What does Supernova mean?

The light bulb in a circuit will most likely have the most resistance, therefore the correct answer is D.

Resistance is the obstruction of electrons in an electrically conducting material.

The mathematical relation for resistance can be understood with the help of the empirical relation provided by Ohm's law.

V=IR

Generally, the electrical element used for doing some specific work in an electric circuit has the highest resistance, for the given question light bulb has the most resistance.

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Answer:

9.3

Explanatin:

Answer:

4.5

Explanation:

The frequency of the electromagnetic waves that are deflected by 10 degrees by the comb with 2 mm spacing is 857 GHz (gigahertz).

The equation for the angle of deflection is given by:

sin(θ) = mλ/d

where m is the order of the diffraction peak, λ is the wavelength of the electromagnetic wave, and d is the spacing between the comb teeth.

The spacing of the comb teeth is 2 mm, and waves that are deflected by 10 degrees. Assume that order of the diffraction peak is 1.

Frequency, f = c/λ

where c is the speed of light, and λ is the wavelength.

Plugging in the given values, we get:

λ = 2 mm * sin(10 degrees) / 1 = 0.35 mm

f = 3 x 10^8 m/s / (0.35 mm) = 857 GHz

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12. The time taken for the journey is 400 s

13. The time taken for the train is 200 s

14. The time taken is 7 h

15. The time taken for the beetle is 12 s

16. The time taken for the journey is 0.0068 h

The time taken in each case as given by the question can be obtain as follow:

12. The time taken for the journey

Time taken = Distance / Speed

Time taken = 26000 / 65

Time taken = 400 s

13. The time taken for the train

Time taken = Distance / Speed

Time taken = 3200 / 16

Time taken = 200 s

14. The time taken to travel

Time taken = Distance / Speed

Time taken = 672 / 96

Time taken = 7 h

15. The time taken for the beetle

Time taken = Distance / Speed

Time taken = 1.08 / 0.09

Time taken = 12 s

16. The time taken for the journey

Time taken = Distance / Speed

Time taken = 35 / 5147

Time taken = 0.0068 h

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Answer:

Impact Craters.

Explanation:

An impact crater can be defined as a circular depression that is caused by impact on any planet or asteroids or any other celestial body's surface. When smaller body in galaxy impacts these larger bodies, they form a circular depression on it's surface.

This is a major feature found in solid object such as the Moon, Mercury, etc.

Therefore, the feature that a planet does not require is an impact crater. As other features are important to define a planet. Thus correct option is C.

Answer:

milk is raised to a certain level for sometimes and immediately cooled to the lower degree

(a) The initial energy of the mass is 76.485 J.

(b) The compression of the spring in the absence of friction is 21.2 cm.

(c)  The compression of the spring in the presence of friction is 19.4 cm.

The initial energy of the mass is determined as follows;

E = K.E + P.E

E = ¹/₂mv² + mgh

where;

E = ¹/₂mv²  + mg x Lsinθ

P.E = ¹/₂(9.4)(2.5)² +  (9.4)(9.8)(0.87)(sin36)

P.E = 76.485 J

The compression of the spring in the absence of friction is calculated as follows;

Ux = E

¹/₂kx² = 76.485

kx² = 2(76.485)

x² = (2 x 76.485)/k

x = √(2 x 76.485)/k

x = √(2 x 76.485 / 3413.7)

x = 0.212 m

x = 21.2 cm

The compression of the spring in the presence of friction is determined by applying the principle of conservation of energy.

E - Fd = Ux

E - μmgd = ¹/₂kx²

76.11 - (0.27 x 9.4 x 9.8 x 0.48) = ¹/₂(3413)x²

64.17 = 1706.5x²

x² = 0.0376

x = √0.0376

x = 0.194

x = 19.4 cm

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The ball's velocity at half of the maximum height relative to the equilibrium point is approximately 1.727 m/s.

To solve this problem, we make useof the law of conservation of energy. The initial potential energy of the system (when the ball is at its highest point before being released) is equal to the final potential energy (when the ball reaches half of its maximum height above the equilibrium point) plus the final kinetic energy.

Initial potential energy = mgh = 0.15 kg x 9.81 m/s² x 0.18 m = 0.26523 J

At half of the maximum height, the ball has traveled a distance of 0.09 meters above the equilibrium point.

Final potential energy = mgh = 0.15 kg x 9.81 m/s² x 0.09 m = 0.132615 J

To find the final kinetic energy, we can use the fact that the spring potential energy at half of the maximum height is equal to the initial potential energy minus the final potential energy:

Spring potential energy = (1/2)kx² = (1/2)(690 N/m)(0.18 m - 0.09 m)² = 0.008415 J

Final kinetic energy = Initial potential energy - Final potential energy - Spring potential energy

Final kinetic energy = 0.26523 J - 0.132615 J - 0.008415 J = 0.1242 J

Finally, we can use the equation for kinetic energy to find the velocity of the ball at half of the maximum height:

Final kinetic energy = (1/2)mv²

v = \(\sqrt{(2 x Final kinetic energy / m) }\)= \(\sqrt{(2 x 0.1242 J / 0.15 kg)}\) = 1.727 m/s

Therefore, the ball's velocity at half of the maximum height relative to the equilibrium point is approximately 1.727 m/s.

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Given,

The force needed, F=560.0 N

The acceleration produced, a=20 m/s²

From Newton's second law, the force applied to an object is equal to the product of the mass of the object and the acceleration produced due to the applied force.

Thus,

Where m is the mass of the object.

On substituting the known values in the above equation,

Therefore the mass of the object is 28 kg

Answer:

C

Explanation:

I think buh were is the question

The force that is acting on the spheres is obtained as  0.006 N from the calculation that is done here.

We know that the force can be obtained by the use of the Coulomb's law. From the Coulomb's law, we know that the force that acts for the charges on the charges must be an attractive force as we can see and then we can be able able to use the formula;

F = K\(q_{1}\)\(q_{2}\)/r^2

F = force on the object

K = electric constant

\(q_{1}\) and \(q_{2}\) = magnitude of the charges on the object.

Then we have;

F = 9 * 10^9 * 2 × 10^–7 *  3 × 10^–7 /(30 * 10^-2)^2

F = 54 * 10^ -5/0.09

F = 0.006 N

Thus, it is clear that we have an attractive force that would act on the species and the magnitude of the charged spheres  0.006 N as we can see from the calculation here.

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Answer:

A. size and mass

Explanation:

The amount the needle on the meter is deflected A. increases

This phenomenon can be explained by Faraday's law of electromagnetic induction. According to this law, when a magnetic field (created by the bar magnet) passes through a coil of wire, it induces an electric current in the wire. This induced current generates its own magnetic field, which interacts with the magnetic field of the bar magnet.

The deflection of the meter needle is a result of this induced current. When the number of coils of wire is increased, there is a greater number of wire loops for the magnetic field to pass through. This leads to a stronger induction of electric current, resulting in a larger deflection of the meter needle.

By increasing the number of coils, more magnetic flux is linked with the wire, resulting in a higher induced electromotive force (emf) and a greater current. This increased current produces a stronger magnetic field around the wire, leading to a larger deflection on the meter. Therefore, increasing the number of coils of wire enhances the magnetic field interaction, resulting in an increased deflection of the meter needle. Therefore, Option A is correct.

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Answer:

protons: 6

electrons: 6

neutrons: 8

Explanation:

atomic number -> number of protons -> 6

mass number -> number of protons + number of neutrons

    so 14-6 = 8. 8 neutrons

this atom is neutral (net charge is 0), so the number of electrons is the same as the number of protons, which is 6

Answer:

the magnitude of the electric field intensity is 20 N/C

Explanation:

 Given the data in the question;

mass m = 1 micro gram = 1 × 10⁻⁹ kg

time duration t = 10 sec

distance s = 1 m

the charge on the particle q = 10⁻¹² Coulomb

force applied on a charged particle due to electric field E is;

F = Eq  ------ equ 1

where q is the charge on the particle.

Also, force on a particle with mass m  will be;

F = ma  ------ equ

where a is acceleration

so F = ma = Eq

ma = Eq -------- equ 3

using kinetic equation

Distance = 1/2×at²

where a is acceleration and t is the time period

now lets consider that initial velocity is zero (0)

Here;

1 m = 1/2 × a × ( 10 s )²

1 m = a × 50 s²

a = 1 m / 50 s²

a = 0.02 m/s²

so, from equation 3

ma = Eq

E = ma / q

we substitute

E = (1 × 10⁻⁹ kg × 0.02) / 10⁻¹² Coulomb

E = 2 × 10⁻¹¹ / 10⁻¹²

E = 20 N/C

Therefore, the magnitude of the electric field intensity is 20 N/C

A inaccessible object is a dynamic variable on the free store without any pointer pointing to it.

Utilize the sextant's arc to determine the angle. By dividing the object's distance from the point of observation by the tan of the angle you calculated, you may use a scientific calculator to get the object's height.

The measuring of heights and distances that are unreachable is made easier by right-triangle trigonometry. By drawing a right triangle with the unknown height or distance as one of its sides and a known side and angle on the other, it is possible to determine the unknown height or distance.

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Answer:

dynamic variable

= 2(4+6)

= 2×10

= 20

HOPE IT HELPS !!!!!!!!

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Answer:

\(\omega=0.37 [rad/s]\)  

Explanation:

We can use the conservation of the angular momentum.

\(L=mvR\)

\(I\omega=mvR\)

Now the Inertia is I(professor_stool) plus mR², that is the momentum inertia of a hoop about central axis.

So we will have:

\((I_{proffesor - stool}+mR^{2})\omega=mvR\)

Now, we just need to solve it for ω.

\(\omega=\frac{mvR}{I_{proffesor-stool}+mR^{2}}\)

\(\omega=\frac{1.5*2.7*0.4}{4.1+1.5*0.4^{2}}\)      

\(\omega=0.37 [rad/s]\)  

I hope it helps you!

The x-component of a vector are < 106.6, 43.07 >

Depending on the angle we are provided, the x-component of a vector can either be cos or sin. Cos always corresponds to the right triangle's side that contacts the specified angle.

If a vector v with magnitude ||v|| makes an angle θ with the positive x-axis then,

v = ||v|| cos θi + ||v|| sin θj

 =  < ||v|| cos θ , ||v|| sin θ >

Magnitude p = 115 km

Angle = 22°

p = ||p|| < cos θ, sin θ >

p = 115 < cos 22°, sin 22° >

p = 115 < 0.927, 0.3746 >

p = < 106.6, 43.07 >

Therefore,  the x-component of a vector are < 106.6, 43.07 >

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Answer: A) Ball A

Explanation:

Density = m/v where m is mass and v is volume

This means the greater the mass, the greater the density.

Because of Ball A's greater mass it would have the greater density.

The two molecules that best complete the reactants' side of the equation\(CO_2\) + 2\(H_2O\) are \(O_2\) and CO.

The correct answer would be \(O_2\) and CO.

Based on the partial chemical equation provided, \(CO_2\) + 2\(H_2O\), we need to select two molecules that complete the reactants' side of the equation while also considering the conservation of mass. Let's evaluate the given options:

1. \(NaCl_3\): This compound, sodium trichloride, does not contain carbon (C) or oxygen (O) atoms, which are required to balance the equation. Therefore, \(NaCl_3\) is not a suitable choice.

2. \(HS_4\): This compound, hydrogen tetrasulfide, also does not contain carbon (C) or oxygen (O) atoms necessary to balance the equation. Hence, \(HS_4\) is not the correct choice.

3. \(CH_4\): This molecule, methane, consists of one carbon atom (C) and four hydrogen atoms (H). It contains carbon but lacks oxygen atoms required for balancing the equation. Thus, \(CH_4\) does not complete the reactants' side.

4. \(O_2\): Oxygen gas (diatomic oxygen) is represented by\(O_2\). It contains two oxygen atoms, which helps balance the equation since there are two oxygen atoms on the product side (2\(H_2O\)). \(O_2\) is a valid choice for completing the reactants' side.

Considering the conservation of mass, we still need a molecule that contains carbon. Among the given options, CO is the only molecule that consists of one carbon atom (C) and one oxygen atom (O). By adding CO to the reactants' side, we balance both carbon and oxygen atoms in the equation.

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Answer:

A. 36.6667 per second

B. 58.6667 per second

C.102.667 per second

In order to determine which of the two solutions of salt water is more concentrated, we need to first understand what concentration means and how it is measured. Concentration refers to the amount of solute dissolved in a given amount of solvent. It is typically measured in units of mass per volume, such as grams per liter (g/L) or milligrams per milliliter (mg/mL). so The second solution is more concentrated

When comparing the concentration of two solutions, the one with a higher concentration has more solute dissolved in the same amount of solvent. Therefore, in the picture provided, we can determine which solution is more concentrated by looking at the relative amounts of solute in each solution.If the solutions have the same concentration, then they must have the same amount of solute dissolved in the same amount of solvent. From the picture, we can see that both solutions are in the same size container and have the same amount of solvent (water) in them. Therefore, we can conclude that they have the same concentration of salt.The amount of solute dissolved in a solution can be increased by either adding more solute or by reducing the amount of solvent. If we were to add more salt to one of the solutions, we would increase the concentration of that solution. Alternatively, if we were to evaporate some of the water from one of the solutions, we would reduce the amount of solvent and increase the concentration of that solution.

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The frictional force may have a magnitude that is equal to or less than sn.

Static denotes being still. Static friction is the friction that exists between two surfaces that are in contact when there is no relative motion between them. It is a force that self-adjusts.

The frictional force that exists between surfaces while they are at rest in relation to one another is known as static friction. When a tiny amount of force is applied, the static force's magnitude is identical in the other direction.

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Answer:

Explanation:

Gravity

The pressure exerted by a rectangular block on the ground is 8 Pascal (Pa) when its weight is 320 N and its dimensions are 4 meters by 10 meters. The greatest pressure occurs when the block is vertically placed at 20 Pa, while the least pressure occurs when it is horizontally placed at 8 Pa.

To calculate the pressure exerted by the rectangular block on the ground, we need to consider the formula for pressure:

Pressure = Force / Area

Given that the weight of the block is 320 N and the dimensions of the block are 4 meters by 10 meters, we can calculate the area of the block in contact with the ground. In this case, it is the length multiplied by the width of the block.

Area = length * width

Area = 4 meters * 10 meters

Area = 40 square meters

Now, we can calculate the pressure exerted by the block on the ground:

Pressure = 320 N / 40 square meters

Pressure = 8 N/m^2 (Pascal)

Therefore, the pressure exerted by the rectangular block on the ground is 8 Pascal (Pa).

To determine the greatest pressure and the least pressure that can be exerted on the ground, we need to consider the orientation of the block.

The greatest pressure occurs when the block is placed vertically on one of its smallest faces. In this case, the entire weight of the block (320 N) is concentrated on a smaller area.

The area in contact with the ground is given by the length multiplied by the width of the smallest face.

Area = 4 meters * 4 meters = 16 square meters

Greatest Pressure = 320 N / 16 square meters = 20 \(N/m^2\)(Pascal)

The least pressure occurs when the block is placed horizontally on one of its largest faces. In this case, the weight of the block is distributed over a larger area.

The area in contact with the ground is given by the length multiplied by the width of the largest face.

Area = 4 meters * 10 meters = 40 square meters

Least Pressure = 320 N / 40 square meters = 8 \(N/m^2\)(Pascal)

Therefore, the greatest pressure that can be exerted on the ground is 20 Pascal (Pa), and the least pressure is 8 Pascal (Pa).

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Answer:

Carry energy and momentum ... 10€. Frequency (Hz). Visible Light not to scale). Viclei | Blue Green | Yellow ... An absorbed photon can have an effect on electrons in an atom: ... To convert between eV's and Joules use the conversion (1eV = 1.6x10-19), ... h. 6.63 x 16 34 = 723 x 10Hz. 350. The energy of a photon varies.

Explanation:

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