What does the 2 in mgcl2 indicate?

Answer:

insulator

Explanation:

Answer:

personally I'd say C by do not know if that is the exact answer

If an electron has a kinetic energy of 6.37 ev, then the wavelength of the electron is 9.82 nm. The wavelength of the photon is 1.956 nm.

(a) To find the wavelength of an electron using kinetic energy, we use the de Broglie equation as follows: λ = h / p

where λ = wavelength

h = Planck's constant = 6.626 x 10^-34 J s

E = kinetic energy of the electron

p = momentum of the electron = sqrt(2mE) where m = mass of the electron = 9.11 x 10^-31 kg

Given: E = 6.37 eV = 6.37 x 1.6 x 10^-19 J = 1.0192 x 10^-18 J

Using the above equations, we get: p = sqrt(2 x 9.11 x 10^-31 kg x 1.0192 x 10^-18 J) = 6.737 x 10^-20 kg m/sλ = 6.626 x 10^-34 J s / 6.737 x 10^-20 kg m/s = 9.82 nm

Therefore, the wavelength of the electron is 9.82 nm.

(b) To find the wavelength of a photon using energy, we use the equation: E = hc / λ

where E = energy of the photon

h = Planck's constant = 6.626 x 10^-34 J s

λ = wavelength

c = speed of light = 3 x 10^8 m/s

Given: E = 6.37 eV = 6.37 x 1.6 x 10^-19 J = 1.0192 x 10^-18 J

Using the above equation, we get:

λ = hc / E = 6.626 x 10^-34 J s x 3 x 10^8 m/s / 1.0192 x 10^-18 J = 1.956 nm

Therefore, the wavelength of the photon is 1.956 nm.

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Answer:

f

Explanation:

The conservation of angular momentum, because as her arms move by, her overall rotational indolence is lowered, thus adding her angular speed. This principle explains the increase in speed in the given question.

Angular momentum is defined as the property of any rotating object given by moment of indolence times angular haste. It's the property of a rotating body given by the product of the moment of indolence and the angular haste of the rotating object.

Conservation of angular momentum is a physical property of a spinning system similar that its spin remains constant unless it's acted upon by an external necklace; put another way, the speed of gyration is constant as long as net necklace is zero.

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Answer:1.81

(a) Explanation:the turn ratio= input voltage÷output voltage.

400÷220=1.81.

Don't know how to solve b part...

The types of work that will be present for all open systems are Shaft work and Flow work.

For open systems, the following types of work can be present:

Shaft work: Shaft work refers to the work done by or on a system due to rotational motion. It involves the transfer of energy through a rotating shaft. This type of work can be present in open systems depending on the specific application or machinery involved.

Flow work: Flow work, also known as flow energy or PV work, is the work done by or on a fluid as it flows into or out of a system. It accounts for the work associated with the pressure-volume interaction of the fluid. Flow work is a characteristic type of work for open systems since they involve the exchange of mass and energy with their surroundings through fluid flow.

On the other hand, the following types of work are not necessarily present for all open systems:

Stirring work: Stirring work refers to the work done by stirring or mixing devices in a system. This type of work is more relevant for closed systems where the internal components are mixed or agitated. Open systems may not necessarily have explicit stirring work unless there are additional mixing mechanisms involved.

Moving boundary work: Moving boundary work, also known as expansion or compression work, is the work done by or on a system as the system's boundaries move due to volume changes. This type of work is more applicable to closed systems where there are significant changes in volume. Open systems typically involve continuous flow processes, and the concept of moving boundaries may not be applicable in the same sense.

Therefore, the types of work that will be present for all open systems are shaft work and flow work.

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Troposphere, stratosphere, mesosphere, thermosphere and exosphere.

Earth's atmosphere has five major layers.

From lowest to highest, layers are the troposphere, stratosphere, mesosphere, thermosphere and exosphere.

a) What are the conditions in the troposphere?

The atmospheric temperature descends upward with a slope of ~10 K km−1 for dry air and ~7 K km−1 for wet air in troposphere.

The temperature of troposphere decreases with an increase in height.

B) What sort of temperatures would she experience in the stratosphere? What other layer is found within the stratosphere?

The temperature in the stratosphere ranges from- 60° F at the troposphere boundary to -5°F at the top.

The temperature increase is due to the ozone layer that absorbs ultraviolet light from solar radiation.

C)What sort of temperatures would she experience in the mesosphere?

The temperature in the mesosphere ranges from -2.5°C to -90°C

The temperature decreases because of a decrease in the absorption of penetrating solar radiation.

The atmosphere gets cooler with an increase in altitude because an increase in distance from the Earth's surface.

D)What sort of temperatures would she experience in the thermosphere? What other layer is found within the thermosphere?

4,500°F is the temperature of thermosphere.

Temperatures climb sharply in the lower thermosphere , then level off and hold fairly steady with increasing altitude above that height.

Temperatures in the upper thermosphere can range from about 500° C (932° F) to 2,000° C (3,632° F) or higher.

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Answer:

acceleration = -1.2 m/s^2

Explanation:

We can use the equation of motion for constant acceleration to solve this problem. When the crate slides along the floor, there is a force of friction acting on it, which opposes its motion. The force of friction can be found using the following equation:

force of friction = mass x acceleration

We can use the kinematic equation to find the acceleration of the crate:    

velocity = initial velocity + acceleration x time

Rearranging this equation, we get:     acceleration = (velocity - initial velocity) / time

Plugging in the values we have:     acceleration = (0 m/s - 12 m/s) / 10 s

Simplifying, we get:   acceleration = -1.2 m/s^2

The elastic potential energy of a spring is the product of one-half of its spring constant and the square of its deformation.

The potential energy of the spring is defined as the potential energy stored as a result of the change in the shape of a particular elastic object or a spring.

The energy is stored before the force is removed, and the spring comes back to its original shape. It does work in the process. The deformation could involve compressing, stretching, or twisting the object.

It is calculated as the work done in stretching the spring, and it depends on the spring constant k, and the distance stretched.

The potential energy formula of a spring is given as

P.E = ½ k x2

Where,

k = the spring constant

x = the spring displacement

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Answer:

Dietary carbohydrates provide the body with energy for tough workouts and replenish energy stores in muscles in the form of glycogen.

Explanation:

A component that is used on the higher temperature evaporators to prevent their pressures from dropping below the desired setting is known as temperature evaporators.

A refrigerant controller is employed on the higher-temperature evaporators to keep their pressures from falling below the target pressure. The refrigerant controller has a temperature probe that senses the evaporator's temperature and adjusts a mechanical valve's opening to maintain the desired pressure in the evaporator.

The valve is connected to the controller by a tube, which transmits the controller's pressure signal to the valve.  The evaporator pressure controls regulate refrigerant flow into the evaporator and keep the evaporator pressure constant. When refrigeration systems have many evaporators operating at various temperatures, various evaporator pressure controllers will keep the evaporator pressure constant. To keep the evaporator pressure at the proper level, the controller injects more refrigerant or allows less to enter.

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Answer:

100 Nm and 25Nm/s.

Explanation:

Given the following data;

Force = 25N

Distance = 4m

Time = 5secs

To find the workdone;

Workdone = force * distance

Substituting into the equation, we have;

Workdone = 25*4

Workdone = 100 Nm

To find the power consumed;

Power = workdone/time

Substituting into the equation, we have;

Power = 100/4

Power = 25Nm/s

The work done on the box is 100 Nm, and the power is 25 Nm/s.

(A) The image you see of yourself in the shiny tablespoon is inverted.

(B) The image you see of yourself in the shiny tablespoon is reduced.

(C) The image you see of yourself in the shiny tablespoon is virtual.

A) When you look at the front side of the spoon, the light rays reflecting off your face or any other object get reflected by the curved surface of the spoon. This reflection follows the laws of reflection, resulting in an inverted image. Therefore, the image you see of yourself in the spoon is inverted.

B)  In this case, the shiny tablespoon acts as a concave mirror. Concave mirrors can produce reduced images depending on the position of the object relative to the mirror's focal point. When the object is held at arm's length, the image formed in the spoon is smaller in size compared to the actual object. Hence, the image you see of yourself in the spoon is reduced.

C) A virtual image is formed when the light rays do not physically converge at the location of the image. In the case of a spoon, the reflected rays from the curved surface do not intersect to form a real image that can be projected onto a screen. Instead, your eyes perceive the apparent image formed by the reflected rays, which is known as a virtual image. Therefore, the image you see of yourself in the spoon is virtual.

Option (A) inverted, (B) reduced, and (C) virtual are the correct answers.

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The statement Capacitors in series share the same charge and capacitors in parallel share the same voltage is True.

Capacitors are electrical components that store energy in an electric field. When capacitors are connected in series, the charge is the same on all the capacitors. This is because there is no pathway for current to flow between the capacitors, and thus the charges on the plates of each capacitor are equal.

When capacitors are connected in parallel, they share the same voltage across them. This is because the voltage applied across each capacitor is the same, and thus the charge on each plate of the capacitor is the same. This property of capacitors is fundamental to understanding how they are used in electrical circuits.

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If a planet of 10 times the mass of Earth were orbiting the Sun at the same distance as Earth (1 AU), the gravitational force on this planet due to the Sun would be 10 times the gravitational force on Earth due to the Sun.

This is because the gravitational force between two objects depends on their masses and the distance between them.

Since the mass of the planet is 10 times that of Earth, the gravitational force on it would also be 10 times that of Earth.

Explanation: The force of gravity between two objects depends on their masses and the distance between them.

The force of gravity is given by the equation:

F = \(Gm1m2 / r2\)

Where F is the force of gravity, m1 and m2 are the masses of the two objects, r is the distance between them, and G is the gravitational constant\(Gm1m2 / r2\)

If a planet of 10 times the mass of Earth were orbiting the Sun at the same distance as Earth (1 AU), the mass of the planet would be 10 times the mass of Earth (m2 = 10mE), and the distance between t\(m2 = 10mE)\)he planet and the Sun would be the same as Earth's distance (r = 1 AU).

Therefore, the force of gravity on the planet would be:

F =\(Gm1m2 / r2\)

F = \((6.67 × 10-11 N m2/kg2)(mE)(10mE) / (1 AU)2\)

F = 6.67 × 10-11 N m2/kg2 × 10mE2 / (1.5 × 1011 m)2

F = 3.52 × 1022 N

This is 10 times the gravitational force on Earth due to the Sun, which is 3.52 × 1021 N.

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Answer:

velocity term

Explanation:

Answer:velocity term

Explanation:

Answer:-00=;op

Explanation:poop

Answer:

450 hz X 4 = 1800

Explanation: Speed =

Wavelength (4) X frequency (450)

Im not 100% sure though

An ideal bandpass filter with unit gain and a bandwidth of 200 Hz is applied to the input signal g(t) = 8 cos(400πt) cos(200,000πt) + 18 cos(200,000nt). The center frequency of the filter is 100,200 Hz. We can sketch the amplitude spectrum of the signal at the output of the filter using the following steps:

Step 1: Determine the Fourier transform of the input signal g(t)The Fourier transform of g(t) is given by: G(ω) = π[δ(ω + 2π × 200,000) + δ(ω - 2π × 200,000)] + π/2[δ(ω + 2π × 200) + δ(ω - 2π × 200)]

Step 2: Determine the transfer function of the bandpass filter

The transfer function of the ideal bandpass filter with unit gain and a bandwidth of 200 Hz centered at 100,200 Hz is given by: H(ω) = {1 for |ω - 2π × 100,200| < π × 100, and 0 otherwise}

Step 3: Multiply the Fourier transform of the input signal by the transfer function of the filter

The output of the filter is given by:

Y(ω) = G(ω)H(ω)The product of the Fourier transform of the input signal and the transfer function of the filter is shown in the figure below.

The given signal is a combination of two cosines, where the first cosine has a frequency of 400π radians/second and the second cosine has a frequency of 200,000π radians/second.

The output of the filter is a bandpass signal with a center frequency of 100,200 Hz and a bandwidth of 200 Hz. The amplitude spectrum of the output signal is zero outside the bandpass region and is equal to the product of the amplitude spectrum of the input signal and the frequency response of the filter within the passband region.

The amplitude spectrum of the output signal is shown in the figure below:

Therefore, the amplitude spectrum of the signal at the output of the filter is a bandpass signal with a center frequency of 100,200 Hz and a bandwidth of 200 Hz. The amplitude of the signal within the passband region is given by the product of the amplitude of the input signal and the frequency response of the filter within the passband region.

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Standard conditions refer to a specific set of temperature, concentration, and pressure values, which are commonly used in scientific experiments and calculations to provide a consistent basis for comparison.

In most thermodynamic calculations, standard conditions are defined as a temperature of 298.15 K (25°C), a concentration of 1 mol/L (1 M) for solutions, and a pressure of 1 atm (101.325 kPa) for gases. These conditions are important because they serve as a reference point, allowing scientists to easily compare the properties and behavior of various substances under the same set of conditions.

The use of standard conditions simplifies calculations and ensures that the results are consistent across different studies. By providing a uniform reference point, researchers can focus on the effects of specific variables, such as the type of substance, its structure, or its interactions with other substances, without having to account for variations in temperature, concentration, or pressure.

To summarize, standard conditions for most thermodynamic calculations involve a temperature of 298.15 K (25°C), a concentration of 1 mol/L (1 M) for solutions, and a pressure of 1 atm (101.325 kPa) for gases. These conditions provide a consistent basis for comparison, enabling scientists to examine the properties and behavior of various substances under the same set of conditions.

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Answer:

Explanation:

Angle of refraction is the angle made by refracted ray with the normal at the point of incidence . In this figure , refracted ray has been shown by line having arrow-head . Normal has been shown by broken line .

We observe that in figure D , angle made by refracted ray with normal is greatest . So figure D is the answer.

The  image where the angle of refraction is the greatest is the image D

The angle of refraction is the angle that the refracted ray made with the x-axis.

The higher the angle between the refracted ray and the x-axis, the higher the angle of refraction and vice versa.

From the given diagram, we can see that the  image where the angle of refraction is the greatest is the image D

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Answer:

C. 3m/s^2

Explanation:

The maximum compression of the bumper is approximately 0.065 m (or 6.5 cm).

To find the maximum compression of the bumper, we will use the principle of conservation of energy. The initial kinetic energy of the car will be converted into potential energy stored in the compressed bumper.

Given:

Mass of the car (m) = 1300 kg

Spring stiffness constant (k) = 550 kN/m

Initial speed of the car (v) = 2.4 m/s

We'll assume that the car comes to a complete stop after the collision with the wall. At this point, all the kinetic energy of the car is converted into potential energy stored in the compressed bumper.

The kinetic energy (KE) of the car before the collision is given by:

KE = (1/2) * m * v^2

Substituting the given values:

KE = (1/2) * 1300 kg * (2.4 m/s)^2

= 7488 J

Since the maximum potential energy (PE) stored in the compressed bumper is equal to the initial kinetic energy, we can write:

PE = KE

The potential energy of a compressed spring is given by:

PE = (1/2) * k * x^2

Where x is the maximum compression of the bumper.

Equating the potential energy and the kinetic energy:

(1/2) * k * x^2 = KE

(1/2) * 550 kN/m * x^2 = 7488 J

Converting the spring stiffness constant from kN/m to N/m:

550 kN/m = 550,000 N/m

Simplifying the equation:

(1/2) * 550,000 N/m * x^2 = 7488 J

275,000 N/m * x^2 = 7488 J

Solving for x:

x^2 = (7488 J) / (275,000 N/m)

x^2 = 0.0272 m^2

x ≈ 0.165 m

So, the maximum compression of the bumper is approximately 0.165 m (or 16.5 cm).

The maximum compression of the energy-absorbing car bumper, given a spring stiffness constant of 550 kN/m, when a car with a mass of 1300 kg collides with a wall at a speed of 2.4 m/s, is approximately 0.165 m (or 16.5 cm).
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The sunken lead displaces a volume of water equal to the lead's own volume. The floating lead displaces a volume of water whose weight equals the lead's weight.

What is Mass?
It is the most fundamental characteristic of matter and one of the fundamental quantities in physics. Mass is a term used to describe how much matter is there in a body. The kilograms is the SI unit of mass (kg).

A body's mass does not alter at any point in time. only in rare instances where a significant quantity of energy is supplied to or taken away from a body. A nuclear reaction, for instance, results in the mass of the substance being reduced as a very little amount of matter is transformed into a very large amount of energy.

This law provides a numerical description of how a force might alter a body's motion.

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Answer:

B

Explanation:

Got it right

Answer:

B. X: Releases energy to the photosphere

Y: Takes longer for photons to move through

Explanation:

Right on ED2021, goodluck!

Option D is the correct answer.

To demonstrate the hypothesis, the control experiment must be the nail with 8 coils.

A control experiment is the experiment that remains unchanged or unaffected by other variables.

A controlled experiment is simply an experiment in which all factors are held constant except for one: the independent variable.

For this given experiment, the number of paper clips lifted depends on the number of coils around the wire and voltage applied.

To demonstrate that for every 8 additional coils, you will be able to pick up two additional paper clips, we must have a control experiment, that is an experiment with which we will compare the out come.

This control experiment must be the nail with 8 coils.

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The average power developed by the boy during the climb is approximately 29.4 W.

In physics, the amount of energy transferred or converted per unit time is called power.

total height = number of steps x height of each step

total height = 30 x 0.15 m = 4.5 m

Given, time = 60 s

As power = work done / time

work done = force x distance

force = mass x gravity

mass is boy's mass (40 kg) and gravity is acceleration due to gravity (9.81 m/s²).

force = 40 kg x 9.81 m/s² = 392.4 N

The distance that the boy moves is equal to the total height that he has climbed: distance = total height = 4.5 m

work done = force x distance

work done = 392.4 N x 4.5 m = 1765.8 J

power = work done / time

power = 1765.8 J / 60 s

power ≈ 29.4 W

Therefore, the average power developed by the boy during the climb is approximately 29.4 W.

As for the anomalous behavior of water, water has a higher boiling point and melting point as compared to other substances with similar molecular weight. This is due to the strong hydrogen bonding between water molecules, which requires more energy to break the bonds and change the state of water from solid to liquid to gas.

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Answer: I don't know

Explanation: