What happens to the value of the universal gravitational constant G as a launched spacecraft moves farther and farther away from Earth

Answers

Answer 1

As a spacecraft moves farther away from Earth, the value of the universal gravitational constant G remains constant.

As a spacecraft moves farther away from Earth, the gravitational force between the spacecraft and Earth decreases. However, this change in gravitational force is not due to any variation in the value of the universal gravitational constant G. The gravitational constant G, approximately equal to 6.674 × \(10^{-11} m^3/(kg s^2)\), is a fundamental constant of nature.

G represents the strength of the gravitational force between two objects and is a fixed value that does not depend on distance. It is a universal constant that applies to all objects and bodies in the universe. Thus, as the spacecraft moves farther away from Earth, the decrease in gravitational force is due to the increasing distance and the inverse square law, which states that the gravitational force weakens with the square of the distance between the objects.

In summary, the value of the universal gravitational constant G remains constant as a spacecraft moves farther away from Earth, while the gravitational force weakens due to the increasing distance according to the inverse square law.

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Related Questions

what must a uranium-235 nucleus absorb before fission will happen​

Answers

Answer:

The arrangement of particles within uranium-235 is somewhat unstable and the nucleus can disintegrate if it is excited by an outside source. When a U-235 nucleus absorbs an extra neutron, it quickly breaks into two parts. This process is known as fission

Answer:

a nuetron

Explanation:

In a nuclear reactor , a neutron is absorbed into a nucleus (typically uranium-235). ... The fast moving neutrons carry most of the energy from the reaction with them (99%) but before the neutrons can collide with fresh uranium nuclei, they need to be slowed down

A) A force of 4. 40 N is applied to a dart over a distance of 54 cm. The dart has a mass of 28 g. Assuming no energy is lost due to friction, what will be the kinetic energy of the dart after it is thrown?

b) Use your result in part a) calculate the speed of the dart

c) If the dart were thrown straight upwards, what maximum height would it reach?

Answers

a) The kinetic energy of the dart after it is thrown is 2.376 J.

b) The speed of the dart is 18.45 m/s.

c) If the dart were thrown straight upwards, the maximum height it would reach is 17.0 m.

a) The work done on the dart by the applied force is given by:

work = force x distance = 4.40 N x 0.54 m = 2.376 J

Since no energy is lost due to friction, all of this work is converted to the kinetic energy of the dart:

kinetic energy = work = 2.376 J

b) The kinetic energy of the dart can also be expressed as:

kinetic energy = (1/2) x mass x velocity^2

Rearranging this equation gives:

velocity^2 = (2 x kinetic energy) / mass

Substituting the values from part a) gives:

velocity^2 = (2 x 2.376 J) / 0.028 kg = 340.29 m^2/s^2

Taking the square root of both sides gives:

velocity = 18.45 m/s

c) When the dart is thrown straight upwards, its initial vertical velocity is zero. The maximum height it will reach can be calculated using the formula:

maximum height = (initial velocity^2) / (2 x acceleration)

where acceleration is the acceleration due to gravity, which is approximately 9.81 m/s^2.

Substituting the speed calculated in part b) gives:

maximum height = (18.45 m/s)^2 / (2 x 9.81 m/s^2) = 17.0 m

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A force of 250N is applied on an object causing it to move for 6m at uniform velocity of 32m/s. Determine the (I) work done (ii)power developed

Answers

The power developed is 8000 W.

Given data:

Force = 250 N

Distance traveled = 6 m

Velocity = 32 m/s

Let's find out the work done on the object by the applied force.

Work done is given by the product of force and distance covered:

W = F × s

W = 250 × 6 = 1500 J

Thus, the work done on the object by the applied force is 1500 J.

Next, let's determine the power developed.

Power is defined as the rate at which work is done, i.e.,

P = W / t

where P is power, W is work done, and t is time taken to do that work.

We know that velocity = distance / time. Rearranging the above expression, we get:

t = d / v

Substituting the given values, we get:

t = 6 / 32

P = W / t

Substituting the calculated value of W and t, we get:

P = 1500 / (6 / 32)

P = 8000 W

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3. What is the potential energy of a 8 Newton book sitting on a shelf that is 12 meters high?​

Answers

Answer:

P = 96 J

Explanation:

Given that,

Weight of the book, W = mg = 8 N

It is placed at a height of 12 m

We need to find the potential energy of the book. The potential energy of an object is given by the formula as follows :

E = mgh

mg = Weight

\(E=8\ N\times 12\ m\\E=96\ J\)

So, the potential energy of the book is 96 J.

Where would you expect to find volcanic mountain ranges and why?

Answers

Answer:

Sixty percent of all active volcanoes occur at the boundaries between tectonic plates. Most volcanoes are found along a belt, called the “Ring of Fire” that encircles the Pacific Ocean. Some volcanoes, like those that form the Hawaiian Islands, occur in the interior of plates at areas called “hot spots.”

Explanation:

Volcanoes are found around tectonic plates because the convection currents move the plates. Where convection currents diverge near the Earth's crust, plates move apart. Where convection currents converge, plates move towards each other, plates converge and the plates move together, also known as ridge push, therefore mountains and volcanoes are formed

Hope this helps :)

A recurrent nova could eventually build up to a:
Select one:
A. planetary nebula.
B. quasar.
C. Type I supernova.
D. Type II supernova.
E. hypernova.

Answers

Option C. is correct. The recurrent nova has the potential to build up its mass over time and eventually reach the critical threshold for a Type I supernova.

Recurrent novae are binary star systems where a white dwarf accretes material from a companion star. When the accreted material reaches a critical mass, a thermonuclear explosion occurs on the surface of the white dwarf, resulting in a nova outburst. Unlike classical novae, recurrent novae experience multiple eruptions over time.

As a recurrent nova continues to accrete material, the mass of the white dwarf gradually increases. If the mass surpasses the Chandrasekhar limit of about 1.4 times the mass of the Sun, a Type I supernova can occur. In a Type I supernova, the white dwarf undergoes a catastrophic explosion, completely destroying the star.

Therefore, the recurrent nova has the potential to build up its mass over time and eventually reach the critical threshold for a Type I supernova.

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HELP ME PLEASE????????????????????????????????

Answers

Ofc
The answer is géstele to the point of view look to the right and boom walalalalalalalalalalallalalalalala

When you are riding in a car then the driver suddenly steps on the gas pedal, why do you feel a jolt and push back?

Answers

Answer:

Effects of Interia

As a more familiar example of inertia, think about riding in a car. ... If the car comes to a sudden stop, your body tends to keep moving forward. When the car starts moving again, your body tends to stay at rest. You move forward because the car seat exerts an unbalanced force on your body.

According to Newton's third law, action and reaction are equal and opposite.

What is Newton's third law?

According to Newton's third law, action and reaction are equal and opposite.

When the car suddenly stops due to the braking force, a reaction force counterbalances it which tends to move the passengers forward hence they all jolt forward.

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Suppose snow is falling in Utah. What type of air mass is responsible for this weather?

Answers

Maritime polar air mass comes from the northern part of the pasific ocean and that air mass goes to Utah.

the electromagnetic spectrum organizes electromagnetic waves based on their

Answers

All electromagnetic waves are organized into a continuum called the electromagnetic spectrum according to their frequency and wavelength.

What are frequency and wavelength?

The wavelength, which will also apply to troughs, is the separation between two wave crests. The frequency is measured on cycles per second (Hz), which is the quantity of vibrations that cross a specific area in a second (Hertz). In this article, the relationship between frequency and wavelength is covered.

What is an example of a wavelength?

Here are some wavelength examples: Yellow Light is a prime example. The wavelength range of all visible light is 400 to 700 nanometers (nm). The wavelength of yellow light is 570 nanometers or such. Wavelength (nm) (nm)

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it takes 2.27 ms for the current in an lr circuit to increase from zero to 0.74 its maximum value. part a determine the time constant of the circuit. express your answer to two significant figures and include the appropriate units.

Answers

it takes 2.27 m-s for the current in an l-r circuit to increase from zero to 0.74 its maximum value. part a determine the time constant of the circuit

To determine the time constant of the LR circuit,

We can use the equation:
Current (I) = Maximum Current (Imax) * (1 - e^(-t/τ))

Where:
- I is the current at time t
- Imax is the maximum current
- t is the time (2.27 m-s)
- τ is the time constant
- e is the base of the natural logarithm (approximately 2.718)

The student question provides the information that the current has reached 0.74 times its maximum value after 2.27 ms.

We can plug these values into the equation:
0.74 * Imax = Imax * (1 - e^(-2.27 m-s / τ))

Since we only need to find τ, we can divide both sides by Imax:
0.74 = 1 - e^(-2.27 m-s / τ)

Now, we can rearrange the equation to isolate τ:
1 - 0.74 = e^(-2.27 m-s / τ)
0.26 = e^(-2.27 m-s / τ)

To find τ, take the natural logarithm of both sides:
ln(0.26) = -2.27 m-s / τ

Finally, solve for τ:

τ = -2.27 m-s / ln(0.26)
τ ≈ 3.25 m-s

The time constant of the circuit is approximately 3.25 m-s.

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A 20 kg mass is hanging on one side of a pulley and a 5 kg mass is hanging on the other. Determine the acceleration of each mass.

Answers

Answer:

i believe it's 7

Explanation:

what is the value of boltzmann constant and where is it used?​

Answers

Answer:

the value of the boltzman constant 8.61 73303 into 10 ratio by - 5 EV upon knev

Select all that apply.

Which of the following are density labels?

Select all that apply.Which of the following are density labels?

Answers

Answer:

g/ml ,because 1 ml = 1 cm^3

and density unit is g/cm^3.

Question. 1 How much heat is necessary to warm 500g of water from 20°C to 65°C?​

Answers

Answer:

The heat necessary to warm 500g of water from 20°C to 65°C is 37,620 J.

Explanation:

GIVEN: m = 500 gm, T₂ = 65°C AND T₁  = 20°C, we know that c (specific heat capacity) = 4180

TO FIND: The heat necessary to warm 500g of water from 20°C to 65°C.

SOLUTION:

By using the heat equation,

              Q=m c ΔT  

             ΔT = T₂ - T1

             ΔT = 65 - 20 = 45°C

In this case,

Q = 0.2 × 4180 × 45 = 37,620 J

When a marble is at rest what happened

Answers

The marble will stay in place until another force pushes it

Answer: the marble will remain in place at a constant velocity of zero

Explanation:

Newton's first law states that a body at rest will remain at rest, and a body in motion will remain in motion in a straight line at a constant velocityunless acted upon by an outside force

which one is better yoga or exercise?

Answers

Answer:

Yoga because It brings together physical and mental disciplines to achieve a peaceful body and mind; it helps manage stress and anxiety and keeps you relaxing and exercising just builds muscles

Explanation:

have great day!

What is the chemical formula for silver and oxygen

Answers

Answer:Ag2 O.

The formula for silver oxide is Ag2 O.

Explanation: one silver atom gives up an electron resulting in a +1 ion. Each oxygen atom requires two electrons to be stable.

True or False: All waves transmit energy, but not matter, from one location to another.

Answers

This is true all waves do transfer energy but they do not transfer matter.

what is the apparent weight of a 95 KG astronaut on this rocket

what is the apparent weight of a 95 KG astronaut on this rocket

Answers

Given:

• Acceleration of rocket = 28.0 m/s²

,

• Mass of astronaut = 95 kg

Let's find the apparent weight of the astranaut.

In a direct rocket motion, as we are coming towards the Earth the weight reduces while as the rocket is going up, you feel more weighted.

Now, to find the apparent weight of the astranaut, apply the formula:

\(A_w=m(g+a)\)

Where:

Aw is the apparent weight

m is the mass = 95 kg

g is acceleration due to gravity = 9.8 m/s²

a is the acceleration of the rocket = 28.0 m/s²

Thus, we have:

\(\begin{gathered} A_w=95(9.8+28) \\ \\ A_w=95(37.8) \\ \\ A_w=3591\text{ N }\approx3.591\text{ kN} \end{gathered}\)

Therefore, the apparent weight of the astranaut is 3.591 kN

ANSWER:

3.591 kN

Question 6
Two ropes are attached to a tree, and forces of F₁ =2.01 +4.03 N and F₂=3.01+6.01 N
are applied. The forces are coplanar (in the same plane). Find the magnitude of the
net force.
15 N

Question 6Two ropes are attached to a tree, and forces of F =2.01 +4.03 N and F=3.01+6.01 Nare applied.

Answers

The net force has a magnitude of C, 5.0 N.

How to determine magnitude?

To find the net force, add the two forces vectorially. Break down each force into its x and y components:

F₁ = (2.01 N)î + (4.03 N)ĵ

F₂ = (3.01 N)î + (6.01 N)ĵ

To find the net force, add the components:

F_net = F₁ + F₂ = (2.01 N + 3.01 N)î + (4.03 N + 6.01 N)ĵ

F_net = 5.02î + 10.04ĵ

The magnitude of the net force is given by:

|F_net| = √((5.02 N)² + (10.04 N)²)

|F_net| = √(25.2004 N²)

|F_net| = 5.02 N (rounded to two decimal places)

Therefore, the magnitude of the net force is 5.0 N.

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a drag racer starts her car from rest and accelerates at 6.8 m/s 2 for the entire distance of 340 m. how long did it take the car to travel this distance? answer in units of s

Answers

Since the car is at rest, its starting speed is 0 m/s, its acceleration is 6.8 m/s2, and the distance the car must travel is 340 m. t =100s

How fast are they moving initially and ultimately?

An object's initial velocity is the rate at which gravity exerts its first force on it. However, the final mass and velocity quantity that gauges the speed and direction of a moving object after it has reached the maximum level acceleration.

Is there a constant initial speed?

The starting velocity of an automobile is zero while it is at rest. Its initial velocity would be greater than zero if a projectile is thrown into the area. The starting velocity will be greater than zero but will become zero if a car stops after pressing the brakes.

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What does saliva begin to break down in the mouth?
answers QUICK I will make you brainst !

Answers

An enzyme called amylase breaks down starches (complex carbohydrates) into sugars, which your body can more easily absorb. Saliva also contains an enzyme called lingual lipase, which breaks down fats.

Can someone help me plz

Can someone help me plz

Answers

answer: High tide

Explanation:

What is the volume of a cone with a height of 27cm and a radius of 13cm? And your answer to the nearest tenth

Answers

Answer:

the volume of the cone is \(4778.36 cm^3\)

Explanation:

The computation of the volume of the cone is shown below:

As we know that

The Volume of the cone is

r denotes the radius

And, h denotes the height

So,

\(= \frac{1}{3} \pi r^2 h \\\\= \frac{1}{3} \times 3.14 \times 13^2 \times 27\\\\= 4778.36 cm^3\)

Hence, the volume of the cone is \(4778.36 cm^3\)

3. A body accelerates constantly at 4m/s² from rest for a distance of 60m. a) How long did it take to reach a distance of 60m? [2] b) Calculate the velocity reached.​

Answers

Answer:

will you mark brainliest.

if you look at yourself in a shiny christmas tree ball with a diameter of 8.8 cm when your face is 25.0 cm away from it, where is your image? express your answer using two significant figures.

Answers

The image of myself, when looking at a shiny Christmas tree ball with a diameter of 8.8 cm from a distance of 25.0 cm, is located 7.1 cm behind the ball.

Find the location of the image?

To determine the location of the image, we can use the mirror equation:

1/f = 1/d₀ + 1/dᵢ

where f is the focal length of the mirror, d₀ is the object distance, and dᵢ is the image distance.

In this case, the Christmas tree ball acts as a convex mirror, and its focal length (f) can be approximated as half its radius, which is 4.4 cm.

Given that the object distance (d₀) is 25.0 cm, we can rearrange the mirror equation to solve for the image distance (dᵢ).

1/dᵢ = 1/f - 1/d₀

1/dᵢ = 1/4.4 - 1/25.0

1/dᵢ ≈ 0.2273 - 0.0400

1/dᵢ ≈ 0.1873

Taking the reciprocal of both sides gives:

dᵢ ≈ 1 / 0.1873

dᵢ ≈ 5.34 cm

Since the image distance (dᵢ) is positive, the image is formed on the same side as the object. Therefore, the image is located approximately 7.1 cm behind the ball (toward the observer).

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Four forces are acting on an object. Force A is 50 N up. Force B is 30 N down. Force C is 25 N up, and Force D is 10 N
down. What is the net force on the object?

Answers

Answer:

The net force on the object is 35 N directed up.

Explanation:

Net Force

The force is a vector because it has magnitude and direction. The net force is the sum of all the individual forces acting on an object.

Let's assume the forces directed upward are positive and the forces directed down are negative.

Force A: +50 N

Force B: -30 N

Force C: +25 N

Force D: -10 N

Net Force= 50 - 30 + 25 - 10 = 35 N

The net force on the object is 35 N directed up.

which of the statements regarding potential energy is true? potential energy cannot be stored and is immediately converted to kinetic energy. potential energy is the energy that an object has based on its position. the potential energy of an object cannot be determined. an object in motion does not have any potential energy.

Answers

The correct statement regarding potential energy is that "potential energy is the energy that an object has based on its position."

This means that an object has the potential to do work based on its position in relation to other objects or forces. For example, a ball at the top of a hill has potential energy due to its position at the top of the hill, and this potential energy can be converted into kinetic energy as the ball rolls down the hill.

The other statements about potential energy are not true.

Potential energy can be stored and is not immediately converted to kinetic energy.

The potential energy of an object can be determined using the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object.

And finally, an object in motion can still have potential energy, such as a pendulum swinging back and forth.

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a dynamite blast at a quarry launches a rock straight upward, and 2.1 s later it is rising at a rate of 12 m/s. assuming air resistance has no effect on the rock, calculate its speed (a) at launch and (b) 4.5 s after launch.

Answers

The rock was launched in the upward direction with an initial velocity of 8.58 m/s.The speed of the rock 4.5 seconds after launch is  35.52 m/s.

Given:

Time after launch (t) = 2.1 s

Rising rate (v) = 12 m/s

(a) By using the equation of motion v = u + at

where,

v denotes the final velocity, u initial velocity, a is the acceleration, and t is the time.

v = u + at

12= u + (9.8) × 2.1 s

u = 12 - (9.8 m/s² × 2.1 s)

u = 12 - 20.58

u = -8.58 m/s

The negative sign indicates that the rock was launched in the upward direction with an initial velocity of 8.58 m/s.

(b) To calculate the speed 4.5 seconds after launch,

v = u + at

v = -8.58 + (9.8) × 4.5 s

v = 35.52 m/s

The speed of the rock 4.5 seconds after launch is  35.52 m/s.

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