What happened to the arrangement and the speed of water molecules when liquid water turns into ice?

(a) The number of moles of Ag⁺ that reacted is 0.05 mmoles and moles of Cl- that reacted is 0.05 mmoles.

(b) The number of moles of AgCl(s) formed is 0.05 moles

(c) The molarity of Ag⁺ after the reaction = 0.0 M

(d) The molarity of NO₃⁻ after the reaction is 0.25 M

The number of moles of Ag and Cl- that reacted is calculated as follows from the equation of the reaction:

AgNO₃ (aq) + NaCl (aq) ---> AgCl (s) + NaNO₃ (aq)

(a) The number of moles of Ag and Cl- that reacted:

Moles of Ag⁺ = 0.5 * 0.1

Moles of Ag⁺ = 0.05 mmoles

Moles of Ag⁺ that reacted = 0.05 mmoles

Moles of Cl⁻ = 0.5 * 0.1

Moles of Cl⁻ = 0.05 mmoles

Moles of Cl⁻ that reacted = 0.05 mmoles

(b) The number of moles of AgCl(s) formed.

Moles of AgCl that formed = 0.05 moles

(c) Since there are no more Ag⁺ ions in the mixture, the molarity of Ag⁺ after the reaction = 0 moles

(d) The molarity of NO₃⁻ after the reaction.

Moles of NO₃⁻ = 0.5 * 0.1

Moles of NO₃⁻ = 0.05 moles

Volume of mixture = 0.2 mL

The molarity of NO₃⁻ after the reaction = 0.05/0.2

The molarity of NO₃⁻ after the reaction = 0.25 M

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Mass number is the sum of the total number of nucleons (neutrons + protons) present in the atom.

Mass number = Protons + Neutrons

Mass number = 6 + 8

Mass number = 14

_______

Hope it helps ⚜

Answer:

Ph level 0-7 is a acid

ph level 7-14 is base

bases turn paper blue

acids dissolve metal

acids contain hydrogen ions

Explanation:

I dont know the last one all I know that they become neutral when acids and bases are mixed.

the answer is:

b. warm ~~> cool

The arbitrary assignment of the reduction of Zn2+(aq) to Zn(s) as E = 0 V serves as a reference point for determining the relative reduction potentials of other redox reactions. This assignment is based on the convention that the standard reduction potential

In the case of the Zn2+(aq) to Zn(s) reduction, the reaction involves the gain of two electrons by Zn2+ ions, leading to the formation of solid zinc metal. The assigned reduction potential of 0 V indicates that, under standard conditions (1 M concentration, 25°C, and 1 atm pressure), the Zn2+ ions have a tendency to accept electrons and be reduced to Zn metal.

Any reduction potential above 0 V suggests a greater tendency for reduction, while a negative reduction potential indicates a lower tendency for reduction compared to the Zn2+(aq) to Zn(s) reaction.

This reference potential allows us to compare the reactivity of other redox systems and predict the feasibility of different reactions. The more positive the reduction potential, the greater the tendency for reduction to occur. Therefore, if we encounter a reduction potential of +0.34 V for another reaction, we can infer that it is more likely to occur spontaneously compared to the Zn2+(aq) to Zn(s) reduction. Conversely, if we encounter a reduction potential of -0.50 V, we can conclude that the reverse reaction (oxidation) is more favorable than the reduction of Zn2+(aq) to Zn(s).

Overall, the assignment of E = 0 V for the reduction of Zn2+(aq) to Zn(s) provides a benchmark for understanding the electrochemical behavior of other redox reactions and allows us to make predictions based on the relative reduction potentials.

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Answer:

the emperical formula if histame is

Explanation:

C5H9N3

Answer:

Explanation:

One mole of any gas at STP takes up 22.4 L

1 mole of gas = 22.4L

2.5 moles of gas takes up = ( 22.4 L/ 1 mole ) x 2.5 mole

= 56 L

Answer:

The [H⁺] for this soluton is 2*10⁻³ M

Explanation:

pH, short for Hydrogen Potential and pOH, or OH potential, are parameters used to measure the degree of acidity or alkalinity of substances.

The values ​​that compose them vary from 0 to 14 and the pH value can be directly related to that of pOH by means of:

pH + pOH= 14

In this case, pOH=11.30, so

pH + 11.30= 14

Solving:

pH= 14 - 11.30

pH= 2.7

Mathematically the pH is the negative logarithm of the molar concentration of the hydrogen or proton ions (H⁺) or hydronium ions (H₃O):

´pH= - log [H⁺] = -log [H₃O]

Being pH=2.7:

2.7= - log [H⁺]

[H⁺]= 10⁻² ⁷

[H⁺]=1.995*10⁻³ M≅ 2*10⁻³ M

The [H⁺] for this soluton is 2*10⁻³ M

The pH of the NaOH solution has been 2.7. The hydrogen ion concentration of the NaOH solution has been 1.9 \(\rm \bold{\times\;10^-^3}\) M.

The pH of the solution has been used for the determination of the Hydrogen ion concentration in the solution. The higher the hydrogen ion concentration, the pH will tend to be more towards the lower side.

The pOH has been the hydroxide ion concentration in the solution, The higher the hydroxide ion concentration, the more pH will move towards the higher range.

The sum of pH and pOH has been the constant quantity.

pH + pOH = 14

The given NaOH solution has pOH 11.30. The pH of the solution will be:

pH + 11.30 = 14

pH = 14 - 11.30

pH = 2.7.

The pH of the NaOH solution has been 2.7.

pH can be defined as the negative log of the hydrogen ion concentration.

pH = -log [\(\rm H^+\)]

2.7 = log [\(\rm H^+\)]

[\(\rm H^+\)] = \(\rm 10^-^2^.^7\)

[\(\rm H^+\)] = 1.9 \(\rm \bold{\times\;10^-^3}\) M

The hydrogen ion concentration of the NaOH solution has been 1.9 \(\rm \bold{\times\;10^-^3}\) M.

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The required tubular length for 99.9% conversion is 116.84 meters.

On Earth, the rate at which cyclohexane reacts with benzene and methylcyclopentane is constrained by high mass transfer.

A tubular reactor with an internal diameter of 5 cm and a length of 20 m will be used to conduct the reaction, and cylindrical pellets with dimensions of 0.5 cm in diameter and 0.5 cm in length will be placed within the reactor's pipes.

Only the exterior surface of the pellets are coated.

The packed bed has a 40% porosity and a 60 dm3/min intake flow rate.

When the intake gas stream includes 5% cyclohexane and 95% hydrogen at 2 atm and 500°C, the tubular length vs. conversion graph should be drawn.

The graph may be used to identify the minimum length of tube necessary for 99.9% conversion.

For cyclohexane diffusion in hydrogen, the Fuller, Schettler, and Giddings Correlation is as follows:

a = 0.8854,

b = 1.764102,

C = 6.0231023.

The tube length vs. conversion graph may be displayed at 2 atm and 500°C when the incoming gas stream includes 5% cyclohexane and 95% hydrogen.

The following equation may be used to determine the rate of reaction:

ra=2.31011 exp[-88580/RT]C_A(1X)/3

The mole balancing equation for an isothermal tubular reactor is given as

dX/dL = -ra/C A,

where X is the conversion and L is the length.

To determine the length of the tubular reactor needed for a specific conversion X, we can integrate the aforementioned equation from X = 0 to X = X.

We must numerically calculate the following equation to obtain the necessary tube length for 99.9% conversion:

∫0.999L0−ra/CA 

dL=0.999XEq L 

for X=0.999

After rearranging the equation above, we get:

0.999L0ra/CA

dL=XX Eq

The aforementioned equation is integrated to give us

L = 116.84 m.

Therefore, the required tubular length for 99.9% conversion is 116.84 meters.

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Answer:

its D

Explanation:

Answer:

D

Explanation:

The amount of heat released from the system as the pentane cools is 67.5kJ.

To determine the heat released from the system as the pentane cools, we need to consider the heat absorbed or released during each of the phase changes (vaporization and fusion) as well as the heat absorbed or released during the temperature change of the substance in each phase.

The heat absorbed or released during a phase change can be calculated using the enthalpy of vaporization (AHvap) or enthalpy of fusion (AHfus) and the number of moles of substance undergoing the phase change.

The heat absorbed or released during a temperature change can be calculated using the specific heat of the substance and the number of moles of substance and the temperature change.

In this case, we can first calculate the heat absorbed or released during the vaporization of the pentane:

Heat = ΔHvap * moles

Heat = 45.3 kJ/mol * 144.29 g / (58.12 g/mol) = 102.1 kJ

Next, we can calculate the heat absorbed or released during the cooling of the pentane vapor to the melting point:

Heat = specific heat * moles * temperature change

Heat = 168 J/mol K * 144.29 g / (58.12 g/mol) * (117 - (-84)) K = 68400 J = 68.4 kJ

Then, we can calculate the heat absorbed or released during the fusion of the pentane:

Heat = ΔHfus * moles

Heat = 120 kJ/mol * 144.29 g / (58.12 g/mol) = 270 kJ

Finally, we can calculate the heat absorbed or released during the cooling of the pentane from the melting point to the final temperature:

Heat = specific heat * moles * temperature change

Heat = 168 J/mol K * 144.29 g / (58.12 g/mol) * (-84 - (-84)) K = 0 J

The total heat released from the system can be calculated by adding up the heat absorbed or released during each of these processes:

Total heat = 102.1 kJ + 68.4 kJ + 270 kJ + 0 kJ = 440.5 kJ

The correct answer is therefore D) 67.5 kJ.

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Answer:

2

Explanation:

Answer:

At one atmosphere and twenty-five degrees Celsius, could you turn it into a liquid by cooling it down? Um, and the key here is that the triple point eyes that minus fifty six point six degrees Celsius and it's at five point eleven ATMs. So at one atmospheric pressure, there's no way that you're ever going to reach the liquid days. So the first part of this question is the answer The answer to the first part of a question is no. How could you instead make the liquid at twenty-five degrees Celsius? Well, the critical point is at thirty-one point one degrees Celsius. So you know, if you're twenty-five, if you increase the pressure instead, you will briefly by it, be able to form a liquid. And if you continue Teo, you know, increase the pressure eventually form a salad, so increasing the pressure is the second part. If you increase the pressure of co two thirty-seven degrees Celsius, will you ever liquefy? No. Because then, if you're above thirty-one point one degrees Celsius in temperature. You'LL never be able to actually form the liquid. Instead, you'LL only is able Teo obtain supercritical co too, which is really cool thing. You know, they used supercritical sio tu tio decaffeinated coffee without, you know, adding a solvent that you'LL be able to taste, which is really cool. But no, you can't liquefy so two above thirty-one degrees Celsius or below five-point eleven atmospheric pressures anyway, that's how I answer this question. Hope this helped :)

If you have carbon dioxide at 1.0 atm and 25°C. We can not  make it liquid by cooling it down. The carbon dioxide does not liquify by increasing pressure and at body temperature  (37°C) .

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Answer:

lungs

Explanation:

Answer:

pH = 4

Explanation:

pH = -log[H⁺] = -log(10⁻⁴) = -(-4) = 4

Answer:

dnidofoeosjnsieiddis8wiejie

The vapor pressure at 85.0°C of a solution prepared by dissolving 0.300 mol of liquid dibromoethane the vapor pressure at 85.0°C of a solution prepared by dissolving 0.300 mol of liquid dibromoethane is 164.83 torr.

The term vapor pressure is defined as the tendency of a material to change into the vapour state, and it increases with temperature.

For calculating mole fraction of C₂H₄Br₂ as follows

X C₂H₄Br₂ = moles of C₂H₄Br₂ / moles of C₂H₄Br₂ + moles of C₃H₆Br₂

= 0.3 / 0.3 + 1.80

= 0.14

For calculating mole fraction of C₃H₆Br₂ as follows:

XC₃H₆Br₂ =  moles of C₃H₆Br₂ / moles of C₂H₄Br₂ + moles of C₃H₆Br₂

= 1.80 / 2.1

= 0.85

For calculating total vapor pressure as follows:

P total = [ ( 0.14 × 127) + (0.85 × 173) ]

= 17.78 + 147.05

= 164.83 torr

Thus, The vapor pressure at 85.0°C of a solution prepared by dissolving 0.300 mol of liquid dibromoethane the vapor pressure at 85.0°C of a solution prepared by dissolving 0.300 mol of liquid dibromoethane is 164.83 torr.

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Answer:

**TAKES POINTS** lol just kidding!! heres your answer: basically all compounds and elements are composed of atoms :)

Explanation:

all elements, and compounds, all matter in point of fact, are composed of atoms. In a compound, there are 2 or more different types of atoms present that are chemically bound In an element there is only the one type of atom

2.51 mol Cu

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Step 1: Define

1.51 × 10²⁴ atoms Cu

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

2.50747 mol Cu ≈ 2.51 mol Cu

7.10 grams of C₈H₁₈ will react with 24.78 g of O₂ in this unbalanced combustion reaction.

Type of chemical reaction that occurs when substance reacts with oxygen gas to produce energy in the form of heat and light is called combustion reaction .

To balance the combustion reaction: C₈H₁₈ + 12.5 O₂ -> 8 CO₂ + 9 H₂O

The coefficients show that 12.5 moles of  O₂ are needed to react with 1 mole of C₈H₁₈.

1 mole of  O₂ has a mass of 32 g, so 24.78 g of  O₂ is:

24.78 g / 32 g/mol = 0.774 mol of O₂

0.774 mol of  O₂ / 12.5 mol of  O₂/mol of C₈H₁₈ = 0.06192 moles of C₈H₁₈

0.06192 moles of C8H18 x 114.23 g/mol of C₈H₁₈ = 7.10 g of C₈H₁₈

Therefore, 7.10 grams of C₈H₁₈ will react with 24.78 g of  O₂ in this unbalanced combustion reaction.

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When the reaction of  Grignard reagent reacted with methanol will yield a tertiary alcohol. Therefore, Option C tertiary alcohol is correct.

Contains a carbon-metal link, Grignard reagents are chemicals used in catalysis. They generally result from the anhydrous reaction of magnesium metal with an alkyl or aryl halide. Because of their high reactivity, Grignard reagents frequently act as nucleophiles in organic reactions.

An alkyl group from a Grignard reagent binds to the oxygen atom of methanol (CH3OH) when it interacts with the methanol, breaking the carbon-metal connection. A precursor alkoxide is created as a result. The equivalent alcohol is then produced by protonating the intermediate alkoxide.

The reaction of a Grignard reagent with methanol leads to the formation of a tertiary alcohol.

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The decomposition of aspirin (acetylsalicylic acid,\(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)).

The decomposition of aspirin (acetylsalicylic acid, \(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)). To determine the moles of each product formed, we need to consider the balanced chemical equation for the reaction:

\(C_{9} H_{8} O_{4} = > C_{7} H_{6}O_{3} +CH_{3} COOH\)

From the equation, we can see that for every 1 mole of aspirin, 1 mole of salicylic acid and 1 mole of acetic acid are produced.

Therefore, the moles of salicylic acid and acetic acid formed will be equal to the number of moles of aspirin that decomposes. If we know the amount of aspirin in moles, we can directly calculate the moles of each product based on stoichiometry.

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carbon is an elements ,The compounds of carbon are called an organic compounds.

Carbon have tendency to catenation. catenation means forming bond with another carbon atom and form a long chain of carbon. This is the reason for the presence variety of number of organic compounds. The atomic size of carbon is small and have the valency of four, forms covalent bond. Carbon is strong and stable. Generally carbon containing compound are organic compounds. Generally all the Organic compounds contain carbon and hydrogen  called as hydrocarbon.

Thus, carbon is an elements ,The compounds of carbon are called an organic compounds.

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Answer:

A possible element with ns2np4 valence orbital is Oxygen(O)
A element that has the most electronegativity and soft is flourine(F)
for part C, it is scandium (Sc) with the last electron filled in the 3d orbital

Answer:

True

Explanation:

Copper has the highest electrical conductivity rating of all non-precious metals: the electrical resistivity of copper = 16.78 nΩ•m at 20 °C. Specially-pure Oxygen-Free Electronic (OFE) copper is about 1% more conductive (i.e., achieves a minimum of 101% IACS).

True is the correct answer.

HNO2 is a bronsted-lowry acid that does not behave as a strong acid when it is dissolved on water.

According to the Bronsted-Lowry idea, nitrous acid is a type of acid. When dissolved in an aqueous solution, it releases H+ ions. And an acid is a chemical that releases H+ ions in water solutions or donates the proton to other substances. Because it causes the release of H+ ions in a water solution, it is an acid. Since it only partially dissociates in water, generating hydronium ions and its conjugate base, it is categorized as a weak acid. The powerful acids are hydrochloric acid, perchloric acid, chloric acid, nitric acid, sulfuric acid, hydrobromic acid, and hydroiodic acid.

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Answer:

Cyanide

Explanation:

Molecular Structure of Each Answer

A:  CN-

B: NO3-

C: OH-

D: SO4 2-

As you can see, only A (Cyanide) is the only compound that does not contain oxygen, meaning it is NOT an oxyanion.

The statement "Superficial zone chondrocytes can get compacted under physiological loading: a multiscale finite element analysis" is true.

Superficial zone chondrocytes are the most exposed to mechanical loading and are therefore at risk of being compacted under physiological loading. A multiscale finite element analysis can be used to model and predict the mechanical behavior of cartilage under physiological loading, allowing for a better understanding of the factors that affect its mechanical properties.

This means that chondrocytes in the superficial zone of cartilage are at risk of being compacted under the physiological loading that it experiences in everyday life. A multiscale finite element analysis can be used to model and predict the mechanical behavior of cartilage under physiological loading, allowing for a better understanding of the factors that affect its mechanical properties.

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