what is (18-7)+(5+7)

Answer: 260.16 cm

Step-by-step explanation:

Answer:

$1300

Step-by-step explanation:

52/5 = 10.4

$125 * 10.4 = $1300

or another way

125/5 = $25/week

$25 week * 52 weeks = $1300

Answer:

Call option and put option ( D )

Step-by-step explanation:

During hedging in stock/financial markets both the Call and put option can be used to hedge the trading position of the trader against the change in exchange. This is because the call or put option is used depending on the initial position of the trader.

Call option is used when the trader is currently holding a short position

Put option is used when the trader is currently holding a long position

Answer:

ok

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

Answer:

1) 12 boxes

2) 3, 6, 12

3) 12

4) 110 degrees

Step-by-step explanation:

1) Count the rectangles. Multiply the length of the rectangle in boxes to the width of rectangle in boxes.

Length: 4 boxes

Width: 3 boxes

4 x 3 = 12

12 boxes

2)

10% of 30 is 0.1 times 30.

0.1 x 30 = 30/10 = 3

20% of 30 is 0.2 times 20.

0.2 x 30 = 30/5 = 6

40% of 30 is 0.4 times 20.

0.4 x 30 = 30/2.5 = 12

3) Count the cubes. Reminder there are 2 boxes you cannot see.

Top Layer: 2

Middle Layer: 4

Back Bottom Layer: 4

Front Bottom Layer: 2

2 + 4 + 4 + 2 = 12

4) I cannot see the semicircle clearly, but I do know that a circle is 360 degrees. A semicircle, half of a circle, is 180 degrees.

180/18 (The angle of each section)

10

11 Sections

10 x 11 = 110

The correct option is c. Analysis of variance.

ANOVA stands for Analysis of Variance, which is a statistical method used to test the equality of three or more population means by analyzing the variance between samples.

In an ANOVA, the variance is partitioned into different components, including the variance between groups and the variance within groups. If the variance between groups is larger than the variance within groups, it suggests that there are significant differences between the means of the groups being compared.

ANOVA is commonly used in experimental research to test the effects of one or more independent variables on a dependent variable. It allows researchers to determine whether the means of different groups are significantly different from one another, and if so, which groups are significantly different.

Overall, ANOVA is a powerful statistical tool that enables researchers to test hypotheses and draw conclusions about the differences between multiple groups or treatments.

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Answer:

-8/9 yw

Step-by-step explanation:

just divide the numbers by each other:D

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Here's the solution :

A. The growth of the bank account is a linear function because it has a constant slope and common difference.

B. A function f(t) to represent the value of the account after t months after Janice opened her account is f(t) = 140t + 1660.

C. The predicted value of the account in July of the same year is $2640.

In order to determine the type of function that can be used to describe the growth of the bank account after a specific number of months, we would have to determine the common difference as follows;

Common difference, d = a₂ - a₁ = a₃ - a₂

Common difference, d = 1940 - 1800 = 2080 - 1940

Common difference, d = 140 = 140 (it is a linear function).

Part B.

At data point (1, 1800) and a slope of 140, a linear function for this line can be calculated by using the point-slope form as follows:

y - y₁ = m(x - x₁)

y - 1800 = 140(x - 1)

y = 140x - 140 + 1800

y = 140x + 1660 ≡ f(t) = 140t + 1660.

Part C.

Lastly, we would determine the predicted value of the account in July of the same year as follows;

f(t) = 140t + 1660.

f(7) = 140(7) + 1660.

f(7) = 980 + 1660.

f(7) = $2640.

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Forecasting plays a crucial role in time series modelling, despite the difficulty of predicting the future.

Forecasting plays a vital role in time series modelling as it allows us to make informed predictions about future values based on historical data patterns.

Although Nils Bohr's quote emphasizes the inherent difficulty of predicting the future, forecasting techniques enable us to uncover meaningful insights and trends, providing valuable information for decision-making and planning.

Time series modelling involves analyzing past data points to identify patterns, trends, and seasonality in a time-dependent sequence. By understanding these patterns, statistical models can be constructed to forecast future values with a certain level of confidence.

This is particularly relevant in various fields such as finance, economics, weather forecasting, and sales forecasting, where accurate predictions are crucial for effective planning and resource allocation.

Forecasting techniques, such as exponential smoothing, moving averages, and autoregressive integrated moving average (ARIMA) models, take into account historical data points and aim to capture underlying patterns and relationships.

These models can then be used to generate forecasts for future time periods, enabling organizations and individuals to anticipate potential outcomes and make informed decisions.

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The answer is (C) 28.26 ft²

To solve the problem, we need to find the radius of the circle, which is half of the length of the segment through the center. Since the length of the segment is 6 feet, the radius is 6/2 = 3 feet.

The area of a circle is given by the formula A = πr², where r is the radius. Substituting the value of the radius, we get:

A = π(3)² = 9π ≈ 28.26 square feet

Rounding to two decimal places, the approximate area of the circle is 28.26 ft^2.

Therefore, the answer is (C) 28.26 ft²

The area of a circle is the amount of space inside the boundary of a circle. It is defined as the product of the square of the radius (r) and the constant pi (π), which is approximately 3.14. The formula for the area of a circle is:

Area = πr^2

Where r is the radius of the circle. The radius is the distance from the center of the circle to any point on the circle's circumference.

The formula shows that the area of a circle is proportional to the square of its radius. This means that if the radius is doubled, the area of the circle will be quadrupled, and if the radius is halved, the area will be reduced to one-fourth.

The area of a circle is often used in geometry and other areas of mathematics, as well as in real-life applications such as calculating the area of a circular garden, a circular swimming pool, or the surface area of a cylinder or sphere.

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Good evening,

Answer: B

Step-by-step explanation:

-1/2(2+6x(-1)) = 3(3-(-1))-10

-1/2(2+-6) = 3(3+1))-10

-1/2(-4) = 3x4-10

2=3x4-10

2=12-10

2=2

Using the quadratic equation:

y = x^2 + 2x - 8

we will get:

a) The distance is 6 units.

b) The x-coordinate of the vertex is x = 1

c) The y-coordinate of the vertex is y = 5

Here we have the quadratic equation:

y = x^2 + 2x - 8

A) To find the distance between the x-intercepts we just need to find the difference between the two x-coordinates, which are x = -2 and x = 4 because here the x-intercepts are (-2, 0) and (4, 0).

The difference between the x-values is:

d = 4 - (-2) = 4 + 2 = 6

So the distance is 6 units.

B) The x-coordinate of the vertex is what we get if we take one of the x-coordinate of the x-intercepts and we add (or subtract, depending on which one we select) half of the distance (6 units) between the two.

We can take the first one (x = -2) and add half of the distance to get:

x = -2 + 6/2

x = -2 + 3

x = 1

C) To get the y-coordinate we need to evaluate the equation in the x-coordinate of the vertex, which is x = 1

y = 1^2 + 2*1 - 8

y = 1 + 2 - 8

y = -5

That is the y-coordinate.

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The particular solution is xp(t) = (-1/24)cos(5t) + (1/10)sin(5t) and the general solution to the differential equation is then x(t) = c1 cos(7t) + c2 sin(7t) - (1/24)cos(5t) + (1/10)sin(5t).

The given initial value problem is a homogeneous linear differential equation of second order with constant coefficients. The characteristic equation is r^2 + 49 = 0, which has complex roots r = ±7i. Since the roots are complex, the general solution is of the form x(t) = c1 cos(7t) + c2 sin(7t).

To find the particular solution, we use the method of undetermined coefficients and assume a solution of the form xp(t) = Acos(5t) + Bsin(5t). We then find that A = -1/24 and B = 1/10. Therefore, the particular solution is xp(t) = (-1/24)cos(5t) + (1/10)sin(5t).

The general solution to the differential equation is then x(t) = c1 cos(7t) + c2 sin(7t) - (1/24)cos(5t) + (1/10)sin(5t).

Using the initial conditions, we can solve for c1 and c2 to obtain x(t) = (1/5)cos(7t-1.107) + (1/24)cos(5t+0.322). Therefore, the solution to the initial value problem can be expressed as the sum of two oscillations with a phase shift of 0.322 for the cos(5t) term.

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The measure of ∠EFD as shown in the diagram is 60.5°.

Tangent line to a plane curve at a given point is the straight line that just touches the curve at that point.

Note: The tangent line of a circle and the radius meets at an angle of 90°

To calculate the value of ∠EFD, we use the theorem of the angle susbtends by an arc of a circle.

From the diagram,

First we need to look for ∠DAE

From the diagram,

Substitute these values into equation 2

Substitute the value of ∠DAE into equation 1

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The relationship between a 90% confidence interval around a mean and a 95% confidence interval around a mean is (b) The 95% C.I. is more precise in estimating a mean than the 90% C.I.

You have a 5% probability of being incorrect with a 95% confidence interval. You have a 10% probability of being incorrect with a 90% confidence interval.

The upper and lower numbers of a range with a 95% confidence interval (CI) of the mean are determined from a sample. This range describes potential possibilities for the mean because the actual population mean is unknown. Hence, the 95% C.I. is more precise in estimating a mean than the 90% C.I.

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The solutions of the quadratic equation x^2 + 3x - 10 = 0 are x = 4 and x = -1.

The solution of the quadratic equation x^2 + 3x - 10 = 0 can be found by using the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

Where (a, b, and c) are 1, 3, and -10

So, the solutions of the equation x^2 + 3x - 10 = 0 are:

x = (-3 ± √(3^2 - 4(1)(-10)) ) / 2(1)

x = (-3 ± √(9 + 40)) / 2

x = (-3 ± √49) / 2

x = (-3 ± 7) / 2

x = (4, -1)

Complete question:

Which of the following is the solution of the quadratic equation x^2 - 3x − 10 = 0?

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To estimate your paycheck, a good percentage to multiply your earning by would be 0.75 or 75%. When calculating your paycheck, it's important to account for taxes, deductions, and other withholdings that may be taken out of your gross pay.  

This accounts for taxes, deductions, and other withholdings that are typically taken out of your paycheck before you receive your net pay. For example, if you earn $1,000 per pay period, multiplying by 0.75 would give you an estimated net pay of $750. However, keep in mind that this is just an estimate and your actual net pay may vary depending on your specific tax situation and other factors.

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Answer:

1. If x is under a square root then x cannot equal a negative number. If x is in the denominator of a fraction then x cannot equal zero.

2. ax2 + bx + c

Step-by-step explanation: Hope this helps :)

Option A. If the alternative hypothesis of the test had been lower-tailed instead of two-tailed, the conclusion of the test would be different.

Recall that a two-tailed test is used when the alternative hypothesis is that the population parameter is different from the null hypothesis value in any direction, while a lower-tailed test is used when the alternative hypothesis is that the population parameter is less than the null hypothesis value.

In the given scenario, if the alternative hypothesis of the test had been lower-tailed instead of two-tailed, we would have tested the following null and alternative hypotheses:

H0: Pharaoh's translation is not worse than the other software's translation.

Ha: Pharaoh's translation is better than the other software's translation.

In this case, we would have calculated the p-value for the lower tail of the sampling distribution, and compared it to the significance level alpha. If the p-value is less than alpha, we would reject the null hypothesis and conclude that Pharaoh's translation is better than the other software's translation. If the p-value is greater than alpha, we would fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that Pharaoh's translation is better than the other software's translation.

Therefore, the correct answer to the question is option A: Unlike the two-tailed test, we would conclude that there is a difference between Pharaoh's translation and the translation of the other software.

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A person weighing 72 pounds on the nearby planet would weigh 162 pounds on Earth. Therefore, a person weighing 72 pounds on the nearby planet would weigh 162 pounds on earth if the weights are proportional.

If a person who weighs 198 pounds on earth would weigh 88 pounds on a nearby planet, then the ratio of their weight on earth to their weight on the nearby planet would be:

198/88 = 2.25

So, if we want to find out what a person weighing 72 pounds on the nearby planet would weigh on earth, we can set up a proportion:

198/88 = x/72

where x is the weight of the person on earth.

To solve for x, we can cross-multiply:

198 * 72 = 88 * x

14256 = 88x

x = 162

Therefore, a person weighing 72 pounds on the nearby planet would weigh 162 pounds on earth if the weights are proportional.

To find the weight of a person on Earth if they weigh 72 pounds on the nearby planet, we'll use proportions.

Let x be the weight of the person on Earth. We can set up the proportion as follows:

198 pounds (Earth) / 88 pounds (nearby planet) = x pounds (Earth) / 72 pounds (nearby planet)

To solve for x, cross-multiply:

198 * 72 = 88 * x

14256 = 88x

Now, divide both sides by 88 to find the weight on Earth:

x = 14256 / 88

x = 162

So, a person weighing 72 pounds on the nearby planet would weigh 162 pounds on Earth.

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Answer:

162 lb

Step-by-step explanation:

The weights are proportional, so set up a proportion and solve for the only unknown.

198 is to 88 as x is to 72

198/88 = x/72

99/44 = x/72

44x = 72 × 99

x = 7128/44

x = 162

Answer: 162 lb

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\(4x + 5y = 6\\5x + 4y = 5\)

The lines are

A. perpendicular.

B. parallel

C. neither

__________________________

C. Would be our answer because parallel lines never intersect

perpendicular lines form 90 degrees of all sides.

Component 3 must be started on day 197 to meet the delivery date of day 200.

To illustrate the backward schedule, we need to start from the delivery date (day 200) and work our way backward, taking into account the lead times and dependencies of each operation.

(a) Backward schedule:

Operation    |  Work Center  |  Time (hours)  |  Start Day

--------------------------------------------------------

Final Assembly |   Work Center 1  |        1       |     200

Sub-assembly 1 |   Work Center 2  |        2       |     199

Component 4     |   Work Center 3  |        3       |     197

Component 2     |   Work Center 4  |        4       |     196

Component 3     |   Work Center 5  |        3       |     ????

(b) To identify when component 3 must be started to meet the delivery date, we need to consider its dependencies and lead times.

From the backward schedule, we see that component 3 is required for sub-assembly 1, which is scheduled to start on day 199. The time required for sub-assembly 1 is 2 hours, which means it should be completed by the end of day 199.

Since component 3 is needed for sub-assembly 1, we can conclude that component 3 must be started at least 2 hours before the start of sub-assembly 1. Therefore, component 3 should be started on day 199 - 2 = 197 to ensure it is completed and ready for sub-assembly 1.

Hence, component 3 must be started on day 197 to meet the delivery date of day 200.

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Answer:

Step-by-step explanation:

\(\frac{4}{7}*2184 = 4*312\\ = 1248\)

Answer:

3i\(\sqrt{3}\)

Step-by-step explanation:

Using the rule of radicals

\(\sqrt{a}\) × \(\sqrt{b}\) ⇔ \(\sqrt{ab}\) and \(\sqrt{-1}\) = i

Given

\(\sqrt{-27}\)

= \(\sqrt{9(3)(-1)}\)

= \(\sqrt{9}\) × \(\sqrt{3}\) × \(\sqrt{-1}\)

= 3i\(\sqrt{3}\)

At the 5% significance level, we have sufficient evidence to conclude that the population mean is higher than 40 hours.

To test the null hypothesis that the population mean is 40 hours against the alternative that it is higher, we can perform a one-sample t-test.

The null hypothesis (H₀): μ = 40 (population mean is 40 hours)

The alternative hypothesis (H₁): μ > 40 (population mean is higher than 40 hours)

Given a sample of 10 students, the sample mean (x') is 45 hours and the sample standard deviation (s) is 10.5409.

Using the t-test, we calculate the test statistic t:

t = (x' - μ₀) / (s / √n)

Where x' is the sample mean, μ₀ is the null hypothesis population mean (40), s is the sample standard deviation, and n is the sample size (10).

Plugging in the values, we get:

t = (45 - 40) / (10.5409 / √10)

t ≈ 2.38

Next, we determine the critical value or the p-value associated with a significance level of 5%. For a one-tailed test (since we are testing if the mean is higher), the critical value is tc = t(α,n-1), where α is the significance level and n-1 is the degrees of freedom.

At a significance level of 5%, with 9 degrees of freedom (n-1), the critical value is tc = 1.833 (obtained from a t-table or statistical software).

Since the calculated t-value (2.38) is greater than the critical value (1.833), we reject the null hypothesis.

Therefore, at the 5% significance level, we have sufficient evidence to conclude that the population mean is higher than 40 hours based on the given sample data.

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Answer:

There isnt a diagram

Step-by-step explanation:

I agree with Andre. There are only two unique bases, not seven different faces as Noah suggests.

Both bases are the same, so you only need to calculate their area once and double it.

The other five rectangles have the same height, meaning you can calculate their areas more efficiently.

Noah's approach of finding the area of seven different faces is unnecessary and overcomplicates the problem.

Thus, I agree with Andre because his process is correct and more straightforward.

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