Answer:
As the mass of the object decreaes, the potential energy also decreases.
Explanation:
100 degrees C equals how many degrees F?
Answer:
212 f
Explanation:
What are the similarities and differences between light waves, water waves, and sound waves?
Answer:
Light waves- electromagnetic waves
water waves- combination of both longitudinal and transverse motions
sound waves- mechanical waves
They all oscillations that carry energy from one place to another.
Explanation:
hi
Similarities between light waves , water waves and sound waves:
Being a wave light waves , water waves and sound waves they all have amplitude , wavelength and frequency .They all have damped oscillations i.e. as far they go their amplitude and intensity decreases with distance.Differences between light waves, water waves, and sound waves:
Light waves are electromagnetic waves, while water waves and sound waves are mechanical waves. Light waves are not a mechanical wave; it can travel through a vacuum such as the empty parts of outer space.Sound and water waves are mechanical waves it means, they require a medium to travel through.The medium may be a solid, a liquid, or a gas, and the speed of the wave depends on the material properties of the medium through which it is traveling.
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What is the acceleration along the ground of a 10 kg wagon when it is pulled with a force of 44 N at an angle of 35° above the horizontal?.
The acceleration of the wagon along the ground is 3.6 m/s².
To solve the problem above, we need to use the formula of acceleration as related to force and mass.
Acceleration: This can be defined as the rate of change of velocity.
⇒ Formula:
Fcos∅ = ma................. Equation 1⇒ Where:
F = Force ∅ = angle above the horizontal m = mass of the wagona = acceleration of the wagon⇒ make a the subject of equation 1
a = Fcos∅/m..................... Equation 2From the question,
⇒ Given:
F = 44 N∅ = 35°m = 10 kg⇒ Substitute these values into equation 2
a = 44(cos35°)/10a = 44(0.8191)/10a = 3.6 m/s²Hence, The acceleration of the wagon along the ground is 3.6 m/s²
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Answer: 3.60 m/s^2
Explanation:
QUESTION-
What is the acceleration along the ground of a 10 kg wagon when it is pulled with a force of 44 N at an angle of 35° above the horizontal?
ANSWER
3.60 m/s^2 = 3.6 m/s^2
Which example below is a negative feedback relevant to Earth’s global energy balance?
Increased CO2 causes the oceans to become more acidic which causes oceanic volcanoes to erupt releasing more CO2 into the environment.
Increased temperature causes more solar radiation to enter the atmosphere thereby decreasing temperature.
Increased temperature causes snow to melt. This exposes bare ground, which absorbs more solar radiation than snow, leading to further increases in temperature.
Burning fossil fuels releases CO2, which traps long-wave radiation causing temperatures to increase.
Increased temperature causes snow to melt, which allows increased vegetation to remove CO2 from the atmosphere thereby reducing temperature.
The negative feedback relevant to Earth's global energy balance is:
Increased temperature causes snow to melt. This exposes bare ground, which absorbs more solar radiation than snow, leading to further increases in temperature.
In this example, the initial increase in temperature leads to the melting of snow. The bare ground exposed as a result absorbs more solar radiation, which further increases the temperature. This positive feedback loop amplifies the initial temperature increase.
On the other hand, negative feedback refers to a process that acts to counteract or reduce the initial change. However, in this example, the process of snow melting and bare ground absorbing more solar radiation reinforces and amplifies the initial temperature increase, making it a positive feedback loop rather than a negative feedback loop.
Therefore, the example "Increased temperature causes snow to melt. This exposes bare ground, which absorbs more solar radiation than snow, leading to further increases in temperature" is not a negative feedback but a positive feedback relevant to Earth's global energy balance.
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True or false Condensation occurs with the removal of thermal energy.
true. condensation is when gas converts to liquid. the molecules move slower because of a loss of thermal energy, so it forms liquid
A 10 kg body is constrained to move along the x-axis. The potential energy (U) of the body in joules is given as a function of its position x in meters by U(x)=6x^2-4x+3. The force on the particle at x=3 meters is...
The force on the particle at x=3 meters can be determined by taking the derivative of the potential energy function with respect to x.
The derivative gives us the force function.
Given that U(x) = 6x^2 - 4x + 3, we can find the force by taking the derivative:
U'(x) = dU(x)/dx = d/dx (6x^2 - 4x + 3)
Taking the derivative of each term separately:
U'(x) = d/dx (6x^2) - d/dx (4x) + d/dx (3)U'(x) = 12x - 4
Now, to find the force at x=3 meters, we substitute x=3 into the force function:
F(3) = 12(3) - 4F(3) = 36 - 4F(3) = 32
Therefore, the force on the particle at x=3 meters is 32 Newtons.
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what is the wavelength of such a wave? the speed of sound in air is 340 m/s.
Answer:
wavelength is λ=fv=440340=0. 77m.
Write three things you already know about golf, three things you want to know, and three things you learned
Answer:
What I know, want to know, and have learned
Explanation:
I know
1. You have to have a golf ball
2. You have to have a golf club
3. Its nice to have a golf cart
Want to know:
1. Where can I play
2. How to play
3. Is it a common sport
Have learned:
1. Golf is hard
2. Top golf is a nice place to golf
3. The goal is to make the ball into the hole
Define work What is the unit for work? For Physics, thanks.
Answer:
Work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement
Explanation:
What are some best practices for different exercises and sports performed:
at high altitude?
in hot weather?
in cold weather?
The name of the region on the celestial sphere where all of the stars are visible to a stargazer (in the northern hemisphere) all year round is
The region on the celestial sphere where all of the stars are visible to a stargazer (in the northern hemisphere) all year round is called the "celestial north pole" or the "north celestial pole."
The celestial sphere is an imaginary sphere that surrounds the Earth, and it is used as a reference system to describe the positions and movements of celestial objects. It is an imaginary projection of the entire sky onto a sphere, with the Earth located at its center.
The celestial North Pole is the point on the celestial sphere directly above the Earth's geographic North Pole. It is the point around which the stars appear to rotate due to the Earth's rotation.
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What is the force on a 1000 kg elevator that is falling freely at 9. 8 m/sec2.
Assume a simply supported beam with span of 15m. It will be exposed to a dead load of 20kN/m (including self-weight) and a live load of 2kN/m along the full span. At the same time, it will be experiencing a concentrated dead load of 23kN + a live load of 1kN at midspan, as well as an additional dead load of 15kN located at 4m from the right support.
The beam has a rectangular cross-section with a width of 600mm and total height of 1000mm. The beam is reinforced with 10- 25M tensions bars at effective depth of 920 mm. The maximum aggregate size used is 20mm, and has the following material properties: f’c = 25MPa ,fy = 400 MPa.
Please perform the following task:
1) Draw the governing shear and bending moment diagram for the factored load.
2) Calculate the moment resistance of the cross section.
3) Comment if this cross section is adequately designed to resist the factored bending moment. (LRFD)
The values of all sub-parts have been obtained.
(1). The maximum factored load the beam can withstand is 45.2 kN/m.
(2). The moment resistance of the cross-section is 291735.65 Nm.
(3). The factored moment demand is 27939.6 Nm
1) To draw the governing shear and bending moment diagram for the factored load, we need to first calculate the maximum factored load that the beam can withstand.
The maximum factored load on the beam is given by:
Dead Load = 20 kN/m + 15 kN
= 35 kN/m.
Live Load = 2 kN/m + 1 kN
= 3 kN/m.
Total Factored Load = 1.2 x Dead Load + 1.6 x Live Load
= 1.2 x 35 kN/m + 1.6 x 3 kN/m
= 45.2 kN/m.
The maximum factored load the beam can withstand is 45.2 kN/m.
The shear force and bending moment diagrams for the given factored load can be obtained as shown below:
Shear Force Diagram:
Bending Moment Diagram:
2) To calculate the moment resistance of the cross-section, we can use the formula:
MR = σst A'(d - a/2) + 0.85f'c A''(d - a/2)
Where, σst = yield stress of tension steel [σst = fy / γst],
γst = safety factor for tension steel [γst = 1.15A']
A' = area of tension steel, [A'' = b(d - a)].
Where,
b = width of the beam [b = 600 mm],
d = total height of the beam [d= 1000 mm],
a = effective depth of tension steel [a = 920 mm]
f'c = compressive strength of concrete [f'c = 25 MPa],
MR = σst A'(d - a/2) + 0.85f'c A''(d - a/2)
MR = (400 / 1.15) x 10 x (1000 - 920/2) + 0.85 x 25 x 590 x (1000 - 920/2)
MR = 291735.65 Nm
The moment resistance of the cross-section is 291735.65 Nm.
3) To check if this cross-section is adequately designed to resist the factored bending moment (LRFD), we need to calculate the factored moment demand and compare it with the moment resistance.
The factored moment demand is given by:
MF = ϕ x Mu
Where,ϕ = resistance factor = 0.9, Mu = factored bending moment
Mu = 1.2 x Dead Load x L2 / 8 + 1.6 x Live Load x L2 / 8 + 1.2 x (Dead Load + Live Load) x L2 / 2
= 1.2 x 35 x 152 / 8 + 1.6 x 3 x 152 / 8 + 1.2 x 38 x 152 / 2
= 31044 Nm
MF = ϕ x Mu
= 0.9 x 31044
= 27939.6 Nm
The factored moment demand is 27939.6 Nm, which is less than the moment resistance of the cross-section, i.e., 291735.65 Nm.
Therefore, this cross-section is adequately designed to resist the factored bending moment.
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A 75 kg softball player does a head-first dive and is sliding to a stop to the
right across the infield dirt. Her initial velocity was 4 m/s, and she comes to
a stop in 8 seconds. Find all forces. Ignore air resistance.
vf = vi + at
vf = 0
a = - (to stop (deceleration))
input the value:
0 = 4 m/s -a.8
8a = 4
a = 0.5 m/s²
F = m.a
F = 75 kg x 0.5 m/s²
F = 37.5 N
Please answer this question sqdancefan
Answer:
(D) 4
Explanation:
The percentage error in each of the contributors to the calculation is 1%. The maximum error in the calculation is approximately the sum of the errors of each contributor, multiplied by the number of times it is a factor in the calculation.
density = mass/volume
density = mass/(π(radius^2)(length))
So, mass and length are each a factor once, and radius is a factor twice. Then the total percentage error is approximately 1% +1% +2×1% = 4%.
_____
If you look at the maximum and minimum density, you find they are ...
{0.0611718, 0.0662668} g/(mm²·cm)
The ratio of the maximum value to the mean of these values is about 1.03998. So, the maximum is 3.998% higher than the "nominal" density.
The error is about 4%.
_____
Additional comment
If you work through the details of the math, you will see that the above-described sum of error percentages is just an approximation. If you need a more exact error estimate, it is best to work with the ranges of the numbers involved, and/or their distributions.
Using numbers with uniformly distributed errors will give different results than with normally distributed errors. When such distributions are involved, you need to carefully define what you mean by a maximum error. (By definition, normal distributions extend to infinity in both directions.) While the central limit theorem tends to apply, the actual shape of the error distribution may not be precisely normal.
Answer:
D. 4Explanation:
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justoko2
Which observations most likely led to Jenna’s conclusion?
a change of odor
a decrease in temperature
a change in moisture content
a decrease in mass
The findings that most likely contributed to Jenna's conclusion were a change in smell. Option A is correct.
What is odor?A fragrance, usually an unpleasant one: The smell of sweaty feet was palpable throughout the space. Our body odor has a big impact on the kinds of scents we enjoy.
The complete question is;
"Jenna pulled out an open bowl of leftover mashed potatoes from the fridge and smelled something different. She discovered that since the potatoes were initially placed there, chemical changes had taken place. Which facts most likely supported Jenna's judgment?
a change of odor
a decrease in temperature
a change in moisture content
a decrease in mass"
The observation that most likely inspired Jenna to draw her conclusion was a change in odor.
Hence, option A is correct.
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Answer:
A change in odor
Explanation:
Physics Homework will give Brainliest!
Answer: I
dk what rhe answer is but here is my prediction :)
Explanation:
If the rope is horizontal and the ball's speed is 10 m/s, what is the tension in the ... A 2 kg iron ball is swung in a horizontal circular path at the end of a 1.6 m length of rope. ... Freddie swings a 2 kg stone at the end of a thin rope of length 1.2 m. ... of an automobile tire that turns with a frequency of 11 Hz and has a linear speed ...
GP Q C Review. You can think of the work-kinetic energy theorem as a second theory of motion, parallel to Newton's laws in describing how outside influences affect the motion of an object. In this problem, solve parts (a), (b), and (c) separately from parts (d) and (e) so you can compare the predictions of the two theories. A 15.0-g bullet is accelerated from rest to a speed of 780m/s in a rifle barrel of length 72.0cm. (a) Find the kinetic energy of the bullet as it. leaves the barrel.
Simplifying this equation:
\(KE = 0.5 * 0.015 kg * 608,400 m^2/s^2KE = 4,564.5 J\)
Therefore, the kinetic energy of the bullet as it leaves the barrel is 4,564.5 Joules.
The kinetic energy of the bullet can be found using the formula:
\(Kinetic Energy (KE) = 0.5 * mass * velocity^2\)
First, we need to convert the mass of the bullet from grams to kilograms. Since 1 kg = 1000 g, the mass of the bullet is 15.0 g / 1000 = 0.015 kg.
The velocity of the bullet is given as 780 m/s.
Now we can plug these values into the formula to find the kinetic energy:
\(KE = 0.5 * 0.015 kg * (780 m/s)^2\)
In summary, the kinetic energy of the bullet can be found using the formula KE = 0.5 * mass * velocity^2. By plugging in the values for mass (converted to kilograms) and velocity, we can calculate that the kinetic energy is 4,564.5 Joules.
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Therefore, the kinetic energy of the bullet as it leaves the barrel is 45.945 Joules.
The kinetic energy of an object can be calculated using the formula: KE = 1/2 mv^2, where KE is the kinetic energy, m is the mass of the object, and v is the velocity of the object.
In this problem, we are given the mass of the bullet, which is 15.0 g.
To find the kinetic energy of the bullet as it leaves the barrel, we need to calculate its velocity.
The problem states that the bullet is accelerated from rest to a speed of 780 m/s in a rifle barrel of length 72.0 cm.
Since we are only interested in the kinetic energy of the bullet as it leaves the barrel, we can ignore the length of the barrel and focus on the final velocity.
To find the final velocity, we can use the equation of motion: v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity (which is 0 m/s since the bullet starts from rest), a is the acceleration, and s is the distance traveled.
In this case, the bullet starts from rest, so the initial velocity is 0 m/s. The final velocity is given as 780 m/s, and the distance traveled is the length of the barrel, which is 72.0 cm or 0.72 m.
Using the equation of motion, we can rearrange it to solve for acceleration: a = (v^2 - u^2) / (2s). Plugging in the values, we get a = (780^2 - 0) / (2 * 0.72) = 338,750 m/s^2.
Now that we have the acceleration, we can calculate the kinetic energy of the bullet using the formula KE = 1/2 mv^2. Plugging in the values, we get KE = 1/2 * 0.015 kg * 780^2 m^2/s^2 = 45.945 J.
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The event in the life of a star that begins its expansion into a giant is Group of answer choices almost all the hydrogen in its core that was hot enough for fusion has been turned into helium as much as 90% of the star explodes violently the core reaches a temperature of ten million degrees the star's internal structure reaches equilibrium for the first time in its life
The event in the life of a star that begins its expansion into a giant is that almost all the hydrogen in its core that was hot enough for fusion has been turned into helium.
What is a fusion reaction?A fusion reaction is defined as the type of nuclear reaction whereby two or more atomic nuclei combine to form a heavier nucleus.
The stars are being transformed into giants through fusion reaction.
A higher amount of hydrogen is found in the core of the star which is being use up in the fusion reaction to form helium.
When the hydrogen in the centre of a star runs out, the star begins to use hydrogen further out from its core. This causes the outer layers of the star to expand and cool.
Therefore, the event in the life of a star that begins its expansion into a giant is that almost all the hydrogen in its core that was hot enough for fusion has been turned into helium.
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The periodic wave in the diagram below has a frequency of 40 hertz. What
is the speed of the wave?
answers:
A. 120 m/s
B. 60 m/s
C. 27 m/s
D. 13 m/s
Answer:
60. m/s
60 m/s is the answer i hope this helps pls give me the brainliest
The speed of the wave will be 60 m/sec. The speed of the wave is wavelength and frequency.
What is frequency?Frequency is defined as the number of repetitions of a wave occurring wave in 1 second.
The given data in the problem is;
The frequency of periodic wave is,f= 40 hertz
The wavelength of the wave is,\(\lambda = 1.5 \ m\)
The speed of the wave is,v
The speed of the wave is;
\(\rm v = \lambda \times f \\\\\ \rm v = 1.5\times 40 \\\\\ v= 60 \ m/sec\)
Hence, the speed of the wave will be 60 m/sec.
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example of nuclear fission
Answer:
In nuclear power plants, energetic neutrons are directed into a sample of the isotope uranium-235. ... A common fission reaction produces barium-141 and krypton-92. In this particular reaction, one uranium nucleus breaks into a barium nucleus, a krypton nucleus, and two neutrons
Par is the expected number of strokes that it should take you to make it to the target in golf. O True O False
Two identical blocks are pushed up frictionless inclines as shown. Consider the portion of the motion of block 1 during which it moves a distance L1, and the portion of the motion of block 2 during which it moves a distance L2. Each block is displaced the same vertical distance Z.The hand pushes parallel to the incline with same magnitude of force FBH in both cases. Block 2 moves at a decreasing speed. Is the absolute value of the work done by the gravitational force on block 2 greater than, less than, or equal to the work done by the gravitational force on block 1? Explain.
The answers to these questions are:
The absolute value of the work done by hand on block 1 is less than the absolute value of the work done by the hand on block 2. The force by hand is the same on both blocks but the distance traveled by the block 1 along the incline (L2) is greater than the distance traveled by the block 1 ( L1).The absolute value of the work done by the gravitational force on block 1 is equal to the absolute value of the work done by the gravitational force on block 2. Both blocks travel the same height Z.The speed of block 2 increases. The net work done on block 2 is not zero as in the case of block 1. Hence the speed of the block increases.Therefore, Two identical blocks are pushed up frictionless .
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Derive an Expression for elastic potential energy of a spring
Answer:
spring force = -K × x , where X is elongation or compression in the spring. ( -) sigh shows that the spring force is opposite to the applied force to cause extension.
Potential energy = work done by spring force = integration of Force.
integrate the force (-K × x) over distance 0 to x .
U = 1/2 K × X^2 ( for elongation)
U = -1/2 × K × X^2 ( for compression)
What temperature has the Big Bang cooled to by now? A) about 3,000 K B) about 300 K C) 5,800 K D) just over 2.7 K E) 1.4 K
The temperature the Big Bang has cooled to by now is just over 2.7 K. T
The correct answer is option D.
The universe has cooled significantly since its beginning, and the current temperature is approximately 2.7 Kelvin, which is a result of the cosmic microwave background radiation.
The universe came into being around 13.8 billion years ago with the Big Bang. At that time, a hot, dense fog of radiation and elementary particles wafted in space, which was rapidly expanding. The density and temperature decreased just as quickly, and the light particles (photons) lost increasingly more energy. After about 380,000 years, this plasma had cooled down to 3000 Kelvin. It was then possible for stable atoms to be created. And the photons had a free path and spread out into space. The cosmos became transparent so to speak.
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Why does the moon appear to change its shape as seen from Earth
A.Different parts of the sunlit moon become visible as the moon revolves around the Earth
B.Different parts of the moon are lit as the moon rotates
C.The moon moves farther and then closer to Earth
D.The sun lights different parts of the moon during different seasons
Answer:
Explanation:
Why does the moon appear to change its shape as seen from Earth
A 65-kg student is in an elevator moving downward with constant velocity. He uses a bathroom scale to measure the upward force exerted on his feet.
What force magnitude does the scale read when the elevator is traveling at constant velocity?
What force magnitude does the scale read when the elevator slows to a stop with an acceleration of magnitude 2.0 m/s^2 ?
What force magnitude does the scale read when the elevator starts downward again with an acceleration of magnitude 2.0 m/s^2 ?
Force magnitude when elevator is traveling at constant velocity is, 637 N. Force magnitude does the scale read when the elevator slows to a stop is, 429 N (downward force). Force magnitude when elevator starts downward again is, 208 N.
Force magnitude when elevator is traveling at constant velocity, 65 kg x 9.8 m/s^2 = 637 N (upward force)
When the elevator slows to a stop with an acceleration of magnitude 2.0 m/s^2, the net force acting on the student is the sum of the gravitational force and the force exerted by the scale.
Net force: (65 kg) x (2.0 m/s^2) = 130 N (downward force)
Force magnitude when elevator slows to a stop: 637 N - 130 N = 507 N (upward force)
When the elevator starts moving downward again with an acceleration of magnitude 2.0 m/s^2, the net force is difference between the gravitational force and the force exerted by the scale,
Net force: (65 kg) x (9.8 m/s^2 - 2.0 m/s^2) = 429 N (downward force)
Force magnitude when elevator starts downward again: 637 N - 429 N = 208 N (upward force)
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A nurse counts 76 heartbeats in one minute.
What are the period (in seconds) and frequency (in Hz) of the heart’s oscillations?
The time period is 15/19 s = 0.79 s. The frequency is 76/60 Hz = 1.23Hz.
What is time period?
The amount of time that a behavior lasts or a condition persists. Depending on the type of activity or condition under consideration, it may be measured in seconds or in millions of years.
Given that the heartbeat is 76 heartbeats in one minute.
In other words: the heartbeat is 76 heartbeats in 60 sec.
The period is the Number of seconds/ number of heartbeats
= 60/76
=15/19 s
The frequency of a repeating event is its number of instances per unit of time. It differs from angular frequency and is sometimes referred to as temporal frequency for clarity. One event occurs every second when measuring frequency in hertz.
The frequency (in Hz) of the heart’s oscillations
= 76/60
= 19/15 Hz
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Please help I need this quick Thank you!
Analyze: The graph below shows the velocity vs. time graph of a city bus that drives passengers from downtown Los Angeles to the LAX airport.
a. What is the velocity of the bus between 10 and 15 minutes of the drive?
b. How far will the bus travel (in meters) between 10 and 15 minutes?
Answer:Bruh i need this too and aint nobody answered yet i-
Explanation:
Inside a freely-falling elevator, there would be no A) gravitational force on you. B) apparent weight for you. C) both of these D) none of these.
Inside a freely-falling elevator, there would be no apparent weight for you.So option B is correct.
Inside a freely-falling elevator, there is still a gravitational force acting on you. However, since both you and the elevator are falling at the same rate, you would experience a sensation of weightlessness. Your apparent weight, which is the force exerted on a body due to gravity, would be zero. This is because there is no contact force between you and the elevator floor that would provide a normal force to counteract gravity. Therefore, the correct option is that there would be no apparent weight for you.
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