Answer:
the answer to that is letter C. (x+7)(x-7)
Pascal stated that pressure is transmitted through a friction-less closed hydraulic system without: O change in temperature O loss O change in heat energy O change in velocity
According to Pascal's principle, pressure is transmitted through a friction-less closed hydraulic system without a change in velocity. This principle states that the pressure applied to a fluid in such a system is uniformly transmitted throughout the fluid without causing a change in the velocity of the fluid particles.
Pascal's principle, formulated by Blaise Pascal, describes the behavior of pressure in a closed hydraulic system. According to Pascal's principle, pressure applied to a fluid in a confined space is transmitted uniformly in all directions and to all parts of the fluid.
In a friction-less closed hydraulic system, such as a hydraulic jack or brake system, the pressure applied to one part of the fluid is transmitted undiminished to other parts of the system. This means that the pressure remains the same throughout the system.
The statement that there is no change in velocity refers to the fact that the fluid particles in the hydraulic system do not experience a change in their speed or velocity. The pressure transmitted through the fluid does not cause the fluid particles to accelerate or change their velocity.
Other options listed in the question:
- Change in temperature: Pascal's principle does not address changes in temperature. It specifically focuses on the transmission of pressure in a closed hydraulic system.
- Loss: Pascal's principle assumes that there are no losses in the transmission of pressure within a friction-less closed hydraulic system.
- Change in heat energy: Pascal's principle does not involve the transfer of heat energy. It solely deals with the transmission of pressure in a closed hydraulic system.
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show that the vectors ⎡⎣⎢121⎤⎦⎥, ⎡⎣⎢131⎤⎦⎥, ⎡⎣⎢141⎤⎦⎥ do not span r3 by giving a vector not in their span.
To show that the vectors ⎡⎣⎢121⎤⎦⎥, ⎡⎣⎢131⎤⎦⎥, ⎡⎣⎢141⎤⎦⎥ do not span R3, we need to find a vector that cannot be expressed as a linear combination of these vectors.
One way to do this is to set up a system of equations and see if there is a solution for the coefficients. For example, let's try to express the vector ⎡⎣⎢010⎤⎦⎥ as a linear combination of the given vectors:
a⎡⎣⎢121⎤⎦⎥ + b⎡⎣⎢131⎤⎦⎥ + c⎡⎣⎢141⎤⎦⎥ = ⎡⎣⎢010⎤⎦⎥
This gives us the following system of equations:
a + b + c = 0
2a + 3b + 4c = 1
a + b + c = 0
We can see that the first and third equations are the same, so we only have two independent equations. This means that we cannot solve for all three coefficients, and therefore the vector ⎡⎣⎢010⎤⎦⎥ cannot be expressed as a linear combination of the given vectors.
Therefore, the vectors ⎡⎣⎢121⎤⎦⎥, ⎡⎣⎢131⎤⎦⎥, ⎡⎣⎢141⎤⎦⎥ do not span R3, as there is at least one vector (⎡⎣⎢010⎤⎦⎥) that is not in their span.
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Please find the area of the square I forgot how to do this please help :(
Answer:
85/2 or 42.5 ft²
Step-by-step explanation:
A = l x w
A = 7.5 (5 2/3)
= 15/2 (17/3)
= 255/6
= 85/2 ft² or 42.5 ft²
Answer:
Step-by-step explanation:
What is 3,0000+2,63754
Answer:
5.63754
Step-by-step explanation:
Hope this helped if it did please mark brainliest
Who can do this ? who do this question; i will make him brightlist and follow him and vote him.
Divide 45 by the difference of 13 and 9 and subtract it from the sum of the product of 3 and 7 and 4 and 2.
Answer:
18.1538461538
Step-by-step explanation:
Do the equation down here
45 ÷ (13 ÷ 9) - (3 × 7) + (4 × 2)
Use the order of operations to answer
Remember PEMDAS.
Answer:
45 ÷ (13 - 9) - (3 * 7) +( 4 * 2) =
Step-by-step explanation:
exact form:
- \(-\frac{7}{4}\)
decimal form
18.1538461538
Factor the expression:
12x - 60
Answer: 12(x-5)
Step-by-step explanation:
Which type of mathematical problem is too complex for a classical computer to solve efficiently?
Calculating the circumference of a circle based on the circle's diameter.
What kind of problems can a quantum computer solve?
Yet another difficult area that quantum computers cater to is that of solving difficult combinatorics problems. The algorithms within quantum computing aim at solving difficult combinatorics problems in graph theory, number theory, and statistics.10 Difficult Problems Quantum Computers can Solve Easily-
Quantum encryption. Simulation of quantum systems. ab initio calculations.Solving difficult combinatorics problems.Supply chain logistics. Optimization.Finance. Drug development.Learn more about quantum computer
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The complete question is -
Which type of mathematical problem is too complex for a classical computer to solve efficiently?
a. converting an irregular fraction to an approximate decimal value
b. multiplying two numbers that both have a large number of digits
c. finding two prime factors that result in a specific value when multiplied
d. calculating the circumference of a circle based on the circle's diameter
To get the echo of a positive integer, we write it twice in a row without a space. For example,
the echo of 2023 is 20232023. Is there a positive integer whose echo is a perfect square? If
so, how many such positive integers can you find? If not, explain why not.
Answer: Yes, but it's extremely hard to find
Step-by-step explanation:
The echo number 20222022202220222022 is the perfect square of 4496890281.
What echo number is a perfect square
An echo number has a perfect square if its square root is also a natural number. After some iterations we found that echo number 20222022202220222022 is a perfect square:
The echo number 20222022202220222022 is the perfect square of 4496890281.
Functions that repeat over time are common in everyday life. The English language has many words that stand for common periods of time. State the period of time from which each term derives.
annual
There are many words in the English language that signifies a certain period of time which are also commonly used in Mathematics like century, decade, etc. One of the term is "Annual" which signifies a time period of one(1) year.
The term Annual refers to any event or something that occurs once a year. For example, if an event occurs once a year then it is known as an Annual event or the annual interest rate is the interest rate that is charged on a loan amount for a time period of one year. Precisely, we can say the time period of the Annual term is 12 months.
In various contexts, the Annual term can be used for example annual events, annual reports, annual interest rates, or annual payments.
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What is the angle between the vectors − 2i 3j k and i 2j − 4k?
The angle between the vectors can be found using the dot product. The formula is θ= |A| =√(x12 + y12 + z12) The angle between the vectors -2i + 3j + k and i + 2j - 4k is approximately 137.8 degrees.
v1 • v2 = (-2i + 3j + k) • (i + 2j - 4k)
= -2 - 6 + 1 = -7
|v1| = \(\sqrt{((-2)^2 + 3^2 + 1^2)}\)
=\(\sqrt{(4 + 9 + 1)}\)
=\(\sqrt{14}\)
|v2| = \(\sqrt{((1)^2 + 2^2 + (-4)^2)}\)
= \(\sqrt{(1 + 4 + 16) }\)
= (\(\sqrt{21}\)
θ= |A| (-7/\(\sqrt{14}\)\(\sqrt{21}\))
= |A| (-7/21*14)
= |A|(-7/294)
= 137.8 degrees
The angle between two vectors can be found using the dot product formula. This formula isθ= |A| =√(x12 + y12 + z12). In the case of the vectors -2i + 3j + k and i + 2j - 4k, this formula can be used to find the angle between them. The dot product of the two vectors is -2 - 6 + 1 = -7. The magnitude of the first vector, |v1|, can be found using the Pythagorean theorem, which is
\(\sqrt{((-2)^2 + 3^2 + 1^2)}\)
= \(\sqrt{(4 + 9 + 1)}\)
= \(\sqrt{14}\).
The magnitude of the second vector, |v2|, can be found using the Pythagorean theorem, which is
\(\sqrt{((1)^2 + 2^2 + (-4)^2)}\)
= \(\sqrt{(1 + 4 + 16)}\)
= \(\sqrt{21}\)
Once the dot product and magnitudes are known, the angle between the two vectors can be found using the formula .Therefore, the angle between the two vectors is approximately 137.8 degrees.
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What is the angle of rotation from figure A to figure A? Assume that the center of rotation is the origin.
A. 360° clockwise
B. 270° clockwise
C. 180° clockwise
D. 90° clockwise
Answer:
the answer is C. 180°clockwise
find domain and range
Domain — x > 1 (I notice opened dot.)
Range — y > 1
The domain and range of the graph is:
Domain: [1, ∞) or {x | x ≥ 1}
Range: [1, ∞) or {y | y ≥ 1}
Here, we have,
For the given graph with a curve starting from the point (1, 1) and increasing continuously in the positive direction only, the domain and range can be determined as follows:
Domain: Since the curve starts from the point (1, 1) and increases continuously in the positive direction only, the domain includes all real numbers greater than or equal to 1.
Therefore, the domain is [1, ∞) or {x | x ≥ 1}.
Range: The curve increases continuously in the positive direction, indicating that the y-values also increase.
Since there are no restrictions or maximum values mentioned, the range is all real numbers greater than or equal to 1.
Therefore, the range is [1, ∞) or {y | y ≥ 1}.
In summary:
Domain: [1, ∞) or {x | x ≥ 1}
Range: [1, ∞) or {y | y ≥ 1}
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pls I need it like now
1. for What values of
the Constant k
does the equation
\((k - 1)x - k {x}^{2} - k\)
have equal roots?
2. find the Positive value of "C" if the
expression
\((2c + 3)y}^{2} - 6y + 4 - c\)
is a perfect
Square
Answer:
Quadratic equation has equal roots
We know that quadratic equation has two equal roots only when the value of discriminant is equal to zero. We know that two roots of quadratic equation are equal only if discriminant is equal to zero.
Step-by-step explanation:
144
So, c must be 144 to make the trinomial a perfect square.
Problem 1
The discriminant formula is
d = b^2 - 4ac
from the original expression given to us, it is in the form ax^2+bx+c with
a = k-1
b = -k
c = -k
So we have a discriminant of
d = b^2 - 4ac
d = (-k)^2 - 4(k-1)(-k)
d = k^2 + 4k(k-1)
d = k^2 + 4k^2 - 4k
d = 5k^2 - 4k
Set this equal to 0 and solve for k. We set d equal to zero because a discriminant of 0 means we have two repeated roots.
d = 0
5k^2 - 4k = 0
k(5k - 4) = 0
k = 0 or 5k-4 = 0
k = 0 or 5k = 4
k = 0 or k = 4/5
There are two possible answers here: k = 0 or k = 4/5======================================================
Problem 2
For this problem, I'll replace every c with k
Also, I'll replace every y with x
The expression turns into (2k+3)x^2-6x+4-k
We'll use the same idea as problem 1. Match it with ax^2+bx+c to find
a = 2k+3
b = -6
c = 4-k
the discriminant is
d = b^2 - 4ac
d = (-6)^2 - 4(2k+3)(4-k)
d = 36 - 4(-2k^2 + 5k + 12)
d = 36 + 8k^2 - 20k - 48
d = 8k^2 - 20k - 12
Set this equal to zero and solve for k
8k^2 - 20k - 12 = 0
4(2k^2 - 5k - 3) = 0
2k^2 - 5k - 3 = 0
2k^2 - 6k + k - 3 = 0
(2k^2-6k) + (k-3) = 0
2k(k-3) + 1(k-3) = 0
(2k+1)(k-3) = 0
2k+1 = 0 or k-3 = 0
2k = -1 or k = 3
k = -1/2 or k = 3
We ignore k = -1/2 as the instructions state the value of c (which I changed to k) is positive.
Answer: 3get these all right and ill give you a bonus of 75-100points
Answer:
1: -6m,
2: 10.3-12m,
3: 28a-7,
4: 5/8h+7
Step-by-step explanation:
so, a helpful thing with these, is to add like terms. with #4, we see that the letter m is with both of the numbers, and since we are adding a bigger negative to a positive, the answer will be a negative with the number. for 6, 2 numbers have an x, and 2 do not. so we add or subtract the like pairs, as in the ones with the letters, and then a separate one for the one with no letters. for the last one, you always want to have a "common denominator" which is the number on the bottom. because 8 is already on the bottom, and 4 is divisible by 8 by 2, we inversely multiply the top and bottom numbers for the "3/4" and would get "6/8" to match the bottom denominator for "1/8" hope this helps
find the length of the graph of f(x)=ln(4sec(x)) for 0≤x≤π3.
To find the length of the graph of f(x)=ln(4sec(x)) for 0≤x≤π/3, we first need to compute the derivative of the function.
f(x) = ln(4sec(x))
f'(x) = (1/sec(x)) * (4sec(x)) * tan(x) = 4tan(x)
Next, we use the arc length formula:
L = ∫ [a,b] √[1 + (f'(x))^2] dx
Substituting in the values, we get:
L = ∫ [0,π/3] √[1 + (4tan(x))^2] dx
We can simplify this by using the identity 1 + tan^2(x) = sec^2(x):
L = ∫ [0,π/3] √[1 + (4tan(x))^2] dx
= ∫ [0,π/3] √[1 + 16tan^2(x)] dx
= ∫ [0,π/3] √[sec^2(x) + 16] dx
= ∫ [0,π/3] √[(1 + 15cos^2(x))] dx
= ∫ [0,π/3] √15cos^2(x) + 1 dx
Using the substitution u = cos(x), we get:
L = ∫ [0,1] √(15u^2 + 1) du
This can be solved using trigonometric substitution, but the details are beyond the scope of this answer. The final result is:
L = 4/3 * √(15) * sinh^(-1)(√15/4) - √15/2
Therefore, the length of the graph of f(x)=ln(4sec(x)) for 0≤x≤π/3 is approximately 3.195 units.
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Solve for X
Solve for X
Answer:
x=9*
Step-by-step explanation:
48*+(5x-3)*+90*=180* (its is 180* because it is a line)
5x+135*=180* (combine like terms)
-135* -135* (subtract 135*)
5x=45* (divide by 5)
x=9*
dont mind the asterisks they are my degree signs
hope this helps
brainliest?
What is 2 1/2+1 1/3x<6? Please hellllppppp!!!!
Which expressions are equivalent to 4(x+3)-10+6x
Answer:
4(x+3)-10+6x
4x+12-10+6x
10x+2
hope this helps
have a good day :)
Step-by-step explanation:
What are the solutions of this quadratic equation? X^2+10=0
Answer:
+3.16i, -3.16i
Step-by-step explanation:
This has complex roots.
ax² + bx + c = 0
a = 1
b = 0
c = 10
Roots: +3.16i, -3.16i
How do you sum a column in Excel on a Mac?
To see the steps of sum a column in Excel on a Mac.
Now, According to the question:
1. Click the first empty cell below a column of numbers.
2. Do one of the following: Excel 2016 for Mac: : On the Home tab, click AutoSum. Excel for Mac 2011: On the Standard toolbar, click AutoSum. ...
3. Press RETURN .
How do you sum cells on a Mac?
Once the cells are selected, press the Command key and the = (equal sign) key at the same time. This will automatically sum the selected cells. If you want to sum a specific range of cells, you can do so by selecting the first cell in the range, pressing the Shift key, and then selecting the last cell in the range.
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Can someone help me!!!
4x+3=3x+13(Alternative interior angles)
4x-3x=13-3
x=10
Value of each angle=43 each
My question is in the picture. Will give brainliest.
C i did it and hope you get it right like i did, and pls give branliest and pleasure
each tile in the model represents 1/4. How many titles make a group of 3/4
Answer:
3 tiles
because 1/4+1/4+1/4=3/4
I hope this helps you!
A real number $x$ is chosen at random between 0 and 1. Find the probability that the first nonzero digit in the decimal expansion of $\sqrt{x}$ is 3.
The probability that the first nonzero digit in the decimal expansion of √x is 3 is,
⇒ P (A) = 2/3
Now, Let A be the event that the first nonzero digit in the decimal expansion of √√{x} is 3.
We want to find P(A).
First, notice that A occurs if and only if 0.3² \leq x < 0.4².
That is, A occurs if and only if √{x} lies between 0.3 and 0.4.
The probability that √{x} lies between 0.3 and 0.4 is the area of the region between the curve y=√{x} and the horizontal lines y=0.3 and y=0.4 over the interval [0, 1].
This area can be found by integrating the function √x over this interval:
∫₀¹ √{x} dx = 2/3
Therefore, P(A) is the ratio of the area of the region between the curve y=√{x} and the horizontal lines y=0.3 and y=0.4 over the interval [0, 1] to the area of the entire rectangle, which is equal to 1.
Hence,
⇒ P(A) = 2/3
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Assume the distribution of IQ scores for adults can be modeled with a normal distribution with a mean score of 100 points and a standard deviation of 10 points. 30% of adults will have an IQ score higher than what value?
Step-by-step explanation:
Use z-score table to find the z-score that corresponds to .7000 ( 70%)
approx .525 s.d. above the mean
.525 * 10 = 5.25 points above 100 = 105.25
Nick,Jim and June share money in the ratio 5:5:3 in total nick and June received £88 how much does Jim get ?
Given:
Nick, Jim and June share money in the ratio 5:5:3.
In total Nick and June received £88.
To find:
The amount received by Jim.
Solution:
Let Nick, Jim and June received 5x, 5x and 3x respectively.
In total Nick and June received £88.
\(5x+3x=88\)
\(8x=88\)
\(x=\dfrac{88}{8}\)
\(x=11\)
Now, the amount received by Jim is
\(\text{Jim get}=5x\)
\(=5(11)\)
\(=55\)
Therefore, the amount received by Jim is £55.
A basket is filled with cards, one for each letter of the alphabet and one for each digit 0-9. One card is chosen.
The basket filled with cards is an illustration of probability
The probability of selecting any card from the basket is 1/36
How to determine the probabilityThe number of letters is:
Letters = 26
The number of digits is:
Digits = 10
This means that the total number of cards is:
n = 36 (i.e. 26 + 10)
So, the probability of selecting a card is:
\(Pr = \frac 1{36}\)
Hence, the probability of selecting any card from the basket is 1/36
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Unit 4 Mid Unit Assessment
2.
1. A scale drawing of a picture frame is 6
inches long and 4 inches wide. If the
scale is 1 inch: 3.5 feet, what is the
length and width of the actual picture
frame?
Answer:
20
Step-by-step explanation:
I need help by tonight 15 points
Answer: option d
Step-by-step explanation:
Answer:
He will land on D
Step-by-step explanation:
A is the starting and the finish point, 100% of the block is from A to A. Therefore, from A to B is 25% and from A to C is 50%. Since there is 4 corners, A to D is the only one that can be 75%. So, if he walks from A to A and then from A to D, that is 100% + 75% which is 175%
Q5) Given the denominator of a closed loop transfer function as expressed by the following expression: S² + 8S-5Kcp + 20 The symbol Kcp denotes the proportional controller gain. You are required to work out the following: 5.1) Find the boundaries of Kep for the control system to be stable. 5.2) Find the value for Kcp for a peak time To to be 1 sec and percentage overshoot of 70%.
5.1) The boundaries of Kcp for system stability are -∞ < Kcp < 1.2 and Kcp > 3.33. 5.2) For a peak time of 1 sec and 70% overshoot, the value of Kcp is approximately 2.14.
5.1) To determine the stability boundaries, we need to find the values of Kcp that make the characteristic equation’s roots have negative real parts. Using the quadratic formula, we find the discriminant Δ = 8^2 – 4(1)(20) = 24. The system is stable when the discriminant is positive, so Δ > 0, which leads to the condition 5Kcp – 24 > 0. Solving for Kcp, we get Kcp > 4.8. Additionally, to avoid complex roots, we need the condition 5Kcp – 24 > 0 to be true, resulting in Kcp < 4.8. Therefore, the stability boundaries are -∞ < Kcp < 1.2 and Kcp > 3.33.
5.2) To find the value of Kcp for a peak time (Tp) of 1 sec and a 70% overshoot, we can use empirical rules. For a 70% overshoot, the damping ratio (ζ) can be found using the formula ζ = (-ln(Overshoot/100)) / (√((π^2) + (ln(Overshoot/100))^2)). From ζ, we can calculate the natural frequency (ωn) using the formula ωn = (4 / (ζ * Tp)). Finally, we can determine the value of Kcp by equating ωn^2 = 5Kcp. By substituting the given values, Kcp is approximately 2.14.
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