kWh

c) The thermal power = 25 Watts

d) The electrical energy, W² = 180 kJ

The resistance of the ohmic conductor, R = 100Ω

The time taken, t = 30 min

t = 30 x 60 seconds

t = 1800 seconds

The current, I = 0.50 A

a) The thermal energy, W¹ dissipated in the conductor is claculated as:

W¹ = I² x R x t

Substitute I = 0.50, t = 1800, R = 100 into the formula above

W¹ = 0.50² x 100 x 1800

W¹ = 45000 Joules

W¹ = 45 kJ

W¹ = 0.0125 kWh

b) The electrical energy consumed by the conductor for the same duration

According to the principle of energy conservation

The electrical energy consumed by the conductor = Thermal energy dissipated in the conductor

Therefore:

The electrical energy consumed by this conductor for the same duration = 0.0125 kWh

c) The value of the thermal power dissipated in this conductor

The thermal power = The thermal energy / Time

The thermal power = 45000/1800

The thermal power = 25 Watts

d) The electrical energy W², consumed by this conductor, for a period of 30 min, if the value of the intensity I is doubled

If the current intensity is doubled, I = 2(0.50)

I = 1 A

The resistance, R = 100 Ω

The time, t = 30 min = 30 x 60 seconds

t = 1800 seconds

W² = I² x R x t

W² = 1² x 100 x 1800

W² = 1 x 100 x 1800

W² = 180000 Joules

The electrical energy if the value of the intensity is doubled, W² = 180 kJ

The distance between object P1 and its image formed is determined as 36 m.

The distance of the image formed by object P1 is calculated as follows;

In a plane mirror; object distance = image distance

image distance of P1 = 18 m

distance between object and image = 18m + 18 m = 36 m

Thus, the distance between object P1 and its image formed is determined as 36 m.

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The vehicle has a 2000kg mass.

Take a mass's acceleration into account. Use the formula F = m a to determine the force's value. Kilogram-meter/second-squared will be used as the unit of force. The short name for this unit, which is made up of the three basic SI units, is newton.

F= ma

m= F/a

m= 50000/25

m= 2000 kg

According to Newton's Second Law of Motion, acceleration (gaining speed) occurs whenever a force acts on a mass (object). This law of motion is best demonstrated by riding a bicycle. The mass is your bicycle. The force that propels you forward on your bicycle comes from your leg muscles.

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a) The time that the ball is in the air is 0.23 second.

b)  The initial horizontal velocity of the ball is 11.74 m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction.

Vertical height of the point = 1.0 meter.

The horizontal distance travelled by the ball = 2.7 m.

a) The time that the ball is in the air is = √(H/2g)

= √(1.0/2×9.8)

= 0.23 second

b) The initial horizontal velocity of the ball is = 2.7 m/0.23 s

= 11.74 m/s

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During the 200-meter race, Michael Phelps moved at a speed of 1.75 metres per second.

More than any other swimmer in history, he won Olympic medals, world titles, US national titles, and set world records. Phelps has made it a priority to support the growth of swimming at all levels during his career. With a total of 28 medals, he is the most successful and decorated Olympian of all time.

Velocity = Distance / Time

In this case, the distance swum is 200 meters and the time taken is 1 minute and 54 seconds, or 114 seconds.

Velocity = 200 meters / 114 seconds

Velocity = 1.75 meters/second (rounded to two decimal places)

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Answer:

Did you forget to attach the image?

Explanation:

So far, we're not sure that you even HAVE a bulb or any switches.

If you had them, you probably would have included a diagram of the circuit you built with them. THEN we could look at the diagram and answer this question.

Right now, we can't.  We haven't seen such a diagram.