What is 1.8 rounded to the nearest tenth

Answer:

12.5 x 24=300

Step-by-step explanation:

The transformations that map the strip pattern onto itself is a horizontal translation, a reflection across a vertical line, a reflection across a horizontal line, a glide reflection, and a 180°. Option A is the correct option.

Here, we have,

the conditions for mapping the strip transformation pattern onto itself:

The strip pattern can be mapped onto itself in two different ways.

The first way is to translate the strip pattern horizontally and then rotate it by 180° degrees.

The second way is to reflect the strip pattern across a vertical line.

Hence, the transformations that map the strip pattern onto itself can be achieved through a horizontal translation, a reflection across a vertical line, a reflection across a horizontal line, a glide reflection, and a 180°.

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complete question:

Which transformations map the strip pattern onto itself?

a horizontal translation, a reflection across a vertical line, a reflection across a horizontal line, a glide reflection, and a 180°

a horizontal translation only

a horizontal translation, a reflection across a horizontal line, and a glide reflection only

a horizontal translation and a 180° rotation only

Answer:

8(4 - n)

Step-by-step explanation:

Which expression correctly represents “eight times the difference of four and a number”? 8 (n minus 4) 8 (4 minus n) 8 (n) minus 4 8 (4) minus n

Do it one piece at a time.

“eight times the difference of four and a number”:     n

“eight times the difference of four and a number”:     4 - n

“eight times the difference of four and a number”:     8(4 - n)

Answer:

the answer is b

Step-by-step explanation:

Answer:

\(x = \frac{9}{ \sqrt{2} } = \frac{9 \sqrt{2} }{2} \)

Answer: 1/8

Step-by-step explanation:

First make the bottom half the same:

3/4*2/2=6/8

We don’t need to change the first portion since they have a common factor

7/8-6/8=1/8

The principal must have a value of $2,500. if the bank manager also wants to advertise that one can earn ​$10 the first​ month.

Hence, with a principal of $3,350, it is possible for the poster to correctly say the statement, as the needed principal is less than $3,350.

As the problem states, simple interest is used, meaning that there is a single compounding per period.

The equation that gives the interest accrued after t years is given as follows:

I(t) = Prt.

The parameters of the interest equation are given as follows:

The values of the measures in this problem are given as follows:

Hence the principal is obtained solving the equation as follows:

10 = P x 1/12 x 0.048

0.004P = 10

P = 10/0.004

P = $2,500.

The problem is of:

"A bank manager wants to encourage new customers to open accounts with principals of at least ​$3,500. He decides to make a poster advertising a simple interest rate of 4.8​%. What must the principal be if the bank manager also wants to advertise that one can earn ​$10 the first​ month? Can the poster correctly​ say, "Open an account of ​$3,500 and earn at least ​$10 interest in 1​ month!"?"

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Given:

Principal value = $1500

Rate of interest = 7% per annum compounded daily

Time = 2 years.

To find:

The amount after 2 years.

Solution:

Formula for amount:

\(A=P\left(1+\dfrac{r}{n}\right)^{nt}\)

Where, P is principal, r is the rate of interest in decimals, n is the number of time interest compounded in an year and t is the number of years.

We know that 1 year is equal to 365 days and the interest compounded daily. So, n=365.

Substituting \(P=1500,\ r=0.07,\ n=365,\ t=2\) in the above formula, we get

\(A=1500\left(1+\dfrac{0.07}{365}\right)^{365(2)}\)

\(A=1500\left(\dfrac{365+0.07}{365}\right)^{730}\)

\(A=1500\left(\dfrac{365.07}{365}\right)^{730}\)

Using calculator, we get

\(A\approx 1725.39\)

The amount after two years is $1,725.39. Therefore, the correct option is (c).

The value of secant XY is 37.5 units.

The Secant-Secant Theorem states that "if two secant segments which share an endpoint outside of the circle, the product of one secant segment and its external segment is equal to the product of the other secant segment and its external segment".

Using the theorem above, we can say:

VZ * VW = VX * VY

30 * 45 = 22.5 * VY

22.5VY = 1350

VY = 1350/22.5

VY = 60 units

Since VY = VX + XY. We have:

60 = 22.5 + XY

XY = 60 - 22.5

XY = 37.5 units

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The inclination of the line represented by the equation y = x + 3 is 1, and the inclination of the line represented by the equation 3x - 2y = 6 is 3/2.

To determine the inclination (or slope) of a straight line, we can examine the coefficients of the variables x and y in the equation of the line.

The inclination represents the ratio of how much y changes with respect to x.

Equation: y = x + 3

In this equation, the coefficient of x is 1, which means that for every increase of 1 in x, y also increases by 1.

This indicates that the inclination of the line is positive, meaning it slopes upwards as x increases.

Since the coefficient of x is 1, the inclination can be expressed as 1/1 or simply 1.

Equation: 3x - 2y = 6

To determine the inclination, we need to rearrange the equation in slope-intercept form (y = mx + b), where m represents the slope.

First, isolate y:

-2y = -3x + 6

Divide the entire equation by -2 to solve for y:

y = (3/2)x - 3

Now we can observe that the coefficient of x is 3/2.

This indicates that for every increase of 1 in x, y increases by 3/2. Therefore, the inclination of this line is positive, indicating an upward slope.

The inclination can be expressed as 3/2.

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The coordinates of the point that corresponds to -5π/4 on the unit circle is (-1/√2, 1/√2).

Given that,

We have to find the coordinates of the point that corresponds to -5π/4 on the unit circle.

We know that any point on the unit circle can be defined as,

(cos θ, sin θ)

where θ is the angle formed with the X axis.

-5π/4 will be the point the corresponds to -225°.

Cos(-5π/4) = cos (5π/4)

                  = cos (π + π/4)

                  = -cos (π/4)

                  = -1/√2

sin (-5π/4) = -sin (5π/4)

                  = -sin (π + π/4)

                  = sin (π/4)

                  = 1/√2

Hence the coordinate of the unit circle is (-1/√2, 1/√2).

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If the length of the rectangle be (3x+2) units and width (4x+10)units then the area of the rectangle be \($x=-\frac{2}{3}, x=-\frac{5}{2}$$\).

The region enclosed by an object's shape is referred to as the area. The area of the shape is the area that the figure or any other two-dimensional geometric shape occupies in a plane.

A rectangle's sides determine its area. In essence, the length and breadth of the rectangle multiplied together gives the area of the rectangle.

Let the length of the rectangle be (3x + 2) units and width of the rectangle be (4x + 10)units.

Area of rectangle = length × breadth

= (3x +2) × (4x +10)

simplifying the above equation, we get

= (3x) × (4x +10) + 2(4x +10)

= 12x² + 30x +8x +20

12x² + 38x + 20 = 0

simplifying the above equation, we get

By using quadratic equation, then

\($x_{1,2}=\frac{-38 \pm \sqrt{38^2-4 \cdot 12 \cdot 20}}{2 \cdot 12}$$\)

simplifying the above equation, we get

\($$\begin{gathered}x_{1,2}=\frac{-38 \pm 22}{2 \cdot 12}\end{gathered}$$\)

Separate the solutions, we get

\($$\begin{aligned}& x_1=\frac{-38+22}{2 \cdot 12}, x_2=\frac{-38-22}{2 \cdot 12} \\& x=\frac{-38+22}{2 \cdot 12}:-\frac{2}{3} \\& x=\frac{-38-22}{2 \cdot 12}:-\frac{5}{2}\end{aligned}$$\)

The solutions to the quadratic equation are:

\($x=-\frac{2}{3}, x=-\frac{5}{2}$$\)

The complete question is:

Find the area of rectangle with length (3x+2) units and width (4x+10)units.

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All tables that represent proportional relationship between x and y are:

B. table B.

E. table E.

In Mathematics and Geometry, a proportional relationship is a type of relationship that produces equivalent ratios and it can be modeled or represented by the following mathematical equation:

y = kx

Where:

Next, we would determine the constant of proportionality (k) by using various data points as follows:

Constant of proportionality, k = y/x

Constant of proportionality, k = (20 - 15)/(10 - 5) = (5 - 4)/(1 - 0)

Constant of proportionality, k = 1.

Therefore, the required linear equation is given by;

y = kx

y = x

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

The y-coordinate of -3f(x-1) when x = 0 is -63

From the question, we have the following parameters that can be used in our computation:

The table of values

So, we have

-3f(x - 1)

When x = 0, we have

y = -3f(0 - 1)

This gives

y = -3f(-1)

From the table, we have

y = -3 * 21

Evaluate

y = -63

Hence, the y-coordinate is -63

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Answer:

Im not sure how to explain this but text me so i can fully explain it to where you understand

Step-by-step explanation:

The values of a and b using the factor theorem for the polynomial f(x), we set f(1) and f(-1) equal to zero. Solving the resulting system of equations, we find that a = 12 and b = -1.

To find the values of a and b using the factor theorem, we need to use the given factors (x - 1) and (x + 1) and the fact that they are roots of the polynomial f(x).
The factor theorem states that if (x - c) is a factor of a polynomial, then f(c) = 0. Therefore, we can set x = 1 and x = -1 in the polynomial f(x) to get two equations.
First, let's substitute x = 1 into f(x):
f(1) = (1)^3 + a(1)^2 + b(1) - 12
f(1) = 1 + a + b - 12
Next, let's substitute x = -1 into f(x):
f(-1) = (-1)^3 + a(-1)^2 + b(-1) - 12
f(-1) = -1 + a - b - 12
Since (x - 1) and (x + 1) are factors, f(1) and f(-1) must equal zero. Therefore, we can set the two equations equal to zero and solve for a and b:
1 + a + b - 12 = 0
-1 + a - b - 12 = 0
Rearraning the equations, we have:
a + b = 11
a - b = 13
Now, we can solve this system of equations. Adding the two equations, we get:
2a = 24
a = 12
Substituting the value of a into one of the equations, we find:
12 - b = 13
b = -1
Therefore, the values of a and b are 12 and -1 respectively.

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The set of 4 integers are is given by the equation A = { 1 , 2 , 3 , 4 }

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the set of 4 integers be represented as set A

Now , the equation will be

Let the first number be 1

The absolute value of 1 is | 1 | = 1

Let the second number be 2

The absolute value of 2 is | 2 | = 2

Let the third number be 3

The absolute value of 3 is | 3 | = 3

Let the fourth number be 4

The absolute value of 4 is | 4 | = 4

And , | 1 | < | 2 | < | 3 | < | 4 |

Hence , the set of integers are { 1 , 2 , 3 , 4 }

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Let x = 2y. Then we want to show

sin(6y) + sin(4y) - sin(2y) = 4 sin(2y) cos(y) cos(3y)

Recall the angle sum identities,

sin(x ± y) = sin(x) cos(y) ± cos(x) sin(y)

cos(x ± y) = cos(x) cos(y) ∓ sin(x) sin(y)

which lets us write

sin(6y) = sin(4y + 2y) = sin(4y) cos(2y) + cos(4y) sin(2y)

sin(4y) = sin(2y + 2y) = 2 sin(2y) cos(2y)

cos(4y) = cos(2y + 2y) = cos²(2y) - sin²(2y)

Ultimately, we use these identities to rewrite the left side as

sin(6y) + sin(4y) - sin(2y)

= 2 (sin(4y) cos(2y) + cos(4y) sin(2y)) + 2 sin(2y) cos(2y) - sin(2y)

= 2 sin(2y) cos²(2y) + (cos²(2y) - sin²(2y)) sin(2y) + 2 sin(2y) cos(2y) - sin(2y)

Notice the underlined common factor of sin(2y). If we remove this from both sides of the identity we want to prove, then it remains to show that

2 cos²(2y) + (cos²(2y) - sin²(2y)) + 2 cos(2y) - 1 = 4 cos(y) cos(3y)

or

3 cos²(2y) - sin²(2y) + 2 cos(2y) - 1 = 4 cos(y) cos(3y)

Recall the Pythagorean identity,

cos²(x) + sin²(x) = 1

which lets us write

3 cos²(2y) - sin²(2y) + 2 cos(2y) - 1

= 3 cos²(2y) - (1 - cos²(2y)) + 2 cos(2y) - 1

= 4 cos²(2y) + 2 cos(2y) - 2

= 2 (2 cos²(2y) + cos(2y) - 1)

= 2 (2 cos(2y) - 1) (cos(2y) + 1)

Recall the half-angle identity for cosine,

cos²(x/2) = 1/2 (1 + cos(x))

which means

cos(2y) + 1 = 2 • 1/2 (1 + cos(2y)) = 2 cos²(y)

and so

2 (2 cos(2y) - 1) (cos(2y) + 1)

= 4 (2 cos(2y) - 1) cos²(y)

= 4 cos(y) (2 cos(2y) - 1) cos(y)

Now notice the underlined factor of 4 cos(y), which also appears in the right side of the identity we want to prove. Eliminate this term and all that's left is to show that

(2 cos(2y) - 1) cos(y) = cos(3y)

which follows from a combination of the identities I mentioned above:

(2 cos(2y) - 1) cos(y)

= 2 cos(2y) cos(y) - cos(y)

= 2 • 1/2 (cos(2y + y) + cos(2y - y)) - cos(y)

= (cos(3y) + cos(y)) - cos(y)

= cos(3y)

as required.

Trigonometric identities involve equations that use the trigonometric functions that are true for all variables in the equation

The identity is given as:

\(\sin(3x) + \sin(2x) - \sin(x) = 4\sin(x)\cos(\frac x2)\cos(\frac{3x}{2})\)

Let x = 2y.

So, we have:

\(\sin(6y) + \sin(4y) - \sin(2y) = 4\sin(2y)\cos(y)\cos(3y)\)

Expand

\(\sin(4y + 2y) + \sin(2y + 2y) - \sin(2y) = 4\sin(2y)\cos(y)\cos(3y)\)

Expand the identities using the angle sum identities,

\(\sin(4y)\cos(2y) + \cos(4y)\sin(2y) + 2\sin(2y)\cos(2y) - \sin(2y) = 4\sin(2y)\cos(y)\cos(3y)\)

Expand cos(4y) and sin(4y)

\(2\sin(2y)\cos^2(2y) + [\cos^2(2y) - \sin^2(2y)]\sin(2y) + 2\sin(2y)\cos(2y) - \sin(2y) = 4\sin(2y)\cos(y)\cos(3y)\)

Factor out sin(2y)

\(\sin(2y)[2\cos^2(2y) + \cos^2(2y) - \sin^2(2y) + 2\cos(2y) - 1] = 4\sin(2y)\cos(y)\cos(3y)\)

Evaluate the like terms

\(\sin(2y)[3\cos^2(2y) - \sin^2(2y) + 2\cos(2y) - 1] = 4\sin(2y)\cos(y)\cos(3y)\)

Substitute

\(\sin^2(2y) = 1 - \cos^2(2y)\)

\(\sin(2y)[3\cos^2(2y) - 1 + \cos^2(2y) + 2\cos(2y) - 1] = 4\sin(2y)\cos(y)\cos(3y)\)

Evaluate the like terms

\(\sin(2y)[4\cos^2(2y) - 1 + 2\cos(2y) - 1] = 4\sin(2y)\cos(y)\cos(3y)\)

\(\sin(2y)[4\cos^2(2y) + 2\cos(2y) - 2] = 4\sin(2y)\cos(y)\cos(3y)\)

Factor out 2

\(2\sin(2y)[2\cos^2(2y) + \cos(2y) - 1] = 4\sin(2y)\cos(y)\cos(3y)\)

Expand

\(2\sin(2y)[2\cos^2(2y) +2\cos(2y) - \cos(2y) - 1] = 4\sin(2y)\cos(y)\cos(3y)\)

Factorize

\(2\sin(2y)[2\cos(2y)( \cos(2y) + 1) -1( \cos(2y) + 1)] = 4\sin(2y)\cos(y)\cos(3y)\)

Factor out cos(2y) + 1

\(2\sin(2y)[( 2\cos(2y) - 1)( \cos(2y) + 1)] = 4\sin(2y)\cos(y)\cos(3y)\)

By half identity, we have:

\(\cos\²(\frac x2) = \frac 12 (1 + \cos(x))\)

Multiply both sides by 2

\(2\cos\²(\frac x2) = (1 + \cos(x))\)

Replace x with 2y

\(2\cos\²(y) = 1 + \cos(2y)\)

So, we have:

\(2\sin(2y)[( 2\cos(2y) - 1)( 2\cos^2(y))] = 4\sin(2y)\cos(y)\cos(3y)\)

\(4\sin(2y)(2 \cos(2y) - 1)(\cos^2(y)) = 4\sin(2y)\cos(y)\cos(3y)\)

Factor out cos(y)

\(4\sin(2y)(\cos(y)(2 \cos(2y) - 1)(\cos(y)) = 4\sin(2y)\cos(y)\cos(3y)\)

Expand

\(4\sin(2y)(\cos(y)(2 \cos(2y)\cos(y) - \cos(y)) = 4\sin(2y)\cos(y)\cos(3y)\)

Using the half identity, we have:

\(4\sin(2y)(\cos(y)(2 * \frac 12 *\cos(2y + y) + \cos(2y - y) - \cos(y)) = 4\sin(2y)\cos(y)\cos(3y)\)

\(4\sin(2y)(\cos(y)(\cos(3y) + \cos(y) - \cos(y)) = 4\sin(2y)\cos(y)\cos(3y)\)

\(4\sin(2y)\cos(y)\cos(3y) = 4\sin(2y)\cos(y)\cos(3y)\)

Recall that:

x = 2y

So, we have:

\(4\sin(x)\cos(\frac x2)\cos(\frac {3x}2) = 4\sin(x)\cos(\frac x2)\cos(\frac {3x}2)\)

Both sides of the equations are the same.

Hence, the identity \(\sin(3x) + \sin(2x) - \sin(x) = 4\sin(x)\cos(\frac x2)\cos(\frac{3x}{2})\) has been proved

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The nearest kilometers to 999.09344471 km is 1000 km.

Given value is 999.09344471 Km.

We have to calculate the round off value to the nearest kilometers. we know that after the decimal if the value of tenth place is 5 or bigger than 5 then we add 1 to the tens place digit, this is the fundamental rule of rounding off.

Now on following this rule from the very right hand side up to the tenth place digit we come to the conclusion that only  the value after the decimal (934) is to be rounded off which is (900).

So 999.09344471 km is finally becomes 999.900 km after rounding of to nearest hundredth value.

Again rounding off 999.900 km to nearest km so it becomes 1000 km.

The nearest kilometers to 999.09344471 km is 1000 km.

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Answer:

8

Step-by-step explanation:

8*8=64

Answer:

1/2=10

Step-by-step explanation:

it depends upon the area of the triwngle

Answer:

12.

Step-by-step explanation:

if to re-write the given condition, then

\(\frac{3}{0.25} =\frac{18}{1.5} =\frac{30}{2.5} =\frac{36}{3} ;\)

it is clear, the required constant is 12 (12 per hour).

\(\boxed{\sf B.\,23x + 62}.\)

\(\sf 5(4x + 12) + 3x + 2\)

\(\sf (5)(4x)+(5)(12) + 3x + 2\\ \\20x+60 + 3x + 2\)

\(\sf 20x+ 3x + 2+60 \\ \\\boxed{\sf 23x + 62} \Longrightarrow Final\,answer.\)

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Answer:

To calculate 2 3/4 of 500 grams, follow these steps:

1. Convert the mixed number to an improper fraction:

2 3/4 = (2 x 4 + 3)/4 = 11/4

2. Multiply the improper fraction by 500:

11/4 x 500 = (11 x 500)/4 = 2,750/4

3. Simplify the fraction by dividing the numerator and denominator by their greatest common factor, which is 2:

2,750/4 = (2 x 1,375)/(2 x 2) = 1,375/2

Therefore, 2 3/4 of 500 grams is equal to 1,375/2 grams or 687.5 grams.

Step-by-step explanation:

Answer:

a.\(y+1=0\)

b.\(2x+4y=1\)

Step-by-step explanation:

We are given that

\((x^2+y^2)^2=3x^2y-y^3\)

a.(0,-1)

Differentiate w.r.t x

\(2(x^2+y^2)(2x+2yy')=6xy+3x^2y'-3y^2y'\).....(1)

Substitute x=0 and y=-1 in equation (1)

\(2(0+1)(-2y')=-3y'\)

\(-4y'+3y'=0\)

\(-y'=0\)

\(y'=0\)

\(m=y'=0\)

Point-slope form:

\(y-y_0=m(x-x_0)\)

Using the formula

\(y+1=0\)

This is required equation of tangent line to the given curve at point (0,-1).

b.(-1/2,1/2)

Substitute the value in equation (1)

\(2(1/4+1/4)(-1+y')=6(-1/2)(1/2)+3(1/4)y'-3(1/4)y'\)

\(2(2/4)(-1+y')=-3/2+3/4y'-3/4y'\)

\(-1+y'=-3/2\)

\(y'=-3/2+1=\frac{-3+2}{2}=-\frac{1}{2}\)

\(m=y'=-1/2\)

Again using point-slope formula

\(y-1/2=-1/2(x+1/2)\)

\(\frac{2y-1}{2}=-\frac{1}{4}(2x+1)\)

\(2y-1=-\frac{1}{2}(2x+1)\)

\(4y-2=-2x-1\)

\(2x+4y=2-1\)

\(2x+4y=1\)

Answer:

a) 5.37% probability that an individual distance is greater than 210.9 cm

b) 75.80% probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

c) Because the underlying distribution is normal. We only have to verify the sample size if the underlying population is not normal.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \(\mu\) and standard deviation \(\sigma\), the zscore of a measure X is given by:

\(Z = \frac{X - \mu}{\sigma}\)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \(\mu\) and standard deviation \(\sigma\), the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \(\mu\) and standard deviation \(s = \frac{\sigma}{\sqrt{n}}\).

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\(\mu = 197.5, \sigma = 8.3\)

a. Find the probability that an individual distance is greater than 210.9 cm

This is 1 subtracted by the pvalue of Z when X = 210.9. So

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{210.9 - 197.5}{8.3}\)

\(Z = 1.61\)

\(Z = 1.61\) has a pvalue of 0.9463.

1 - 0.9463 = 0.0537

5.37% probability that an individual distance is greater than 210.9 cm.

b. Find the probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

Now \(n = 15, s = \frac{8.3}{\sqrt{15}} = 2.14\)

This probability is 1 subtracted by the pvalue of Z when X = 196. Then

\(Z = \frac{X - \mu}{\sigma}\)

By the Central Limit Theorem

\(Z = \frac{X - \mu}{s}\)

\(Z = \frac{196 - 197.5}{2.14}\)

\(Z = -0.7\)

\(Z = -0.7\) has a pvalue of 0.2420.

1 - 0.2420 = 0.7580

75.80% probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

The underlying distribution(overhead reach distances of adult females) is normal, which means that the sample size requirement(being at least 30) does not apply.

Step-by-step explanation:

it seems you solved the tricky part yourself already.

just to be sure, let's do the first derivative here again.

the easiest way would be for me to simply multiply the functional expression out and then do a simple derivative action ...

f(t) = (t² + 6t + 7)(3t² + 3) = 3t⁴ + 3t² + 18t³ + 18t + 21t² + 21 =

= 3t⁴ + 18t³ + 24t² + 18t + 21

f'(t) = 12t³ + 54t² + 48t + 18

and now comes the simple part (what was your problem here, don't you know how functions work ? then you are in a completely wrong class doing derivatives; for that you need to understand what functions are, and how they work). we calculate the function result of f'(2).

we simply put the input number (2) at every place of the input variable (t).

so,

f'(2) = 12×2³ + 54×2² + 48×2 + 18 = 96 + 216 + 96 + 18 =

= 426

Answer:

  3

Step-by-step explanation:

The number of tubes can be found from an inequality that relates the number of square inches that can be painted to the number of square inches that must be painted.

Let t represent the number of tubes.

  1400t ≥ 3672 . . . . . the number of tubes that will paint at least 3672 in²

  t > 2.623 . . . . . divide by 1400

If only whole numbers of tubes are available, then ...

  3 tubes are needed to paint the ramp.

Answer:

Step-by-step explanation:

 The number of tubes can be found from an inequality that relates the number of square inches that can be painted to the number of square inches that must be painted.

Let t represent the number of tubes.

 1400t ≥ 3672 . . . . . the number of tubes that will paint at least 3672 in²

 t > 2.623 . . . . . divide by 1400

If only whole numbers of tubes a