What happens to objects in space when they no longer have force accelerating them?

Let's conclude that the distant galaxies all appear to be moving away from us and with the more distant ones moving faster. This is the reason why we assume and infer that the universe is actually expanding.

"The universe is expanding," you may have heard because scientists revealed that faraway galaxies are leaving us at a noticeably faster rate than those closer to our home, our galaxy. So no, universe is not growing in size and it is not rotating rapidly.

Did you know that the Hubble Law states that because the universe is expanding, it may be used to calculate distances between galaxies? It never states that universe expands because the galaxy appear to be made of dark matter.

So the astounding hypothesis that the universe appears to be accelerating suggests that it is expanding faster than previously observed.

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Answer:

C

Explanation:

There is a decrease in temperature and daylight and plants produce less food.

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Explanation:

W = F * d      <====   ( Force * distance)

     500 N  * .7 m = 350 J

Answer:

A.

Explanation:

Answer: negative acceleration of 4 m/s^2

Explanation: i took the exam on edge

The one that most likely recounts acceleration in the given scenario would be:

A). Negative acceleration of 4 m/s^2

Given that,

The direction of the object = East

Change in Velocity = Final velocity - Initial Velocity

\(= 25 - 65 m/s\)

\(= -40 m/s\)

As we know,

Acceleration \(=\) Change in Velocity ÷ time

\(= -40\) ÷ \(10\)

\(= -4\) \(m/s\)

Thus, option A is the correct answer.

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At 0 frequency (0Hz) or DC, the capacitor acts like an open circuit due to its reactance for this reason blocking off any output voltage feedback. As a result, little or no negative feedback is furnished from the output again to the input of the amplifier.

Therefore at low frequencies, the LPF has finite output and at high frequencies the output is nil, that's identical to an integrator circuit. for this reason, a low skip filter can be said to be worked as an integrator. Then the voltage variant in C may be very small.

A common op-amp circuit uses a remarks capacitor to limit the bandwidth. proscribing op-amp bandwidth will reduce noise, so a remarks capacitor is not an unusual way to reduce noise. To apprehend how the comments capacitor works, remember that a capacitor acts as a brief to “high frequency” AC indicators.

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Answer:

The instrument is thermometer

As to why electrons orbit in only certain orbits, a compelling explanation views orbital electrons as having specific energy levels. These energy levels are determined by the amount of energy the electron possesses, and are quantized, meaning they can only exist at certain discrete values. When an electron absorbs or emits energy, it transitions between these energy levels, resulting in the emission or absorption of a photon.

This explanation comes from the theory of quantum mechanics, which provides a mathematical framework for understanding the behavior of subatomic particles. In this theory, electrons are described by wave functions that determine the probability of finding an electron at a particular location in space. These wave functions are associated with specific energy levels, which dictate the electron's behavior within the atom.

Overall, the specific energy levels and quantization of electrons in an atom are a result of the wave nature of subatomic particles and the mathematical principles of quantum mechanics.

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The illusion of movement that results from two or more stationary, adjacent lights blinking on and off in quick succession is called the stroboscopic effect.

This effect creates the illusion of continuous motion, even though the lights are actually stationary. The blinking lights create a series of still images that the brain interprets as movement. This effect is often used in dance clubs and stage performances to create a dynamic atmosphere. However, it is important to note that the stroboscopic effect can also cause discomfort and seizures in individuals with photosensitive epilepsy.

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To find the current in the resistor, we can use Ohm's Law and the concept of equivalent resistance. Thus, option A is correct.

First, let's calculate the equivalent resistance of the three cells connected in parallel. When resistors are connected in parallel, the reciprocal of the equivalent resistance is equal to the sum of the reciprocals of the individual resistances:

1/Req = 1/R1 + 1/R2 + 1/R3

Given that R1 = R2 = R3 = 22 Ω (internal resistance of each cell), we can substitute the values:

1/Req = 1/22 + 1/22 + 1/22

1/Req = 3/22

Taking the reciprocal of both sides, we find:

Req = 22/3 Ω

Now we can use Ohm's Law to calculate the current (I) in the resistor. Ohm's Law states that the current flowing through a resistor is equal to the voltage across it divided by its resistance:

I = V/R

Given that V = 1.1 V (emf of each cell) and R = 32 Ω (resistance), we can substitute the values:

I = 1.1/32

Calculating this value, we find:

I ≈ 0.034375 A

Therefore, the current in the resistor is approximately 0.034375 A.

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The student did not break the law of conservation of linear momentum because the final momentum of the hockey puck will be equal to the initial momentum of the hockey stick.

The law of conservation of linear momentum states that the total momentum of an isolated system is always conserved.

That is the sum of initial momentum is equal to the sum of the final momentum of the object.

Mathematically, the law of conservation of linear momentum is given as;

Pi = Pf

m₁u₁ = m₂u₂

where;

The hockey puck speeds up because it gained momentum from the hockey stick and hockey stick will slow down to maintain the law of conservation of linear momentum.

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Answer:

Explanation:

See the attachment for the details.  A right triangle is formed to find the hypotenuse of the two legs consisting of the actual driving distances and times.  The hypotenuse gives the vector information for the displacement at the end of 8 hours of driving.  

The individual driving times and distances are summed to provide:

(a) How far did he travel?

103 km

(b) What was his average speed?

12.88 km/h

(c) What was his displacement?

73.82 km

(d) What was his average velocity?

9.228 km/h

Answer:

\(\huge\boxed{196\:N}\)

Explanation:

Mass and weight ain't the same thing. So, for calculating weight we would use Newton's 2nd Law of Motion i.e. Force = Mass × Acceleration.

According to question,

The mass is 20kg

Acceleration is 9.8 m/s^2

Putting the given values into the formula,

F = 20 × 9.8

F = 196N

So, the weight of the rock is 196 N

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Answer:

Its A

Explanation:

a) At the point the block is released, the initial velocity is zero, so the initial kinetic energy of the block is zero. The block is at a height of 55 meters from the ground, so its gravitational potential energy can be calculated using the formula;

PE = mghwhere m = 6 kg (mass of the block), g = 9.8 m/s² (acceleration due to gravity), and h = 55 m (height of the block from the ground)PE = mgh = (6 kg) (9.8 m/s²) (55 m) = 3,234 JTherefore, the gravitational potential energy of the block when it was released was 3,234 Joules (J).b) The kinetic energy of the block at the point of impact can be calculated using the formula; KE = ½mv²where m = 6 kg (mass of the block), and v = 30 m/s (velocity of the block)KE = ½mv² = ½ (6 kg) (30 m/s)² = 2,700 J.

Therefore, the kinetic energy of the block at the point of impact was 2,700 Joules (J).c) The law of conservation of energy states that energy cannot be created or destroyed, it can only be transformed from one form to another. At the point of impact, the block loses its kinetic energy. The mechanical energy "lost" by the block can be calculated as the difference between the initial potential energy and the final kinetic energy.

ΔE = PE - KE= (3,234 J) - (2,700 J) = 534 J

When the block hit the ground, it created a loud sound, generated heat, and also caused the ground to shake. Therefore, the mechanical energy that was "lost" by the block was transformed into sound energy, heat energy, and seismic energy.

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Explanation:

Significant figures of a number written in positional notation are digits that carry meaningful contributions to the measurement resolution of the number.

Answer:

The value of a physical quantity is expressed by a number followed by some suitable unit.

Explanation:

every measurement of a quantity is an attempt to find true value.

rules for identifying significant figures:

1)All non-zero numbers ARE significant. e.g. The number 33.2 has THREE significant figures because all of the digits present are non-zero.

2)Zeros between two non-zero digits ARE significant. e.g. 2051 has FOUR significant figures. The zero is between  2 and  5.

3)Leading zeros are NOT significant. e.g.  The number 0.54 has only TWO significant figures. 0.0032 also has TWO significant figures. All of the zeros are leading.

4)Trailing zeros to the right of the decimal ARE significant. e.g.  There are FOUR significant figures in 92.00.

5)Trailing zeros in a whole number with the decimal shown ARE significant. e.g. Placing a decimal at the end of a number is usually not done. By convention, however, this decimal indicates a significant zero. For example, "540." indicates that the trailing zero IS significant; there are THREE significant figures in this value.

Answer:

It has several other objects in its orbit, though few are as massive as itself."

The correct answer is option A. Water is not a state/ phase of matter

States are those phases that describe its physical attributes as well as how its constituent particles are arranged. Solid, liquid, gas, and plasma are the four main states of matter that can exist.

When something melts, it transitions from a solid to a liquid condition.

Water has a freezing point of 0°C.The melting point of flour is around 220 degrees Celsius, which is greater than that of salt and sugar. Sublimation is the process by which a solid transforms into a gaseous state, as in the case of camphor. Examples of changes in the states of matter include the melting of ice, the freezing of water, the burning of camphor, the melting of wax, and the production of precipitates.

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When a moving body's direction changes, its velocity doesn't always go to zero. Only when the body's total displacement is zero does velocity become zero.

A change in the body's state of motion is reflected in either a change in the body's speed or its direction of motion. A force is an attempt to alter the status of an object, whether it is stationary or moving. The speed shift might indicate acceleration or slowdown (deceleration). Acceleration measures the change in speed as opposed to velocity, which measures speed in a vector (also in a vector). The velocity is zero, which indicates that although the item is not moving, there is a force exerted on it due to acceleration.

Hence the change in motion is zero

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Answer:

The same.

Explanation:

Temperature is a measure of the average kinetic energy of a substance; if two pieces of iron have the same temperature, then their particles will have the same amount of average kinetic energy.

Answer 1 - The average kinetic energy of the particles of two pieces of iron at the same temperature and mass would be the same

Answer 2 - The particles of an object move FASTER when the temperature increases

Answer 3 - When a tight fitting lid is run under hot water, the lid  

E/X/P/A/N/D/S as the temperature increases.

Answer 4 - I dont know sorry!

Answer 5 - What happens when something reaches absolute zero?

The p a r t i c l e s completely stop moving

Answer:

electric field to be measured and influence the source producing electric field to be measured.

Explanation:

The test charge used to mea... To measure the electric field at a point, the test charge used should be very small so that it does not change the electric field to be measured and influence the source producing electric field to be measured.

The amount of heat transferred is proportional to the temperature difference between the objects and the heat capacity of the object.

Warmness is based totally on the authentic story of Neil McCauley, a calculating criminal and ex-Alcatraz inmate who was tracked down by way of Detective Chuck Adamson in 1964. In 1961, McCauley was transferred from Alcatraz to McNeil, as mentioned in the film.

Considering the fact that Michael Mann's warmness got here out, he's been citing the film as a concept for the paintings he did inside the Dark Knight. Connections have been drawn among the visuals, the interrogation scene, and even solid member William Fitchner, who's in each movie.

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The kinetic energy of the truck is approximately 1,964,180 Joules. The kinetic energy of the car is approximately 250,003 Joules.

To calculate the kinetic energy of each vehicle, use the formula:

Kinetic Energy (KE) = 1/2 × mass × velocity²

Given the mass and velocity of each vehicle, plug in the values and calculate the kinetic energy.

For the truck:

Mass = 6,000 kg

Velocity = 92 km/h

= 92,000 m/3600 s

≈ 25.56 m/s

Using the formula:

KE = 1/2 × 6,000 kg × (25.56 m/s)²

Calculating the result:

KE = 1/2 × 6,000 kg × 655.3936 m²/s²

KE ≈ 1,964,180 Joules

Therefore, the kinetic energy of the truck is approximately 1,964,180 Joules.

For the car:

Mass = 1,200 kg

Velocity = 100 km/h

= 100,000 m/3600 s

≈ 27.78 m/s

Using the formula:

KE = 1/2 × 1,200 kg × (27.78 m/s)²

Calculating the result:

KE = 1/2 × 1,200 kg × 771.6884 m²/s²

KE ≈ 250,003 Joules

Therefore, the kinetic energy of the car is approximately 250,003 Joules.

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The criteria and the constraints of a project aims to find if the criteria are met by certain standards.

Criteria and constraints can be tested in several ways to ensure that they are being met:

User Acceptance Testing (UAT): This is a testing process that involves end-users to determine if the requirements specified in the criteria and constraints have been met. UAT allows you to verify that the solution meets the needs of the end-users.

System Testing: This is a comprehensive testing process that validates the entire system, including the criteria and constraints. System testing verifies that the system functions as intended and meets the specified requirements.

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The net work required to cause the particle to move to the right at 47 m/s is 30.102 Joules.

To determine the net work required to change the particle's velocity from moving left at 27 m/s to moving right at 47 m/s, we can use the work-energy principle.

The work-energy principle states that the net work done on an object is equal to the change in its kinetic energy.

The kinetic energy of a particle is given by the equation:

KE = (1/2) * m * v^2

where m is the mass of the particle and v is its velocity.

Let's calculate the initial kinetic energy (KE_initial) and final kinetic energy (KE_final) of the particle.

Given:

Mass of the particle (m) = 41 g = 0.041 kg

Initial velocity (v_initial) = -27 m/s (negative sign indicates motion to the left)

Final velocity (v_final) = 47 m/s

Calculate the initial kinetic energy:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 0.041 * (-27)^2

= 0.5 * 0.041 * 729

= 14.9575 J

Calculate the final kinetic energy:

KE_final = (1/2) * m * v_final^2

= (1/2) * 0.041 * 47^2

= 0.5 * 0.041 * 2209

= 45.0595 J

Calculate the net work done:

Net work = KE_final - KE_initial

= 45.0595 - 14.9575

= 30.102 J

Therefore, the net work required to cause the particle to move to the right at 47 m/s is 30.102 Joules.

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Answer:

Physics is a natural science that involves the study of matter and its motion through space and time, along with related concepts such as energy and force.

The markdown price for a mountain bike is $584.35

Markdown price is the discount offered by the shopkeepers to the customers to increase the sales rate.

M.P = S.P (1-r/100)

The following expression can be used every time we have to find the markdown price.

Substitute Selling price S.P =$899 and the percent r =35/100 =0.35, we get

M.P = $899(1-0.35)

M.P =$584.35

Thus, the markdown price is $584.35

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The customary system of measurement is used, in which a gallon is the closest unit of volume to a liter. Option (A) is correct.

The International unit of volume closest in size to a liter is: Liter. The definition of liter, which is the International System unit of volume is "a volume of 1000 cubic centimeters." Since the International System unit of volume is "a volume of 1000 cubic centimeters," the International unit of volume closest in size to a liter is the liter.

In everyday life, liters are frequently utilized to calculate the volume of liquid or dry matter. The liter is used in science and technology for calculations and information storage. A container that holds 1 liter of water is the same as a 1 liter container that holds oil or flour.A liter is abbreviated as "L" or "l" in scientific notation.

It's also abbreviated as "ℓ" (which looks like a script lowercase letter "L") on the Internet, but this is not widely used. In most countries, the metric system of measurement is used for quantity, weight, and volume. In the United States, Liberia, and Myanmar, however, the customary system of measurement is used, in which a gallon is the closest unit of volume to a liter.

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1. The given data are:Volume of material collected = 30 mLTime taken for collecting the volume of material = 10 sDensity of the material = 0.5 g/mLThe mass flow rate of material is defined as the mass of material flowing through a unit cross-sectional area per unit time.Mass = Density × Volume.

∴ Mass flow rate = Density × Volume / Time ∴ Mass flow rate = 0.5 g/mL × 30 mL / 10 s = 1.5 g/s. Therefore, the mass flow rate of material is 1.5 g/s.2. Given data are:Area of pipe = 9 m²Velocity of water = 5 m/sThe flow rate of water is defined as the volume of water flowing through a unit cross-sectional area per unit time.

Flow rate = Velocity × Area ∴ Flow rate = 5 m/s × 9 m² = 45 m³/sTherefore, the flow rate of water is 45 m³/s.3. Volumetric flow rate of a process stream is the volume transported through a pipe per unit time.4. The given data are:Mass of material collected = 400 kgTime taken for collecting the mass of material = 5 sDensity of the material = 100 kg/m³.

The volume flow rate of material is defined as the volume of material flowing through a unit cross-sectional area per unit time.Volume = Mass / Density ∴ Volume flow rate = Mass / Density × Time.

∴ Volume flow rate = 400 kg / (100 kg/m³) × 5 s = 20 m³/sTherefore, the volumetric flow rate of material is 20 m³/s.5. Given data are:Standard deviation, σ = 15Mean, μ = 100The probability that x ≤ 112 can be calculated using the standard normal distribution table.The standard normal variate, z = (x - μ) / σ ∴ z = (112 - 100) / 15 = 0.8The value of the probability can be calculated by referring to the standard normal distribution table.

Using the standard normal distribution table, the probability that z is less than or equal to 0.8 is 0.7881. Therefore, the probability that x ≤ 112 is 0.7881 or 78.81%.

1. The mass flow rate of material is 1.5 g/s.2. The flow rate of water is 45 m³/s.3.

Volumetric flow rate of a process stream is the volume transported through a pipe per unit time.4. The volumetric flow rate of material is 20 m³/s.5. The probability that x ≤ 112 is 0.7881 or 78.81%.

This problem deals with mass flow rate, volumetric flow rate, and flow rate.

Flow rate is the volume of a fluid that flows through a cross-sectional area of a pipe or duct per unit time. It is commonly used in the study of fluids. The flow rate of a fluid can be expressed in terms of mass flow rate or volumetric flow rate.

Mass flow rate is the mass of a fluid flowing through a unit cross-sectional area of a pipe or duct per unit time. It is denoted by and its SI unit is kg/s. The formula for mass flow rate is = ρ/, where ρ is the density of the fluid, is the volume of the fluid flowing through a unit cross-sectional area of the pipe or duct, and is the time taken for the fluid to flow through the pipe or duct.

Volumetric flow rate is the volume of a fluid flowing through a unit cross-sectional area of a pipe or duct per unit time. It is denoted by and its SI unit is m³/s. The formula for volumetric flow rate is = /, where is the volume of the fluid flowing through a unit cross-sectional area of the pipe or duct, and is the time taken for the fluid to flow through the pipe or duct.In problem 1, the mass flow rate of material is calculated using the formula = ρ/. In problem 2, the flow rate of water is calculated using the formula = /.

In problem 4, the volumetric flow rate of material is calculated using the formula = /. The solution to problem 5 requires the use of the standard normal distribution table to calculate the probability that x ≤ 112.

This problem dealt with flow rate, mass flow rate, and volumetric flow rate. The formulas for calculating flow rate, mass flow rate, and volumetric flow rate were discussed. The solutions to the problems were obtained by applying the appropriate formula. The use of the standard normal distribution table was required to solve problem 5.

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