Answer:
Below
Explanation:
A VOLTAGE is induced across the coil.... if the ends of the coil are connected together or to a circuit, a current will flow
Can you list out the signs (positive or negative) of objective and eyepiece of microscope (simple and compund) and telescope?
NO SPAM ❌❌
For compound microscope: the objective lens produces a real, inverted image that is then magnified by the eyepiece lens to produce an upright, virtual image.
For simple microscope: The objective lens produces a real, inverted image that is viewed directly by the eye without the need for an eyepiece lens.
For telescope: The objective lens or mirror produces a real, inverted image that is then magnified by the eyepiece lens to produce an upright, virtual image. The eyepiece can be positive or negative depending on the desired magnification.
What are objective and eyepieces?The following are some signs (positive or negative) of objective and eyepiece lenses in microscopes and telescopes:
Objective lens:
Positive sign (+): used for normal, upright specimens; brings light rays to a focus in front of the lensNegative sign (-): used for inverted specimens; brings light rays to a focus behind the lensEyepiece lens:
Positive sign (+): increases the magnification of the image and produces a larger virtual imageNegative sign (-): decreases the magnification of the image and produces a smaller virtual imageLearn more about objective and eyepiece here: https://brainly.com/question/14055649
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What color light can you add to cyan light to make green?
To make green light from cyan light, you need to add red light to it. Cyan light has a wavelength of around 490-520 nanometers, which means it is close to blue-green on the visible spectrum. When you add red light, which has a wavelength of around 620-750 nanometers, the combination of the two colors will produce green light. This is because red and cyan are complementary colors, meaning they are opposite each other on the color wheel, and when mixed together, they produce green light.
~~~Harsha~~~
Answer:
yellow light
Explanation:
Yellow light can be added to cyan light to make green.
consider a long, closely wound solenoid with 10,000 turns per meter.
The current needed in the solenoid to produce a magnetic field inside, near its center, that is 1/10th times the Earth's magnetic field of 10 µT is approximately 1 A.
Determine the magnetic field inside the solenoid?The magnetic field inside a long solenoid is given by the formula B = μ₀ * n * I, where B is the magnetic field, μ₀ is the permeability of free space, n is the number of turns per unit length (in this case, 10,000 turns/m), and I is the current.
We are given that the desired magnetic field is 1/10th times the Earth's magnetic field, which is 10 µT. Converting 10 µT to Tesla gives 10 * 10⁻⁶ T.
Substituting the given values into the formula, we have 10 * 10⁻⁶ T = (4π * 10⁻⁷ T·m/A) * (10,000 turns/m) * I.
Simplifying the equation and solving for I, we find I ≈ 1 A. Therefore, a current of approximately 1 Ampere is needed in the solenoid to produce a magnetic field inside, near its center, that is 1/10th times the Earth's magnetic field.
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Complete question here:
AM (10%) Problem 10: Consider a long, closely wound solenoid with 10,000 turns per meter. What curent, in ampere. is seeded in the solenoid to produce a magnetic field inside the solenoid. near its centers hat is 1of times the Earth's m feld of 10 rade Summa
derive an expression for the heat transfer rate through the x =l
The heat transfer rate through a material with a thickness of x = l can be expressed as q = -kA(dT/dx), where q is the heat transfer rate, k is the thermal conductivity, A is the cross-sectional area, and (dT/dx) is the temperature gradient across the material.
Heat transfer is the process of thermal energy transfer from one object or region to another due to a temperature difference. The rate of heat transfer, denoted as q, can be determined using Fourier's Law of heat conduction. In the case of a material with a thickness of x = l, the heat transfer rate can be expressed as q = -kA(dT/dx), where k is the thermal conductivity of the material, A is the cross-sectional area perpendicular to the heat flow direction, and (dT/dx) represents the temperature gradient across the material.
The negative sign in the equation indicates that heat transfers from regions of higher temperature to regions of lower temperature. The thermal conductivity, k, is a material property that describes how well a material conducts heat. It quantifies the amount of heat energy transferred per unit area per unit time for a temperature difference of 1 degree Celsius. The cross-sectional area, A, is the area perpendicular to the direction of heat flow. The temperature gradient, (dT/dx), represents the change in temperature with respect to the distance along the material. It indicates how the temperature varies as we move through the material from one side (x = 0) to the other side (x = l).
By using this expression, we can calculate the heat transfer rate through a material with a thickness of x = l, taking into account the material's thermal conductivity, cross-sectional area, and temperature gradient.
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On Planet X, an astronaut has maximum walking speed of 1.9 m/s. The astronaut's legs are each 1.3 m long. What is the constant of acceleration due to gravity on Planet X?
A. 8.3 m/s2
B. 2.8 m/s2
C. 3.8 m/s2
D. 1.1 m/s2
Answer:
Acceleration due to Gravity:
Explanation:
Here g is acceleration due to gravity. So C. 3.8 m/s2
A boy is twirling a model airplane on a string 4 feet long. if he twirls the plane at 0.25 revolutions per minute, how far does the plane travel in 4 minutes? round to the nearest tenth.
Answer:
25.13 ft
Explanation:
r = 4 feet
ω=0.25 revolution per minute
=1 revolution in 4 minutes
total number of revolution N = 1 (in 4 minutes )
v=rω
distance traveled = 2×N×π×r
=2×1×π×4
=8π
= 25.13ft in 4mins
when light is incident on an interface between two materials, the angle of the refracted ray depends on the wavelength, but the angle of the reflected ray does not. why should this be true
Because different visible light colors have distinct wavelengths and barely varying refractive indices, the wavelength of the light influences the angle of refraction.
For instance, you cannot tell the difference when white light passes through a flat piece of glass because it is so slight.
The reflected beam will always be refracted at the same angle that it impacted the surface since light will then continue to go through the same medium and at the same speed.
A periodic wave's wavelength is its spatial period, or the length over which its shape repeats. It is a property of both travelling waves and standing waves as well as other spatial wave patterns. It is the distance between two successive corresponding locations of the same phase on the wave, such as two nearby crests, troughs, or zero crossings.
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the postive part of atoms
Answer:
The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge). The outermost regions of the atom are called electron shells and contain the electrons (negatively charged)
Explanation:
4. A boy on a 2.0 kg skateboard initially at rest tosses an 8.0 kg jug of water
in the forward direction. If the jug has a speed of 3.0 m/s relative to the
ground and the boy and skateboard move in the opposite direction at 0.60
m/s, find the boy's mass.
The boy's mass is approximately 9.75 kg.
According to the law of conservation of momentum, the total momentum of the system before the water jug is tossed should be equal to the total momentum of the system after the water jug is tossed. The momentum of an object of mass m moving at a velocity v is given by the product of the mass and velocity, i.e., p = mv. Therefore, we can write:
(m1 + m2)vi = m1v1 + m2v2
where m1 and v1 are the mass and velocity of the skateboard and boy before the water jug is tossed, m2 and v2 are the mass and velocity of the water jug after it is tossed, and vi is the initial velocity of the system (which is zero).
Substituting the given values, we get:
(2.0 kg + m) × 0 = 2.0 kg × (-0.60 m/s) + 8.0 kg × 3.0 m/s
Simplifying, we get:
-1.2 m/s × 2.0 kg = 8.0 kg × 3.0 m/s - 2.0 kg × 0.60 m/s
-2.4 kg⋅m/s = 23.4 kg⋅m/s
Solving for m, we get:
m = (23.4 kg⋅m/s) / (2.4 kg⋅m/s) ≈ 9.75 kg
Therefore, the boy's mass is approximately 9.75 kg.
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An incompressible Newtonian fluid flows steadily between two infinitely long, concentric cylinders of radius ri and ro, for the inner and outer cylinders, respectively. Outer cylinder is fixed and the inner cylinder moves horizontally with a uniform velocity Vi. Assuming laminar, axisymmetric and fully-developed flow, determine the velocity distribution in the gap. Find expression for Vi (in terms of other relevant variables) that the drag on the inner cylinder becomes zero.
The velocity distribution in the gap between two infinitely long, concentric cylinders of radius ri and ro, for the inner and outer cylinders, respectively, assuming laminar, axisymmetric and fully-developed flow is given by the following equation: u(r) = (ri^2 - r^2)V_i / (2ro^2 - 2ri^2)
The velocity distribution in the gap between two infinitely long, concentric cylinders of radius ri and ro, for the inner and outer cylinders, respectively, assuming laminar, axisymmetric and fully-developed flow can be determined using the following steps:
Assume that the flow is laminar. This means that the flow is smooth and there are no eddies or turbulence.
Assume that the flow is axisymmetric. This means that the flow is the same in all directions around the axis of the cylinders.
Assume that the flow is fully developed. This means that the velocity profile is the same at all distances from the axis of the cylinders.
With these assumptions, the velocity distribution can be determined using the Navier-Stokes equations. The Navier-Stokes equations are a set of equations that govern the motion of fluids.
The solution to the Navier-Stokes equations for the velocity distribution in the gap between two infinitely long, concentric cylinders of radius ri and ro, for the inner and outer cylinders, respectively, assuming laminar, axisymmetric and fully-developed flow is given by the following equation:
u(r) = (ri^2 - r^2)V_i / (2ro^2 - 2ri^2)
where:
u(r) is the velocity at a distance r from the center of the inner cylinder
ri is the radius of the inner cylinder.
V_i is the velocity of the inner cylinder.
This is the velocity distribution in the gap between two infinitely long, concentric cylinders of radius ri and ro, for the inner and outer cylinders, respectively, assuming laminar, axisymmetric and fully-developed flow.
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A car drives 16 miles south and then 12 miles west. What is the magnitude of the car’s displacement?
Answer:20 miles
Explanation:
The increase in resistant strains of insects to chemicals is a result of:
A. natural selection creating new organisms
B. evolution of new species
C. increase in those offspring who inherited resistant traits from their parents
D. all of the above
Answer:
answer D. all of the above
a metallic surface is illuminated with light of wavelength 400 nm. if the work function for this metal is 2.4 eV. what is the maximum kinetic energy of the ejected electrons, in electron volts?
Assume that
1 eV = 1.6 * 10^-19
c = 3 * 10^8
h = 6.626 * 10^-34
I already got the answer before and I know that the max kinetic energy is 0.71 eV but when I tried to solve it again, I forgot what to do.
I tried getting the cut off wave lengths and using that combined with the wavelength provided to get the K.E max but it didn't work
The maximum kinetic energy of the ejected electrons will be 0.71 eV.
What is the kinetic energy of electrons?The kinetic energy (KE) of electrons is defined as the product of one-half of the mass of the electron to the square of the velocity at which electrons spin in orbit.
Given data;
λ(Wavelength)= 400 × 10⁻⁹ m
Φ(Work function)=2.4 eV
c(Speed of light)= 3 ×10⁸ m/sec
h(Constant) = 6.626 * 10^-34
\(\rm \phi = 2.4 eV = 2.4 \times 1.6 \times 10^{-19} \\\\ \rm \phi =3.84 \times 10^{-19} \ J\)
The maximum kinetic energy is found as;
\(\rm KE= \frac{hc}{\lambda} - \phi \\\\ KE= \frac{6.64 \times 10^{-34}}{400 \times 10^{-9}} -3.84 \times 10^{-19} \\\\ KE=1.14\times 10^{-19} \ J\)
Unit conversion:
1 eV = 1.6 * 10⁻¹⁹ j
1 J=1/( 1.6 * 10⁻¹⁹) ev
KE=0.71 eV
Hence, the maximum kinetic energy of the ejected electrons will be 0.71 eV.
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14. A 75 kg BASEBALL PLAYER RUNS AT A VELOCITY OF 10 m/s TO GET TO SECOND BASE. IN
ORDER TO GET TO THIRD BASE QUICKLY SHE INCREASES HER SPEED TO 12 m/s.
DETERMINE THE WORK DONE BY THE BASEBALL PLAYER.
A. 1650 J
B. 1550 J
C. -1650 J
D. -1550 J
Answer:
-1650 J
Explanation:
When an object moves at a certain velocity v0 and changes it to v1, a change in its kinetic energy is achieved.
what is 40% of 230 i need to know soon plz im only 7
Answer:it's 92 my friend
Explanation:
have a great day
Answer:
92
Explanation:
0.4 · 230 = 92
Which statement indicates that motion has occurred?
A. The reference point has changed.
B. The position of the object has changed.
C.The object has not changed.
D. The object being described has changed
What is the current that is flowing through a wire that has a magnetic field strength of 8.20 x 10^-4 T at a distance of 0.00500 m from the wire?
The current flowing through the wire is approximately 6.503 Amperes.
To determine the current flowing through a wire based on the magnetic field strength at a given distance, you need additional information. The magnetic field strength around a straight wire is given by Ampere's law, which relates the field strength (B) to the current (I) and the distance (r) from the wire. The equation is as follows:
B = (μ₀ * I) / (2π * r)
Where:
B is the magnetic field strength,
I is the current,
r is the distance from the wire,
μ₀ is the permeability of free space (μ₀ = 4π × 10^(-7) T·m/A).
In your case, you are given the magnetic field strength (B = 8.20 x 10^(-4) T) and the distance (r = 0.00500 m) but not the current (I). Therefore, we rearrange the equation to solve for I:
I = (B * 2π * r) / μ₀
Now, let's calculate the current:
I = (8.20 x 10^(-4) T * 2π * 0.00500 m) / (4π × 10^(-7) T·m/A)
Simplifying the equation:
I = (8.20 x 10^(-4) T * 0.0314159265 m) / (4π × 10^(-7) T·m/A)
I ≈ 6.503 A
Therefore, the current flowing through the wire is approximately 6.503 Amperes.
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Sounds with frequency greater than 20 000Hz
Answer:
sound with frequency greater than 20000 hz is infrasonic sound
Determine: The speed of a 6.6 MeV proton. The speed of a 12 MeV helium atom. The specific type of particle that has 1.14 keV of kinetic energy when moving with a speed of 2.0×10^7m/s.
The speed of a 6.6 MeV proton is approximately 1.53 x 10^8 m/s.
The speed of a 12 MeV helium atom is approximately 2.50 x 10^8 m/s.
To determine the speed of a 6.6 MeV proton, we can use the equation for the kinetic energy of a particle:
K = (1/2)mv^2
where K is the kinetic energy, m is the mass of the particle, and v is its speed. Rearranging the equation to solve for v, we get:
v = √(2K/m)
The mass of a proton is approximately 1.67 x 10^-27 kg. Substituting K = 6.6 MeV = 6.6 x 10^6 eV and m = 1.67 x 10^-27 kg, we get:
v = √(2 x 6.6 x 10^6 eV / 1.67 x 10^-27 kg) = 1.53 x 10^8 m/s
Therefore, the speed of a 6.6 MeV proton is approximately 1.53 x 10^8 m/s.
To determine the speed of a 12 MeV helium atom, we can use the same equation:
v = √(2K/m)
The mass of a helium atom is approximately 6.64 x 10^-27 kg (the mass of two protons and two neutrons). Substituting K = 12 MeV = 12 x 10^6 eV and m = 6.64 x 10^-27 kg, we get:
v = √(2 x 12 x 10^6 eV / 6.64 x 10^-27 kg) = 2.50 x 10^8 m/s
Therefore, the speed of a 12 MeV helium atom is approximately 2.50 x 10^8 m/s.
To determine the specific type of particle that has 1.14 keV of kinetic energy when moving with a speed of 2.0 x 10^7 m/s, we can again use the same equation:
K = (1/2)mv^2
Rearranging to solve for m, we get:
m = 2K/v^2
Substituting K = 1.14 keV = 1.14 x 10^3 eV and v = 2.0 x 10^7 m/s, we get:
m = 2 x 1.14 x 10^3 eV / (2.0 x 10^7 m/s)^2 = 2.85 x 10^-27 kg
This mass corresponds to that of an electron. Therefore, the particle with 1.14 keV of kinetic energy when moving with a speed of 2.0 x 10^7 m/s is an electron.
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radiation of a certain wavelength causes electrons with a maximum kinetic energy of 0.60 ev to be ejected from a metal whose work function is 2.90 v. what will be the maximum kinetic energy with which this same radiation ejects electrons from another metal whose work function is 2.19 ev?
The maximum kinetic energy with which the same radiation ejects electrons from another metal with a work function of 2.19 eV is 1.31 eV.
When radiation of a certain wavelength falls on a metal surface, it can eject electrons from the surface if the energy of the radiation is greater than the work function of the metal. The work function is the minimum energy required to remove an electron from the metal surface. The maximum kinetic energy of the ejected electrons depends on the difference between the energy of the radiation and the work function of the metal. If the maximum kinetic energy of the ejected electrons is 0.60 eV for one metal with a work function of 2.90 eV, then the energy of the radiation can be calculated as 3.50 eV. Using this same radiation, the maximum kinetic energy of the ejected electrons for another metal with a work function of 2.19 eV can be calculated as 1.31 eV. This is because the difference between the energy of the radiation and the work function of the second metal is 3.50 eV - 2.19 eV = 1.31 eV.
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a child sprays her sister with water from a garden hose. the water is supplied to the hose at a rate of 0.123 l/s, and the diameter of the nozzle is 5.43 mm. at what speed ???? does the water exit the nozzle?
The water exists the nozzle at the speed of 5.315 m/s when rate of flow and diameter is given.
What is the water flow rate?Your water flow rate is the measurement of how many gallons of water could potentially come out of your kitchen faucet or bathtub per minute.
Given, Rate of flow= 0.123 l/s = 0.000123 m^3/s
and d= 5.43 mm= 0.00543m
r= 2.715 * 10^-3
Flow rate= water velocity * area of the nozzle
Area of nozzle = π* r²
= 3.14 *( 2.715 * 10^-3)²
= 2.314 * 10^-5
0.000123 = V * 2.314 * 10^-5
Speed at which the water exits= 5.315 m/s
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At what conditions acceleration of a body is zero?
Answer:
when there is uniform velocity the acceleration of a body is zero
THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THANKS!!!
THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THANKS!!!
What is the fundamental frequency of a mandolin string that is 42.0 cm long when the speed of waves of the string is 329 m/s?
Answer:
391.67Hz
Explanation:
The fundamental frequency formula in string is expressed as;
Fo = V/2L
V is the velocity of the wave = 329m/s
L is the length of the string = 42cm = 0.42m
Substitute
Fo = 329/2(0.42)
Fo = 329/0.84
Fo = 391.67Hertz
Hence the fundamental frequency of a mandolin string is 391.67Hz
a horizontal, 2.00 m long, 3.00 kg uniform beam that lies along the east-west direction is acted on by two forces. at the east end of the beam, a 200 n force pushes downward. at the west end of the beam, a 200 n force pushed upward. what is the torque about the center of mass of the beam?
The torque about the center of mass of the beam is 0 Nm.
To calculate the torque about the center of mass of the beam, follow these steps:
1. Identify the forces acting on the beam:
At the east end, there is a 200 N downward force, and at the west end, there is a 200 N upward force.
2. Calculate the distance from the center of mass to each force:
Since the beam is 2.00 m long, the center of mass is at the midpoint, which is 1.00 m from each end.
3. Calculate the torque due to each force:
Torque is the product of force and the perpendicular distance from the center of mass.
For each force, the torque will be 200 N * 1.00 m = 200 Nm.
4. Determine the direction of each torque:
The downward force at the east end creates a counterclockwise torque, while the upward force at the west end creates a clockwise torque.
5. Calculate the net torque about the center of mass:
Since both torques have the same magnitude but act in opposite directions, the net torque is 0 Nm.
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In the reaction shown, iron reacts with water to form iron oxide (Fe3O4) and hydrogen gas (H₂).
3Fe + 4H₂0
Fe3O4 + 4H₂
Which of these BEST describes the iron (Fe) reactant?
A. molecule
B. ion
C. compound
D. Element
Cold water does not react with iron. Iron, however, interacts with steam to create iron and hydrogen oxide. Fe3O4 + 4H2 = 3Fe(s) + 4H2O. Iron (II, III) oxide, also known as ferric oxide (Fe3O4), is a combination of Fe O and Fe2O3.
What happens when water and iron are combined?Ferric oxide (Fe2O3) and hydrogen gas are produced when ferrous oxide (Fe O) and water (H2O) combine (H2). This reaction yields a black solid called Fe3O4, which is frequently used as an antirust pigment. Understanding the chemical equation for this reaction is required to determine whether a specific mixture will produce Fe3O4: 2Fe3+(aq)+3H2 = 2Fe(s)+3H2(g) (g). According to this equation, two moles of iron metal will interact with to create two moles of ferric ion and three moles of hydrogen gas, it takes three moles of hydrogen gas. All of the iron will be transformed to Fe3+ ions and no Fe3O4 will occur if the combination only contains one mole of each component.
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Please refer to the picture
Answer:
I think it's D :)
Explanation:
astronomers can now report that active star formation was going on at a time when the universe was only 20% as old as it is today. when astronomers make such a statement, how can they know what was happening inside galaxies way back then? a.they look at a graph that shows the way galaxy redshifts change with time b.they examine the spectra of galaxies (or the overall colors of galaxies) with the highest redshifts they can find c.they look at radio waves coming from nearby active galaxies d.they look at the elements in comets, which formed when our solar system was first forming e.they look at the open clusters in the milky way galaxy
Astronomers can now report that active star formation was going on at a time when the universe was only 20% as old as it is today. when astronomers make such a statement, they examine the spectra of galaxies (or the overall colors of galaxies) with the highest redshifts they can find.
SO option B is correct.
Who are Astronomers?An astronomer is described as a scientist in the field of astronomy who focuses their studies on a specific question or field outside the scope of Earth by observing astronomical objects such as stars, planets, moons, comets and galaxies – in either observational or theoretical astronomy.
Astronomers are known to use redshifts to measure how the universe is expanding, and thus to determine the distance to our universe's most distant and therefore oldest objects.
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pls help guys this is my 7th time posting XD
Answer:
Explanation:
initial velocity u = 54 km/h = 15 m/s
final velocity v = 18 km/h = 5 m/s
distance s = 10 m
1. v^2 = u^2 + 2as
5^2 = 15^2 + 2a × 10
25 = 225 + 20a
25 - 225 = 20a
20 a = -200
a = -200/2
a = -100m/s^2
∴Deacceleration = -100m/s^2
2. v = u + at
5 = 15 -100t
5-15 = -100t
-10 = -100t
t = 100 / 10
∴t = 10 sec
Total distance covered by the car 10 m
To me, the hardest part of this whole thing is keeping the units straight. We're starting out with information given to us in kilometers, hours, and meters, and we have to come up with answers in m/s² , seconds, and meters.
When I worked this problem, I jumped right in without thinking, and I immediately got bogged down when I had to go off to the side and convert some units.
Now I know better. THIS time, before we get all tangled up trying to solve anything, let's get clever and change everything to m/s right now !
(54 km/hour) · (1,000m/km) · (1 hour/3600 sec) = 15 meters/second
(18 km/hour) · (1,000 m/km) · (1 hour/3600 sec) = 5 meters/second
NOW I'll betcha it's gonna be about 70% faster and easier !
i). Acceleration = (change in speed / time for the change)
We know the distance, but not the time. I know there's a formula for it, but I've learned so many formulas during my lifetime that I can't remember ALL of them. So I just memorize some of them, and I work things out from the formulas that I know. Here's how I do time:)
Average speed during the given slow-down = (1/2)·(15+5) = 10 m/s
Distance covered during the given slow-down = 10 m.
Time = (distance) / (average speed) = (10m) / (10 m/s) = 1 second
Acceleration = (change in speed) / (time for the change)
Acceleration = (5 m/s - 15 m/s) / (1 second)
Acceleration = (-10 m/s) / (1 second)
Acceleration = -10 m/s² (or 'Deceleration' = 10 m/s² )
_____________________________________________
For parts ii). and iii)., there's a big shift in the question.
It only gave you the slow-down from 54 to 18 km/hr for the purpose of calculating the deceleration. NOW, for the rest of the answers, it's talking about a complete stop ... 0 m/s .
____________________________________________
ii). Time required to stop = (initial speed) / (deceleration)
Time to stop from 54 km/hr = (15 m/s) / (10 m/s²)
Time to stop = 1.5 seconds
iii). Distance covered = (average speed) · (time to stop)
Distance covered = (7.5 m/s) · (1.5 sec)
Distance covered = 11.25 meters
OR ... use the official formula:
Distance = (1/2) · (acceleration) · (time² )
Distance = (1/2) · (10 m/s²) · (1.5 sec)²
Distance = 11.25 meters yay !
explain why a sharp point needle pierce easily than a blunt edge
A sharp point needle pierce easily than a blunt edge, because of high pressure of needle. Pressure is nothing but the force per unit area. in he needle there is force applied on very small area therefore it has high pressure applied on the area. whereas, blunt edge has large area for equal force, that is why.
Pressure is defined as the force applied perpendicular to an object's surface per unit area across which that force is dispersed. Gauge pressure is the pressure in relation to the surrounding atmosphere. Pressure is expressed using a variety of units.
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1. Wave equation A. Show that the conservation of momentum equation can be written in terms of the дф. Ət' velocity potential as po (VQ£ + 1/2V|V4|²) + Vp = 0, where ₁ = B. Using the adiabati
The given equation, po (VQ£ + 1/2V|V4|²) + Vp = 0 can be obtained by substituting the expressions for pressure and velocity potential in terms of the дф. Ət. To derive the main answer from the given information, the following explanation can be used:
The wave equation is the second-order partial differential equation for describing wave propagation. The conservation of momentum equation can be written in terms of the дф. Ət' velocity potential as po (VQ£ + 1/2V|V4|²) + Vp = 0, where ₁ = The potential energy of a fluid flow per unit volume can be defined as V = ρgy. Here, ρ is the density of the fluid, g is the acceleration due to gravity, and y is the height of the fluid column.
According to the Bernoulli's principle, the sum of the kinetic energy and the potential energy of a fluid flow is constant along a streamline. The conservation of momentum equation can be derived from the Bernoulli's principle by considering the forces acting on a fluid element. The forces acting on a fluid element include the pressure force, the gravitational force, and the viscous force. The pressure force can be expressed in terms of the velocity potential, while the gravitational force can be expressed in terms of the potential energy. The viscous force can be neglected for inviscid flow. The conservation of momentum equation can be written as po (VQ£ + 1/2V|V4|²) + Vp = 0, where ₁ = The potential energy per unit mass of a fluid flow can be expressed as P = ργ, where γ is the gravitational potential. According to the adiabatic condition, the change in temperature of a fluid flow due to the expansion or compression is negligible. The adiabatic condition can be used to derive the equation of state for an ideal gas. The equation of state for an ideal gas can be written as PVᵏ = constant, where P is the pressure, V is the volume, and k is the adiabatic index. The adiabatic condition can be used to derive the sound wave equation, which describes the propagation of sound waves in an ideal gas. The sound wave equation can be written as ∇²Ψ - 1/c² ∂²Ψ/∂t² = 0, where Ψ is the acoustic potential, and c is the speed of sound. The sound wave equation is a second-order partial differential equation that describes the propagation of sound waves in an ideal gas.
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